helppppppppppppppppp asappppppp

Answer:

Step-by-step explanation:

y=4x-5

put y=3 and x=2

3=4(2)-5

3=8-5

3=3 so the point lies on the line

y=18+2x

put y=17 and x=-1

17=18+2(-1)

17=18-2

17=16

so the point does not lie on the line

Answer:

Question 1:

Point = (x,y) = (2,3)

So, x = 2, y = 3

Let's put this in the equation to check whether it lies on the line or not

=> 3 = 4(2)-5

=> 3 = 8-5

=> 3 = 3

Since LHS = RHS so The point lies on the line

Question 2:

Point = (x,y) = (-1,17)

So, x = -1, y = 17

Let's put this in the equation to check whether it lies on the line or not

=> 17 = 18+2(-1)

=> 17 = 18-2

=> 17 ≠ 16

Since LHS ≠ RHS, So this point doesn't lie on the line.

Answer:

....................... what is the queston

Step-by-step explanation:

Answer:

What type of math is this

Step-by-step explanation:

Answer:

Step-by-step explanation:

You have omitted relevant parts of the question. What is the question? Are you looking for the area of the yard? The amount of fencing needed?

What units are used? (Feet, yards, meters, etc.)

area of yard = 75×55 = 4125 units²

amount of fencing needed = perimeter of rectangle = 2(75+55) = 260 units.

The total length of the fencing is the perimeter of the rectangular yard which is P = 260 feet

The perimeter P of a rectangle is given by the formula, P=2 ( L + W) , where L is the length and W is the width of the rectangle.

Perimeter P = 2 ( Length + Width )

Given data ,

The width of the rectangular yard W = 55 feet

The length of the rectangular yard L = 75 feet

Let the perimeter of the rectangular yard be = P

And , the required fencing = Perimeter of rectangular yard

Perimeter of rectangular yard P = 2 ( L + W )

Substituting the values in the equation , we get;

Perimeter of rectangular yard P = 2 ( 55 + 75 )

Perimeter of rectangular yard P = 2 ( 130 )

Perimeter of rectangular yard P = 260 feet

Therefore , the value of P is 260 feet

Hence , the perimeter of yard is 260 feet

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Mr. Fuller wants to put fencing around his rectangular-shaped yard. the width of the yard is 55 feet and the length is 75 feet. how many feet of fencing does Mr. Fuller

Answer:

-6

Step-by-step explanation:

27-3/2x=36

53-3x=72

3x=-18

x=-6

Using the inequality rule we know that 11 is greater than -11, (11 > -11).

Mathematical expressions with inequalities are those in which the two sides are not equal.

Contrary to equations, we compare two values in inequality.

Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

Two expressions in inequality aren't always equal, which is denoted by the symbols >, <, ≤, or ≥.

So, let's say the inequality equation looks like this: A

Right now, A is valued at

Let p be used to representing the initial number.

P equals 11, so

Let q be used to representing the second number.

Q has a value of -11.

-11 and 11 are both numbers that are greater than zero.

Then, 11 > -11 ... (1)

A has a value of 11 > -11.

Therefore, using the inequality rule we know that 11 is greater than -11, (11 > -11).

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Correct question:
Is 11 greater than, equal to, or less than -11?

Answer:

30 60 90

Step-by-step explanation:

The class width used for the frequency distribution is 6.

The class midpoint for the class 23-29 is 26.

The class midpoint for the class 30-36 is 33.

The class midpoint for the class 37-43 is 40.

To find the class width of the frequency distribution, we need to determine the range of each age class. The range is the difference between the upper and lower boundaries of each class. Looking at the table, we can see that the class boundaries are as follows:

23-29

30-36

37-43

For the class 23-29, the lower boundary is 23 and the upper boundary is 29. To find the class width, we subtract the lower boundary from the upper boundary:

Class width = 29 - 23 = 6

So, the class width for the frequency distribution is 6.

To find the class midpoint for each class, we take the average of the lower and upper boundaries of each class.

For the class 23-29:

Class midpoint = (23 + 29) / 2 = 52 / 2 = 26

For the class 30-36:

Class midpoint = (30 + 36) / 2 = 66 / 2 = 33

For the class 37-43:

Class midpoint = (37 + 43) / 2 = 80 / 2 = 40

So, the class midpoint for the class 23-29 is 26, for the class 30-36 is 33, and for the class 37-43 is 40.

