Fuses and ____________________ are designed to protect the circuit from a direct ground or short-circuit condition.

Answer:

Beam of 25" depth and 12" width is sufficient.

I've attached a detailed section of the beam.

Explanation:

We are given;

Beam Span; L = 20 ft

Dead load; DL = 0.50 k/ft

Live load; LL = 0.65 k/ft.

Beam width; b = 12 inches

From ACI code, ultimate load is given as;

W_u = 1.2DL + 1.6LL

Thus;

W_u = 1.2(0.5) + 1.6(0.65)

W_u = 1.64 k/ft

Now, ultimate moment is given by the formula;

M_u = (W_u × L²)/8

M_u = (1.64 × 20²)/8

M_u = 82 k-ft

Since span is 20 ft, it's a bit larger than the average span beams, thus, let's try a depth of d = 25 inches.

Effective depth of a beam is given by the formula;

d_eff = d - clear cover - stirrup diameter - ½Main bar diameter

Now, let's adopt the following;

Clear cover = 1.5"

Stirrup diameter = 0.5"

Main bar diameter = 1"

Thus;

d_eff = 25" - 1.5" - 0.5" - ½(1")

d_eff = 22.5"

Now, let's find steel ratio(ρ) ;

ρ = Total A_s/(b × d_eff)

Now, A_s = ½ × area of main diameter bar

Thus, A_s = ½ × π × 1² = 0.785 in²

Let's use Nominal number of 3 bars as our main diameter bars.

Thus, total A_s = 3 × 0.785

Total A_s = 2.355 in²

Hence;

ρ = 2.355/(22.5 × 12)

ρ = 0.008722

Design moment Capacity is given;

M_n = Φ * ρ * Fy * b * d²[1 – (0.59ρfy/fc’)]/12

Φ is 0.9

f’c = 4,000 psi = 4 kpsi

fy = 60,000 psi = 60 kpsi

M_n = 0.9 × 0.008722 × 60 × 12 × 22.5²[1 - (0.59 × 0.008722 × 60/4)]/12

M_n = 220.03 k-ft

Thus: M_n > M_u

Thus, the beam of 25" depth and 12" width is sufficient.

The materials which are possible candidates are brass, stainless steel, aluminum and copper is to be subjected to a tensile load.

Tensile load, also known as tension, is a force applied to an object in order to extend, deform, or disrupt the object. Tensile load is the opposite of compressive load, which compresses or squeezes an object. Tensile load is often used in engineering and material science to measure the strength of a material or object. When a material is subjected to a tensile load, it will stretch and deform until it reaches its breaking point. The amount of force it takes to cause the material to reach its breaking point is known as the tensile strength of the material.

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

The given number a[15:0] = 0110110010001111 represents a 16-bit binary value.

Here, a[14:13] refers to the 14th and 13th bits from the left side of the binary value, which are '10'. Similarly, a[3:2] refers to the 3rd and 2nd bits from the left side of the binary value, which are '10' as well. Therefore, we can conclude that a[14:13] is equal to a[3:2].

In a binary numbering system, the position of each bit represents a power of 2. For instance, the leftmost bit has a value of 2^15, followed by 2^14, 2^13 and so on. So, a[14:13] represents the decimal value of (1 x 2^14) + (0 x 2^13) = 16384 in binary. Similarly, a[3:2] represents the decimal value of (1 x 2^3) + (0 x 2^2) = 8 in binary. As both values are equal to '10' in binary, we can conclude that a[14:13] is equal to a[3:2].

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Answer:

1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.

2) The weakest point on cross section A is located at the point where the bending moment is maximum.

3) The von-Mises stress at the weakest point is given by:

σ = M/I

where M is the bending moment and I is the moment of inertia of the cross section.

4) The factor of safety n is given by:

n = Sy/σ

where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.

Explanation:

Hope this helps!

