Work done is given by
dw=Pdv, w=∫₁²(NkT/V-Nb)dv
The amount of work is 5708.00923 J.
What sort of moles are cancerous?border that is erroneous Frequently, the edges are jagged, serrated, or blurry in outline. It's possible for the pigment to penetrate the nearby skin. unbalanced color: There could be various tones of tan, brown, and black. There may also be white, black, red, pink, and blue patches.
What is the quickest method for eliminating moles?Using traps or bait with in spring or fall will increase your chances of successfully eliminating moles from your yard. The primary runway, or active runway, should be used for both goods. Usually, these are the vertical tunnels in your grass or the ones that round the outside of your property.
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During a chemical reaction, Bromine (Br) would be expected to
o gain 1 valence electron to have a full octet
O lose 1 valence electron to have a full octet
O gain 7 valence electrons to have a full octet
o lose 7 valence electrons to have a full octet
Answer:
During a chemical reaction, Bromine (Br) would be expected to gain 1 valence electron to have a full octet.
Explanation:
In the periodic table the elements are ordered so that those with similar chemical properties are located close to each other.
The elements are arranged in horizontal rows, called periods, which coincide with the last electronic layer of the element. That is, an element with five electronic shells will be in the fifth period.
The columns of the table are called groups. The elements that make up each group coincide in their electronic configuration of valence electrons, that is, they have the same number of electrons in their last.
The elements tend to resemble the closest noble gases in terms of their electronic configuration of the last layer, that is, having eight electrons in the last layer to be stable.
Bromine belongs to group 17 (VII A), which indicates that it has 7 electrons in its last shell. So bromine requires more energy to lose all 7 electrons and generate stability, than it does to gain 1 electron and fill in 8 electrons to be stable. So:
During a chemical reaction, Bromine (Br) would be expected to gain 1 valence electron to have a full octet.
Tariah is riding on her bike at 4m/s (North). If she accelerates at a rate of 1.5 m/s^2 for 2 s, what is her final velocity?
ANSWER:
7 m/s
STEP-BY-STEP EXPLANATION:
Given:
Initial velocity (u) = 4 m/s
Acceleration (a) = 1.5 m/s^2
Time (t) = 2 s
We can calculate the final velocity using the following formula:
\(v=u+a\cdot t\)We replace and calculate the value of the final velocity:
\(\begin{gathered} v=4+2\cdot1.5 \\ v=4+3 \\ v=7\text{ m/s} \end{gathered}\)The final velocity is equal to 7 m/s.
Energy Representations 3: Power and Efficiency:Question 2
This Sankey diagram shows the energy transformations
in a mixer used to stir ingredients together. If the
percentage of non-useful energy produced by the mixer
is 30%, what is the energy efficiency of the mixer?
Select one:
10%.
70%.
100%.
30%.
Electric energy
Sound
Thermal energy
energy
Kinetic energ
The energy efficiency of the mixer is 70%.
The Sankey diagram shows the amount of energy absorbed, the amount of useful energy, and the amount of non-useful energy.
Input energy = output energyInput energy = useful energy + non-useful energyInput energy (I) = useful energy (U) + waste energy (W)The efficiency of a device
η = (U/I) × 100%
Input energy is always 100%I = U + W
100% = U + 30%
U = 100% - 30%
U = 70%
The efficiency of the mixer
η = (U/I) × 100%
η = (70%/100%) × 100%
η = (7/10) × 100%
η = 70%
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True or False – All transformations fit the Law of Conservation of Energy.
Answer:
The correct answer is true.
Compare resistance of electrical flow through wires to the resistance of water flow in a pipe. How are they similar?
Answer:
Resistance to the flow of electricity in wires and resistance to the flow of water in pipes are similar in several ways:
Both are affected by the size of the conductor: In both cases, the resistance to flow is affected by the size of the conductor. A larger diameter wire or pipe will offer less resistance to the flow of electricity or water than a smaller diameter one.
Both are affected by the length of the conductor: The resistance to flow also increases with the length of the conductor. A longer wire or pipe will offer more resistance to the flow of electricity or water than a shorter one.
Both are affected by the material of the conductor: Different materials have different resistances to flow. In electrical wires, metals are commonly used as they have low resistance. In pipes, materials such as copper, plastic, or steel may be used depending on the specific application.
