Consider the following sequences 71
(i) In (1+1)
(ii) e^/(n²+1);
(iii) √√n²+2n - 11.

Which of the above sequences is monotonic increasing?
A. (i) and (iii) only.
B. (i), (ii) and (iii).
C (i) only
D. (ii) and (iii) only.
E. (i) and (ii) only.

Answer:

Step-by-step explanation:

we will replace the expression -2b-a  with the values

-2(-2)-3=4-3=1

The probability is 0.96 that a randomly selected camper does not like to have a cookout, based on the given information and the complement rule of probability.

To determine the probability that a randomly selected camper does not like to have a cookout, we need to find the complement of the event C (the event that the camper likes to have a cookout).

Looking at the Venn diagram, we see that the probability of event C is 0.04 (represented by the intersection of circles C and A). Therefore, the probability of the complement of event C (not liking to have a cookout) is equal to 1 minus the probability of event C.

1 - 0.04 = 0.96

Hence, the probability that a randomly selected camper does not like to have a cookout is 0.96.

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The population size of mantis shrimp will be approximately 266 individuals after 5 years.

The intrinsic rate of increase is an essential concept in population biology. It is the rate at which a population is growing at a particular moment in time. The population size after a particular period can be calculated using the intrinsic rate of increase with the help of this formula:

Nt = N0e^(rt)

where Nt is the future population size, N0 is the initial population size, r is the intrinsic rate of increase, and t is the time in years.

The population size of mantis shrimp is 475 individuals and the intrinsic rate of increase is -0.10.

We can calculate the population size after 5 years using the above formula as follows:

Nt = N0e^(rt)

Nt = 475 * e^(-0.10 * 5)

Nt = 475 * e^(-0.50)

Nt ≈ 266

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Seema left 6/11 of the book for reading over the weekend.

To calculate the part of the book left for reading during the weekend, we need to subtract the part of the book Seema read during the weekday from the total book.

If Seema reads 5/11 of the book during the weekday, then:

This means 6/11 of the book is left for reading during the weekend. It is important to note that the fraction of the book read during the weekday and the fraction left for reading during the weekend add up to the total book. This means that 11/11 of the book will be read by Seema in total.

This question should be written as:

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Answer:

try 5

Step-by-step explanation:

Answer: 7x + 9w if you are just simplifying

Step-by-step explanation:

The probability that a randomly chosen string of seven hexadecimal digits has at least one repeated digit is approximately 1 - ((16 * 15 * 14 * 13 * 12 * 11 * 10) / 16^7).

The probability that a randomly chosen string of seven hexadecimal digits has at least one repeated digit can be calculated using the concept of probability. There are a total of 16 possible characters in hexadecimal system (0-9 and A-F) and for each of the seven digits, there are 16 possible choices. Therefore, there are a total of 16^7 possible strings of seven hexadecimal digits.

To calculate the probability of having at least one repeated digit, we need to calculate the number of strings that have no repeated digits and subtract it from the total number of possible strings.

The number of strings with no repeated digits can be calculated as follows:

- For the first digit, there are 16 possible choices
- For the second digit, there are 15 possible choices (since one digit has already been chosen)
- For the third digit, there are 14 possible choices
- And so on, until the seventh digit, for which there are 10 possible choices (since six digits have already been chosen)

Therefore, the number of strings with no repeated digits is:

16 x 15 x 14 x 13 x 12 x 11 x 10

To calculate the probability of having at least one repeated digit, we need to subtract this number from the total number of possible strings and divide by the total number of possible strings:

1 - (16 x 15 x 14 x 13 x 12 x 11 x 10) / (16^7)

This gives us the probability that a randomly chosen string of seven hexadecimal digits has at least one repeated digit.

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Answer:

C. y = -7x - 11

Step-by-step explanation:

slope intercept form is y=mx+b

where m is the slope and b is the y-intercept

so slope is rise/run, and by the line shown in the graph, we can see that it's a negative slope as it's going down from left to right.

the rise is 7 (from one point to the other, up and down)

and the run is 1 (left and right)

from that, we get -7 as the slope.

