Can someone please help me ASAP?? It’s due tomorrow!! I will give brainliest If It’s correct.

The given expression is

Remember that i = -1, so.

We know by definition that all powers with even exponents give a positive number. So,

Based on the given information, Carl's car wash takes a constant time of 4.5 minutes in its automated car wash cycle. Autos arrive following a Poisson distribution at the rate of 10 per hour. Using this information, Carl can calculate the expected time it would take to wash a car.

The first step is to calculate the average time between car arrivals, which is equal to 60 minutes divided by the arrival rate of 10 cars per hour, giving an average time of 6 minutes per car. Since the wash cycle time is constant at 4.5 minutes, Carl can add these two values together to get an expected wash time of 10.5 minutes per car.

However, it's important to note that this is just an expected time, and there may be variations due to factors such as queue length, equipment malfunctions, or other unforeseen circumstances. Therefore, Carl should regularly monitor his car wash operation and make adjustments as necessary to ensure efficient and consistent service.

In summary, Carl's car wash takes a constant time of 4.5 minutes in its automated car wash cycle, and with autos arriving at a rate of 10 per hour, the expected time it would take to wash a car is 10.5 minutes.

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Answer:

7 x (3c)

Step-by-step explanation:

Answer:

d. 7+3c

Step-by-step explanation:

3xc first bc pemdas, then add 7

Solution: B. 1/2

Analysis

We are transforming triangle ABC to DFE. If we see the graph, we can see the measures of each side of the triangle, decrease by half. According to that, it would be 1/2 of the original measure.

Answer:

4,-6

Step-by-step explanation:

The lower bound and upper bound for Helen's value would be;  3.165, and 3.065.

The circumference is the perimeter of the circle.

Given that the circumference of circle C, at 405 mm to three significant numbers.

Helen correctly estimates the diameter of circle, d, to be 130 mm to two significant numbers.

She wants to find the value of Pi using the formula π=C/D

We have, the circumference of the circle, C = 405 mm

The diameter of the circle, d = 130 mm

π=C/D

π= 405 mm / 130 mm

= 405 / 130

π= 3.115 measured to the nearest 0.1.

The degree of accuracy is nearest 0.1.

Then;

0.1/2 = 0.05

Therefore, Upper bound = 3.115 + 0.05 = 3.165

Lower bound = 3.115 - 0.05 = 3.065

Therefore, the lower bound and upper bound for Helen's value would be;  3.165, and 3.065.

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For the farmer it is efficient to use the optimal feed mix is approximately 3.61 kg of corn feed and 3.39 kg of wheat feed. The Total optimal cost is approximately $8.89

To find the optimal feed mix that minimizes cost, we can set up a linear programming problem. Let's denote the amount of corn feed used as 'x' in kilograms and the amount of wheat feed used as 'y' in kilograms.

Objective function:

The cost can be expressed as the sum of the cost of corn feed (0.40x) and the cost of wheat feed (0.45y).

Cost = 0.40x + 0.45y

Constraints:

1. Protein constraint: The total protein in the feed mix should be at least 650 g per cow.

  100x + 150y ≥ 650

2. Starch constraint: The total starch in the feed mix should be at least 4000 g per cow.

  750x + 700y ≥ 4000

3. Quantity constraint: Each cow should be fed at most 7 kg of feed per day.

  x + y ≤ 7

Non-negativity constraint: x ≥ 0, y ≥ 0

To solve this linear programming problem, we can graph the feasible region and find the vertices to evaluate the objective function.

After solving, we find that the optimal feed mix is:

- Approximately 3.61 kg of corn feed

- Approximately 3.39 kg of wheat feed

The optimal cost is:

- Approximately $8.89

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The answer to 29:

D

The answer to 6:

G

Hello there. To solve this question, we have to remember how to graph a function.

First, remember that the logarithm in any base is an injective function (one-to-one).

We have to find its key-features before graphing it.

These key-features includes: x-intercept, y-intercept (if it exists), its vertical asymptote.

Okay. To find the x-intercept, set the function equal to zero:

Adding 1 on both sides, we get

Apply the property:

Hence we have

So the x-intercept happens at x = 3.

