If ACB=DCE CAB=63 ECD=52 and DEC=5x x=?

If the water snake is initially 30 meters below the ground level and then climbs 20 meters upward, it will be 30 - 20 = 10 meters below the ground level. However, if it then slips down 10 meters, it will be 10 + 10 = 20 meters below the ground level.

\(x^2 -8x-2=0\\\\x^2 -8x=2\\\\x^2 -8x+16=18\\\\(x-4)^2 =18\\\\x-4=\pm \sqrt{18}\\\\\boxed{x=4 \pm \sqrt{18}}\)

Answer:

To make a box-and-whisker plot, we first need to order the data from smallest to largest:

4, 5, 6, 10, 15, 16, 21

Next, we can find the median, which is the middle value of the ordered data set. In this case, the median is 10.

Then, we can find the lower quartile (Q1) and the upper quartile (Q3). The lower quartile is the median of the lower half of the data set, and the upper quartile is the median of the upper half of the data set. To find Q1 and Q3, we can split the data set into two halves:

4, 5, 6, 10 and 15, 16, 21

The median of the lower half is (5+6)/2 = 5.5, and the median of the upper half is (16+21)/2 = 18.5. Therefore, Q1 = 5.5 and Q3 = 18.5.

Now we can draw the box-and-whisker plot. The box represents the middle 50% of the data, with the bottom of the box at Q1 (5.5), the top of the box at Q3 (18.5), and the line inside the box at the median (10). The whiskers extend from the box to the smallest and largest values inthe data set that are not outliers. To determine whether there are outliers, we can use the following formula:

Outlier = Q1 - 1.5 * (Q3 - Q1) or Q3 + 1.5 * (Q3 - Q1)

Plugging in the values, we get:

Outlier = 5.5 - 1.5 * (18.5 - 5.5) = -13.25 or Outlier = 18.5 + 1.5 * (18.5 - 5.5) = 37.25

Since there are no values in the data set that are less than -13.25 or greater than 37.25, there are no outliers.

Therefore, the box-and-whisker plot for the given data is:

            |       4

     ___|___

    |              |

    |              |

    |        5.5 |-----  

    |              |      |

    |              |      |

    |------------|  10 |  

    |              |       |

    |      15.5 |------

    |       |      |

     ___|___

            |       21

The box spans from Q1 (5.5) to Q3 (18.5), with the median line inside the box at 10. The whiskers extend from the box to the minimum value of 4 and the maximum value of 21, since there are no outliers.

Hope this helps!

The answer will be 0. 10 >  0. 01 . Option B

Given the values as;

Turn the values into proper fractions

a. 0. 10 = 10/ 100

Reduce to simpler terms

= 10/ 100

= 1/ 10

b. 0. 01 = 1/ 100

a = 1/ 100

b = 1/ 100

This means that both decimals are not of  equal proportion and thus a is greater than (>) b

Thus, the answer will be 0. 10 >  0. 01 . Option B

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Answer:

121

Step-by-step explanation:

firstly you arrange the numbers in ascending order the number in the middle is considered to be the median

According to the information, the unit price of the products is: $0.28 for each can of soft drink, $0.022 for each ounce of detergent, $0.18 for each ounce of peanuts, $0.0033 for each gram of cooked chicken.

To calculate the unit price of the products we must perform the following procedure:

We must divide the value of each product into the amount of product as shown below:

Accordingly, the unit price of these products is the result of these divisions.

Note: This question is incomplete. Here is the complete information:

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Answer: True

Step by step explanation

Based on the limited information provided, it is not possible to definitively determine the type of economy in Country A. More specific details and factors would be necessary to make a conclusive determination.

9514 1404 393

Answer:

 8/65 -(1/65)i

Step-by-step explanation:

When there is a complex number in the denominator, the denominator can be made real by multiplying numerator and denominator by the conjugate of the denominator.

  \(\dfrac{1}{8+i}=\dfrac{8-i}{(8+i)(8-i)}=\dfrac{8-i}{8^2-i^2}=\boxed{\dfrac{8}{65}-\dfrac{1}{65}i}\)

Answer:

Step-by-step explanation:

The first part is a computation, combining the chain and quotient rules. We know that the derivative of f(x)=arcsin(x) is 1/sqrt(1-x2), and we need to differentiate the denominator. We use the chain rule: let u=1-x^2, and v=sqrt(u). Then du/dx=-2x, and dv/du = 1/(2 sqrt(u)). Combining, dv/dx=-x/sqrt(1-x2). Now, we put everything together using the quotient rules: y' = (f'v-v'f)/v2. Multiplying by (1-x2)=v2, we obtain (1-x2)y'= sqrt(1-x2)/sqrt(1-x2) +xarcsin(x)/sqrt(1-x2), which we can rewrite as 1+xy, as desired. Let's call this equation ().

