The Heisenberg's uncertainty principle seem not to play a significant role here because value of Planck's constant 'h' is very small compared to location.
Consider a scenario where an electron's location is measured to demonstrate Heisenberg's uncertainty principle. A photon must collide with an item and then return to the measuring instrument in order to determine its position.
When a photon collides with an electron, momentum is transferred since photons have a finite amount of momentum. The electron's momentum will grow as a result of this momenta transfer. As a result, every attempt to determine a particle's location will make the value of its momentum more ambiguous.
The Heisenberg uncertainty principle is applicable to both microscopic and macroscopic objects.
According to Heisenberg's principle,
Δx. ΔP ≥ \(\frac{h}{4\pi}\)
where, ΔP = mΔV
h = 6.626 X 10⁻³⁴
From the above formula, the uncertainty in position for macroscopic will be very small.
While, the uncertainty uncertainty in position for. microscopic particles (like elections) will be huge.
Δx. ΔP ≥ \(\frac{h}{4\pi}\)
h = 6.626 × 10⁻³⁴ J.s
The value of Planck's constant 'h' is very small compared to location and momentum of macroscopic bodies.
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If a rocket takes off from earth with a certain force what must be true about earth
If a rocket takes off from Earth with a certain force, there are several things that must be true about Earth to make this possible.
Firstly, Earth must have a gravitational field that attracts the rocket toward its center. This gravitational force pulls the rocket toward the ground, and the rocket must overcome it with a force greater than the force of gravity in order to take off.
Secondly, Earth's atmosphere must be present, as the rocket needs to push against the air molecules to create thrust and lift off the ground. Thirdly, Earth's surface must be firm enough to support the launch of the rocket, with a strong and stable launchpad to prevent any accidents.
Fourthly, Earth's rotational speed and position in its orbit around the Sun must also be taken into account, as this affects the required trajectory of the rocket for a successful launch. Overall, a combination of Earth's gravitational force, atmosphere, surface conditions, and position in its orbit all play a crucial role in enabling a rocket to take off from Earth.
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A building has a flat roof of area
42.0 m2. Wind blows over the top of
the roof at 14.8 m/s. The air inside
the building is stationary. What is
the TOTAL force acting on the roof?
[?] N
The TOTAL force acting on the roof is 5,947.6 N.
What is the total force acting on the roof?
The pressure difference between inside and outside building is calculated as;
ΔP = ¹/₂ρv²
where;
ρ is the density of airv is the speed of the airΔP = ¹/₂ x 1.293 x 14.8²
ΔP = 141.6 Pa
The TOTAL force acting on the roof is calculated from the product of the pressure difference and area.
F = ΔP x A
F = 141.6 x 42
F = 5,947.6 N
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At 10 meters, a signal has a strength of 100 mW. About how strong will it be at 40 meters?
A) about 0.5 mW
B) about 5 mW
C) about 25 mW
D) about 6 mW
The closest answer to this value is option C) about 25 mW. However, it is important to note that this is only an approximate estimate and the actual signal strength may vary depending on various factors.
The strength of a signal decreases as it travels further from its source due to factors such as attenuation and interference. To calculate the approximate strength of a signal at 40 meters, we need to consider the distance between the source and the receiver, as well as any obstacles or interference that may affect the signal.
Assuming that the signal decreases in strength by a factor of 4 for every 10 meters of distance traveled (which is a common approximation), we can use the following formula to estimate the signal strength at 40 meters:
Signal strength at 40 meters = (Signal strength at 10 meters) x (distance ratio)^2
Distance ratio = (distance at 40 meters) / (distance at 10 meters) = 4
Plugging in the values, we get:
Signal strength at 40 meters = 100 mW x 4^2 = 1600 mW
Therefore, the signal strength at 40 meters is approximately 1600 mW. However, this value is not one of the options given in the question. To find the closest answer, we can use a logarithmic scale to convert the signal strength from mW to dBm (decibel-milliwatt), which is a more commonly used unit for measuring signal strength.
Using the formula dBm = 10 x log10 (mW), we get:
Signal strength at 40 meters = 32 dBm
To convert this value back to mW, we use the formula mW = 10^(dBm/10), which gives us:
Signal strength at 40 meters = 1584.89 mW
The closest answer to this value is option C) about 25 mW. However, it is important to note that this is only an approximate estimate and the actual signal strength may vary depending on various factors.
