Find the area of a sector with radius 55mm and arc 1.8 radians.

Answer:

95°

Step-by-step explanation:

X is the same of H that is you answer

Answer:

761 R 4

Step-by-step explanation:

0 7 6 1

5 3 8 0 9

− 0      

 3 8    

− 3 5    

   3 0  

 − 3 0  

     0 9

   −   5

       4

The largest value that f(4) can possibly be is 29.

The mean value theorem states that for a function f(x) that is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), there exists a number c in the open interval (a, b) such that:

f(b) - f(a) = f'(c)(b - a)

In this case, we are given that f(0) = -3 and that f'(x) ≤ 8 for all values of x. To determine how large f(4) can possibly be, we can use the mean value theorem with a = 0 and b = 4:

f(4) - f(0) = f'(c)(4 - 0)

Substituting the given values:

f(4) - (-3) = f'(c)(4)

f(4) + 3 = 4f'(c)

Since f'(x) ≤ 8 for all values of x, we can say that f'(c) ≤ 8. Therefore:

f(4) + 3 ≤ 4f'(c) ≤ 4(8) = 32

Therefore, we have:

f(4) ≤ 32 - 3 = 29

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Answer: 3-dimensional prism

Step-by-step explanation:

Answer:

Answer:

2. (-3f)

3. (4f)

4. x - 11 (not sure if this one is correct)

Step-by-step explanation:

Move -3 to the left of f = -3f

Move 4 to the left of f = 4f

f(x)=x+11 f ( x ) = x + 11

Answer:

59.) 80 smokers, 280 nonsmokers.

61.) 240 men, 200 women

Step-by-step explanation:

59.)

Start with:

\(\frac{2}{7}= \frac{x-100}{x+100}\)

Cross product.

\(2x+200=7x-700\)

Subtract \(2x\) from both sides of the equation.

\(200=5x-700\)

Add \(700\) to both sides of the equation.

\(900=5x\)

Divide by \(5\)

\(x=180\)

Substitute in your x-value.

\((180)-100 = 80\)

\((180)+100= 280\)

61.)

Start with:

\(6x+5x=440\)

Combine like terms.

\(11x=440\)

Divide by the coefficient of \(x\), which is \(11\)

\(x=40\)

Substitute.

\(6(40)=240\)

\(5(40)=200\)

Answer:

262.44 cubic metres.

Step-by-step explanation:

First, we can calculate the volume of the cylinder by doing pi * r^2 * h. In this case, r is 5 / 2 and h is 7.

pi * (5/2)^2 * 7 = pi * 25/4 * 7 = pi * 6.25 * 7 = pi * 43.75 = 3.14159265 * 43.75 = 137.4446784 cubic m.

Seconds, we calculate the volume of the cube. It is 5^3 = 5 * 5 * 5 = 25 * 5 = 125 cubic m.

137.4446784 + 125 = 262.4446784, which is about 262.44 cubic metres.

Hope this helps!

Answer:

5*5*5=125

volume of cylinder=137.44

137.44+125=262.44

Step-by-step explanation:

Jing worked 14 hours and Amare worked 28 hours. The equation and its solution demonstrate how to use algebra to solve a real-world problem.

The equation for this question is x + 2x = 42, where x represents the number of hours worked by Jing and 2x represents the number of hours worked by Amare. To solve this equation, we must divide both sides of the equation by 3, which gives us x = 14 and 2x = 28. This means that Jing worked 14 hours and Amare worked 28 hours.In this equation, the variable x represents the number of hours worked by Jing, which we can solve by dividing both sides of the equation by 3. On the left side of the equation, we are left with x, which equals 14. On the right side of the equation, we are left with 2x, which equals 28. This means that Jing worked 14 hours and Amare worked 28 hours. The equation and its solution demonstrate how to use algebra to solve a real-world problem. By using algebra, we can easily solve this problem and find the number of hours each person worked. This process can be used to solve other real-world problems, such as calculating the cost of items or the amount of time needed to complete a task. Algebra is an important tool that can be used to make calculations and solve problems quickly and accurately.

