To determine the charge on the predominant form of phosphoric acid at pH 9.5, we need to consider the pKa values of its ionizable hydrogen atoms.
Phosphoric acid (H₃PO₄) has three ionizable hydrogen atoms, which can be sequentially deprotonated. The pKa values given are 2.15, 6.82, and 12.38.At pH 9.5, we need to determine which ionization steps have occurred and calculate the charge accordingly.Since pH 9.5 is between the pKa values of 6.82 and 12.38, the predominant form will be a mixture of the second and third ionizations.At pH 9.5, the predominant form of phosphoric acid will have lost two protons, resulting in the formation of HPO₄²⁻, which is the conjugate base of H₂PO₄⁻.Therefore, the charge on the predominant form of phosphoric acid at pH 9.5 is 2- (two negative charges) in the form of HPO₄²⁻.
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you weigh 150 pounds, and your friend is dragging you on a sled up a hill by pulling on a rope with 50 n of force. you are moving in a straight line and at constant speed. your acceleration is:_____
The acceleration of the person being dragged on the sled is zero. The acceleration due to gravity is approximately 9.8 m/s², the mass of the person is approximately 68.04 kg (150 pounds / 2.2046).
The person being dragged on the sled is moving at a constant speed, which means there is no change in velocity. According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The person's weight of 150 pounds can be converted to mass using the formula: mass = weight / acceleration due to gravity.
Since the person is moving at a constant speed, the net force acting on them must be zero. The force of 50 N exerted by the friend pulling the rope is balanced by the force of friction opposing the motion.
Therefore, the acceleration of the person being dragged on the sled is zero. The force of friction in this case is equal in magnitude and opposite in direction to the force applied by the friend. This balance of forces allows the person to maintain a constant speed while being dragged up the hill.
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Get some points uwu
What part of the telescope focuses the light
Answer:
Objective lens is the answer
Convert the following (using conversion factors): 0.0062m³ = ____ cm³
Answer:
in the converson to cm³
l m= 100cm
what about :
l m³ = 1000×1000×1000
= 1000000cm³
After this we :
1 m³ = 1000000cm³
how about:
100m³ = 100 × 1000000cm³
= 100000000cm³
what did carl sagan mean when he said that we are all "star stuff"?
When Carl Sagan claimed that we are all made of "star stuff," he was referring to the fact that the components that make up our bodies, as well as all matter on Earth, were originally created in the cores of stars.
In its infancy, the cosmos was primarily made up of hydrogen and helium, with just minute amounts of lithium present. Nucleosynthesis is the process through which stars turn lighter elements like carbon, nitrogen, and oxygen into heavier elements like carbon, nitrogen, and oxygen over the course of billions of years.
Supernovae are the explosions that occur as stars reach the end of their lives. These explosions distribute the components that make up stars and planets into space, where they can eventually form new stars, planets, and even life.
Because of this process, the atoms that make up our bodies and all other matter on Earth are composed of the same elements that were produced in the cores of stars billions of years ago. This is true for all matter on the planet. In other words, we are composed of the same "star stuff" that makes up the universe, and we are related to the cosmos in ways that we are just starting to grasp. However, we are comprised of the same "star stuff" that makes up the universe.
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A student drops a feather off the top a building. The feather averages 1.5m/s while
fluttering to the ground.
Determine all unknowns.
The acceleration with which an object falls through a fluid decreases as the speed of the object increases under gravity, to the point where the speed becomes constant, which is known as the terminal speed of the object
The unknown parameters are the mass of the feather, the density of the air, the feather's projected area and the coefficient of drag
The reason the above selected parameters are the correct unknowns is as follows;
The known parameter;
The speed of the feather the student drops off the building's top = 1.5 m/s
The required parameter;
The unknown parameters
Method;
Determine the terminal velocity parameters of the feather
The terminal velocity, \(\mathbf{V_t}\), of an item is the maximum steady speed the item reaches as it falls through a fluid. The terminal velocity of the feather is given by the following equation
\(Terminal \ velocity, V_t = \mathbf{\sqrt{\dfrac{2 \cdot m \cdot g}{\rho \cdot A \cdot C_d} }}\)
Where;
\(\mathbf{V_t}\) = Terminal velocity = The constant speed of the feather
m = Mass of the feather
g = Gravitational acceleration
ρ = Air density
A = The feather's projected area
\(C_d\) = Drag coefficient
The average speed of the feather = 1.5 m/s = The feathers typical or most common speed = The terminal velocity of the feather, \(\mathbf{V_t}\);
Plugging in \(\mathbf{V_t}\) = 1.5 m/s gives;
\(V_t = 1.5 \ m/s = \mathbf{\sqrt{\dfrac{2 \cdot m \cdot g}{\rho \cdot A \cdot C_d} }}\)
Therefore, the unknown parameters with regard to the feather falling are the parameters that are to be specified, including;
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how was mount Everest made? Please i am handing out 100 points
Answer:
Mount Everest formed from a tectonic smashup between the Indian and Eurasian tectonic plates tens of millions of years ago.
