Find cos0, where 0 is the angle shown. Give an exact value, not a decimal approximation. (listing BRAINLEST)​

Rick would need to have at least 100 cars on hand to immediately be able to deliver any car (model, option package, color).

To immediately deliver any car, Rick Rich's dealership must have all possible combinations of Mercedes models, option packages, and colors in stock.

With five models, four option packages, and five colors, there are 5 x 4 x 5 = 100 possible combinations.

Therefore, Rick would need to have at least 100 cars on hand, each representing a unique combination of model, option package, and color. It's worth noting that having exactly 100 cars on hand would only allow Rick to deliver one of each possible combination, so it may be prudent to have additional inventory on hand to meet demand for more popular combinations.

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Answer:

.682

Step-by-step explanation:

Answer:

Step-by-step explanation:

4x + 3c = -2

4x = -2 - 3c

x = (-2 - 3c)/4

Answer:

The frequency is 3 more than expected.

The total number of genes involved in fruit diameter in tomatoes is 4.

\(1/4^{n}\) = ratio of F2 individuals expressing either extreme Phenotype

In the above equation, 'n' represents the number of genes involved.

The term 'extreme phenotype' refers to the phenotype of one of the parents from the P1 generation. In this case, it denotes the parents with fruit diameters of 8 cm and 16 cm. In the F2 generation, which consists of a total of 256 offspring, there is only 1 offspring that resembles either P1 parent.

The ratio of individuals expressing either extreme phenotype = Number of springs with either extreme phenotype / Total number of off spring.

ratio of F2 individuals expressing either extreme Phenotype = 1/256

Apply the value of 1/256 to the first equation.

That is, \(1/4^{n}\)  = 1/256

1\(1/4^{4}\) = 1/256

As shown above, the value of 'n' is 4.

Therefore, the total number of genes involved in fruit diameters is 4.

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Answer:

Step-by-step explanation:

Solving the problem

Stacy is correct

Answer:

\(\huge 4 \times \frac{2}{3} = \frac{8}{3} =\boxed{2 \frac{2}{3} }\)

Answer:

S₂₇ = 1188

Step-by-step explanation:

using the given formula for \(S_{n}\) , that is

\(S_{n}\) = \(\frac{n}{2}\) (a₁ + \(a_{n}\) )

with a₁ = 5 and \(a_{n}\) = a₂₇ = 83 , then

S₂₇ = \(\frac{27}{2}\) (5 + 83) = 13.5 × 88 = 1188

Step-by-step explanation:

Find the factors of x that makes it zero.. Equate the equation to y and use it to find the value of y. Then get your values for x and y and plot the graph

Answer:

The answer to this question is 13

The model for S(t) is given as:

S(t) = (-0.03t^2 + 1.6t - 13.65)^(-1)

This model predicts the searching period length in days. It is an inverse function of the quadratic equation (-0.03t^2 + 1.6t - 13.65). As the temperature increases, the searching period decreases, indicating that the larvae are more efficient at finding the host tree at higher temperatures.

To calculate S(25), we substitute t = 25 into the equation:

S(25) = (-0.03(25)^2 + 1.6(25) - 13.65)^(-1)

= (-0.03(625) + 40 - 13.65)^(-1)

= (-18.75 + 26.35)^(-1)

= 7.6^(-1)

= 0.1316 days

Therefore, when the air temperature is 25 degrees Celsius, the predicted length of the searching period is approximately 0.1316 days.

The model for N(t) is given as:

N(t) = -0.85t^2 + 45.4t - 547

This model predicts the percentage of larvae surviving the searching period. It is a quadratic function (-0.85t^2 + 45.4t - 547). As the temperature increases, the percentage of larvae surviving the searching period may increase or decrease depending on the behavior of the quadratic function.

To calculate N(25), we substitute t = 25 into the equation:

N(25) = -0.85(25)^2 + 45.4(25) - 547

= -0.85(625) + 1135 - 547

= -531.25 + 1135 - 547

= 56.75%

Therefore, when the air temperature is 25 degrees Celsius, the predicted percentage of larvae surviving the searching period is 56.75%.

2. The rate of change of the searching period S(t) with respect to temperature t can be found by taking the derivative of the function S(t) with respect to t, which is denoted as ds/dt.

ds/dt = d/dt [(-0.03t^2 + 1.6t - 13.65)^(-1)]

To find when ds/dt = 0, we set the derivative equal to zero and solve for t:

ds/dt = 0

However, without the specific equation of S(t) in its original form, it is not possible to provide an exact value of t when ds/dt equals zero.

