Given a number is a whole number, write an expression to describe the preceding whole number.

Answer:

560

Step-by-step explanation:

1=160

2=320

3=480

4=640

5=800

6=960

7=1120

8=1280

9=1440

JUST ADD 160 EACH TIME

hope this is what your looking for   :)

Answer:

x = 44.25

Step-by-step explanation:

9 + 6.6x = 7x - 8.7

    -7x       -7x

---------------------------

9 - 0.4x = -8.7

-9             -9

-0.4x = -17.7

÷-0.4   ÷-0.4

-------------------

x = 44.25

we know that

when you want to figure out a tip, you take your total bill and multiply it by the percentage you would like to tip them

so

15%=15/100------> 0.15

$63*0.15=$9.45

the answer is

$9.45

Answer:

\(\angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)

Step-by-step explanation:

\(\frac{\sin(\angle BAC)}{13}=\frac{\sin 23^{\circ}}{6} \\ \\ \sin \angle BAC=\frac{13\sin 23^{\circ}}{6} \\ \\ \angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)

Answer: Tyler traveled 16 blocks

Step-by-step explanation:

The radius of Deimos to one significant digit in meters is approximately 9.4 m

.

Given the ratio of the Sun-from-Mars distance to Deimos-from-Mars distance is 365,000, the distance between Mars and Deimos can be found to bedeimos distance = Sun-Mars distance / 365,000

Next, we can find the diameter of Deimos by noting that 550 of its diameters is equal to the distance it takes to transit the shadow of Mars during a lunar eclipse.

Let's call the diameter of Deimos "d", so we can

diameter = 1/550 * deimos distance

Finally, the Sun appears about 8.4 times as large as Deimos in the Martian sky. If we call the radius of Deimos "r", then the radius of the Sun is 8.4r.

Using the information given, we can set up the following equation:

deimos distance / (3,000,000 + r) = 8.4r / (3,000,000)Simplifying and solving for r,

we get:r = 9.39 m (rounded to one significant digit)

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Answer:

Approximately \(0.7\; {\rm ft}\).

Step-by-step explanation:

If the current bounce is of height \(h\; {\rm ft}\), the next bounce would be of height \((78\%\, h)\; {\rm ft}\), which is equal to \((0.78\, h)\; {\rm ft}\).

It is given that the first bounce is of height \(6.5\; {\rm ft}\). Relative to this first bounce:

In general, the \(n\)th bounce would have been dampened \((n - 1)\) times. The height of that bounce would be \(((0.78)^{n - 1}\, 6.5)\; {\rm ft}\).

Thus, the \(10\)th bounce would have been dampened \((10 - 1) = 9\) times. The height of that bounce would be \(((0.78)^{10 - 1} \, 6.5)\; {\rm ft} \approx 0.7\; {\rm ft}\) (rounded to the nearest tenth, one digit after the decimal point.)

Answer:

400 pieces

Step-by-step explanation:

To find the amount of units the could buy we divide 20,000 by 50

20,000 ÷ 50

= 400

-Chetan K

Answer:400 pieces

Step-by-step explanation:

Given,

Budget=$20000

Each piece costs=$50

According to question,

Total pieces that can be bought=20000/50

                                                     =400 (answer)

Answer:

5

Step-by-step explanation:

We cannot repeat an x value for the relation to be a function

Since x=3 ,4, 7 are already used

We must let x=5

Answer:

y = 3x +3 y

Step-by-step explanation:

The values of x and y in the system of equations are x = 1 and y = 2

Linear equations are equations that have constant average rates of change.

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

4x + 3y = 10

y - x = 1

Make y the subject in the second equation, by adding x to both sides of the equation

y - x + x = x + 1

This gives

y = x + 1

Substitute y = x + 1 in 4x + 3y = 10

4x + 3(x + 1) = 10

4x + 3x + 3 = 10

Evaluate the like terms

7x = 7

This gives

x = 1

Substitute x = 1 in y = x + 1

y = 1 + 1

Evaluate

y = 2

Hence, the solution for the system of linear equations 4x + 3y = 10 and y - x = 1 are x = 1 and y = 2

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Possible question

Solve for x and y in the following system of equations

y - x = 1

4x + 3y = 10

Using the simplex method, the optimal solution for the given linear program is z = 14, with x1 = 0 and x2 = 5. There are no alternative optimal solutions.

