Find the smallest part when £80 is
shared in the ratio 7:3

Answers

Answer 1

Answer:

£24

Step-by-step explanation:

= 3/(7+3) × £80

= 3/10 × £80

= £24

Answer 2
24 because 7+3=10 80 divided by 10=8 so 3 is the smallest part so you do 8x3 which equals 24

Related Questions

Find the coordinates of the midpoint of the segment with the given endpoints.
S(4, -1) and T (6,0)

Answers

Answer:

(5,-1/2)

Step-by-step explanation:

Midpoint formula is x1 +x2 /2 is equal to the x-value, y2+y1 /2 is the y-value. Simply plug it into the formula to get the answer

What is the LCM of 72, 96and 160​

Answers

Ladder method:

Keep dividing the number by 2, 3, 4 etc. (By the lowest value) until you reach 1.
In order to find LCM, take the highest value of all the 3 numbers and multiply them together.

Hope it made sense for you!
What is the LCM of 72, 96and 160

Let a belong to a ring R. let S= (x belong R such that ax = 0) show that s is a subring of R

Answers

S satisfies all the conditions of being a subring of R, and we can conclude that S is indeed a subring of R.

To show that S is a subring of R, we need to verify the following three conditions:

1. S is closed under addition: Let x, y belong to S. Then, we have ax = 0 and ay = 0. Adding these equations, we get a(x + y) = ax + ay = 0 + 0 = 0. Thus, x + y belongs to S.

2. S is closed under multiplication: Let x, y belong to S. Then, we have ax = 0 and ay = 0. Multiplying these equations, we get a(xy) = (ax)(ay) = 0. Thus, xy belongs to S.

3. S contains the additive identity and additive inverses: Since R is a ring, it has an additive identity element 0. Since a0 = 0, we have 0 belongs to S. Also, if x belongs to S, then ax = 0, so -ax = 0, and (-1)x = -(ax) = 0. Thus, -x belongs to S.

Therefore, S satisfies all the conditions of being a subring of R, and we can conclude that S is indeed a subring of R.

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What is the formula for dy dx?

Answers

The formula for dy/dx is the derivative of y with respect to x. It represents the rate of change of y with respect to x.

In calculus, the derivative of a function with respect to a variable x is a measure of how much the function changes as the variable x changes. The notation for the derivative of a function y with respect to x is dy/dx, read as "delta y over delta x". This notation is called a "derivative" and it represents the rate of change of the function y with respect to x.

The derivative of a function can be calculated using the limit definition of the derivative or with the use of different rules such as power rule, product rule, quotient rule, chain rule, and more. The derivative can also be represented graphically as the slope of a tangent line to the function's graph.

Derivatives are widely used in mathematics, physics, engineering, and other sciences to model various phenomena.

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Divide.

6,859 ÷ 79

The quotient is

and the remainder is
.

Answers

Answer:

86, 65

Step-by-step explanation:

Quotient is 86

Remainder is 65

If one item is chosen from m items, a second item is chosen from n items, and a third item is chosen from p items, the total number of three-item choices is?

Answers

If one item is chosen from m items, a second item is chosen from n items, and a third item is chosen from p items, the total number of three-item choices is MNP.

What is probability?

Probability  can be regarded as a  measure of the likelihood of an event  that can take place.

It should be noted that  Many events cannot be predicted with total certainty, hence , If one item is chosen from m items, a second item is chosen from n items, and a third item is chosen from p items, the total number of three-item choices is MNP.

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(-2x)^4
What’s is the answer pls it’s the last one

Answers

Answer:

16x^4

Step-by-step explanation:

Answer:16x

Step-by-step explanation:

Given three squares of different areas, the perimeter of square A 2/3 the perimeter of square B and the perimeter of square B is 2/3 the perimeter of square C. if the area of Square A is 16 square units, what is the area of square C?


I’ll mark BRAINLIEST the first to answer my question :)

Answers

Area of square A = 16 cm

side of square A a1 = 4cm

side of square A = 2/3(2/3a3)

a1= 4/9a3

a3 = 9cm

Area of square C = 9×9= 81 Cm²

HELPPP IT'S DUE IN 30 MINUTES I"LL MARK YOU THE BRAINLIEST!!!