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What type of relationship exists between the comma teasel and all of the other plant
Answer:
Parasitic Relationship
A symbiotic relationship that is mutualism exists between the comma teasel and all of the other plants.
What is a Symbiotic relationship?Symbiosis or symbiotic relationship is any type of close and long-term biological interaction which is present between two different biological organisms, be it mutualistic relationship, commensalistic relationship, or parasitic relationship. The organisms, each termed as a symbiont, must be of different species.
The comma teasel and all of the other plants share a relationship where, the comma teasel pollinates flowers of different plant species. Pollination is important for the reproduction in plants and in return, the plants provide nectar to the organism.
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jocelyn stood in the middle of a trampoline causing the springs around the edge to stretch. Her identical twin, Jennifer, who has the same mass, joined her in the center of the trampoline.
How is conduction shown here:
Conduction Transfers Thermal Energy Through Direct Contact
Answer:
Conduction is the transfer of heat between substances that are in direct contact with each other. ... Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them.
Explanation:
Which characteristics are common to most salamanders? Check all that apply.
They undergo internal fertilization. They lose their tails as adults. They have wet, moist skin. They have long, strong legs. They begin life with gills.
what is 404.2 rounded to the nearest ten thousandth?
Answer:
The answer to your question is 404.2000
Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57 The 5-number summary is nothing, nothing, nothing, nothing, and nothing, all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)
Answer:
The 5-number summary is
1. Median = 0.93 W/kg
2. Lower quartile = 0.69 W/kg
3. Upper quartile = 1.16 W/kg
4. Minimum value = 0.54 W/kg
5. Maximum value = 1.42 W/kg
Explanation:
We are given the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones.
1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57
What is 5-number summary?
A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.
These statistical characteristics are:
1. Median
2. Lower quartile
3. Upper quartile
4. Minimum value
5. Maximum value
1. Median:
Arrange the data in ascending order
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
(n+1)/2 gives the median value of the data set.
(11 + 1)/2 = 6th position
Therefore, 0.93 W/kg is the median of the data set.
2. Lower quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The lower quartile is the median of the lower half of the data set.
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
The median is 6/2 = 3rd position
Therefore, the lower quartile of the data set is 0.69 W/kg
3. Upper quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The upper quartile is the median of the lower half of the data set.
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The median is 6/2 = 3rd position
Therefore, the upper quartile of the data set is 1.16 W/kg
4. Minimum value:
The minimum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the minimum value of the data set is 0.54 W/kg
5. Maximum value
The maximum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the maximum value of the data set is 1.42 W/kg
The box plot is illustrated in the attached diagram.
Relate the movement produced by seismic waves to the observations a person
would make of them as they traveled across Earth's surface.
Answer:
Theoretically it would be side to side
Explanation:
This answer is most likely to be side to side because of the tectonic plates shifting but to be honest who knows
The seismic waves which travel across Earth's surface are surface waves. The surface waves move up and down or back and forth in a circular motion.
What are seismic waves?A seismic wave can be described as a wave of acoustic energy that travels through the Earth. They form due to an earthquake, volcanic eruption, magma movement, and a large man-made explosion. Seismic waves are differentiated from seismic noise which is persistent low-amplitude vibration developing from various natural and anthropogenic sources.
The velocity of a seismic wave depends on the elasticity and density of the medium. The velocity of the waves tends to increase with depth through Earth's crust and mantle but reduces drastically going from the mantle to Earth's outer core.
Seismic surface waves travel along the surface of the earth and can be classified as a form of mechanical surface waves. These surface waves, diminish as they get further from the surface and travel more slowly than seismic body waves (P and S).
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3. A car is travelling at initial speed u = 32 m/s. It then starts to decelerate with a = -2.0 m/s2
for 8.0 seconds.
a) What is the speed of the car after 8.0 seconds?
b) How far did the car travel during those 8.0 seconds?
Please help
Please find attached photograph for your answer. Do comment whether it is useful or not.
a girl on her bike (of 35 kg) runs into a tree. initially going 4.5 m/s East, she rebounds going 3.3 m/s West. she interacts with the tree for 0.03 s. Determine the average force she experiences
The girl encounters a 9100 N average force to the west.
