Answers
3.
Hope it helps have a great day.
Related Questions
What are the index of summation, the upper bound of summation, and the lower bour ∑i=29(i−8) index of summation upper bound lower bound
Answers
The given summation expression ∑i=29(i−8) has the index of summation (i), the upper bound (29), and the lower bound (unspecified).
The index of summation, denoted by the letter in the summation notation, represents the variable that takes on different values as the sum is computed.
In this case, the index of summation is "i". The upper bound specifies the last value of the index for which the summation is performed. In this case, the upper bound is 29.
However, the lower bound is not specified in the given expression. The lower bound represents the starting value of the index for which the summation begins. Without a specified lower bound, we cannot determine the full range of values over which the summation is computed.
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Alex has a 48 -ounce sports drink. He drinks 16 ounces. What
percentage of ounces does Alex have left of his sports drink?
Answers
Answer:
32% or just 32
Step-by-step explanation:
a spinner has three sections. the table shows the results of spinning the arrow on the spinner 80 times. what is the experimental probability of the arrow stopping over section 1? responses 128 1 over 28 720 7 over 20 713 7 over 13 45 4 over 5 section 1section 2section 3 283616
Answers
The experimental probability of the arrow stopping over section 1 is 7/13, or 0.538.
To calculate this, you need to take the number of times the arrow stopped on section 1 (45) and divide it by the total number of times the arrow was spun (80). This can be expressed as a fraction (45/80), which can be simplified to 7/13. To convert this fraction to a decimal, divide the numerator by the denominator (7/13 = 0.538).
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answer for branniest
Answers
Answer: Hard to say... Your image is a black Screen.
Answer:
what am i anwsering
Step-by-step explanation:
What is the cost of 4 pairs of Nikes if each pair is $365.68 along with 120 peaches that each cost $9.00? Help giving away 30 points
Answers
Answer: The cost of the 4 pairs of Nikes is $257.68. Each pair cost $64.42.
Step-by-step explanation:
First, I did 120 times $9.00 for the total cost of all the peaches.
120 times $9.00 = $108
Second, I subtracted the $108 from $365.68, so I could get the total price for the 4 pairs of Nikes.
$365.68 - $108 = $257.68
Last, I divided $257.68 by 4, so I could get the cost for each pair of Nikes.
$257.68 divided by 4 = $64.42
Therefore,
The cost for the peaches is $108.
The cost for all the Nikes is $257.68
The cost for each pair of Nikes is $64.42
, Hope this helps :)
Have a great day!!
n an analysis of leg strength for 57 female athletes, with y = maximum leg press and x = number of 200-pound leg presses until fatigue, the regression equation is ý = 240.85 +4.81x. Complete parts a through c using the software output shown below for observations at x = 25. Predicted Values for New Observations New Obs Fit SE Fit 95% CI 95% PI 361.10 5.22 (350.66,371.54) (282.28,439.92) 1 a. Show how the software got the "Fit" of 361.10. O A. The "Fit" is y evaluated at x = 25 or y = 240.85 +4.81(25). 57 - 240.85 O B. The "Fit" is x evaluated at y = 57 or x = 4.81 O C. The "Fit" is y evaluated at x = 25 or y = 240.85 +4.81(25). OD. The "Fit" is evaluated at y = 57 or 8 = 57 - 240.85 4.81 b. Using the predicted value and se value, explain how the software got the interval listed under "95% CI." Choose the correct answer below. O A. The 95% confidence interval is labeled as "95% CI." These bounds are given by ý + se. OB. The 95% confidence interval is labeled as "95% CI." These bounds are given by ý +2se. OC. The 95% confidence interval is labeled as "95% CI." These bounds are given by se + 2º Interpret the interval listed under "95% CI." Choose the correct answer below. O A. For all female high school athletes who can do 25 leg presses, there is 95% confidence that the mean of their maximum leg press is between about 351 and 372 pounds. OB. For all female high school athletes who can do 25 leg presses, predict that 95% of them have a maximum leg press between about 351 and 372 pounds. O C. For the female high school athletes in this sample who can do 25 leg presses, there is 95% confidence that the mean of their maximum leg press is between about 351 and 372 pounds. OD. For the female high school athletes in this sample who can do 25 leg presses, predict that 95% of them have a maximum leg press between about 351 and 372 pounds c. Interpret the interval listed under "95% PL." O A. For all female high school athletes who can do 25 leg presses, there is 95% confidence that the mean of their maximum leg press is between about 282 and 440 pounds. OB. For the female high school athletes in this sample who can do 25 leg presses, predict that 95% of them have a maximum leg press between about 282 and 440 pounds. O c. For all female high school athletes who can do 25 leg presses, predict that 95% of them have a maximum leg press between about 282 and 440 pounds. OD. For the female high school athletes in this sample who can do 25 leg presses, there is 95% confidence that the mean of their maximum leg press is between about 282 and 440 pounds.