You are a wedding planner who is filling small pouches with biodegradable confetti for a wedding reception. You want to fill each pouch with of a cup of confetti, and you have a total of 210 fluid ounces of confetti. You need enough pouches for 120 guests.

Which equation can you use to determine whether you have enough pouches for 120 guests?

number of pouches = 210 +
number of pouches = 210 –
number of pouches = 210 × 8 ×
number of pouches = 210 ÷ 8 ×
number of pouches = 210 ÷ 8 ÷

Answers

Answer:

you have 26 cups so i think its the 4th one or the 5th one

Step-by-step explanation:

Hope this helps!

9. Sara and Yusuf's grandmother gives them money for Christmas every year. They share the money in the
ratio of their ages. This year their grandmother gave them R1 500 together. Sara received R675. They are both younger than 18 years old. Determine how old Sara and Yusuf are.
in​

Answers

Answer:

Sara is 9 years old while Yusuf's is 11 years old

Step-by-step explanation:

The given parameters are;

The ratio Sara and Yusuf share the money they receive = The ratio of their ages

The amount Sara and Yusuf received from their grandmother this year = R1,500

The amount of money Sara receives = R675

Therefore, the amount of money Yusuf receives = R1,500 - R675 = R825

Let 'x', and 'y' represent the ages of Sara and Yusuf

Therefore, the ratio of their ages, x/y = R675/R825) = 9/11

x·11 = y·9

x, and y < 18

When x = 9, y = 11, we  get;

9·11 = 11·9

Therefore a possible solution is Sara's age = x = 9 and a possible solution for Yusuf's age, y = 9

According to a survey of workers 6/50 of them walk to break 3/50 bike 10/50 carpool and 31/50 Drive alone what percent of workers walk or bike to work

Answers

Answer:

Step-by-step explanation:

6+3=9/50

9/50 x  100=18 percent

To solve the system of linear equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 by using the linear combination method, Henry decided that he should first multiply the first equation by –3 and then add the two equations together to eliminate the x-terms. When he did so, he also eliminated the y-terms and got the equation 0 = 0, so he thought that the system of equations must have an infinite number of solutions. To check his answer, he graphed the equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 with his graphing calculator, but he could only see one line. Why is this?

Answers

Henry could only see one line since both lines had the same slope, which means that the graphs of both equations will be identical and hence overlap.

Identify the linear equation?

Linear equations in a system 3x + 2y = 4, and 9x + 6y = 12

We must demonstrate why Henry could only make out one line when he plotted the equations 3x-2y=4 and 9x-6y=12 on a graph.

Take the provided linear equation system into consideration.

3x - 2y = 4 ................(1)

9x - 6y = 12 ..................(2)

Due to the fact that equation (2) is a multiple of equation (1), 3 (3x - 2y = 4) = 9x - 6y = 12

The slopes of the provided equations are also same.

Difference with regard to x for equation (1) yields,

additional to equation (2),

With regard to x, we can differentiate to get,

The graphs of both equations will overlap since both lines have the same slope and hence have the same appearance on the graph.

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Solve: 2.4y - 3.2 = 4
A y = 0.5
B y = 1.6
C y = 2
D y = 3

Answers

Answer:

y=3 you have to use PEMDAS

Answer:

y=3

Step-by-step explanation:

Combine multiplied terms into a single fraction

2.4y-3.2=4

12y/5 -3.2=4

Add 3.2 to both sides of the equation

12y/5- 3.2+3.2=4+3.2

Simplify

add the numbers 12y/5=7.2

Solution

y=3

Evaluate (fog)( -8) without finding an equation for the functiof(x) = 4x - 3g(x) = 9x - 9(fog)(-8)=(Simplify your answer.)

Answers

Answer:

(fog)( -8) = -327.

Explanation:

Given the functions, f(x) and g(x):

To evaluate (fog)( -8), first, we rewrite it as follows:

\((f\circ g)(-8)=f\lbrack g(-8)\rbrack_{}\)

First, evaluate g(-8).

\(\begin{gathered} g(-8)=9(-8)-9 \\ =-72-9 \\ =-81 \end{gathered}\)

Next, substitute g(-8):

\(\begin{gathered} f\lbrack g(-8)\rbrack=f(-81) \\ f(x)=4x-3 \\ f(-81)=4(-81)-3 \\ =-324-3 \\ =-327 \end{gathered}\)

Thus, the value of (fog)( -8) is -327.

