Find the amount of air needed to fill a basketball whose diameter is 9.45 in. Use 3.14 for

Answer:

Minimum--> 250

Q1--> 255

Q2--> (Median): 307

Q3--> 433

Maximum-->507

Step-by-step explanation:

To find the five-number summary of this data set, we need to determine the minimum value, maximum value, and three quartiles (Q1, Q2, Q3) which divide the data into four equal parts.

First, we need to sort the data set in ascending order:

{ 250, 253, 255, 267, 307, 425, 433, 435, 507 }

Minimum: 250

Maximum: 507

To find the quartiles, we need to find the median of the entire data set (Q2) and then the medians of the two halves of the data set, which will give us Q1 and Q3.

Q2 (Median): The median of the entire data set can be found by averaging the two middle numbers.

Q1: The median of the lower half of the data set is 255, which is the middle value of { 250, 253, 255, 267, 307 }. Therefore, Q1 = 255.

Q3: The median of the upper half of the data set is 433, which is the middle value of { 425, 433, 435, 507 }. Therefore, Q3 = 433.

Volume of the cylinder is 15197.60(to the nearest hundredth).

In mathematics, Cylinder is  the basic 3d shapes,  which has two parallel circular bases at a distance. The two circular bases are joined by a curved surface, at a fixed distance from the center which is called height of the cylinder.

Given that the radius of the cylinder  is 11yd.

and the height of the cylinder is 40yd.

Formula for the volume of cylinder  is π × r² × h where π=3.14, r= radius and h= height.

Putting the values we get,

Volume of the cylinder is = 3.14 × (11)² × 40 cubic yd.

                                          = 15197.6

Hence, Volume of the cylinder is 15197.60(to the nearest hundredth).

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Answer:

Number of 2-point questions on the test as per given condition is equals to 8.

Total number of questions in a test = 28

Total points allotted for test = 100

Questions distribution as per points :

2-point questions, 4-point questions, and 5-point questions

'x' represents the 5-point questions

As per condition given,

Number of 2-point questions = 2x

Number of( 2-point  +  4-point +  5-point ) questions = 28

⇒ 2x + 4-point questions  + x = 28

⇒ 4-point questions  = 28 - 3x

Substitute the value in the given condition of the equation we get,

2(2x)+4(28-3x)+5(x) = 100

4x+112-12x+5x=100

112-3x=100

x=4

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Answer:

The sum of the areas of square N and square L is equal to the area of square K

The sampling method used in this problem is classified as:

Simple Random Sampling

Samples may be classified as:

In this problem, all the options are assigned a number and then taken, hence a Simple Random Sample is used.

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Answer:

Translate point J 12 units down and 6 units right.

The dataset represented by the given box plot is 12, 15, 15, 17, 19, 19, 20, 22, 24 option B.

A box plot, sometimes called a box whisker plot, shows the distribution of a dataset graphically. The minimum value, the first quartile (25th percentile), the median (50th percentile), the third quartile (75th percentile), and the maximum value are the five main values used to standardise this method of displaying the distribution of data.

Two whiskers that extend from a rectangular box make up a box plot. The range of values between the first and third quartiles is represented by the box, which is known as the interquartile range (IQR).

From the given box plot we observe that the minimum value is 12 and the maximum value is 24.

Here, the median is 19.

From the information the two data set that have the corresponding values are:

12, 15, 15, 17, 19, 19, 20, 22, 24

12, 15, 17, 17, 19, 19, 22, 22, 24

The lower quartile is 15.

The upper quartile is 21.

Calculating the lower quartile for the data sets:

12, 15, 15, 17, 19, 19, 20, 22, 24

Lower quartile = 15

Hence, the dataset represented by the given box plot is 12, 15, 15, 17, 19, 19, 20, 22, 24 option B.

