help me, please i need help

Answer:

98,100,A

Plz mark me brainliest.

Step-by-step explanation:

Answer:

2006

Step-by-step explanation:

Trust

The series converges for x in the interval [-1, 1), with the left end included and the right end not included.

To find all the values of x for which the given series converges, we will use the Ratio Test. The series is given by:

\(\sum_{n=1}^\infty \frac{(4 x)^n}{n^{8}}\)

Let's apply the Ratio Test:

\(\lim_{n \to \infty} \frac{\frac{(4 x)^{n+1}}{(n+1)^{8}}}{\frac{(4 x)^n}{n^{8}}} = \lim_{n \to \infty} \frac{n^8 (4x)^{n+1}}{(n+1)^8 (4x)^n}\)

Simplify the expression:

\(\lim_{n \to \infty} \frac{4x n^8}{(n+1)^8}\)

Now, we need to find the values of x for which this limit is less than 1, as the Ratio Test states that the series converges if this limit is less than 1.

\(\frac{4x}{(1+\frac{1}{n})^8} < 1\)

Divide both sides by 4:

\(x < \frac{1}{(1+\frac{1}{n})^8}\)

As n approaches infinity, the term \(\frac{1}{n}\) approaches 0:

\(x < \frac{1}{(1+0)^8} = \frac{1}{1}\)

So, for the series to converge, x must be less than 1.

The series is convergent from x = -1, left end included (Y) to x = 1, right end not included (N).

Your answer: The series converges for x in the interval [-1, 1), with the left end included and the right end not included.

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The sample means are Mean(Y) = 61.4 and Mean(X) = 15, the sample variances are Variance(Y) ≈ 1124.89 and Variance(X) ≈ 2.67, the sample standard deviations are Standard deviation(Y) ≈ 33.56 and Standard deviation(X) ≈ 1.63, the sample covariance is Covariance(X, Y) ≈ -131.69, and the sample correlation is Correlation(X, Y) ≈ -0.77.

a. To find the sample means, variances, and standard deviation, we can use the following formulas:

Sample mean of income (Y):

Mean(Y) = (100 + 65 + 47 + 112 + 34 + 85 + 92 + 83 + 67 + 29) / 10 = 614 / 10 = 61.4

Sample mean of education (X):

Mean(X) = (18 + 14 + 14 + 16 + 12 + 16 + 18 + 14 + 16 + 12) / 10 = 150 / 10 = 15

Sample variance of income (Y):

Variance(Y) = [(100 - 61.4)^2 + (65 - 61.4)^2 + (47 - 61.4)^2 + (112 - 61.4)^2 + (34 - 61.4)^2 + (85 - 61.4)^2 + (92 - 61.4)^2 + (83 - 61.4)^2 + (67 - 61.4)^2 + (29 - 61.4)^2] / 9 ≈ 1124.89

Sample variance of education (X):

Variance(X) = [(18 - 15)^2 + (14 - 15)^2 + (14 - 15)^2 + (16 - 15)^2 + (12 - 15)^2 + (16 - 15)^2 + (18 - 15)^2 + (14 - 15)^2 + (16 - 15)^2 + (12 - 15)^2] / 9 ≈ 2.67

Sample standard deviation of income (Y):

Standard deviation(Y) = √Variance(Y) ≈ √1124.89 ≈ 33.56

Sample standard deviation of education (X):

Standard deviation(X) = √Variance(X) ≈ √2.67 ≈ 1.63

b. To find the sample covariance and correlation, we can use the following formulas:

Sample covariance:

Covariance(X, Y) = [(18 - 15)(100 - 61.4) + (14 - 15)(65 - 61.4) + (14 - 15)(47 - 61.4) + (16 - 15)(112 - 61.4) + (12 - 15)(34 - 61.4) + (16 - 15)(85 - 61.4) + (18 - 15)(92 - 61.4) + (14 - 15)(83 - 61.4) + (16 - 15)(67 - 61.4) + (12 - 15)(29 - 61.4)] / 9 ≈ -131.69

Sample correlation:

Correlation(X, Y) = Covariance(X, Y) / (Standard deviation(X) * Standard deviation(Y)) ≈ -131.69 / (1.63 * 33.56) ≈ -0.77

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Correct question-

Consider the following random sample of income and education: Income(Y) Education(X) 100 18 65 14 47 14 112 16 34 12 85 16 92 18 83 14 67 16 29 12 a. Find sample means, variances and standard deviation. b. Find sample covariance and correlation.