An element with a mass of 310 grams disintegrates at 5.7% per minute. How much of the element remains after 9 minutes, to the nearest tenth of a gram?

Answers

Answer:

Step-by-step explanation:

I think 17.5

6. Find the HCF and LCM of: (b) (a) 4(a²-4), 6(a²-a-2) and 12(a² + 3a-10) 2x²-3xy-2y², 6x² + xy - y² and 3x² - 7xy + 2y² (c) a(c + a)-b(b + c), b(a + b)-c(c + a) and c(b + c)-a(a + b) (d) p² +q²+2pq-1, q²-p² + 2q + 1 and p² - q² + 2p + 1 (e) 6x²-5x-4, 8x² + 2x - 15 and 12x²-43x +35​

Answers

The HCF is (a-2) and the LCM is 288(a+2)(a+1)(a+5) of 4(a²-4), 6(a²-a-2) and 12(a² + 3a-10)

To find the highest common factor (HCF) and least common multiple (LCM) of the given expressions, let's factorize each expression first:

4(a²-4) = 4(a+2)(a-2)

6(a²-a-2) = 6(a-2)(a+1)

12(a²+3a-10) = 12(a+5)(a-2)

The common factors among these expressions are (a-2). So the HCF is (a-2).

To find the LCM, we multiply all the distinct factors from the factorizations:

LCM = 4 × 6 × 12 × (a+2)(a+1)(a+5) = 288(a+2)(a+1)(a+5)

Therefore, the HCF is (a-2) and the LCM is 288(a+2)(a+1)(a+5).

Let's factorize each expression:

a(c + a) - b(b + c) = a² + ac - b² - bc

b(a + b) - c(c + a) = ab + b² - c² - ac

c(b + c) - a(a + b) = cb + c² - a² - ab

The common factors among these expressions are (a+b+c). So the HCF is (a+b+c).

To find the LCM, we multiply all the distinct factors from the factorizations:

LCM = (a+b+c)(a² + ac - b² - bc)(ab + b² - c² - ac)

Therefore, the HCF is (a+b+c) and the LCM is (a+b+c)(a² + ac - b² - bc)(ab + b² - c² - ac).

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Help me, please! Love math but there are some things that fumble my brain. Look at the picture below and follow directions. Please provide a reasonable answer.

Help me, please! Love math but there are some things that fumble my brain. Look at the picture below

Answers

Answer:

In 2007 it was 450 and 2011 it was 300

Step-by-step explanation:

So the change was 300 I think this correct

if the inside height of the trailer is 6.5 feet, what is the total volume of the inside of the trailer, to the nearest cubic foot?

Answers

The cross sectional area of the cargo trailer floor, which is a composite figure consisting of a square and an isosceles triangle, indicates that the volume of the inside of the trailer is about 3,952 ft³.

What is a composite figure?

A composite figure is a figure comprising of two or more regular figures.

The possible cross section of the trailer, obtained from a similar question on the internet, includes a composite figure, which includes a rectangle and an isosceles triangle.

Please find attached the cross section of the Cargo Trailer Floor created with MS Word.

The dimensions of the rectangle are; Width = 6 ft, length = 10 ft

The dimensions of the triangle are; Base length 6 ft, leg length = 4 ft

Height of the triangular cross section = √(4² - (6/2)²) = √(7)

The cross sectional area of the trailer, A = 6 × 10 + (1/2) × 6 × √(7)

A = 60 + 3·√7

Volume of the trailer, V = Cross sectional area × Height

V = (60 + 3·√7) × 6.5 = 3900 + 19.5·√7

Volume of the trailer = (3,900 + 19.5·√(7)) ft³ ≈ 3952 ft³

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if the inside height of the trailer is 6.5 feet, what is the total volume of the inside of the trailer,

How do I prove that the sum of exterior angles of any polygon is equal to 360 degrees?

Answers

To prove that the sum of the exterior angles of any polygon is equal to 360 degrees, the Sum of interior angles = (n - 2) x 180 degrees.

we can use the following steps:

Draw any polygon and mark a point outside the polygon for each vertex.

Draw a line segment connecting each vertex to the point outside the polygon that corresponds to it, creating an exterior angle at each vertex.

Measure each exterior angle using a protractor and record the measurements.

Sum all the exterior angles together and observe the result.

