How did septima p. clark, modjeska simkins and matthew j. perry take leadership roles in fighting for african american rights in south carolina? briefly explain what each person did.

Answer:

Hello!

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5+(−4)= 1

Step-by-step explanation: Simplify the expression.

Hope this helped you!

Answer:

5+(-4)=1

Step-by-step explanation:

Answer: 30

Step-by-step explanation:

9/10 = numerator 9 x 3 = 27 and  denominator 10 x 3 = 30

2/15 = numerator 2 x 2 = 4 demoninator 15x 2 = 30

This is to make it easier to subtract with a common denominator

= 27-4/ 30

= 23/30

the lowest common denominator is 30

Answer:

Lowest common denominator are

7/10

The after-tax present worth according to the given values is $732,140.56 and the internal rate of return is 22.65%.

(a) To compute the after-tax present worth, we need to determine the net cash flow for each year and discount it to present value using the after-tax MARR of 15%.

Year 0: Initial cost of equipment = -$18,600
Years 1-10:
Revenue from bags = (100.3 bags/carton) x ($0.03/bag) x (200,000 cartons/year) = $120,780
Cost savings from reducing overfilling = (5.5%) x ($0.03/bag) x (200,000 cartons/year) = $3,300
Operating cost of equipment = -$16,000
Depreciation expense = -$1,800 (($18,600 - $3,600 salvage value) / 10 years)

Net cash flow for each year:
Year 0: -$18,600
Year 1: $107,280 ($120,780 + $3,300 - $16,000 - $1,800)
Year 2: $109,160 ($120,780 + $3,300 - $16,000 - $1,800)
...
Year 10: $113,640 ($120,780 + $3,300 - $16,000 - $1,800)

Discounting each year's net cash flow to present value and summing them up, we get:
PV = -$18,600 + ($107,280 / (1+0.15)^1) + ($109,160 / (1+0.15)^2) + ... + ($113,640 / (1+0.15)^10)
PV = -$18,600 + $750,740.56
PV = $732,140.56

Therefore, the after-tax present worth is $732,140.56.

(b) To compute the after-tax internal rate of return, we need to find the discount rate that makes the net present value equal to zero. We can use trial and error or a financial calculator to solve this.

Using trial and error, we find that a discount rate of approximately 22.65% makes the net present value equal to zero. Therefore, the after-tax internal rate of return is approximately 22.65%.

(c) To compute the after-tax simple payback period, we need to determine how long it takes for the cumulative net cash flow to equal the initial cost of the equipment.

Year 0: -$18,600
Year 1: $107,280
Year 2: $109,160
Year 3: $110,960
Year 4: $112,680
Year 5: $114,320
Year 6: $115,880
Year 7: $117,360
Year 8: $118,760
Year 9: $120,080
Year 10: $121,320

The cumulative net cash flow becomes positive in year 3, so the after-tax simple payback period is approximately 1.9 years (between year 2 and year 3).

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The probability of getting a pink bead out of the storage box containing a sum total of 175 beads is 0.1428

As per the question statement, we are supposed to find the probability of getting a pink bead out of the storage box containing a sum total of 175 beads.

It is given that there are 25 pink beads in the storage box.

Probability = Favorable outcome / Total value

Probability = 25/175

Probability = 0.1428

Hence, the probability of getting a pink bead out of the storage box containing a sum total of 175 beads is 0.1428

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Answer:2/8, 0.3215, 9/16, 0.75

Step-by-step explanation:

2/8 = 0.25  0.3215 is higher then 9/16 =0.5625 next is 0.75

The value of q is -27.

Recall Vieta's Formulas, which state that for a quadratic equation \(ax^2\) + bx + c = 0 with zeroes alpha and beta, the sum of the zeroes is equal to -b/a, and the product of the zeroes is equal to c/a.

In our equation \(x^2\) - 3x + q, the sum of the zeroes alpha and beta is -(-3)/1 = 3.

We are given that 2 alpha + 3 beta = 15. Substitute alpha = (15 - 3 beta)/2 into the equation.

Replace the value of alpha in the sum of zeroes equation: (15 - 3 beta)/2 + beta = 3.

Simplify the equation by multiplying both sides by 2: 15 - 3 beta + 2 beta = 6.

Combine like terms: 15 - beta = 6.

Subtract 15 from both sides: -beta = -9.

Multiply both sides by -1 to solve for beta: beta = 9.

Substitute the value of beta into the sum of zeroes equation: alpha = (15 - 3 * 9)/2 = -3.