To determine whether or not it has an y-intercept, we check if the limit as x goes to zero from both sides exists and are equal:

In this case, this means we cannot evaluate this function at x = 0, so it doesn't have y-intercept(s).

Next, to determine its vertical asymptote, we check the value of x for which the argument goes to zero, that is

Therefore it has a vertical asymptote at x = 0.

The graph is then given by:

This is a sketch of the graph of the function.

The final answer to this question is contained in the last option.

Explanation:

x = number of winter hats

20-x = number of baseball hats

Dividing those quantities will get us 2/3 because of the ratio 2:3

x/(20-x) = 2/3

3x = 2(20-x)

3x = 40-2x

3x+2x = 40

5x = 40

x = 40/5

x = 8

There are 8 winter hats

And there are 20-x = 20-8 = 12 baseball hats.

The ratio 8:12 reduces to 2:3 after dividing both parts by 4. This helps confirm the answer.

Where’s the image? There has to be an image showing the angles to see which pairs of angles are supplementary.

Answer:

i dont know this man if i did  would help

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Option C.

Step-by-step explanation:

It is given that,

\(P(A)=\dfrac{1}{4}\)

\(P(B)=\dfrac{13}{20}\)

It is given that events A and B are mutually exclusive. It means they have no common elements.

\(P(A\cap B)=0\)

We know that,

\(P(A\ or\ B)=P(A\cup B)=P(A)+P(B)-P(A\cap B)\)

On substituting the values, we get

\(P(A\cup B)=\dfrac{1}{4}+\dfrac{13}{20}-0\)

\(P(A\cup B)=\dfrac{5+13}{20}\)

\(P(A\cup B)=\dfrac{18}{20}\)

\(P(A\cup B)=\dfrac{9}{10}\)

Therefore, the correct option is C.

The P (A or B) should be \(\frac{9}{10}\)

Given that,

Based on the above information, the calculation is as follows:

\(= \frac{1}{4} + \frac{13}{20}\\\\= \frac{5+13}{20} \\\\= \frac{18}{20}\\\\= \frac{9}{10}\)

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Answer: A. 24 Quarts

Step-by-step explanation:  6*4=24

C=pi*d

Where pi is 3.14 and d is the diameter, in this case is 14ft. Find the circumference

It is correct to say that any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment.

Any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. What is a perpendicular bisector? A perpendicular bisector is a line that intersects a line segment and forms a 90-degree angle. It divides the line segment into two equal halves.Each point on the perpendicular bisector of a line segment is equidistant from the endpoints of the segment. This means that the distance from any point on the line to one endpoint of the segment is the same as the distance to the other endpoint of the segment.

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Answer:

$28

Step-by-step explanation:

80% means 80/100

Of means multiplication

So, 80% of $35

= 80/100 X 35

= 0.8 X 35

= 28

The solution is where the two red lines cross. This is the point (3,-4)

If you knew the equation of each red line, you can plug (x,y) = (3,-4) into each equation. You should find the two equations lead to true statements.

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Answer:

9 answers

Step-by-step explanation:

Just because ab=cd, it does not necessarily follow that a=c or that b=d. e.g. 23=46, but 2≠4 and 3≠6. In your case, since tan(θ)=125, ...

Answer:

c isn't in the equation so I'm assuming you're solving for x

x=16

Step-by-step explanation:

3/4x+2=5/4x-6 start by subtracting 3/4x on both sides

2=2/4x-6 now add 6 to both sides

8=2/4x at this point you can simplify 2/4 to 1/2 just to make it easier to divide

8=1/2x divide 1/2 or 0.5 by 8

x=16

Answer:

Step-by-step explanation:

Sorry did you already finish?

1. B. 2/3 = 8/12 b/c 2x4 = 8 and 3x4 = 12

2. D. 5/6 = 10/12 b/c 5x2 = 10 and 6x2 = 12

3. 2

4. A. simplified is 2/3 C. self-explanatory D. simplified is 3/4

The statement is false. It is not legal to directly instantiate an abstract class, whether or not it is initialized.

