Galena's specific gravity is 7.5, that of quartz 2.65, and that of liquid mercury 13.6. Given equal-sized samples (volumes) of galena and quartz, which will feel heavier? Choose one: A. galena B. The same volume of water will feel heavier than both of them. C. They will feel about equal. D. quartz

The assembly and disassembly of IFs are regulated by a variety of factors, including phosphorylation, subunit availability, pH, and ionic strength.

Intermediate filaments (IFs) are components of the cytoskeleton that control a variety of biological processes. IFs are typically less dynamic than microtubules and actin filaments, and they appear to be more stable. The assembly and disassembly of intermediate filaments are regulated by phosphorylation-dephosphorylation mechanisms.

The assembly and disassembly of intermediate filaments are controlled by a variety of factors. One of the primary determinants of IF dynamics is phosphorylation. Phosphorylation of specific residues on the IF proteins affects both the ability of the protein to form filaments and its stability once it has formed a filament.

In some cases, the presence of free subunits can promote filament formation, while in others, the formation of complexes between subunits can inhibit filament assembly. Changes in pH or ionic strength can also affect the assembly and disassembly of IFs.Intermediate filaments (IFs) are cytoskeletal structures that are typically more stable than microtubules or actin filaments.

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The Actual Mechanical Advantage (AMA) is the ratio of the output force to the input force and can be calculated by dividing the output force (320 N) by the input force (90 N). This gives an AMA of 3.556.

Force is an external influence that causes an object to move, stop, accelerate, or change direction. It is expressed in a variety of ways, such as the push of a hand, the pull of gravity, or a blast of air. It can also be expressed in terms of energy, such as sound waves, radiation, or electrical current. Force is a vector quantity, meaning it has both magnitude and direction. This means that when two forces act on an object, the result is the sum of the forces acting in the same direction, and the difference of the forces acting in opposite directions.

a) The Actual Mechanical Advantage (AMA) is the ratio of the output force to the input force and can be calculated by dividing the output force (320 N) by the input force (90 N). This gives an AMA of 3.556.

b) The Ideal Mechanical Advantage (IMA) is the ratio of the output distance to the input distance and can be calculated by dividing the output distance (2.9 m) by the input distance (8.2 m). This gives an IMA of 0.353.

c) The efficiency of the block-and-tackle can be calculated by dividing the AMA by the IMA and multiplying by 100. This gives an efficiency of 100 x 3.556/0.353 = 1008.8%. This means that the block-and-tackle is able to convert 1008.8% of the input force into output force.

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Answer:

Explanation:

Given:

m = 5.41 kg

g = 9.8 m/s² - acceleration of gravity

a = 75·g = 75·9.8 ≈ 735 m/s²

__________________

F - ?

Newton's second law:

F = m·a

F = 5.41·735 ≈ 3 980 N

→ The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:

1C = 6.24150975⋅10¹⁸e

Q(e) = Q(C) × 6.24150975 × 10¹⁸

Q(e) = 96,500 × 6.24150975 × 10¹⁸

Q(e) = 6.02305690875 × 10²³

which is round off to

→ 6.03 × 10²³ electrons

Answer:

Answers will vary. Sample response : The most common injuries from sports include ankle sprains, concussion, bone fractures, knee tears, hamstring strains, and groin strain.

Explanation:

Sample response, EDGE 2021

Answer:

200,000 joules <3

Explanation:
just accept it

Answer:

\(2.00 * 10^5J\)

Explanation:

Make use of your conversion factors:

\(200KJ * \frac{1000J}{1kJ} = 200,000J = 2.00* 10 ^5J\)

Or alternatively make use of your scientific notation. \(kilo = 10^3\)

Therefore \(200kJ = 200*10^3J=2.0*10^2*10^3J = 2.0*10^5J\)

Answer:

No, according to Newton's first law of motion, the block cannot exert a force on itself, and the body will remain at rest unless unbalanced forces act on it

However according to Newton's third and first laws of motion the action of gravity pulling the block down the plane is equal to the reaction force of friction, preventing the motion

Explanation:

According to Newton's third law, the action force of gravity on the block tending to drag the block down along the inclined plane is equal to the reaction force of the frictional force of the inclined plane due to the interactions between the surfaces of the block and the plane which tends to prevent the motion of the block when both the component of the gravitational force down the plane and the frictional force are equal.

