Consider the analytic solution of the projectile problem described in Section 1.1.2. Write a MATLAB script that will prompt the user to enter the launch speed and angle,and will compute the peak height ,flight time, and horizontal distance travelled using the analytic equations.

The net displacement can be calculated by summing the three vectors.

15m, \(135^{0}\) have x = -7.5m and y = 7.5m

35m, \(40^{0}\) NW have x = -26,8m and y = 22.5m

20m, \(15^{0}\) NE have x = 19.3m and y = 5.2m

The the net displacement is x = -15m and y = 35.2m or 38.26m, \(23.07^{0}\) NW

To learn more about vector, click here https://brainly.com/question/18151035

#SPJ1

An archeologist is exploring a cave; she follows a secret passage 15 m, 135°, then 35 m, 40° NW. Finally, 20 m, 15° NE. The net displacement -15m and y = 35.2m or 38.26m,  NW.

The net displacement can be calculated by summing the three vectors.

15m,  have x = -7.5m and y = 7.5m

35m,  NW have x = -26,8m and y = 22.5m

20m,  NE have x = 19.3m and y = 5.2m

The the net displacement is x = -15m and y = 35.2m or 38.26m,  NW

Displacement vectors have a length or magnitude equal to the shortest distance between a start point and an end point. Adding vectors to get a net displacement requires separating them by dimensions, and . And displacement vectors, like all vectors, have both a magnitude, or length, and a direction.

Learn more about net, here:

https://brainly.com/question/29589154

#SPJ1

Answer:

156.28m

Explanation:

Given;

His displacement is 900 m 80° North of west

Let North and South represent y axis and west east represent axis.

the x component of his displacement vector can be written as;

dx = dcosθ

Where d is the resultant displacement = 900m

θ is the angle with the x axis = 80°

Substituting the values;

dx = 900cos80°

dx = 156.2833599002 m

dx = 156.28 m

the x component of his displacement vector is 156.28m

Answer:

A Peak

B Period

C 1/2 Period

D Trough

E Period

F 1/2 Period

Explanation:

Science

Answer:

23 cm from the mirror

Explanation:

Emily needs to add 0.108 kg of ice to the hot tea.

1. Determine the heat lost by the hot tea. We can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Q_lost = (0.250 kg) * (4186 J/kg·°C) * (99.0°C - 8.0°C)

2. Determine the heat gained by the ice as it melts and reaches the final temperature.

Q_gained = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

3. Since the energy lost by the tea is equal to the energy gained by the ice, we can set up an equation:

Q_lost = Q_gained

4. Substitute the values and solve for m_ice, the mass of ice.

(0.250 kg) * (4186 J/kg·°C) * (99.0°C - 8.0°C) = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

5. Simplify and solve the equation:

(0.250 kg) * (4186 J/kg·°C) * (91.0°C) = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

(955085 J) = (m_ice) * (334000 J/kg) + (m_ice) * (33488 J)

(955085 J) = (m_ice) * (367488 J)

m_ice = (955085 J) / (367488 J)

m_ice ≈ 0.108 kg

Therefore, Emily needs to add approximately 0.108 kg of ice to the hot tea to reach a final temperature of 8.00 degrees Celsius.

For more such questions on ice, click on:

https://brainly.com/question/20534573

#SPJ8

Answer: The pressure of the solid on the surface depends on the area of contact. The greater the force or the smaller the area the greater the pressure.

The minimum force (Fmin) required to move the block up the ramp is 12.7 N.

Mass of the block (m) = 3.3 kg

Angle of the ramp (θ) = 37°

Coefficient of friction between the block and the ramp (μg) = 0.44

Coefficient of kinetic friction between the block and the ramp (uk) = 0.30

Step 1: Resolve the forces acting on the block.

The weight of the block (mg) can be resolved into two components:

- The force acting parallel to the incline (mg*sinθ)

- The force acting perpendicular to the incline (mg*cosθ)

Step 2: Calculate the force of friction.

