describe the changes in both the hydrogen ion concentration and ph of the gastric juice of a human after ingesting this type of antacid

Answer:

1. carbon

Explanation:

carbon atoms bound to one another and other atoms by covalent bonds and found in the cells of living organisms. Hydrogen, oxygen and nitrogen are typical elements which, in addition to carbon, make up organic compounds.

Answer:

for what? is there supposed to be a picture?

Explanation:

??

Answer: 204 L

Explanation:

According to ideal gas equation:

\(PV=nRT\)

P = pressure of gas = 0.262 atm

V = Volume of gas = ?

n = number of moles = \(\frac{\text {given mass}}{\text {molar mass}}=\frac{11.7g}{4g/mol}=2.92\)

R = gas constant =\(0.0821Latm/Kmol\)

T =temperature =\(-50^0C=(273+(-50))K=223K\)

\(V=\frac{nRT}{P}\)

\(V=\frac{2.92\times 0.0820 L atm/K mol\times 223K}{0.262atm}=204L\)

Thus volume occupied by 11.7 g of Helium in a balloon is 204L

The volume at 6.30 atm is 0908 L and the pressure is 173 atm.

Part 1.

Sample volume =2.60 L

Pressure =2.20 atm

Volume=?

As per Boyle's law,

P1V1=P2V2

2.20 ATM*2.60 L=6.3 atm * V2

V2=0.308 L

The volume at 6.30 atm is 0908 L.

Part 2.

Volume=0.0330 L

Pressure=?

As per Boyle's law,

P1V1=P2V2

2.2 atm*2.6 L=P2*0.330 L

P2=173 atm

The pressure is 173 atm.

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Taking into account the reaction stoichiometry, 2.1528 moles of CO₂ can be produced from 31.00g pentene.

In first place, the balanced reaction is:

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 72 grams of C₅H₁₂ form 5 moles of CO₂, 31 grams of C₅H₁₂ form how many moles of CO₂?

moles of CO₂= (31 grams of C₅H₁₂×5 moles of CO₂) ÷72 grams of C₅H₁₂

moles of CO₂= 2.1528 moles

Finally, 2.1528 moles of CO₂ can be produced.

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Answer:

Me India is located in Asia and its capital name is New Delhi.

Explanation:

\(india \\ 1)india \: is \: the \: 7 \: th \: largest \: country \\ 2)home \: to \: old \: civilizations \\ 3)father \: of \: the \: nation \: mahathma \: gandi \\ 4)country \: is \: divided \: in \: to \: 28state \\ 5)1000of \: lnguages \: 100 \: of \: cultures \: \\ so \: india \: is \: very \: much \: attractive \\ very \: much \: special \\ 1947 \: august15 \: indias \: independce \: day \\ thank \: you \: \\ jai \: hind\)

The enthalpy change, δH∘, for the reverse of the formation of methane is +74.8 kJ/mol.

The reverse of the formation of methane from carbon and hydrogen gas is given as, ch4(g)→c(s)+2h2(g).

The formation of methane from carbon and hydrogen gas is an exothermic reaction and the reverse reaction, which is the decomposition of methane, is an endothermic reaction.

To find the enthalpy change of the reverse reaction, δH°, we can use Hess's Law, which states that the enthalpy change of a reaction is independent of the route taken.

It means that the sum of the enthalpy changes of the reactants should be equal to the sum of the enthalpy changes of the products, regardless of the reaction pathway.

In this problem, we can use the enthalpy of formation of methane from its constituent elements, carbon and hydrogen.

The enthalpy change of the formation of methane is given by the following equation:

C(s) + 2H2(g) → CH4(g) ΔH° = –74.8 kJ/mol

This means that 74.8 kJ of heat is released when 1 mole of methane is formed from carbon and hydrogen gas.

Since the reverse reaction is the decomposition of methane into its constituent elements, the enthalpy change would be the opposite sign of the enthalpy change for the formation of methane.

Therefore,

ΔH°(reverse reaction) = -ΔH°(forward reaction) ΔH°(reverse reaction)

= -(-74.8 kJ/mol)ΔH°(reverse reaction)

= +74.8 kJ/mol

Thus, the enthalpy change, δH∘, for the reverse of the formation of methane is +74.8 kJ/mol.

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Therefore, the number of water molecules (X) in the formula is approximately 2.42 × 10²⁴. Therefore, both compounds contain the same percentage of oxygen. The percent of anhydrous compound in the beaker is 53.8%.

