For the reactionA(g) ? 2B(g), a reaction vessel initially contains only A at a pressure of PA=1.19 atm . At equilibrium, PA =0.20 atm . Calculate the value of Kp. (Assume no changes in volume or temperature.)

Answer:

16.67 grams  of  H₂ is generated from the electrolysis of 150 grams of H₂O

Explanation:

Electrolysis is the decomposition of a chemical element under the effect of an electric current. So, electrolysis of water is the process of decomposing the H₂O molecule into separate oxygen and hydrogen gases due to an electric current passing through the water.

The balanced equation of electrolysis of water is:

2 H₂O → O₂ + 2H₂

Being:

then the molar mass of the compounds that participate in the reaction is:

If the following amounts in moles are reacted by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction):

the amount of mass, by stoichiometry, that reacts and is produced is:

Then you can apply the following rule of three: if by stoichiometry 36 g of H₂O generate 4 g of H₂, 150 g of H₂O how much mass of H₂ will it generate?

\(massofH_{2} =\frac{150 grams of H_{2}O*4 grams ofH_{2} }{36 grams of H_{2}O}\)

mass of H₂= 16.67 grams

16.67 grams  of  H₂ is generated from the electrolysis of 150 grams of H₂O

Answer: Extensive!

Explanation:

Chlorophyll molecules in chloroplasts normally only fluoresce a very small amount compared to chlorophyll that has been extracted into a solvent solution, true.

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Answer:

vanadium

Explanation:

Answer:

7.4 moles solute

Explanation:

From definition of Molarity (M) = moles solute (n)/volume of solution in Liters(V)

=> moles solute (n) = Molarity (M) x Volume (L) = (3.7 moles/L)(0.500L) = 7.4 moles solute

Answer:

The atoms of different elements vary in size and mass.

Explanation:

2.20 g (to 3 sig. figs.) the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

hexane is C6H14 or put another way, as in the question CH3(CH2)4CH3. Actually, it is incorrect as depicted in the question.Nonetheless..

2C6H14 + 19O2 ===> 12CO2 + 14H2O ... balanced equation

moled hexane present = 2.6 g x 1 mole/130 g = 0.02 moles

moles O2 present = 5.29 g x 1 mole/32 g = 0.165 moles

Which reactant is limiting? Hexane = 0.02/2 = 0.01; O2 = 0.165/19 = 0.0087

Thus O2 is limiting...

moles of H2O that can be produced =0.165 moles O2 x 14 H2O/19 CO2 = 0.122 moles H2O

Mass of water( H2O) = 0.122 moles x 18 gm/mole = 2.20 g (to 3 sig. figs.)

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Cations are positively charged ions that form when an atom loses one or more electrons from its outermost shell. The elements that are most likely to form cations are those with low ionization energies, meaning they require relatively little energy to remove an electron from their outermost shell. This typically includes metals and elements with small atomic radii.

In the list provided, the elements that are most likely to form cations are calcium, barium, magnesium, potassium, and rubidium. These elements are all metals that readily lose electrons to form positively charged ions. Calcium, barium, and magnesium are alkaline earth metals and have two valence electrons in their outermost shell, which they readily lose to form cations with a +2 charge. Potassium and rubidium are alkali metals and have one valence electron, which they readily lose to form cations with a +1 charge.

Iodine, bromine, selenium, sulfur, and fluorine are nonmetals and have relatively high ionization energies, making them less likely to form cations. However, they can form anions, which are negatively charged ions that form when an atom gains one or more electrons.

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Answer:

When you look only at the “before” and “after” of a change, you are considering it as static change. In this perspective, you look at change as a one-dimensional shift. A situation or object was one way, and now it is different because some outside force acted on it to make it change.

Explanation:

Its the def

The ratio of octene to oxygen is 1:12.

To determine the ratio of octene (C8H16) to oxygen (O2) in the given reaction, we need to examine the balanced chemical equation. However, the equation you provided does not seem to be balanced. The coefficients for each compound must be determined to achieve a balanced equation before we can calculate the desired ratio.