False. The tangent line to a graph at a point is defined as the line that touches the graph at that point and has the same slope as the graph at that point. It does not necessarily touch the graph at only one point.

The statement is incorrect. The tangent line to a graph at a point is defined as the line that touches the graph at that point and has the same slope as the graph at that point. In general, a tangent line can touch the graph at multiple points or even coincide with a portion of the graph for a certain interval.

The key characteristic of a tangent line is that its slope matches the slope of the graph at the point of tangency. Therefore, the tangent line is not limited to touching the graph at only one point.

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The applicant must be able to type at least 30 words per minute in English. A candidate will receive extra points on the CPCT scorecard if his or her speed typing ability exceeds the minimal requirement.

Words per minute :

Words per minute, often known as wpm or WPM, is a measurement of the number of words processed in a minute and is frequently used to gauge the speed of typing, reading, or sending and receiving Morse code. Since words can vary in length, it is common practice to standardize the length of a "word" in English to five characters or keystrokes, including spaces and punctuation, for the purposes of measuring text entry. For instance, using this method with plain English text would count the phrases "I run" and "let's discuss" as two words instead of one each.

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For the given Problem, The correct option giving Rachel's height in inches is (D) 70.

A z-score, also called standard score, can be used to measure- how much an observation or data point deviates from the mean of the distribution. By Subtracting the mean of the given distribution from the observation and after that dividing it by the standard deviation will give us the z-score for given observations.

Given:

Mean height (μ) = 65 inches

Standard deviation (σ) = 2 inches

Percentile (P) = 99%

The Z-score, commonly known as the standard score, helps in quantifying how much a data point deviates from the mean. It can be computers as:

\(Z = (X - \mu) / \sigma\)

where X is the value of the data point.

We can rearrange the equation to solve for X:

\(X = Z * \sigma + \mu\)

We may use a regular normal distribution table or a Z-table to obtain the Z-score corresponding to the 99th percentile. The Z-score for the 99th percentile is roughly 2.33.

\(X = 2.33 * 2 + 65\\\\X = 4.66 + 65\\\\X = 69.66\\\\{X}\;\approx70\; inches\)

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The equation to represent the total amount of money Richard make in an hour is  y = 9 + 2x    .

In the question ,

it is given that ,

Richard is working at a retail shop ,

let the number of membership sold in an hour be = "x" ,

let the total amount of money earned be = "y" .

amount of money earned in hour = $9 ,

amount that he gets for each membership sold = $2 .

So , According to the question ,

the equation that represent the given situation is given as

y = 9 + 2x

Therefore , the equation for the situation is y = 9 + 2x .

The given question is incomplete the complete question is

Richard works at a retail shop. he makes $9 an hour, plus $2 for each membership he sells. let x represent the number of memberships sold and y represent the total amount of money he will make in an hour. write an  equation represents this situation ?

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Answer:

D

Step-by-step explanation:

surface area of cylinder

=(area of base)×2 + (area of curved surface)

\(=(\frac{20}{2} )^{2} \pi\)× 2 + \(20\pi\) × 25

=2 × \(\pi\) × \(10^{2}\) + 2 × \(\pi\) × 10 × 25

Answer:

y=9x

Step-by-step explanation:

For these x's and y's, we can notice that y is always equal to 9 times the value of x. 0 equals 9 * 0, 9 equals 9 * 1, 18 equals 9 * 2, 27 equals 9 * 3, and 36 equals 9 * 4.

We have just shown that y equals 9 times x, which is just y=9*x, or y=9x.

The random process Y(t) is not wide-sense stationary (WSS) because the phase term, ϕ, is uniformly distributed between 0 and π/4. In a WSS process, the statistical properties, such as mean and autocorrelation, should be independent of time.

