help ?
The net of a right circular cylinder is shown.

net of a cylinder where the radius of each circle is labeled 5 meters and the height of the rectangle is labeled 8 meters

What is the surface area of the cylinder? Use π = 3.14 and round to the nearest whole number.

220 m2
283 m2
408 m2
628 m2

Answer:

6 times a larger number (so 6y) is equal (=) to the sum of a smaller number and 18 (x+18)

6y = x+18

Twice of larger number (2y) and the difference of smaller number (x) is equal to 6

2y - x = 6

solve for y. Divide both terms for 6.

6y/6 = 1/6x+3

y = 1/6x+3

second equation solve for y

move x to the right of equal

2y = x + 6

y = 1/2x + 3

Answer:

C

Step-by-step explanation:

I took the test 2021

The values of the trigonometric functions with the given constraints are:

sin(theta) = 3/5

cos(theta) = -8/17

tan(theta) = -51/40

cot(theta) does not have a solution

sec(theta) = -17/8

csc(theta) does not have a solution.

Simply put, trigonometric functions—also referred to as circular functions—are the functions of a triangle's angle.

Given the constraints:

tan(theta) = -15/8

sin(theta) > 0

cos(theta) = 8/17

tan(theta) < 0

sin(theta) = 3/5

theta lies in Quadrant II

cos(theta) = -4/5

theta lies in Quadrant III

cot(theta) = -3

cos(theta) > 0

csc(theta) = 4

cos(theta) < 0

Using these constraints, we can find the values of the trigonometric functions:

1. sin(theta): Since sin(theta) > 0 and theta lies in Quadrant II, sin(theta) = 3/5.

2. cos(theta): Since cos(theta) = 8/17 and cos(theta) < 0, we can multiply both the numerator and denominator by -1 to get cos(theta) = -8/17.

3. tan(theta): We know that tan(theta) = -15/8 and tan(theta) < 0. Since tan(theta) = sin(theta)/cos(theta), we have tan(theta) = (3/5) / (-8/17) = -51/40.

4. cot(theta): We are given that cot(theta) = -3. Since cot(theta) = 1/tan(theta), we have -3 = 1 / (-15/8), which simplifies to -3 = -8/15. This is not true, so there is no solution for this constraint.

5. sec(theta): We can find sec(theta) by taking the reciprocal of cos(theta), which gives sec(theta) = -17/8.

6. csc(theta): We are given that csc(theta) = 4. Since csc(theta) = 1/sin(theta), we have 4 = 1 / (3/5), which simplifies to 4 = 5/3. This is not true, so there is no solution for this constraint.

In summary, the values of the trigonometric functions with the given constraints are:

sin(theta) = 3/5

cos(theta) = -8/17

tan(theta) = -51/40

cot(theta) does not have a solution

sec(theta) = -17/8

csc(theta) does not have a solution.

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The translation of the polygon is 8 units to the left.

Since,

A translation moves a shape up, down, or from side to side, but it has no effect on its appearance. A transformation is an example of translation. A transformation is a method of changing a shape's size or position. Every point in the shape is translated in the same direction by the same amount.

A translation in the coordinate plane moves every point on a figure a given distance in a given direction. The position of any point (x, y) on the figure changes to (x + a, y + b), where a and b are real numbers.

Given data ,

Let the polygon be represented as ABCD

Now , the coordinates of the polygon is given as

The coordinate of A = A ( 1 , 5 )

The coordinate of B = B ( 3 , 1 )

The coordinate of C = C ( 7 , 1 )

The coordinate of D = D ( 5 , 5 )

Now , the translated polygon is having the coordinates as

The coordinate of A' = A' ( -7 , 5 )

The coordinate of B' = B' ( -5 , 1 )

The coordinate of C' = C' ( -1 , 1 )

The coordinate of D' = D' ( -3 , 5 )

So , the translation rule is ( x , y ) → ( x - 8 , y )

And , the figure is translated 8 units to the left

Hence , the translation is 8 units to the left

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The length of side b is 56m, angle A is 45°, and angle C is 67°.

In the given triangle with side lengths a = 74m, b ≈ 56m, and c = 36m, the length of side b is approximately 56m.