Assuming you meant the combustion reaction of octene, a balanced equation would be:

C8H16 + 12O2 → 8CO2 + 8H2O

From the balanced equation, we can see that for every 1 mole of octene (C8H16), we require 12 moles of oxygen (O2) to completely react.

This means that for every 1 mole of octene, we need 12 moles of oxygen to fully combust the octene and produce the corresponding amounts of carbon dioxide (CO2) and water (H2O) as shown in the balanced equation.

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Answer:

a) Chlorine Trifluoride

b) Dichlorine Heptoxide

GOOD LUCK FOR FUTURE! :)

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 15.8 cm³

density = 3 g/cm³

We have

mass = 3 × 15.8

We have the final answer as

Hope this helps you

Answer:

No of Moles in excess at the end of the reaction  is 0.25 moles

Explanation:

AgNO3  +   Mg3P2  → Ag3P + Mg(NO3)2

Balancing the equation we get

6AgNO3  +   Mg3P2  → 2Ag3P + 3Mg(NO3)2

6 moles of AgNO3 needs 1 mole of Mg3P2

using unitary method

AgNO3 = \(\frac{1}{6}*Mg3P2\)

1.5 AgNO3 = \(\frac{1}{6}*1.5\)

                  = 1/4 = 0.25moles of Mg3P2

So 1.5 Moles of AgNO3 requires 0.25Mg3P2 for complete reaction but we have 0.5Moles of Mg3P2 available Therefore Mg3P2 is in excess

No of Moles in excess at the end of the reaction = 0.5 - 0.25 = 0.25moles

The correct answer is option a

Increased availability of carbon dioxide has a direct impact on plant growth. Carbon dioxide is a critical component of photosynthesis, the process through which plants convert light energy into chemical energy. In normal conditions, carbon dioxide concentrations in the atmosphere can be a limiting factor for photosynthesis.

When more carbon dioxide is available, plants are able to take in higher amounts of this gas, leading to increased rates of photosynthesis. As a result, plants experience enhanced growth, including increased biomass, larger leaves, and improved reproductive capacity.

Carbon dioxide, along with water and sunlight, is essential for photosynthesis. Higher carbon dioxide levels can potentially stimulate photosynthesis and have been observed to improve plant productivity in certain environments.

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The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2. The fuel is determined to be methane (CH4).

The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as:

CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2.

Given the volumetric analysis of the products of combustion, we can determine the value of x in the hydrocarbon fuel. The percentage of carbon dioxide (CO2) corresponds to the carbon atoms in the fuel, so 9.45% CO2 implies x = 1. The fuel is therefore methane (CH4).

To calculate the air-fuel ratio, we compare the moles of air to the moles of fuel in the balanced equation. From the equation, we have (2x + 1) moles of oxygen (O2) and 3.76(2x + 1) moles of nitrogen (N2) for every 1 mole of fuel. Substituting x = 1, we find that the air-fuel ratio is 17.2 kg of air per kg of fuel.

To determine the heat transfer rate and combustion efficiency on a lower heating value (LHV) basis, we need to calculate the molar enthalpies of the reactants and products. Using standard molar enthalpies of formation, we can calculate the change in molar enthalpy for the combustion reaction. The heat transfer rate can be obtained by multiplying the change in molar enthalpy by the mass flow rate of the fuel. The combustion efficiency on an LHV basis can be calculated by dividing the actual heat transfer rate by the ideal heat transfer rate.

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Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one  M & M= 0.5 \ cm^3\\\\

M&M 1 mole\(= 6.02 \times 10^{23}\\\\\)

Calculating volume of M& M mole\(= 0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3\\\\\)

Calculating the cube mole\(L^3= 3.01 \times 10^{23}\ cm^3\\\\\)

\(L=6.70176 \times 10^{7}\ cm\\\\\)

   \(=6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km\)

Therefore 18 tractor trailers wouldn't be sufficient.

Answer:

change an object's motion. So basically it can cause an object to move, change direction, or stop moving.

Explanation:

Answer:

5cm is the answer because 5-5 is o and the one 5 is remaining so 5 is the answer.

Answer:

2.7*10^23

Explanation:

first work out the moles

So do 36g / 80 (80 is bromine's relative Atomic Mass number)

You have 0.45 M

Then, do 0.45 * 6.02*10^23

You get 2.7*10^23, which is your answer

An enthalpy shift of -231 kJ results in the production of 7.44 g of MgO.