What is force?The interaction between two things or between an object and its surroundings is characterized by force, a physical quantity. It can be explained simply as the push or pull that one item applies to another.
How do you determine it?An object's mass (m) multiplied by its velocity (v) will give it momentum (p):
p = mv
The girl's initial momentum is:
To the East, p1 = (35 kg)(4.5 m/s) = 157.5 kg*m/s
The girl strikes the tree and rebounded with a speed of 3.3 m/s to the west. Her final momentum (p2) can be found as follows:
To the West, p2 = (35 kg)(-3.3 m/s) = -115.5 kg*m/s
Thus, the girl's change in momentum (∆p) is: ∆p = p2 - p1 = -115.5 kgm/s - 157.5 kgm/s = -273 kg*m/s to the West.
We are aware that the time spent interacting with the tree was 0.03 seconds. Hence, using the impulse-momentum theorem, the girl's average force (F) can be calculated as follows:
F = Δp / Δt
F = (-273 kg*m/s) / (0.03 s) = -9100 N to the West
The force is acting in the opposite direction to the girl's starting velocity, which is to the east, as indicated by the force's negative sign. As a result, the girl encounters a 9100 N average force to the west.
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The weight of a box is having a mass of 100 kg is ___n
Answer: the weight of the box is 980N
Explanation:
The weight an object has is defined as the force of gravity acting on that object which is given as
w =m x g
Since weight is defined as a force, it can also be written as
w=mg
= F= mg
where m= mass of the object in kg given as 100Kg
an g is the gravitational acceleration in m/s^2 = g is 9.8 m/s2
F= mg
F = 100 kg x 9.8 m/s2
F== 980Kgm/s^2 = 980N
Therefore the weight of the box is 980N
A lightbulb has 25 W stamped on it. What does this mean?
Answer:
A lightbulb has 25 W stamped on it. What does this mean?:
These labels mean that each lightbulb has Its respective power delivered to It when It Is connected to a constant
Explanation:
The coldest clouds in the ISM are molecular clouds, so named because their temperatures are low enough and their densities high enough for atoms to join together into molecules. These clouds are capable of collapsing to form new stars, in a stellar nursery like the one in the left image. The Pleiades (right image) is an example of stars that formed recently within such a nursery.
Molecular clouds range in mass from a few times the mass of our Sun (solar masses) to 10 million solar masses. Individual stars range from 0.08 to about 150 solar masses.
What does all of this imply about how stars form from molecular clouds?
Stars form from molecular clouds through a process known as stellar formation.
These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.
The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.
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Answers the questions
1. At what distance did the object start to move ?
Answer:
it started to move a 1 second
Answer:
at one second :p
Explanation:
Two protons are 1 meter apart. Determine the Fg and Fe. How do the forces of Gravitation and Coulomb’s Law impact the system? Does the force cause the protons to attract or repulse? Is the force always that way or just due to the system being 2 protons? Which Force is larger? By how much?
Answer:
fe
Explanation:
so if the Impact of the system is 2 than it appositive will be fe
Answer:
Explanation:
Given:
q₁ = q₂ = q = +1.6·10⁻¹⁹ C
m₁ = m₂ = m = 1.67·10⁻²⁷ kg
r = 1 m
k =
G = 6.67·10⁻¹¹ N·m² / kg²
k = 9·10⁹ N·m² / C²
__________________
Fg - ?
Fe - ?
Gravitational force of attraction of protons:
Fg = G·m₁·m₂ / r² = G·m² / r²
Coulomb repulsive force of protons:
Fe = k·q₁·q₂ / r² = k·q² / r²
The Coulomb force of repulsion of protons is greater than the force of gravitational attraction of protons:
Fe / Fg = k·q² / (G·m²) = (k/G)· (q/m)²
Fe / Fg = (9·10⁹ /6.67·10⁻¹¹)· (1.6·10⁻¹⁹/1.67·10⁻²⁷ )² ≈ 1,2·10³⁶ times more
LAYERS OF THE EARTH THAT SURROUNDS AND PROTECTS US FROM DANGEROUS RAYS FROM THE SUN
A.Atmosphere B.Biosphere
C.Hydrosphere D.Lithosphere
a bus is moving with the velociity of 36 km/hr . after seeing a boy at 20 m ahead on the road, the driver applies the brake and the bus gets stopped at 10 m distance. Now, calculate acceleration as well as time taken by this bus to stop.
