Answers
The question is incomplete. Here is the complete question.
A baseball palyer hits a 5.1 oz baseball with an initial velocity of 140ft/sat an angle of 40° with the horizontal as shown. Determine
a) The kinetic energy of the ball immediately after it is hit
b) The kinetic energy of the ball when it reaches its maximum height
c) The maximum height above the ground reached by the ball.
Answer: a) KE = 131.64 J
b) KE = 0
c) h = 126 ft
Explanation: Kinetic energy is the energy an object posses due to its motion. It can be calculated as \(KE=\frac{1}{2}mv^{2}\)
a) Kinetic energy's unit is Joule. So, we have to transform ounce in kg and ft/s in m/s for the units to correspond:
m = 5.1(0.02835)
m = 0.1445 kg
v = 140 ft = 42.67 m/s
Then, kinetic energy is
\(KE=\frac{1}{2}(0.1445)(42.67)^{2}\)
KE = 131.64 J
Kinetic energy immediately after the ball is hit is 131.64 J.
b) At its maximum height, the ball has its highest potential energy. Because of the law of conservation of energy, when potential energy is maximum, kinetic energy is minimum and vice-versa. So, at the maximum height, kinetic energy is 0.
c) This type of motion is projectile motion. The maximum height on a projectile motion can be determined by
\(v_{y}^{2}=v_{0y}^{2}-2g\Delta y\)
When h is maximum, \(v_{y}=0\)
Velocity of the ball has an angle with the horizontal, so initial velocity at the y-axis is
\(v_{0y}=v_{0}sin(\theta)\)
Substituting and solving
\(v_{y}^{2}=v_{0}^{2}sin^{2}(\theta)-2gh\)
\(0=(42.67)^{2}sin^{2}(40)-2(9.8)h\)
\(19.6h=(42.67)^{2}(0.643)^{2}\)
\(h=\frac{(1820.73)(0.4132)}{19.6}\)
h = 38.4 m
Transforming into ft: h = 126 ft
The maximum height above the ground reached by hte ball is 126 feet.
Related Questions
Star A has a magnitude of 1.0 and is 60 times brighter than B. What is magnitude of B?
Answers
Answer:
The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:
Brightness ratio = 2.512^(magnitude difference)
60 = 2.512^(magnitude of A - magnitude of B)
Taking the logarithm base 2.512 of both sides:
log base 2.512(60) = magnitude of A - magnitude of B
Solving for the magnitude of B:
magnitude of B = magnitude of A - log base 2.512(60)
magnitude of B = 1.0 - log base 2.512(60)
Calculating the value:
magnitude of B ≈ 1.0 - 2.799
magnitude of B ≈ -1.799
Therefore, the magnitude of Star B is approximately -1.799.
Explanation:
Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.
Explanation:To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.
Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.
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Which type of wave has a wave perpendicular to the disturbance?
A. mechanical
B. transverse
C. surface
D. longitudinal
Answers
Answer:
B. transverse
Explanation:
The type of wave that has a perpendicular wave to the disturbance is transverse wave
To perform this maneuver, the dancer relies on the fact that the position of her center of gravity
A. Is near the center of the torso.
B. Is determined by the positions of her arms and legs.
C. Moves in a horizontal path.
D. Is outside of her body.
Answers
option (B) is correct answer.
What is acceleration due to gravity ?
Gravitational acceleration is the acceleration experienced by an object due to gravity. Its SI unit is m/s2. It is vector magnitude because it has both magnitude and direction. The standard value of g on the surface of the earth at 0m above sea level is 9.8m/s2. Suppose an object [test mass (m)] is moved from a height "h" above the ground [source mass (M)], and as it approaches the ground it begins to move downwards, increasing its velocity. We know that the velocity of an object changes only under the action of a force. In this case the force is provided by gravity.
Under the action of gravity, the object begins to accelerate towards the center of the earth. The center of the Earth is at a distance "r" from the test mass. Then ma = GMm/r2 (applies the equivalence principle)
⇒ a = GM/r2 . . . . . . (1)
The above acceleration is due to the earth's gravitational pull, so we call it the gravitational acceleration and it does not depend on the test mass. The value near the ground is 9.8 ms-2. Therefore the acceleration due to gravity (g) is given by = GM/r2.