Answers
y = 240.85 + 4.81(25) = 361.10
Therefore, the predicted maximum leg press for a female athlete who can do 25 leg presses until fatigue is 361.10 pounds.
b. The 95% confidence interval listed under "95% CI" is given by the formula:
95% CI = (Fit - 1.96 SE, Fit + 1.96 SE)
where "Fit" is the predicted maximum leg press and "SE" is the standard error of the estimate, which is given as 5.22 in the software output.
Therefore, the 95% confidence interval is:
95% CI = (361.10 - 1.96(5.22), 361.10 + 1.96(5.22)) = (350.66, 371.54)
c. The 95% prediction interval listed under "95% PI" is the range of values within which we can predict with 95% confidence that a new observation will fall.
In this case, the 95% prediction interval is given by the formula:
95% PI = (Fit - 1.96 SE, Fit + 1.96 SE)
where "Fit" is the predicted maximum leg press and "SE" is the standard error of the estimate, which is given as 5.22 in the software output.
Therefore, the 95% prediction interval is:
95% PI = (361.10 - 1.96(5.22), 361.10 + 1.96(5.22)) = (282.28, 439.92)
Thus, we can predict with 95% confidence that a new female athlete who can do 25 leg presses until fatigue will have a maximum leg press between about 282 and 440 pounds.
.Use the given decision tree to answer the questions that follow. Payoffs are profits/losses. s1 (0.78) -$4,700 A s2 $14,200 s1 -$5,000 (в s2 (0.22) $15,200 Q a) The expected value at node A, EV(A) is $____ b) The expected value at node B, EV(B) is $____ c) The expected value at node C, EV(C) is $____ d) The expected value with perfect information, EV with PI is $____ e) The expected value of perfect information, EV PI is $ ____
Answers
The expected value of perfect information is $580.$
Given decision tree is shown below: [asy]
size(200,200);
draw((0,0)--(20,-20)--(20,-40), MidArcArrow(size=8));
draw((0,0)--(20,-10)--(20,-30), MidArcArrow(size=8));
draw((20,-20)--(40,-25)--(40,-15), MidArcArrow(size=8));
draw((20,-10)--(40,-5)--(40,-15), MidArcArrow(size=8));
label("$s1 (0.78)$", (0,0), W);
label("$s2$", (0,0), E);
label("$-4700$",(20,-20), W);
label("$14200$",(20,-10), W);
label("$-5000$",(40,-15), W);
label("$15200$",(40,-25), W);
[/asy]
$$EV(C) = (0.45)\cdot(-3000)+(0.55)\cdot(-600)
$$EV(C) = -1300$$
The expected value with perfect information, EV with PI is $ 4670.$
EV with PI is equal to the maximum expected value at each decision node. $$EV with PI = \max\{EV(B), EV(C)\}
$$EV with PI = \max\{780,-1300\}
$$EV with PI = 780$$
e) The expected value of perfect information, EV PI is $ 580.
$ the expected value of perfect information is calculated as the difference between the expected value with PI and the expected value at the decision node.
$$EV PI = EV with PI - EV(A)
$$EV PI = 780 - (-702)
$$EV PI= 1482$$
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Which of the following correlation coefficients represents the strongest relationship between two variables? -.75 +.60 .00 +.30
Answers
The correlation coefficient that represents the strongest relationship between two variables is -0.75.
In correlation coefficients, the absolute value indicates the strength of the relationship between variables. The strength of the association increases with the absolute value's proximity to 1.
The maximum absolute value in this instance is -0.75, which denotes a significant negative correlation. The relevance of the reverse correlation value of -0.75 is demonstrated by the noteworthy unfavorable correlation between the two variables.
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A recycling center claims to give 96
cents for every 12 aluminum cans
turned in.
Answers
Using the cross-multiplication formula we conclude that 768 cents will be given for 96 can recycled.
What is cross-multiplication?Cross multiplying is the process of multiplying the denominator of the second fraction on the other side of the equals to sign by the numerator of the first fraction on the same side.