Answer:
Assumption: the acceleration of this bus is constant while the brake was applied.
Acceleration of this bus: approximately \(\left(-6.0\; \rm m \cdot s^{-2}\right)\).
It took the bus approximately \(1.7\;\rm s\) to come to a stop.
Explanation:
Quantities:
Displacement of the bus: \(x = 10\; \rm m\).Initial velocity of the bus: \(\displaystyle u = 36\; \rm km \cdot hr^{-1} = 36\; \rm km \cdot hr^{-1}\times \frac{1\; \rm m \cdot s^{-1}}{3.6\; \rm km\cdot hr^{-1}} = 10\; \rm m \cdot s^{-1}\).Final velocity of the bus: \(v = 0\; \rm m\cdot s^{-1}\) because the bus has come to a stop.Acceleration, \(a\): unknown, but assumed to be a constant.Time taken, \(t\): unknown.Consider the following SUVAT equation:
\(\displaystyle x = \frac{1}{2}\, \left(a\, t^2\right) + u\, t\).
On the other hand, assume that the acceleration of this bus is indeed constant. Given the initial and final velocity, the time it took for the bus to stop would be inversely proportional to the acceleration of this bus. That is:
\(\displaystyle t = \frac{v - u}{a}\).
Therefore, replace the quantity \(t\) with the expression \(\displaystyle \left(\frac{v - u}{a}\right)\) in that SUVAT equation:
\(\displaystyle x = \frac{1}{2}\, \left(a\, \left(\frac{v -u}{a}\right)^2\right) + u\, \left(\frac{v - u}{a}\right)\).
Simplify this equation:
\(\begin{aligned}x &= \frac{1}{2}\, \left(a\, {\left(\frac{v -u}{a}\right)}^2\right) + u\, \left(\frac{v - u}{a}\right) \\ &= \frac{1}{2}\left(\frac{{(v - u)}^2}{a}\right) + \frac{u\, (v - u)}{a} =\frac{1}{a}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)\end{aligned}\).
Therefore, \(\displaystyle a= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)\).
In this question, the value of \(x\), \(u\), and \(v\) are already known:
\(x = 10\; \rm m\).\(\displaystyle u =10\; \rm m \cdot s^{-1}\).\(v = 0\; \rm m\cdot s^{-1}\).Substitute these quantities into this equation to find the value of \(a\):
\(\begin{aligned} a &= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right) \\ &= \frac{1}{10\; \rm m}\times \left(\frac{{\left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)}^2}{2} + \left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)\times 10\; \rm m \cdot s^{-1}\right)\\ &\approx -6.0\; \rm m \cdot s^{-2}\end{aligned}\).
(The value of acceleration \(a\) is less than zero because the velocity of the bus was getting smaller.)
Substitute \(a \approx -6.0\; \rm m \cdot s^{-2}\) (alongside \(u = 10\; \rm m \cdot s^{-1}\) and \(v = 0\; \rm m \cdot s^{-1}\)) to estimate the time required for the bus to come to a stop:
\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}}{-6.0\; \rm m \cdot s^{-2}} \approx 1.7\; \rm s\end{aligned}\).
A 70.0 kg person leaps from a bridge in with a bungee cord attached and falls 120 meters. If the bungee cord stretches 2.5 meters during the stopping process, what’s its force constant (k)?
The force constant of the bungee cord when a person of mass 70 kg leaps on a bridge with it is 219.52 N/m.
What is force constant?The force constant or spring constant is a measure of the stiffness of a spring. It is the force per unit deformation of the spring. Its SI unit is N/m.
To calculate the force constant of the bungee cord, we use the formula below.
Formula:
K = 2mgh/e²............. Equation 1Where:
K = Force contant of the bungee cordm = Mass of the persong = Acceleration due to gravityh = Height at which the person falle = extensionFrom the question,
Given:
m = 70 kgg = 9.8 m/s²h = 120 me = 2.5 mSubstitute these values into equation 1
K = (2×70×9.8/2.5²)K = 219.52 N/mHence, the force constant of the bungee cord is 219.52 N/m.
