Did the control experiment verify or refute the results from exercise 1? use your results from exercises 1 and 2 to validate your answer.

Experiment 1 E Data Table 1 B Data Table 2 Data Table 1: Antacid Neutralization Data Mass of 0. 59 Crushed Antacid (9) Concentration 1. 0 of HCI (M) Volume HCI 5. 0 (mL) Concentration 1. 0 of NaOH (M) Initial NaOH 9. 4 mL Volume (mL) Final NaOH 8. 2 mL Volume (mL) Total Volume 1. 2 mL of NaOH Used (mL) Experiment 1 Data Table 1 Data Table 2 Data Table 2: Experimental Results I 0. 1825 g 0. 0012 HCl available for neutralization (g): Moles of NaOH required to reach stoichiometric point (mol): HCI neutralized by antacid (g): НСІ neutralized per gram of antacid (9) 0. 1387 0. 2774 Experiment 2 El Data Table 3 B Data Table 4 Data Table 3: Control Experiment Data Concentration 1. 0 of HCI (M) Volume HCI 5. 0 (mL) Concentration 1. 0 of NaOH (M) Initial NaOH 9. 2 mL Volume (mL) Final NaOH 3. 6 mL Volume (mL) Total Volume 5. 6 mL of NaOH Used (mL) Data Table 4: Control Experiment Results 0. 2049 Moles of 0. 0056mol NaOH needed to neutralize 5. 0 mL of 1. OM HCI (mol): Grams of HCI neutralized (g): NaOH 4. 4mL volume difference between back titration and control (ml): Grams of 0. 160g HCI neutralized by NaOH volume difference (9)

Answer: signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.

Explanation:

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The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.

The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):

E = V * Q

Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):

Q = E / V

Substituting the given values, we have:

Q = 64 MJ / 330 V

To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:

Q = (64 * 10^6 J) / 330 V

Calculating the division:

Q ≈ 193,939.39 Coulombs

Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.

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All of the properties such as ice floating on water, while most solids would sink when placed in its liquid are all due to the structure of the compounds.

The structure of the compounds includes the bonding angle, the type of bonds, the size of the molecule,  the interactions between the molecules etc.  Slight changes in the chemical structure and affect the properties if the compound.

Isomeric compounds with the same  chemical formula but different structures can have different melting and boiling point and differ in reactivity and flammability.

Another common change in isomers are with the double bonds.  A double bond can be in the cis formation or in the trans formation, and this will affect its properties as trans isomers will be having high melting point than the cis isomer.

Thus, structure of compounds  do determine the properties of the compounds.

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Answer:

20/1000=0.02    denity+mass divided by volume

Answer:

TRUE :)

Explanation:

blood is pumped through the pulmonary artery to the lungs, where it picks up oxygen and releases carbon dioxide.

Answer:

False

Explanation:

it takes it to tha lungs.

Answer: 2,3 and 5

Explanation:

Answer:

B. Less humidity

C. No precipitation

E. Cooler temperatures

( Hope this helps ) <3    ( Give person above brainliest )

(a) Prandtl number:Prandtl number is a dimensionless quantity, and it represents the ratio of momentum diffusivity to thermal diffusivity. It is usually represented as Pr = v/α, where v is kinematic viscosity and α is thermal diffusivity. It is one of the key parameters that determine the flow characteristics of fluids. The Prandtl number can be determined by the following formula:Pr = μ*Cp/k = 0.001 * 1000 / 1 = 1The Prandtl number is 1.(b) Hydrodynamic and Thermal Boundary Layer:Thermal boundary layer and hydrodynamic boundary layer are the two types of boundary layers. The thermal boundary layer and hydrodynamic boundary layer have different lengths in fluid flow over a flat plate, and the thermal boundary layer is always longer than the hydrodynamic boundary layer because of the low thermal conductivity of the fluid.The ratio of the length of the thermal boundary layer to the length of the hydrodynamic boundary layer can be expressed as:δt/δ = (Pr)^1/2Where δt is the length of the thermal boundary layer, δ is the length of the hydrodynamic boundary layer, and Pr is the Prandtl number. The Prandtl number is greater than 1 for fluids with high viscosity and low thermal conductivity, and the thermal boundary layer is larger than the hydrodynamic boundary layer.Therefore, there is a relationship between the hydrodynamic and thermal boundary layer, and it is directly proportional to the square root of the Prandtl number. In summary, the thermal boundary layer and hydrodynamic boundary layer are related, and the Prandtl number plays a key role in their relationship.