We then find "b" which is the y-intercept, and we can see that the y-intercept is going to be under the x-axis, which means it's negative. From that, we can assume it's -11.

so we get y = -7x - 11

In the given triangle value of \(x= 73.4\) units and \(y= 46.2\) units ( round to nearest tenth)

" Triangle is defined as the two dimensional geometrical shape with three vertices, three sides and three angles enclosed in it."

Formula used

Pythagoras theorem

(Hypotenuse)² = (adjacent side)² + (perpendicular side)²

\(tan\theta = \frac{perpendicular side}{adjacent side}\)

According to the question,

In the given triangle,

Hypotenuse \(= x\)

Perpendicular side \(= y\)

Adjacent side \(= 57\)

Value of \(\theta = 39\)

Substitute the value of the given triangle in the formula to get the missing values,

\(tan 39\°= \frac{y}{57} \\\\\implies 0.8098 = \frac{y}{57}\\\\\implies y = 57 \times 0.8098\\\\\implies y = 46.1586\)

\(\implies y= 46.2\) units (round to nearest tenth)

Substitute the value in the Pythagoras theorem we get,

\(x^{2} = (46.2)^{2} +(57)^{2} \\\\\implies x^{2} = 2134.44 + 3249\\\\\implies x = \sqrt{5383.44} \\\\\implies x = 73.37\)

\(\implies x = 73.4\) units (round to nearest tenth)

Hence, In the given triangle value of \(x= 73.4\) units and \(y= 46.2\) units ( round to nearest tenth)

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Answer:

12 2/8

Step-by-step explanation:

split 11 5/8 into 11 and 5/8

add 3/8 and 5/8 to make 1

add 11 to make 12

then and the 2/8

the complete answer is 12 and 2/8

Your answer is 12.25.

\(11\frac{5}{8} +\frac{3}{8} =12\\12+\frac{2}{8} =12.25\)

Answer:

part A: 4 batches of pancakes

part B: draw something this I think

Answer:

y = 42x

Step-by-step explanation:

since it is linear it is proportional

using y = mx + c where m is the gradient

working out the gradient pick any two coordinates, I'll use (6, 252) and (12, 504)

\(gradient \: = \frac{change \: in \: y}{change \: in \: x} \)

\( gradient = \frac{504 - 252}{12 - 6} = 42\)

m = 42

input m = 42 in y = mx + c

the equation is now y = 42x + c

use one of the coordinates (6, 252) or (12, 504), I'm using (6, 252)

y = 42x + c where y = 252 and x = 6, solving for c:

252 = (42 × 6) + c

252 = 252 + c

c = 0

so the final equation is y = 42x

The statement t = (42, 56, 7) creates a tuple with the elements 42, 56, and 7, and assigns it to the variable t, allowing us to reference and use these values using the variable t.

The statement t = (42, 56, 7) associates the variable t with a tuple that contains the elements 42, 56, and 7. In Python, a tuple is an ordered collection of elements enclosed in parentheses. Each element in the tuple is separated by a comma.

By assigning the tuple (42, 56, 7) to the variable t, we can use t to reference and access the elements within the tuple. For example, t[0] would retrieve the first element, which is 42, t[1] would retrieve the second element, which is 56, and t[2] would retrieve the third element, which is 7.

In summary, the statement t = (42, 56, 7) creates a tuple with the elements 42, 56, and 7, and assigns it to the variable t, allowing us to reference and use these values using the variable t.

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Answer:

98.92

Step-by-step explanation:

8.75*2+74.95 = 92.45 x 1.07 = 98.92

The equation are given as

1. The equation is given as

The answer is

2. The equation is given as

The answer is

The given type of effect is called predictive.

What is linear regression?

When predicting a variable's value based on the value of another variable, linear regression analysis is used. The dependent variable is the one you're trying to forecast. The independent variable is the one that you are utilizing to forecast the value of the other variable.