In a similar manner, the numerator of the second fraction is multiplied by the denominator of the first fraction. Cross-multiplication is another name for the butterfly method. We employ the cross-multiply approach to identify one or more variables in a fraction. Cross multiplying is another method for comparing fractions.
We will do simple cross-multiplication here
given that for 12 cans we get 96 cents, that is
⇒ 12/96
and for 96 cans we get x cents, that is
⇒ x/96
Now, we do cross-multiplication here
⇒ 12/96 = 96/x
⇒ 12x = 96 × 96
⇒ x = (96 × 96)/12
⇒ x = 768 cents
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Correct question
A recycling center claims to give 96 cents for every 12 aluminum cans turned in. How much cents will they give if u recycled 96 cans?
Let R be the region bounded by the following curves. Find the volume of the solid generated by revolving the shaded region shown to the right about the x-axis. y=6 -3x, y = 0, and x = 0 AY Y6-3x The volume of the solid is cubic units. (Type an exact answer.)
Answers
Therefore, the volume of the solid generated by revolving the shaded region about the x-axis is (20π/3) cubic units.
To find the volume of the solid generated by revolving the shaded region about the x-axis, we can use the method of cylindrical shells.
The region bounded by the curves y = 6 - 3x, y = 0, and x = 0 forms a triangular region in the first quadrant. Let's find the limits of integration for x.
The line y = 0 intersects with the curve y = 6 - 3x at x = 2. Therefore, the limits of integration for x will be from x = 0 to x = 2.
Now, let's consider a vertical strip at a specific x-value within this region. The height of this strip is given by the difference between the curves y = 6 - 3x and y = 0, which is (6 - 3x) - 0 = 6 - 3x.
The width of the strip is dx.
The circumference of the shell is the distance traveled by revolving the strip around the x-axis, which is given by 2πx.
The volume of the shell is then given by the product of the circumference and the height, which is (2πx) * (6 - 3x) * dx.
Integrating this expression from x = 0 to x = 2 will give us the total volume of the solid:
V = ∫[0 to 2] (2πx) * (6 - 3x) dx.
Simplifying and evaluating the integral, we get:
V = 2π ∫[0 to 2] \((6x - 3x^2) dx.\)
V = 2π \([3x^2/2 - x^3/3]\) evaluated from 0 to 2.
V = 2π \([(3(2)^2/2 - (2)^3/3) - (3(0)^2/2 - (0)^3/3)]\)
V = 2π [(3(4)/2 - (8)/3) - 0].
V = 2π [(6 - 8/3)].
V = 2π [(18/3 - 8/3)].
V = 2π (10/3).
V = (20π/3) cubic units
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instructor number of failures prof. a 13 prof. b 0 prof. c 11 prof. d 16 what are the .95 (5 percent risk of type i error) upper and lower control limits for the p-chart?
Answers
The Average proportional failure of the instructors is 0.10
From the question we are told that
Sample size 100
Instructor Number of Failures
Prof. A 13
Prof. B 0
Prof. C 11
Prof. D 16
Confidence level= 0.95
From Z table
Z=1.96
Generally proportion for failure is mathematically given as
proportion of failure = number of failure/ sample size
Prof A
Pa = 13/100
Pa = 0.13
Prof B
Pb = 0/100 = 0
Prof c
Pc = 11/100 = 0.11
Prof D
Pd = 16/100 = 0.16
Average proportional failure = (0.13 + 0.16 + 0.11 +0)/4 = 0.10
Therefore the Range is 0.0412 to 0.1588
Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options
Therefore, the Average proportional failure of the instructors is 0.10
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if f(x)=5x-1 and g(x) 2x^2 +1, what is 6he value of (f×g)(-3)
Answers
Answer: D
Step-by-step explanation:
\(f(3)=5(-3)-1=-16\\\\\\g(3)=2(-3)^{2}+1=19\\\\(f\times g)(3)=-16 \times 19=\boxed{-304}\)
4. Magdalene is replacing part of a concrete walkway.
3 ft
15 ft
7 ft
3 ft
4 ft
a. Analyze and Persevere Describe how Magdalene could decompose the walkway to find
the area.
b. How many square feet of walkway is Magdalene replacing?
