I need help with this plz help me

A force vector with magnitude 750 N and angle 30⁰ can be written as a Cartesian vector as: F = 375√3 i + 375 j

A vector can be written as its x-component and y-component.

Suppose the angle of a vector F with the positive x-axis is θ, then its components are given by:

Fx = F cos θ

Fy = F sin θ

Then,

F = Fx i + Fy j

  = F cos θ i + F sin θ j

In the given problem, θ = 30⁰, F = 750.

Hence,

Fx = 750 cos 30⁰

    = 750 (1/2)√3 = 375√3

Fy = 750 sin 30⁰

   = 750 (1/2) = 375

Thus, the vector can be written as a Cartesian vector:

F = 375√3 i + 375 j

Your question is incomplete, most likely your question was:

Express the force as a Cartesian vector. F 750 N. The angle of the force vector with the horizontal is 30⁰.

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The percentage of incident power reflected by the interface is  83.3% of the given standing wave.

Standing wave ratio in Region 1, SWR = 13.4

Distance between the two minima in Region 1 = 22.14 cm - 7.14 cm = 15 cm

Attenuation experienced in Region 2 = 12.2 dB/cm

Permeability of the conductor, μ = μ0 = 4π × 10⁻⁷ H/m

Permittivity of the conductor, ε = ε0 = 8.854 × 10⁻¹² F/m

We are to find:

a) The frequency f in Hz

b) The reflection coefficient magnitude

c) The phase constant β2

d) The value of σ in Region 2

e) The complex-valued intrinsic impedance in Region 2

f) The percentage of incident power reflected by the interface, P_ref/P_inc

Solution:

a) To find the frequency f, we need to use the formula for the distance between the two minima in Region 1:

λ/2 = 15 cm

λ = 30 cm

Since λ = c/f, where c is the speed of light, we have:

f = c/λ = 3 × 10⁸ m/s / 0.3 m = 1 × 10⁹ Hz

b) The reflection coefficient magnitude can be found using the formula:

SWR = (1 + |Γ|) / (1 - |Γ|)

Rearranging the equation, we get:

|Γ| = (SWR - 1) / (SWR + 1) = (13.4 - 1) / (13.4 + 1) = 0.917

c) The phase constant β2 can be found using the formula:

β2 = ω√(με - jωσ)

where ω = 2πf

Substituting the given values, we get:

β2 = 2π × 10⁹ √((4π × 10⁻⁷) × (8.854 × 10⁻¹²) - j × 2π × 10⁹ × σ)

d) To find the value of σ in Region 2, we need to use the attenuation experienced:

Attenuation = 12.2 dB/cm

Attenuation = 20 log (e^-αd) = -αd × 8.686

where α is the attenuation constant and d is the distance traveled.

Substituting the given values, we get:

12.2 = -α × 1 cm × 8.686

α = -1.404 dB/cm

α = ω√(με)√(1 + j/ωσ)

Substituting the given values and solving for σ, we get:

σ = 4.39 × 10⁷ S/m

e) The complex-valued intrinsic impedance in Region 2 can be found using the formula:

Z2 = (jωμ) / σ

Substituting the given values, we get:

Z2 = j(2π × 10⁹)(4π × 10⁻⁷) / (4.39 × 10⁷) = j0.57 Ω

f) The percentage of incident power reflected by the interface can be found using the formula:

P_ref / P_inc = |Γ|^2

Substituting the value of |Γ| found in part (b), we get:

P_ref / P_inc = 0.840

Therefore, about 84% of the incident power is reflected by the interface.

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The mass of the asteroid Swift is approximately 377.55 kg.

Mass can be best described as the amount of matter present in any object or body.

On Earth, the acceleration due to gravity is approximately 9.8 m/s^2.

To calculate the mass of the asteroid Swift, we will  convert its weight from newtons to kilograms (kg), which is the unit of mass in the International System of Units (SI):

Weight = 3700 N

Acceleration due to gravity on Earth (g) = 9.8 m/s^2

Weight = Mass x Acceleration due to gravity

Mass = Weight / Acceleration due to gravity

Mass = 3700 N / 9.8 m/s^2

Mass = 377.55 kg

In conclusion,  The mass of the asteroid Swift is approximately 377.55 kg.

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The fusion of carbon into heavier elements is the subsequent stage in the life cycle of a star with a mass of around twelve times that of the Sun. When the helium in the star's core is depleted, the star enters this phase, also referred to as the carbon-burning phase.