Both can be reduced by minimizing obstructions: Resistance to flow can be reduced in both cases by minimizing obstructions in the path of the flow. In pipes, for example, the use of smooth inner walls and proper pipe bends can help reduce resistance. In electrical wires, minimizing the number of connections and using high-quality connections can help reduce resistance.
Overall, resistance to flow is a fundamental concept that applies to the flow of electricity and water, and the factors affecting resistance are similar in both cases.
Using the mass of the HSR (400 tons), calculate the velocity and the kinetic energy of the HSR if it travelled a distance of 180 km in just 1h 30min minutes.
Answer:the velocity and the kinetic energy of the HSR if it travelled a distance of 180 km in just 1h 30min minutes.
In your answer, explain how can you know if the HSR has more kinetic energy. How can kinetic energy be transferred or transformed?
Explanation:suiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
The kinetic energy of the given mass is 2173 kJ. The energy of an object or body due to its movement is called kinetic energy.
What is kinetic energy?It is the energy of an object or body due to its movement. It can be calculated by the formula,
\(KE = \dfrac 12 mv^2\)
Where,
\(m\) - mass = 400 tons = 400000 kg
\(v\) - velocity
First, calculate the velocity.
\(v = \rm \dfrac {180 \km}{1.5 \ hours}\\\\v = 12 km/h\\\\v = 3.3 m/s\)
Now, put the values in the formula,
\(KE = {\rm \dfrac 12 400000\ kg \times (3.3 \ m/s)^2}\\\\KE = 2178000 {\rm \ kg .m^2/s^2}\\\\KE = 2173\rm \ kJ\)
Therefore, the kinetic energy of the given mass is 2173 kJ.
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whose responsibility is it when someone commits a criminal act.
Answer:
police
Explanation:
the cart of mass 10 kg shown aboe moves without frictional loss on a level table. a 10 n force pulls on the cart horizontally to the right. at the same time a 30 n force at an angle of 60 degrees above the horizontal pulls on the cart to the left. what is the magnitude of the horizontal acceleration on the cart?
1.8 m/s² is the magnitude of the horizontal acceleration on the cart
F = ma
10N – (30Ncos60º) = (10kg)a
a=1.8 m/s²
Acceleration refers to any process where velocity changes. There are only two ways to accelerate: either by speeding up your acceleration or by reversing your acceleration. Because velocity consists of both a speed and a direction, this is the case.
You cannot possibly be accelerating if you don't also change your direction and speed, regardless of how quickly you are moving. As a result, a jet does not experience acceleration even when moving at a high speed—in this case, 800 miles per hour—because its velocity is constant. After landing, the jet will begin to slow down and then suddenly stop.
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A student is investigating the affect of different salts on melting points. Four patches of ice of equal
size are roped off and a
different type of salt is poured on each, one receives table salt (NaCl), one
receives Calcium Chloride (CaCl2), one receives Potassium Carbonate (KCO3) and the fourth
receives inert sand instead. Each patch receivęs an equal amount of salt or sand. The student
measures the volume of ice remaining and subtracts it from the original volume of ice to see how
much melted away. What is a control variable in this experiment?
A. The size of the ice patches.
B. The type of salt applied to the ice.
C. The amount of ice that melted.
D. None of these.
Answer:
A. The size of the ice patches
Explanation:
In an experiment, the control variable also known as the CONSTANT is the variable that must be kept uniform or the same for all groups throughout the experiment in order not to influence the outcome of the experiment.
According to the experiment described in this question, the effect of different salts on melting points is investigated by a student. Sodium chloride (NaCl), Calcium Chloride (CaCl2), Potassium Carbonate (KCO3) and inert sand are the four types of salt used. The volume of the ice used and melted was finally measured. This means that the SIZE OF THE ICE PATCHES USED is the control variable of the experiment as the same size was used for all groups throughout.
Answer:
the size of the ice patches
Explanation:
HELP ASAP!!!
which statements below best describes colors, Check all that apply
black pigment is the absorption of red, green, and blue light.
black pignment is the reflection of red, green, and blue light
white light is the combination of red, green, and blue light
white pigment is the absorption of red, green, and blue light
Answer:
1)Black pigment is the absorption of red, green, and blue light.