Explanation:
The gravitational force is 2336 N for an object that is 4.15 x 10^6 m above the surface of the Earth? The radius of the Earth is 6.378 x 10^6 m. (Earth's mass is 5.97 x 10^24 kg) What is the mass of the object above earth?
Answer:
34kg
Explanation:
gold is sold by the troy ounce (31.103 g). what is the volume in cm3 of 1 troy ounce of pure gold (19300 kg/m3)?
The volume of the gold with given specs is 1.610 cm³.
Density of the gold as given in the question : 19300 kg/m³
Density of the gold in changed units i.e g/cm³ : 19.3 g/cm³
The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Formula: = m/V, m is the object's mass, and V is its volume.
Density = Mass / volume
=> Volume = Mass / density
Substituting the values :
Volume = (31.103)/(19.3)
Volume = 1.610 cm³
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One forecasting model was used to forecast demand for a product. The forecasts and the demand are shown in the table below. B Actual Forecast 11 40 41 35 38 3 38 35 33 30 IX Calculate Moan Absolute Deviation (MAD) and Mean Squared Error (MSE). Show all details and use 1 decimal in your answer For the toolbar, press ALT+F10 (PC) or ALT+FN-F10 (Mac). BI V S Paragraph Arial 14px V QUESTION 1 The department manager is using a combination of methods to forecast sales of tonsters at a local department store. The demanders shown in the be Week Actu Demand 11 24 bo 2 bas x III A Using trend projection, calculate foresting values for week and week & Show details of your answer For the toolbar, pro ALT.F10 PC) O ALT.FN.F10 Mac BIS Paragraph Arial 14 Focus Chile we state
The estimated demand for Week 4 is 36.3
MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:
MAD= Sum of| Actual demand - Forecast demand | / number of periods
In the given table, the Actual demand is shown as B and the forecast demand is shown as F.
B Actual Forecast 11 40 41 35 38 3 38 35 33 30
Calculation of MAD:
Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0
The number of periods is 9 as shown in the table.
MAD= 103/9MAD= 11.44
Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:
MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.
Calculation of MSE:
Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854
The number of periods is 9 as shown in the table.
MSE= 2854/9MSE= 317.1
Therefore, the calculated MAD is 11.44 and MSE is 317.1.
Trend Projection formula is given by:
Y = a + bx
where Y is the estimated demand for a particular period.
a is the Y-intercept
b is the slope of the regression line x is the period number
In the given table, the Week number is shown as X and the Actual demand is shown as Y.
Week number Actual Demand 11 24 22 29
Using trend projection for Week 3, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4
Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35
Therefore, the estimated demand for Week 3 is 35.
Using trend projection for Week 4, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78
Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3
Therefore, the estimated demand for Week 4 is 36.3.
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If the display is located 12.6 cm from the 12.0-cm focal length lens of the projector, what is the distance between the screen and the lens?
What is the height of the image of a person on the screen who is 3.0 cm tall on the display?
The distance between the screen and the lens is 144 cm.
The height of the image of a 3.0 cm tall person on the screen is 34.3 cm.
We can use the thin lens equation to determine the distance between the screen and the lens:
1/f = 1/do + 1/di
1/di = 1/f - 1/do
1/di = 1/12.0 cm - 1/12.6 cm
1/di = 0.0833 cm⁻¹
di = 12.0 cm / 0.0833 cm⁻¹
di = 144 cm
To find the height of the image of a 3.0 cm tall person on the screen, we can use the magnification equation:
m = -di/do
m = -di/do
m = -(144 cm)/(12.6 cm)
m = -11.43
height of image = magnification x height of object
height of image = (-11.43) x (3.0 cm)
height of image = -34.3 cm
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light cannot _ around objects
Answer:
mark me Brainliest
Explanation:
light cannot travel around objects
Answer:
Translucent objects allow light to pass through them but they distort it.
Explanation:
Example: frosted or stained glass. Opaque objects do not allow light to pass through them. Example: brick walls, human beings.
A car going 20 MPH steps on the accelerator and accelerated at a rate of 10 MPH per second for 3 seconds. What is the final velocity of this car?