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Answer:

5.59

Step-by-step explanation:

Answer:

solution given:

by using Pythagoras law:

h²=p²+b²

x²=8²+4²

x=√80units

Answer:

a) -73°C, -15°C, -12°C, 0°C, 16°C, 37°C, 96°C

a) 96°C, 37°C, 16°C, 0°C, -12°C, -15°C, -73°C

b) -36°C, -15°C, -7°C, -1°C, 0°C, 20°C, 23°C

b) 23°C, 20°C, 0°C, -1°C, -7°C, -15°C, -36°C

SOLUTION:

Case: Expression

Method:

r - 17m - 8 = 3(2r-4m)-5(m+3-r)+7

Simplifying the R.H.S

3(2r-4m)-5(m+3-r)+7

Distributing

6r - 12m -5m -15 +5r + 7

Collecting like terms

6r - 5r -12m -5m -15 + 7

Simplifying

r -17m -8

Final answer:

Both expressions are equivalent

Answer:

x= -2

-------

7

Step-by-step explanation:

<1. combine like terms.>

<2.divide both sides of the equation by same terms.>

<3.Simplify.>: then Answer while come x= -2

------

7

Answer:

12/20

Step-by-step explanation:

\(\displaystyle \frac{3}{5}=\frac{3}{5}\cdot\frac{4}{4}=\frac{12}{20}\)

The answer is:

In-depth-explanation:

The denominator of 3/5 is 5. To get from 5 to 20, we multiply it by 4.

We need to multiply both the numerator and the denominator by 4, so we do this:

\(\sf{\dfrac{3\times4}{5\times4}}\)

\(\sf{\dfrac{12}{20}}\)

Answer:

72

Step-by-step explanation:

So draw a square and make an right angle in one of  the squares  corners! so basically what ever is on one side it's on the other side so theirs two 12 so 144 the dived my 2 which is 72!

I don't remember this sorry!

Answer:

900 kg

Step-by-step explanation:

Let's assume the cost price (C.P.) of sugar is Rs. x per kg.

The total quantity of sugar is 1500 kg.

Let the quantity of sugar sold at 8% profit be represented by y kg.

The quantity of sugar sold at 18% profit would then be (1500 - y) kg.

Using the rule of alligation, we can set up the following proportion:

(8% profit) y kg

-------------- = ------

(18% profit) (1500 - y) kg

Simplifying the proportions, we find that the difference in percentages is 4% (18% - 14% = 4%) and 6% (14% - 8% = 6%).

The ratio of these differences is 2:3.

This means that for every 2 kg of sugar sold at 8% profit, 3 kg of sugar is sold at 18% profit.

Since y represents the quantity sold at 8% profit (2 kg), we can calculate the quantity sold at 18% profit (3 kg) as follows:

(2 kg) * (3/2) = 3 kg

Therefore, the quantity sold at 18% profit is 900 kg.

The output value of (f∘g)(x) is:  \((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

The domain of (f∘g)(x) is (-∞, -3) U (-3, ∞).

In this scenario, we would determine the corresponding composite function of f(x) and g(x) under the given mathematical operations (multiplication) in simplified form as follows;

\(f(x) = \frac{x-6}{x +3}\)

g(x) = 4x - 15

Next, we would write the numerators and denominators in factored form as follows;

(x - 6)(4x - 15)

4x² - 15x - 24x + 60

4x² - 29x + 60

Now, we can derive the corresponding composite function of f(x) and g(x);

\((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

For the restrictions on the domain, we would have to equate the denominator of the rational function to zero and then evaluate as follows;

x + 3 ≠ 0

x ≠ -3

Domain = (-∞, -3) U (-3, ∞).

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Answer:

\(x^{2} +5x+5x+25\\x^{2} +10x+25\)

Step-by-step explanation:

\((x+5)^{2} =x^{2} +10x+25\)

Answer:

3/9

Step-by-step explanation:

Answer:

So, 3 households would use 20 4/5 x 3 = 62 1/5 L of water per day.

Step-by-step explanation:

Each household uses 613 1/5 ÷ 10 = 61 3/5 L of water in 3 days.