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Solution

We have the following system of equations:

3.25x - 1.5 y= 1.25 (1)

13x -6y= 10 (2)

We can solve for x in the first equation and we got

We can replace this into the second equation and we got:

Then we can solve for y on this way:

Since 5 is not equal to 10 then we can conclude that this system of equations has no solution

Answer:

1+2x-63x^2

Step-by-step explanation:

(1-7x)(1+9x)

1-7x+9x-63x^2

1+2x-63x^2

Answer:

Step-by-step explanation:

The area of a trapezoid is the average of the parallel bases times the height.

A=h(a+b)/2 and since we have two identical trapezoids the total are will be

A=h(a+b) in this case

A=15(32+25)=855mm^2

As you can see below, both expressions result in the same value of 105. This demonstrates the application of the associative law in regrouping terms and maintaining the equivalence of the expression.

The associative law in mathematics states that the grouping of numbers in an addition or multiplication operation does not affect the result. In other words, you can regroup terms within parentheses without changing the value of the expression.

Using the associative law, we can regroup the terms in the expression s + (r + 75) by removing the parentheses and rearranging the terms:

s + (r + 75) = (s + r) + 75

The expression (s + r) + 75 is equivalent to s + (r + 75) because the addition operation is associative.

Let's take an example to illustrate this:

Suppose s = 10 and r = 20.

Using the original expression:

s + (r + 75) = 10 + (20 + 75) = 10 + 95 = 105

Using the expression with regrouped terms:

(s + r) + 75 = (10 + 20) + 75 = 30 + 75 = 105

As you can see, both expressions result in the same value of 105. This demonstrates the application of the associative law in regrouping terms and maintaining the equivalence of the expression.

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The best interpretation of the probability that the number landing face up will be less than 3 is \(\frac{1}{3}\).

For many rolls of the die, the long-run relative frequency of a number less than 3 landing face up is \(\frac{1}{3}\).

As per the given question a fair die with its faces numbered from 1 to 6 will be rolled.

Here we have to calculate the probability that the number landing face up will be less than 3.

The event of the number landing face up will be less than 3 is exhaustive, mutually exclusive, and independent face of a die = 6

(1, 2, 3, 4, 5, 6)

Favorable number of faces of a die = 2

(1, 2)

Since the number landing faces up will be less than 3.

Therefore the probability that the number landing face up will be less than 3

\(=\frac{\text { Favourable Number }}{\text { Total Number }}$\)

\(& =\frac{2}{6} \\\)

\(& =\frac{1}{3}\)

Therefore the best interpretation of the probability that the number landing face up will be less than 3 is \(\frac{1}{3}\)

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The long-run relative frequency of a number less than 3 landing face up is 2/3.

The best interpretation of the probability that the number landing face up will be less than 3 is that for many rolls of the die, the long-run relative frequency of a number less than 3 landing face up is 2/3. This can be expressed mathematically as P(x<3) = 2/3, where P(x) is the probability of the number landing face up being less than 3.

For a single roll of the die, the probability of a number less than 3 landing face up is 1/2. This is because there are three numbers (1,2,3) which are less than 3, and 6 possible outcomes. Therefore, the probability of any one of those three numbers landing face up is 3/6, or 1/2.

For multiple rolls of the die, the probability of a number less than 3 landing face up is the sum of the probabilities of each of those three numbers landing face up. This can be expressed mathematically as P(x<3) = (1/2) + (1/2) + (1/2), or 2/3.

Therefore, for many rolls of the die, the long-run relative frequency of a number less than 3 landing face up is 2/3.

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Answer:

Theoretical probability is a method to express the likelihood that something will occur. It is calculated by dividing the number of favorable outcomes by the total possible outcomes. The result is a ratio that can be expressed as a fraction (like 2/5), or a decimal.

Step-by-step explanation:

The number of seats on the 24th row is 3220.

The number of chairs in the 24th row is a function of the rate at which the chairs increase and the number of rows. The formula that can be used to determine the number of seats on the 24th row is:

P x [r x (n - 1)]

Where:

70 x [2x  (24 - 1)]

70 x  (2 x 23)

= 70 x 46

= 3220

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a. $456 would be the amount a customer could save during the first year by switching from Cable Zone to Super Vision.

b. Super Vision raises the rates 23% after a new customer's first year,  a customer who switched from Super Vision save $180 in the second year.

c. Super Vision raises the rates 18% for the third year compared to the second year, for the third year, Cable Zone would be cheaper.

a. To calculate how much a customer could save during the first year by switching from Cable Zone to Super Vision, we need to compare the costs of the two providers.

