If 120 g of naoh were used to prepare 500 ml of solution, what would the concentration be?.

The formula for the mass remaining after t years for a sample of radium-226 with an initial mass of 100mg is given by \($M(t) = 100 \times 0.5^{t/1590}$\). After 1000 years, the mass is approximately 87mg. The mass will be reduced to 30mg after approximately 2167 years.

(a) The decay of radium-226 follows an exponential decay model, where the amount of radium remaining decreases by half every 1590 years. The formula for the mass remaining after t years can be derived using the half-life concept. Let M(t) represent the mass remaining after t years, then the equation can be written as \($M(t) = 100 \times 0.5^{t/1590}$\). Here, 100 represents the initial mass of the sample, and 0.5 is the decay constant derived from the half-life.

(b) To find the mass after 1000 years, we substitute t = 1000 into the formula: \($M(1000) = 100 \times 0.5^{1000/1590}$\). Evaluating this expression gives us approximately 87mg.

(c) To determine when the mass will be reduced to 30mg, we need to solve the equation \($M(t) = 30$\) for t. Substituting M(t) and rearranging the equation gives us \($100 \times 0.5^{t/1590} = 30$\). Solving this equation, we find t ≈ 2167 years. Therefore, it will take approximately 2167 years for the mass of the radium-226 sample to be reduced to 30mg.

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Answer:

orce = rate of change of momentum which is m a if the mass is constant

10 Newtons = change of momentum/0.10 second

so change of momentum = 1 kg m/s

by the way the change in speed would be 1/5 = .2 m/s

Explanation:

If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be  1 Ns.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then we have to find out what the impulse exerted by the force on the object.

P = force × time

  = 10 × 0.1

  = 1  Ns

Thus, If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be  1 Ns.

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A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in the spring is formulated as follows

                                                 PE = ½kx²

Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.

In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:

F = kx

Where F is the force acting on the spring, x is the displacement, and k is the force constant,

So that:

F = kx

240 N = 120 N/m . x

x = 240 N/120 N/m

x = 2 m

Once x is known, then we can calculate the potential energy of the spring:

PE = ½kx²

PE = ½ (120) (2²)

PE = 60 x 40

PE = 240 Nm

So, the elastic potential energy stored in the spring is 240 Nm.

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Since the powerful gravitational pull of the Sun, all of the the solar system's planets revolve around it. The Sun basically attracts the solar system's planets, encompassing Earth, as well as allows them to be in orbit.

Kepler's laws of planetary motion was initially published at 1609 and 1619 by Johannes Kepler which implies the description of the main orbits of planets around the Sun.

They explain the following scenarios:

Thus, this way, the orbits of the planets around the sun work.

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25.1 grams are still present after 8.1 days. When the Gold-198 has a half-life of 2.7 days.

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that wants to give up some energy in order to move to a more stable form.

The half-life of the gold  =2.7 days

Sample size  = 200 grams

N is the left amount after the given time =?

Constant of rate = 0.26

The rate constant is found as;

\(\rm \lambda = \frac{0.693}{t^{\frac{1}{2}}} \\\\ \lambda = 0.256 \ days^{-1}\)

The amount after the given time;

\(\rm N=N_0 \times e^{-\lambda t} \\\\\ N = 200 \times e^{-0.256 \times 8.1 \ days} \\\\N=25.1 \ gm\)

Hence,25.1 grams are still present after 8.1 days.

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According to the problem it takes 3 seconds to reach a speed of 29. 4m/s.

Speed is the rate of change in the position of an object over a given period of time. It is a scalar quantity, meaning it is a magnitude with no direction. Speed is the magnitude of the velocity vector. It is measured in units such as meters per second (m/s), kilometers per hour (km/h), or miles per hour (mph). Speed is determined by the formula speed = distance/time.

The equation for calculating the time it takes for an object to reach a certain velocity given an initial velocity of zero is t = (vf - vi) / a,where an is the acceleration, vi is the starting velocity, and vf is the final velocity.

In this case, vf = 29.4 m/s, vi = 0 m/s, and a = 9.8 m/s^2.

t = (29.4 - 0) / 9.8

t = 3 seconds

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Answer:

Work done by the shopper on the cart: The force of 40 N at an angle of 30 degrees downward from the horizontal can be resolved into its horizontal and vertical components. The horizontal component of the force is:F_horizontal = F * cos(theta) = 40 N * cos(30) = 34.64 N

The work done by the shopper on the cart is equal to the force applied multiplied by the distance moved, multiplied by the cosine of the angle between the force and the displacement. In this case, the displacement is 15 m, and the angle between the force and the displacement is 30 degrees. Therefore:Work = F * d * cos(theta) = 34.64 N * 15 m * cos(30) = 448.5 J

Speed of the cart at the tofu section: The initial potential energy of the cart and shopper is equal to their combined mass (85 kg) multiplied by the acceleration due to gravity (9.81 m/s^2) multiplied by the height of Twin Peaks (600 m). 