3)White light is the combination of red, green, and blue light
Two airplanes leave an airport at the same
time. The velocity of the first airplane is
690 m/h at a heading of 68.5
◦
. The velocity
of the second is 590 m/h at a heading of 156◦
.
How far apart are they after 1.8 h?
Answer in units of m.
The distance between first airplane and second airplane after 1.8 hours of their departure is 1598.22 meters.
What is cosine formula for vector addition?The cosine formula for vector addition is -
|R|² = |A|² + |B|² + 2AB cosφ
Where - φ is the angle between vectors A and B.
Given is two airplanes that leave the airport at same time. The velocity of the first airplane is 690 m/h at a heading of 68.5°. The velocity of the second airplane is 590 m/h at a heading of 156°.
The length of the position vector of first airplane →
|OA| = velocity x time = 690 x 1.8 = 1242 miles.
The length of the position vector of second airplane →
|OB| = velocity x time = 590 x 1.8 = 1062 miles
Angle between vectors OA and OB →
φ = 156° - 68.5° = 87.5°
In the triangle ΔOAB, using the triangle law of vector addition, we get →
OA + AB = OB
AB = OB - OA
AB = OB + (- OA)
Now, using the formula for resultant of addition of two vectors →
AB² = (OB)² + (- OA)² + 2(OA)(- OB) cosφ
AB² = OB² + OA² + - 2(OA)(OB)cosφ
AB² = 11,27,844 + 15,42,564 - 2 x 1242 x 1062 x cos(87.5°)
AB² = 11,27,844 + 15,42,564 - 2 x 1242 x 1062 x 0.044
AB² = 26,70,408 - 1,16,072.352 = 25,54,335.648
AB = √25,54,335.648
AB = 1598.22 meters
Hence, the distance between first airplane and second airplane after 1.8 hours of their departure is 1598.22 meters.
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The diagram below shows the velocity vectors for two cars that are moving relative to each other.
From the frame of reference of car 1, what is the velocity of car 2?
Answer:
The answer is "\(5 \ \frac{m}{s} \ west\)"
Explanation:
\(\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\\)
velocity of car | respect to car :
\(\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\\)
\(=\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west\)
Answer:
70 m/s east
Explanation:
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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PLEASE HELPPPP!!!! I NEED THIS DONE IN UNDER 3 DAYS!
Answer:
Question 7 is "Weight force down is greater than the air drag"
Question 8 is "600 N"
Explanation:
Question 7: When looking at the forces acting on the skydiver it's important to look at what force is larger, in this case, it's the weight. If two forces are acting in opposite directions, then the body will move in the direction of the force that has a larger value, 735 N.
Question 8: When the question tells you that the forces should be balanced, it means that they should turn out to equal zero if you were to subtract the forces, or you can think of it as trying to get the side that has a smaller number to be equal to the number that is greater. Since the question specifically says the parachute will ADD drag to the equation, you solve this one by asking yourself "What number + 135 will equal 735?" This ends up being 600 N.
Hope this helps!
Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?
Answer:
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
Explanation:
According to Coulomb's law, the magnitude of force between two point object having change \(q_1\) and \(q_2\) and by a dicstanced is
\(F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)\)
Where, \(\epsilon_0\) is the permitivity of free space and
\(\frac{1}{4\pi\spsilon_0}=9\times10^9\) in SI unit.
Before dcollision:
Charges on both the sphere are \(q_1\) and \(q_2\), d=20cm=0.2m, and \(F_c=1.35\times10^{-4}\) N
So, from equation (i)
\(1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}\)
\(\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)\)
After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.
Charges on both the sphere are mean of total charge, i.e
\(\frac{q_1+q_2}{2}\)
d=20cm=0.2m, and \(F_c=1.406\times10^{-4}\) N
So, from equation (i)
\(1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}\)
\(\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}\)
\(\Rightarrow q_1+q_2=\pm5\times 10^{-8}\)
As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.
\(\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)\)
\(\Rightarrow q_1=5\times 10^{-8}-q_2\)
The equation (ii) become:
\((5\times 10^{-8}-q_2)q_2=6\times10^{-16}\)
\(\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0\)
\(\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}\)
From equation (iii)
\(q_1=2\times10^{-8}, 3\times10^{-8}\)
So, the magnitude of initial charges on both the sphere are \(3\times10^{-8}\) Coulombs\(=0.03 \mu C\) and \(2\times10^{-8}\) Colombs or \(0.02 \mu C\).
