Compare the kinetic energy of a 21,000 kg truck moving at 130 km/h with that of an 84.0 kg astronaut in orbit moving at 28,000 km/h.

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

Given the following the details;

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

\(Quantity \; of \; charge = \frac{Energy}{Electric \; potential}\)

Substituting the values into the formula, we have;

\(Quantity \; of \; charge = \frac{40}{8}\)

Quantity of charge = 5 Coulombs

Therefore, the quantity of charge must be 5 Coulombs.

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\(\boxed{\sf E=QV}\)

\(\\ \rm\longmapsto Q=\dfrac{E}{V}\)

\(\\ \rm\longmapsto Q=\dfrac{40}{8}\)

\(\\ \rm\longmapsto Q=5C\)

Hence total charge must be 5C.

Note:-

SI unit of charge is Coulomb (C)

Answer:

b

Explanation:

Bar magnets have two magnetic poles

Answer:d for apex

Explanation:

The velocity is 22 m/s while the acceleration is 12 m/s^2.

We know that the velocity can be obtained from the equation that have been given for the distance that is covered. We know that we have been given the distance that is covered as;  x = 20t + 6t^2

Then we know that;

Velocity = dx/dt = 20 + 12t

Velocity = 20 + 12(1) = 22 m/s

The acceleration can be obtained from;

Acceleration = d^2x/dt^2 = 12 m/s^2

Thus we have used the equation to obtain the velocity and the acceleration.

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Explanation:

The WORK required to stop the truck is equal to the initial Kinetic Energy of the truck  ( 1/2 m v^2)

1/2 mv^2   = 1/2 * 2000 * 30^2  = 900 000 J

Distance travelled in 10 seconds is

  d = vot  - 1/2 at^2      where a = 30 m/s / 10 s = 3 m/s^2

     = 30 (10) - 1/2 ( 3)(10^2) = 150 meters

Work = F * d

900 000 = F * 150

   F = 6000 N

Answer:

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

\(\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N\)

Thus, the net force over the body is:

\(F=(913.14N)\hat{i}+(274.87N)\hat{j}\)

Next, you calculate the magnitude of the force:

\(F=\sqrt{(913.14N)+(274.87N)^2}=953.61N\)

and the direction is:

\(\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°\)

9514 1404 393

Answer:

  0.2 m/s

Explanation:

The average velocity is the change in position divided by the change in time:

  (8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s

The boy's average velocity is 0.2 m/s.

Answer:

Velocity Has vector Quantity

Answer:

the same

Explanation:

Answer:

1- 66mL

2-16mL

3-7.8mL

Explanation:

they are numbered from left to right, and have the number of the values. Dont forget the measurements, because sometimes if they are forgotten, they are counted wrong.

Answer:

Irms =226A

Explanation:

The current is high because the total impedance is relatively low. Actually, plugging such a circuit into a 120-V outlet would most likely burn out the circuit elements

Answer:

70m/s²

Explanation:

we will use the first equation of Dalton to find it

Tina's speed as she passes David is 25.0 m/s, which is the same as David's speed. To solve this problem, we can use the kinematic equations of motion:

Position as a kinematic equations of time: x = x0 + v0t + (1/2)at^2

Final velocity as a function of time: v = v0 + at

First, let's find out how long it takes for Tina to catch up to David. We can use the second equation above to find the time it takes for Tina to reach David's speed:

v = v0 + at

25.0 m/s = 0 + 2.60 m/s^2 * t

t = 9.62 s

Now we can use the first equation to find how far Tina travels during that time:

x = x0 + v0t + (1/2)at^2

x = 0 + 0 + (1/2)(2.60 m/s^2)(9.62 s)^2

x = 120.3 m

Therefore, Tina drives 120.3 meters before passing David. To find her speed as she passes David, we can use the second equation above:

v = v0 + at

v = 0 + 2.60 m/s^2 * 9.62 s

v = 25.0 m/s is the final velocity.

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Answer:

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Explanation:

In order to solve this problem we will use the grating equation:

mλ = d Sin θ

where,

m = order = 3

λ = wavelength of light = ?

d = slit separation = 2 μm = 2 x 10⁻⁶ m

θ = angle = 60°

Therefore,

(3)λ = (2 x 10⁻⁶ m)Sin 60°

λ = 1.732 x 10⁻⁶ m/3

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Answer and Explanation:

There is no probability of obtaining such a circuit of closed track current carrying wire whose field of magnitude displays i.e.  \(B \alpha \frac{1}{r^2}\)

The magnetic field is a volume of vectors

And \(\phi\ bds = 0\). This ensures isolated magnetic poles or magnetic charges would not exit

Therefore for a closed path,  we never received magnetic field that followed the \(B \alpha \frac{1}{r^2}\) it is only for the simple current-carrying wire for both finite or infinite length.