Answer:

i think its 8

Explanation:

O4 is 4 oxygen  and then its doubled with the 2 at the end

Answer:

than what can i do lol

Answer:

Both are only physical changes

Boyle's Law relates pressure and volume of a fixed amount of gas at constant temperature; they are inversely related.

Boyle's Law, named after the scientist Robert Boyle, describes the relationship between pressure and volume of a gas. According to this law, if the temperature remains constant, the pressure and volume of a given amount of gas are inversely proportional to each other. This means that as the volume of a gas increases, the pressure decreases, and vice versa.

The mathematical expression for Boyle's Law is P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume. Boyle's Law is fundamental in understanding the behavior of gases and is used in various applications, such as in the study of gas behavior and in the design of ventilation systems.

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When you buy a municipal bond for $10,000 with a 4% interest rate and hold it until maturity in 10 years, you would typically receive interest payments semiannually.

Municipal bonds usually pay interest on a semiannual basis, meaning you receive two payments each year. To calculate the interest payment amount, you would divide the annual interest rate by 2, as you receive payments every six months. In this case, the annual interest rate is 4%, so the semiannual interest rate would be 2% (4% divided by 2). To determine the interest payment amount, you would multiply the bond's face value ($10,000) by the semiannual interest rate (2%). Thus, each interest payment would amount to $200 ($10,000 multiplied by 2%).

Over the course of 10 years, you would receive a total of 20 interest payments (2 payments per year for 10 years). Therefore, the cumulative interest payments would amount to $4,000 ($200 per payment multiplied by 20 payments). It's important to note that municipal bond interest payments and terms can vary, so it's essential to review the specific details of the bond before making any investment decisions.

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Answer:

I believe it's because it's based on gravity

Explanation:

mass is like your true weight while weight is your mass and some equation with gravity. it's been a few years

Answer:

When baking soda is mixed with vinegar, something new is formed. The mixture quickly foams up with carbon dioxide gas. If enough vinegar is used, all of the baking soda can be made to react and disappear into the vinegar solution.

Explanation:

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Elements on the right side of the periodic table are mostly Non - metals.

And Nonmetals exist in all three states of matter. The majority are gases, such as nitrogen and oxygen. Bromine is a liquid. A few are solids, such as carbon and sulfur.

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The E° for cell reaction is - 2.37 V and  2.23 V and E for cell reaction  = 2.22V and ΔG = - 428.39kJ/mol.

The formula for solving the equation for given cell is as follows :

                      E°cell , Ecell and Δ\(G_{rnx}\)

The standard cell potential is the potential of cell at standard condition of 1MConcentration and pressure 1 atm E°cell

calculation :

                E°cell = E° cathode - E° anode          it is calculated using the Nernst equation which is discussed below :

                  Ecell = E°cell -- \(\frac{RT}{nF}\) 1n K  = E°cell -- \(\frac{0.0591}{n}\)log \(\frac{Products}{Reactants}\)

Here, F is the Faraday's constant, R is the gas constant, T is the temperature, and n is the number of transferred electrons. K is the equilibrium constant.

The Gibbs free energy is the greatest work that is finished by a framework . The standard cell potential is without like energy by the recipe as follows;and F is Faraday's steady.

A system's maximum amount of work is referred to as its Gibbs free energy. The standard cell potential is connected with the free energy by the recipe as follows:    Δ G = -n F Ecell

Here, E cell is cell potential

Δ G is the free energy n is the quantity of electrons moved and F is Faraday's steady.

 Oxidation :                                        

Mg ⇒ Mg ²⁺ + 2e⁻ E⁰anode = - 2.37 V

Reduction:Sn²⁺ + 2e⁻⇒ Sn E⁰

So,  cathode = - 0.14V

The standard cell potential is calculated as follows:E⁰ cell = - 0.14 V- (- 2.37 V ) =  2.23 V

The half reaction potentials for the oxidation and reduction are determined. They are subbed in the equation and the standard cell potential is determined.

Number of electrons transferred ,      n = 2   ,[Mg²⁺]   = 0.055M   ,  [ Sn²⁺ ]  = 0.030 M               The Nernst equation for reaction :

Ecell = E °cell = \(\frac{0.0591}{n}\)log Mg ²⁺ / Sn²⁺

The cell potential for reaction is :

                       Ecell = 2.23V - \(\frac{0.0591}{2}\)log\(\frac{0.055M}{0.030M}\)= 2.22V

 The values are substituted for the reaction calculated here in the Nernst equation and cell potential.     