A molecule is a group of two or more atoms held together by chemical bonds. It is the smallest unit of a compound that has the chemical properties of that compound. Molecules can be made up of atoms of the same element or different elements.

Here,

Question 1:

If KB5O8·XH2O contains 24.6% of water and its formula weight is 293.15 g/mol, we can calculate the molecular weight of the water and use that to determine the value of X. The molecular weight of water is 18.015 g/mol (rounded to the hundredths place).

The mass of water in the compound is:

24.6% of 293.15 g/mol = 72.1989 g/mol

The number of moles of water is:

72.1989 g/mol ÷ 18.015 g/mol = 4.0061 mol

The number of water molecules is:

4.0061 mol × Avogadro's number = 2.42 × 10²⁴ molecules

Therefore, the number of water molecules (X) in the formula is approximately 2.42 × 10²⁴.

Question 2:

To calculate the percent of oxygen in ammonium nitrite and ammonium carbonate, we need to determine the molecular formulas of each compound.

The molecular formula of ammonium nitrite is NH4NO2, and its molecular weight is approximately 64.06 g/mol. The percent of oxygen in ammonium nitrite is:

(2 × 16.00 g/mol ÷ 64.06 g/mol) × 100% = 50.0%

The molecular formula of ammonium carbonate is (NH4)2CO3, and its molecular weight is approximately 96.09 g/mol. The percent of oxygen in ammonium carbonate is:

(3 × 16.00 g/mol ÷ 96.09 g/mol) × 100% = 50.0%

Therefore, both compounds contain the same percentage of oxygen.

Question 3:

To calculate the percent of anhydrous compound in the beaker, we need to determine the mass of water that was lost during heating.

The mass of the hydrate (including water) is:

134.92 g – 128.89 g = 6.03 g

The mass of the anhydrous compound is:

132.14 g – 128.89 g = 3.25 g

The mass of water lost during heating is:

6.03 g – 3.25 g = 2.78 g

The percent of anhydrous compound in the beaker is:

(3.25 g ÷ 6.03 g) × 100% = 53.8%

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Answer:

c i think

Explanation:

Answer:

I can’t see the whole page

Explanation:

When the gas emits at a rate that is 0. 667 times that of CO₂, it has a molar mass of 62.9 g/mol.

Graham's Law states that a gas's rate of effusion is inversely related to the square root of its molar mass.

√[M(b)/M(a)] = R(a)/R(b)

R is the effusion rate.

square root = sqrt = √

the molar mass, M

Square root of R(a)/R(CO) is √[M(CO)/M(a)].

(0.667)² = 28 g/mol/ M(a)

( by squaring both sides)

M(a)(0.667)² = 28

M(a) = 28/(0.667)²

M(a) = 62.9 g/mol.

The molar mass of the unidentified gas is 62.9 g/mol.

What effect has Graham's law?

According to Graham's law of diffusion, the ratio of the square root of the molecular weights of gas particles to their diffusion rates is equivalent.

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The empirical formula : FeBr₃

A 8.310 g sample of Iron, so mol of Iron(Ar=55.845 g/mol) :

\(\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{8.310}{55.845}\\\\mol=0.149\)

Mass of metal bromide formed : 43.98 g, so mass of Bromine :

\(\tt =mass~metal~bromide-mass~Iron\\\\=43.98-8.310\\\\=35.67~g\)

then mol Bromine (Ar=79,904 g/mol) :

\(\tt \dfrac{35.67}{79,904}=0.446\)

mol ratio of Iron and Bromine in the compound :

\(\tt 0.149\div 0.446=1\div 3\)

Answer:

By Convection

Explanation:

Bromothymol blue was used to indicate the pH of the solution.

Bromothymol blue is a pH indicator, which means it changes color in response to changes in the pH of the solution. In particular, bromothymol blue is yellow in basic solutions (pH 7.6 - 6.0) and blue in acidic solutions (pH 6.0 - 7.6).

In the experiment, the presence of bromothymol blue allowed the researchers to observe changes in the pH of the solution, and to make more accurate measurements of the pH than would be possible without the indicator. This information was likely used to track the progress of the reaction or to monitor the pH of the solution at different stages of the experiment. By using bromothymol blue, the researchers were able to gain a better understanding of the conditions of the reaction and to make more informed conclusions about the results.

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The reaction that shows oxidation is the one that has been shown in option D.