Regarding the behavior when t = 0, we cannot determine this without further information or the specific form of the function S(t). The behavior at t = 0 depends on the equation itself and how it is defined.

3. The rate of change of the percentage of larvae surviving the searching period N(t) with respect to the length of the searching period S(t) can be found by taking the derivative of the function N(t) with respect to S(t), denoted as dN/dS.

dN/dS = d/dS [(-0.85t^2 + 45.4t - 547)]

This rate of change provides information about how the percentage of larvae surviving the searching period changes with respect to the length of the searching period. It gives insight into the sensitivity

2x + 3x + 140 = 360 (being complete turn angle)

5x + 140 = 360

5x = 360-140

5x = 220

x = 44

now 2x = 2 × 44 = 88

3x = 3 × 44 = 132

Answer:

y = -6x + 8

Step-by-step explanation:

\begin{bmatrix}6x+y=8\\ y=-6x+8\end{bmatrix}

I don't know why it came out like this

The meaning of the interval is "there has been no change in support for the candidate". Thus, option (a) is correct.

The 90% two-proportion z-confidence interval (-0.0199, 0.0510) represents the likely range of the genuine difference between the two polls in support of candidate X.

Because the interval comprises 0, the difference in support between the two polls is unlikely to be statistically significant. In other words, there is no compelling evidence that there has been a significant shift in support for the candidate.

Options b), c), d), and e) imply a substantial change in support for the candidate, either positive or negative.

Thus, option (a) is correct.

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To calculate the book value of the Biologique Recherche facial machine after the first year using the straight-line depreciation method, we can use the following formula:

Book Value = Cost - (Depreciation Expense * Number of Years Depreciated)

In this case, the cost of the machine is $123,000, the useful life is 4 years, and the residual value is $42,500. We can use these values to calculate the annual depreciation expense as follows:

Annual Depreciation Expense = (Cost - Residual Value) / Useful Life

= ($123,000 - $42,500) / 4

= $30,375

To calculate the book value of the machine after the first year, we can plug these values into the formula above:

Book Value = $123,000 - ($30,375 * 1)

= $123,000 - $30,375

= $92,625

Therefore, the book value of the Biologique Recherche facial machine after the first year using the straight-line depreciation method would be $92,625.

Answer:

$92,875

Step-by-step explanation:

To calculate the book value of the machine after the first year using the straight-line depreciation method, you would need to subtract the annual depreciation expense from the original cost of the machine. The annual depreciation expense is calculated by subtracting the residual value of the machine from the original cost and dividing that amount by the useful life of the machine in years.

In this case, the annual depreciation expense would be calculated as follows:

Annual depreciation expense = ($123,000 - $42,500) / 4 years = $30,125 per year

Therefore, the book value of the machine after the first year would be:

Book value = $123,000 - $30,125 = $92,875

This means that the machine would be recorded on Rebecca's balance sheet as having a value of $92,875 after the first year of use.

To show that if n≥2k, every tournament on n vertices has a transitive subtournament on k vertices, we can compute it as:

pick any vertex v, let

\(L = \{u:u\to v\},\)

Now let,

\(R=\{u:v\to u\}.\)

By u --> v, there is an edge from u to v

\(|L|+|R| = 2^{k+1}-1\)

so, one of L and R contains at least 2k points. Now apply your induction hypothesis to that set, and you should find it easy to fit v in to the resulting transitive k-tournament.

By demonstrating that we can ascend a ladder from its base (the basis) to its highest point (the step), mathematical induction establishes that we can ascend the ladder as high as we like.

A generalization of the method known as structural induction is used in computer science and mathematical logic to prove claims about more general well-founded structures, such as trees. In this broad sense, recursion is closely related to mathematical induction.

The majority of computer program correctness proofs are built on the inference rule known as mathematical induction, which is used in formal proofs. Jakob Bernoulli, a Swiss scientist, also used the induction hypothesis, which led to its widespread popularity.

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The minimum sample size required when you want to be 95% confident that the sample mean is within one unit of the population mean is 56

Given in the question,

Margin of error = 1

Assuming,

Population standard deviation = 3.8

\(\alpha\) = 0.5, \(\alpha\)/2 = 0.025 so Z\(\alpha\)/2 = 1.96

Margin of error can be calculated as

Margin of error = Z\(\alpha\)/2*SD/\(\sqrt{n}\)

n = (Z\(\alpha\)/e*SD/Margin of error)^2 = (1.96*3.8/1) = 55.47 or 56

So its answer is 56 i.e. option A.