Cable Zone charges $46 for monthly home phone service, $36 for monthly Internet service, and $56 for monthly cable television. Therefore, the total cost per month with Cable Zone is:

$46 (home phone) + $36 (Internet) + $56 (cable television) = $138

Super Vision, on the other hand, offers all three services for a flat $100 monthly fee. So, the customer would save:

$138 (Cable Zone cost) - $100 (Super Vision cost) = $38 per month

Therefore, during the first year, the customer could save:

$38 (monthly savings) * 12 (number of months) = $456

b. After the first year, Super Vision raises the rates by 23%. The new monthly fee would be:

$100 (original fee) + 23% (rate increase) * $100 (original fee) = $123

To calculate the savings in the second year, we need to compare the new Super Vision fee to the cost with Cable Zone:

$138 (Cable Zone cost) - $123 (Super Vision cost) = $15 per month

Therefore, in the second year, the customer would save:

$15 (monthly savings) * 12 (number of months) = $180

c. If Super Vision raises the rates by 18% for the third year compared to the second year, we need to calculate the new monthly fee. The new Super Vision fee would be:

$123 (second-year fee) + 18% (rate increase) * $123 (second-year fee) = $145.14

To determine which company is cheaper for the third year, we compare the new Super Vision fee to the cost with Cable Zone:

$138 (Cable Zone cost) - $145.14 (Super Vision cost) = -$7.14

In this case, the Super Vision cost is higher than the Cable Zone cost by $7.14 per month. Therefore, for the third year, Cable Zone would be cheaper.

Overall, during the three-year period, the customer would save a total of $456 (first year) + $180 (second year) = $636 by switching to Super Vision.

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The correct inequality which has no solution will be;

⇒ x ≤ –2 and 2x ≥ 6

⇒ x ≤ –1 and 5x ≤ 5

What is Inequality?

A relation by which we can compare two or more mathematical expression is called an inequality.

Given that;

There are some inequality is shown.

Now,

Find the inequality which has no solution as;

a) x ≤ –2 and 2x ≥ 6

⇒ x ≤ - 2

⇒ 2x ≥ 6 = x ≥ 6/2 = x ≥ 3

We get;

⇒ x ≤ - 2 and x ≥ 3

Which is not possible.

Hence, it has no solution.

b) x ≤ –1 and 5x ≤ 5

⇒ x ≤ - 1

⇒ 5x ≤ 5 = x ≤ 1

We get;

⇒ x ≤ - 1 and x ≤ 1

Which is not possible.

Hence, it has no solution.

c) x ≤ –1 and 3x ≥ –3

⇒ x ≤ - 1

⇒ 3x ≥ - 3 = x ≥ - 1

We get;

⇒ x ≤ - 1 and x ≥ - 1 ⇒ x = - 1

Thus, It has solution.

d)  x ≤ –2 and 4x ≤ –8

⇒  x ≤ –2 and

⇒ 4x ≤ - 8 = x ≤ - 2

Thus, It has solution.

Therefore, The correct inequality which has no solution will be;

⇒ x ≤ –2 and 2x ≥ 6

⇒ x ≤ –1 and 5x ≤ 5

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Answer:

m = 5

Step-by-step explanation:

A quadratic function is in the form \(ax^{2} +bx+c\).

To factor an equation, you are looking for two numbers that multiply to c (are factors of c), and add to b. In this case, c = -15, and b = 2.

The factors of -15 include 1, 3, 5, 15, -1, -3, -5, and -15.

After looking through the possible combinations, we can come to the conclusion that the only factors that multiply to -15 and add to 2 are 5 and -3, as 5 x -3 = -15, and 5 + -3 = 2.

You can now plug these numbers into the factored form (x + factor1)(x + factor2).

This then becomes (x + -3)(x + 5) or (x - 3)(x + 5).

Therefore, m = 5.

Answer:

1. B. <1 and <2

2. C. 37°

3. B. 40°

Step-by-step explanation:

1. Complementary angles add up to 90°.

From the diagram given, <1 and <2 are complementary because they sum up to 90°.

The answer is B. <1 and <2

2. Given that,

m<1 = 37°, m<4 = 37° also.

This is because m<1 and m<4 are Vertical angles. Vertical angles pair are equal.