To solve the linear program using the simplex method, we start by converting the problem into standard form with all constraints in the form of inequalities and non-negative variables. The initial tableau for the problem is as follows:

 |   x1  |   x2  |   s1   |   s2   |   b   |

--------------------------------------------

z |  -3   |   6   |   0    |   0    |   0   |

--------------------------------------------

s1|   5   |   7   |   1    |   0    |   35  |

--------------------------------------------

s2|  -1   |   2   |   0    |   1    |   2   |

--------------------------------------------

Next, we perform the simplex iterations to improve the objective function value. After performing the necessary row operations, we arrive at the final tableau:

 |   x1  |   x2  |   s1   |   s2   |   b   |

--------------------------------------------

z |   0   |   1   |  3/2   |  -1/2  |   14  |

--------------------------------------------

s1|   0   |   0   |   4    |   3    |   5   |

--------------------------------------------

s2|   1   |   0   |  -1/2  |   5/2  |   3   |

--------------------------------------------

From the final tableau, we can see that the optimal solution is z = 14, with x1 = 0 and x2 = 5. The decision variable x1 is at its lower bound, indicating that it is non-basic. Therefore, there are no alternative optimal solutions in this case.

In summary, the optimal solution for the given linear program is z = 14, with x1 = 0 and x2 = 5. There are no alternative optimal solutions.

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The probability density function for a normal distribution N(68, 5) reaches its maximum height at x = 68, which is the mean of the distribution. The function does not touch the x-axis at μ±30.

The probability density function (PDF) for a normal distribution is bell-shaped and symmetrical around its mean. In this case, the mean (μ) is 68, and the standard deviation (σ) is 5.

(a) To find the x value at which the PDF reaches a maximum, we look at the mean of the distribution, which is 68. The PDF is highest at the mean, and as we move away from the mean in either direction, the height of the PDF decreases. Therefore, the x value at which f(x) reaches a maximum is x = 68.

(b) The PDF of a normal distribution does not touch the x-axis at μ±30. The x-axis represents the values of x, and the PDF represents the likelihood of those values occurring. In a normal distribution, the PDF is continuous and never touches the x-axis. However, the PDF becomes close to zero as the values move further away from the mean. Therefore, the probability of obtaining values μ±30, which are 38 and 98 in this case, is very low but not zero. So, the PDF does not touch the x-axis at μ±30, but the probability of obtaining values in that range is extremely small.

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a) The probability that a tire will be too narrow is 0.252492. b)The probability that a tire will be too wide is 0.091211. c) , the probability that a tire will be defective is 0.252492 + 0.091211 = 0.343703.

a. To calculate the probability that a tire will be too narrow, we need to find the area under the normal distribution curve that falls below the lower specification limit.

Using the Z-score formula, we calculate the Z-score for the lower specification limit as follows:

Z = (Lower specification limit - Mean) / Standard deviation

Z = (22.8 - 23) / 0.15

Z = -0.666667

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the left of Z = -0.666667 is approximately 0.252492.

b. To calculate the probability that a tire will be too wide, we need to find the area under the normal distribution curve that falls above the upper specification limit.

Using the Z-score formula, we calculate the Z-score for the upper specification limit as follows:

Z = (Upper specification limit - Mean) / Standard deviation

Z = (23.2 - 23) / 0.15

Z = 1.333333

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the right of Z = 1.333333 is approximately 0.091211.

c. The probability that a tire will be defective is the sum of the probabilities of it being too narrow and too wide, since being outside the specification limits indicates a defect.

Therefore, the probability that a tire will be defective is approximately 0.252492 + 0.091211 = 0.343703.

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The heap-sorting-based algorithm for finding the k smallest positive elements from an unsorted array has an expected analytical time complexity of O(n + k log n).

Constructing the Heap:

Start by constructing a max-heap from the given array.

Since we are only interested in positive elements, we can exclude the negative elements during the heap-building process.

To build the heap, iterate through the array and insert positive elements into the heap.

Extracting the k smallest elements:

Extract the root (maximum element) from the heap, which will be the largest positive element.

Swap the root with the last element in the heap and reduce the heap size by 1.

Perform a heapify operation on the reduced heap to maintain the max-heap property.

Repeat the above steps k times to extract the k smallest positive elements from the heap.

Time Complexity Analysis:

Heap-building: Building a heap from an array of size n takes O(n) time.

Extracting k elements: Each extraction operation takes O(log n) time.

Since we are extracting k elements, the total time complexity for extracting the k smallest elements is O(k log n).