Answer:
50 mile/hr
Explanation:
Vf = Vo + at
Vf = 20 + 10 (3) = 50 mile/hr
Suppose you were given the statement "All points on a rigid object have the same angular acceleration and angular speed." a. How could you use the bugs in Ladybug Revolution to test this idea?b. Is the angular displacement also the same or does it differ? Explain your reasoning
The following propositions are true with regard to an object's points rotating around a fixed point. They all rotate at the same pace. All of them experience the same angular acceleration
The angular speed for a circular motion about a particular point is equal at all locations along the circular path and is calculated as;
Where
α=ω÷t
The number of rotations about a fixed point is N.
The time of motion is T.
As a result, the position of an item spinning around a fixed point has no bearing on its angular speed.
The specified same angular acceleration is
Each object in the circular path will move at a different tangential speed and acceleration depending on its position.
We may therefore draw the conclusion that the claims that are true for all points in the object spinning about a fixed point are that they all have the same angular acceleration and angular speed.
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When a cyclist is decelerating uphill the forces on him are balanced or unbalanced
Answer:
Unbalanced
Explanation:
A cyclist decelerating uphill has unbalanced forces acting on him. An unbalanced force acting on a body has a net force which is greater than zero. When a body is accelerating or decelerating, the forces are not balanced.
A body with a net force of zero has balanced forces acting on it. Such body is moving with constant acceleration. According to newton's first law of motion" a body will remain in state of rest or of uniform motion unless an external force acts on it". The external force causes acceleration to change drastically.the capacity of the gasoline tank in an automobile is 12 gallons. how many liters is this?
Answer: 45.4249
Explanation: 12 gallons converted to liters = 45.4249 liters
Answer:45.42
Explanation:
1 Gallon = 3.785 liters
3.785 × 12 = 45.42
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Hope this helps
what is the molar solubility of la(io3)3 in pure water? ksp = 1.0 × 10−11 for la(io3)3.
The molar solubility of La(IO₃)₃ in pure water is approximately 1.0 × 10⁻⁴ mol/L.
The molar solubility of a compound refers to the maximum amount of the compound that can dissolve in a given solvent at a specific temperature, typically expressed in moles per liter (mol/L). To determine the molar solubility of La(IO₃)₃ in pure water, we can use the given value of the solubility product constant (Ksp) for La(IO₃)₃, which is 1.0 × 10⁻¹¹.
La(IO₃)₃ dissociates into La³⁺ and IO₃⁻ ions in water. Let's assume x mol/L represents the molar solubility of La(IO₃)₃. According to the balanced chemical equation, one mole of La(IO₃)₃ produces one mole of La³⁺ ions and three moles of IO₃⁻ ions.
Therefore, the solubility product expression for La(IO₃)₃ is:
Ksp = [La³⁺][IO₃⁻]³
Since the concentration of La³⁺ ions is equal to the molar solubility (x) and the concentration of IO₃⁻ ions is three times the molar solubility (3x), we can substitute these values into the Ksp expression:
Ksp = (x)(3x)³
1.0 × 10⁻¹¹ = 27x⁴
Solving for x, we find:
x ≈ 1.0 × 10⁻⁴ mol/L
Therefore, the molar solubility of La(IO₃)₃ in pure water is approximately 1.0 × 10⁻⁴ mol/L.
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An open system starts with 52 J of mechanical energy. The energy changes
to 45 J of mechanical energy and 2 J of thermal energy. What is the final total
energy of the system?
A. 50 J
B. 54 J
C. 47 J
O D. 9 J
Answer:
ITS C 47
Explanation:
At t = 10 s, a particle is moving from left to right with a speed of 5. 0 m/s. At t = 20 s, the particle is moving right to left with a speed of 8. 0 m/s. Assume the particle's acceleration is constant and that to the right is the positive direction.
Given,
At time t = 10 s moving from left to right speed of particle = 5 m/s
at t = 20 s moving from right to left speed of particle is = 8 m/s
a) acceleration
a = v/t
a= -8-5/20-10
a = -1.3 m/s²
b) using equation of motion
v = u + at
5 = u - 1.3 × 10
u = 5 + 13
u = 18 m/s
c) v = u + at
0 = 18 - 1.3t
t = 13.85 s
What is acceleration?
Uniform or constant acceleration is a type of motion where an object's velocity changes by an equal amount during a period of time that is the same length.
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A platinum resistance thermometer measures temperature by the change in the electrical resistance of a platinum wire. The coefficient of resistivity for platinum is 3.92×10
−3
∘
C
−1
. At a temperature of 20.0
∘
C, the thermometer has a resistance of 50.0Ω; when immersed in a crucible containing melting indium its resistance is 76.8Ω. What is the melting point of indium? Question 9 An electric fire has a heating element rated at 1 kW when operating at 230 V. (a) what is its resistance? (b) what will be the power dissipation if the mains voltage drops to 210 V, assuming that the element obeys Ohm's Law?