Answers
a. To decompose the walkway and find the area, Magdalene could break the walkway down into smaller rectangles and then add up the areas of each rectangle to find the total area. In this case, she could break the walkway down into two rectangles with dimensions of 3 ft by 15 ft and 7 ft by 4 ft. She could then find the area of each rectangle using the formula A = l x w (where A is the area, l is the length, and w is the width) and add them together to get the total area.
b. To find the area of the walkway that Magdalene is replacing, we can use the same method as in part a. The dimensions of the walkway she is replacing are:
3 ft
15 ft
7 ft
3 ft
4 ft
Breaking this down into two rectangles, we get:
Rectangle 1: 3 ft x 15 ft = 45 sq ft
Rectangle 2: 7 ft x 4 ft = 28 sq ft
Adding the areas of these two rectangles together, we get:
45 sq ft + 28 sq ft = 73 sq ft
Therefore, Magdalene is replacing 73 square feet of walkway.
Find the relationship between zeros and x-intercepts of the polynomial x2 + 15x + 54.They are equal to zeroThey are oppositesThey are sameThey are different
Answers
Given:
x2 + 15x + 54.
Required:
Find the relationship between zeros and x-intercepts of the polynomia
Explanation:
Although the zeroes of
\(\begin{gathered} x^2+15x-9 \\ \\ are\text{ -6,-9} \\ \\ And\text{ the x-intercepts of it are -6 and -9 } \\ \\ \\ they\text{ mean different things.} \end{gathered}\)Required answer:
They are different
Create a real-world problem that represents 2/3 and 2/5.
Answers
Answer: Hi!
Sara had 2/3 of a piece of cake. Jasmine had 2/5 of a piece of cake. How much cake did Sarah and Jasmine have in total?
Hope this helps!
Answer:
If Kaylah had 2/5 of a pizza, and Allia had 2/3 of a pizza how much would they eat together?
he puppy weighed 2 pounds when it was born. He has gained weight, but still weighs less than 11 pounds. How much weight could he have gained? n = 9 pounds n > 9 pounds n < 9 pound
Answers
Answer:
n=9
Step-by-step explanation:
just did it
204, 200,196,... find the 31st term
Answers
Answer:
31st term = 84
Step-by-step explanation:
Given:
204, 200,196,...
Find:
31st term
Computation:
204, 200,196,...
First term a = 204
Difference d = a3 - a2
Difference d = 196 - 200
Difference d = -4
An = a + (n-1)d
A31 = 204 + (31-1)(-4)
A31 = 204 - 120
A31 = 84
Answer:
84
Step-by-step explanation:
what is the value of the expression 4(80+b) - 12, where b = 20?
Answers
Answer:
388
Step-by-step explanation:
Substituting b = 20 in the expression :
4(80 + 20) - 124(100) - 12400 - 12388If sin 0 = three-fifths, what is the measure of the angle? a. 53.1º b. 36.9º c. 30.1º d. 59º
Answers
Answer:
We can use inverse sine (or arcsine) function to find the measure of the angle, since:
sin(theta) = opposite/hypotenuse
In this case, sin(theta) = 3/5, which means that if we draw a right triangle with one angle equal to theta, and the opposite side of length 3, and the hypotenuse of length 5, then the sine of that angle will be 3/5.
Using inverse sine function, we get:
theta = arcsin(3/5) = 36.9º
Therefore, the measure of the angle is b. 36.9º
Please help I need an answer ASAP!!!!!!!
Answers
Answer:
A its the mos resonable one
The middle school band has a boy to girl ratio of 4:6.
The band had 20 members last year and 25 members this year.
How many girls and how many boys are in the band in each of these two years?
A. Last year: 8 boys and 12 girls. This year: 10 boys and 15 girls
B. Last year: 12 boys and 8 girls. This year: 13 boys and 12 girls
C. Last year: 8 boys and 12 girls. This year: 12 boys and 13 girls
D. Last year: 12 boys and 8 girls. This year: 15 boys and 10 girls.
Answers
Answer:
A
Step-by-step explanation:
20×4/10=8
25×4/10=10
The equation d = startfraction 13 over v endfraction shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the substance. what happens to the density as the volume approaches 0? the density approaches infinity. the density approaches 0. the density approaches 1. the density approaches 13.
Answers
Answer:
(a) the density approaches infinity
Step-by-step explanation:
As with any inverse relation, when one variable gets smaller, the other gets larger.
When the volume approaches zero, the density approaches infinity.
Answer:
its A
Step-by-step explanation:
the question is on the sheet.