The dancer relies the position of center center of gravity is determined by the Positions of her arms and legs.
Hence option (B) is correct answer.
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There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of this cliff. What is the velocity of the boulder just before it strikes the ground?
Answers
Answer:
Vf = 69.61 m/s
Explanation:
We will use the third equation of motion to solve this problem:
\(2gh = V_{f}^2 - V_{i}^2\\\)
where,
g = acceleration due to gravity = 9.81 m/s²
h = height of cliff = 247 m
Vf = final velocity = ?
Vi = initial velocity = 0 m/s (boulder breaks loose from rest)
Therefore,
\((2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\\)
Vf = 69.61 m/s
Lab Report Sun, Earth, and Moon Models It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U5_ Lab_SunEarthAndMoonModels_Alice_Jones.doc). Introduction 1. What was the purpose of the investigation? Type your answer here: 2. What causes the bright part of the moon to appear bright? Type your answer here: Experimental Methods 1. What materials did you use to create your model? Type your answer here: 2. Describe how you created your model. Type your answer here: Develop a Model 1. Show your model and the relationships between the components. Include labeled pictures or diagrams that describe causal accounts for the phases of the moon and eclipses. Type your answer here: Use a Model 1. Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Type your answer here: 2. Use your model to explain why a lunar eclipse does not occur every month when there is a full moon. Type your answer here:
Answers
1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.
2. The bright part of the moon appears bright due to the reflection of sunlight.
Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.
Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.
Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.
Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.
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True or False: A rough rock will absorb more radiant energy than a smooth rock
Answers
I’d say it’s False
What do virtually all daily task require ?
Answers
Answer:muscle strength
Explanation: bc well you would need it
A satellite has a mass of 6463 kg and is in a circular orbit 4.82 × 105 m above the surface of a planet. The period of the orbit is 2.0 hours. The radius of the planet is 4.29 × 106 m. What would be the true weight of the satellite if it were at rest on the planet’s surface?
Answers
Answer:
The weight of the planet is 29083.5 N .
Explanation:
mass of satellite, m = 6463 kg
height of orbit, h = 4.82 x 10^5 m
period, T = 2 h
radius of planet, R = 4.29 x 10^6 m
Let the acceleration due to gravity at the planet is g.
\(T = 2\pi\sqrt\frac{(R+h)^3}{gR^2}\\\\2\times 3600 = 2\times3.14\sqrt\frac{(4.29+0.482)^3\times10^{18}}{g\times 4.29\times 4.29\times 10^{12} }\\\\24.2 g =108.67\\\\g = 4.5 m/s^2\)
The weight of the satellite at the surface of the planet is
W = m g = 6463 x 4.5 = 29083.5 N
What is the surface area of the right cone below?
OA. 63 units²
15
OB. 99 units²
O C. 126 units²
13
OD. 54 units²
Answers
Answer:
option d is the answer of given statement
The surface area of the right cone is 54π units². Hence option D correct.
What is Surface Area ?The surface area of a solid object is a total area measured that the surface of the object occupies. the surface area of the cube is 6 times side², cause it has 6 faces.
The surface area is total area occupied by the surface of the object.
A cone is geometrical shape which is having circular base and cone shaped body. when a line is drawn from tip to the center of the base it will make right angle between radius and height of the cone. We can apply Pythagoras theorem to get values of radius, height and hypotenuse.
The total area of the cone is nothing but area of the base plus curved area of the body.
Hence area of the cone is,
A = πr²+πr\(\sqrt[]{r^{2}+h^{2} }\)
Given,
r = 3
hypotenuse = \(\sqrt[]{r^{2}+h^{2} }\) = 15
A = ?
A = π3²+π3*15
A = π (9+45)
A = 54π units²
Hence area of the cone is 54π units².
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Imagine you have three flashlights. One has a blue light, one has a green light and
one is red. If you were to shine each of those lights in the same spot, what color do
you think you would see? Explain.
Answers
Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
What is the visible spectrum?
At one end of the electromagnetic wave line, which has the group of the visible spectrum. This has been referred to as the visible light of the spectrum. The visible light with the shortest of the wavelength has the blue light and the one with the longest has the red light.
The primary colors of the light has been the spectrum are red, blue, and green. The combination of these colors will form other as well as the colors which has been referred to as the secondary colors. The combination of the beam of the red light and the beam of green light will form yellow color.