To determine if the random process Y(t) is wide-sense stationary (WSS), we need to examine its statistical properties. A WSS process has two main characteristics: time-invariance and finite second-order moments.

Let's analyze the given process: Y(t) = A sin(wet + ϕ), where A is the amplitude, ω is the angular frequency, et is the time, and ϕ is uniformly distributed between 0 and π/4.

1. Time-Invariance: A WSS process should exhibit statistical properties that are independent of time. In this case, the phase term ϕ is uniformly distributed between 0 and π/4. As time progresses, the phase term ϕ changes randomly, leading to time-dependent variations in the process Y(t). Therefore, the process is not time-invariant and does not satisfy the first condition for WSS.

2. Finite Second-Order Moments: A WSS process should have finite mean and autocorrelation functions. Let's examine the mean and autocorrelation of Y(t):

Mean: E[Y(t)] = E[A sin(wet + ϕ)] = A E[sin(wet + ϕ)]

Since ϕ is uniformly distributed between 0 and π/4, its expected value is E[ϕ] = (0 + π/4) / 2 = π/8.

E[Y(t)] = A E[sin(wet + ϕ)] = A E[sin(wet + π/8)]

The expected value of sin(wet + π/8) is not zero, and it varies with time. Therefore, the mean of Y(t) is time-dependent, violating the WSS condition.

Autocorrelation: R_Y(t1, t2) = E[Y(t1)Y(t2)] = E[A sin(wet1 + ϕ)A sin(wet2 + ϕ)]

Expanding this expression and taking expectations, we have:

R_Y(t1, t2) = A^2 E[sin(wet1 + ϕ)sin(wet2 + ϕ)]

The product of two sine terms can be expanded using trigonometric identities. The resulting expression will involve cosines and sines of the sum and difference of the angles. Since ϕ is uniformly distributed, these trigonometric terms will also vary with time, making the autocorrelation function time-dependent.

Hence, we can conclude that the random process Y(t) is not wide-sense stationary (WSS) due to the time-dependent phase term ϕ, which violates the time-invariance property required for WSS processes.

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Answer:

red 420 times

Step-by-step explanation:

The results show red (18)  out of ( 18+10+7+19+6)

  18 / 60

18/60  *   1400 = 420 times

The area surface generated by revolving the curves about the x-axis is 9.87 square units

To find the surface area generated by revolving the curve y=sin(x) about the x-axis, we use the formula:

S = 2π∫aᵇ y ds

where a and b are the limits of integration, y is the function being revolved, and ds is the differential element of arc length.

To find ds, we use the formula:

ds = √(1 + (dy/dx)²) dx

where dy/dx is the derivative of y with respect to x.

Taking the derivative of y=sin(x), we get:

dy/dx = cos(x)

Substituting into the formula for ds, we get:

ds =√(1 + cos²(x)) dx

Now we can substitute y=sin(x) and ds into the formula for surface area and integrate from x=0 to x=π:

S = 2π \(\int\limits^\pi_0\) sin(x) √t(1 + cos²(x)) dx

This integral cannot be evaluated in terms of elementary functions, so we must use numerical methods to approximate the value. Using a numerical integration tool, we get:

S ≈ 9.87

Therefore, the surface area generated by revolving the curve y=sin(x) about the x-axis is approximately 9.87 square units.

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Venn diagram:

The percentage of students that studied mathematics = 25%
The percentage of students that studied electronics = 20%
The percentage of students that studied Communications = 55%
The percentage of students that studied both electronics and Communications subjects = 10%

P(studied Communications or electronics or both subjects)
= P(studied Communications) + P(studied electronics) - P(studied both electronics and Communications subjects)
= 55% + 20% - 10%
= 65%

Therefore, the probability that a student studied Communications or electronics or both subjects is 65%.

P(studied mathematics and Communications subjects)
= P(studied mathematics) × P(studied Communications)
= 25% × 55%
= 13.75%

Therefore, the probability that a student studied mathematics and Communications subjects is 13.75%.

Drawing a Venn diagram, we have 25% studying Mathematics (M), 20% studying Electronics (E), and 55% studying Communications (C).10% studied both Electronics and Communications.