Using the knowledge in computational language in python it is possible to write a code that output the number of characters excluding the three characters commonly used for end-of-sentence punctuation.

   import re

   def check_sentence(text):

     result = re.search(r"^[A-Z][A-Za-z\s]*[\.\?!]$", text)

     return result != None

   print(check_sentence("Is this is a sentence?")) # True

   print(check_sentence("is this is a sentence?")) # False

   print(check_sentence("Hello")) # False

   print(check_sentence("1-2-3-GO!")) # False

   print(check_sentence("A star is born.")) # True

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A state's department of transportation is considering whether to buy or lease an rfid tracking system.

Net Present Worth (NPW) for Buy - Lease

= -$1500 + $3500 × (P/A, i, 4) + $1500 × (P/F, i ,5)

= 0

In Canada[citation needed] or the United States, a government agency devoted to transportation is most frequently referred to as the department of transportation (DOT).

The biggest is a federal agency called the United States Department of Transportation, which regulates interstate travel. All of the states in the United States, the provinces of Canada, and numerous local agencies also have similar organizations and employ DOT officers to enforce the law in their respective regions.

According to the DOT's mission statement, their objective is to create an "efficient and modern transportation system" in order to "improve the quality of life for all Americans."

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A typical oil control ring is a critical component in a piston engine and is responsible for regulating the amount of oil that enters the combustion chamber. It is designed as a separate part and consists of three distinct sections - the top rail, the second rail, and the expander.

The top rail of the oil control ring is designed to scrape oil off the cylinder walls and direct it back into the oil sump. The second rail sits below the top rail and helps to seal the oil control ring against the cylinder walls. The expander, which is located below the second rail, ensures that the oil control ring stays in place and maintains the proper tension against the cylinder walls.

Together, these three sections of the oil control ring work in unison to regulate the flow of oil into the combustion chamber, ensuring that the engine operates at optimal efficiency while minimizing the risk of oil leakage and excessive oil consumption. The design of the oil control ring can vary based on the specific engine application and the manufacturer's design preferences, but its function remains consistent across all applications.

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Answer: Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick.

Explanation:

The main function of a materials engineer is to develop, study and test materials that are used on order to make different products.

Material engineer solve problems in other engineering fields, like electrical, aerospace, civil, mechanical, chemical, and nuclear.

From the information given in the question, the correct option is "Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick."

Answer:

nice

Explanation:

The most accurate statement is (b), as it reflects the cranial-to-caudal sequence of development in the embryo, which influences the ossification timing of upper and lower limbs.

To determine the best statement that describes the reason for the difference in ossification stages between upper and lower limbs, let's briefly review the process of limb development in an embryo. Limb ossification occurs as the embryo develops, with different parts of the body ossifying at different times. The statements provided are as follows:

a) The caudal limbs must end up longer and therefore ossification begins later.
b) The embryo develops more rapidly cranially.
c) The cranial limb is much more important for later fetal development.
d) The blood flow to the lower limb arises closer to the heart and therefore gets more oxygen and nutrients.

Out of these options, statement (b) "The embryo develops more rapidly cranially" best describes the reason for upper limb ossification being listed at the stage shown and lower limb ossification at the later stage. This is because, during embryonic development, there is a general pattern of development from the head (cranial) region to the tail (caudal) region. This principle, known as the cranial-to-caudal sequence, explains why ossification of the upper limbs occurs earlier than that of the lower limbs.

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Approximately 1 solar heating panel is required to heat the water from 20ºC to 40ºC.

To estimate the number of 4'x8' solar heating panels required to heat water at a home from 20ºC to 40ºC, we need to consider the energy requirements, efficiency, solar irradiation, and the heat capacity of water.

- Daily water usage: 125 gallons

- Efficiency (η): 0.7

- Direct Normal Irradiation (DNI): 7 kW-hr/m2

- Heat capacity of water: 4200 J/(kg ºC)

First, we need to convert the daily water usage from gallons to kilograms. Since 1 gallon is approximately 3.78541 kilograms, the daily water usage is approximately 471.9275 kg.

