finally, apply snell's law and find the ray's angle of incidence θ1 on the diamond. express your answer in θ1 =___ degrees.

Answer:

Explanation:(a) What is her weight on earth? (b) What are her mass and her weight on the moon, where g = 1.62 ms–2? Solution: (a) On earth. W = m g = 55.0 x 9.8 = 539 N. (b) On moon, her mass remains the same, but the acceleration due to gravity

As the bobsled moves down the slope and hits the spring, the kinetic energy, gravitational potential energy and thermal energy change. So, option a, c and d is correct choice.

The energy associated with an object's motion is known as kinetic energy. Kinetic energy is a scalar quantity that is dependent on the object's mass and velocity.

When the bobsled hits the spring, some of the kinetic energy is transferred to the spring, causing it to compress. This compression results in the spring gaining elastic potential energy, which is the energy stored in a stretched or compressed spring.

Gravitational potential energy is the energy stored in an object as a result of its position in a gravitational field.

The bobsled has gravitational potential energy due to its position on the slope. As it moves downhill, this gravitational potential energy is converted into kinetic energy, which is the energy of motion.

Thermal energy is the energy associated with the random motion of particles in a substance.

When the temperature of a substance rises, its particles move faster, resulting in an increase in thermal energy.

When the temperature of a substance decreases, its particles move slower, resulting in a decrease in thermal energy. Thermal energy is transferred from one object to another as heat flow.

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question:

which energies change as the bobsled moves down the slope and hits the spring?

a. Kinetic energy

b. Elastic potential energy

c. Gravitational potential energy

d. Thermal energy

The energy output from active galactic nuclei is much greater than the energy output from normal galaxies, often by several orders of magnitude. Active galactic nuclei (AGNs) are powered by the accretion of  matter onto a supermassive black hole at the center of the galaxy.

This process releases enormous amounts of energy in the form of radiation and outflows of material, such as jets of highly energized particles that can extend thousands of light-years from the black hole. In contrast, normal galaxies are powered primarily by the nuclear fusion reactions that take place in their stars. The energy output from AGNs can be so great that it can significantly affect the surrounding environment and even influence the evolution of the galaxy itself. For example, the intense radiation from an AGN can ionize gas in the galaxy, creating regions of hot, glowing gas known as emission nebulae. The outflows of material from an AGN can also help to regulate star formation in the galaxy by heating or expelling gas from the interstellar medium.

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Two stars with the same mass number can be different in their luminosity, life time and distance with respect other stars and planets.

Stars are spatial objects with brightness and are made of gases and dust. The major part of stars are hydrogen and helium gases. There are trillions of stars for each galaxies in the universe.

The energy formed inside the stars is from  the nuclear fusion of hydrogen nuclei forming helium nuclei releases tones of heat and light energy. The light and heat energy produced from each stars differ.

The luminosity or brightness of stars with same mass will be different. The life time of each stars also differ from other stars.

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Answer:

false

Explanation:

The major characteristic an organic compound has which an inorganic

compound doesn't  have is the presence of carbon atoms in the molecule.

This helps us to differentiate the compounds into their respective divisions.

Inorganic compounds

Organic compounds

We can observe that inorganic compounds lack carbon atoms which makes

the answer valid.

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Answer:

B and E because yk thats the asnwer

The work done to slide the crate along the loading dock is 5,440 J.

To calculate the work done, we need to determine the component of the force that acts in the direction of motion. Multiplying this component by the displacement will give us the work done.

In this case, the force of 200 N is at an angle of 34° from the horizontal. By decomposing this force into its horizontal and vertical components, we find that the horizontal component is 200 N * cos(34°).

Multiplying this by the displacement of 27 m gives us the work done, which is approximately 5,440 J.

Work is defined as the product of force and displacement when the two are in the same direction.

In this scenario, the force applied to the crate is at an angle of 34° from the horizontal, but only the horizontal component of the force contributes to the work done in moving the crate along the loading dock.

The vertical component of the force does not contribute to the displacement of the crate in the horizontal direction.

By finding the horizontal component of the force and multiplying it by the displacement, we can determine the work done.

It is important to consider the angle and the appropriate components of the force to accurately calculate the work.

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a) The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\).

b) The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\).

c) The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\).

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together.