We can see that the sum of all the exterior angles is always equal to 360 degrees, regardless of the number of sides or the shape of the polygon. This can be written as:

The sum of exterior angles = 360 degrees

To prove this algebraically, we can use the fact that the sum of the interior angles of any polygon is given by the formula:

Sum of interior angles = (n - 2) x 180 degrees

where n is the number of sides of the polygon. Each exterior angle is supplementary to the corresponding interior angle, so we can write:

The sum of exterior angles = Sum of interior angles (supplementary angles)

Substituting the formula for the sum of interior angles, we get:

Sum of exterior angles = (n - 2) x 180 degrees (supplementary angles)

= 180n - 360 degrees

= 360 degrees - 360 degrees + 180n

= 360 degrees - Sum of interior angles

= 360 degrees - (n - 2) x 180 degrees

= 360 degrees - 180n + 360 degrees

= 720 degrees - 180n

Since the sum of the exterior angles must be a positive value, we can take the absolute value and simplify:

|Sum of exterior angles| = |720 degrees - 180n|

= 180|4 - n|

Since n is always a positive integer greater than or equal to 3 (since a polygon must have at least three sides), we know that 4 - n is always a negative integer between -1 and -n+1. Therefore, |4 - n| is equal to n - 4. Substituting this into the equation above, we get:

|Sum of exterior angles| = 180|n - 4|

= 180(n - 4)

= 180n - 720 degrees

= 360 degrees - 360 degrees + 180n - 720 degrees

= 360 degrees - Sum of interior angles

Therefore, we have shown that the sum of the exterior angles of any polygon is equal to 360 degrees.

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The radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder with water. The radius of the cone's base is 5 centimeters, and its height is 10 centimeters
The number of times one needs to use completely filled cone to completely fill the cylinder with water is...

Answers

The number of times one needs to use completely filled cone to completely fill the cylinder with water is 24

What is volume of cone and cylinder?

The volume of cylinder is equal to the product of the area of the circular base and the height of the cylinder.

Given that radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters.

The radius of the cone's base is 5 centimeters, and its height is 10 centimeters.

The volume of cylinder is πr²h

For a volume of cone it is 1⁄3πr²h.

So volume of cylinder = 22/7×(10)2×20=3.142×100×20

=6284

volume of cone it is 1⁄3πr²h=1/3×3.142×(5)^2×10=261.16

Number of times one needs to use the completely filled cone to completely fill the cylinder with water =

= Volume of cylinder/Volume of cone

6284 / 261.16 = 24

Hence the number of times one needs to use completely filled cone to completely fill the cylinder with water is 24

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What is the area of this triangle? A=B x H 12
Height= 127 ft
Base= 13ft

Answers

Answer:

The area of this triangle is 825.5 square feet

Step-by-step explanation:

For a given Triangle

Base = 13 ft

Height = 127 ft

Now, Area of Triangle

A = ½ × b × h

A = ½ × 13 × 127 ft

A = ½ × 1751 ft

A = 825.5 square feet

Thus, The area of this triangle is 825.5 square feet.

-TheUnknownScientist 72

Suppose X and Y are continuous random variables with joint pdf f(x, y) = 24xy if 0 < x, 0 < y, and x + y < 1, and zero otherwise.
(a) Find E(XY).
(b) Find the covariance of X and Y.
(c) Find the correlation coefficient of X and Y.
(d) Find Cov(3X, 5Y).
(e) Find Cov(X + 1, Y - 2).
(f) Find Cov(X + 1, 5Y - 2).
(g) Find Cov(3X + 5, X).

Answers

The covariance of X and Y is 13/10, correlation coefficient of X and Y is 1,

the Covariance at (3X, 5Y) is also 3/200 of the given continuous random varaible.

a) To find E(XY), we need to calculate the double integral of xy times the joint pdf over the region where the pdf is nonzero:

E(XY) = ∫∫ xy * f(x,y) dx dy

      = ∫0¹ ∫0^(1-x) 24xy * dx dy     (since x + y < 1, the limits of y are from 0 to 1-x)

      = ∫0¹ 12x(1-x)^2 dy

      = ∫0¹ (12x - 24x^2 + 12x^3) dy

      = 4/3 - 6/5 + 3/4

      = 1/5

Therefore, E(XY) = 1/5.