Next, we calculate the energy required to heat the water from 20ºC to 40ºC using the formula:

Energy = Mass of water * Specific heat capacity * Temperature change

Temperature change = (40ºC - 20ºC) = 20ºC

Energy = 471.9275 kg * 4200 J/(kg ºC) * 20ºC = 19,773,090 J

Now, we need to calculate the energy received from the solar panels. The total energy received can be obtained by multiplying the DNI by the area of the solar panels and the efficiency.

Area of a 4'x8' panel = 4 ft * 8 ft = 32 ft2

Converting to square meters: 32 ft2 * 0.092903 m2/ft2 = 2.97256 m2

Total energy received = DNI * Area of panels * Efficiency

Total energy received = 7 kW-hr/m2 * 2.97256 m2 * 0.7 * 3600 kJ/kWh * 1000 J/kJ = 65,647,040 J

Finally, we can calculate the number of panels required by dividing the energy required by the energy received per panel:

Number of panels = Energy required / Total energy received

Number of panels = 19,773,090 J / 65,647,040 J = 0.301

Please note that this calculation is an estimation based on the given data and assumptions. Other factors such as system losses, temperature variations, and specific panel efficiency may affect the actual number of panels required in a real-world scenario.

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The value of x in the equation 2.728x - 7.011 = -1.329x + 2.828 is 2.425.

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

The equation is given as:

2.728x - 7.011 = -1.329x + 2.828

Collect the like terms

2.728x + 1.329x = 2.828 + 7.011

4.057x = 9.839

Divide

x = 9.839 / 4.057

x = 2.425

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If the siding is fastened to the studs through the sheathing, the International Residential Code prescribes 3/8-inch plywood for sheathing walls with a typical stud spacing of 16 inches.

The minimum plywood thickness required by the IRC is 1/2 inch if the nails only go through the sheathing and not through the studs.

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Answer:

Maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration. Therefore it is not possible.

Explanation:

let's first determine the mass fraction of the phases as follows

\(W_{a}=\frac{m_{a} }{m_{a}+m_{p_{g2}p_{b} } }\)

Given that masses are \(m_{a}=7.39kg\) and \(m_{p_{g2}p_{b} }=3.81kg\)

Thus, \(W_{a} =\frac{7.39}{7.39+3.81}=0.659\)

\(W_{M_{g2Pb} } =1-W_{a}=1-0.659=0.341\)

Now determine the concentration

\(W_{a}=\frac{C_{0}-C_{a} }{C_{b}-C_{a} }\)

At 81% PB and 70% Pb only point at which \(M_{g2Pb}\) exists, we can solve

\(0.659=\frac{70-81}{C_{b}-81 }\)

\(C_{b}=\)64.3%

Refer text book page no. 326, figure 9.20, from figure we can say maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration.

Answer:

The answer could be correct

Explanation:

According to your explanation this would really help out the Analyze the example of this band saw wheel and axle. The diameter of the wheel is 14 inches. The diameter of the axle that drives the wheel is 3/4 inch. The actual force needed to cut through a one-inch-thick softwood board is 1.75 pounds. Consider the efficiency of this band saw to be 22%.

Questions: Calculate ideal mechanical advantage when the effort force is applied to the axle.

Questions: considering the efficiency calculate the actual mechanical advantage of the wheel and axle.

Questions: If you used the same wheel and axle in a different way and applied effort force to the wheel to drive the axle, what is the ideal mechanical advantage of the wheel and axle?

Answer:

answer is C. his seat belt

Control charts for variables are based on data that come from continuous measurement processes.

These processes generate numerical measurements of a characteristic of interest, called a variable. The variable can be any measurable attribute such as weight, length, height, volume, temperature, pressure, and so on. The data obtained from measuring the variable is plotted on a control chart to monitor the stability and performance of the process over time.
Variables control charts consist of two types: X-bar and R charts. The X-bar chart displays the average value of the variable, and the R chart displays the range or variation of the variable. Both charts are used together to detect any shifts or changes in the process mean or variability.
The data used to construct the control charts should be representative of the process being monitored and should be collected in a systematic and consistent manner. The data should be accurate, precise, and unbiased. Typically, a minimum of 20 to 25 consecutive samples of the variable is collected before constructing the control charts.
In summary, control charts for variables are based on data that come from continuous measurement processes of a measurable attribute. The data is used to construct X-bar and R charts to monitor the stability and performance of the process over time. The quality of the data is essential to ensure the reliability and usefulness of the control charts.