The force of friction can be calculated using the equation:

Force of friction (Ff) = μg * (mg*cosθ)

Step 3: Determine the minimum force required.

To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.

Thus, the minimum force required (Fmin) is given by:

Fmin = Ff + Fapplied

Step 4: Substitute the given values and calculate.

Ff = μg * (mg*cosθ)

Fmin = Ff + Fapplied

Now, let's calculate the values:

Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))

Ff ≈ 12.717 N

Fmin = 12.717 N + Fapplied

Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.

To know more about friction, refer here:

https://brainly.com/question/13000653#

#SPJ11

The force needed to lift the load would be directed upwards, but the force delivered to the opposite end of the lever would be directed downwards towards the ground.

The mechanical advantage is defined as the load to effort ratio (MA).

In other words, utilising a lever offers you more force or power than the effort you put in. Levers are used to multiply force. A lever has a stronger mechanical advantage if the distance from the effort to the fulcrum is greater than the distance from the load to the fulcrum.

To know more about force visit:-

https://brainly.com/question/13191643

#SPJ1

Respuesta:

2 × 10⁴ V

Explicación:

Paso 1: Información provista

Paso 2: Convertir q a Coulomb

Usaremos el factor de conversión 1 C = 10⁹ nC.

4 nC × 1 C/10⁹ nC = 4 × 10⁻⁹ C

Paso 3: Calcular el potencial eléctrico (V) de la esfera

Usaremos la siguiente fórmula.

V = W/q

V = 7 × 10⁻⁵ J/4 × 10⁻⁹ C = 2 × 10⁴ V

Answer:

bacteria like

virus

The  Energy of the a high-energy neutron  be 940.51 MeV.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of neutron: m₀ = 939.6 MeV/c².

a high-energy neutron is travelling at a speed of 18 million m/s

v = 1.8 × 10⁷ m/s.

Hence, Energy of the neutron be  = m₀c²/√(1- v²/c²) = 940.51 MeV.

Learn more about speed here:

https://brainly.com/question/28224010

#SPJ1

Answer: D  Medium B is denser than Medium A because light bends more in Medium B.

Explanation: The more the light bends the less energy it has

B. Good cleave.  A good cleave is required to obtain minimal loss from a prepolished /splice connection. A prepolished/splice connection is a type of fibre optic connector .

With a prepolished ferrule that provides for rapid and uncomplicated fibre optic cable field terminations. Typically, the ferrule is pre-polished at the manufacturer to achieve a good surface smoothness and reduced insertion loss. Nonetheless, a good cleave is required to obtain low loss in the field. Cleave is the technique of cutting a fibre optic cable using a precision tool to create a smooth, flat endface perpendicular to the fiber's axis. A proper cleave guarantees that the fibre endface is devoid of imperfections or abnormalities that might scatter light and increase insertion loss.

learn more about Cleave  here:

https://brainly.com/question/28148910

#SPJ4

To estimate the air density in kg/m^3 given the air temperature of 70 degrees F and barometric pressure of 15.5 lbf/in^2 in Narragansett, Rhode Island, we can use the ideal gas law.

The air density can be calculated by converting the temperature to Kelvin and the pressure to Pascals, and then applying the ideal gas law equation.

To begin, we need to convert the temperature from Fahrenheit to Kelvin. The Kelvin temperature scale is used in scientific calculations, and the conversion is done by adding 273.15 to the temperature in Celsius. In this case, 70 degrees F is approximately 21.1 degrees Celsius, so adding 273.15 gives us a temperature of approximately 294.25 Kelvin.

Next, we need to convert the barometric pressure from pounds per square inch (lbf/in^2) to Pascals (Pa). One atmosphere is approximately equal to 101,325 Pascals. To convert from pounds per square inch to Pascals, we can use the conversion factor of 6894.76 Pascals per square inch. Therefore, the barometric pressure of 15.5 lbf/in^2 is approximately equal to 106,686.38 Pascals.