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what acceleration of a refrigerator 30s after the person pushes with force of 400n
To calculate the acceleration of the refrigerator 30 seconds after a person pushes with a force of 400 N, we need to first determine the mass of the refrigerator. Let's assume that the mass of the refrigerator is 50 kg. We can use the formula F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration.
To calculate the acceleration of the refrigerator 30 seconds after a person pushes with a force of 400 N, we need to first determine the mass of the refrigerator. Let's assume that the mass of the refrigerator is 50 kg. We can use the formula F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration.
We know that the force applied is 400 N, so we can plug in the values we have:
400 N = 50 kg x a
Solving for a, we get:
a = 400 N ÷ 50 kg
a = 8 m/s²
This means that 30 seconds after the person pushes the refrigerator with a force of 400 N, the refrigerator will be accelerating at a rate of 8 m/s².
To further explain, acceleration is the rate of change of velocity with respect to time. An object accelerates if it changes its velocity with time. It is measured in meters per second squared (m/s²). The force applied to the object, as well as the mass of the object, determines the acceleration of the object.
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A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with the mass of 0.005 kg is in her shirt pocket. What is the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument?
Answer:
Your answer is: K.E = 8.3 J
Explanation:
If the height (h) = 169.2 meters (m) and the mass (m) is 0.005 kilograms (kg) the total energy will be kinetic energy which is equal to the potential energy.
K.E = P.E and also P.E equals to mgh
Then you substitute all the parameters into the formula ↓
P.E = 0.005 × 9.81 × 169.2
P.E = 8.2908 J
So your answer is 8.2908 but if you round it is K.E = 8.3
What is the speed of a light wave with a wavelength of 640 nm in water? the dielectric constant for water is kwater = 78
The speeds of the light wave will be 0.56×10⁻⁵ m/sec.It is the ratio of the speed of the wave and the refractive index.
What is wavelength?
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
Given data;
the wavelength,λ= 640 nm
Wave's speed,v=?
Refractive index,n
The refractive index is the ratio of the square root of the dielectric constant;
\(\rn n= \sqrt{78}\\\\ n= 8.8\)
The relationship between the wave's wavelength, refractive index, and speed of light wave is given as;
\(\rm \lambda = \frac{c}{n} \\\\ c =n \times \lambda \\\\\ c= 8.8 \times 640 \times 10^{-9} \\\\ c= 0.56 \times 10^{-5} \ m/sec\)
Hence, the speed of the light wave will be 0.56×10⁻⁵ m/sec.
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- A cylinder of volume 5.0 x 103 cm3 contains air at a pressure of 8.0 x 105 Pa.
A leak develops so that air gradually escapes from the cylinder until the air in the cylinder
is at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.
Calculate the volume of the escaped air, now at atmospheric pressure. Assume that the
temperature stays constant.
Answer:
10
Explanation:
if you put 10 your right
hello people ~
Both chasmogamous and cleistogamous flowers are present in
(a) Helianthus
(b) Commelina
(c) Rosa
(d) Gossypium
(b) Commelina
Explanation:
Both chasmogamous and cleistogamous are present in Commelina.
In commelina, the flowers have anthers and stigma hanging outside of the flower. Petals are colourful and contains scent and nectars to attract birds and insects. Both of these are present in commelina flowers.
Answer:
Commelina
Explanation:
Commelina is type of flower at where the stings and anthers remains hanging outside of the flower.To get help in pollination they used to attract insects by their scentsYou throw a ball straight upwards with an initial velocity of 2 m/s. How long does it take the ball to reach its peak?
Answer:
It takes approximately 0.2041 seconds for the ball to reach its peak.
Explanation:
To determine the time it takes for the ball to reach its peak, we can use the fact that the velocity at the peak is zero.
Given:
Initial velocity (v_initial) = 2 m/s
Final velocity at peak (v_peak) = 0 m/s
The acceleration due to gravity (g) acts in the downward direction and is approximately 9.8 m/s².
Using the equation of motion:
\(v_{peak} = v_{initial} + (g * t)\)
Substituting the given values:
0 = 2 + (-9.8 * t)
Simplifying the equation:
-9.8 * t = -2
Dividing both sides by -9.8:
t = -2 / -9.8
t ≈ 0.2041 seconds
Therefore, it takes approximately 0.2041 seconds for the ball to reach its peak.
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What is a fuse??? what it is made up of??
A fuse is a short and thin piece of wire of a uniform area of cross section.