To solve the triangle, we can use the Law of Cosines and the fact that the sum of angles in a triangle is 180 degrees. Given angle B = 67°51', we have:

Using the Law of Cosines, we have:

b² = a² + c² - 2ac * cos(B)

Substituting the known values:

b² = 74² + 36² - 2 * 74 * 36 * cos(67°51')

Calculating the value of b:

b ≈ √(74² + 36² - 2 * 74 * 36 * cos(67°51'))

b ≈ 55.92m (rounded to the nearest whole number, b ≈ 56m)

Using the Law of Cosines again, we have:

cos(A) = (b² + c² - a²) / (2 * b * c)

Substituting the known values:

cos(A) = (56² + 36² - 74²) / (2 * 56 * 36)

Calculating the value of A:

A = cos⁻¹((56² + 36² - 74²) / (2 * 56 * 36))

A ≈ 45° (rounded to the nearest whole number)

Using the fact that the sum of angles in a triangle is 180 degrees:

C = 180° - A - B

Substituting the known values:

C ≈ 180° - 45° - 67°51'

Calculating the value of C:

C ≈ 67°9' (rounded to the nearest whole number, C ≈ 67°)

Therefore, in the given triangle, the length of side b is approximately 56m, angle A is approximately 45°, and angle C is approximately 67°.

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Answer:

A

Step-by-step explanation:

The opposite sides of a parallelogram are congruent, then

WT = VU = 21.3 → A

Answer:

length = 20 feet

Step-by-step explanation:

the area (A) of a rectangle is calculated as

A = length × width

let width be w , then length is 4w

given A = 100 , then

4w × w = 100

4w² = 100 ( divide both sides by 4 )

w² = 25 ( take square root of both sides )

\(\sqrt{w^2}\) = \(\sqrt{25}\)

w = 5

width = 5 feet and length = 4 × 5 = 20 feet

Step-by-step explanation:

It is a square so the sides are all equal

area = side  X side

      =   6 mm  X 6 mm = 36 mm^2

The boundary lines are y > -3x + 4: dotted line and  y <= 8x + 1: solid line

From the question, we have the following parameters that can be used in our computation:

y > -3x + 4

y <= 8x + 1

The boundary line for the inequality "<" is a dotted line, which means that the endpoint is not included in the solution set.

The boundary line for the inequality ">=" is a solid line, which means that the endpoint is included in the solution set.

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Answer:  2 • (y2 + 11y + 14)

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "y2"   was replaced by   "y^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((8•(y2))+7y)+4)-(3•((2y2-5y)-8))

STEP

2

:

Trying to factor by splitting the middle term

2.1     Factoring  2y2-5y-8  

The first term is,  2y2  its coefficient is  2 .

The middle term is,  -5y  its coefficient is  -5 .

The last term, "the constant", is  -8  

Step-1 : Multiply the coefficient of the first term by the constant   2 • -8 = -16  

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   -5 .

     -16    +    1    =    -15  

     -8    +    2    =    -6  

     -4    +    4    =    0  

     -2    +    8    =    6  

     -1    +    16    =    15  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

2

:

 (((8•(y2))+7y)+4)-3•(2y2-5y-8)

STEP  

3

:

Equation at the end of step

3

:

 ((23y2 +  7y) +  4) -  3 • (2y2 - 5y - 8)

STEP

4

:

STEP

5

:

Pulling out like terms

5.1     Pull out like factors :

  2y2 + 22y + 28  =   2 • (y2 + 11y + 14)  

Trying to factor by splitting the middle term

5.2     Factoring  y2 + 11y + 14  

The first term is,  y2  its coefficient is  1 .

The middle term is,  +11y  its coefficient is  11 .

The last term, "the constant", is  +14  

Step-1 : Multiply the coefficient of the first term by the constant   1 • 14 = 14  

Step-2 : Find two factors of  14  whose sum equals the coefficient of the middle term, which is   11 .

     -14    +    -1    =    -15  

     -7    +    -2    =    -9  

     -2    +    -7    =    -9  

     -1    +    -14    =    -15  

     1    +    14    =    15  

     2    +    7    =    9  

     7    +    2    =    9  

     14    +    1    =    15  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Answer:

Same lol

Step-by-step explanation:

Answer:

Bored, but I'm good :) how are you?

We can see that point (-2, 4) lies inside the shaded region, and hence, it is a solution to the given system. Therefore, the correct option is D. (-2, 4).

The given system of equations is:

2x + 3y > 6 (1)3x + 2y < 6 (2)

In order to identify the solutions to the given system, we will first solve each of the given inequalities separately.