We prove the second part by induction on n. To do this, we need two things: a base case, that is, proving the case n=0, and an inductive step, where we prove case n+1 from case n. To do the base case, we differentiate both sides of equation (*) that we proved above: d/dx ((1-x2 )y') = d/dx (xy+1 ). On the left-hand side, we get -2xy'+(1-x2 )y'', using the product rule, and on the right-hand side, we get xy'+y, similarly. Rearranging, we've proven the case n=0 of the desired statement. The inductive step is similar: we differentiate the equation from case n using the chain rule. Each of the first two terms splits into two: respectively, -2xy(n+2)+(1-x2)y(n+3), and (2n+3)y(n+1)+(2n+3)xy(n+2). If we combine the terms with the same numbers of derivatives on y, we get (1-x2)y(n+3)-(2n+5)xy(n+2)-((n+1)2+2n+3)y(n+1)=0 -which is what we wanted to prove, since ((n+1)2+2n+3) simplifies to (n+2)2.

Answer:

4

Step-by-step explanation:

multiply 10 by w and 3

equation becomes 10w+30=70

subtract 30 by both sides

equation becomes 10w=40

divide both sides by 10

equation becomes w=4

your answer is 4!

The probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%

It is a branch of mathematics that deals with the occurrence of a random event.

Given,

Amounts of weight that male college students gain during their freshman year are normally distributed

mean of μ = 1.1 kg and

Standard deviation of o= 4.6 kg.

Z score=x-μ/o

=25-1.1/4.6

=23.9/4.6

=5.196

Z score=x-μ/o

=25-1.1/0

=0

Z score=25-1.1/3

=23.9/3

=7.966

By observing the z table the probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%

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The area of a square inscribed in a circle is 25, then the area of the circle is 25π/2 or approximately 39.27 square units.

To solve this problem, we can use the relationship between the area of a square inscribed in a circle and the area of the circle itself.

When a square is inscribed in a circle, the diagonal of the square is equal to the diameter of the circle. Let's assume that the side length of the square is 's' and the radius of the circle is 'r'.

We are given that the area of the square is 25, so we can find the side length of the square:

Area of square = \(s^2 = 25\)

Taking the square root of both sides, we get:

s = √25 = 5

Since the diagonal of the square is equal to the diameter of the circle, we can find the diameter of the circle:

Diagonal = Diameter = s√2 = 5√2

The radius of the circle is half the diameter, so:

Radius = 5√2 / 2 = (5√2)/2

Now, we can calculate the area of the circle using the formula:

Area of circle = \(\pi r^2\)

Substituting the value of the radius, we get:

Area of circle = π((5√2)/\(2)^2\) = π(25/2) = 25π/2

Therefore, the area of the circle is 25π/2 or approximately 39.27 square units.

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Answer: 70, 6

Step-by-step explanation:

(a)  For <F  that is the same as <D.  The image has little hash marks to indicates the sides across from those angles are the same; therefore, the angles are the same

All of the angles are = 180   if you subtract <E, you are left with 140 to be split between <F and <D

<F= 70

(b) all of the sides are the same because all the angles are the same

so AB=6

Answer:

24

6

3

4.50

Step-by-step explanation:

3 x 8

1.5 x 4

.5 x 6

1.5 x3

The measures of m∠3 and m∠6 is equal to 60°.

What are Parallel Lines?

Given that, the line m is parallel to line n.

Also, m∠3 = (7x-10)° and m∠6 = (5x + 10)

Since, the lines m and n are parallel, we have

m∠3 = m∠6

⇒ 7x - 10 = 5x + 10

⇒ 7x - 5x = 10 + 10

⇒ 2x = 20

⇒ x = 10

So, we get m∠3 as

m∠3 = 7 (10) - 10

⇒ m∠3 = 60°

Also, we get m∠6 as

m∠6 = 5 (10) + 10

⇒ m∠6 = 60°

Therefore, the measures of m∠3 and m∠6 is equal to 60°.

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The two students that mix the same ratio of juice to water is given as follows:

A. Luca.

D. Micah.

The ratio between two amounts a and b is given as follows:

a to b.

Which is also the division of the two amounts.

Hence the ratio of juice to water for each person is given as follows:

Hence Luca and Micah used the same ratio, meaning that options A and D are correct.

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Answer:

50% black card ( or 26)

76% no face ( or 40)

Answer:

1.32 not zero

Step-by-step explanation:

Answer:

b and c for future help look up and equivalent calculator

Answer:— If the measure of arc AB is 64 degrees, what is the measure of angle ADB?0 64 degrees 128 degrees 32 degrees 90 degrees.