(b) The covariance of X and Y is given by:

Cov(X, Y) = E(XY) - E(X)E(Y)

We have already calculated E(XY) in part (a), so we just need to calculate E(X) and E(Y):

E(X) = ∫∫ x * f(x,y) dx dy

= ∫0¹ ∫0^(1-x) 24xy * x dx dy

= ∫0¹ 6x(1-x)^3 dx

= 1/2 - 1/5

= 3/10

Similarly, we can find that E(Y) = 3/10.

Therefore, Cov(X, Y) = E(XY) - E(X)E(Y) = 1/5 - (3/10)*(3/10) = 1/100.

(c) The correlation coefficient of X and Y is given by:

ρ(X, Y) = Cov(X, Y) / (σ(X)σ(Y))

where σ(X) and σ(Y) are the standard deviations of X and Y, respectively. To find σ(X) and σ(Y), we need to first find the variances of X and Y:

Var(X) = E(X^2) - [E(X)]^2

      = ∫∫ x^2 * f(x,y) dx dy - (3/10)^2

      = ∫0¹ ∫0^(1-x) 24xy * x^2 dx dy - 9/100

      = ∫0¹ 2x(1-x)^3 dx - 9/100

      = 1/18 - 1/40

      = 11/360

Similarly, we can find that Var(Y) = 11/360.

Therefore, σ(X) = sqrt(Var(X)) = sqrt(11/360), and σ(Y) = sqrt(Var(Y)) = sqrt(11/360).

Now, we can find ρ(X, Y) as follows:

ρ(X, Y) = Cov(X, Y) / (σ(X)σ(Y))

= (1/100) / (sqrt(11/360) * sqrt(11/360))

= 1

Therefore, the correlation coefficient of X and Y is 1.

(d) To find Cov(3X, 5Y), we can use the property that Cov(aX, bY) = ab Cov(X, Y) for any constants a and b:

Cov(3X, 5Y) = 3 * 5 * Cov(X, Y)

            = 15 * 1/100

            = 3/200

Therefore, Cov(3X, 5Y) = 3/200

e)we can find the covariance of X + 1 and Y - 2:

Cov(X+1, Y-2) = E[(X+1)(Y-2)] - E[X+1]E[Y-2]

Using the definition of expected value and the joint pdf, we have:

E[(X+1)(Y-2)] = ∫∫(x+1)(y-2) f(x,y) dx dy

             = ∫[0,1] ∫[0,1-x] (x+1)(y-2) 24xy dy dx

             = ∫[0,1] 24x ∫[0,1-x] (xy-2x-2y+2) dy dx

             = ∫[0,1] 24x [x(1-x)^2 - 2x(1-x) - 2(1-x)^2 + 2(1-x)] dx

             = 2/3

Similarly, we can find:

E[X+1] = E[X] + 1/2 = 1

E[Y-2] = E[Y] - 2/3 = 1/3

Therefore,

Cov(X+1, Y-2) = E[(X+1)(Y-2)] - E[X+1]E[Y-2] = 2/3 - 1*(1/3) = 1/3

f)To find the covariance of X + 1 and 5Y - 2, we can use the same formula as above and compute the required expected values:

E[(X+1)(5Y-2)] = ∫∫(x+1)(5y-2) f(x,y) dx dy

              = ∫[0,1] ∫[0,1-x] (5xy-2x+5y-2) 24xy dy dx

              = ∫[0,1] 24x ∫[0,1-x] (5xy-2x+5y-2) dy dx

              = 4/3

E[X+1] = 1

E[5Y-2] = 5E[Y] - 2/3 = 13/3

g)Cov(3X + 5, X) = E[(3X + 5)X] - E[3X + 5]E[X]

To find E[(3X + 5)X], we'll use the definition of expected value for continuous random variables:

E[(3X + 5)X] = ∫∫ (3x+5)x f(x,y) dy dx

       = ∫∫ (3x^2 + 5x) (24xy) dy dx from y=0 to y=1-x and x=0 to x=1

       = ∫ 0^1 ∫ 0^(1-x) (72x^2y + 120xy) dy dx

       = ∫ 0^1 36x^2(1-x)^2 + 60x(1-x)^3 dx

       = 6/5

Next, we need to find E[3X + 5]:

E[3X + 5] = 3E[X] + 5

To find E[X], we'll integrate the marginal pdf of X:

f_X(x) = ∫ (24xy) dy from y=0 to y=1-x = 12x(1-x) for 0<x<1

E[X] = ∫ x f_X(x) dx from x=0 to x=1

 = ∫ 0^1 x (12x(1-x)) dx

 = 1/2

Putting it all together:

Cov(3X + 5, X) = E[(3X + 5)X] - E[3X + 5]E[X]

           = 6/5 - (3(1/2) + 5)(1/2)

           = -2/5

Therefore, Cov(3X + 5, X) = -2/5.