In this question we shall apply principle of energy conservation and principle of linear momentum conservation to model an inelastic collision between two carts.

a) The combination of cart and ramp can be considered a conservative system as there are no non-conservative forces (i.e. friction), the final velocity of cart A (\(v_{A}\)) is related to the change in gravitational potential energy:

\(\frac{1}{2}\cdot M\cdot v_{A}^{2} = M\cdot g \cdot 2\cdot H\) (1)

Now we clear \(v_{A}\) and simplify the resulting expression:

\(v_{A} = 2\cdot \sqrt{g\cdot H}\)

The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

b) We apply the same approach used in part b) to find the final velocity:

\(\frac{1}{2}\cdot (2\cdot M) \cdot v_{B}^{2} = (2\cdot M)\cdot g \cdot H\) (2)

Now we clear \(v_{B}\) and simplify the resulting expression:

\(v_{B} =\sqrt{2\cdot g\cdot H }\)

The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\). \(\blacksquare\)

c) The final velocity (\(v\)system is determined by principle of linear momentum conservation:

\(3\cdot M\cdot v = M\cdot 2\cdot \sqrt{g\cdot H}-2\cdot M\cdot \sqrt{2\cdot g\cdot H}\)

\(3\cdot v = 2\cdot (1-\sqrt{2})\cdot \sqrt{g\cdot H}\)

\(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\)

The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together. \(\blacksquare\)

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Work done on the jet by the catapult is 3.31x10⁷j

We are given that,

Thrust = F = 2.10105N

As a result, the work performed by the engines and the catapult will be equal to the kinetic energy of the jet at takeoff. then the formula can be used to determine the work the jet did.

Work done by the engines = Force x Distance

Work done by the engines,

(2.10 X 10⁵J)x 90m = 1.89 x 10⁷J

Total kinetic energy = 5.20x 10⁷J

The total kinetic energy minus the work produced by the engines is the amount of work the catapult does on the jet.

Therefore the

work done on the jet by the catapult =( 5.20 X 10⁷J) -(1.89 X 10⁷) work done on the jet by the catapult = 3.31x10⁷j

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Answer:

yhnjienfjknijeanfijawenkwamfjkamenkgtama4eikoatgjj

Explanation:

ga4tgaew4gtaegae4gaegae5tatgaeata54aetgaetg

a. To determine the velocity of each object before they collide, we can apply conservation of mechanical energy.

For the 2-kg bob compressed against the spring, the potential energy stored in the spring when compressed is given by:

PE_spring = 0.5 * k * x^2,

where k is the spring constant (50 N/m) and x is the compression distance (0.6 m).

PE_spring = 0.5 * 50 N/m * (0.6 m)^2 = 9 J

The potential energy is converted entirely into kinetic energy before the collision:

KE_bob = PE_spring = 9 J

Using the formula for kinetic energy:

KE = 0.5 * m * v^2,

where m is the mass and v is the velocity, we can solve for the velocity of the 2-kg bob:

9 J = 0.5 * 2 kg * v^2

v^2 = 9 J / 1 kg

v = √(9 m^2/s^2) = 3 m/s

Therefore, the velocity of the 2-kg bob before the collision is 3 m/s.

For the 3-kg block on the incline, we can determine its velocity using the conservation of potential and kinetic energy.

The potential energy at the top of the incline is given by:

PE_top = m * g * h,

where m is the mass (3 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (4 m).

PE_top = 3 kg * 9.8 m/s^2 * 4 m = 117.6 J

The potential energy is converted into kinetic energy:

KE_block = PE_top = 117.6 J

Using the formula for kinetic energy, we can solve for the velocity of the 3-kg block:

117.6 J = 0.5 * 3 kg * v^2

v^2 = 117.6 J / 1.5 kg

v = √(78.4 m^2/s^2) ≈ 8.85 m/s

Therefore, the velocity of the 3-kg block before the collision is approximately 8.85 m/s.

b. If the collision between the objects is elastic, the total momentum before the collision is equal to the total momentum after the collision.

Total momentum before the collision:

P_before = m1 * v1 + m2 * v2,

where m1 and m2 are the masses, and v1 and v2 are the velocities.

P_before = (2 kg * 3 m/s) + (3 kg * 8.85 m/s)

P_before ≈ 36.55 kg·m/s

Since the collision is elastic, the total momentum after the collision remains the same.

Total momentum after the collision:

P_after = (2 kg * v1') + (3 kg * v2'),

where v1' and v2' are the velocities after the collision.

We need to solve this equation for v1' and v2'. More information is required about the nature of the collision (head-on or at an angle) to determine the specific velocities after the collision.

c. To determine how much the spring will be compressed by the object(s) after the collision, we need to consider the conservation of mechanical energy.