Given:

A variable with a value of x1 x2 is added to the general linear regression model to account for two predictive variables, x1 and x2 and the effect on the response variable.

Linear regression is one of the most generally utilized predictive displaying methods.

It is spoken to by a condition = + + , where an is the catch, b is the slant of the line and e is the blunder term.

This condition can be utilized to predict the estimation of an objective variable dependent on a given predictor variable(s).

The predictor variable is the name given to an autonomous variable utilized in regression examinations.

The predictor variable gives data on a related ward variable concerning a specific result.

Hence, the given type of effect is called predictive.

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Answer:

54

Step-by-step explanation:

We'll call the number "ab".

From left to right, the value of this number will be \(10a+b\).

From right to left, the value of this number will ve \(10b+a\).

From the question,

\(10a+b=1.2(a+10b)\\10a+b=1.2a+12b\\8.8a=11b\)

For a and b to be whole numbers,

\(\left \{ {{a=5} \atop {b=4}} \right.\)

So the number is 54.

Answer:

a=2

Step-by-step explanation:

5+14a=9a-5 subtract 9a from both sides

5+5a=-5 subtract 5 from both sides

5a=-10 divide by 5 on both sides

a=-2

hope you do well :)

An equation is considered linear if it is in the form of y=mx+b where m is the slope of the equation and b is the y-intercept.

There are several properties possessed by linear equations, which are as follows:

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We have shown that every basis B of V.

To show that every basis of the dual space V* is the dual basis of a basis of V, we can make use of the concept of the double dual space.

Let V be a finite-dimensional vector space over the field F, and let B = {v₁, v₂, ..., vₙ} be a basis of V. We want to show that there exists a dual basis B* = {f₁, f₂, ..., fₙ} of V* such that fᵢ(vⱼ) = δᵢⱼ, where δᵢⱼ is the Kronecker delta.

First, we define the dual space V* as the set of all linear functionals from V to the field F. Each linear functional in V* takes a vector in V and maps it to a scalar in F.

Next, we define the double dual space V** as the set of all linear functionals from V* to the field F. In other words, V** is the dual space of V*.

Now, let's consider the evaluation map Φ: V → V** defined as Φ(v)(f) = f(v) for all v ∈ V and f ∈ V*.

The key idea is that the evaluation map Φ is an isomorphism. This means that it is a one-to-one and onto linear map that preserves vector space operations.

Since V and V** are isomorphic, they have the same dimension. Let's denote dim(V) = n.

Since B is a basis of V, we can extend B to a basis B' = {v₁, v₂, ..., vₙ, vₙ₊₁, ..., vₘ} of V, where m ≥ n. The additional vectors vₙ₊₁, ..., vₘ are linearly independent with respect to V.

Now, we can define a set B*' = {f₁, f₂, ..., fₙ} of linear functionals in V* such that fᵢ(vⱼ) = δᵢⱼ for all i and j. These functionals form the dual basis of B.

Next, we extend B*' to a basis B** = {f₁, f₂, ..., fₙ, fₙ₊₁, ..., fₘ} of V** such that m ≥ n. The additional functionals fₙ₊₁, ..., fₘ are linearly independent with respect to V**.

Using the isomorphism Φ, we can map the vectors vₙ₊₁, ..., vₘ from the extended basis B' of V to functionals in V**. Let's denote these functionals as Φ(vₙ₊₁), ..., Φ(vₘ).

Since V and V** are isomorphic, each functional in V** corresponds to a unique vector in V. Thus, we can associate the functionals Φ(vₙ₊₁), ..., Φ(vₘ) with vectors uₙ₊₁, ..., uₘ in V.

Now, we have the basis B** = {f₁, f₂, ..., fₙ, Φ(vₙ₊₁), ..., Φ(vₘ)} of V**.

Finally, using the isomorphism Φ, we can map the functionals in B** back to V, obtaining the basis B' = {Φ⁻¹(f₁), Φ⁻¹(f₂), ..., Φ⁻¹(fₙ), uₙ₊₁, ..., uₘ} of V.