Therefore, the overall time complexity of the heap-sorting-based algorithm for finding the k smallest positive elements is O(n + k log n).

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Carpenter remove \(3/16\) inches from the top of the plank to the same thickness of wood from the top and bottom of the plank.

How many inches does the carpenter remove from the top of the plank ?

A wooden plank is \(5ft\) long and \(1\frac{1}{2}\) inches thick

to make the plank \(1\frac{1}{8}\) inches thick

Carpenter needs  to cut off

\(=1\frac{1}{2} -1\frac{1}{8} \\=\frac{3}{2} -\frac{9}{8} \\=\frac{3}{8}\)

Carpenter cuts each side

\(=\frac{3}{8} /2\\=\frac{3}{16} inches\)

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Answer: 12

Step-by-step explanation:

Answer:

118.7 inches squared.

Step-by-step explanation:

The area is the total space taken up by a flat (2-D) surface or shape. The area is always measured in square units.

Diameter is the length across the entire circle, the line splitting the circle into two identical semicircles.

The expression for solving the area of a circle is A = π × \(r^{2}\).

To solve for the semicircle above, we can divide the diameter into 2 to get the radius.

So, the radius of the upper semicircle is 6 inches.

If the radius of a circle is 6 inches, then you can substitute r for 6 into the formula.

This simplifies to A = 36π. If a semicircle if half the size of a normal circle, then it will be A = 18π, because 36 ÷ 2 = 18.

To solve for the lower semicircle, we can do the same this as we did above.

But wait, we don't know the radius or diameter!

No worries! To solve for the diameter of the circle, we can take the line that is parallel to the semicircle (the one that has a length of 12in) and subtract 6 from it. We subtract 6 from it because the semicircle takes up the remaining length of the line, not including the 6in.

To solve for the lower semicircle, we can divide the diameter by 2 to get the radius.

So, the radius of the circle is 3.

Now we can insert 3 into the expression.

This simplifies to A = 9π. If a semicircle if half the size of a normal circle, then it will be A = 4.5π because like above, 9 ÷ 2 = 4.5.

Adding the two semicircles together:

So, the area of both semicircles is approximately 70.6858 square inches.

To solve for the area of a rectangle we use the expression:

Inserting the dimensions of the rectangle:

So, the area of the rectangle is 48 square inches.

Adding the two areas together:

Therefore, the area of the entire figure, rounded to the nearest tenth is \(118.7\) \(in^{2}\).

Answer:

goldfish

Step-by-step explanation:

In analyzing the performance of implementing the given methods over Singly Linked List and Doubly Linked List data structures, we consider the Big-O notation, which provides insight into the time complexity of these operations as the size of the list increases.

Add to Start of List:

Singly Linked List: O(1)

Doubly Linked List: O(1)

Both Singly Linked List and Doubly Linked List offer constant time complexity, O(1), for adding an element to the start of the list.

This is because the operation only involves updating the head pointer (for the Singly Linked List) or the head and previous pointers (for the Doubly Linked List). It does not require traversing the entire list, regardless of its size.

Add to End of List:

Singly Linked List: O(n)

Doubly Linked List: O(1)

Adding an element to the end of a Singly Linked List has a time complexity of O(n), where n is the number of elements in the list. This is because we need to traverse the entire list to reach the end before adding the new element.

In contrast, a Doubly Linked List offers a constant time complexity of O(1) for adding an element to the end.

This is possible because the list maintains a reference to both the tail and the previous node, allowing efficient insertion.

Add at Given Index:

Singly Linked List: O(n)

Doubly Linked List: O(n)

Adding an element at a given index in both Singly Linked List and Doubly Linked List has a time complexity of O(n), where n is the number of elements in the list.

This is because, in both cases, we need to traverse the list to the desired index, which takes linear time.

Additionally, for a Doubly Linked List, we need to update the previous and next pointers of the surrounding nodes to accommodate the new element.

In summary, Singly Linked List has a constant time complexity of O(1) for adding to the start and a linear time complexity of O(n) for adding to the end or at a given index.

On the other hand, Doubly Linked List offers constant time complexity of O(1) for adding to both the start and the end, but still requires linear time complexity of O(n) for adding at a given index due to the need for traversal.

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Let x be the number of child tickets sold

Let y be the number of adult tickets sold

Amount received for the child tickets: 5.90x

Amount received for the adult tickets: 9.40y

Total sales of 1001.30:

127 tickets were sold:

Use the two equations above as a system of equations, to solve it:

1. Solve y in the second equation.

2. Use the value you get in step 1 to substitute y in the first equation:

3. Solve x:

The value of x is 55

Answer:

65.97

Step-by-step explanation:

The formula for the volume of a cone is V=1/3hπr².

