If photosynthesizing Chlorella (a unicellular green alga) cells are supplied with water made with 18O (H218O) and the cells are allowed to photosynthesize for a short period of time, where are we likely to find the heavy oxygen?

The elements arranged in increasing order of the most positive electron affinity for each group are:

(a) Li, Na, K

(b) I, Br, Cl, F

(c) Ba, Ca, Si, P, O

(a) Li, Na, K: In this group, the electron affinity increases as we move from left to right in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Li, Na, and K.

(b) F, Cl, Br, I: In this group, the electron affinity generally increases as we move from left to right and from bottom to top in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are I, Br, Cl, and F.

(c) O, Si, P, Ca, Ba: In this group, the electron affinity generally increases as we move from left to right and from top to bottom in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Ba, Ca, Si, P, and O.

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The density of copper having a molar volume of 7.09 cm³/mol at 25℃ is 8.96 g·cm⁻³.

The density of copper is the ratio of its mass to volume. That is, we need to calculate the mass of 1 cm³ of copper, which is equal to the density of copper. We can use the molar mass of copper to find out the mass of 1 mole of copper.

Molar mass of copper (Cu) = 63.5 g·mol⁻¹

We know that 1 mole of copper has a volume of 7.09 cm³. We can use this information to find the mass of 1 cm³ of copper.

Mass of 1 cm³ of copper = Mass of 1 mole of copper ÷ Volume of 1 mole of copper = 63.5 g ÷ 7.09 cm³ = 8.96 g/cm³

Therefore, the density of copper at 25℃ is 8.96 g·cm⁻³.

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Note that the point at which oxygen changes from liquid to gas is 90k. See the attached graph.

To plot the data, we can use a line graph with temperature (T) on the x-axis and density (d) on the y-axis. Here is a plot of the data:

From the plot, we can see that the density of oxygen decreases as the temperature increases. At around 90 K, there is a significant drop in density, indicating a change in state from liquid to gas. We can circle this temperature as the point at which oxygen changes from liquid to gas.

Therefore, we can circle the temperature 90 K as the point at which oxygen changes from liquid to gas.

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80g•1moles/68.94g= 1.16g

Answer:

See explanation

Explanation:

Recall that;

Speed = Distance/time

Distance = Speed * time

Speed = 200 km/h

Time = 4 hours

Distance = 200 km/h * 4 hours = 800 kilometres

Displacement has to do with distance covered in a specified direction, in this case, the direction is towards Zambales.

Hence, the displacement is  800 kilometres towards Zambales.

Answer : The molecular formula of benzoyl peroxide is \(C_{14}H_{10}O_4\)

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

\(n=\frac{\text{Molecular mass}}{\text{Empirical mass}}\)

As we are given that the molar mass of compound is, 0.242 kg/mol.

Molecular mass = 0.242 kg/mol = 242 g/mol      (1 kg = 1000 g)

The empirical mass of \(C_7H_5O_2\) = 7(12) + 5(1) + 2(16) = 121 g/eq

\(n=\frac{\text{Molecular mass}}{\text{Empirical mass}}\)

\(n=\frac{242}{121}\)

\(n=2\)

Molecular formula = \((C_7H_5O_2)_n\) = \((C_7H_5O_2)_2\) = \(C_{14}H_{10}O_4\)

Thus, the molecular formula of benzoyl peroxide is \(C_{14}H_{10}O_4\)

Answer:

Melting point

Explanation:

Melting point is a intensive property and Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.

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Answer:

Explanation:

Yes melting point!

In the presence of excess oxygen, there is a greater production of CO2 and ATP molecules compared  to the absence of oxygen in anaerobic

respiration.

Glucose is the energy molecule that is the end product of the digestion of carbohydrates. During cellular respiration, the glucose molecule is broken down to release carbon dioxide, water and ATP.

In the presence of excess oxygen, there is a greater production of CO2 and ATP molecules compared  to the absence of oxygen in anaerobic

respiration.

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The complete nuclear equation is;

253/99 Es + 4/2He → 256/101 Md + 1/0n

The atomic and mass numbers of the particles involved are displayed in a nuclear equation, which is a symbolic depiction of a nuclear process. It is used to explain the alterations that take place inside atomic nuclei during nuclear reactions, such as radioactive decay, fusion, and fission.

Typically, nuclear equations have two sides that are divided by an arrow. On the left side of the arrow are the reactants, or initial particles, and on the right side are the products, or final particles. The arrow denotes the process of transformation or reaction.

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the answer is 19.95 g H2O (rounded to two decimal places). So, the closest option to this answer is 19.97 g H2O.

The balanced equation is:

3 CuO + 2 H3PO4 --> Cu3(PO4)2 + 3 H2O

According to the equation, 2 moles of H3PO4 react to form 3 moles of H2O. Therefore, we can set up a proportion to find the amount of H2O produced:

2 mol H3PO4 : 3 mol H2O

x grams H3PO4 : y grams H2O

To find y, we need to convert the given mass of H3PO4 to moles using its molar mass:

72.41 g H3PO4 × (1 mol H3PO4 / 98.0 g H3PO4) = 0.738 mol H3PO4

Now we can use the proportion to find y:

2 mol H3PO4 / 3 mol H2O = 0.738 mol H3PO4 / y mol H2O

y = 1.107 mol H2O

Finally, we can convert the number of moles of H2O to grams using its molar mass:

1.107 mol H2O × (18.015 g H2O / 1 mol H2O) = 19.95 g H2O

Therefore, the answer is 19.95 g H2O (rounded to two decimal places). So, the closest option to this answer is 19.97 g H2O.