Solution of the first inequality:

2x + 3y > 6 ⇒ 3y > –2x + 6 ⇒ y > –2x/3 + 2

The graph of the first inequality is shown below:

As we can see from the above graph, the region above the line y = –2x/3 + 2 satisfies the first inequality.

Solution of the second inequality:3x + 2y < 6 ⇒ 2y < –3x + 6 ⇒ y < –3x/2 + 3

The graph of the second inequality is shown below:

As we can see from the above graph, the region below the line y = –3x/2 + 3 satisfies the second inequality.

The solution to the system is given by the region that satisfies both the inequalities, which is the shaded region below:

We can see that point (-2, 4) lies inside the shaded region, and hence, it is a solution to the given system.

Therefore, the correct option is D. (-2, 4).

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The given system of inequalities doesn't have a solution among the provided options. In addition, the provided solutions seem to be incorrect because they consist of three numbers whereas the system is in two variables.

To solve this system, we will begin by looking at each inequality separately. Starting with 2x + 3y > 6, we need to find the values of x and y that satisfy this inequality. Similarly, for the second inequality, 3x + 2y < 6, we need to find the values of x and y that meet this requirement. A common solution for both inequalities would be the solution of the system. Yeah, None of the given options satisfy both inequalities, so we can't find a common solution in the options provided.

It's important to notice that the values in the options are trios while the system is in two variables (x and y). Therefore, none of these options can serve as a solution for the system. The coordinates should only contain two values (x, y), one value for x and another for y.

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Answer The small triangles each have an area of 12m^2 and the big rectangle had an area of 80m^2. This would mean that the combined area is 104m^2

Step-by-step explanation: The rectangle shape can be found by multiplying 8 by 10 to get 80m^2. The two triangles can be found by multiplying 4 (half of 8) by 6 and then dividing it by two. This would mean that the small triangles each have an area of 12.

(i) The graph is attached below. (ii) the minimum value of the function is h = 30, when x = 5. (iii) the horizontal distance traveled by the rider between the two splashes is 2 × 9 m = 18 m.

Acceleration is a physical quantity that measures the rate at which the velocity of an object changes over time. It is a vector quantity, meaning that it has both magnitude and direction.

Acceleration is defined as the change in velocity of an object divided by the time interval over which the change occurred. It is typically measured in meters per second squared (m/s²) in the metric system, or in feet per second squared (ft/s²) in the imperial system.

If the velocity of an object is increasing, its acceleration is said to be positive. If the velocity is decreasing, the acceleration is said to be negative or deceleration. If the velocity is constant, there is no acceleration.

(i) Using the given scale, we can plot the graph of h = 1.2x² - 12x + 30 for 0 ≤ x ≤ 10 as follows:

Parabolic graph is attached below.

(ii) The constant term 30 in the equation represents the minimum height of the pirate ship ride above ground level. This is because the equation is in the form of a quadratic function in standard form, y = ax² + bx + c, where the vertex of the parabola is at the point (-b/2a, c - b²/4a). In this case, the vertex is at (5, 0), which means that the minimum value of the function is h = 30, when x = 5.

(iii) We are given that a rider is 19.2 m above ground level, which means that h = 19.2. We can substitute this value into the equation and solve for x:

19.2 = 1.2x² - 12x + 30

1.2x² - 12x + 10.8 = 0

x² - 10x + 9 = 0

(x - 1)(x - 9) = 0

Therefore, the rider is at a height of 19.2 m when he is either 1 m or 9 m away from the starting point. Since the rider swings back and forth, the distance between the two splashes is twice the distance from the starting point to either splash. Therefore, the horizontal distance traveled by the rider between the two splashes is:

2 × 9 m = 18 m

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Answer:

ok

Step-by-step explanation:

Answer:

Elena made 10 batches.

Step-by-step explanation:

1 batch uses 2/3 cup

Elena used 6 2/3 cup

The number of batches is the quotient of 6 2/3 and 2/3.

We need to divide 6 2/3 by 2/3. First, we convert 6 2/3 into a fraction.

6 2/3 ÷ 2/3 = 20/3 ÷ 2/3 = 20/3 × 3/2 = 10

Answer: Elena made 10 batches.

Answer:

10

Step-by-step explanation:

2/3 for 1 cup if he used 6 2/3 of sugar then its 10.

if you times 2/3 by 10 its 6.66 and 6.66 is 2/3

1/3=33

2/3=66

3/3=100

Given:

The distance traveled in 10 seconds is 450 feet.

