Galaxies all formed at the same time, long ago. If you observe two galaxies at different distances from you, the more distant one will... Group of answer choices actually be younger. appear the same age. appear younger. appear older. actually be older.

Answer: the first one is speed

the second one is acceleration

the last is velocity

Explanation:

i got you

Answer:

c

did it on usa test prep

Answer:

current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.

Explanation:

Answer:

current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.

trust me i just did it

Explanation:

The radii listed here are based on the atomic and particle radii reported in the periodic table and may not be exact values for every situation.

Here are the objects listed from smallest to largest based on their radii:

1) Electron

2) Proton

3) Neutron

4) Hydrogen atom

5) Helium atom

6) Oxygen atom

7) Carbon atom

Keep in mind that the sizes of atoms and particles can vary depending on their state (e.g. gas, liquid, solid) and their surroundings. Additionally, the radii listed here are based on the atomic and particle radii reported in the periodic table and may not be exact values for every situation.

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Answer:

Look at pic

Explanation:

Answer:

Non-renewable resources work very well and produce a lot of energy, however it is bad for the environment and since it's nonrenewable it must be used scarcely.  

Renewable energy has an endless supply and is better for the environment than nonrenewable energy, but it is harder to get enough energy out of these resources compared to non-renewable resources.

Explanation:

Above

19600N\(m^{2}\) is the total pressure near the bottom of the pool as per the given data in the statement.

Pressure:  The perpendicular force applied to surface of any object tending to be distributed per unit area is known as pressure.

According to the given data :

length of the pool = 22m

breadth of the pool =8.5 cm=0.085 m

depth =2 m

To find the pressure near the bottom of the pool we use the following formula

P=hpg, where h=height or depth, p= density of liquid and g= 9.8m/s

P=2*1000*9.8

P=19600N\(m^{2}\)

Hence, 19600N\(m^{2}\) is the total pressure near the bottom of the pool as per the given data in the statement.

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19600N\(m^{2}\) is the total pressure near the bottom of the pool as per the given data in the statement.

Pressure:  The perpendicular force applied to surface of any object tending to be distributed per unit area is known as pressure.

According to the given data :

length of the pool = 22m

breadth of the pool =8.5 cm=0.085 m

depth =2 m

To find the pressure near the bottom of the pool we use the following formula

P=hpg, where h=height or depth, p= density of liquid and g= 9.8m/s

P=2*1000*9.8

P=19600N\(m^{2}\)

Hence, 19600N\(m^{2}\) is the total pressure near the bottom of the pool as per the given data in the statement.

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A blue light with a wavelength of 460 nm falling on a pair of slits separated by 0.075 mm would create interference fringes with an angular position of approximately 0.00613 radians and adjacent bright fringes spaced at approximately 2.4 cm on a screen placed 2 meters away.

To analyze the interference pattern created by a pair of slits, we can use the principles of Young's double-slit experiment. In this case, we have a pair of slits separated by a distance of 0.075 mm (or 7.5 x 10^-5 meters), and a blue light with a wavelength of 460 nm (or 4.6 x 10^-7 meters).

To determine the characteristics of the interference pattern, we can calculate the angular positions of the bright fringes (maxima) using the formula:

θ = λ / d

where:

θ is the angular position of the fringe,

λ is the wavelength of light, and

d is the slit separation.

Let's calculate the angular position of the bright fringes:

θ = (4.6 x 10^-7 m) / (7.5 x 10^-5 m)

  ≈ 0.00613 radians

Now we can calculate the distance between adjacent bright fringes on a screen placed at a distance 'D' from the slits using the formula:

y = D * tan(θ)

where:

y is the distance between adjacent fringes on the screen, and

D is the distance between the screen and the slits.

The distance 'D' will affect the spacing between the fringes. Assuming a reasonable value for 'D,' such as a few meters, we can estimate the fringe spacing. Let's assume D = 2 meters:

y = (2 m) * tan(0.00613 radians)

  ≈ 0.024 m or 2.4 cm

So, for a screen placed 2 meters away from the slits, the distance between adjacent bright fringes would be approximately 2.4 cm.