Carbon nuclei start to fuse at high pressures and temperatures, creating elements like oxygen and neon. By releasing energy throughout the fusion process, the star can keep its balance. But when the carbon fuel runs out, the star's core compresses, raising warmth and pressure even more.

The advancement to the ultimate phases of star development is marked by the beginning of future fusion processes, such as the fusion of oxygen and neon.

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Answer:

30cm

Explanation:

Answer:

110

Explanation:

on accellus

Answer:

the density is 2

Explanation:

p= m/v

p is density

m is mass

v is volume

6/3 = 2

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

\(E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J\)

So, the gravitational potential energy of a squirrel is 53.312 J.

(a) For a transfer from the perigee of the inner orbit to the apogee of the outer orbit, the minimum total delta-v required is approximately 5.58 km/s and the time of flight is approximately 16.31 hours.

(b) For a transfer from the apogee of the inner orbit to the perigee of the outer orbit, the minimum total delta-v required is approximately 5.04 km/s and the time of flight is approximately 17.76 hours.

To solve this problem, we can use the patched-conic approximation and the vis-viva equation to calculate the required delta-v and time of flight for each transfer.

(a) For the transfer from the perigee of the inner orbit to the apogee of the outer orbit, we need to calculate the velocity at the perigee of the inner orbit (V1p), the velocity at the apogee of the outer orbit (V2a), and the velocity change required (delta-v). Using the vis-viva equation, we can calculate V1p and V2a as follows:

V1p = sqrt(mu / rp) * (1 + e)

V2a = sqrt(mu / ra) * (1 - e)

where mu is the gravitational parameter of the Earth, rp and ra are the radii of the perigee and apogee of the respective orbits, and e is the eccentricity of the orbits.

Next, we can calculate the delta-v required using the following equation:

delta-v = sqrt(V2a^2 + V1p^2 - 2V1pV2a*cos(delta))

where delta is the angle between V1p and V2a. Since the apse lines are common, the angle delta is equal to the true anomaly at the perigee of the outer orbit (nu2p). Therefore, we can calculate delta as follows:

cos(delta) = cos(nu2p) = (e2 + cos(nu2p)) / (1 + e2*cos(nu2p))

where e2 is the eccentricity of the outer orbit.

Finally, we can calculate the time of flight (T) using the following equation:

T = pi * sqrt((a1 + a2)^3 / (8*mu))

where a1 and a2 are the semimajor axes of the inner and outer orbits, respectively.

(b) For the transfer from the apogee of the inner orbit to the perigee of the outer orbit, we follow the same steps as above, but with the following changes:

We calculate V1a and V2p (velocities at apogee and perigee, respectively) using the vis-viva equation.

The angle delta is now equal to the true anomaly at the apogee of the inner orbit (nu1a).

We use the formula T = pi * sqrt((a1 + a2)^3 / (8*mu)) with a1 and a2 swapped.

Using the given values for the two orbits, we can calculate the required delta-v and time of flight for both transfers as follows:

(a) For transfer from perigee of inner orbit to apogee of outer orbit:

V1p = 10.917 km/s, V2a = 3.078 km/s, cos(delta) = 0.336, delta-v = 5.58 km/s, T = 16.31 hours

(b) For transfer from apogee of inner orbit to perigee of outer orbit:

V1a = 1.522 km/s, V2p = 7.231 km/s, cos(delta

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The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

The converse of a statement switches the subject and the predicate and negates both. In the original statement, the subject is "pilots" and the predicate is "mechanics."

The original statement states that there is no overlap between pilots and mechanics. In the converse statement, the subject becomes "mechanics" and the predicate becomes "pilots," and it still states that there is no overlap between the two groups.

Therefore, The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

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Answer:

destructive i.e. colour of light wont reflect from  film

Explanation:

An anti-reflection (AR) coating needs to have zero reflectance in air for light with a wavelength equal to four times the coating thickness.

Lens surfaces, other optical components, and photovoltaic cells can all benefit from an anti-reflection (AR) coating, which is a form of optical coating used to reduce the reflection.

Here,

Anti-reflective coatings are utilised in a wide range of applications where it is desirable to have low loss or low reflection of light as it travels through an optical surface.

The simplest interference anti-reflective coating consists of a single, extremely thin layer of transparent material with a refractive index equal to the square root of the substrate's refractive index. A coating of this type should theoretically have zero reflectance in air for light with a wavelength (inside the coating) equal to four times the coating thickness. For wavelengths in a wide band around the centre, reflection is similarly reduced. A "quarter-wave layer" is a layer that has a thickness equal to one-fourth of a design wavelength.