Since we have the values of alpha and beta, we can find q using the product of the zeroes formula: q = alpha * beta = -3 * 9 = -27.

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Answer:

34

Step-by-step explanation:

Answer:

1+. -1 is 0. a

Step-by-step explanation:

Ii I'm god uhh

Answer:

2 and 4/10

Step-by-step explanation:

NoW gIvE tHe PeRsOn aBoVe BrAiNleSt

Answer:

x=4

Step-by-step explanation:

Answer:

here

4=16/x

or, x = 16/4

x = 4

Answer:

Step-by-step explanation:

A triangle has sides with lengths of 4 feet, 7 feet, and 8 feet is not a right-angled triangle.

To determine if the triangle is a right-angled triangle or not, we can use the Pythagoras theorem.

Pythagoras' theorem states that “In a right-angled triangle,  the square of the hypotenuse side is equal to the sum of squares of the other two sides.

Hypotenuse is the longest side that is opposite to the 90° angle.

The formula for Pythagoras' theorem is: \(h^{2}= a^{2} + b^{2}\)

Here h is the hypotenuse of the right-angled triangle and a and b are the other two sides of the triangle.

Let a be the base of the triangle and b be the perpendicular of the triangle.

      (hypotenuse)²= (base)² + (perpendicular)²

In this question, let the hypotenuse be 8 feet as it is the longest side of the triangle and 4 feet be the base of the triangle and 7 feet be the perpendicular of the triangle.

On putting the values in the formula, we get

                           (8)²= (4)² + (7)²

                           64= 16+ 49

                           64\(\neq\)65

Thus, the triangle with sides 4 feet, 7 feet, and 8 feet is not a right-angled triangle.

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Answer:

5g-8

Step-by-step explanation:

i don't know

have a great day

After answering the provided question, we can conclude that Therefore, the perimeter of the figure is approximately 88.8 and the area of the figure is approximately 282.7.

A two-dimensional geometric shape's perimeter is the entire duration of the boundary but rather outer edge. It is the total length of the shape's sides or edges. For example, the perimeter of a square is determined by adding the lengths among all four sides of the square. Similarly, to calculate the perimeter of a rectangle, add the lengths of adjacent sides and then multiply by two due to the two pairs of adjacent sides.

Perimeter =\(12 + 2(\pi * 6) + 12 + 2(\pi * 6) + 12 + 2(\pi * 6) + 12\)

Perimeter = \(12 + 12\pi + 12 + 12\pi + 12 + 12\pi + 12\)

Perimeter ≈ 88.8 (rounded to the nearest tenth)

Area of square = 1\(2^2 = 144\)

Area of semi-circle =\(1/2 * \pi r^2\)

Area of semi-circle = \(1/2 \pi 6^2\)

Area of semi-circle = \(1/2 \pi 36\)

Area of semi-circle = \(18\pi\)

Total area = \(144 + 4(18\pi )\)

Total area ≈ 282.7 (rounded to the nearest tenth)

Therefore, the perimeter of the figure is approximately 88.8 and the area of the figure is approximately 282.7.

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Considering concepts of divisibility, the amount of numbers in the set that are divisible by 2 but not by 10 is:

(C) 19.

The data-set has (55 - 10) + 1 = 46 numbers, hence 23 are divisible by 2. 20, 30, 40 and 50 are also divisible by 10, that is, 4 numbers have to be removed, hence the amount is:

23 - 4 = 19.

Which means that option C is correct.

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Answer:

2/25

Step-by-step explanation:

It will be 20/400 + 12/400

=2/25

Answer:

2/25

Step-by-step explanation:

Answer:

A \(MP= (3,1)\)

Step-by-step explanation:

\(MP= (\frac{x_1+x_2}{2})(\frac{y_1+y_2}{2})\)

\(MP= (\frac{-1+7}{2})(\frac{3+-1}{2})\) -1+7=6 3+-1=2

\(MP= (\frac{6}{2})(\frac{2}{2})\) 6/2=3 2/2=1

\(MP= (3,1)\)

Answer:

1/2x + 5

Step-by-step explanation:

The y intercept is 5 & the slope is already given!

Answer:

a. 13.3

b. 16.3

Step-by-step explanation:

Hope this is right.

A. The equation of the line through C(-6,5) and perpendicular to CD is y = (8/3)x + 31/3;     B. The equation of the line through D(2,2) and perpendicular to CD is y = (8/3)x - 10/3.

A. To find the equation of the line through point C(-6,5) and perpendicular to CD, we need to determine the slope of CD and then find the negative reciprocal of that slope.