Note that this calculation assumes ideal conditions and does not account for other factors such as diffraction or the finite size of the slits. However, it provides a rough estimate of the fringe spacing based on the given parameters.

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A variable that the researcher controls is an independent variable.

In experimental research, the independent variable is manipulated or changed by the researcher to observe its effect on the dependent variable. The independent variable is the presumed cause or influence on the dependent variable. It is called "independent" because its value or level is not dependent on any other variable in the study.

For example, in a study investigating the effect of different teaching methods on student achievement, the teaching method would be the independent variable. The researcher can control and manipulate the teaching method by assigning participants to different groups that receive different instructional approaches. The dependent variable, in this case, would be the student achievement, which is measured to determine the impact of the different teaching methods.
By controlling the independent variable, researchers can establish a cause-and-effect relationship between the independent and dependent variables. This allows them to draw conclusions about the effects of the independent variable on the dependent variable. The manipulation of the independent variable provides researchers with control over the research design, allowing them to test specific hypotheses and draw meaningful conclusions from their studies.

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There are two correct options, matter, and energy.

First, we define mass as the quantity of matter in a body, so, if something has mass, it must have matter.

And that matter must be in some place, so it takes space.

By definition, "matter is any substance that has mass and a volume" (and if it has a volume, it takes space).

So the correct option is matter.

But there is another correct option, energy.

By Einstein's energy formula, we know that:

E = mc^2

Where m is mass and c is the speed of light. So, anything that has a mass also has energy, then there are two correct options.

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The central pitch around which a scale and its associated harmonies is built is called Tonic.

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The temperature in Celsius at which it is exactly twice the temperature in Fahrenheit is 160 °C.

The temperature can be converted from (°F) Fahrenheit to (°C) Celsius by using the formula:

°F = (9÷5) × °C + 32

To know the point where the temperature in Fahrenheit is exactly twice that in Celsius, then we can set up the equation:

2 ×°C = (9÷5) ×°C + 32

By simplifying the equation:

2 × °C - (9÷5) × °C = 32

On multiplying by 5 to cancel the fraction:

10 × °C - 9 × °C = 160

°C = 160

Hence, the temperature in Celsius at which it is exactly twice the temperature in Fahrenheit is 160 °C.

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Answer:

Musical instruments are grouped by how they produce the pitch.

Pitch is the highness or lowness of a tone.

Explanation:

:)

During dilemma, a person may experience conflicting thoughts and emotions, uncertainty, anxiety, and stress. Two alternative solutions you implemented to solve the dilemma are the Pros and cons list and Seeking advice.

They may struggle to make a decision, as each option has its pros and cons. To solve a dilemma, one can consider alternative solutions, weigh their potential outcomes, and decide which one aligns better with their values, beliefs, and goals. Here are two examples of alternative solutions:

Pros and cons list: One way to solve a dilemma is by making a list of pros and cons for each option. This can help to clarify the potential benefits and drawbacks of each choice, which can help in making a more informed decision.

Seeking advice: Another way to solve a dilemma is to seek advice from a trusted friend, family member, or professional. Talking through the situation with someone else can help to gain a different perspective and see the situation from a new angle.

Ultimately, the solution to a dilemma will depend on the specific situation and the individual's unique circumstances. It's important to take the time to consider all options and their potential outcomes before making a decision.

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Answer:

false its an attraction property

Answer:

True

The attraction is a chemical property.

Answer:

Vf = 25.7 [m/s]

Explanation:

To solve this problem we must use the following kinematics equation:

\(v_{f} ^{2}= v_{i} ^{2}-(2*a*x)\)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 30 [m/s]

a = desacceleration = 2 [m/s^2]

x = distance = 60 [m]

Note: the negative sign in the equation means that the car slows down.