We have to know that the process that we call oxidation would have to do with the loss of the electrons that we have in a system. If we are dealing with a neutral atom that has been oxidized then we would see an increase in the oxidation number of the atom. This same effect would be seen if we are looking at the oxidation of any other chemical specie that is under consideration.

We need to look at the reactions that have been shown in the options that we have and then compare it with the overall redox reaction equation that we see at it has been shown in the reaction that has been attached to the question that we have in the attachment that is shown above here.

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A certain fluid has poured on the engine, causing the vehicle to smoke under the hood without overheating.

fluids are any liquids, gases, or basically any materials that, when under stress, exhibit a continual change in shape and are unable to withstand tangential or shearing forces at rest.

Thermostat, density, and composition are a few of the most basic ideas in fluid characteristics. Extensive properties, or properties which are dependent on the quantity of material present, include mass and volume.Temperature, pressure, and density are some examples of intense properties.

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The Florida mouse (Podomys floridanus) is typically found in close association with various types of vegetation.

The Florida mouse (Podomys floridanus) is typically found in close association with various types of vegetation, particularly in the southeastern coastal plain of the United States. This species is endemic to the state of Florida and is primarily found in habitats such as pine forests, oak hammocks, palmetto thickets, and brushy areas.

The Florida mouse has specific habitat requirements, including a mix of dense ground cover and overhead vegetation. It prefers areas with well-developed undergrowth, leaf litter, and fallen logs. These habitats provide shelter, protection from predators, and a source of food.

The vegetation composition in the Florida mouse's habitat is crucial for its survival. It relies on the availability of seeds, fruits, and plant materials as its primary food source. The presence of shrubs, grasses, and herbaceous plants contributes to the overall diversity and abundance of food resources.

The Florida mouse's association with vegetation extends beyond foraging and food availability. The dense vegetation provides cover and protection from predators, as well as suitable nesting sites. The mouse constructs nests in burrows or under dense vegetation, utilizing natural materials like grasses, leaves, and twigs.

Conservation efforts for the Florida mouse often focus on habitat preservation and restoration. Maintaining suitable vegetation structure and composition is crucial for the survival and population viability of this species. Protection of its preferred habitat ensures the availability of food, cover, and nesting resources necessary for its survival and reproduction.

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Answer:

The Nitric Acid Test is used to check if silver is pure or plated. To do so, file a small part of the item in a discreet area where it cannot be seen. Apply a few drops of nitric acid. If the area turns into creamy white, the silver is pure or sterling.

Explanation:

Answer:

b. tendons connected muscles to bone.

1. The approximate percent of water in the hydrate is 16%

2. The value of x in the hydrate is 2

Mass of hydrate, SnCl₂•xH₂O = 0.366 g

Mass of water, H₂O = 0.0586 g

Percentage of water =?

Percentage = (mass of water / mass of hydrate) ×100

Percentage of water = (0.0586 / 0.366) × 100

Percentage of water = 16%

To obtain the value of x, we shall determine the formula of the hydrate. This can be obtained as follow:

Divide by their molar mass

SnCl₂ = 0.3074 / 190 = 0.0016

H₂O = 0.0586 / 18 = 0.0032

Divide by the smallest

SnCl₂ = 0.0016 / 0.0016 = 1

H₂O = 0.0032 / 0.0016 = 2

Thus, the formula of the hydrate is SnCl₂•2H₂O

Comparing the formula of the hydrate (SnCl₂•2H₂O) with SnCl₂•xH₂O, we can see that the value of x is 2

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Explanation:

20 molecules of C3H8 react with _100_ molecules of O2 to produce _60_ molecules of CO2 and

_80_ molecules of H2O. Use stoichiometric ratios from the balanced equation.

Hope this helps!

The answer to the fill in the blanks question about "__________ is to break a substance into cations and anions." is Ionization.  

Ionization is the process by which ions are created when an atom or molecule gains or loses an electron. An atom or molecule becomes negatively charged (an anion) when it gets an electron and positively charged (a cation) when it loses an electron (a cation). In the process of creating an ion, energy can be acquired or lost. Any process by which electrically neutral atoms or molecules are changed into electrically charged atoms or molecules (ions) through the gain or loss of electrons is referred to as ionization in chemistry and physics. Ionization energy, sometimes referred to as ionization potential, is the amount of energy needed to remove an electron from an isolated atom or molecule in physics and chemistry.

