Determine the Conjugate base of the following acids? 1. HCIO4 2. H2O 3. HCN 4. NH4+

Answer:

D.

Explanation:

The electron cloud has negligible mass. Most mass come from the nucleus.

Answer: The average atomic mass of copper is 65.5456 amu.

Explanation: Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

   .....(1)

For  isotope:

Mass of  isotope = 62.9296 amu

Percentage abundance of  isotope = 69.17 %

Fractional abundance of  isotope = 0.6917

For  isotope:

Mass of  isotope = 64.9278 amu

Percentage abundance of  isotope = 30.83%

Fractional abundance of  isotope = 0.3083

Putting values in equation 1, we get:

Thus, the average atomic mass of copper is 65.5456 amu.

According to the solving the energy of a photon:

3 x 10⁺²⁰.

The correct option is C.

Radiation is the term used to describe energy that travels through space at the speed of light. Both an electric and a magnetic field are present along with this energy, which has wave-like characteristics. Electromagnetic waves are another name for radiation.

A photon is a fundamental particle that functions as both the force carrier again for electromagnetic force and a quantum of both the electromagnetic field, which includes electromagnetic radiation like light and radio waves. Due to their lack of mass, photons always travel at speeds of light in a vacuum, which is 299792458 m/s.

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

The energy in one photon can be formulated as

E = h * f

Wavelength of photon=λ=6 μm = 6.10⁻⁶ m

E = h x \($\frac{c}{\lambda}$\)

E = \($=6,626.10^{-34} \times \frac{3.10^8}{6.10^{-6}}$\)

E = \($3.3 \times 10^{-20} \mathrm{~J}$\)

According to the solving The energy of a photon : 3 x 10⁺²⁰.

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Answer:

false

Explanation:

first of all;-energy lead to an indotermic reaction.

indotermic is a reaction that absorbs energy \

*it has positive enthalpy of reaction

*Heat content of product is greater than that of reactant

*Heat is added to reactant side

example;- CO^2+2H^2+891kj --------- CH4 +2O2

Answer:

because it includes all compunds with h and c

Explanation:

Writing Balanced Chemical Equations of Reaction:

Chemical reactions occur between chemical elements or compounds, called reactants, to form different elements or compounds, called products. Chemists resort to chemical equations to convey this information concisely.

A correctly written chemical equation conveys information on the state of matter (liquid, gas, solid precipitate, aqueous solution, etc) of each reagent, as well as the amount of each. All charges and quantities of each element must be balanced correctly.

Simplifying :

We are required to write the balanced chemical equation for the reaction between nitrogen dioxide (NO₂) and water (H₂O). We are told that nitric acid (HNO₃) and nitrogen monoxide (NO) are formed.

Let's begin by writing out the reaction, together with the states of each reactant:

NO₂(g) +H₂O(l) →HNO(aq)+ NO(g).

Unfortunately, this equation is not balanced. There are 2 'atoms' of hydrogen on the left hand side, and only one on the right hand side. Thus, let's introduce a coefficient of 2 on the nitric acid:

NO₂(g) +H₂O(l) →  2HNO₃(aq) +NO(g).

It is still not balanced: there are three 'atoms' of nitrogen on the right hand side, and only one on the left hand side. Let's introduce a coefficient of 3 on the nitrogen dioxide:

3NO₂(g)  +H₂O(l)  → 2HNO₃(aq) +NO(g).

Finally, all atoms are balanced. This is the complete balanced equation for the given reaction. All states of matter are also included.

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Answer:

The answer is 10

Explanation:

The solutions well by inverting the volumetric flask at least 10 times.

To prepare the calibration standards from the stock solution, you need to use the dilution equation: C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution you need to take, C2 is the concentration of the calibration standard you want to prepare, and V2 is the volume of the calibration standard.

For the 1 μg/mL calibration standard, the equation will be:

25 μg/mL × V1 = 1 μg/mL × 10 mL

Solving for V1 gives:

V1 = (1 μg/mL × 10 mL) / 25 μg/mL = 0.4 mL

So you need to take 0.4 mL of the stock solution and dilute it to 10 mL with deionized water to prepare the 1 μg/mL calibration standard.