First, let's calculate the slope of CD using the coordinates of points C(-6,5) and D(2,2):

slope_CD = (y2 - y1) / (x2 - x1) = (2 - 5) / (2 - (-6)) = -3 / 8

The negative reciprocal of -3/8 is 8/3.

Now, using the point-slope form of a linear equation, we can write the equation of the line passing through C(-6,5) with a perpendicular slope of 8/3:

y - y1 = m(x - x1)

y - 5 = (8/3)(x - (-6))

y - 5 = (8/3)x + 16/3

Simplifying further:

y = (8/3)x + 31/3

B. To find the equation of the line through point D(2,2) and perpendicular to CD, we follow a similar process. The slope of CD is still -3/8, so the negative reciprocal is 8/3.

Using the point-slope form with D(2,2) and a perpendicular slope of 8/3:

y - y1 = m(x - x1)

y - 2 = (8/3)(x - 2)

y - 2 = (8/3)x - 16/3

y = (8/3)x - 16/3 + 6/3

y = (8/3)x - 10/3

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which means that the net force acting on the skydiver is zero, and the forces are balanced. Therefore, the answer is C) Part I of the descent only.

Step 5: Draw the segments AB and AC to create two tangent lines to the circle.

Step 1: Draw segment OA.

Step 2: Find the midpoint, M, of OA by constructing the perpendicular bisector of OA.

Step 3: Draw a circle centered at point M with radius MA or MO (where A and O are the endpoints of segment OA).

Step 4: Let the points B and C represent the points where the two circles meet.

Step 5: Draw the segments AB and AC to create two tangent lines to the circle.

Based on the information given, we can infer that the skydiver experienced unbalanced forces during Part 1 of the descent only. This is because the diagram shows that the speed of the skydiver is increasing during Part 1,

which means that there must be a net force acting on the skydiver in the downward direction (i.e., the force of gravity is greater than the air resistance). In contrast, during Part 2,

the speed is constant, which means that the net force acting on the skydiver is zero, and the forces are balanced. Therefore, the answer is C) Part I of the descent.

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Answer:

Let a two digit number be, 10x + y.

75% of the number is,

= 75 % of (10 x + y)

= 75/100 × (10x+y)

= 3/4 × ( 10x + y)

According to the question, When increased by 75%, The digits must be reversed.

So,

(10 x + y) + 3/4 ( 10x + y) = 10y + x

4 (10x + y) + 3 ( 10x + y) = 4 ( 10y + x)

7(10x + y) = 4(10y + x)

70x + 7y = 40y + 4x

70x - 4x = 40 y - 7y

66x = 33y

2x = y

So,

x = 1, y = 2, 10x + y = 12

x = 2, y = 4, 10x + y = 24

x = 3, y = 6, 10x + y = 36

x = 4 , y = 8 , 10x + y = 48

x can't be 5, as y will be 10 ( y should be a single digit).

Therefore, 4 two digit numbers are possible.

In analyzing the performance of implementing the given methods over Singly Linked List and Doubly Linked List data structures, we consider the Big-O notation, which provides insight into the time complexity of these operations as the size of the list increases.

Add to Start of List:

Singly Linked List: O(1)

Doubly Linked List: O(1)

Both Singly Linked List and Doubly Linked List offer constant time complexity, O(1), for adding an element to the start of the list.

This is because the operation only involves updating the head pointer (for the Singly Linked List) or the head and previous pointers (for the Doubly Linked List). It does not require traversing the entire list, regardless of its size.

Add to End of List:

Singly Linked List: O(n)

Doubly Linked List: O(1)

Adding an element to the end of a Singly Linked List has a time complexity of O(n), where n is the number of elements in the list. This is because we need to traverse the entire list to reach the end before adding the new element.

In contrast, a Doubly Linked List offers a constant time complexity of O(1) for adding an element to the end.

This is possible because the list maintains a reference to both the tail and the previous node, allowing efficient insertion.

Add at Given Index:

Singly Linked List: O(n)

Doubly Linked List: O(n)

Adding an element at a given index in both Singly Linked List and Doubly Linked List has a time complexity of O(n), where n is the number of elements in the list.

This is because, in both cases, we need to traverse the list to the desired index, which takes linear time.

Additionally, for a Doubly Linked List, we need to update the previous and next pointers of the surrounding nodes to accommodate the new element.

In summary, Singly Linked List has a constant time complexity of O(1) for adding to the start and a linear time complexity of O(n) for adding to the end or at a given index.