Answers
area of the whole figure
\( = (x + 1)(2x + 3) \\ = x(2x + 3) + 1(2x + 3) \\ = 2 {x}^{2} + 3x + 2x + 3 \\ = {2x}^{2} + 5x + 3\)
area of the unshaded region
\( = x(2x) \\ = {2x}^{2} \)
area of the shaded region
\( = {2x}^{2} + 5x + 3 - {2x}^{2} \\ = ( {2x}^{2} - {2x}^{2} ) + 5x + 3 \\ = 5x + 3\)
THEREFORE,
THE AREA OF THE FRAME IS C. 5x + 3
Solve the initial value problem y′=3cosx+2 with y(3π/2)=8
Answers
The solution of the initial value problem y′=3cosx+2 with y(3π/2)=8 is y(x) = 3sin(x) + 2x - 1/2π.
To solve the initial value problem y′=3cosx+2 with y(3π/2)=8, we need to find a function y(x) that satisfies the differential equation and the initial condition.
First, we find the antiderivative of 3cos(x) + 2, which is 3sin(x) + 2x + C, where C is a constant of integration. Then, we apply the initial condition y(3π/2) = 8 to determine the value of C.
y(3π/2) = 3sin(3π/2) + 2(3π/2) + C = -3/2π + 3π + C = 8
Solving for C, we get C = -1/2π. Thus, the solution to the initial value problem is:
y(x) = 3sin(x) + 2x - 1/2π
To verify that this solution satisfies the differential equation, we can take its derivative:
y′(x) = 3cos(x) + 2
Substituting this expression into the differential equation y′=3cosx+2, we see that y(x) is indeed a solution.
In summary, we solved the initial value problem y′=3cosx+2 with y(3π/2)=8 by finding the antiderivative of the given function, applying the initial condition to determine the constant of integration, and verifying that the resulting function satisfies the differential equation.
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Find the area of the circle. Round your answer to the nearest whole number, if necessary.
A circular object with a radius of 10 inches.
area: about
in.2
Answers
Why is it that when comparing a squares area with a rectangles area, with the SAME PERIMETER, that the square has a greater area?
Answers
s = side length of square
4s = perimeter of square
L = length of rectangle
W = width of rectangle
P = 2L+2W = perimeter of rectangle
4s = 2L+2W .... since we want the perimeters the same
4s = 2(L+W)
s = 0.5(L+W)
s^2 = (0.5(L+W))^2 ... square both sides
s^2 = 0.25(L+W)^2
The last equation shows the area of the square, s^2, in terms of L and W. This way we can connect the square to the rectangle.
-----------------------------------
The area of the rectangle is LW
Let's subtract this from the area of the square and see what we get
A = area of square = s^2
B = area of rectangle = LW
C = difference in area
C = A - B
C = s^2 - LW
C = 0.25(L+W)^2 - LW
C = 0.25(L^2+2LW+W^2) - LW
C = 0.25L^2+0.5LW+0.25W^2-LW
C = 0.25L^2-0.5LW+0.25W^2
C = 0.25(L^2-2LW+W^2)
C = 0.25(L-W)^2
Regardless of what we pick for L and W, the expression (L-W)^2 is always positive. Squaring a negative number leads to a positive result.
So C is always positive as long as \(L \ne W\)
If C > 0, and C = A - B, then
C > 0
A-B > 0 .... replace C with A-B
A > B .... add B to both sides
This shows the square area is always larger than the rectangle.
Again this only works if L and W are different values. If L = W, then the argument falls apart because the rectangle becomes the square.
We make \(L \ne W\) to have a nonsquare rectangle.
study smart one triangle has vertices a,b, and c. another has vertices t, r, and i. are the 2 triangles similar?
Answers
"Study smart one triangle has vertices a,b, and c. another has vertices t, r, and i, are the 2 triangles similar?"
It is not possible to determine if the two triangles are similar based on the information provided.
In order for two triangles to be similar, they must have the same shape but not necessarily the same size. The sides of the two triangles must be in proportion and corresponding angles must be congruent.
Similarity between two triangles can be determined by using the criterion of AAA similarity or SAS similarity, which states that two triangles are similar if:
All three angles of one triangle are congruent to the corresponding angles of the other triangle (AAA similarity)Two angles of one triangle are congruent to the corresponding angles of the other triangle, and the sides opposite to those angles are in proportion (SAS similarity)without knowing the measures of the angles and sides of the triangles, it is impossible to determine if the two triangles are similar.
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plz help me put this from least to greatest
Answers
Answer:
0.09
1/9
9/10
91%
there is the answer hope it helps!!!
1) What percentage of 48 is 62?
Answers
Answer:
77.42
Step-by-step explanation:
48/62=77.42
What is the slope of the line in the graph?