The vertical distance through which the book falls is determined as 1,048.8 m.

The vertical distance through which the book falls is calculated as follows;

h = vt + ¹/₂gt²

where;

h = (16 x sin52)(13.4)  + (0.5)(9.8)(13.4²)

h = 1,048.8 m

Thus, the vertical distance through which the book falls is determined as 1,048.8 m.

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Lamarck's theory of evolution, also known as Lamarckism, proposed two main ideas. Firstly, the theory of use and disuse suggests that organs or traits that are used more frequently become stronger and more developed, while those that are not used gradually deteriorate over generations. Secondly, the theory of inheritance of acquired characteristics states that an organism can pass on traits acquired during its lifetime to its offspring.

Under Lamarck's theory, an organism might evolve by developing or strengthening certain traits through use and passing them on to the next generation. For example, if a giraffe stretches its neck to reach leaves high in the trees, its offspring would inherit a longer neck. This gradual elongation of the neck would continue over generations.

In contrast, under Darwin's theory of natural selection, an organism might evolve through the process of adaptation to its environment. For instance, consider a bird population with varying beak sizes. If the available food source consists of small seeds, individuals with smaller beaks are more likely to survive and reproduce, passing on their genes for smaller beaks. Over time, the average beak size in the population would decrease due to the selective advantage of smaller beaks in obtaining food.

In summary, Lamarck's theory proposed that acquired traits can be inherited, leading to gradual changes in an organism's characteristics. Darwin's theory, on the other hand, emphasized the role of natural selection in the adaptation of organisms to their environment, resulting in the accumulation of advantageous traits over generations.

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This means that the distance at which a person can distinguish the individual holes in the acoustic tile is approximately 1.23 degrees from the tile.

The distance at which a person can distinguish the individual holes in the acoustic tile depends on the size of the holes, the diameter of the pupil of the observer's eye, and the wavelength of the light in the room.

To determine the distance, we can use the Rayleigh criterion, which states that an object can be resolved if the angular resolution of the eye is greater than the angular size of the object. The angular size of an object can be calculated using the formula:

θ = 2 * tan\(^-1\)(π * D / λ)

where θ is the angular size, D is the diameter of the pupil of the eye, and λ is the wavelength of the light.

In this case, the diameter of the pupil of the observer's eye is given as 4.00 mm and the wavelength of the room light is given as 675.0 nm.

To find the distance at which the individual holes can be distinguished, we can rearrange the formula for θ to solve for D:

D = θ / (2 * tan\(^-1\)(π * D / λ))

Plugging in the given values, we get:

D = 4.00 mm / (2 * tan\(^-1\)(π * 4.00 mm / 675.0 nm))

= 0.0249 radians

= 1.23 degrees

This means that the distance at which a person can distinguish the individual holes in the acoustic tile is approximately 1.23 degrees from the tile. This distance will increase as the observer moves further away from the tile, but the angular resolution of the eye is not ideal and the resolution may be limited.  

.

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Work is performed by him is zero.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.

Given in the question a force of 1200 N crate but it doesn't move.

Work = force x distance. In units, Joules = Newtons x meters.

So: Work = 1200 Newtons x 0 meters

Work  = 0 joules.

Work is performed by him is zero.

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1) The missing properties are \(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\) and \(h = 640.59\,\frac{kJ}{kg}\). (Subcooled liquid)

2) The missing properties are \(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\) and \(x = 0.394\). (Liquid-gas mix)

3) The missing properties are \(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\) and \(u = 3251.7\,\frac{kJ}{kg}\). (Superheated steam)

4) The missing properties are \(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\) and \(x = 2.988\times 10^{-3}\). (Solid-gas mix)

In this question we must determine the phase associated to the given pressure (\(p\)), in kilopascals, temperature (\(T\)), in degrees Celsius, specific volume (\(\nu\)), in cubic meters per kilogram, internal energy (\(u\)), in kilojoules per kilogram, enthalpy (\(h\)), in kilojoules per kilogram, or quality (\(x\)), no unit.