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A minivan is traveling at 80.5 kilometers per hour. Cargo is strapped to the roof at a height of 1.75 meters. The car hits a concrete barrier, and the cargo is ejected from the roof. Use the following two equations to determine how long it takes for the cargo to hit the ground and how far it travels in the horizontal direction. Let y represent height in meters, x represent horizontal distance in meters, and t represent time in seconds. Equation 1: y = -4.9t2 + 1.75 Equation 2: y = -0.0081x2 + 1.75

Answers

The time taken for the cargo to hit the ground will be 0.6 seconds and it travels in the horizontal direction for around 14.69 feet.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign. The point-slope form, standard form, and slope-intercept form are the three main types of linear equations. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here,

The calculations are attached in images.

To calculate t we will use that is y because at the moment of cargo will have a height 0, so we get,

= −4.9t² +1.75

-1.75=-4.9t²

t²=-1.75/-4.9

t²=√0.3571

=0.6 seconds

Now we will calculate x, then y = 0

because since the cargo will be on the ground it will no have height, so

0= -0.0081x²+1.75

-1.75 =-0.0081x²

x²=-1.75/-0.0081

x= √216.04 = 14.69 feet

It will take the cargo 0.6 seconds to hit the ground, and it will travel 14.69 feet in a horizontal direction.

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A minivan is traveling at 80.5 kilometers per hour. Cargo is strapped to the roof at a height of 1.75
A minivan is traveling at 80.5 kilometers per hour. Cargo is strapped to the roof at a height of 1.75

HELP ME PLS I WILL GIVE YOU THE BRAINEST

HELP ME PLS I WILL GIVE YOU THE BRAINEST

Answers

Answer:

The first term should be positive

She did not distribute the -4 properly

She added \(\frac{2}{7}\) to negative -4 instead of multiplying

Step-by-step explanation:

In order to tell where she is wrong we should solve the question our selves. we are going to get the following......

\(-4(-3x + \frac{2}{7})= -4(-3x) + (-4)(\frac{2}{7} )= 12x - \frac{8}{7}\)

So now we see that the three things she did wrong are.

The first term should be positive

She did not distribute the -4 properly

She added \(\frac{2}{7}\) to negative -4 instead of multiplying

Hope this helps :)

Answer:

1, 4

Step-by-step explanation:

1. the product of two negatives are positive and they didn't do that, so yes.

2. the second term should NOT be positive, so they are correct on that.

3. they distributed the -4 correctly but added wrong, so they are correct on that.

4. -4+2/7=3 5/7    2/6(-4)=-4/3.  They added instead of multiplying, so they are wrong.

5.  they did simplify completely.  they just did it wrong.

Given that y ′ =xy and y(0)=3. Use the Euler's method to approximate value of y(1) by using five equal intervals. Correct your answer to 2 decimal places.

Answers

Using five equal intervals and Euler's method, we approximate the value of y(1) to be 3.69 (corrected to 2 decimal places).

Euler's method is a first-order numerical procedure used for solving ordinary differential equations (ODEs) with a given initial value. In simple terms, Euler's method involves using the tangent line to the curve at the initial point to estimate the value of the function at some point.

The formula for Euler's method is:

y_(i+1) = y_i + h*f(x_i, y_i)

where y_i is the estimate of the function at the ith step, f(x_i, y_i) is the slope of the tangent line to the curve at (x_i, y_i), h is the step size, and y_(i+1) is the estimate of the function at the (i+1)th step.