The total mechanical energy after the collision is equal to the sum of potential and kinetic energy:

Total Energy_after = PE_spring + KE_bob,

where PE_spring is the potential energy stored in the spring and KE_bob is the kinetic energy of the 2-kg

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The wavelength of an electromagnetic wave that has a frequency of 1 hertz  more than 1 m.

In a vacuum, electromagnetic waves move at a constant speed of 3.00 x 108 ms-1. Both the magnetic and electric fields have no effect on them. However, they can exhibit diffraction or interference. Any medium, including air, a solid, or a vacuum, can be traversed by an electromagnetic wave. It is not dependent on a medium to spread or move from one location to another. The opposite is true for mechanical waves, which require a medium to propagate (like sound or water waves). Transverse waves are electromagnetic waves. Thus, they are evaluated based on their amplitude (height) and wavelength (distance between the highest and lowest points of two successive waves).

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Both travel rearward, but the daughter accelerates more quickly motion.

Every action has an equal and opposite response, according to Newton's third law of motion. Consequently, when the two skaters collide. They'll both advance backward together.

However, the mother weighs 100 kg, compared to the daughter's 50 kg. due to the daughter's lower mass. Daughter as a result accelerates more quickly in the reverse direction.

As a result, both travel backward, but the daughter does so more quickly than the mothe motionr.

The following is an expression that represents Newton's second law:

a = F/m and F = ma or

According to this law, a body's acceleration is determined by two variables. The first is the body's mass and the net force that is operating on it. The acceleration is directly proportional to the net force acting on the body and inversely proportional to the mass.

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1. The statement, specific heat capacity is the amount of heat per unit mass required to raise the temperature of a substance by one Kelvin is true. 2. The statement, substance with the smaller specific heat capacity requires less energy to raise its temperature by 1°C is true. 3. Calorimeter is used to measure the heat generated or consumed by a substance during a chemical reaction or physical change.

Specific heat capacity is the quantity of heat energy required to increase the temperature of a given substance by one unit per unit mass. It characterizes the substance's resistance to temperature changes when heat is added or removed. Thus, the accurate statement is that, specific heat capacity represents the amount of heat per unit mass needed to raise the substance's temperature by one Kelvin or one degree Celsius.   The specific heat capacity of a substance determines the energy required to raise its temperature.

When comparing two substances with the same mass but different specific heat capacities, the substance with the lower specific heat capacity necessitates less energy to increase its temperature by 1°C. Thus, the accurate statement is that, the substance with the smaller specific heat capacity requires less energy to raise its temperature by 1°C. A calorimeter is an instrument utilized to measure the heat generated or absorbed during a chemical reaction or physical change.  Its purpose is to prevent heat exchange with the surroundings, enabling accurate heat measurements. Thus, the accurate statement is that, the heat generated or consumed by a substance during a chemical reaction or physical change.                                                                                        

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Answer:

The Photosphere

Explanation:

It's photosphere is the sun's area that lights .  This layer is responsible for nearly all of the Sun's light. 

Answer:

The photosphere

Explanation:

The light we see from the sun comes from the photosphere.

Answer:

(a) Parallel to the incedent ray

Answer:

=> Power = 60×10×10/60

=> Power = 6000/60

=> Power = 100 Watt

Hence the power output of a pump is 100 Watts.

Answer:

\(\tau=5.81\times 10^5p\ N-m\)

Explanation:

We have,

Electric field, \(E=6.19\times 10^5\ N/C\)

The electric dipole vector at an angle of 69.9 degrees from the direction of the field.

The torque acting on a molecule is given by :

\(\tau=p\times E\\\\\tau=pE\sin\theta\)

p is electric dipole moment

\(\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m\)

So, the magnitude of the torque acting on the molecule is \(5.81\times 10^5p\ N-m\).

The scale in the elevator will read the same value as it did when the elevator was at rest after the elevator reaches its final constant speed as it heads to the bottom floor.

After the elevator reaches its final constant speed as it heads to the bottom floor, the scale in the elevator will read the same value as it did when the elevator was at rest. This is because the scale measures the force exerted by the person standing on it, and this force remains constant once the elevator is moving at a constant speed.

When the elevator is at rest or moving at a constant speed, the force experienced by the person standing on the scale is equal to their weight. This weight is the force exerted on their body due to gravity. Gravity pulls us downwards with a constant acceleration, so the weight of a person remains the same as long as the acceleration is constant.