From the calculation;
1) Melting point of indium = 171.4°
2) The resistance is 52.9 ohm
3) The power dissipated is 834 W
Temperature coefficient of resistanceThe temperature coefficient of resistance is a measure of how much the resistance of a material changes with temperature. It quantifies the relationship between the change in resistance and the change in temperature.
We have that;
R1/R2 = (1 + αt1)/(1 + αt2)
50/76.8 = (1 + (3.92 * \(10^-3\) * 20))/(1 + (3.92 *\(10^-3\) * t))
0.65 = 1.0784/1 + 0.00392t
0.65(1 + 0.00392t) = 1.0784
0.65 + 0.0025t = 1.0784
t = 171.4°
P = \(V^2\)/R
R = \(V^2\)/P
R = \(230^2\)/1000
R = 52.9 ohm
The new power is;
P =\(210^2\)/52.9
P = 834 W
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What is the reason why real gas deviate from ideal gas?
Real gases deviate from ideal gas behavior due to intermolecular forces, finite volume of gas particles, non-ideal behavior at high pressures and low temperatures, and the size and shape of gas molecules. These factors result differences in observed gas behavior compared to ideal gases
Intermolecular Forces: Ideal gases are assumed to have no intermolecular forces or interactions between the gas particles. However, real gases do experience intermolecular forces, such as London dispersion forces, dipole-dipole interactions, and hydrogen bonding.
These forces cause deviations from ideal gas behavior by affecting the behavior of gas particles and their interactions with each other. At high pressures or low temperatures, intermolecular forces become more significant, leading to larger deviations from ideal gas behavior.
Volume of Gas Particles: Ideal gases are considered to have negligible volume for the gas particles themselves. In reality, gas particles have a finite volume.
At high pressures, the volume occupied by the gas particles becomes significant compared to the total volume of the gas, leading to deviations from ideal gas behavior. This effect is captured by the van der Waals equation, which includes a correction term to account for the volume of gas particles.
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Can you please help me with this question?
(a) The peak voltage is 100 mV.
(b) The root mean square voltage is 70.71 mV.
(c) The period of the wave is 0.1 s.
(d) The frequency of the wave is 10 Hz.
What is the peak voltage?
The peak voltage is calculated as follows;
volts/dev = 10 mV
time/dev = 0.1 s
Volts/t = 10 mV / dev x dev/ 0.1 s
Volts/t = 100 mV
The root mean square voltage is calculated as follows;
Vrms = √2/2 x V₀ = 0.7071 x V₀
Vrms = 0.7071 x 100 mV
Vrms = 70.71 mV
The period of the wave, T = 0.1 s.
The frequency of the wave is the reciprocal of the period and it is calculated as;
f = 1 / T
f = 1 / 0.1 s
f = 10 Hz
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Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
What is the kinetic energy of a 2000kg boat moving at 5m/s?
Answer:
25000 J or 25 kJ
Explanation:
K = 1/2 mv^2
where mass is in kilograms kg
and velocity is in metres per seconds m/s
Here, m = 2000, v = 5
v^2 = 5*5 = 25
1/2 mv^2 = 1/2 * 2000 * 25
= 50000/2
= 25000
Hope it helps!
Suppoe that a high-energy neutron i travelling at a peed of 18 million m/. Find it energy in MeV (million electron volt (eV))
The energy of the high energy neutron is 940.51 MeV.
Speed is nothing but the distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity with the SI unit meter/second.
We know that mass of the neutron m₀ = 939.6 MeV/c²
A high energy neutron is travelling at a speed of 18 million m/s.
Given that, v = 1.8 * 10⁷ m/s
The energy of neutron is calculated with the formula, m₀* c²/√(1 - v²/c²)
⇒ 939.6 * (3* 10⁸)²/√[1 - (1.8 * 10⁷)²/(3* 10⁸)²]
⇒ 940.51 MeV
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If a car can go from 0-69mi/hr in 8. 0 seconds, what would be its final speed after 5. 0 seconds if it’s starting speed was 50mi/hr
A moving object's final speed after accelerating and accelerating over time. 93.125 m/s is the final speed.
How is a car's acceleration determined?According to the equation a = v/t, acceleration (a) is the product of the change in velocity (v) and the change in time (t). In terms of meters per second squared (m/s2), this enables you to calculate how quickly velocity varies.
