We will have the following:
\(\frac{8oz}{day}\ast\frac{0.0625lb}{1oz}\ast\frac{7day}{1week}=\frac{3.5lb}{week}\)A phone company charges a base fee of $12 per month plus an additional charge per minute.the monthly phone cost c can be represented by this equation: c=12+a •m, where a is the additional charge per minute, and m is the number of minutes used.
What equation can be used to find the number of minutes a customer used I we know a and c
Answer:
Hi there!
Your answer is
(C-12)/A = M
Step-by-step explanation
c=12+a * m
SOLVE FOR M!
C=12+AM
-12
C-12+AM
Divide out A to isolate M
(C-12)/A = M
The equation that can be used to find the number of minutes[m] a customer used is - m = (c - 12)/a
What is equation rearrangement?
Equation rearrangement is a process of arranging the equation parameters in terms of a specific parameter.
Given is a phone company that charges a base fee of $12 per month plus an additional charge per minute. The monthly phone charge cost [c] can be represented by the equation: c = 12 + a x m, where [a] is the additional charge per minute, and [m] is the number of minutes used.
The given equation is -
c = 12 + a x m
Since, we know the values of [a] and [c], we can solve for [m] as follows -
c = 12 + a x m
c - 12 = a x m
m = (c - 12)/a
Therefore, the equation that can be used to find the number of minutes[m] a customer used is -
m = (c - 12)/a
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(2x^2-9x-5) \div(x-5)
Answer:2x+1
Step-by-step explanation:
brody is working two summer jobs, making $10 per hour babysitting and making $15 per hour cleaning tables. In a given week, he can work a maximum of 13 total hours and must earn at least $150. If x represents the number of hours babysitting and y represents the number of hours cleaning tables, write and solve a system of inequalities graphically and determine on possible solution.
Answer:
10x+15y≥150
Step-by-step explanation:
Graph y≤13−x (shading down)
graph y≥10− 3/2x (shading up)
3 6 9 12 15 18 21 24 27 30 is odd or even numbers?
Answer: Half of them are even and half of them are odd.
Step-by-step explanation:
The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.
The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.
Therefore, out of the given numbers, half of them are even and half of them are odd.
________________________________________________________
Every day, the Lee Pet Store uses 1/3 of a bag of dog food to feed the dogs. How many days
will 1 1/3 bags of dog food last?
If f(x) = −2 + 8, what is f(−1.8)?
4
6
10
12
Answer:
10
Step-by-step explanation:
right on edge, ITS NOT 6
Answer: 10
Step-by-step explanation:
edge2020
What is the slope of the line that passes through the points (3, 6) and (1, 2)? Write your answer in simplest form.
Use a stem-and-leaf plot to display the data, which represent the thickness (in centimeters) of ice measured at 20 different locations on a frozen lake. Describe any
patterns.
5.8 6.5 6.9 7.2 5.1 4.9 4.3 5.8 7.0 6.8
8.7 7.5 7.2 5.8 7.2 8.0 7.2 6.9 5.9 7.9
Determine the leaves in the stem-and-leaf plot below.
Key: 3|3= 3.3
Ice Thickness
4|
5|
6|
7|
8|
Answer/Step-by-step explanation:
To represent the data given on a stem and leaf plot, the whole number in a given value would be used as the stem, while the number after the decimal point is the leaf. (Key: 3|3 = 3.3).
For example, in the first stem in the first row, we have 4 as the stem. All values that starts with 4 point would be represented in this row. The digit after 4 point for each of the values would be written on the leaf column in the first row, from the least to the largest. For the first row we have: 4 | 3 9.
Same applies to the rest rows.
The stem plot would look like the one below:
Ice Thickness:
Stem | Leaf
4 | 3 9
5 | 1 8 8 8 9
6 | 5 8 9 9
7 | 0 2 2 2 2 5 9
8 | 0 7
The data of the stem-and-leaf plot shows a bell-shaped pattern with majority of the ice thickness for the 20 locations clustering around the center of the data distribution.
What is the value of the digit in the ones place?
2,615
A. 50
B. 5
OC. 2,000
OD. 100
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Given: Circle k(O) with OT ⊥ XY, and OU ⊥ WZ and X=Z. Prove: XY=WZ
The answer of the given question based on circle is we have shown that XY = WZ, since both line segments are equal to XM.