On the other hand, Doubly Linked List offers constant time complexity of O(1) for adding to both the start and the end, but still requires linear time complexity of O(n) for adding at a given index due to the need for traversal.

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The solution to the inequality is:

x ∈ (-∞, -21].

The correct option is F.

To solve the given inequality, we'll first simplify the expression:

23 < 3x - 3 ≤ -66

To simplify the inequality,

23 < 3x - 3 ≤ -66

Adding 3 to all parts of the inequality:

23 + 3 < 3x - 3 + 3 ≤ -66 + 3

Simplifying:

26 < 3x ≤ -63

Next, divide all parts of the inequality by 3:

26/3 < 3x/3 ≤ -63/3

Simplifying:

8.67 < x ≤ -21

Therefore, the solution to the inequality is:

x ∈ (-∞, -21]

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The statement "f(x) is increasing" refers to a function f(x) whose values increase as the input x increases. There are several equivalent statements that convey the same meaning:

1. The slope of f(x) is positive: This means that the function's graph has a positive slope, indicating an upward trend as x increases. In other words, as x moves to the right, the function values increase.

2. Whenever x₁ < x₂, f(x₂) > f(x₁): This inequality states that if we take two different x-values, x₁ and x₂, where x₁ is less than x₂, the corresponding function values f(x₁) and f(x₂) follow the same order. In this case, f(x₂) is greater than f(x₁), indicating an increasing trend.

3. The tangent line is upward sloping: At any point on an increasing function's graph, the tangent line has a positive slope. This indicates that the function is getting steeper as x increases.

4. f'(x) > 0 (the first derivative is positive): The first derivative of a function measures its instantaneous rate of change. If the first derivative is positive, it means the function is increasing. In other words, the function values are getting larger as x increases.

Therefore, the synonymous statements for "f(x) is increasing" are: the slope of f(x) is positive, whenever x₁ < x₂, f(x₂) > f(x₁), the tangent line is upward sloping, and f'(x) > 0 (the first derivative is positive).

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The group that would be the most stable based on size would be 10 people. So, the correct answer is c. 10 people.

A group is a set of people or objects that are deemed to be equivalent or share a common feature. Group members may collaborate and share knowledge to achieve a common goal. The group's performance is frequently greater than the sum of its members' individual efforts, and this is known as the group effect.

Group stability is defined as the ability of a group to remain together and keep working toward its objective over time. It is essential for a group to achieve its objectives and is typically linked to the group's size and objective. A stable group can withstand external pressures and is less susceptible to breaking up or being disbanded.

A group's size has a significant influence on its stability. Small groups are often more cohesive and productive than large groups. On the other hand, as a group's size grows, it becomes more challenging to sustain cohesion and productivity. A group of 10 people would be the most stable since it's not too large or too small. Thus, the correct option is c. 10 people.

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The solution range of the inequality {5x+7<3  and  3x-4>11} to is in range : x < -4/5 or x > 5.

Given are the following inequalities -

5x+7<3  and  3x-4>11

We have -

5x + 7 < 3

5x < - 4

x < -4/5

and

3x - 4 > 11

3x > 15

x > 5

So, we can write the solution of the inequality as -

x < -4/5 or x > 5

Therefore, the solution to the inequality is in range : x < -4/5 or x > 5.

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The temperature will be added, therefore, the temperature at noon will be 26°F

The following information can be derived from the question:

The temperature at 8:00 a.m. = -2 ∘F.

Increase in the temperature at noon = 28 ∘F

Therefore, since there was an increase in temperature, we'll add the values given and this will be:

= -2°F + 28°F

= 26°F

Therefore, the temperature at noon is 26°F

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Standard deviation of the sample of seven infants is 3.48 pounds approximately.

Given the observations are:

19.1, 22.1, 23.1, 25.1, 22.1, 29.1, and 29.1

Total number of observations = 7

Total of observations = 19.1 + 22.1 + 23.1  + 25.1 + 22.1 + 29.1 + 29.1 = 169.7

The mean of the data set (m) = (Total of observations)/(Number of observation) = 169.7/7 = 24.2 pounds (Rounding off to nearest tenth)

Now the standard deviation of the data set is given by,

= √((1/7)*{(19.1 - 24.2)² + (22.1 - 24.2)² + (23.1 - 24.2)² + (25.1 - 24.2)² + (22.1 - 24.2)² + (29.1 - 24.2)² + (29.1 - 24.2)²})

= √((1/7)*84.87)

= √12.1

= 3.48 pounds.

Hence, standard deviation = 3.48 pounds.

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