The answer is: C. 37°

3. If m<1 = 50°, then:

m<5 = 90 - m<4

m<1 = m<4 = 50° (vertical angles)

m<5 = 90 - 50 (substitution)

m<5 = 40°

Answer is B. 40°

Answer:

C and E

Step-by-step explanation:

23 > 16 and \(23\geq 16\) are both true statements since the quantity of 23 is greater than that of 16.

Answer:

7 + 2 = 9, so AC = 7/9 and CD = 2/9

1 + 2 = 3, so AB = 1/3 = 3/9 and

BD = 2/3 = 6/9

AB + BC = AC

3/9 + BC = 7/9, so BC = 4/9

AB:BC:CD = (3/9):(4/9):(2/9) = 3:4:2

Step-by-step explanation:

x = by - 3/2

x + 3/2 = by

y = x/b + 3/(2b)

now compare this to the first equation :

y = 2x + 3

the system has infinite solutions, if both equations are actually identical.

and they are only identical, if b = 1/2

y = x/(1/2) + 3/(2 × 1/2) = 2x + 3

Answer:

Step-by-step explanation:

To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.

h = -16t^2 + 56t

h = -16t^2 + 156t - 248

-16t^2 + 56t = -16t^2 + 156t - 248

You can cancel out the -16t^2's to get

56t = 156t - 248

=> 0 = 100t - 248

=> 248 = 100t

=> 2.48 = t

Using this time value, plug into either equation to find the height.

h = 16(2.48)^2 + 56(2.48)

Final answer:

h = 40.4736

Answer:

60.85% probability that the sample mean is between $1.4 million and $1.5 million per year

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

In millions of dollars.

\(\mu = 1.47, \sigma = 0.3, n = 30, s = \frac{0.3}{\sqrt{30}} = 0.0548\)

What is the probability that the sample mean is between $1.4 million and $1.5 million per year?

This is the pvalue of Z when X = 1.5 subtracted by the pvalue of Z when X = 1.4. So

X = 1.5

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{1.5 - 1.47}{0.0548}\)

\(Z = 0.55\)

\(Z = 0.55\) has a pvalue of 0.7088

X = 1.4

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{1.4 - 1.47}{0.0548}\)

\(Z = -1.28\)

\(Z = -1.28\) has a pvalue of 0.1003

0.7088 - 0.1003 = 0.6085

60.85% probability that the sample mean is between $1.4 million and $1.5 million per year

Answer:

\( z= \frac{1.4-1.47}{\frac{0.3}{\sqrt{30}}}= -1.278\)

\( z= \frac{1.5-1.47}{\frac{0.3}{\sqrt{30}}}= 0.548\)

And we can find the probability with this difference:

\( P(-1.278<z<0.548) = P(z<0.548) -P(z<-1.278) =0.708-0.101= 0.607\)

So then the probability that the sample mean is between $1.4 million and $1.5 million per year is 0.607

Step-by-step explanation:

For this case we have the following info given:

\( \mu = 1.47\) the true mean for the problem

n =30 represent the sample size

\( \sigma = 0.3 millions\) represent the population deviation

And we want to find this probability

\( P(1.4< \bar X <1.5)\)

And we can use the z score given by:

\( z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}\)

And if we find the z scores for the limits we got:

\( z= \frac{1.4-1.47}{\frac{0.3}{\sqrt{30}}}= -1.278\)

\( z= \frac{1.5-1.47}{\frac{0.3}{\sqrt{30}}}= 0.548\)

And we can find the probability with this difference:

\( P(-1.278<z<0.548) = P(z<0.548) -P(z<-1.278) =0.708-0.101= 0.607\)

So then the probability that the sample mean is between $1.4 million and $1.5 million per year is 0.607

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Answer:

The rate of change is 28.

Step-by-step explanation:

The equation is in slope-intercept form,  y = mx + b, where m is the slope, and b is the y-intercept.

Answer:

4/5

Step-by-step explanation:

7 1/5 - 6 2/5

We need to borrow from the 7 in the form of 5/5

6 + 5/5 + 1/5 - 6 2/5

6 6/5 - 6 2/5

0 + 4/5

4/5

Answer:

4/5

Step-by-step explanation:

7 1/5 - 6 2/5= 36/5 - 32/5= 4/5

Answer:

112.5

67.5

Step-by-step explanation:

We know the ratio is:

5:3

So, we can write it as:

5x+3x=180, with 5x being one angle, and 3x being the other

combine like terms

8x=180

divide both sides by 8

x=22.5

5(22.5)=112.5

3(22.5)=67.5

So, one angle is 112.5 and the other is 67.5.

Hope this helps!