Therefore: Potential energy = m * g * h = 85 kg * 9.81 m/s^2 * 600 m = 498,690 J

Since the shopper neglects friction, all of the potential energy is converted into kinetic energy at the bottom of the hill. The kinetic energy of the cart and shopper can be found using the formula:

Kinetic energy = 0.5 * m * v^2

where m is the mass of the cart and shopper, and v is their speed.

Therefore:Kinetic energy = 0.5 * 85 kg * v^2 Since the potential and kinetic energies are equal, we can set them equal to each other and solve for the speed v: Potential energy = Kinetic energym * g * h = 0.5 * m * v^2v = sqrt(2 * g * h) = sqrt(2 * 9.81 m/s^2 * 600 m) = 109.43 m/s

Power exerted by the shopper in stopping the cart:The shopper brings the cart to rest over a distance of 15 m in a time of 2.7 s. The average force exerted by the shopper on the cart can be found using Newton's second law: F = m * a = m * (v_f - v_i) / twhere m is the mass of the cart, v_i is the initial speed of the cart (which is zero), v_f is the final speed of the cart, and t is the time taken to stop the cart. Solving for F gives:F = m * (v_f / t)The work done by the shopper in stopping the cart is equal to the force applied multiplied by the distance moved, which is 15 m. Therefore:Work = F * d = m * (v_f / t) * d = 24 kg * (0 - 0) / 2.7 s * 15 m = 0 JSince no work is done in bringing the cart to rest, the power exerted by the shopper is zero.Acceleration due to gravity on the unknown planet:The final speed of the 4 kg ball is 12 m/s, and it falls a distance of 60 m. The initial speed is zero, so the final velocity is equal to the velocity acquired due to gravity. The final velocity can be found using the formula:v_f^2 = v_i^2 + 2 * g * hwhere v_i is the initial velocity (which is zero), h is the height fallen, and g is the acceleration due to gravity.

This statement is true due to the echoing effect that is caused by numerous sound reflections.

The mechanically maximum flux that is transferred by transverse sound pressure in a transparent medium (like air) that is the direct source of hearing is the feeling experienced by the perception of hearing.

Sound power (J/s or W in SI units) is the rate of energy, or sound energy per unit of time, that is emitted by the a source. Acoustic audio power is transmitted as sound travels across a medium. The sound intensity is a vector quantity that has direction thru a surface and is defined as the sound transmitting power through a surface (W/m2).

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Answer:

0.8s

Explanation:

Given parameters:

Height of shelf  = 3m

Unknown:

Time it will take to hit the ground  = ?

Solution:

To solve this problem, we use the expression below;

         x  = ut + \(\frac{1}{2}\) gt²  

x is the height

u is the initial velocity  = 0m/s

g is the acceleration due to gravity  = 9.8m/s²

t is the time taken  = ?

Now insert the parameters and solve for t;

    3  = (0 x t) +( \(\frac{1}{2}\) x 9.8 x t²)

    3 = 4.9t²

       t² = 0.6

       t = 0.8s

The woman exerts a pressure of approximately XXX Pa on the floor.

To calculate the pressure exerted by the woman on the floor, we first determine the force she exerts, which is equal to her weight. Assuming the woman weighs 50.0 kg, we multiply this by the acceleration due to gravity (9.8 m/s²) to find the force of 490 N. The area over which this force is distributed is determined by the circular heel of each shoe. Given a radius of 0.500 cm (0.005 m), we calculate the area using the formula πr². Finally, dividing the force by the area gives us the pressure exerted by the woman on the floor in pascals (Pa).

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Answer:

The products of cellular respiration are carbon dioxide and water

Explanation:

When you talk or listen using a Paper cut telephone you are a part of the system that can be used to transmit sound identify the five main parts of this system are speaker vocal cord , air vibration at speaker's end , travelling of vibration , air vibration at listener's end , sound get heard by the listener .

The five main parts in  Paper cut telephone  are

1) The speakers vocal cord vibrates

2) The air vibrates in the speaker's paper cut pot

3) The voice of speaker travels through the stretched string and reaches the listener's paper cut pot

4) The air in the listener's paper cut pot vibrates

5) The vibrations are heard by the

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The person's final displacement is 1 km.

To determine the final displacement of the person, we need to consider the distances traveled in each direction and their respective signs. In this case, traveling east is considered positive (+) displacement, and traveling west is considered negative (-) displacement.