By putting an into the calculation, we may find the value of a using the formula v = u +/- a t where v = final velocity, u = beginning speed, a = accelerated, and t = period.
calculation:-
60 = 0 + a × 8\sa = 6098 = 8.625 m/s-1
As a result, the final speed after 8 seconds will be V = u +/- a t.
V = 50 + 8.625 × 5\sV = 93.125 m/s.
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Design an experiment to separate the components of a mixture of two solids - Sodium chloride and Sucrose. Both compounds are soluble in water, but Sucrose is much more soluble in an organic solvent (Dichloromethane) than water. Sodium chloride does not dissolve in dichloromethane.
By utilizing a funnel filter made of Sodium chloride salt as a filtration method. The organic solvent will be evaporated using the rotary evaporation method, leaving the sucrose behind.
Where is HCl found in the body?All plants naturally generate sugar, the well-known and adored simple carbohydrate, also called by its chemical formula, sucrose. This includes fruits, veggies, and even nuts. Plants including berries, vegetables, and nuts naturally contain sugars like glucose in various amounts. Sucrose is also commercially generated from sugar cane and beets.
What is HCl used for in everyday life?According to a research, ingesting "natural" sugar might be just as bad for your health as consuming high- fructose corn syrup. Sucrose, a carbohydrate, provides the energy your body needs to perform both mental and physical work. Your body converts foods like starch and sucrose into glucose and fructose during digestion. Your body breaks down food to provide your cells energy. Reduce the fructose and glucose down.
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What would be the likeliest effect of moving the pitchers mound in the MLB closer so that it’s 50 feet from home plate?
The guilty batter will often be removed from the game after charging the mound, though depending on the situation, there may also be a fine or suspension. Discipline for throwing a beanball may also be applied to the pitcher.
Pitchers There were worries that the game was unfairly rigged in favor of the pitcher and was therefore no longer entertaining to watch. In order to assist the batters, the pitching mound was dropped from 15 inches to 10 inches, and the strike zone was restored to its 1961 dimensions.Simple logic underlies the decision to relocate the mound: Pitchers in the modern day stand significantly taller and throw much harder than pitchers in the nineteenth century. As a result, today's batters have less time to react to pitches that are released closer to home plate and move faster toward their targets.For more information on MLB pitchers kindly visit to
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A 1500 kg 1500 kg elevator initially moving upward at 7.0 m/s 7.0 m/s slows to a stop in 3.5 seconds 3.5 seconds. Assuming there is no friction involved in the stopping procedure, what is the tension ( T T) in the supporting cable while the elevator slows to a stop?
When the elevator comes to a stop, the supporting cable is held at -3000 N of tension.
What is Force?A force that is transmitted when a rope, cable, or string is pulled tight is tension. The pulling force that an object exerts on a rope, cable, or string transmits along its length to another object that is attached to the other end is known as tension. The force along the length of a rope or cable that is being stretched or pulled is known as tension in physics.
We must determine the elevator's net force in order to determine the supporting cable's tension. The sum of the elevator's acceleration and mass creates this net force. As a result of the elevator's slowdown in this instance, its acceleration is negative (opposing its velocity).
The elevator's acceleration can be determined using the equation for average acceleration:
where a = (v_f - v_i) / t
The elevator's acceleration is denoted by a, the elevator's final velocity is denoted by v_f, and the initial velocity is denoted by v_i, which is 7.0 m/s. The time interval is denoted by t, which is 3.5 seconds.
a = (0 - 7.0) / 3.5
a = -2.0 m/s²
The net force on the elevator is given by the equation:
F_net = m × a
where:
F_net is the net force on the elevator
m is the mass of the elevator (1500 kg)
a is the acceleration of the elevator (-2.0 m/s²)
Substituting the values:
F_net = 1500 × -2.0
F_net = -3000 N
Since the cable is the only force , the tension (T) in the cable must be equal to the net force:
T = F_net
T = -3000 N
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Why cloth and leather are used to make safety clothing for people who work with heat. A.they are both good sources of heat. B they both can produce electrical energy C they both can absorb light energy. D they are both poor conductors of heat
Answer: D
Explanation:
An arrow is shot at an angle of 35° and a velocity of 50 m/s. How long does it take to return to its original starting height?
Answer:
4.02 s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 35°
Initial velocity (u) = 50 m/s
Acceleration due to gravity (g) = 10 m/s²
Time of flight (T) =?
The time of flight of the arrow can be obtained as follow:
T = 2uSineθ / g
T = 2 × 35 × Sine 35 / 10
T = 70 × 0.5736 / 10
T = 7 × 0.5736
T = 4.02 s
Therefore, the time taken for the arrow to return is 4.02 s