Therefore, we have shown that every basis B of V

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Answer:

A = 280 ft²

Step-by-step explanation:

the figure is composed of a rectangle and a triangle.

area of rectangle = 20 × 10 = 200 ft²

area of triangle = \(\frac{1}{2}\) bh ( b is base and h the height )

b = 20 and h = 18 - 10 = 8 , then

area = \(\frac{1}{2}\) × 20 × 8 = 10 × 8 = 80 ft²

total area A = 200 + 80 = 280 ft²

A triangle has all three angles summing up to 180. If two of the sides measure 40 degrees and 50 degrees, then the third side measures as follows;

The third angle, which is labelled as angle A measures 90 degrees, and that means the triangle is a "right angled triangle."

Initially travelling away from it at a speed of +0.156 m/s, a M = 9.00 kilogram ball collides head-on with a M = 10.0 kg ball that is moving at +3.00 m/s.

\($v_{1, \mathrm{f}}=\left(\frac{m_1-m_2}{m_1+m_2}\right) v_{1, \mathrm{i}}+\left(\frac{2 m_2}{m_1+m_2}\right) v_{2, \mathrm{i}}$$v_{2, \mathrm{f}}=\left(\frac{2 m_1}{m_1+m_2}\right) v_{1, \mathrm{i}}+\left(\frac{m_2-m_1}{m_1+m_2}\right) v_{2, \mathrm{i}}$\)

If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p = m•v.

When momentum, p, and kinetic energy, KE, are conserved during a collision, the collision is said to be elastic. KE0 = KEf and po = pf are the results, respectively. KE = 1/2 mv2, thus we will write 1/2 m1 when we remember that (v1i) 2 + 1/2 m2(vi)2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) When the cue ball and the 2 ball collide with velocities of 0.0m/s before and after, 100% of the momentum of the cue ball is transmitted to the "8." It follows that the "8" ball is moving at a speed of 2.0 m/s. The masses' initial kinetic energy is given by K.E1 = 1/2 m1u21 + 1/2 m2u22.

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The final solution of the given problem is X = 2.82, Y = 1.04 for an Optimal solution Value of -16.93.

Given the optimization problem in 2X2 – 14X + 2XY + Y2 – 18Y + 50s.t. X + 4Y ≤ 8, we have to find the minimum solution to the given problem.

Solution To find the solution to the given optimization problem, we need to use the Lagrange multiplier method. Using this method, we have the following system of equations: 2x - 14 + 2y = λ4y - λ = 0x + 4y ≤ 8Solving the above equations, we get the following solutions:x = 3, y = 1, λ = 6

The optimal solution is X = 3, Y = 1, for an optimal solution value of -17. If the right-hand side of the constraint is increased from 8 to 9, the objective function would change by -2.29. (Decrease by 2.29)Now, we have to resolve the problem with a new right-hand side of 9.

The new optimization problem will be in 2X2 – 14X + 2XY + Y2 – 18Y + 50s.t. X + 4Y ≤ 9

Using the same method as above, we have the following system of equations:2x - 14 + 2y = λ4y - λ = 0x + 4y ≤ 9Solving the above equations, we get the following solutions:x = 2.82, y = 1.04, λ = 6.07

The objective function value is -16.93 so the actual increase/decrease is only -0.07 rather than -2.29. Hence, the actual change is very different from the estimated change.

Therefore, the final solution of the given problem is X = 2.82, Y = 1.04 for an optimal solution value of -16.93.

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answer:

x=16

Step-by-step explanation:

Answer:

11.5 inches

Step-by-step explanation:

Just subtract the .5 inch from 12. The max of variance that it can have.

Explanation:

x = number of coins Karen has

4x = four times the number of coins she has

4x-4 = number of coins Bill has, four fewer than 4x

Add up the first and third expressions to get

(x) + (4x-4) = (x+4x) - 4 = 5x-4

The two of them have a combined 5x-4 coins