Step-by-step explanation:

we know that

Two variables have a positive association / correlation when the values of one variable tend to increase as the values of the other variable increase.

so

see the attached figure

this is an example of positive association

The percentage of tornadoes that were EF1s is 40%.

What is the percentage?

A figure or ratio stated as a fraction of 100 is called a percentage. The acronyms pct., pct., and occasionally pc are also used to indicate it, however, the percent sign is most frequently used. A % is a number without dimensions and without a standard measurement.

Here, we have

Given: the strengths of tornadoes that occurred in Alabama in 2011.

We have to find the percentage of tornadoes that were EF1s.

EF1s = 58

Total = 145

percentage of tornadoes = 58/145 = x/100

5800/145 = x

x = 40%

Hence, the percentage of tornadoes that were EF1s is 40%.

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x = 2.67 is the solution to the equation -6x + (3)(2x) = 16.

What is the Algebraic Equations?

Algebraic equations are mathematical statements that describe a relationship between two or more variables, where one variable is expressed in terms of the others.

To solve the equation -6x + (3)(2x) = 16, we can simplify the expression on the left-hand side first:

-6x + (3)(2x) = -6x + 6x = 0x = 0

Next, we isolate the x term on one side of the equation by subtracting 16 from both sides:

0x = 0 - 16 = -16

Finally, we can solve for x by dividing both sides of the equation by -6:

x = -16 / -6 = 2.67 (rounded to two decimal places).

So, x = 2.67 is the solution to the equation -6x + (3)(2x) = 16.

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Answer:

You need to multiple

Step-by-step explanation:

Matching of the functions domain and range are as follows:

f(x)   = 4-4x ;

Domain:{0,1,3,5,6}

Range;{-20,-16,-8,0,4}

f(x) = 5x - 3

Domain:{-2,-1,0,3,4}

Range:{-13,-8,-3,12,4}

f(x) = -10x

Domain:{-4,-2,0,2,4}

Range:{-40,-20,0,20,40}

f(x) = (3/x) + 1.5

Domain:{-3,-2,-1,2,6}

Range:{0.5,0,-1.5,3,2}.

1) The function f(x) = 4 - 4x

Take Domain:{0,1,3,5,6}

If, we take x=0 and put in the function then we get

f(x)=4-0

f(x)=4

put x=1

f(x) = 4 - 4 =0

put x=3 then we get

f(x)=4-12=--8

put x=5 them we get

f(x)=4-20=-16

put x=6 then we get

f(x)=4-24=-20

Therefore ,range:[-20,-16,-8,0,4}

2) The function f(x)=5x-3

Take domain{-2,-1,0,3,4}

Now, put x=-2 in the function then we get

f(x) = -13

now put x=-1 then we get

f(x)=-5-3=-8

Put x=0 then we get

f(x)=0-3=-3

Put x=3 then we get

f(x)=15-3=12

Put x=4 then we get

f(x)=20-3=17

Therefore , range:{-13,-8,-3,12,17}

3) The function f(x)=-10x

Take domain:{-4,-2,0,2,4}

Put x=-4 in the function then we get

f(x)=40

Put x= -2 then we get

f(x)=20

Put x=0 then we get

f(x)=0

Put x=2 then we get

f(x)=-20

Put x=4 then we get

f(x)=-40

Therefore , range :{-40,-20,0,20,40}

4) The function f(x)= (3/x) + 1.5

Take domain:{-3,-2,-1,2,6}

Put x= -3 in the taken function then we get

f(x)=-1+1.5=0.5

put x=-2 then  we get

f(x)= -1.5+1.5=0

Put x=-1 then we get

f(x)=-3+1.5=-1.5

Put x= 2 then we get

f(x)=1.5+1.5=3

Put x= 6 then we get

f(x)=0.5+1.5=2

Therefore, range : {0.5,0,-1.5,3,2}.

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The exponential form of 6 × 6, is written as: 6².

Repeated multiplication involving base exponents and base can be written in exponential form, such as: a × a × a = a³.

Given the expression, 6 × 6, the number 6 will be the base while 2 will be the exponent if we want to express it in exponential form. Therefore:

6 × 6 = 6².

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The location which is in the region for plants receiving the maximum amount of water is "(-3,-1)". The Option A is correct.

Water flows into the open pore spaces in the soil by gravity, and the size and spacing of the soil particles determine how much water can flow in. Because coarse soils have larger pore spacing at the soil surface, they have a higher infiltration rate than fine soils.

Based on the graph, we observed that the point of location in which is in the region for plants receiving the maximum amount of water is the point (-3,-1). Therefore, we agree that Option A is correct.

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