When the elevator starts moving, there is a brief moment when the scale reading may change due to the acceleration or deceleration. But once the elevator reaches its final constant speed, the acceleration becomes zero. At this point, the scale reading will return to the person's weight, which is the force exerted on the scale.

In conclusion, the scale in the elevator will read the same value as it did when the elevator was at rest after the elevator reaches its final constant speed as it heads to the bottom floor.

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Power sources that are connected in parallel should have the same voltage output. This statement is true.

What does it mean when we say two power sources are connected in parallel?  Power sources are connected in parallel to increase the current output. This means that the positive terminals of the power sources are connected to the other positive terminals, and the negative terminals of the power sources are connected to the other negative terminals. This results in the voltage output remaining the same, but the current output increasing. This is useful when more current is required for a particular application. To summarize, when power sources are connected in parallel, the voltage output should remain the same, and the current output should increase.

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Thermal noise is the unavoidable noise that occurs due to the thermal motion of particles in electrical circuits.

This type of noise is present everywhere in the universe as it is due to the thermal motion of particles.

This thermal motion is the random movement of particles that is a result of their temperature. At higher temperatures, the particles in a substance have a higher thermal motion, which results in more thermal noise.

The electrical circuit has resistance, and when a current flows through it, the resistance causes collisions between electrons and other atoms. This interaction between the moving electrons and atoms in the conductor produces thermal noise.

Thermal noise is proportional to the temperature of the conductor and is independent of the current or voltage of the signal passing through it. The power of thermal noise is given by the formula P = kTB, where k is Boltzmann's constant, T is the temperature in Kelvin, and B is the bandwidth of the signal.

Hence, it can be deduced that thermal noise is an inevitable occurrence present universally, as it arises from the thermal agitation of particles within electrical circuits. This phenomenon pervades various environments and cannot be eliminated.

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Answer:

Relative to Carlos the Whataburger is moving at 0 speed.

Explanation:

Carlos speed, \(V_A\) = 35 m/s

speed of another car, \(V_B\) = -25 m/s

The speed of the Whataburger, \(V_w\)  = 35 m/s since it is in the same car as Carlos.

The relative of the Whataburger to Carlos is given as;

\(V = V_A - W_w\\\\V = 35 \ m/s - 35 \ m/s\\V = 0\)

Therefore, Relative to Carlos the Whataburger is moving at 0 speed.

Answer:

The power of the car, the gear ratio, weight of the car, aerodynamics of the car, grip of the tires on the road, calorific value of the fuel used, and friction would affect the speed of the car.

Answer:

\( s = ut + \frac{1}{2} a {t}^{2} \\ u = 0 \\ a = 4.2 \: m {sec}^{ - 2} \\ t = 10sec \\ s = 0 + \frac{1}{2} (4.2) {10}^{2} \\ = 1.2 \times 100 \\\boxed{ s = 120 \: m}\)

Answer:

Technically everything has somewhat of a magnetic field. I guess

Answer:

Y

Explanation:

Acceleration = (v-u)/t

W = (29-11)/6 = 3

X = (34-10)/12 = 2

Y = (40-12)/7 = 4

Z = (28-20)/8 = 1

So the answer is Y = 4.

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The acceleration 0f book is 1.1029 m/s²

Acceleration is the general term for any process where the velocity changes. There are only two ways to accelerate: either by increasing speed or decreasing direction, or both. The reason for this is that velocity includes both a speed and a direction.

The definition of acceleration is the speed at which velocity varies with respect to time. Acceleration is a vector quantity since it has both a magnitude and a direction.

Given,

velocity = 2.25

time = 2.04

accerlation = v - v0/t

= Δv/Δt

= 2.25/2.04

= 1.1029 m/s²

Therefore the acceleration of book is 1.1029 m/s²

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The energy lost to other forms like sound and heat, is mv². If the velocity of the blocks after collision is zero.

Mass of both the block, m₁ = m₂ = m

Velocity of both the block, v₁ = v₂ = v

Velocity after collision = 0

Combined mass after collision, = m+m = 2m

Initial energy of 1 block, = 0.5mv²

Initial energy of 2 block, = 0.5mv²

Total energy before collision = 0.5mv² + 0.5mv² = mv²

Energy after collision, = (2m)×0² = 0

So energy lost, = mv² - 0 = mv²

This energy converts into thermal energy, and sound energy.

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