Similarly, you can calculate the volume of the stock solution you need to take for the other calibration standards:

For the 2 μg/mL calibration standard:

V1 = (2 μg/mL × 10 mL) / 25 μg/mL

=> 0.8 mL

For the 5 μg/mL calibration standard:

V1 = (5 μg/mL × 10 mL) / 25 μg/mL

=> 2 mL

For the 8 μg/mL calibration standard:

V1 = (8 μg/mL × 10 mL) / 25 μg/mL

=> 3.2 mL

Eppendorf pipettes to transfer the appropriate volume to the 10 mL volumetric flasks, and then dilute to the mark with deionized water. Remember to mix the solutions well by inverting the volumetric flask at least 10 times, and to rinse your glassware and pipettes with deionized water prior to use.

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The product of electrolysis : Al at cathode and Cl₂(chlorine) at anode

Given

Aluminum chloride compound

Required

The product of electrolysis

Solution

The rule :

The reaction at the cathode(the negative pole) :

1. the reduced active metal is water, other than that the metal will be reduced

2. H⁺ of the acid will be reduced

The reaction at the anode((the positive pole) :

1. if the electrodes are not inert then the metal is oxidized

2. If inert then:

a. OH⁻ from the base will be oxidized

b. The halogen metal will oxidize

In the electrolysis of molten AlCl₃ with an inert electrode, the cation will be reduced at the cathode and the anion will be oxidized at the anode

Cathode : Al³⁺ + 3e⁻ ⇒ Al(s)

Anode : 2Cl⁻⇒Cl₂(g) + 2e⁻

Coenzymes such as NADH and FADH2 are used to carry electrons to and from many kinds of oxidation/reduction reactions.

What are coenzymes?

A macromolecule that catalyses a chemical process is an enzyme. In other words, it creates the possibility of a negative reaction. Smaller molecules are used to construct enzymes to create an active component. The coenzyme is one of an enzyme's most crucial components.

Small molecules make up coenzymes. They are unable to catalyse reactions on their own, but they can assist enzymes in doing so. Coenzymes are organic nonprotein molecules that join with the protein molecule (apoenzyme) to create the active enzyme, according to the technical definition (holoenzyme).

In biological oxidation-reduction reactions, NADH and FADH2 are two coenzymes that are extremely important. Along with the transfer of electrons, hydrogen ions also occur.

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Direct contact between objects causes conduction or heat transfer. The heat is transferred inside the fluid during convection. Heat transfer in radiation happens by electromagnetic waves without the use of particles.

First, ascertain whether the two things are in contact. If they are, conduction is how heat is transferred between them. Determine whether there is a fluid medium, such as a liquid or gas, connecting the items if they are not in contact.

Evidence of heat transport is apparent. Convection is the phenomenon that causes the air to shimmer over radiators. Conduction is the phenomenon that causes you to feel warm when you place your hand on a spoon that has been sitting in a hot bowl of soup (radiation).

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In the system at equilibrium liquid water-water vapor, if liquid water is added to the system, more liquid water molecules will change to water vapor until a new equilibrium is reached.

If a constraint (such as a change in pressure, temperature, or concentration of a reactant) is applied to a system in equilibrium, the equilibrium will shift so as to tend to counteract the effect of the constraint.

Let's consider the following system at equilibrium.

H₂O(l) + heat ⇄ H₂O(g)

Which statement best describes what will happen if liquid water is added to the system?

In the system at equilibrium liquid water-water vapor, if liquid water is added to the system, more liquid water molecules will change to water vapor until a new equilibrium is reached.

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Answer:

More liquid water molecules will change to water vapor until a new equilibrium is reached. Yes. This will happen to counteract the excess of liquid water.

All of the liquid water molecules that are added will become water vapor. No. Some liquid molecules will change to vapor to attain a new equilibrium.

More water vapor molecules will change to liquid water until a new equilibrium is reached. No. The change will happen in the inverse sense.