To determine the amount of MgO produced during an enthalpy change of -231 kJ, we need to use stoichiometry and the enthalpy change per mole of MgO produced.

The balanced chemical equation for the formation of MgO from Mg and O2 is:

2Mg(s) + O₂(g) → 2MgO(s)

The enthalpy change for this reaction is -1204 kJ/mol of MgO produced.

To find the amount of MgO produced during an enthalpy change of -231 kJ, we can use the following equation:

(-231 kJ) x (1 mol MgO/ -1204 kJ) x (40.3 g MgO/1 mol MgO) = 7.44 g MgO

Therefore, 7.44 g of MgO are produced during an enthalpy change of -231 kJ.

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Hydrogen cyanide has a triple bond between the carbon and nitrogen, and a polar covalent bond between the hydrogen and carbon; Phosgene has three polar covalent bonds and two double bonds between carbon and oxygen atoms.

In hydrogen cyanide (HCN), there is a polar covalent bond between the hydrogen and nitrogen atoms, due to the difference in electronegativity. The nitrogen has a lone pair of electrons, which is involved in a coordinate covalent bond with the carbon atom.

This results in a triple bond between carbon and nitrogen, with a partial negative charge on the nitrogen and a partial positive charge on the carbon. Overall, the molecule is polar.

In Phosgene (COC12), the carbon atom is bonded to two oxygen atoms and a chlorine atom. The carbon-oxygen bonds are polar covalent, due to the difference in electronegativity.

The carbon-chlorine bond is also polar covalent for the same reason. However, the molecule is nonpolar due to the symmetry of the molecule.

The two dipole moments of the polar bonds are equal and opposite and hence cancel each other, resulting in a net zero dipole moment.

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Sorry this question is incomplete.

Answer:electrons

Explanation:

The method cbo.additem(s) adds an item s into a combobox cbo. Option C

The method that adds an item 's' into a ComboBox 'cbo' depends on the programming language or framework being used. However, based on common naming conventions and methods used in various programming languages, the most likely correct option is (c) cbo.addItem(s).

In many programming languages and frameworks, the method to add an item to a ComboBox is typically named 'addItem' or 'add' followed by the item's name or value. Let's analyze the given options to determine the most appropriate choice:

(a) cbo.addChoice(s):

This option uses the term 'addChoice,' which is not commonly used for adding items to ComboBoxes. It is less likely to be the correct method name.

(b) cbo.addObject(s):

Similar to option (a), 'addObject' is not a common method name for adding items to ComboBoxes. It is often used for adding objects to other data structures but not ComboBoxes specifically.

(c) cbo.addItem(s):

This option is the most commonly used method name for adding items to a ComboBox. It follows standard naming conventions and accurately describes the action of adding an item to the ComboBox.

(d) cbo.add(s):

This option is less specific and might be used in some cases, but 'addItem' is a more appropriate and descriptive method name for ComboBoxes.

(e) cbo.getItems():

This option retrieves the items from the ComboBox rather than adding an item. It is used to get the existing items in the ComboBox and not to add new ones.

In summary, based on standard naming conventions and commonly used methods in programming languages, the most appropriate method for adding an item 's' to a ComboBox 'cbo' is (c) cbo.addItem(s).

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Answer:

What is the most likely source of nitrogen in runoff? Fossil fuel emissions.

There are approximately 6.64 x 10^-22 moles of nitrogen in 4x10^2 particles.

Mole is an SI unit used to measure the amount of any substance.

To determine the number of moles of nitrogen in 4x10^2 particles, we need to use Avogadro's number, which is the number of particles in one mole of a substance. Avogadro's number is approximately 6.022 x 10^23 particles per mole.

We can use the following formula to calculate the number of moles:

moles = number of particles / Avogadro's number

moles of nitrogen = 4x10^2 particles / 6.022 x 10^23 particles per mole

moles of nitrogen = 6.64 x 10^-22 moles

Therefore, there are approximately 6.64 x 10^-22 moles of nitrogen in 4x10^2 particles.

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