What is Pythagorean theorem?The Pythagorean theorem is fundamental concept in mathematics that relates to sides of right triangle. It states that square of the length of hypotenuse (the side opposite the right angle) is equal to sum of the squares of lengths of the other two sides (the legs).
To prove that XY = WZ, we will use the fact that the line segment connecting the center of a circle to the midpoint of a chord is perpendicular to the chord.
Let M be the midpoint of XY, and N be the midpoint of WZ. Since X = Z, we know that XM is parallel to ZN, and therefore MZNX is a parallelogram.
Let O be center of circle k(O). Then, by the perpendicularity property mentioned above, we know that OM is perpendicular to XY, and ON is perpendicular to WZ.
Since M and N are midpoints of XY and WZ respectively, we have:
XM = MY, and ZN = NW
Therefore, by the Pythagorean theorem, we have:
OX² = OM² + MX², and OZ² = ON² + NZ²
Adding these two equations gives:
OX² + OZ² = OM² + MX² + ON² + NZ²
Since MZNX is a parallelogram, we know that OM = ON, and MX = NZ. Substituting these values gives:
OX² + OZ² = 2OM² + 2MX²
But since OM is perpendicular to XY and ON is perpendicular to WZ, we have:
OM² + MX² = XM²/4, and ON² + NZ² = ZN²/4
Substituting these values gives:
OX² + OZ² = XM²/2 + ZN²/2
But since MZNX is a parallelogram, we know that XM = ZN. Therefore:
OX² + OZ² = XM²
Thus, we have shown that XY = WZ, since both line segments are equal to XM.
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What is the place value of 2 in 369.425
Answer:
The two is in the hundredths place
Step-by-step explanation:
369.425
hundreds tens ones. tenths hundredths thousandths
3 6 9 . 4 2 5
The two is in the hundredths place
Answer:
The place value of 2 in 369.425 is hundredths.
The number 369.425 is a decimal number. It has a whole number part (369) and a decimal part (0.425). The decimal part is divided into tenths, hundredths, thousandths, and so on. The 2 is in the hundredths place.
Step-by-step explanation:
what is 32,020.20 rounded to the nearest tenths
Answer:
32,020
Explanatiojn:
I need some help with this problem
Answer:(-(3x^(3)-x-1))/((x^(2)+1)^(2))
The length of a rectangle is 5 cm more than 2 times its width. The perimeter of the rectangle is 34. Define variables to find both length and width. Write an equation to find the perimeter of the rectangle. What are the dimensions of the rectangle?
Answer:
many take time and solve it step by step
Step-by-step explanation:
sorry I am lost
Mia receives 5.75% commission on all her sales. One month she sold$12,000 worth of goods. How much was her commission for the month?a. $1,250b. $1,923.08c. $8,125d. $690
The commission rate is 5.75%
Amount sold for the month= $12,000.
Then, the amount she receives for the month is;
\(\frac{5.75}{100}\times\text{ \$12000}\)\(=\text{ \$690}\)CORRECT OPTION: D
what is the product of -2 1/4 and -4 1/2
Answer:
i think 6 5/8
Step-by-step explanation:
So distribute
-2*-4+-2*1/2=7 1/2
1/4*-4+1/4*1/2=-7/8
7 4/8 - 7/8 is 6 5/8
Pentagon PQRST is shown on the coordinate grid below. Given that the pentagon was translated 6 units to the right and labeled P'Q'R'ST'. what are the coordinates of T'? HE
Answer:
i think its X=0
hopes it helps
Step-by-step explanation:
7) Find the area (in cm).
h
7 x 6 square
The Hamilton’s are installing a new pool in their backyard .The scale drawing below represents the new pool,where 1 centimeter represents 5 feet.
I need help solving this
The cylinder has a volume of 150.796 in³. The cylinder has a surface area of 175.929 in².
What's volume of cylinder ?The quantity of three-dimensional space that an object or closed surface occupies is referred to as volume in mathematics. The cubic units of volume are m³, cm³, in³, and so on.
How does surface area work?The sum of all of an object's faces is its surface area in three dimensions. Wrapping, painting, and finally building things to achieve the best possible design are examples of real-world applications of the concept of surface areas.
Evaluating :Given that a volume of cylinder = h × r² × π
h = 12 in
r = 2 in
volume = ?