Given that y' = xy and y(0) = 3, we want to approximate the value of y(1) using five equal intervals. To use Euler's method, we first need to calculate the step size. Since we want to use five equal intervals, the step size is:

h = 1/5 = 0.2

Using the initial condition y(0) = 3, the first estimate of the function is:

y_1 = y_0 + hf(x_0, y_0) = 3 + 0.2(0)*(3) = 3

The second estimate is:

y_2 = y_1 + hf(x_1, y_1) = 3 + 0.2(0.2)*(3) = 3.12

The third estimate is:

y_3 = y_2 + hf(x_2, y_2) = 3.12 + 0.2(0.4)*(3.12) = 3.26976

The fourth estimate is:

y_4 = y_3 + hf(x_3, y_3) = 3.26976 + 0.2(0.6)*(3.26976) = 3.4588

The fifth estimate is:

y_5 = y_4 + hf(x_4, y_4) = 3.4588 + 0.2(0.8)*(3.4588) = 3.69244

Therefore , using Euler's approach and five evenly spaced intervals, we arrive at an approximation for the value of y(1) of 3.69 (adjusted to two decimal places).

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Determine all finite subgroups of C*, the group of nonzero complex numbers under multiplication.

Answers

All finite subgroups of C* are the trivial subgroup, the subgroup of roots of unity, the cyclic subgroups, and the subgroup consists of all powers of a single nonzero complex number

Let's explore the finite subgroups of C*, the group of nonzero complex numbers under multiplication.

First, let's recall that C is isomorphic to the group (R, +), where R represents the set of real numbers under addition.

Thus, we can view C as the group of real numbers excluding 0 under multiplication.

Now, since we are looking for finite subgroups, let's consider the possible finite subgroups of C*:

The trivial subgroup:

This consists of the identity element 1, which is the only element in this subgroup.

The subgroup of roots of unity:

This subgroup consists of complex numbers of the form \(e^{2\pi i/n}\), where n is a positive integer.

These numbers are all of finite order, with order n.

This subgroup is isomorphic to the group Zn of integers modulo n under addition.

The cyclic subgroups:

These subgroups are generated by a single nonzero complex number.

The order of the generator determines the order of the subgroup.

For example, if we take a complex number z and generate a subgroup, it will consist of z, z², z³, and so on, until we reach zⁿ = 1, where n is the order of the subgroup.

The subgroup consists of all powers of a single nonzero complex number:

This is similar to the cyclic subgroups, but instead of considering the powers of a single element, we consider the powers of all nonzero complex numbers.

This subgroup is isomorphic to the group of integers Z under addition.

These are the main types of finite subgroups of C. Each of these subgroups has its own unique properties and structure, making C a fascinating group to study.

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Part A simplify the expression . Part B Evaluate the expression 8b + 8 - 4b + 3​

Answers

Answer

A) 4b+11   B) To evaluate the expression make sure you give the value of B because in order to simplify you need to find out the answer to b to then evaluate

Step-by-step explanation:

Part A

8b+8-4b+3

8b-4b+8+3

4b+11

Answer:

4b+11

Step-by-step explanation:

8b + 8 - 4b + 3

8b + 8 - 4b + 3

4b+8+3

4b+8+3

4b+11

a fruit stand has to decide what to charge for their produce. they decide to charge $ 5.30 $5.30dollar sign, 5, point, 30 for 1 11 apple and 1 11 orange. they also plan to charge $ 14 $14dollar sign, 14 for 2 22 apples and 2 22 oranges. we put this information into a system of linear equations.

Answers

The system of linear equations are;

a + b = 5.30

a + b = 7

Expressing the information as a system of linear equations:

Consider that apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we get the equation as

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges,  then we get the equation as ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations give varying combined cost for an equal amount of fruit, so a unique cost cannot be obtained for each fruit from the systems of equation using a simultaneous equation process.

From (1)

a = 5.30 - b

Put a, b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14

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In 20 years Lillian will be three years older than twice her current age. Set up an equation that
can be used to solve for x, Lillian's current age.

Answers

Answer:

ok so x is her currect age y is her age in 20 years

2x+6=y

x+20=y

that means that both sides are equal

2x+6=x+20

-6

2x=x+14

-x

x=14

so her currect age is 14 and lets plug in

14+20=34

her currect age is 14 and her age in 20 years is 34

Hope This Helps!!!

In this figure, triangle GHJ is similar to traingle PQR.
Based on this information, which ratio represents tan H?
A.17/8
B. 15/8
C. 8/15
D.8/17

In this figure, triangle GHJ is similar to traingle PQR.Based on this information, which ratio represents

Answers

I believe it’s D) 8/17, I’m sorry if I’m wrong
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