All of the liquid water molecules that are added will remain liquid water. No. Some liquid molecules will change to vapor to attain a new equilibrium.

Explanation:

Answer:

A change in the shape of a substance

Explanation:

Because when ths shape of a sunstance changes , its physical appearance changes .A physical change is a change to the physical—as opposed to chemical—properties of a substance. They are usually reversible. The physical properties of a substance include such characteristics as shape (volume and size), color, texture, flexibility, density, and mass.

Answer:

The potential of the Standard Hydrogen Electrode (S.H.E.) under the given conditions would be approximately 0.070 volts.

Explanation:

To determine the potential of a Standard Hydrogen Electrode (S.H.E.), we need to consider the Nernst equation, which relates the electrode potential to the concentrations of the species involved. The Nernst equation is given as:

E = E° - (RT/nF) * ln(Q)

Where:

E is the electrode potential

E° is the standard electrode potential

R is the ideal gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin

n is the number of electrons transferred in the balanced redox equation

F is the Faraday constant (96,485 C/mol)

Q is the reaction quotient (ratio of products to reactants)

In the case of the S.H.E., the standard electrode potential (E°) is defined as 0 volts.

Given that the hydrogen ion concentration ([H+]) is 0.21 M, the hydrogen gas pressure (pH2) is 3.2 atm, and the temperature (T) is 298 K, we can use these values to calculate the potential of the S.H.E.

First, we need to calculate the reaction quotient (Q). In the case of the S.H.E., the reaction is the reduction of protons (H+) to hydrogen gas (H2):

Q = [H+] / pH2

Substituting the given values:

Q = 0.21 M / (3.2 atm)

Now, we can substitute the values into the Nernst equation:

E = 0 V - (8.314 J/(mol·K) * 298 K / (2 * 96,485 C/mol) * ln(0.21 M / (3.2 atm))

Calculating this expression:

E ≈ 0 V - (0.0257 V) * ln(0.0656)

E ≈ 0 V - (0.0257 V) * (-2.7207)

E ≈ 0 V + 0.070 V

E ≈ 0.070 V

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B. Mg is the element contains 4.95×10234.95×1023 atoms.

To identify the element from the given information, we need to use the concept of molar mass and Avogadro's number. The molar mass of an element is the mass of one mole of its atoms, and Avogadro's number is the number of atoms in one mole of a substance.

First, we can calculate the number of moles of the element in the sample using the formula:

moles = number of atoms / Avogadro's number

Substituting the given values, we get:

moles = 4.95×10^23 / 6.022×10^23

moles = 0.821

Next, we can calculate the molar mass of the element using the formula:

molar mass = mass / moles

Substituting the given values, we get:

molar mass = 20.0 g / 0.821 mol

molar mass = 24.36 g/mol

Finally, we can use the periodic table to identify the element that has a molar mass of approximately 24.36 g/mol. Among the choices given, only magnesium (Mg) has a molar mass close to this value (24.31 g/mol).

Therefore, the element in the sample is magnesium (Mg).

In summary, the given information allows us to calculate the number of moles and molar mass of the element, which can be used to identify the element using the periodic table. This type of calculation is commonly used in analytical chemistry to determine the identity and composition of unknown samples. Therefore, Option B is correct.

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If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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Answer:

6

Explanation:

The given reaction is aluminium with hydrochloric acid

2Al + 6HCl → 2AlCl3 + 3H2

the product is aluminium chloride and hydrogen gas.

We can clearly, calculate that there are 2*3=6 chlorine atoms in product side of the reaction.

Answer:

C. 6

Edg2021

Explanation:

Person is right.

Answer:

a weak acid consist of mostly non ionized acid molecule

H+ appear on left hand side and the coefficient is 16 in the balanced redox reaction under acidic aqueous conditions.

What is redox reaction?

Redox reactions, also referred to as oxidation-reduction processes, are reactions in which electrons are transferred from one species to another. An oxidized species is one that has lost electrons, whereas a reduced species has gained electrons.