Volume of cylinder = h × r² ×π
= =12 × 3.14×(2)²
=37.68 × 4
=150.796 in³
B). Surface area of cylinder= 2πr² + 2πrh
=2× 3.14 × (2)²+2× 3.14× 2×12
=175.929in²
The formula V=r²(h) can be used to determine a cylinder's volume. Simply multiplying the area of the circular base shape by the height is all that is required to determine a cylinder's volume.
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Atlanta and Cincinnati 440 miles apart. John leaves Cincinnati; driving
toward Atlanta at an average rate of 60 mph. Pat leaves Atlanta at the same time, driving toward Cincinnati in her antique auto, averaging 28 mph. How long will it take them to meet?
Answer:
5 hours
Step-by-step explanation:
28x = 60(440-x)
28x = 60*440 - 60x
88x = 60*440
x = 60*440/88
x = 300mi, distance Jon travels
300mi/60mph = 5hrs, the time it took them to meet
CHECKING OUR ANSWER
60MPH*5HR + 28MPH*5HR = 300MI + 140MI = 440MI
answer thissss pleaseee
Answer:45 degree angle
Step-by-step explanation: am smart
11 You randomly choose a number from 1 to 10. Find P(even or less than 5).
You randomly choose a number from 1 to 10
We are asked to find the probability P(even or less than 5)
There are a total of 10 possible numbers
\(1,2,3,4,5,6,7,8,9,10\)How many of them are even?
\(even=2,4,6,8,10\)There are 5 even numbers.
So, the probability of getting an even number is
\(P(even)=\frac{5}{10}=\frac{1}{2}=0.5\)How many of them are less than 5?
\(less\: than\: 5=1,2,3,4\)There are 4 numbers less than 5.
So, the probability of getting a number less than 5 is
\(P(less\: than\: 5)=\frac{4}{10}=\frac{2}{5}=0.4\)Finally, we need to add these probabilities to find the combined probability (or means to add)
\(\begin{gathered} P(even\: or\: less\: than\: 5)=P(even)+P(less\: than\: 5) \\ P(even\: or\: less\: than\: 5)=0.5+0.4 \\ P(even\: or\: less\: than\: 5)=0.90 \end{gathered}\)Therefore, the probability P(even or less than 5) is 0.90
Suppose that a study of elementary school students reports that the mean age at which children begin reading is 5.3 years with a standard deviation of 1.1 years.
Step 1 of 2: If a sampling distribution is created using samples of the ages at which 35 children begin reading, what would be the mean of the sampling distribution of sample means? Round to two decimal places, if necessary.
Answer:
The mean of the sampling distribution of sample means is equal to the population mean, which is 5.3 years.
give thanks for more! your welcome!
Step-by-step explanation:
The Simple interest on $160
for 6 month's at 5% per
annum
Answer:4$
Step-by-step explanation:
How many paths are there from $A$ to $B,$ if you travel along the edges? You can travel along each edge at most once, but you can pass through the same point more than once. (You can pass through $B,$ as long as you end up at the point $B.$)
Answer:
9
Step-by-step explanation:
You don't need to pass through each edge once.
If we name the top vertex 1 and the bottom vertex 2 then here are the possible combinations:
A-1-B
A-B
A-2-B
A-1-B-A-2-B
A-2-B-A-1-B
A-B-1-A-2-B
A-B-2-A-1-B
A-1-B-2-A-B
A-2-B-1-A-B
Some people say 6 because they think you need to pass through all the edges. But the only restriction with travelling on the edges is you can't pass one twice. The point is read the wording and it becomes easy.
Hope this helps!
Is the function f(x) = 10 linear or nonlinear?
What is the midpoint of the segment shown below?
O A. (0, 3)
OB. (0,4)
O C. (0, 2)
O D. (0, 1)
The mid point of the line segment is (0, 2)
How to find mid point of a segment?A midpoint of a line segment is the point on a segment that bisects the segment into two congruent segments.
Therefore, the mid point of a line segment can be represented as follows:
m = (x₁ + x₂ / 2, y₁ + y₂ / 2)
Hence,
(-4, 6)(4, -2)
Therefore,
x₁ = -4
x₂ = 4
y₁ = 6
y₂ = -2
Hence,
m = (-4 + 4 / 2, 6 -2 / 2)
m = (0/2, 4 / 2)
m = (0, 2)
Therefore,
mid point = (0, 2)
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