Therefore, the percentages become as follows: M = 25% - 10% = 15% E = 20% - 10% = 10% C = 55%.

Part 2 - To obtain the probability that a student studied Communications or Electronics or both subjects

P(Communication or Electronics) = P(Communication) + P(Electronics) - P(Communication and Electronics) = 55% + 20% - 10% = 65%.

The probability that a student studied Communications or Electronics or both subjects is 65%.

Part 3 -To obtain the probability that a student studied Mathematics and Communications subjects,

P(Mathematics and Communications) = P(Mathematics) * P(Communications) = 25% * 55% = 13.75%.

The probability that a student studied Mathematics and Communications subjects is 13.75%.

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the intersection S₁ ∩ S₂ can be a subspace of Rⁿ, while the union S₁ U S₂ and the direct sum S₁ ⊕ S₂ are not necessarily subspaces of Rⁿ.

The union S₁ U S₂ is the set that contains all elements that belong to either S₁ or S₂. It is not necessarily a subspace of Rⁿ because it may not satisfy the closure properties of addition and scalar multiplication.

The intersection S₁ ∩ S₂ is the set that contains elements common to both S₁ and S₂. It can be a subspace of Rⁿ if it satisfies the closure properties of addition and scalar multiplication.

The direct sum S₁ ⊕ S₂ is not a set itself but rather a concept used to combine subspaces. It represents the set of all possible sums of vectors from S₁ and S₂. This concept is used to study the relationship between the two subspaces but is not a subspace itself.

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To get the total number of different ways, multiply 1,536 x 18 = 7,344.

7,344 different ways. Raven has 19 choices for drinks, 12 choices for appetizers, and 8 choices for desserts. The formula for calculating the number of different ways is 19 x 12 x 8 = 1,536. Since Raven needs to pick 3 drinks, 3 appetizers, and 2 desserts, the formula is 3 x 3 x 2 = 18. To get the total number of different ways, multiply 1,536 x 18 = 7,344.

The formula can be used to calculate the number of different ways to combine any number of choices. For example, if Raven had 24 choices for drinks, 15 choices for appetizers, and 7 choices for desserts, the formula would become 24 x 15 x 7 = 3,240. If Raven still had to pick 3 drinks, 3 appetizers, and 2 desserts, the total would be 3 x 3 x 2 = 18. Multiplying 3,240 x 18 = 57,720 different ways.

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Answer: A=448+196pi, P=60+14pi

Step-by-step explanation:

I'm assuming that the figures which appear to be semicircles are semicircles and that the quadrilateral is a rectangle.

The perimeter is 16 + 16 + 28 + (28/2)(pi)= 60+14pi

area is area of rectangle + area of semicircle

= (16)(28)+(pi)(14)(14)=448+196pi

Answer:

the second one I think, as it is clearer and makes more sense

The jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

The expression is given below.

⇒ 0.8 + 0.3

The sign of both terms are similar that is positive.

If the sign of the number is positive, then we move rightward. Similarly, if the sign of the number is negative, then we move leftward.

First, the jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

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Answer:

RQ + QS = RS

Hope this helps!

Answer:

x = 40

Step-by-step explanation:

x = 8 x 5

x = 40

that's it

Answer:

this is super easy...

u first rotate it 90° until the BC is downwards.

then rotate it one round until it comes to the way it was..that means once again BC down...hope it is clear...

Answer:

the probability that the member is neither a doctor not a lawyer​ is 60%

Step-by-step explanation:

Total: 60 members

Doctor: 15

Lawyer: 9

Lawyer + Doctor: 15 + 9 = 24

60 - 24 = 36 members are neither

36 / 60 = 0.6 x 100 = 60

the size of the union of the three sets is: |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C| = 3  × 24 million - 3 × 1.4 million + 1.2 million ≈ 69 million