Now, we can apply the ideal gas law equation, which states that the density (ρ) of a gas is equal to the pressure (P) divided by the product of the gas constant (R) and the temperature (T). The gas constant R is approximately 8.314 J/(mol·K). However, since we are interested in air density in kg/m^3, we need to convert the units. The molar mass of air is approximately 28.97 g/mol, so we can use the ideal gas law equation with the appropriate units to calculate the air density in kg/m^3.

By substituting the values into the equation, we have:

ρ = (P / (R * T)) * (M / V)

Where ρ is the air density, P is the pressure, R is the gas constant, T is the temperature, M is the molar mass of air, and V is the volume.

With the given temperature of 294.25 K and barometric pressure of 106,686.38 Pascals, we can calculate the air density in kg/m^3 using the ideal gas law equation.

Learn more about ideal gas law here:

brainly.com/question/30458409

#SPJ11

Since the man raises his body a vertical distance 0.63m to go from stage 1 to stage 2, the work done by the man is 493.92 J

Work done is the force times distance moved in the direction of the force.

It is given mathematically by W = Fd where

Since the the man raises his body a vertical distance 0.63m to go from stage 1 to stage 2, the workdone here is workdone against gravity. This is given mathematically by W = mgh where

Given that the man moves 0.63 m from stage 1 to stage 2, we have that

Substituting the values of the variables into the equation, we find the work done by the man. So,

W = mgh

W = 80 kg × 9.8 m/s² × 0.63 m

W = 493.92 kgm²/s²

W = 493.92 J

So, the work done by the man is 493.92 J

Learn more about work done here:

https://brainly.com/question/25816840

#SPJ1

Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

\(R_{t} = 341.7 \: \Omega\)

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

\( R' = R_{1} + R_{2} + R_{3} \)

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.  

Entonces:

\( R' = 3R \)

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)

\( R'' = \frac{3}{4}R \)

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)

Esta resistencia está ahora en paralelo con R₇, entonces:

\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)

\( R'''' = \frac{11}{15}R \)

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

\(V-i_{1}R-i_{3}R=0\) (1)

Malla 2

\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)

Malla 3

\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)

Recordemos tambien que:

\(i_{1}=i_{2}+i_{3}\) (4)

\(i_{2}=i_{4}+i_{5}\) (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

\(i_{1}=3/13\: A\)

\(i_{2}=4/65\: A\)

\(i_{3}=11/65\: A\)

\(i_{4}=1/65\: A\)

\(i_{5}=3/65\: A\)

Finalmente:

Pudes aprender mas de mallas aquí:

https://brainly.lat/tarea/11593276

A) Minimum recommended spiral parameter: 150.03m.

b) Distance P: 150.03m.

c) Distance Q: 4.122m.

d) Angle Φs: 16°30'14.0".

e) Distance Tc: 150.03m.

a) Calculation for the minimum recommended spiral parameter:

Design radius (R) = 300 m

Maximum superelevation (e_max) = 0.06 m/m

Spiral Parameter (A) = (R + e_max) / 2

A = (300 m + 0.06 m/m) / 2

A ≈ 150.03 m

b) Calculation for the distance P:

Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.

P ≈ 150.03 m

c) Calculation for the distance Q:

Distance Q represents the length of the circular curve. It is given by the formula:

Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)

Deflection angle at Point of Intersection = 16°30'14.0"

Converting the angle to decimal degrees:

16° + (30'/60) + (14.0"/3600) = 16.504°

Q = 16.504° / (360° / D)

Q ≈ D / 21.814

Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.

Q ≈ 90° / 21.814

Q ≈ 4.122 m

d) Calculation for the angle Φs:

The angle Φs is the deflection angle at the Point of Intersection.

Φs = 16°30'14.0"

e) Calculation for the distance Tc:

Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.

Tc ≈ 150.03 m

learn more about superelevation Here:

https://brainly.com/question/29679195

#SPJ4

We have a 180-n, 5.0-m ladder leaning up against a frictionless glass wall. The angle formed between the ladder and the ground is 53.1 degrees. So, the coefficient of static friction is 0.101.

we need to determine the forces acting on the ladder and use these forces to calculate the coefficient of static friction between the ladder and the ground.