Therefore, the minimum sample size is 56.

The sample size is defined as the number of compliances used for determining the estimations of a given population. The size of the sample has been drawn from the population. slice is the process of selection of a subset of individualities from the population to estimate the characteristics of the whole population. The number of realities in a subset of a population is named for analysis.

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Two triangles than make the whole triangle are proportional then

and the upper side of the left triangle is x

we can calculate the lenght of upper triangle

then

we join the relations

we use cross-multiplication. The product of 21 by 30 dividing between 15 is equal to x

the value of x is 42 units

Answer:

SAS

Step-by-step explanation:

Answer:

SAS (side-angle-side)

Step-by-step explanation:

=========================================

Explanation:

The perimeter around the circle, aka circumference, is found through this formula

C = 2*pi*r

That's for a full circle. However, we're dealing with semicircles here, so we cut that in half to get pi*r to represent the curved distance around half the circle.

For the outer larger semicircle, that curved distance is exactly 14pi

For the inner smaller semicircle, that curved distance is 7pi, since 7 is half of 14.

The total curved portions is 14pi+7pi = 21pi

Then we add on the last straight line portion that's 14 cm long to get a total perimeter of 21pi+14

This is the exact perimeter in terms of pi.

The last thing to do is replace pi with 3.14 and simplify

21pi+14 = 21*3.14+14 = 79.94

This value rounds to 80

Answer:

A

Step-by-step explanation:

Answer:

f(x) = -3x+1

Step-by-step explanation:

every straight graph has an equation f(x) = m * x + b

when the graph goes up when you look at it from left to right, m is a positive number. when it goes down, then m is negative.
the value of m you can read when you go 1 to the right and then count how many you need to go up/down to meet the graph. in this picture, you need to go down 3.
So m = -3
b is how many you habe to go up (+) or down (-) from the center point 0
so in this case you see on the picture that the graph is hitting the y line on 1

so your equation is -3x + 1

Answer:

The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

For the third class 78 - 83 ; the upper limit = 83

The class width for this histogram 5

The number of students that took the exam simply refers to the frequency is  84

The percentage of students that scored higher than 95.5 is 53%

Step-by-step explanation:

The objective of this question is to use the following histogram that shows the exam scores for a Pre-algebra class to answer the question given:

NOW;

The table given in the question can be illustrated as follows:

S/N           Class                Score          Frequency

1                 68  - 73            70.5           0

2                73 - 78             75.5           4

3                78 - 83             80.5           8

4                83 - 88             85.5           12

5                88 - 93            90.5           16

6                93 - 98            95.5           20

7                98 - 103           100.5          24                            

TOTAL:                                                 84

a) The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

b) For the third class 78 - 83 ; the upper limit = 83  ( since the upper limit is derived by addition of  5 to the last number showing  in the highest value specified by the number in the class interval which is 78 ( i.e 78 + 5 = 83))

c)   The class width for this histogram 5 ; since it  is the difference  between the upper and lower boundaries  limit of the given class.

So , from above the difference in any of the class will definitely result into 5

d) The number of students that took the exam simply refers to the frequency ; which is (0+4+8+12+16+20+24) = 84

e) Lastly; the percentage of students that scored higher than 95.5 is ;

⇒\(\dfrac{20+24}{84} *100\)

= 0.5238095 × 100

= 52.83

To the nearest percentage ;the percentage of students that scored higher than 95.5 is 53%

Answer:

1. 98-103 (6th class)

2. 88

3. 5

4. 84

5. 52%

Step-by-step explanation:

Find attached the frequency table.

The class of exam scores falls between (1, 2, 3, 4, 5, or 6).

The exam score ranged from 68-103

1) The largest number of exam scores = 24

The largest number of exam scores is in the 6th class = 98 -103

Step 2 of 5:

The upper class limit is the higher number in an interval. Third class interval is 83-88

The upper class limit of the third class 88.