The balanced redox reaction under acidic aqueous conditions using the smallest whole-number coefficients is written as

\(2MnO+16H^{+} +10I^{-}\) →  \(2Mn2^{+} + 8H_{2} O + 5I^{2}\)

Therefore, the H+ is present on left side with a coefficient of 16 in the balanced redox reaction under acidic aqueous conditions.

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Answer:

6

Explanation:

if there is 10n and the friction is 4n on the table then it is 6n.

i hope this helps you! :)

Answer: I believe you are talking about the world's first recorded nuclear explosion that took place on the plains of the Jornada del Muerto Dessert.

Explanation: It is to be noted that the Trinity site is still considered to be radioactive, and Trinitite which is a green glass-like substance is found abundantly in the area. Trinity was an atmospheric test conducted by the U.S. Army on July 16th of 1945. The site was chosen because of its isolated, flat grounded, non-windy lands. This experiment was so tightly gatekept that not even the military policemen whom rode with it knew of its contents.

Answer:

4.9 m^3

Explanation:

volume= 1.0 x 3.25 x 1.50= 4.875 -> 4.9m^3

Answer:

True

Explanation:

Given that

• T1 = 290K,

• T2 = 250K

• V1 = 1L

• V2=...?

We will use Charles's law formula to determine the resulting volume

V1 / T1 = V2 / T2.

→V2 = (V1*T2 )/T1

=1*250/290

=0.86 L

This is true because when temperature decreases , volume also decreases .

Answer:

dilute sulphuric acid has less no. of h +ions so it can't react properly

The final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l will be 475 K.

The volume as well as Kelvin temperature will be directly proportional whenever the pressure on even a sample of such a dry gas remains held constant. PV = k would be the law's equation.

Charle's law give the relation between the temperature and volume is shown as:

\(V_{1} / T_{1} = V_{2} / T_{2}\)

where. V is volume and T is temperature.

Given data :

\(V_{1} =22.4 l\\V_{2} = 38.3 l\\T_{1} = 278 K\\T_{2} = ?\)

Put the value of given data in above equation.

22.4 l /   38.3 l = 278k / \(T_{2}\)

\(T_{2}\) = 475 K.

Therefore, the final temperature will be 475 K.

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The solubility at 25 °C of Zn(OH)₂ in pure water is 5.18 x 10⁻³⁸ M, and in a 0.0050 M ZnSO₄ solution, it is 7.20 x 10⁻⁴⁹ M.

What is solubility?

Solubility refers to the ability of a substance, known as the solute, to dissolve in a solvent and form a homogeneous mixture called a solution.

The chemical equation for the dissolution of Zn(OH)₂ in water is:

Zn(OH)₂(s) ⇌ Zn²⁺(aq) + 2OH⁻(aq)

The Ksp expression for the dissolution of Zn(OH)₂ is:

Ksp = [Zn²⁺][OH⁻]²

Substituting these concentrations into the Ksp expression, we get:

Ksp = (x)(2x)² = 4x³

Solubility in pure water (H₂O):

Since the solubility product expression is given by Ksp = 4s³, and we know that x represents the solubility, we can substitute the value of x into the equation:

4x³ = 4(6.0 x 10⁻¹³)³

Calculating this, we find:

4x³ ≈ 5.18 x 10⁻³⁸

Therefore, the solubility of Zn(OH)₂ in pure water at 25°C, rounded to 2 significant digits, is approximately 5.18 x 10⁻³⁸ M.

Solubility in a 0.0050 M ZnSO₄ solution:

Using the same solubility product expression, we can substitute the concentration of Zn²⁺ from the ZnSO₄ solution, which is 0.0050 M, into the equation:

4s³ - (0.0050) * (4s)² = 0

4(6.0 x 10⁻¹³)³ - (0.0050) * 4(6.0 x 10⁻¹³)² = 0

Calculating this, we find:

4s³ ≈ 7.20 x 10⁻⁴⁹

Therefore, the solubility of Zn(OH)₂ in the 0.0050 M ZnSO₄ solution at 25°C, rounded to 2 significant digits, is approximately 7.20 x 10⁻⁴⁹ M.

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