First, let's consider the forces acting on the ladder. The weight of the ladder is 180 N, and the weight of Dr. Harbison is 800 N. These two forces act vertically downward on the ladder. The ladder is leaning against the glass wall at an angle of 53.1 degrees, so there is also a horizontal force acting on the ladder due to the ladder's weight. This horizontal force is equal to the weight of the ladder times the sine of the angle between the ladder and the vertical, or

(180 N) (sin 53.1 degrees) = 159 N.

Now let's consider the forces acting on the ground. The weight of the ladder and Dr. Harbison is acting vertically downward on the ground, and there is also a horizontal force acting on the ground due to the ladder's weight. This horizontal force is equal to the weight of the ladder times the cosine of the angle between the ladder and the vertical, or

(180 N)(cos 53.1 degrees) = 99 N.

The coefficient of static friction is defined as the ratio of the force of friction to the normal force. In this case, the normal force is the weight of the ladder and Dr. Harbison acting on the ground, or 980 N. The force of friction is the force that acts horizontally on the ground to balance the horizontal force acting on the ladder.

To find the coefficient of static friction, we can set up the following equation:

coefficient of static friction = force of friction / normal force

Substituting in the values we have calculated, we get:

coefficient of static friction = 99 N / 980 N

Solving this equation gives us a coefficient of static friction of approximately 0.101. This means that the ground needs to have a coefficient of static friction of at least 0.101 with the ladder in order for the ladder to not slip.

To know more about static friction please refer: https://brainly.com/question/13000653

#SPJ4

The electrical power generated by a residential solar panel array with a surface area of 457ft² is 6580.8 watts.

The commercial solar panel generates about 0.10 W/in². To find the electrical power generated by a residential solar panel with a surface area (S) of 457 ft²  we need to convert the unit from ft² to in², as follows:

\( S = 457 ft^{2}*\frac{144 in^{2}}{1 ft^{2}} = 65808 in^{2} \)

Then, the electrical power generated is:

\( P = \frac{0.10 W}{in^{2}}*65808 in^{2} = 6580.8 W \)

Therefore, the electrical power generated by the residential solar panel is 6580.8 W.

You can learn more about electric power here: https://brainly.com/question/16641884?referrer=searchResults

I hope it helps you!  

a)The angular frequency when the current amplitude be equal to 1/3 of its maximum possible value is ω₁ = 64.752 krad/s.

b) The current amplitude and voltage amplitude across each element is

I =0.09333A

Vr = 11.667V

Vl = j9.06496V

Vc =-j57.6353 V

Angular frequency measures how quickly an object oscillates with respect to time.

25nF = j40M/ω

a) jω(1.5m H) =j4M/ω

ω =163.2993 krad/s

Imax =35/125 =0.28A

0.009333 =35 /[125+jω(1.5m) - j40M/ω]

(125)² +[(15mω₁) - 40m/ω₁]² = 140625

15mω₁ ²-3535ω₁ - 40m =0

ω₁ = 64.752 krad/s

b) I =0.09333A

Vr =0.09333 x 123 = 11.667V

Vl = I(jω₁ x 1.5 m) = j9.06496V

Vc =-j57.6353 V

Learn more about angular frequency.

https://brainly.com/question/14103673

#SPJ4

Answer:

1/8

Explanation:

2R is the same as 1D, so you are a full diameter above yhe earth. The diameter of the earth is 12,742km, space starts at 100km so it probably isn't a third or a quarter. it is most likely an 1/8 or 1/9. if I had to guess it would be 1/8

The answer for (iv) is;

E.M.F of the battery refers to the chemical energy in the battery that is being converted into electrical energy for the flow of electrons to carry current in a circuit.

Big Bang, what sort of instrument would it be best to use: gravity.

The force of attraction between any two objects in the universe is known as gravity or gravitational force.

The mass of the object and the square of the distance between them determine the force of attraction. The weakest known force in nature, it is by far. There are only two factors that matter when discussing the gravitational force between two objects: mass and distance.