The person travels 5 km east, so we have a displacement of +5 km.

Then, the person turns around and travels 3 km west. Since the person is now moving in the opposite direction, the displacement would be -3 km.

Finally, the person travels 1 km west, which adds another -1 km to the displacement.

To find the final displacement, we add up the individual displacements:

Final Displacement = (+5 km) + (-3 km) + (-1 km)

Simplifying, we get:

Final Displacement = 5 km - 3 km - 1 km

Final Displacement = 1 km

Therefore, the person's final displacement is 1 km.

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Answer:

Circuit

Explanation:

because a roughly circular line, route, or movement that starts and finishes at the same place.

This question can be solved by using the concepts of electrical energy, electricity, circuit, and electric current.

The flow of electricity from one place to another is called "Electrical Energy".

The electric current or electricity is defined as the rate of flow of electric charges from one point to another point, along a path known as a circuit. Electrical energy is caused by the movement of electric charges or the electric current from one point to another point of the circuit.

Therefore, this flow of electricity or electric current from one place to another place is termed Electrical Energy.

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The attached picture shows examples of electrical energy.

To determine which subatomic particle has a longer lifespan, we compare the average lifetimes of the tau lepton and the neutral pion. The average lifetime of the tau lepton is 2.906 x 10^-12 seconds, and the average lifetime of the neutral pion is 8.4 x 10^-17 seconds.

Comparing these values, we can see that the average lifetime of the tau lepton (2.906 x 10^-12 seconds) is significantly longer than the average lifetime of the neutral pion (8.4 x 10^-17 seconds).

To calculate how many times longer the lifespan of the tau lepton is compared to the neutral pion, we divide the average lifetime of the tau lepton by the average lifetime of the neutral pion:

(2.906 x 10^-12 seconds) / (8.4 x 10^-17 seconds) = 3.453 x 10^4

Therefore, the tau lepton has a lifespan that is approximately 3.453 x 10^4 (34,530) times longer than the neutral pion.

Explanation:

∑τ = Iα

(6 N) (0.80 m) = I (0.5 rad/s²)

I = 9.6 kg m²

ANSWER

EXPLANATION

We want to find out how wings help a plane to fly.

The wings of an airplane are there to help lift the plane. They are shaped to make air move faster over the wings.

They are used for lifting, landing, turning and controlling the airplane. The curve on the wings make the air move faster than the air at the bottom of the wings which appropriates Bernoulli's principle to push the plane into the air.

The wavefunctions for the particle-on-a-ring problem exhibit no preferred position on the ring, meaning that the probability of finding the particle at any specific angle is independent of the angular variable.

In the particle-on-a-ring problem, we consider a particle confined to move along a circular ring. The wavefunction of the particle, denoted by ψ, describes its probability distribution. To demonstrate that the wavefunctions show no preferred position on the ring, we need to show that the probability density, given by ψ∗ψ, is independent of the angular variable ϕ.

The wavefunction for the particle-on-a-ring is given by ψ(ϕ) = (1/√2π)e^(imϕ), where m is an integer representing the angular momentum of the particle. The probability density is given by ψ∗ψ = |ψ(ϕ)|^2 = (1/2π), which is a constant value independent of ϕ. This means that the probability of finding the particle at any particular angle on the ring is the same for all angles.

This result can be understood intuitively by considering the symmetry of the problem. Since the particle is confined to a circular ring, there is no preferred position or direction on the ring. The wavefunction must therefore exhibit this symmetry and be constant throughout the ring.

In summary, the wavefunctions for the particle-on-a-ring problem show no preferred position on the ring because the probability density is constant and independent of the angular variable ϕ.

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Answer:

ok thx lol I like that are you okay??????

Answer:

why do you quit????

Explanation:

Answer:

Movement Time

explanation:

Answer:

We can use the formula for the transformer voltage ratio, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage:

Np/Ns = Vp/Vs

where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.

We know that Vp = 220 V and Vs = 140 V, and we are trying to find Ns. We also know that Np = 30, since that is the number of turns in the primary coil. Substituting these values into the formula, we get:

30/Ns = 220/140

Simplifying the right side of the equation, we get:

30/Ns = 11/7

Cross-multiplying, we get:

11Ns = 210

Dividing both sides by 11, we get:

Ns = 19

Therefore, the answer is b.) 19.

The springs generate a combination of forces.Therefore, it may be said that when springs are utilized in parallel, their constants add up.

In springs the force must be the same. In parallel circuits the sum of all the currents going through each branch must be equal to the total current going into the branches. In parallel springs, the total force from all the springs must equal the total force from the mass.

2. Springs in Parallel: In parallel combination, force developed in each spring will be different but deflection in each spring will be equal.

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