A combination is a way of selecting a subset of objects from a larger set without regard to their order. The formula for the number of combinations of n objects taken r at a time is:
C(n, r) = n! / (r! ×  (n - r)!)
where n! means the factorial of n, which is the product of all positive integers up to n. For example, 5! = 5 ×  4 ×  3 ×  2 ×  1 = 120.
To apply this formula to our problem, we first need to count the total number of coins in the pile. Since there are at least 16 of each type, the minimum total is:
16 + 16 + 16 + 16 = 64
But there could be more coins of each type, so the total could be larger than 64. However, we don't need to know the exact number, only that it is large enough to allow us to choose 16 coins from it.
Using the formula for combinations, we can calculate the number of different collections of 16 coins that can be chosen from the pile:
C(64, 16) = 64! / (16! × (64 - 16)!) ≈ 1.1 billion
That's a very large number! It means there are over a billion ways to choose 16 coins from a pile that contains at least 16 of each type.
To answer the second part of the question, we need to count the number of collections that contain at least 3 coins of each type. One way to do this is to use the inclusion-exclusion principle, which says that the number of elements in the union of two or more sets is equal to the sum of their individual sizes minus the sizes of their intersections, plus the sizes of the intersections of all possible pairs, minus the size of the intersection of all three sets, and so on.
In this case, we can consider three sets:
- A: collections with at least 3 pennies
- B: collections with at least 3 nickels
- C: collections with at least 3 dimes
- D: collections with at least 3 quarters
The size of each set can be calculated using combinations:
|A| = C(48, 13) ≈ 24 million
|B| = C(48, 13) ≈ 24 million
|C| = C(48, 13) ≈ 24 million
|D| = C(48, 13) ≈ 24 million
Note that we have to choose 3 coins of each type first, leaving 4 coins to be chosen from the remaining 48 coins.
The size of the intersection of any two sets can be calculated similarly:
|A ∩ B| = C(43, 10) ≈ 1.4 million
|A ∩ C| = C(43, 10) ≈ 1.4 million
|A ∩ D| = C(43, 10) ≈ 1.4 million
|B ∩ C| = C(43, 10) ≈ 1.4 million
|B ∩ D| = C(43, 10) ≈ 1.4 million
|C ∩ D| = C(43, 10) ≈ 1.4 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 43 coins.
The size of the intersection of all three sets can also be calculated:
|A ∩ B ∩ C| = C(38, 7) ≈ 1.2 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 38 coins.

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Answer:

\(\frac{11}{15} \)

Step-by-step explanation:

\(\frac{1}{3} \) + \(\frac{2}{5} \)

The least common multiple of 3 and 5 is 15. Convert \(\frac{1}{3} \) and \(\frac{2}{5} \) to fractions with denominator 15.

\(\frac{5}{15} \) + \(\frac{6}{15} \)

Since \(\frac{5}{15} \) and \(\frac{6}{15} \) have the same denominator, add them by adding their numerators.

\(\frac{5+6}{15} \)

Add 5 and 6 to get 11.

\(\frac{11}{15} \)

Hope it helps and have a great day! =D

​

Answer:

A

Step-by-step explanation:

crawl before you walk.

Answer:

The volume would be 3,421.19m

The probability of selecting an orange marble is 0.33.

Option B is the correct answer.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

The number of times each marble is selected.

Green = 4

Black = 6

Orange = 5

Total number of times all marbles are selected.

= 4 + 6 + 5

= 15

Now,

The probability of selecting an orange marble.

= 5/15

= 1/3

= 0.33

Thus,

The probability of selecting an orange marble is 0.33.

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This graph represents a function Because it passes the vertical line test.

Let us first understand the Vertical Line Test.

In this test, we draw a few random vertical lines on a graph and check whether any one or more than one lines intersect the graph, no matter once or more.

If there exists a line that intersects the graph, we say the graph passes the vertical line test.

The vertical line test is a visual way to determine if a curve is a graph of a function or not. A function can only have one output, y, for each unique input, x.

Hence this graph passes the vertical line test because there are many vertical lines that intersect it.

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The radian value of 72/8 is given by \(\frac{\pi}{20}\) radian.

We know that 1 = \(\frac{\pi}{180}\) radian

So given the number is 72/8

72/8 = 9

1 = \(\frac{\pi}{180}\) radian

9 \(=\frac{\pi}{180}\times9=\frac{\pi}{20}\) radian

Hence the radian value of 72/8 is \(\frac{\pi}{20}\) radian.

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