Considerion the nature of charges too,
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
when the parachute is fully open, the effective drag coefficient of the skydiver plus the parachute increases to 60.0 kg/m . what is the drag force fdrag acting on the skydiver immediately after she has opened the parachute?
The drag force acting on the skydiver immediately after she has opened the parachute is 588 N
since we are provided with a coefficient which is 60.0 kg/m, the problem we are dealing with is related to drag force which is The resistance offered by a liquid, like water or air, which is called the drag force, when an object moves through it. It acts in a direction inverse to the object’s movement. It is produced by the relative speed between the strong object and the liquid. Whether the object or liquid is moving, drag happens as long as there's a difference in their speeds. Since it is safe to move, drag tends to moderate the object. A successful way to diminish it is to change the shape of the object and make it streamline.
Here the drag force is equal to its weight,
F= mg = 60* 9.8 =588 N
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Distributive shock is the result of which of the following? - Pump failure - Poor vessel function - Low fluid volume - Rapid deoxygenation
Distributive shock is the result of poor vessel function.
Shock is a life-threatening medical condition that occurs when the body is not getting enough blood flow. Shock is a result of many underlying conditions that damage the circulatory system, decrease blood volume, or reduce the heart's pumping capacity. Distributive shock is one of the four types of shock.
Distributive shock is a type of shock that occurs as a result of poor blood vessel function. Distributive shock is characterized by a sudden drop in blood pressure, which results in a lack of oxygen and nutrients to vital organs and tissues.
The following three types of distributive shock are common:
Anaphylactic shockSeptic shockNeurogenic shockIn the body, the capillaries are responsible for delivering nutrients and oxygen to the cells while also removing waste materials. In distributive shock, the capillaries are dilated, causing blood to pool in the small veins and venules and leading to a sudden drop in blood pressure. This drop in blood pressure lowers oxygen and nutrient delivery to organs and tissues, resulting in organ failure, brain damage, and death.
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what force Pushes up on an airplane ?
Explanation:
As it flies, a plane is in the center of four forces. Lift (upward force) and thrust (forward push, provided by a propeller) get a plane into the air. Gravity and drag (air resistance, which is friction caused by air rubbing against the plane) try to pull the plane down and slow its speed.hope it helps
A wave was measured to have an energy of 3.810x1020J. What was the wavelength of
that EM wave?
Wavelength is the distance between successive crests (or troughs) of a wave.
Using the equation E = hf, we can calculate the frequency of the wave using the given energy.
E = hf
3.810x1020J = (6.626x10-34J·s)f
f = 5.741x1015Hz
Using the equation c = λf, we can calculate the wavelength of the wave using the calculated frequency.
c = λf
3.00x108m/s = λ(5.741x1015Hz)
λ = 5.21x10-7m.
Hence, the wavelength of that EM wave was λ = 5.21x10-7m.
What is Wavelength?
Wavelength is the distance between two successive crests (or troughs) of a wave. It is a measure of the length of a wave, and is usually measured in meters. Wavelength is an important concept in physics, especially in the fields of electromagnetism and optics, as it is related to the frequency and energy of a wave. Wavelengths can range from fractions of a nanometer to kilometers in size.
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Why do the interiors of saturn and jupiter contain large amounts of liquid metallic hydrogen?
The interiors of Saturn and Jupiter contain a large amount of large metallic hydrogen because liquid hydrogen transforms into liquid metallic hydrogen as one descends, reaching a depth of 12,000 kilometers as the radius of Jupiter is 71,000 kilometers the hydrogen is below the cloud layers.
Helium and hydrogen make up the majority of the atmospheres of Jupiter and Saturn. The hydrogen changes from a high-pressure gas to liquid hydrogen a few hundred kilometers below the cloud levels. It would take some fairly intense pressures to create this on Earth, but it is possible. It's a component of rocket fuel.
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if the steam engine does 2500 j of work and its thermal energy increases by twice as much, how much heat is produced by the steam engine
The amount of heat produced by the steam engine is J = 2500 J.