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Assuming that cell B5 contains the sales amount for the first salesperson, the IFS function to determine the commission rate in cell C5 is:

=IFS(B5>35000, 0.05, B5>25000, 0.04, B5>0, 0.02)

This formula checks the sales amount in B5 against each threshold amount in descending order (starting with $35,000), and returns the corresponding bonus rate if the sales amount is greater than that threshold. If the sales amount is less than or equal to zero, it returns a bonus rate of 0%.

To fill the formula down through cell C8, select cell C5 and drag the fill handle down to cell C8. This will copy the formula to the other cells in the group, adjusting the cell references as needed.

GivenDataRadius of the spoked wheel, r = 705 mmCord speed at point P, v = 2.0 m/sVelocity of point E = VeWe know that linear velocity (v) = angular velocity (ω) × radius (r)We can find the angular velocity using the formula:ω = v / rω = 2 / 0.705= 2.84 rad/s

We know that the velocity of point A is perpendicular to the incline and the velocity of point E is parallel to the incline.As no slipping occurs, the velocity of point B is zero.The velocity of point E is given byVe = ω × r = 2.84 × 0.705 = 2.00 m/sLet VA be the velocity of point A. Then we can write:VA / Ve = AB / AEBut AB = 2r and AE = r + hSo we haveVA / 2 = AB / (r + h)VA / 2 = 2r / (r + h)VA = 4r / (r + h)Substitute the values to obtainVA = 4 × 705 / (705 + 300) = 2.22 m/sTherefore, the velocities of points A and B are VA = 2.22 m/s and VB = 0 m/s respectively.Note that the solution has a word count of 159 words.

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According to the information, the velocity of point A is v = 1.0 m/s and the velocity of point B is v = 2.0 m/s.

Fist we have to consider that since no slipping occurs, the linear velocity of any point on the wheel must be equal to the tangential velocity of the cord. At point P, the cord speed is given as v = 2.0 m/s.

Now, to determine the velocities of points A and B, we need to consider the relationship between linear velocity, angular velocity, and radius. The linear velocity of a point on the wheel is equal to the product of the angular velocity and the radius of the wheel.

Additionally, the radius of the wheel is given as r = 705 mm, which is equivalent to 0.705 m, we can calculate the angular velocity (ω) of the wheel by dividing the linear velocity of point P (v) by the radius (r).

Now, we can calculate the velocities of points A and B using the angular velocity and their respective radii.

Velocity of point A:

Velocity of point B:

Since the radius of point A (r_A) is 0.705 m, the velocity of point A is:

Since the radius of point B (r_B) is twice the radius of point A, i.e., 2 * 0.705 m = 1.41 m, the velocity of point B is:

According to the above, the velocity of point A is v_A = 2.0 m/s and the velocity of point B is v_B = 4.0 m/s.

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Answer:

For a Singular matrix, the determinant must be equivalent to 0.

Explanation:

A matrix is a rectangular array in which elements are arranged in rows and columns.

Each square matrix has a determinant. The determinant is a numerical idea that has a fundamental function in finding the arrangement just as investigation of direct conditions. For a Singular matrix, the determinant must be equivalent to 0.

Explanation:

R = √(A²+B²–2ABCos(x°))

x⁰ = 180–135

x° = 45°

R = √(350²+180²–2(350(180))Cos(45)))

R = 256.524

Answer:

The scale factor is used to make models of real-life objects. For example, a toy car is modeled to look just like a real car but at a smaller size. The ratio of the toy car to the real car might be 1:24 1: 24 . Which means that for every one unit of length on the toy car, the real thing is 24 times that size.