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Answer:

when X =2/3

y=2-9*2/3

2-6

-4

that's it

Answer: 6.4031

Step-by-step explanation:

d = √((x2 - x1)2 + (y2 - y1)2)

Find the difference between coordinates:

(x2 - x1) = (-2 - -6) = 4

(y2 - y1) = (-3 - 2) = -5

Square the results and sum them up:

(4)2 + (-5)2 = 16 + 25 = 41

Now Find the square root and that's your result:

Exact solution: √41 = √41

Approximate solution: 6.4031

Hope it helped

Answer:

9/50

Step-by-step explanation:

Answer:

please mark me as brainlist

The value of the expression b²/c² is 46656.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

We can use the given equations to express a, b, c, and d in terms of k:

a/b = b/c = c/d = k

From a/d = 1/216,

we have:

a/d = k² / (c/d)

Substituting k = b/c and simplifying:

a/d = (b/c)² / (c/d)

a/d = b² / (c² x d)

Multiplying both sides by c².

(a/d) x c² = b² / d

Substituting k = c/d:

(a/d) x c² = b² / k

Substituting a/b = k and solving for b²/c².

a/b = k

a = k x b

b = a/k

b² = a²/k²

(b²/c²) = (a²/k²) / (a²/k² x (d/c)²)

(b²/c²) = 1 / (d²/k²)

Substituting k = c/d and simplifying:

(b²/c²) = d²

Substituting a/d = 1/216:

(b²/c²) = (216²)

Therefore,

The value of the expression b²/c² is 46656.

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The complete question is:

If a/b=b/c=c/d=k plus a/d=1/216 calculate b2/c2

Can you help me with this please, it's urgent?

The standard error for the distribution of sample means for a population with a mean of 100 and a standard deviation of 15 and a sample size of 25 is:

3

The standard error for the distribution of sample means can be calculated using the formula:

SE = (standard deviation) / sqrt(sample size)

In this case, the standard deviation is 15 and the sample size is 25. Plugging these values into the formula, we get:

SE = (15) / sqrt(25)

SE = (15) / 5

SE = 3

Therefore, the standard error for the distribution of sample means is 3. This means that the distribution of sample means will have a standard deviation of 3, which is smaller than the standard deviation of the population (15). This is because the larger the sample size, the smaller the standard error, and the more accurately the sample means will represent the population mean.

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Answer:

3917

Step-by-step explanation:

Sunday:9845

Saturday:5928

9845-5928

=3917

The statement is true. The DecimalFormat class is part of the Java API, specifically within java.text package, so it is automatically available to your programs. You can use it to format numbers in various ways, such as for displaying currency or percentages.

DecimalFormat is a concrete subclass of NumberFormat that formats decimal numbers. It has a variety of features designed to make it possible to parse and format numbers in any locale, including support for Western, Arabic, and Indic digits. It also supports different kinds of numbers, including integers (123), fixed-point numbers (123.4), scientific notation (1.23E4), percentages (12%), and currency amounts ($123). All of these can be localized.

To obtain a NumberFormat for a specific locale, including the default locale, call one of NumberFormat's factory methods, such as getInstance(). In general, do not call the DecimalFormat constructors directly, since the NumberFormat factory methods may return subclasses other than DecimalFormat. If you need to customize the format object, do something like this:

NumberFormat f = NumberFormat.getInstance(loc);

if (f instanceof DecimalFormat) {

    ((DecimalFormat) f).setDecimalSeparatorAlwaysShown(true);

}

A DecimalFormat comprises a pattern and a set of symbols. The pattern may be set directly using applyPattern(), or indirectly using the API methods. The symbols are stored in a DecimalFormatSymbols object. When using the NumberFormat factory methods, the pattern and symbols are read from localized ResourceBundles

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True. The Decimal Format class is a part of the Java API and is included in the java.text package.

It is automatically available to Java programs without the need for any additional installations or imports.

The Decimal Format class is part of the Java API, and it is automatically available to your programs.

The Java API is a collection of pre-written classes, methods, and interfaces that are part of the Java Development Kit (JDK).

These classes and methods provide a wide range of functionalities that can be utilized by Java developers to build robust applications.
The Decimal Format class, specifically, is a subclass of the Number Format class and is used to format decimal numbers according to a specific pattern.

The class provides methods to format and parse decimal numbers and can be used to specify the number of digits after the decimal point, the use of a thousand separator, and the currency symbol.
The Decimal Format class in your Java program, you simply need to import the class using the import statement, and then create an instance of the class.