By steam tables we know that saturation temperature associated with pressure is 151.83 °C, which means that water is a subcooled liquid and quality does not apply herein.

The missing properties are summarized below:

\(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\), \(h = 640.59\,\frac{kJ}{kg}\)

The missing properties are \(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\) and \(h = 640.59\,\frac{kJ}{kg}\). (Subcooled liquid) \(\blacksquare\)

By steam tables we know that water is a mix of gaseous and liquid phases. Hence, the missing properties are summarized below:

\(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\), \(x = 0.394\)

The missing properties are \(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\) and \(x = 0.394\). (Liquid-gas mix) \(\blacksquare\)

By steam tables we know that water is a superheated steam. Hence, missing properties are summarized below:

\(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\), \(u = 3251.7\,\frac{kJ}{kg}\)

The missing properties are \(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\) and \(u = 3251.7\,\frac{kJ}{kg}\). (Superheated steam) \(\blacksquare\)

By ice tables we know that properties correspond to a mix of solid and gaseous phases. Thus, missing properties are summarized below:

\(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\), \(x = 2.988\times 10^{-3}\)

The missing properties are \(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\) and \(x = 2.988\times 10^{-3}\). (Solid-gas mix) \(\blacksquare\)

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The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

\(\rm F=qvBsin\theta\)

where

The magnitude of the charge   \(q=5.7\ \mu C =5.7\times 10^{-6} \ C\)

The velocity of the charge        \(v=4.5\times 10^5\ \frac{m}{s}\)

The magnitude of the magnetic field   \(3.2\ mT=0.0032\ T\)

The angle between the directions of v and B  \(\theta =90^o-37^o=53^o\)

By substituting the values we will get:

\(F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)\)

\(F=6.6\times 10^{-3}\ N\)

Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

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Answer:

a - on edge

Explanation:

yes

Since the bullet was moving to the right, the stopping force will act to the left.

So, the magnitude of the stopping force is 2.2 N, and its direction is to the left.

To determine the magnitude of the stopping force acting on the bullet, we can use the principle of impulse and momentum. The impulse experienced by an object is equal to the change in momentum it undergoes. Mathematically, impulse is given by the equation:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the bullet is initially moving to the right with a speed of 220 m/s. After hitting the target, it travels an additional 24.2 cm into the target, which means its final velocity is zero (since it stops). Let's calculate the initial and final momenta.

Initial momentum = mass × initial velocity

= 0.010 kg × 220 m/s

= 2.2 kg·m/s

Final momentum = mass × final velocity

= 0.010 kg × 0 m/s

= 0 kg·m/s

The change in momentum is equal to the initial momentum minus the final momentum:

Change in momentum = Final momentum - Initial momentum

= 0 kg·m/s - 2.2 kg·m/s

= -2.2 kg·m/s

Since momentum is a vector quantity, the negative sign indicates that the bullet's momentum has reversed direction.

Impulse = Force × Time

Since the stopping force is constant, the time over which it acts is not given explicitly. However, since we are only interested in the magnitude of the force, we can assume that the time of impact is very small, so we can neglect it in this calculation.

Therefore, the magnitude of the stopping force is given by:

Force = Impulse / Time

Since the impulse is equal to the change in momentum (-2.2 kg·m/s) and the time is assumed to be very small, we can say that the magnitude of the stopping force is approximately 2.2 N.

As for the direction of the stopping force, it is opposite to the initial direction of the bullet's motion.

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Answer:

A. Neon and argon

General Formulas and Concepts:

Explanation:

Elements that have a full valence shell (the outermost shell), are in Group 18 of the Periodic Table.

Because their outermost shell is full, they are inert, meaning that they do not like to bond or react with other elements.

Therefore, these gases with a stable full valence shell are known as Noble Gases.

A. would be the correct answer.

Answer:argon and krypton

Explanation:

Noble gases

Since distance is a scalar quantity and displacement is the vector quantity, the distance travelled is 19 m while displacement is 3 m

Displacement is the distance travels in a specific direction. It is a vector quantity. Both distance and displacement are measured in meter.