Therefore, Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
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A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
Answers
Answer:
3.88 × 10^-4 m
Explanation:
Given that a person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
The total weight = 614 + 85
The total weight = 699N
Let the total area of contact = A
Pressure = Force / A
Substitute all the parameters into the formula
900000 = 699 /A
A = 699 / 900000
A = 7.77 × 10^-4 m
The area of contact between each tire and the ground will be = A/2
That is, 7.77 / 2 = 3.88 × 10^-4 m
Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.
Mr. Bissell creates a diagram of electric and magnetic fields to teach his students about the concepts. He includes the similarities and differences between the fields on the diagram. Which of the following statements should he add about the similarities between the two fields?
Answers
The similarity between electric field and magnetic field is that both fields attract or repel charges in the field.
What is an electric field?
The force per unit charge that a vanishingly small positive test charge would experience if held fixed at a given point in space is the definition of the electric field at that location.Since force is a vector (i.e., having both magnitude and direction), and the electric field is defined in terms of force, it follows that an electric field is a vector field.The term "force field" is occasionally used to describe fields that can be defined in this way.The gravitational field between two masses and two charges behaves similarly, with both obeying an inverse-square law as the distance between them increases.To know more about electric field, click the link given below:
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every magnet has two poles which can be separated true or false
Answers
Answer:
true it
Explanation:
glade it cannot be speretated
lectric Charges
The glass is attracting the pieces of paper. What does
this tell you about the charges on the glass and the
paper?
The glass and the paper have the same charge.
O The glass and the paper have different charges.
ONeither the glass nor the paper has a charge.
Answers
In Fig. 2-2, what is the acceleration at 1.0 s?velocity (m/s)2010time (s)02.010physics graph 2- 10-20Figure 2-2
Answers
Given:
The velocity is v = 10 m/s
The time is t = 1 s
To find the acceleration
Explanation:
The acceleration can be calculated by the formula
\(a\text{ =}\frac{v}{t}\)On substituting the values, the acceleration will be
\(\begin{gathered} a=\frac{10}{1} \\ =10\text{ m/s}^2 \end{gathered}\)Thus, the acceleration will be 10 m/s^2
Imagine a proton at rest a certain distance from a negatively charged plate. It is released and collides with the plate. Then imagine the similar case of an electron at rest, the same distance away, from a plate of equal and opposite charge. In which case would the moving particle have the greater speed when the collision occurs
Answers
Answer:
v_e »v_proton
Explanation:
To analyze which body has more energy, let's use the concepts of energy
starting point. Before releasing the particle
Emo = U = e V
final point.
Em_f = K = ½ m v²
energy is conservative
Em₀ = em_f
eV = ½ m v²
v² = 2eV / m
we see that the velocity of the body is inversely proportional to the mass of the atom.
For the present cao the mass of the proton is much greater than the mass of the electron
which
v_e »v_proton
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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A Cambra pouce car traveling at 28 m/s slow
at a rate of at 3.6 m/s every second find.
a) The time taken for the police car to come to Stop?
Answers
Answer:
t = 7.8 seconds
Explanation:
Given that,
The initial speed of the car, u = 28 m/s
Acceleration of the car, a = 3.6 m/s²
We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.
\(v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s\)
So, the required time is 7.8 seconds.
A cannonball is fired horizontally from a 10 m high cliff at 20 m/s. How long will the cannonball be in the air? How far away will the cannonball strike the ground?
Answers
Answe ¡Buenos días! –
#3 ¡Buenas tardes! –
#4 ¡Bienvenid
if a bus drives 2km due east,5km 45 degrees north of east, 4km at 30 degrees north of west, then 2km due south. what is the bus's resultant displacement?
Answers
The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.
The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.
The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km
The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km
The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.
Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km
The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km
The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east
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In a showdown on the streets of Laredo, the good guy drops a 5.00-g silver bullet at a temperature of 20.0°C into a 100-cm' cup of water at 90.0°C. Simultaneously, the bad guy drops a 5.00-g copper bullet at the same initial temperature into an identical cup of water.
Which one ends the showdown with the coolest cup of water in the West? Neglect any energy transfer into or away from the container.
Answers
The silver would be coolest since it has the lowest heat capacity.