For example:
import java. text. Decimal Format.
public class MyClass

{
public static void main (String [] args) {
Decimal Format df = new Decimal Format("#.00");
double num = 1234.5678
System.out.println(df.format(num));
}
}
The Decimal Format class using the import statement, and then create an instance of the class called df.

We then use the format method of the class to format the decimal number 1234.5678 with two decimal places.
The Decimal Format class is an essential part of the Java API and is automatically available to your programs.

Its inclusion in the Java API makes it easier for Java developers to format decimal numbers in their applications.

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The area of the squares are

A = 17 units², B = 20 units², C = 13 units², and D = 37 units²

Count the number of complete squares that are fully contained within the shape. Start from one corner of the shape and count each square until you reach the opposite corner. Include any partial squares as well.

If there are partial squares, estimate the area they cover. You can do this by visualizing how much of each square is filled by the shape and approximate the area accordingly.

Add up the areas of the complete squares and the estimated areas of the partial squares to find the total area of the shape.

Here we have 4 squares A, B, C, and D

Now count the number of unit squares covered by each square

Number of squares covered by A =  17

Hence, the Area of Square A = 17 units²

Number of squares covered by B = 20

Hence, the Area of square B = 20 units²

Number of squares covered by C = 13

Hence, the Area of square C = 13 units²

Number of squares covered by D = 37

Hence, the Area of square D = 37 units²

Therefore,

The area of the squares are

A = 17 units², B = 20 units², C = 13 units², and D = 37 units²

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Complete Question is attached below

Regression analysis is a statistical method that is used to model the relationship between a dependent variable (the response) and one or more independent variables (the predictors).

In the case of car sales data, a regression model can be developed to predict the selling price of a car based on horsepower and manufacture year, incorporating an interaction term.

The predicted price for a car manufactured in either 2002 or 2003 with a horsepower of 69 can be determined by plugging the values into the regression model.

The interaction term in the model allows for the effect of the interaction between horsepower and manufacture year on the selling price to be captured.

The prediction can then be compared to the overall average price in each year to determine if the prediction deviates from the average.

If the prediction is higher than the average, it could indicate that the car is in high demand or has other desirable features that make it more valuable.

On the other hand, if the prediction is lower than the average, it could indicate that the car is less desirable due to factors such as age or low horsepower.

The comparison between the prediction and the overall average price in each year can provide valuable information about the car's value and its potential to sell at a higher price.

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Answer:

y = -1x + 1

Step-by-step explanation:

The slope is -1

This is because the graph goes down 1 unit (-1) as it goes to the right 1

Slope is change in y/ change in x or -1/1  or -1

The y - intercept is where the graph touches the y-axis. And this is 1 point above 0.

Slope-intercept form = y = mx + b

m = slope

b = y - intercept

y = -1x + 1

-Chetan K

Answer:

y = -1x + 1

Step-by-step explanation:

Calculate the slope from two points:

I picked (0,1) and (4,-3)

Rise = (-3 - 1) = -4

Run = (1 - 0) = 4

Slope or Rise/Run = -4/4 or -1

y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).  We can find the y-intercept since we have point (0,1).  b is 1.

Putting the slope and y-intercept into the equation:

y = -1x + 1

As per the unitary method, mixture identifies the substance

The term unitary method in statistics means mathematical process to calculate the value of a single unit from the value of multiple units and the value of multiple unit rate from the value of a single unit.

Here we have given that A student passes a magnet over 10 grams of a powder. Four grams of the powder stick to the magnet, while 6 grams do not.

And we need to find in which of these identifies the substance

While we looking into the given question , we know that the properties of the components of substance are different.

We also know that one component has magnetic properties, another does not.

Therefore, here we have at least 2 individual substances that were mixed together and we have a mixture.

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Answer:

A

Step-by-step explanation:

Remember x does not repeat for a different y, such as in B the -8 repeats, C the -3 repeats, and D 3 repeats

Answer:

a is the answer for this question

12 x 5 = 60

10x 6= 60

so 5 packs of pencils and 6 packs of erasers.

Answer:

sorry i don't know

Step-by-step explanation:

The derivative \(\frac{dy}{dx}\) of the parametric equations x = 4 sin(t) and y = 5 cos(t) is \(\frac{-5}{\sqrt{16 - x^{2} } }\).  