Given that Lilia rides 4 m to the school. After school she rides an extra 7 m, but then she rides an extra 8 m in the opposite direction.

The distance will be the sum of all the given parameters. That is,

Distance = 4 + 7 + 8 = 19 m

But displacement is vector quantity.

Displacement = 4 + 7 - 8 = 3 m

Therefore, the distance travelled is 19 m while displacement is 3 m

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Answer:

An engine made of heat!

Okay actual answer, A heat engine is a mechanical energy converter that transforms heat or thermal energy to mechanical energy.

The required coefficient of heat transfer is 244.71 W/K and the outlet oil temperature is 492.82 K.

Given values are:

Mass flow rate of water, m_{w} = 360 kg/h per tube

Diameter of the metal tube,

D = 19 mm

Thickness of the metal tube, δ = 1.3 mm

Length of the metal tube, L = 2 m

Mass flow rate of oil, m_{o} = 6.675 kg/s per tube

Inlet temperature of oil, T_{oi} = 370 K

Inlet temperature of water, T_{wi} = 280 K

Coefficient of heat transfer on the oil side, h_{oi} = 1.7 m^{2} K/kW

Coefficient of heat transfer on the water side, h_{wi} = 2.5 m^{2} K/kW

Specific heat of the oil, c_{o} = 1.9 kJ/kgK

The formula for finding the coefficient of heat transfer is given by;

Q = UAΔT  where, Q = m_{o}c_{o}(T_{oo}- T_{oi}) , ΔT = (T_{wo}-T_{wi}) / ln(T_{wo}-T_{wi})/ (T_{oo}- T_{oi})

Now, we need to calculate UA first.

UA = 1/(1/h_{oi}+ δ/(kA)+ 1/h_{wi})

In order to get A, we need to calculate the area of the cross-section of the tube.

A = π/4 D^{2}- π/4 (D- 2δ)^{2}

Now, let's put the given values in the above equations and get the answer.

To calculate the area of the cross-section of the tube, we have;

A = π/4 D^{2}- π/4 (D- 2δ)^{2}A = π/4 (0.019)^{2}- π/4 (0.019- 2× 0.0013)^{2}A = 2.335× 10^{-4} m^{2}So, UA = 1/(1/1.7+ 0.0013/(56.2× 2.335× 10^{-4})+ 1/2.5)UA = 244.71 W/K

The mass flow rate of water in kg/s is360 kg/h = 0.1 kg/s

So, we have ΔT = (T_{wo}-T_{wi}) / ln(T_{wo}-T_{wi})/ (T_{oo}- T_{oi})

Here, the temperature of water leaving the cooler is not given.

So, let's assume it to be T_{w}Now, ΔT = (T_{w}-T_{wi}) / ln(T_{w}-T_{wi})/ (T_{oo}- T_{oi})

Putting the given values, we have ΔT = (T_{w}- 280) / ln(T_{w}- 280)/ (370- T_{oi})

After calculation, we will get ΔT as 17.96 K.

Now, we have Q = UAΔTQ = 244.71× 17.96Q = 4407.82 W

Now, Q = m_{o}c_{o}(T_{oo}- T_{oi})

Therefore, 4407.82 = 6.675× 1.9× (T_{oo}- 370)T_{oo}- 370 = 122.82 K

Therefore, T_{oo} = 492.82 KThe required coefficient of heat transfer is 244.71 W/K and the outlet oil temperature is 492.82 K.

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Answer:

The charge of a neutron is 0  

The charge of an electron is -1

Explanation:

Answer:

The charge of Neutrons is: 0

The charge of Electrons is: -1

Explanation:

Neutrons are uncharged and Electrons are negatively charged. The negative charge of one electron balances the positive charge of one proton. Both protons and neutrons have a mass of 1, while electrons have almost no mass.

Answer: Rotational motion

Explanation: The two types of motion of the rolling ball are translational motion and rotational motion. The center of mass of the ball undergoes translational motion whereas the ball undergoes rotational motion in the center of mass frame.