Explanation:

To calculate the amount of horsepower required for a car to accelerate from 0 to 25 m/s in 6.0 seconds, we need to use the formula:Horsepower = (Force x Distance) ÷ TimeWe can find the force by using Newton's second law of motion, which states that force = mass x acceleration. The acceleration, in this case, is the change in velocity over time, which can be calculated as:acceleration = (final velocity - initial velocity) ÷ time = (25 m/s - 0 m/s) ÷ 6.0 s = 4.17 m/s²Using the acceleration, we can find the force required to accelerate the car:force = mass x accelerationSince the mass of the car is not given, we can't find the force directly.

.To find the weight of the car, we can use the formula:w = mgwhere w is the weight, m is the mass, and g is the acceleration due to gravity. Since weight is a force, we can use the same approximation we used for the force of friction:w ≈ mg = force of frictionTherefore, we can find the weight of the car:w = force of friction = mgμkNow we have everything we need to find the horsepower:Horsepower = (Force x Distance) ÷ Time= (mgμk x 25 m) ÷ 6.0 s= (w/μk x 25 m) ÷ 6.0 s= (mg x 25 m) ÷ (μk x 6.0 s)= (w x 25 m) ÷ (μk x 6.0 s)Substituting the weight of the car (w) and the coefficient of kinetic friction (μk), we get:Horsepower = (m x g x 25 m) ÷ (μk x 6.0 s)= (m x 9.8 m/s² x 25 m) ÷ (0.6 x 6.0 s)= 408.33 m/s³ x m / 0.36 s= 1134.8 m²/kg/s³ x m= 1134.8 W= 1.52 horsepowerTherefore, approximately 1.52 horsepower is required for the same car to accelerate from 0 to 25 m/s in 6.0 seconds.

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The trucking company owns two types of trucks: Type A and Type B. In summary, Type A trucks have both refrigerated and non-refrigerated space, while Type B trucks only have refrigerated space.  

Type A trucks have 40 cubic meters of refrigerated space and 10 cubic meters of non-refrigerated space. This means that these trucks can transport perishable goods that require temperature control in the refrigerated space, while also having additional space for non-perishable items that do not require refrigeration.

Type B trucks have 10 cubic meters of refrigerated space. These trucks are designed specifically for transporting perishable goods that require temperature control. For instance, they can be used to transport frozen foods, dairy products, or any other goods that need to be kept at a specific temperature to prevent spoilage.

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Answer:

105°touch sensce what I could wathskb

A disk interface that is designed and developed to use parallel data transfer but with high reliability and an advanced command set is: C. PATA.

A hard-disk drive can be defined as an electro-mechanical, non-volatile data storage device that is made up of magnetic disks (platters) that rotates at high speed.

Disk Management can be defined as a type of utility that is designed and developed to avail end users an ability to convert two or more basic disks on a computer system to dynamic disks.

In Computer technology, PATA is a disk interface that is designed and developed to use parallel data transfer but with high reliability and an advanced command set.

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When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations: Codes of Ethics,  Ethical Training and Education,  Ethical Committees, etc.

Personal ethics refers to an individual's own moral principles and values that guide their behavior and decision-making in their personal life. It involves considering what is right or wrong based on one's own beliefs, values, and experiences. Personal ethics are subjective and can vary from person to person.

Professional ethics, on the other hand, refers to the ethical standards and principles that govern the behavior of professionals within their specific field or industry. For engineers, professional ethics encompass the moral obligations and responsibilities they have towards their clients, employers, colleagues, society, and the environment. Professional ethics provide a framework for engineers to ensure that their actions and decisions align with the values and expectations of their profession.

When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations:

1. Codes of Ethics: Many professional engineering organizations have established codes of ethics that provide guidelines and standards for ethical conduct in the engineering profession. These codes outline the responsibilities and ethical principles that engineers should uphold.

2. Ethical Guidelines and Policies: Companies and organizations often have their own ethical guidelines and policies in place. These documents help engineers understand the ethical expectations within their specific workplace or industry.

3. Ethical Training and Education: Continuous education and training in ethics can equip engineers with the knowledge and skills to identify and address ethical issues. Professional development programs and workshops may focus on ethical decision-making and provide case studies or scenarios to enhance ethical reasoning.