The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.

The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:

Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s

= -10.0 g·cm/s + 2800.0 g·cm/s

= 2790.0 g·cm/s

Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:

Total momentum after collision = (0.50 g + 70.0 g) × v

= 70.50 g × v

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":

Total momentum before collision = Total momentum after collision

2790.0 g·cm/s = 70.50 g × v

v = 2790.0 g·cm/s ÷ 70.50 g

v = 39.5 cm/s

This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.

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Answer:

B. iron ore

Explanation:

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Answer:

Parsley is an herb.

Explanation:

Both herbs and spices come from plants but herbs are the fresh part of the plant while spice is the dried root, dried stalk, seed or dried fruit of the plant and is almost always dried not fresh.

The change in surface area of Gaussian surface with radius (r) is 8πr.

The electric field experienced by a charge is calculated as follows;

\(E = \frac{Q}{4\pi \varepsilon_o r^2}\)

where;

The electric field reduces by a factor of \(\frac{1}{r^2}\)

The surface area of a sphere is given as;

\(A = 4\pi r^2\)

\(\frac{dA}{dr} = 8\pi r\)

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

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Answer:

    v = 0

Explanation:

This is a relative velocity exercise, using the Galilean transformation

          v = v₁ + v '

where v₁ is the speed of the object with respect to the mobile system, v' the speed of the mobile system and v the speed of the object with respect to the fixed system.

We can also write this expression with subscripts

        v_at = v_am + v_mt

where v_at   velocity with respect to the ground

          v_am  speed respecting the mobile system

          v_mt   velocity of the mobile system with respect to the earth

System a mobile is the train with speed v ’= 50 mile / h

the speed of the ball with respect to the mobile system is v = - 50 mile / h

the velocity of the ball with respect to the fixed system is

         v = 50 -50

         v = 0

The magnitude of the force on the tooth is approximately 0.022 N.

To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.

First, we need to calculate the strain (ε) of the stainless-steel wire.

Strain is defined as the change in length divided by the original length:

ε = ΔL / L₀

Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:

\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)

Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.

Stress is defined as the force per unit area:

σ = E * ε

Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:

σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²

Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:

F = σ * A

The cross-sectional area (A) can be calculated using the formula for the area of a circle:

A = π * (d/2)²

Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:

\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)

Finally, we can calculate the force:

\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)

Therefore, the magnitude of the force on the tooth is approximately 0.022 N.

Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.

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Answer:

Increase in length, e = 61.59 * 10⁻²m

The closest value from the options is option D. 61.65 x 10-2m

Explanation:

Young Modulus = stress/strain = (F/A)(/e/L) = F * L/A * e

where F = force; L = original length; A = area; e = increase in length

making e subject of formula;  \(e = F * L/Y * A\)

Also force, F =  mass * acceleration due to gravity;

mass = density * volume = density * area * length = ρ * A * L

Therefore, force, F = ρ * A * L * g

e = ρ *A * L* L * g/Y * A = ρgL²/Y

density = 0.7 gcm⁻³ = 0.7 * 10³ kgm⁻³; g = 9.8 ms⁻²

e = {0.7 * 10³ kgm⁻³ * (6.7 m)² * 9.8 ms⁻²}/5 * 10⁶ Nm²

e = 61.59 * 10⁻² m

The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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False. E=hf, where h is Planck's constant, c is the speed of light, f is the frequency, and is the wavelength; and E=hc/, where E is directly proportional to frequency and inversely proportional to wavelength.

With respect to the wavelength of the radiation, photon energy is inversely proportional.

Two formulas can be used to determine a photon's energy: E = h f is a formula that can be used if the photon's frequency is known. This equation, sometimes known as Planck's equation, was created by Max Planck.

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The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO

When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.

When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.

            At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.

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alpha is the excess return on an investment after adjusting for market related volatility and random fluctuations.

beta is a measure of volatility relative to a benchmark ,such as the S&P 500.

Explanation:

alpha and beta are two different parts of an equation used to explain the performance of stocks and investments funds. But in maths alpha and beta is the Greek alphabet