The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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Answer:

1.6L

Explanation:

Given parameters:

Initial volume  = 1.5L

Initial temperature  = 5°C  = 5 + 273  = 278K

Final temperature  = 30°C = 30 + 273  = 303K

Unknown:

Final or new volume  = ?

Solution;

Since pressure is constant, we simply apply Charles's law to solve this problem.

Using the expression below,

          \(\frac{V_{1} }{T_{1} }\)   = \(\frac{V_{2} }{T_{2} }\)

V and T are volume and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

         \(\frac{1.5}{278}\)   = \(\frac{V_{2} }{303}\)

          278V₂  = 1.5 x 303

                V₂  = 1.6L

Answer:

b, the fastest the car has traveled out of those options is 4-5 seconds.

Explanation:

Answer: B because the car traveled the farthest in the shortest amount of time on the graph.

Answer:

Explanation:

Angle of refraction is the angle made by refracted ray with the normal at the point of incidence . In this figure , refracted ray has been shown by line having arrow-head . Normal has been shown by broken line .

We observe that in figure D , angle made by refracted ray with normal is greatest . So figure D is the answer.

The  image where the angle of refraction is the greatest is the image D

The angle of refraction is the angle that the refracted ray made with the x-axis.

The higher the angle between the refracted ray and the x-axis, the higher the angle of refraction and vice versa.

From the given diagram, we can see that the  image where the angle of refraction is the greatest is the image D

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the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Galileo Galilei made the first detailed observations of the largest planet in our solar system.

Galileo Galilei made the first detailed observations of Jupiter in solar system. Galileo is renowned for his discoveries. He was the first to report telescopic observations of mountains on the moon, moons of Jupiter,  phases of Venus, and rings of Saturn. He also invented an early microscope and a predecessor to the thermometer.

Galileo's discoveries about the Moon, Jupiter's moons, Venus, and sunspots supported the idea that the Sun was the center of the Universe.  Work of Galileo also laid the foundation for today's modern space probes and telescopes.

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The two elements found in a sample of compound dinitrogen oxide, which is a gas at room temperature are nitrogen and oxygen.

Dinitrogen oxide or nitrous oxide is commonly known as laughing gas,

Dinitrogen oxide is a chemical compound, an oxide of nitrogen with the formula N₂O.

At room temperature, this gas is colorless, non-flammable gas, and has a slightly sweet scent.

Dinitrogen oxide or Nitrous Oxide is also called laughing gas or happy gas due to its intoxicating effects when inhaled.

From the chemical formula of Dinitrogen oxide which is written as;

N₂O  = two nitrogen atoms and on1 oxygen atom

The compound of  Dinitrogen oxide is made of;

2 atoms of nitrogen and 1 atom of oxygen

Thus, the compound of Dinitrogen oxide which is a gas at room temperature is made of two element. These two elements contained by the gas sample are known as nitrogen and oxygen.

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Answer:

nitrogen and oxygen.

Explanation:

the reason is cause i got it right

The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

Work done = Force (N) × distance (m)

According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;

W = 3N × 25metres

W = 75Nm

Therefore, 75Nm is the work done on the table.

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Answer:

3.8 × 108 m

Explanation:

Use formula: v^2 = G x m central / r

G = 6.77 e-11

Also, it was right on Edge.

Good luck!

The distance between Earth and its moon is 3.8×10⁸ m.

A force that causes a body to follow a curved path is known as a centripetal force. It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path.

It is "a force by which bodies are dragged or driven, or in any manner tend, towards a point as to a center," according to Isaac Newton.

Given parameters:

Mass of the Earth: M = 6.0 × 10²⁴ kg.

Mass of the moon: m = 7.3 × 10²² kg.

Moon's tangential speed: v = 1,025 m/s

Let the distance between the center of Earth and the moon is r.

Hence,

GMm/r² = mv²/r

r = GM/v²

= 6.7 × 10 ⁻¹¹ × 6.0 × 10²⁴ / (1,025)²

= 3.82×10⁸ m.

Hence, by subtracting Earth's radius = 6.4 x 10⁶ m, we get, the distance between Earth and its moon is 3.8×10⁸ m.

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