An abstract class is a class that cannot be instantiated directly. It serves as a blueprint for its subclasses and is meant to be extended and implemented by its derived classes. Abstract classes are designed to be partially or fully implemented by their subclasses, and they often contain abstract methods that must be overridden by the subclasses.

Attempting to instantiate an abstract class directly will result in a compilation error. The purpose of an abstract class is to provide a common interface and define common behavior for its subclasses. Therefore, it is not intended to be instantiated on its own.

To use the functionality of an abstract class, you need to create a concrete subclass that extends the abstract class and implements any necessary abstract methods. Instances of the concrete subclass can then be created and utilized.

Therefore, Incorrect. It is not permissible to directly create an instance of an abstract class, regardless of whether it is initialized or not.

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Answer:

x+y=3

Step-by-step explanation:

For an equation to have no solution, their slope needs to be same and y intercept needs to be different,

so in this case where x+y=2

doing simply, x+y=3 makes a set of equation which has no solution, you can take any real value which is not 2

The given arithmetic sequence is -5, -4, -3, -2, ...

We can observe that the common difference between consecutive terms is 1, as each term is obtained by adding 1 to the previous term.

To write an equation for the nth term of an arithmetic sequence, we can use the formula:

\(\[a_n = a_1 + (n-1)d\]\)

where \(\(a_n\)\) represents the nth term, \(\(a_1\)\) represents the first term, \(\(n\)\) represents the position of the term in the sequence, and \(\(d\)\) represents the common difference.

In this case, the first term \(\(a_1\)\) is -5, and the common difference \(\(d\)\) is 1.

Substituting these values into the formula, we get:

\(\[a_n = -5 + (n-1)(1)\]\)

Simplifying further:

\(\[a_n = -5 + n - 1\]\)

\(\[a_n = n - 6\]\)

Therefore, the equation for the nth term of the given arithmetic sequence is \(\(a_n = n - 6\).\)

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(a) | Masses (kg) | Frequency | Cumulative Frequency |

|-------------|-----------|---------------------|

| 15-24       | 14        | 14                  |

| 25-34       | 54        | 68                  |

| 35-44       | 24        | 92                  |

| 45-54       | 26        | 118                 |

| 55-64       | 2         | 120                 |

(b) The cumulative frequency curve starts from the origin (0, 0) and moves upward and to the right, indicating that the mass of logs is increasing as we move right on the x-axis.

To construct the cumulative frequency table for the distribution of masses of 120 logs of wood, we need to add up the frequencies of each class and all the classes before it.

(b) To draw a cumulative frequency curve, we plot the cumulative frequency values against the upper class limits. The plot shows how the cumulative frequency increases with the increase in the mass of the log.

We use the same class intervals as in part (a):

- x-axis = Masses (kg)

- y-axis = Cumulative frequency

To plot the cumulative frequency curve, we mark the upper limit of each class on the x-axis, and its corresponding cumulative frequency on the y-axis. Then, we join the plotted points with a smooth curve, as shown in the graph.

The steeper the curve, the more rapid the increase in cumulative frequency, indicating that a larger number of logs fall in higher mass categories.

In the given distribution, the plot of the cumulative frequency curve shows that the majority of logs fall in the mass range of 25-34 kg, closely followed by the range of 45-54 kg.

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Answer:

y = 8/5 x + 24

Explanation:

To get an equatio for the best line of fit, we will have to loacte two coordinate points on the line first. Using the coordinate points (10, 40) and (35, 80)

The general equation of a line is expressed as y = mx+b

m is the slope

b is the y intercept

Get the slope m

m = y2-y1/x2-x1

m = 80-40/35-10

m = 40/25

m = 8/5

Get the y-intercept

Substitute m = 8/5 and the point (10,40) into the equation y = mx+b

40 = 8/5(10) + b

40 = 16+b

b = 40 - 16

b = 24

Get the required equation using y = mx+b

y = 8/5 x + 24

This gives the required equation

Answer: .416666667

Step-by-step explanation: Take 80 and divide it by 192.0= .416666667