What is the heat capacity?Heat capacity, also known as thermal capacity, is the amount of heat energy required to raise the temperature of a substance by a certain amount. It is expressed as the amount of heat energy per unit temperature change, and is usually measured in joules per kelvin (J/K) or calories per degree Celsius (cal/°C).
Heat capacity is a key property of materials that provides important information about their thermal behavior and is critical for many areas of science and technology.
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4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
Answers
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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An airplane is flying through a thundercloud at a height of 2010 m. (A very dangerous thing to do because of updrafts, turbulence, and the possibility of electric discharge.) If there is a charge concentration of 46.9 C at height 4090 m within the cloud and −59.7 C at height 570 m, what is the magnitude of the electric field E at the aircraft? The Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of V/m.
Answers
Answer:
The value is \(E = 3.5619 *10^{5} V/m \)
Explanation:
From the question we are told that
The height of the airplane is \(h = 2010 \ m\)
The first charge concentration is \(Q = 46.9 \ C\)
The height of the first charge concentration is \(h_1 = 4090 \ m\)
The second charge concentration is \(Q_2 = −59.7 \ C\)
The height of the second charge concentration is \(h_1 = 570 \ m\)
The electric field due to the first charge concentration is
\(E_1 = \frac{k * |Q_1|}{(h_1 -h)^2}\)
Here k is the Coulomb constant given in the question
\(E_1 = \frac{8.98755*10^9 * |46.9|}{(4090 - 2010)^2}\)
\(E_1 = 9.7429 *10^{4} \ V/m\)
The electric field due to the second charge concentration is
\(E_2 = \frac{k * |-59.7|}{(h -h_2)^2}\)
\(E_2 = \frac{8.98755*10^9 * |-59.7|}{(2010 - 570)^2}\)
\(E_2 = 2.5876 *10^{5} V/m\)
Generally the superposition principle can be applied in this question as follows
\(E = E_1 + E_2\)
=> \(E = 9.7429 *10^{4}+ 2.5876 *10^{5} \)
=> \(E = 3.5619 *10^{5} V/m \)
Blue light with a wavelength of 4.57 E-7 m is used in Young's experiment with the slits separated by a distance of 2.42 E-4Y
m. The screen is located at a distance from the slits of 4.5 m. Calculate the distance on the screen between the central
bright fringe and the first bright fringe. Show all work for full credit.
Answers
The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.
In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:
y = (m * λ * L) / d
where:
y is the distance between the fringes on the screen,
m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),
λ is the wavelength of the light,
L is the distance from the slits to the screen, and
d is the distance between the slits.
Given the values:
λ = 4.57E-7 m (blue light wavelength)
d = 2.42E-4 m (distance between the slits)
L = 4.5 m (distance from the slits to the screen)
For the central bright fringe (m = 0), the distance (y) is:
y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y = 0
Therefore, the central bright fringe coincides with the point where the two beams of light overlap.
For the first bright fringe (m = 1), the distance (y) is:
y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y ≈ 8.52E-3 m
This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.
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A cannon is evaluated at an angle of 45 degree. It fires a ball with a speed of 300 m/s. What is the horizontal range of the ball
Answers
Answer:
The horizontal range of the cannonball is 9180.4 meters.
Explanation:
The horizontal range of a cannonball can be calculated using the following formula:
range = (speed * speed * sin (2 * angle)) / acceleration due to gravity
In this case, we are given that the cannon is fired at an angle of 45 degrees and that the speed of the ball is 300 m/s. We can plug these values into the formula to calculate the horizontal range of the ball:
range = (300 * 300 * sin (2 * 45)) / 9.8
= (90000 * sin (90)) / 9.8
= (90000 * 1) / 9.8
= 9180.4 m
A shopping mall is putting up lights for the holidays. When they plug the holiday lights in they do not light up.
What kind of circuit are the Christmas lights on?
What can the employees do to make the lights work?
Answers
Answer:
Explanation:
Remark
Anybody who has dealt with Christmas Tree lights knows what can be done. You must take a bulb you know to be good and try each bulb in turn until the whole string lights up. If two bulbs are dead, give up and go buy another string. Two bulbs create a lot of combinations.