Now replacing:

\(v_{f}^{2}=(30)^{2}-(2*2*60)\\ v_{f}^{2} = 660\\v_{f} =\sqrt{660} \\v_{f}=25.7[m/s]\)

Show us the experiment then

The plane flies at speed of 160m/s should drop the package when it reaches at a distance of 824m.

A dropped object travels quickly in the direction of the earth's center. Newton's second law states that the net force applied on an object determines its acceleration. If air resistance is small, the gravitational force, which is also known as an object's weight (w), acts as the net force on any falling object.

Free-fall acceleration seems to be another name for gravitational acceleration. Gravitational fields established by masses pull other masses approach them.

\(h = ut + 1/2 gt^2 ; u=0130 = 1/2 \times 9.8 \times t^2t= 5.15sec\)

The packet travel with the time period of 5.15sec

The distance = v x t

                      160m/s x 5.15s = 824m

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Answer:

the electric force and the magnetic force.

The quantity that describes how tightly packed matter is inside an object is density.

Density is the measure of how much mass is contained within a given volume of an object. It is a fundamental property of matter and is determined by dividing the mass of the object by its volume. In other words, density represents the concentration of matter within a given space.

When matter is tightly packed inside an object, it means that the mass is distributed over a smaller volume, resulting in a higher density. Conversely, if the matter is loosely packed, the mass is spread out over a larger volume, leading to a lower density. For example, a lead ball and a cotton ball of the same size would have significantly different densities because lead is a denser material compared to cotton.

Density is an essential concept in various scientific disciplines, including physics, chemistry, and materials science. It has practical applications in many fields, such as engineering, construction, and even everyday life. Understanding density helps in determining the buoyancy of objects in fluids, predicting the behavior of materials under different conditions, and designing efficient structures. Therefore, density serves as a key parameter for describing how tightly packed matter is within an object.

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Answer:

9800000N/m²

Explanation:

Given parameters:

Depth of the submarine  = 1000m

Weight of the water above  = 9,800,000N per unit area

Unknown:

Pressure  = ?

Solution:

The pressure at this depth is the force or weight per unit area.

    Pressure  = \(\frac{Force }{Area}\)  

    Pressure  = \(\frac{9800000}{1}\)  

    Pressure  = 9800000N/m²

The value of the angular acceleration of the disk when it is released is 14.6 rad/s^2

To solve this problem, we can use the conservation of energy principle. The potential energy stored in the compressed spring is converted into the kinetic energy of the disk as it rolls without slipping.

The potential energy stored in the spring is given by:

U = (1/2) k d^2

where k is the spring constant and d is the distance the spring is compressed.

The kinetic energy of the disk is given by:

K = (1/2) I w^2

where I is the moment of inertia of the disk and w is its angular velocity.

Since the disk rolls without slipping, the linear velocity of the disk is related to its angular velocity by:

v = R w

where R is the radius of the disk.

The total energy of the system is conserved, so we can write:

U = K

Substituting the expressions for U and K, we get:

(1/2) k d^2 = (1/2) I w^2

Solving for w, we get:

w = sqrt((k d^2) / I)

To find the moment of inertia I, we can use the formula for the moment of inertia of a solid disk:

I = (1/2) m R^2

Substituting the given values, we get:

I = (1/2) (40 kg) (0.3 m)^2 = 1.8 kg m^2

Substituting this value and the given values for m, k, and d into the expression for w, we get:

w = sqrt((50 N/m) (0.4 m)^2 / 1.8 kg m^2) = 2.17 rad/s

Finally, we can find the angular acceleration alpha using the formula:

alpha = w^2 / R

Substituting the value of w and R, we get:

alpha = (2.17 rad/s)^2 / 0.3 m = 14.6 rad/s^2

Therefore, the value of the angular acceleration of the disk when it is released is 14.6 rad/s^2.

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Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.

The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:

Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.

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1. According to Hubble's law, with H0 = 70 km/s/Mpc, the recessional velocity of a galaxy at a distance of 220 Mpc is approximately 15,000 km/s.