The square of the distance between two things has an inverse relationship with the force of gravity, which depends directly on the masses of the two items. The best theories of string theory propose that gravity is so weak because, in contrast to other forces, it may enter and exit these extra dimensions. We only get to taste a tiny bit of gravity's tremendous power.

Learn more about gravity herebrainly.com/question/10470988

#SPJ4.

Thus, an amplitude of 0.69 meters is required for objects to begin escaping contact with the ground during an earthquake with a frequency of 0.60 Hz.

An earthquake-produced surface wave can be approximated by a sinusoidal transverse wave, with a frequency of 0.60 Hz, which is typical for earthquakes.

To determine the amplitude needed for objects to begin leaving contact with the ground, we must ensure that the acceleration (a) of the wave is greater than the acceleration due to gravity (g), which is approximately 9.81 m/s².

The equation for the acceleration of a sinusoidal wave is:

a = Aω²

where A is the amplitude, and ω is the angular frequency. The angular frequency can be calculated using:

ω = 2πf

where f is the frequency (0.60 Hz). Substituting the value, we get:

ω = 2π(0.60) ≈ 3.77 rad/s

Now, we can set the acceleration (a) equal to g:

Aω² = g

Substituting ω and g into the equation, we can solve for the amplitude (A):

A(3.77)² = 9.81

A ≈ 0.69 m

Therefore, an amplitude of approximately 0.69 meters is needed for objects to begin leaving contact with the ground during an earthquake with a frequency of 0.60 Hz.

Know more about the sinusoidal transverse wave

https://brainly.com/question/14599236

#SPJ11

Answer:

The angular velocity after the children jump off is approximately 1.4 rad/s

Explanation:

The given parameters are;

The masses of each child, m₁, and m₂ = 60 kg

The mass of the merry-go-round, m₃ = 140 kg

The initial angular velocity, \(\omega_i\) = 0.75 rad/s

The angular velocity after the children jump off = \(\omega_f\)  

According to the principle of conservation of angular momentum

The angular momentum = I × ω

The moment of inertia, I = m × R²

The total initial angular momentum = \(I_i \times \omega_i = m_i \times R^2 \times \omega_i\)

The total angular momentum after the children jump off = \(I_f \times \omega_f = m_f \times R^2 \times \omega_f\)

The initial mass, \(m_i\) = m₁ + m₂ + m₃ = 60 kg + 60 kg + 140 kg = 260 kg

The final mass, \(m_f\) = m₃ = 140 kg

According to the principle of conservation of linear momentum, we have;

\(I_i \times \omega_i\) = \(I_f \times \omega_f\)

Therefore;

260 kg × R² × 0.75 rad/s = 140 kg × R² × \(\omega_f\)

∴ \(\omega _f\) = (260 kg × R² × 0.75 rad/s)/(140 kg × R²) = 1.39285714 rad/s. ≈ 1.4 rad/s

The angular velocity after the children jump off, \(\omega _f\) ≈ 1.4 rad/s.

The correct option is e.

The Keck telescopes are twin telescopes that have a mirror assembly made up of 36 smaller hexagonal mirrors working together as they used active optics technology. The correct answer is option e.

They were able to combine the advantages of a refracting telescope and a reflecting telescope. They used the active optics technology to overcome the difficulties that would otherwise be faced when creating a mirror larger than 10 meters. The Keck telescopes were the largest in the world when they were completed.

They were the first instruments to employ a novel technique known as "segmented mirror technology," which allowed for the construction of mirrors up to 30 meters in diameter.

In addition, the Keck telescopes had a motorized drive system that allowed them to move smoothly, and their mountaintop location reduced atmospheric interference, allowing them to capture sharp images of deep space. Other large telescopes did not have these features.

To learn more about telescopes:

https://brainly.com/question/556195#

#SPJ11

Answer:

the number of protons.

Explanation:

the atomic number is the number of protons in the nucleus of an atom. the number of protons Define the identity of an element.