Hence,

An anti-reflection (AR) coating needs to have zero reflectance in air for light with a wavelength equal to four times the coating thickness.

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The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

Suppose the angle between the polarizer and the axis of filter is θ.

The intensity of light that is passing after the filter is 0.2 l₀.

From the law of Malus, we have

I = I₀ \(cos^{2}\)θ

0.2I₀= I₀ \(cos^{2}\)θ

0.2 =  \(cos^{2}\)θ

\(cos\\\)θ = 0.447

θ = 60°

Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.

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The core of a highly evolved high mass star, depending on the type of stellar remnant, can be as small as the size of the Earth (for a white dwarf) or as compact as about 10 kilometers (for a neutron star).

The core of a highly evolved high mass star is typically a compact object known as a stellar remnant. There are two main types of stellar remnants that can form depending on the mass of the star: white dwarfs and neutron stars.

A white dwarf is the remnant of a star with a mass up to about 8 times that of the Sun. Its core is about the size of the Earth, which is much smaller compared to the original size of the star.

On the other hand, a neutron star is formed when a star with a mass greater than about 8 times that of the Sun undergoes a supernova explosion. The core of a neutron star is incredibly dense and compact, with a radius typically on the order of 10 kilometers (6.2 miles). Neutron stars are composed primarily of tightly packed neutrons and are extremely massive.

In summary, the core of a highly evolved high mass star, depending on the type of stellar remnant, can be as small as the size of the Earth (for a white dwarf) or as compact as about 10 kilometers (for a neutron star).

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The power developed is 8000 W.

Given data:

Force = 250 N

Distance traveled = 6 m

Velocity = 32 m/s

Let's find out the work done on the object by the applied force.

Work done is given by the product of force and distance covered:

W = F × s

W = 250 × 6 = 1500 J

Thus, the work done on the object by the applied force is 1500 J.

Next, let's determine the power developed.

Power is defined as the rate at which work is done, i.e.,

P = W / t

where P is power, W is work done, and t is time taken to do that work.

We know that velocity = distance / time. Rearranging the above expression, we get:

t = d / v

Substituting the given values, we get:

t = 6 / 32

P = W / t

Substituting the calculated value of W and t, we get:

P = 1500 / (6 / 32)

P = 8000 W

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Answer:

I don't understand Spanish

can you explain it in English

If "0.3 minute" is correct, then it's 9,543,272 Joules.

If it's supposed to say "0.3 SECOND", then the KE is 2,651 Joules.

Answer:

4.2 is the answer

Explanation

The image formed in a plane mirror is an equal distance behind the mirror as the object in front of it.

Step 1: the equation to this problem would be: 8.4/2

Step 2: 8.4 ÷ 2 = 4.2

Hope you could understand.

If you have any query, feel free to ask.

(a) To find the tension in the connecting cord with a horizontal force of 2.3 N, identify the forces acting on the system and the horizontal force will be equal to the tension in the cord.

1. Identify the forces acting on the system. There are two forces acting on the system: the horizontal force (2.3 N) and the tension in the cord (T).

2. Since the surface is frictionless and the pulley is massless and frictionless, the horizontal force will be equal to the tension in the cord. Therefore, T = 2.3 N.

So, the tension in the connecting cord is 2.3 N.

(b) To find the largest value of the magnitude of the horizontal force without the cord becoming slack, follow these steps:

1. Identify the forces acting on the system. There are two forces acting on the system: the horizontal force (F) and the tension in the cord (T).
2. In order for the cord to not become slack, the tension in the cord must be greater than or equal to zero. Therefore, T ≥ 0.
3. Since the surface is frictionless and the pulley is massless and frictionless, the horizontal force will be equal to the tension in the cord. Therefore, F = T.
4. Since T ≥ 0, it follows that F ≥ 0.

So, the largest value of the magnitude of the horizontal force without the cord becoming slack is any value greater than or equal to zero.

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Trigonometry and the law of reflection can be used to determine the angle at which the laser beam should be pointed at the mirrored ceiling to strike the midway of the far wall. This angle relies on the distance between the laser source, mirrored ceiling, and the midpoint of the far wall.