2. If H0 = 60 km/s/Mpc, the recessional velocity of a galaxy at a distance of 220 Mpc would be approximately 13,000 km/s.

3. If H0 = 80 km/s/Mpc, the recessional velocity of a galaxy at a distance of 220 Mpc would be approximately 17,000 km/s.

4. According to Hubble's law, with H0 = 70 km/s/Mpc, a galaxy with a recessional velocity of 3000 km/s would be approximately 43 Mpc away.

5. If H0 = 60 km/s/Mpc, a galaxy with a recessional velocity of 3000 km/s would be approximately 50 Mpc away.

6. If H0 = 80 km/s/Mpc, a galaxy with a recessional velocity of 3000 km/s would be approximately 38 Mpc away.

1. According to Hubble's law, the recessional velocity of a galaxy is given by the formula v = H0 × d, where v is the recessional velocity, H0 is the Hubble constant, and d is the distance to the galaxy. In this case, H0 is given as 70 km/s/Mpc and the distance is 220 Mpc. Plugging in these values, we have v = 70 km/s/Mpc × 220 Mpc = 15,400 km/s. Rounding to two significant figures, the recessional velocity of the galaxy is approximately 15,000 km/s.

2. If we change the value of H0 to 60 km/s/Mpc and keep the distance at 220 Mpc, the new recessional velocity would be v = 60 km/s/Mpc × 220 Mpc = 13,200 km/s. Rounding to two significant figures, the recessional velocity of the galaxy would be approximately 13,000 km/s.

3. If H0 is increased to 80 km/s/Mpc while keeping the distance at 220 Mpc, the new recessional velocity would be v = 80 km/s/Mpc × 220 Mpc = 17,600 km/s. Rounding to two significant figures, the recessional velocity of the galaxy would be approximately 17,000 km/s.

4. To find the distance to a galaxy with a given recessional velocity, we can rearrange Hubble's law: d = v / H0. Using H0 = 70 km/s/Mpc and v = 3000 km/s, we have d = 3000 km/s / 70 km/s/Mpc = 42.86 Mpc. Rounding to two significant figures, the distance to the galaxy would be approximately 43 Mpc.

5. If we change H0 to 60 km/s/Mpc and keep the recessional velocity at 3000 km/s, the new distance would be d = 3000 km/s / 60 km/s/Mpc = 50 Mpc.

6. If H0 is increased to 80 km/s/Mpc while keeping the recessional velocity at 3000 km/s, the new distance would be d = 3000 km/s / 80 km/s/Mpc = 37.5 Mpc. Rounding to two significant figures, the distance to the galaxy would be approximately 38 Mpc.

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Sibling relationships are thought to be so important because they often provide a lifelong source of emotional support and social learning.

Siblings are often the longest lasting relationships in a person's life, and they can provide a sense of emotional support throughout one's life. Siblings also play a significant role in social learning, as they provide a natural context for children to learn social skills such as conflict resolution, negotiation, and communication.

Additionally, siblings may share similar experiences and understandings due to their shared upbringing, which can lead to a strong bond. Overall, sibling relationships are thought to be important due to their potential for lifelong support and social learning.

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When a block slides on a frictionless horizontal surface, two forces of equal magnitude, F, act on it. These forces can be explained using Newton's laws of motion.

According to the first law, an object will continue moving with a constant velocity unless acted upon by a net external force. In this case, the block is initially at rest, so the net force acting on it is zero. However, when the forces of magnitude F are applied, there is a net external force acting on the block, causing it to accelerate. This acceleration is described by the second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. Therefore, the block will experience an acceleration when the forces of magnitude F are applied to it.

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Explanation:

electrical energy into heat energy

electrical , thermal

Answer:

I would hope they can change this question

Answer:

The energy stored in an inductor is given as:

EL=1/2 LI ²

So, when the current is doubled, the energy stored in the inductor will become 4 times.