If the steam engine does 2500 J of work and its thermal energy increases by twice as much, the total change in thermal energy is 2 * \(2500 J = 5000 J.\)
According to the first law of thermodynamics, the change in thermal energy (ΔQ) is equal to the work done (W) plus the heat added (Q). Therefore, we can write the equation as follows:
\(\Delta Q = W + Q\)
Since the work done is 2500 J and the change in thermal energy is 5000 J, we can substitute these values into the equation:
\(5000 J = 2500 J + Q\)
Simplifying the equation, we find that the amount of heat produced by the steam engine is \(Q = 5000 J - 2500 J = 2500 J.\)
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simple machines are in a mousetrap
Answer:
A mousetrap makes use of a simple machine called a lever.
Explanation:
In a second-class lever the effort force is at the other end, with the load in the middle. In a third-class lever, the load is at the end and the effort force is between the fulcrum and the load. When you set the mousetrap, you are using a second-class lever. Sorry if I get this wrong. I am in 5th grade! ♥
The displacement of a car moving with constant velocity 9.5 m/s in time interval between 3 seconds to 5 seconds is given by odt. What is the displacement of the car during that interval in meters?
The displacement of a car moving with a constant velocity of 9.5 m/s in a time interval between 3 seconds to 5 seconds is 19 meters.
It given by the formula: Δx = vΔt where Δx = displacement v = velocity Δt = time interval Substituting the given values, we get:Δx = 9.5 m/s × (5 s - 3 s)Δx = 9.5 m/s × 2 sΔx = 19 m, the displacement of the car during the given interval is 19 meters.
The given formula is derived from the definition of velocity which is the change in displacement per unit time. Since the velocity of the car is constant, we can assume that its acceleration is zero. Therefore, the car is not changing its velocity, which means that the displacement during that interval is equal to the product of velocity and time.In this case, we are given the initial and final times, and we need to find the displacement during that time interval.
The difference between the two times is 2 seconds. Multiplying the velocity with the time interval, we get the displacement of the car. The unit of displacement is meter, which is the same as the unit of distance.
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A mother finds her daughter’s mug of hot cocoa on a table an hour after she had been drinking it. As the mother pours out the cocoa, she sees brown solids in the bottom of the mug. How can this be explained?(1 point)
The cocoa was mixed with hot water, but some cocoa settled as it cooled because the solubility went up.
All dissolved substances will come out of solution over time. If the mother waits long enough, then all of the powder will appear at the bottom of the mug.
The cocoa was mixed with hot water, but some cocoa settled as it cooled because the solubility went down.
This would only happen if too much cocoa powder was added in the first place, because the solubility should not change.
Answer:
The cocoa was mixed with hot water, but some cocoa settled as it cooled because the solubility went down.
Answer:
C
Explanation:
The ???? ,of an object is a vector that is directed toward
the center of the Earth.
The Weight is a vector whose magnitude is the product of the mass m of the object and the magnitude of the local gravitational acceleration. Its always directed toward the center of the Earth.
Define Eukaryote cells and Prokaryote cells
Answer:
Ekaryote cells
an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaea.
prokaryote cells
microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria
Because of a frictional force of 2.6 N, a force of 2.8 N must be applied to a
textbook in order to slide it along the surface of a wooden table. The book
accelerates at a rate of 0.11 m/s?.
a. What is the unbalanced force on the book?
b. What is the mass of the book?
(a) The unbalanced force will be "0.2 N".
(b) The mass of book "1.818 kg".
Unbalanced force and mass:Given:
Applied force = 2.8 NFrictional force = 2.6 NAcceleration = 0.11 m/s²(a) Total unbalanced force,
→ \(F_{net} = 2.8-2.6\)
\(= 0.2 \ N\)
(b) By applying Newton's second law,
→ \(F = ma\)
or,
→ \(m = \frac{F_{net}}{a}\)
By substituting the values,
\(= \frac{0.2}{0.11}\)
\(= 1.818 \ kg\)
Thus the above approach is correct.
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the ring systems around jupiter and saturn lay outside the planets respective roche limits true or false how do you know
False; the ring systems around Jupiter and Saturn are outside of the respective roche limits of those planets.
Why are Saturn's rings thought to be subject to the Roche limit?Roche Limit is inside the Ring. A planet's gravitational tidal effects can no longer keep an orbiting entity together at a certain orbital radius. The tidal forces pull the material apart, preventing it from forming into a single, huge entity inside this boundary.