To find the derivative \(\frac{dy}{dx}\), to differentiate the parametric equations x = 4 sin(t) and y = 5 cos(t) with respect to t using the chain rule. Taking the derivative of x and y separately, we have  \(\frac{dx}{dt}\)= 4 cos(t) and \(\frac{dy}{dt}\) = -5 sin(t).

Next, we can find \(\frac{dy}{dx}\) by dividing \(\frac{dx}{dt}\) by \(\frac{dy}{dt}\):

\(\frac{dy}{dx}\)=  \(\frac{\frac{dy}{dt}}{\frac{dx}{dt}}\)=   \(\frac{(-5 sin(t))}{(4 cos(t))}\) = \(\frac{-5}{4}\) tan(t).

To eliminate the parameter t, we can use the relationship between x and y: \(x^{2}\) + \(y^{2}\)= 16 (derived from x = 4 sin(t) and y = 5 cos(t)). Rearranging this equation, we have \(y^{2}\) = 16 - \(x^{2}\).

Differentiating both sides with respect to x, we get:

2y\(\frac{dy}{dx}\) = -2x

Solving for \(\frac{dy}{dx}\)  = \(\frac{-5}{\sqrt{16 - x^{2} } }\)

To find the second derivative   \(\frac{d^{2}y }{dx^{2} }\) , we differentiate  \(\frac{dy}{dx}\) with respect to x. Using the quotient rule, we differentiate the numerator and denominator separately and simplify the expression to obtain

                  \(\frac{d^{2}y }{dx^{2} }\)   =  \(\frac{-5}{\sqrt{16 - x^{2} } }\) - \(\frac{-5x^{2} }{8(16 - x^{2} )^{\frac{3}{2} } }\)

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Answer:

-3x² - 3x - 2

Step-by-step explanation:

simplify the first part

-2x * x - 2x * 3

-2xx - 6x

simplify the second part

(x-1)(x-2)

x * x + x * -2 + -1 * x + -1 * -2

xx + -2x - x + 2

xx - 3x + 2

subtract the simplified expressions

-2xx - 6x - (xx - 3x + 2)

-2xx - 6x - xx + 3x - 2

-3xx - 3x - 2

Answer:

29

Step-by-step explanation:

5^2 = 5x5

=25+4

=29

Answer:

29

Step-by-step explanation:

Here, b=5

Now a= b^2+4

= (5)^2+4

=25+4

=29 Ans

the volume of the region contained in the cylinder x² + y² = 9, bounded above by the plane z = x and below by the xy-plane is 0.

Given: The cylinder is x² + y² = 9, bounded above by the plane z = x and below by the xy-planeWe know that, the cylinder is x² + y² = 9Which is (x/a)² + (y/b)² = 1Where a = 3 and b = 3The plane is z = xThe region is bounded below by the xy-plane Thus, the volume of the region can be found by integrating z = x with limits of x² + y² ≤ 9.So, V = ∭ dx dy dz where the limits are given by the cylinder and the plane.V = ∫∫∫ (x) dV ... (1)Now, converting the integral into cylindrical coordinates we have,∫∫∫ (x) dV = ∫θ = 0 to 2π ∫r = 0 to 3 ∫z = 0 to r cos θ (r cos θ) rdzdrdθ ... (2)x = r cos θ, y = r sin θ, and z = z.We know that the limits of x² + y² ≤ 9 in cylindrical coordinates are 0 ≤ θ ≤ 2π, 0 ≤ r ≤ 3, 0 ≤ z ≤ r cos θ.Using (2) in (1), we haveV = ∫θ = 0 to 2π ∫r = 0 to 3 ∫z = 0 to r cos θ (r cos θ) rdzdrdθ= ∫θ = 0 to 2π ∫r = 0 to 3 [r² cos θ / 2] dr dθ= ∫θ = 0 to 2π [ 9 cos θ / 2 ] dθ= 9 [ sin θ ]θ = 0 to 2π= 0Thus, the volume of the region contained in the cylinder x² + y² = 9, bounded above by the plane z = x and below by the xy-plane is 0.

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Answer:

7y-3x-8z

Step-by-step explanation:

(3y+4y)+(2x-5x)-8z

7y+(2x-5x)-8z

7y-3x-8z