Step-by-step explanation:

answer is 65.97 hope it helps

Answer:

0.75

Step-by-step explanation:

The slope-intercept form is one way to write a linear equation (the equation of a line). The slope-intercept form is written as y = mx+b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis).

Answer:

First one: Rotation

Second one: Translation

Third one: Reflection

Fourth one: Translation

Step-by-step explanation:

Answer:

I hope I helped you!

This happens because as we increase the values (from 3, 4, and 5) the increase in the squares is greater

A pythagorean triple is a set of 3 numbers such that the sum of the squares of the two smaller ones is equal to the square of the larger one, here we have:

3² + 4² = 5²

9 + 16 = 25

25 = 25

Now, why we can't have another set of 3 consecutive numbers?

This happens because as we increase the values of the integers, more increases the values of the correspondent squares.

That also means that the distance (in units) between the largest value and the previous ones must increase, and that is why there aren't more pyhtagorean triples where all the digits are consecutive integers.

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The resulting value will give you the mass of the ball of radius 3 centered at the origin with the given density function.

To find the mass of the ball with a radius of 3 centered at the origin, we need to integrate the density function over the volume of the ball.

The density function is given as f(ρ, φ, θ) = 5e^(-ρ^3), where ρ represents the radial distance, φ represents the azimuthal angle, and θ represents the polar angle.

In spherical coordinates, the volume element is given by ρ^2 sin(φ) dρ dφ dθ.

To integrate over the ball, we need to set the limits of integration as follows:

ρ: 0 to 3

φ: 0 to π

θ: 0 to 2π

The mass of the ball can be calculated using the integral:

Mass = ∫∫∫ f(ρ, φ, θ) ρ^2 sin(φ) dρ dφ dθ

Mass = ∫[0 to 2π] ∫[0 to π] ∫[0 to 3] 5e^(-ρ^3) ρ^2 sin(φ) dρ dφ dθ

This integral needs to be evaluated numerically using appropriate software or numerical techniques.

The resulting value will give you the mass of the ball of radius 3 centered at the origin with the given density function.

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Step-by-step explanation:

do you happen to have a photo reference your sentence is a bit confusing

Answer:

44 = 4 · g OR g · 4 = 44

Step-by-step explanation:

So first we need to know what a variable is...

A variable is an unknown number in a math sentence

Knowing that we can write the equation.

"44 is the product 4 and Greg's height. Use the variable g to represent Greg's height"

Since we do not know Greg's height that is what we will use variable g to substitute it.

"44 is the product 4 and g"

Now all we have to do is convert this into an equation

(Note: Whenever you see product of something know that it means that you need to multiply)

So your final answer is...

44 = 4 · g

(Explanation: Since it says 44 is the product of then it means it is the answer so we will put an equal sign)

Hope this helps :)

The probability of one of three students being accepted to a program while the other two are not accepted is 3.2%, or 1.5:1, which is equivalent to a 66.7% chance.

The probability of one of three students being accepted to a program while the other two are not accepted can be calculated by dividing the total number of favorable outcomes by the total number of possible outcomes.

To calculate this, we need to know the probability of each individual student being accepted. For example, if the probability of each student being accepted is 0.2, the probability of one student being accepted while the other two are not would be (0.2)x(1-0.2)x(1-0.2), or 0.032. This would be written as a 3.2% chance.

The probability of one student being accepted while the other two are not can also be calculated using a permutation formula. The formula for this is

P(n,r) = n!/(n-r)!,

where n is the total number of students and r is the number of students accepted.

In this case, n = 3 and r = 1. So, P(3,1) = 3!/2! = 3/2 = 1.5.

This means that there is a 1.5:1 ratio of one student being accepted while the other two are not. This is equal to a 66.7% chance.

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To prove that two angles in two triangles are congruent, you must use the Angle-Angle Postulate (AA).  The Angle-Angle Postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the two triangles are congruent.

Therefore, to prove that two angles in two triangles are congruent, you must first show that the two angles have the same measure. This can be done by using the Angle Addition Postulate or by using subtracting the measure of one angle from the measure of the other.

Three vertices and three sides make up a triangle, which is a polygon. The triangle's angles are created when the three sides are joined end to end at a point. The three angles of the triangle sum up to 180 degrees.

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