The circuit is a series circuit.
provident fund Rs. 100.000,
and income tax Rs. 70,000 through cheque No. 0155
Prepare Goshwara Vouchers (AGF No. 10) of District Agriculture Development Office
Bhaktat
the following
2075/01/2
10.000 a
Mrs. Devmaya who had taken Rs. 20,000 for machinery advance
returned whole amount through bank voucher and cleared her
advance
Bank order letter of Rs. 300,000 was received as additional revolvin
fund release.
Issued a cheque of Rs. 179,000 for distribution of salary for the mont
after deducting Rs. 40,000 for provident fund and Rs. 1,000 for incom
2075/01/7
000 W
icher of
2075/01/28
tax.
17 was
d.
2075/01/29
2075/01/29
Rs. 30,000 paid in advance to Account Officer Mr. Ranjan Khakur
for the purchase of office chair through cheque No. 04891.NO
Paid rent to house owner for the month of Baishakh, Jestha, Asha
Rs. 30,000 through cheque No. 00255. LAD - I. HOUSCAE
23 0000
20005
- Advance
ODO
CNIB
179ooo
or Br Salady
con PF
3- Income toy
NRS
Answers
Answer:
whatz dis 4
Explanation:
A student is using two circuits to investigate power consumption. She connects two identical light bulbs in series in one circuit and in parallel in the second circuit. What should she measure to calculate which configuration uses more power?
Responses
A The resistance of the bulbs and the potential difference of the battery.The resistance of the bulbs and the potential difference of the battery.
B The current flowing into each bulb and the potential difference across each bulb.The current flowing into each bulb and the potential difference across each bulb.
C The current flowing out of the battery and the resistance of each bulb.The current flowing out of the battery and the resistance of each bulb.
D The potential difference of the battery and the resistance of the battery.
Answers
The potential difference across the each bulb and the current entering each bulb.
What occurs if you connect two light bulbs in series?Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.
When are two identical bulbs linked in both series and parallel?The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.
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What does the elasticity (stretchiness) of the resistance band determine?
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The resistance band's elasticity (stretchiness) dictates how easily it can be stretched or can be flexible.
What does the resistance band's elasticity determine?It is the proportion of tensile stress to strain, where strain is the amount of deformation and tensile stress is the tension force applied to a surface area (amount of stretch of the resistance band).
Instead than requiring you to hold additional weight per se, resistance bands function by providing an external resistance force that can be imposed. They are flat, occasionally looping bands that might be thin or thick.
Both rubber bands and springs have a unique quality. The stretch distance affects how hard a band pulls back. The spring constant, denoted by the symbol k (in units of N/m), is a proportionality constant.
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Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between them.
1 ) Find the magnitude of the net gravitational force exerted by the two larger masses on the 74.8 kg mass.
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2 /kg^2.
Answer in units of N.
2 ) Leaving the distance between the 141 kg and the 494 kg masses fixed, at what distance from the 494 kg mass (other than infinitely remote ones) does the 74.8 kg mass experience a net force of zero?
Answer in units of m.
Answers
( 1) The net gravitational force between the 74.8 kg mass is 8.09 x 10⁻⁵ N.
( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.
What is net gravitational force on the middle mass?The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.
F = ( GmM ) / ( R² )
where;
G is universal gravitation constantm is the mass of the middle massM is the mass of the first massR is the distance of separation between the two massesThe force between the first mass and the middle mass is calculated as;
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )
F' = 1.8 x 10⁻⁵ N
The force between the third mass and the middle mass is calculated as;
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )
F'' = 6.29 x 10⁻⁵ N
The net gravitational force on the middle mass;
F (net) = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N
F ( net ) = 8.09 x 10⁻⁵ N
Let the distance of zero net force from the 141 kg mass = d.
then the distance from the 494 kg mass = 0.396 m - d
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )
F' = 0.704 x 10⁻⁶ / d²
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²
F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²
for zero net force, the two forces must be equal
0.704 x 10⁻⁶ / d² = 2.47 x 10⁻⁶ / ( 0.396 - d )²
0.704 (0.396 - d )² = 2.47d²
(0.396 - d )² = ( 2.47d² ) / ( 0.704 )
(0.396 - d )² = 3.51d²
0.396 - d = √ ( 3.51d² )
0.396 - d = 1.87d
1.87d + d = 0.396
d (1.87 + 1) = 0.396
d (2.87) = 0.396
d = 0.396 / 2.87
d = 0.138 m
The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m
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