Calculation for the free energy for reaction ,

                                             ] Δ\(G_{rxn}\) = -nFE cell

       = - 2 × 96485 C/ mol ×2.22 V

                          = --428393J/mol × \(\frac{1KJ}{1000J}\)  = - 428.39kJ/mol

The cell potential for the response is subbed in the recipe and free energy for the response is determined

Nernst equation :

The standard electrode potential, absolute temperature, the number of electrons involved in the redox reaction, and activities (often approximated by concentrations) of the chemical species undergoing reduction and oxidation, respectively, can all be used to calculate the reduction potential of a half-cell or full cell reaction using the Nernst equation, a chemical thermodynamic relationship.

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Answer:

20.76 L OF CO2 WILL BE PRODUCED BY 45 G OF METHANE.

Explanation:

Equation of the reaction:

CH4 + 02 --------> CO2 + 2H20

Molar mass of methane = ( 12+ 1*4) g/mol = 16 g/mol

Calculate the number of moles present in 45 g of methane

1 mole of methane = 16 g / mol of methane

(45 / 16) mole of methane = 45 g of methane

= 2.8125 moles

Using the ideal gas equation:

PV = nRT

P = 1 atm

n = 2.812 moles

T = 90 C

R = 0.082 L atm/ mol C

V = unknown

So we have:

V = nRT / P

V = 2.8125 * 0.082 * 90 / 1

V = 20.756 L

In the production of CO2 by 45 g of methane, 20.756 L of methane was used.

Then, the volume of CO2 produced by this volume will be 20.756 L since 1 mole of methane produces 1 mole of CO2.

In other words;

1 mole of CH4 = 1 mole of CO2

22.4 dm3 of CH4 = 22.4 dm3 of CO2

20.76 DM3 = 20.76 dm3

The volume of CO2 produced will therefore be 20.76 L

Answer:

B

Explanation:

The concentration of [OH-] in a 0.500 M solution of aqueous ammonia is 2.95 x 10^-3 M.

To calculate the [OH-] of a 0.500 M solution of aqueous ammonia, we need to use the equilibrium constant expression for the reaction of ammonia with water:
NH3 (aq) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)
The Kb value given is for the reaction:
NH3 (aq) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)
Kb = [NH4+][OH-]/[NH3]
We are given the concentration of NH3, so we can solve for [NH4+] and [OH-].
Kb = 1.74 x 10^-5
[NH3] = 0.500 M
[NH4+] = [OH-] = x (let the concentration of NH4+ and OH- be x)
Kb = [NH4+][OH-]/[NH3]
1.74 x 10^-5 = x^2/0.500
x^2 = 8.7 x 10^-6
x = 2.95 x 10^-3 M

The [OH-] in a 0.500 M solution of aqueous ammonia is 2.95 x 10^-3 M. The solution is obtained by using the equilibrium constant expression for the reaction of ammonia with water. The Kb value given is used to solve for the concentration of NH4+ and OH-. The [OH-] concentration is equal to the concentration of NH4+. By using this method, we can easily calculate the [OH-] of aqueous ammonia solutions with different concentrations.

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Answer:

It is polar bond

The description is given below u will be more clear about it

Explanation:

Non polar bonds form between two atoms that share their electrons equally. Polar bonds form when two bonded atoms share electrons unequally.

Hope it will help :)

The compositions of all phases present at 600°C, a 30% wt Al - 70% wt Si alloy consists of two phases: α-Al phase with approximately 10% wt Si and Si phase with approximately 2% wt Al.

To determine the phases present and their compositions, we need to consult the Al-Si phase diagram.

1. Locate the Al-Si phase diagram and find the 600°C isotherm line.
2. Identify the 30% wt Al - 70% wt Si composition point on the diagram and see where it intersects the 600°C isotherm line.
3. Determine the phases present at this intersection point.
4. Read the compositions of each phase from the phase boundaries around the intersection point.

From the Al-Si phase diagram at 600°C, the 30% wt Al - 70% wt Si alloy falls within the α-Al solid solution phase, which is primarily aluminum with dissolved silicon, and the Si phase, which is primarily silicon with dissolved aluminum.

For the α-Al phase composition, read the weight percentage of Si in α-Al from the phase boundary on the left side of the intersection point. This value is approximately 10% wt Si in α-Al.

For the Si phase composition, read the weight percentage of Al in Si from the phase boundary on the right side of the intersection point. This value is approximately 2% wt Al in Si.

In summary, at 600°C, a 30% wt Al - 70% wt Si alloy consists of two phases: α-Al phase with approximately 10% wt Si and Si phase with approximately 2% wt Al.

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