Therefore, each household uses an average of 61 3/5 ÷ 3 = 20 4/5 L of water per day.

The probability that the animal's weight will be less than 151 pounds is 0.50.

The correct option is B.

Since the given probability distribution ranges from 148 to 152, and we need to find the probability that the animal's weight will be less than 151 pounds, we can add the probabilities corresponding to the weights less than 151.

From the distribution, we see that the probability of the animal's weight being less than 151 pounds is 0.2 + 0.3 = 0.5.

Therefore, the answer is O 0.50.

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The graph of g(x) is obtained from the graph of f(x) by the following transformations:

- A horizontal stretch by a factor of 9. This is because the graph of g(x) is 9 times wider than the graph of f(x).

- A vertical translation down by 2 units. This is because the graph of g(x) is 2 units lower than the graph of f(x).

In other words, to obtain the graph of g(x) from the graph of f(x), we stretch the graph horizontally by a factor of 9 and then translate it down by 2 units.

Here is a more detailed explanation of the transformations:

- Horizontal stretch by a factor of 9: To stretch the graph horizontally by a factor of 9, we multiply all of the x-coordinates by 9. This means that every point on the graph of f(x) will be moved 9 units to the right on the graph of g(x).

- Vertical translation down by 2 units: To translate the graph down by 2 units, we subtract 2 from all of the y-coordinates. This means that every point on the graph of f(x) will be moved 2 units down on the graph of g(x).

Answer:

Y = -4x +(-6) is required answer ....

Answer:

\(x=7+\sqrt{3},\:x=7-\sqrt{3}\)

Step-by-step explanation:

\(\mathrm{Switch\:sides}\)

\(x^2-14x+46=0\)

\(\mathrm{Solve\;wit\;Quadratic\;formula}\)

\(x_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:46}}{2\cdot \:1}\)

\(\sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:46}}{2\cdot \:1}=2\sqrt{3}\)

\(x_{1,\:2}=\frac{-\left(-14\right)\pm \:2\sqrt{3}}{2\cdot \:1}\)

\(\mathrm{Separate\:the\:solutions}\)

\(x_1=\frac{-\left(-14\right)+2\sqrt{3}}{2\cdot \:1},\:x_2=\frac{-\left(-14\right)-2\sqrt{3}}{2\cdot \:1}\)

\(\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\)

\(x=7+\sqrt{3},\:x=7-\sqrt{3}\)

~Lenvy~

its 90  degree because

∠2 and ∠4 are vertical angles. Their measures are equal, so m∠4 = 90 .

∠3 and ∠4 form a straight angle, so∠4=120°.

angle four measures 45°

Answer:

147°

Step-by-step explanation:

∠4 and 33° are unilateral angles (the sum of them is equal to 180°)

\(∠4 = 180° - 33° = 147°\)

\(44+\cfrac{7}{8}r\implies 44+\cfrac{7}{8}\left( -\cfrac{1}{2} \right)\implies 44-\cfrac{7}{16}\implies \cfrac{(16)44~~ - ~~(1)7}{\underset{\textit{we'll use this LCD}}{16}} \\\\\\ \cfrac{704~~ - ~~7}{16}\implies \cfrac{697}{16}\implies 43\frac{9}{16}\)

Answer:

That's correct (756)

Step-by-step explanation:

336/4 = 84

84 * 5 = 420

420 + 336 = 756

Using the given percentages we can calculate that the 87.27 percent of questions needed to be answered correctly .

The word "percent" comes from the Latin phrase per centum, which meaning "hundred" or "by the hundred."

The number of questions that are required to pass = 48

total number of questions = 55

Percentage of questions = 48/55 × 100 = 87.27 %

Therefore he will need to answer  87.27 %  question correctly to pass.

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Answer:

yesss it does

Step-by-step explanation:

CONGRATULATIONSSSSS

Answer:

Incorrect

Step-by-step explanation:

10x10x10x10 or 10 to the 4th power has 4 0's and 1,000 only has 3. So, 10x10x10x10=10,000