Step 3 of 5:

Class width = upper class limit - lower class limit

We can use any of the class interval to find this as the answer will be the same. Using the interval between 73-78

Class width = 78 - 73

Class width for the histogram = 5

Step 4 of 5:

The total of students that took the test = sum of all the frequency

= 0+4+8+12+16+20+24 = 84

The total of students that took the test = 84

Step 5 of 5:Find the percentage of students that scored higher than 95.5

Number of student that scored higher than 95.5 = 20 + 24 = 44

Percentage of students that scored higher than 95.5 = [(Number of student that scored higher than 95.5)/(total number of students that took the test)] × 100

= (44/84) × 100 = 0.5238 × 100 = 52.38%

Percentage of students that scored higher than 95.5 = 52% (nearest percent)

1) The probability distribution of the average weekly earnings for employees in general automotive repair shops is the sampling distribution of the sample mean. According to the Central Limit Theorem, if the sample size is large enough, the sampling distribution of the sample mean is approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

2) To find the probability that the average weekly earnings is less than $445, we can standardize the sample mean and use a z-table. The z-score for $445 is calculated as follows: z = (445 - 450) / (50 / sqrt(100)) = -1. Using a z-table, we find that the probability that the average weekly earnings is less than $445 is approximately 0.1587.

3) Since we are dealing with a continuous distribution, the probability that the average weekly earnings is exactly equal to any specific value is zero.

4) To find the probability that the average weekly earnings is between $445 and $455, we can subtract the probability that it is less than $445 from the probability that it is less than $455. The z-score for $455 is calculated as follows: z = (455 - 450) / (50 / sqrt(100)) = 1. Using a z-table, we find that the probability that the average weekly earnings is less than $455 is approximately 0.8413. Therefore, the probability that it is between $445 and $455 is approximately 0.8413 - 0.1587 = 0.6826.

5) In answering questions 2-4, we made an assumption about the population distribution based on the Central Limit Theorem. We assumed that since our sample size was large enough (n=100), our sampling distribution would be approximately normal.

6) If we assume that weekly earnings for employees in all general automotive repair shops are normally distributed with a mean of $450 and a standard deviation of $50, then we can calculate the z-score for an employee earning more than $480 in a given week as follows: z = (480 - 450) / 50 = 0.6. Using a z-table, we find that the probability that an employee will earn more than $480 in a given week is approximately 1 - 0.7257 = 0.2743.

Answer:

  y = -1000x +11000

Step-by-step explanation:

Given:

  (x, y) = (sales price, number sold) = (3, 8000), (6, 5000)

Find:

  slope-intercept equation for a line through these points

Solution:

When given two points, it often works well to start with the 2-point form of the equation for a line.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Filling in the given points, you have ...

  y = (5000 -8000)/(6 -3)/(x -3) +8000

  y = (-3000/3)(x -3) +8000

  y = -1000x +3000 +8000 . . . . eliminate parentheses

  y = -1000x +11000 . . . . the desired equation

Answer:

  27.  B. $464.61

  28.  A. $107.79

Step-by-step explanation:

From the last balance shown, subtract the three remaining debits, and add the credit. That sum is ...

  $415.25 -16.16 -18.18 -16.30 +100 = $464.61

__

The rate applied quarterly is 0.07/4 = 0.0175. That is, each quarter, the account balance is multiplied by 1.0175. After 4 quarters, the balance has been multiplied by 1.0175^4 ≈ 1.071859. The new balance will be ...

  1500 × 1.071859 ≈ $1607.79

The amount in excess of $1500 is the interest earned:

  $1607.79 -1500.00 = $107.79 . . . . interest earned

Option (D) She can use the commutative property to rewrite the expression as (70 + 30 + 12.8) + 6.1 is correct.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

It is given that:

Patti is using mental math to evaluate the expression (70 + 12.8 + 30) + 6.1.

The number expression is:

= (70 + 12.8 + 30) + 6.1

As we know from the commutative property

a +  b = b + a

Applying commutative property in the number expression:

= (70 + 30+ 12.8) + 6.1

She can use the commutative property to rewrite the expression as (70 + 30 + 12.8) + 6.1.

Thus, option (D) She can use the commutative property to rewrite the expression as (70 + 30 + 12.8) + 6.1 is correct.

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Answer:

10ft

Step-by-step explanation:

Let assume the volume of the box be 480ft^3

Required

height h

Volume of the box = length * width * height

Substitute

480 = 8 * 6 * h

480 = 48 * h

h = 480/48

h = 10ft

Hence the height of the box if the volume of 480ft^3 is 10ft

Answer:

just do 68986

- 64997

______

3,989