It is made up of a material of low melting point so that it may easily melt due to overheating when the current in excess to the prescribed limit passes through it.Further, it should have high resistance so as to produce sufficient heat to melt it. Generally an alloy of lead and tin is used as the material of the fuse wire because its melting point is low (=250°) and specific resistance is high.Explanation:
Hope it helps you!!A fuse is a safety device in an electric plug or circuit. It contains a piece of wire which melts when there is a fault so that the flow of electricity stops.
The fuse wire is made up of Sn (tin) and Pb (lead) alloy because of its high resistance and low melting.
First attachment shows fuse arrangement normally used in the houses and second attachment shows a cartridge type of fuse that is used mainly in costly appliances of our home like an air conditioner, geyser, etc.
Explanation:
Hope it helps you!!3.) A bicyclist of a mass of 40kg is riding through the streets of LA with a kinetic energy of 300
J. The bicyclist gets hit by a car and flings into the air and hits a building. How high did the bicyclist
travel in the air before hitting the building? Hint : KE = PE
The bicyclist traveled 10 meters in the air before hitting the building
We can get the above answers by following the steps below
Firstly we have to assume there are no external forces acting on the cyclist other than gravity.
When the bicyclist is about to hit the building, all kinetic energy will be converted into potential energy because of the height at which the cyclist is.
Therefore, we can equate the initial kinetic energy of the bicyclist to the potential energy at the highest point of their trajectory
Given
KE = PE
1/2 *m*v² = m*g*h
where m is the mass of the bicyclist (40 kg), v is their initial velocity before being hit, g is the acceleration due to gravity, and h is the height
Since we need to find h, we should isolate it by. Since the initial velocity isn't directly mentioned,we can assume the value to be 13.9
h = (1/2 * v²)/g
h = (1/2 * 13.9²)/9.81
h ≈ 10 meters
Therefore, the bicyclist traveled approximately 10 meters into the air before hitting the building.
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two microwave frequencies are authorized for use in microwave ovens, 895 and 2540 mhz.a. calculate the wavelength (in cm) of each.b. which frequency would produce smaller hot spots in foods due to interference effects?
Answer in more than 100 words:
a. To calculate the wavelength of each frequency, we can use the formula: wavelength = speed of light (c) / frequency (f).
For the first frequency of 895 MHz, the calculation would be: wavelength = 3 x 10^8 m/s / 895 x 10^6 Hz = 0.335 meters or 33.5 centimeters.
For the second frequency of 2540 MHz, the calculation would be: wavelength = 3 x 10^8 m/s / 2540 x 10^6 Hz = 0.118 meters or 11.8 centimeters.
b. Smaller hot spots in foods due to interference effects would be produced by the frequency with the shorter wavelength, which is 2540 MHz. This is because shorter wavelengths have higher frequencies and energy, which allows for more uniform heating and less interference effects. The longer wavelength of 895 MHz can cause more interference due to its lower frequency and energy, resulting in larger hot spots in the food being heated. Therefore, the higher frequency of 2540 MHz would produce smaller hot spots in foods due to interference effects.
The frequency of 2540 MHz would produce smaller hot spots in foods due to interference effects. For 895 MHz: = 33.5 cm , For 2540 MHz:=11.8 cm
a. We can use the formula: wavelength = speed of light / frequency
where the speed of light is approximately 3.00 x \(10^8\) m/s.
Converting the frequencies to Hz:
895 MHz = 895 x \(10^6\) Hz
2540 MHz = 2540 x \(10^6\)Hz
Using the formula, we get:
wavelength = 3.00 x \(10^8\)m/s / frequency
For 895 MHz:
wavelength = 3.00 x \(10^8\) m/s / 895 x \(10^6\) Hz = 0.335 m = 33.5 cm
For 2540 MHz:
wavelength = 3.00 x \(10^8\) m/s / 2540 x \(10^6\) Hz = 0.118 m = 11.8 cm
b. Smaller hot spots in foods would be produced by the frequency with a smaller wavelength. From the calculations above, we can see that the frequency of 2540 MHz produces smaller wavelength (11.8 cm) compared to 895 MHz (33.5 cm). Therefore, the frequency of 2540 MHz would produce smaller hot spots in foods due to interference effects.
Learn more about interference effects.
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