Is there a ring system around Saturn?Saturn, the second-largest planet in our solar system, is situated six planets away from the Sun. Similar to Jupiter, Saturn is a gas giant with a sizeable globe that is mostly made of hydrogen and helium. Other planets also have rings, but none of them are as spectacular or complicated as Saturn's.
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Determine the required pressure differential for overbalance
drilling to a depth of 9000 ft and mud density is 12
ppg. Given that the pore pressure is 3800 psi. is this
overbalanced drilling? Why?
The required pressure differential for overbalance drilling to a depth of 9000 ft with a mud density of 12 ppg and a pore pressure of 3800 psi is 5200 psi. This indicates overbalanced drilling.
Overbalanced drilling refers to the practice of maintaining a higher drilling fluid pressure than the formation pore pressure to prevent wellbore instability and influxes of formation fluids. To determine the required pressure differential for overbalance, we can use the hydrostatic pressure equation:
\(\[ P_{\text{diff}} = \text{Mud Density} \times \text{Depth} \]\)
Given that the depth is 9000 ft and the mud density is 12 ppg (pounds per gallon), we can calculate the pressure differential as:
\(\[ P_{\text{diff}} = 12 \times 9000 = 108,000 \text{ psi-ft} \]\)
However, we need to convert the units from psi-ft to psi. Since 1 psi-ft is equivalent to 0.052 ppg, we can calculate the pressure differential as:
\(\[ P_{\text{diff}} = 108,000 \times 0.052 = 5,616 \text{ psi} \]\)
Comparing this with the pore pressure of 3800 psi, we can see that the required pressure differential for overbalance drilling (5616 psi) is higher than the pore pressure (3800 psi). Therefore, this drilling operation is considered overbalanced.
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What would be the magnitude and direction of the initial acceleration of an electron moving with velocity 2.88 x 105 m/s into the page at point P?
the magnitude and direction of the initial acceleration of an electron moving with velocity 2.88 x 105 m/s into the page at point P is 6.1 x 10^18 m/s²,
Given: Velocity (v) = 2.88 x 10^5 m/s.
The initial acceleration is unknown but needs to be determined.
The magnitude and direction of the initial acceleration can be determined using the right-hand rule. The right-hand rule states that if the fingers of the right hand are curled in the direction of the magnetic field lines, the thumb indicates the direction of the force on a positive charge. The force on a negative charge is in the opposite direction to that on a positive charge. This is known as the Fleming's left-hand rule.A negative charge moves in the direction opposite to the magnetic field lines. Therefore, the initial acceleration of an electron moving with a velocity of 2.88 x 10^5 m/s into the page at point P is given as:Initial acceleration = F/mWhere F is the force and m is the mass of the electron.Since the electron is moving into the page and the magnetic field is perpendicular to the page, the force acting on the electron will be perpendicular to both the velocity and magnetic field direction.Therefore, the direction of the initial acceleration of the electron will be perpendicular to the velocity and magnetic field direction.Using the right-hand rule, we can determine the direction of the force acting on the electron. The thumb of the right hand points in the direction of the force acting on a positive charge. Since an electron is negatively charged, the direction of the force acting on the electron will be opposite to the direction of the thumb of the right hand.The direction of the force acting on the electron is out of the page. Therefore, the direction of the initial acceleration of the electron is out of the page.The magnitude of the initial acceleration is given by:Initial acceleration = F/m = qvB/mwhere q is the charge on the electron, B is the magnetic field, and m is the mass of the electron.The direction of the force acting on the electron is perpendicular to both the velocity and magnetic field direction. Therefore, the angle between the velocity and magnetic field is 90°.Hence, sin(90°) = 1.
Therefore, the magnitude of the initial acceleration is given as:Initial acceleration = F/m = qvB/m = qvB/m x 1 = (1.6 x 10^-19 C) x (2.88 x 10^5 m/s) x (1.2 T) / (9.11 x 10^-31 kg)= 6.1 x 10^18 m/s² (approx.)
Therefore, the magnitude of the initial acceleration of an electron moving with a velocity of 2.88 x 10^5 m/s into the page at point P is 6.1 x 10^18 m/s², and its direction is out of the page.
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