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The mass of oxygen is needed to react with 1.39 gal of methanol  is 6266.4g

Given:

methanol = 1.39 gal = 1.39 *3.79 =5.2681 L=5268.1 mL

density of methanol is 0.793 g/mL

weight of methanol = 0.793 * 5268.1 =4177.6 g

From the Balance Equation we know that 2 mole of methanol react with 3 mole of oxygen

since

mass of oxygen is needed to react = 4177.6/2 * 3 =6266.4g

complete Que :

What mass of oxygen is needed to react with 1.39 gal of methanol according to the balanced equation below? (1.00 gal - 3.79 L, and the density of methanol is 0.793 g/mL.) 2 CH2OH(1) + 3 02(g) 2 C02(%) + 4H2O

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Answer:

The trachea is a tube-like structure within the neck and upper chest. It transports air to and from the lungs when a person breathes. When a person inhales, air travels through the nose or mouth, down the trachea, and into the lungs.

Explanation:

Brainliest plz

The disproportionation reaction of the radicals produced by the most energetically favored homolytic bond cleavage in the molecule CH3-CH2-CH-CH2-CH3 would form the alkane-alkene pair CH4 and (CH3)2C=C(CH3)2.                                  

The most energetically favored homolytic bond cleavage in the given molecule would be the one between the two carbon atoms in the middle of the chain, resulting in two radicals - one with a methyl group and the other with a propyl group. To form an alkene, these radicals need to combine in a way that would lead to the formation of a double bond. Among the given options, only option C has two radicals that can combine to form a double bond between the second and third carbon atoms, resulting in the alkene CH2=CH-CH=CH-CH3. Therefore, the answer is (C) CH3CH2CH2 and CH2=C(CH3)CH=CH2.
The primary carbon radical formed after cleavage will react with a secondary carbon radical, leading to the formation of methane (CH4) and the alkene, 2,3-dimethyl-2-butene [(CH3)2C=C(CH3)2].

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The balloon inflated indoors after deflating outdoors in the chilly winter weather due to Charles law.

A rule that says the volume of a perfect gas at constant pressure is inversely correlated with the absolute temperature.

The balloon contracts as a result of the helium becoming denser than before as the temperature drops. In order to preserve heat, the helium molecules lose energy, slow down, and migrate closer together. As a result, the volume within the balloon reduces since they are moving closer together rather than outward toward the balloon's shell, which would cause the balloon to expand and subsequently contract. The Charles law is the gas law that makes this happen.

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Answer:

A) 2

B) 1

C) 3

D) 4

i hope its right

a. The limiting reagent is o-phenylenediamine.

b. The theoretical yield of benzil quinoxaline is 0.388 g.

A limiting reagent is the reactant that runs out first and limits the amount of products that can be produced in a chemical reaction.

In the given problem, the chemical reaction is given as:

O-phenylenediamine + Benzil → Benzil quinoxaline

Mass of o-phenylenediamine, m1 = 0.1473 g

Mass of Benzil, m2 = 0.2162 g

Molar mass of o-phenylenediamine = 108.12 g/mol

Molar mass of Benzil = 210.25 g/mol

Calculation of moles of reactants:

moles of o-phenylenediamine, n1 = mass / molar mass = 0.1473 g / 108.12 g/mol = 0.0013625 moles

moles of Benzil, n2 = mass / molar mass = 0.2162 g / 210.25 g/mol = 0.0010285 moles

To find out which reactant is the limiting reagent, we need to calculate the mole ratio of reactants in the chemical reaction:

Mole ratio of o-phenylenediamine to Benzil = 1:1

The reactant that is not in excess and is fully consumed is the limiting reagent.

Limiting reagent in this reaction is o-phenylenediamine as it has the smaller number of moles compared to Benzil.

Now, we will calculate the theoretical yield of benzil quinoxaline using the limiting reagent.

o-phenylenediamine is the limiting reagent in this reaction.

So, moles of benzil quinoxaline that can be produced = moles of o-phenylenediamine = 0.0013625 moles

Molar mass of Benzil quinoxaline = 284.31 g/mol

Theoretical yield of Benzil quinoxaline, Y = moles of product × molar mass = 0.0013625 moles × 284.31 g/mol = 0.3877 g ≈ 0.388 g

Therefore, the limiting reagent is o-phenylenediamine and the theoretical yield of Benzil quinoxaline is 0.388 g.

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