We would need to know the distances between the laser source, mirrored ceiling, and the midpoint of the far wall to calculate the angle at which the laser beam should be directed at the mirrored ceiling to strike the midpoint of the far wall. Once we know these locations, we can determine the angle of impact for the laser beam by applying the rule of reflection and trigonometry. The angle of incidence is specifically equal to the angle between the incoming laser beam and the normal to the reflected surface and can be determined using the following formula:

The angle of impact is equal to arctan(distance to the far wall's centre/distance to the mirrored ceiling).

Noting that this is a basic formula, it should be noted that the particular circumstance may call for additional calculations or modifications.

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The velocity of the horse is 20 meters/second.

To find the velocity of the horse, we can use the formula:

velocity = distance / time

In this case, the distance is 1900 meters and the time is 95 seconds. Plugging in these values into the formula, we get:

velocity = 1900 meters / 95 seconds

Simplifying, we find that the velocity of the horse is:

velocity = 20 meters/second

Speed is the speed and the bearing of movement of an item. Speed is a basic idea in kinematics, the part of traditional mechanics that depicts the movement of bodies. Velocity. As a shift in course happens while the dashing vehicles turn on the bended track, their speed isn't steady.

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The Law of Conservation of Energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.

As the object falls to the ground, its potential energy is converted into kinetic energy. The potential energy is determined by the object's mass and its height above the ground. As the object falls, its height decreases and its potential energy decreases, but this decrease in potential energy is compensated by an increase in kinetic energy. The kinetic energy is determined by the object's mass and its velocity. As the object's height decreases and its velocity increases, its kinetic energy increases.

As the object falls, the total amount of energy remains constant. The initial potential energy of 10 J is equal to the final kinetic energy of the object. This is an example of the Law of Conservation of Energy in action. The object's potential energy is transformed into kinetic energy, but the total amount of energy remains the same.

Answer:c

Explanation:

Answer:

A. The velocity increases during the time periods labeled A and C.

Explanation:

Answer: C. 39 s

Explanation:

We know the constant speed is 0.22 m/s. We have to get to 8.5 m. We divide 8.5 m by 0.22 = 38.6. After we estimate, 6 is greater than 5, so 39 s.

The right response is  B.

Line C refers to the bag that at the start of the experiment had a solution that was isotonic to the 0.6 M solutions.

The graph's line A denotes the bag with the greatest starting sucrose content.

As there is still a substantial rise in mass over this time period, line B in the graph represents bags that contain a solution that is hypertonic at 60 minutes.

Since there is still a significant loss of mass after 60 minutes, line D on the graph represents bags containing hypotonic solutions at that point.

The bag with the lowest starting sucrose content is shown by line E on the graph.

The graph's lines A, C, and E stand in for the bags containing the solutions that, after 60 minutes, become isotonic. After 60 minutes, line D is still hypotonic, but line B is still hypertonic.

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Answer:

Hey there!

This viewpoint probably comes from somebody who believes in the functionalism approach.

Let me know if this helps :)

A contact lens with a +3.014 diopters power will enable a farsighted woman with a near point of 70.0 cm to see objects clearly at a distance of 27.3 cm.

We have do = 23cm and di = -75cm

So 1/f = 1/do + 1/di = 1/23 + 1/(-75) = .03014

So f = 1/.03014=33.17

So power = 1/0.3317 = +3.014Diopters (converging lens)

In optics, a diopter represents the magnifying power of a lens or lens system. The power of a lens is proportional to unity (one) divided by the focal length (see lens), so the power of a lens in diopters is mathematically equal to 1 meter is divided by the focal length. A healthy human eye can concentrate on an object or picture that is 1/40 of a meter away with an optical power of roughly 40 diopters. A average young person's eye has an additional 20 diopters of adjustment.

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With a vacuum wavelength of 488 nm and an electron mass of 9.11*10^-31 kg, an electron travelling at 1490.45 m/s has the same momentum as a photon.

The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has magnitude but no direction as a unit of measurement. Speed is the rate at which anything moves over a predetermined distance. The elementary electric charge of the electron, sometimes known as the symbol e or, is a negative one. Given that they have no known components and are part of the first generation of lepton particles, electrons are frequently regarded as being elementary particles to its wavelength.

E = mc^2

mc^2 = hc/(lamda)

v = h/m(lamda)

v = 6.626*10^-34/9.11*10^-31*488*10^-9

v = 1490.45 m/s

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Answer:

The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.

Hope it helps!!!

Answer:

their will be no change in this..

The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.