To find the distance traveled in 1 minute:

In 10 seconds, the distance is 450 feet.

In 20 seconds the distance will be,

In 30 seconds the distance will be,

In 40 seconds the distance will be,

In 50 seconds the distance will be,

In 60 seconds the distance will be,

Hence, the distance traveled in 1 minute is 2700 feet.

So, the table becomes,

The simplified expression for f(x+h) is, f(x+h) = x^3 + 3x^2h + 3xh^2 + h^3 - 5x - 5h + 8. This corresponds to option d in your list of choices.

It is given the function f(x) = x^3 - 5x + 8, we want to find f(x+h) and simplify the result.

1. Replace x with (x+h) in the function f(x) = x^3 - 5x + 8.
2. f(x+h) = (x+h)^3 - 5(x+h) + 8

Now, we will simplify the expression,

3. Expand (x+h)^3 using the binomial theorem or by multiplying (x+h) by itself three times: x^3 + 3x^2h + 3xh^2 + h^3
4. Distribute -5 to the terms inside the parenthesis: -5x - 5h
5. Combine the terms obtained in steps 3 and 4 with the constant 8: x^3 + 3x^2h + 3xh^2 + h^3 - 5x - 5h + 8

So, the simplified expression for f(x+h) is,

f(x+h) = x^3 + 3x^2h + 3xh^2 + h^3 - 5x - 5h + 8

This corresponds to option d in your list of choices.

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Answer:

4846.59

Step-by-step explanation:

21/2= 10.5 as your radius

10.5^3(3.14)(4/3) = 4846.59

Answer:

Uh dude their are no questions??

Step-by-step explanation:

The trapezoidal rule is a numerical integration method that uses trapezoids to estimate the area under a curve. The trapezoidal rule can be used for both definite and indefinite integrals. The trapezoidal rule approximation, Tn, to the integral sin r dz is given by:

Tn = (b-a)/2n[f(a) + 2f(a+h) + 2f(a+2h) + ... + 2f(b-h) + f(b)]where h = (b-a)/n. To determine how large n should be so that Tn is accurate to within 0.00001, we can use the error bound given in Section 5.9 of the course text. According to the error bound, the error, E, in the trapezoidal rule approximation is given by:E ≤ ((b-a)³/12n²)max|f''(x)|where f''(x) is the second derivative of f(x). For the integral sin r dz, the second derivative is f''(r) = -sin r. Since the absolute value of sin r is less than or equal to 1, we have:max|f''(r)| = 1.

Substituting this value into the error bound equation gives:E ≤ ((b-a)³/12n²)So we want to choose n so that E ≤ 0.00001. Substituting E and the given values into the inequality gives:((b-a)³/12n²) ≤ 0.00001Simplifying this expression gives:n² ≥ ((b-a)³/(0.00001)(12))n² ≥ (b-a)³/0.00012n ≥ √(b-a)³/0.00012Now we just need to substitute the values of a and b into this expression. Since we don't know the upper limit of integration, we can use the fact that sin r is bounded by -1 and 1 to get an upper bound for the integral.

For example, we could use the interval [0, pi/2], which contains one full period of sin r. Then we have:a = 0b = pi/2Plugging in these values gives:n ≥ √(pi/2)³/0.00012n ≥ 5073.31Since n must be an integer, we round up to the nearest integer to get:n = 5074Therefore, we should choose n to be 5074 so that the trapezoidal rule approximation, Tn, to the integral sin r dz is accurate to within 0.00001.

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The smallest values that appear in the sequence are 2/3 and 1. Therefore, the limit inferior of {x_n} is 2/3.

To find the limit superior and limit inferior of the sequence {x_n}, we need to analyze the behavior of the sequence as n approaches infinity.

First, let's write out the terms of the sequence:
\(x_1 = 1 + (-1)^1 + 2/1 = 1 - 1 + 2 = 2x_2 = 1 + (-1)^2 + 2/2 = 1 + 1 + 1 = 3/2x_3 = 1 + (-1)^3 + 2/3 = 1 - 1 + 2/3 = 2/3x_4 = 1 + (-1)^4 + 2/4 = 1 + 1 + 1/2 = 3/2...\\\)
We can observe that for odd values of n, x_n alternates between 2 and 2/3, and for even values of n, x_n alternates between 3/2 and 1. As n increases, the terms of the sequence oscillate between these four values.