4. Professional Networks and Support: Engaging with professional networks, such as engineering associations and societies, can provide engineers with opportunities to discuss ethical challenges with peers and seek advice or guidance from experienced professionals.

5. Ethical Committees and Advisors: Some organizations have dedicated ethics committees or advisors who can provide guidance and assistance when engineers encounter ethical problems. These committees may offer confidential consultations and help engineers navigate complex ethical issues.

6. Legal and Regulatory Resources: Laws and regulations play a crucial role in defining ethical boundaries and providing legal frameworks. Engineers can consult legal resources, regulations, and guidelines to ensure compliance with legal and ethical requirements.

7. Ethical Decision-Making Frameworks: Engineers can utilize ethical decision-making frameworks, such as the Ethical Decision-Making Model or the SAD Formula (Scrutinize, Analyze, and Decide), to systematically evaluate ethical dilemmas and arrive at well-considered decisions.

By utilizing these resources, engineers can enhance their understanding of ethics, address ethical challenges effectively, and uphold the highest standards of professional conduct.

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In Stokes flow, the fluid velocity is proportional to the forces acting on the fluid and the fluid is assumed to be viscous and incompressible. The fluid velocity near a rotating sphere in Stokes flow can be determined using the equations of fluid dynamics.

Kinematic reversibility is a property of Stokes flow, which states that the fluid flow is symmetric with respect to time reversal. This means that if the fluid velocity is recorded at a certain time, then the same velocity field will be obtained if time is reversed and the flow is replayed in the reverse direction.

When a sphere is rotating near a wall, the flow of fluid around the sphere creates a velocity field that pushes the sphere away from the wall. This flow can be considered as the fluid being pushed away from the sphere and towards the wall. If the flow is time-reversed, the fluid velocity field would be the same, but the direction of the velocity would be reversed. This means that the fluid would be drawn towards the sphere and away from the wall, pulling the sphere towards the wall.

Therefore, based on the property of kinematic reversibility in Stokes flow, the rotating sphere near a wall will experience a force that could either push it away from the wall or draw it towards the wall, depending on the direction of the flow.

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Answer:

provides the Organization with accurate data analytics ,

provides/ensures strict compliance in the organization,

helps in lowering the cost of managing data in the organization and

provides the data scientists access to the exact data they require to work with

Explanation:

The adoption of a data platform by an organization for the purpose of  handling Data, helps to simplify data governance by :

i)provides the Organization with accurate data analytics ,

ii) provides/ensures strict compliance in the organization,

iii) It helps in lowering the cost of managing data in the organization and

iv) provides the data scientists access to the exact data they require to work with

Answer:

\(250\ \text{lbm/min}\)

\(625\ \text{ft/min}\)

Explanation:

\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)

\(V_1\) = Velocity of water at section 1 = 100 ft/min

\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)

\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)

\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)

Mass flow rate is given by

\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)

The mass flow rate through the pipe is \(250\ \text{lbm/min}\)

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)

The speed at section 2 is \(625\ \text{ft/min}\).

(a) The mass flow rate will be "250 lbm/min".

(b) At section 2, the speed will be "625 ft/min".

According to the question,

Section 1 area, A₁ = 10 ft²

Section 2 area, A₂ = 2 ft²

Water's velocity, V₁ = 100 ft/min

Volume at section 1, v₁ = 4 ft³/lbm

(a) We know the formula,

Mass flow rate, m = ρA₁V₁

                              = \(\frac{A_1 V_1}{v_1}\)

By substituting the values,

                              = \(\frac{10\times 100}{4}\)

                              = \(\frac{1000}{4}\)

                              = 250 lbm/min

(2) The speed will be:

→ m = ρA₂V₂

or,

  V₂ = \(\frac{m}{\rho A_2}\)

By substituting the values,

       = \(\frac{250}{0.2\times 2}\)

       = \(\frac{200}{0.4}\)

       = 625 ft/min

Thus the responses above are correct.  

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