The limit superior, denoted as lim sup(x_n), is the largest limit point of the sequence. In this case, we can see that the largest values that appear in the sequence are 2 and 3/2. Therefore, the limit superior of {x_n} is 2.

The limit inferior, denoted as lim inf(x_n), is the smallest limit point of the sequence. In this case, the smallest values that appear in the sequence are 2/3 and 1. Therefore, the limit inferior of {x_n} is 2/3.

To summarize:
lim sup(x_n) = 2
lim inf(x_n) = 2/3.

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The limit superior of the sequence is 18, and the limit inferior of the sequence is 2.

To find the limit superior and limit inferior of the sequence {x_n}, where x_n = 1 + (-1)^n + 2^(n/1), we need to determine the behavior of the sequence as n approaches infinity.

First, let's evaluate the individual terms of the sequence for some values of n:

When n = 1,

x_1 = 1 + (-1)^1 + 2^(1/1)

= 1 - 1 + 2

= 2

When n = 2,

x_2 = 1 + (-1)^2 + 2^(2/1)

= 1 + 1 + 4

= 6

When n = 3,

x_3 = 1 + (-1)^3 + 2^(3/1)

= 1 - 1 + 8

= 8

When n = 4,

x_4 = 1 + (-1)^4 + 2^(4/1)

= 1 + 1 + 16

= 18

We observe that the terms of the sequence alternate between values of 2 and 18. Thus, the sequence does not converge to a single value as n goes to infinity.

To find the limit superior and limit inferior, we consider the subsequences of even and odd terms separately.

For the even terms (n = 2, 4, 6, ...), the terms of the sequence are always 18. Thus, the limit superior of the sequence is 18.

For the odd terms (n = 1, 3, 5, ...), the terms of the sequence are always 2. Thus, the limit inferior of the sequence is 2.

Therefore, the limit superior of the sequence is 18, and the limit inferior of the sequence is 2.

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It is unlikely that the projected rebounds in 15 shots will actually happen.

Total shots fired equals 10.

To find that there were 15 shots total.

Consider S to be the likelihood that your team will rebound and miss a shot.

P(S) = Number of rebounds / Total Number of outcomes

P(S) = 7/15

P(S) = 0.46

Consequently, it is unlikely that the projected rebounds in 15 shots will actually happen.

Thus, it is unlikely that the projected rebounds in 15 shots will actually happen.

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The complete question is-

During a basketball game, you record the number of rebounds from missed shots for each team.  How many rebounds should your team expect to have in 15 missed shots?

Picture for question is attached.

Answer:

8640in²

Step-by-step explanation:

A = I * W * H

A= 27*16*20

A=8640in²

The probability of the low bid on the next intrastate shipping contract falling within the range of 20 to 25 thousand dollars can be determined by calculating the probability density function for a uniform distribution.

In this case, the low bids for intrastate shipping contracts are uniformly distributed between 20 and 25 thousand dollars. Since it is a uniform distribution, the probability density function (PDF) is constant within this range and zero outside of it. To find the probability that the next low bid falls within this range, we need to calculate the area under the PDF curve within the range of 20 to 25.

The PDF of a uniform distribution is given by 1 divided by the range of the distribution. In this case, the range is 25 - 20 = 5 thousand dollars. Therefore, the PDF is 1/5. To calculate the probability, we need to find the area under the PDF curve within the range. The area of a rectangle with width 5 and height 1/5 is simply 5 * (1/5) = 1. Therefore, the probability that the low bid on the next intrastate shipping contract falls within the range of 20 to 25 thousand dollars is 1, or 100%.

In conclusion, based on the information provided, the probability that the low bid on the next intrastate shipping contract falls within the range of 20 to 25 thousand dollars is 100%. This is because the low bids are uniformly distributed in this range, and the probability density function is constant within this interval.

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0.2 * 12 = 2.4

2.4 + 12 = $14.4

please give brainliest

Answer:

-2/3 is the right answer

Answer: it’s 8 if that 29 is supposed to be a 39 otherwise i don’t know

Step-by-step explanation:

Searching it up gives your answer right then and there.

The first record of zero was founded in Mesopotamia 3 B.C

Inventor:

The Mayans invented it independently circa 4 A.D

Then it was only then during mid-fifth century it spread to Cambodia

Near the end of seventh century it went to China, and Islamic counties at the end of the eighth century.

(Correct me if I'm wrong not all website's are reliable,So sorry if I'm wrong.)