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Mass of evaporating dish and cover=19.50 grams mass of evaporating dish, cover and lead = 22.45 grams mass of evaporating dish, cover and lead oxide product=22.90 grams.The empirical formula for the product is PbO.

An empirical formula is a compound's chemical formula that only specifies the ratios of the elements it contains and not the precise number or arrangement of atoms. This would be the compound's element with the lowest whole number ratio.

Given:

A.Dish + Cover = 19.50 gram

B.Dish + Cover + lead = 22.45 grams grams

C.Dish + Cover + lead oxide = 22.90 grams

Mass of lead reacted = B-A

= 22.45 grams - 19.50 gram

= 2.95 gram

No. of moles of lead = 2.95/207.2

= 0.01g/mol

Mass of lead oxide = C-A

= 22.90 - 19.50

= 3.4 gram

Mass of oxygen in lead oxide = 3.4 - 2.95

= 0.45g

Number of moles of oxygen = 0.45/16

= 0.028moles

Therefore, it is PbO.

Thus, the empirical formula for the product is PbO.

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The percentage (w/v) of dextrose in the solution is approximately 1.9817%. To determine the percentage (w/v) of dextrose in a solution with a given osmolarity, we need to calculate the amount of dextrose present in 100 mL of the solution.

First, we convert the osmolarity from mosmol/L to mosmol/100 mL:

100 mosmol/L = 100 mosmol/100 mL

Next, we calculate the number of moles of dextrose present in 100 mL of the solution:

Number of moles = Osmolarity (in mosmol/100 mL) / 1000

Number of moles of dextrose = 100 mosmol/100 mL / 1000 = 1 mosmol/100 mL

Now, we can calculate the mass of dextrose present in 100 mL of the solution:

Mass of dextrose = Number of moles of dextrose * Molecular weight of dextrose

Mass of dextrose = 1 mosmol/100 mL * 198.17 g/mol = 1.9817 g/100 mL

Finally, we can calculate the percentage (w/v) of dextrose:

Percentage (w/v) = (Mass of dextrose / Volume of solution) * 100

Percentage (w/v) = (1.9817 g/100 mL / 100 mL) * 100 = 1.9817%

Therefore, the percentage (w/v) of dextrose in the solution is approximately 1.9817%.

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Answer:

2. Chemical reactions changes occur when the bonds between atoms in a molecule are created or destroyed.

3. When you reach your its boiling point, the molecules in liquid have enough energy to become a gas.

4. When you have a solid with more than one type of compound, it is called a mixture.

5. A Crystal is a form of solid where the atoms are arranged is a very specific order.

6. If you have different types of molecules dissolved in a liquid, it is called a solution

Answer:

151.87dm³

Explanation:

Given parameters:

Volume of hydrogen gas  = 6.78mole

Unknown:

Volume of hydrogen gas formed at STP  = ?

Solution:

To solve this problem;

   1 mole of a gas at STP  = 22.4dm³ So;

   6.78 mole of gas  = 6.78 x 22.4  = 151.87dm³

It would require approximately 19,008 joules of energy to heat a frozen can of juice (360 grams) from -5 °C to 110 °C.

We need to use the specific heat capacity formula:

Q = mcΔT

Where

First, we need to convert the mass of the can of juice from grams to kilograms:

m = 360 g = 0.360 kg

Next, we need to find the specific heat capacity of the juice. The specific heat capacity varies depending on the type of juice, but for the purposes of this calculation, we can assume a value of around 4200 J/kg°C, which is the specific heat capacity of water.

c = 4200 J/kg°C

Finally, we can calculate the energy required to heat the can of juice:

Q = mcΔT

Q = (0.360 kg)(4200 J/kg°C)(110°C - (-5°C))

Q = (0.360 kg)(4200 J/kg°C)(115°C)

Q = 19,008 J

Therefore, it would require approximately 19,008 joules of energy to heat a frozen can of juice (360 grams) from -5 °C to 110 °C.

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Answer:

i think the first one is gravity and second one is rotation

Explanation:

The volume of the 0.7×10⁻³ M NaOH solution needed is 1.79 mL

The following data were obtained from the question:

The volume of the stock solution needed can be obtained as follow:

M₁V₁ = M₂V₂

0.7×10⁻³ × V₁ = 0.5×10⁻⁴ × 25

Divide both side by 0.7×10⁻³

V₁ = (0.5×10⁻⁴ × 25) / 0.7×10⁻³

V₁ = 1.79 mL

Thus, the volume of the stock solution needed is 1.79 mL

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The percent composition of an element in a compound can be found by the following formula:

Therefore, we must first find the weight of the lead(II) nitride molecule. The molecular formula of lead (Il) nitride is Pb3N2, so the molar mass of the element will be:

Molar Mass Pb3N2= Atomic Mass Pb x 3 + Atomic Mass N x 2

the values of the atomic mass of the elements are found in the periodic table.

Atomic Mass Pb=207.2u

Atomic Mass N=14.0067u

So, the molar mass of Pb3N2 will be:

The percent composition of nitrogen in Pb3N2 will be:

Answer: The percent composition of nitrogen in a compound of lead (Il) nitride is 4.31%

you decide to test your pillbugs' preference for an acidic environment versus a nonacidic environment. on one side of the chamber you place filter paper moistened with water. Dry filter paper is appropriate to place on the other side to test this variable.

Armadillidiidae (Pillbugs) is a family of woodlice, a terrestrial crustacean group in the order Isopoda. Unlike members of some other woodlice families, members of this family can roll into a ball, an ability they share with the outwardly similar but unrelated pill millipedes and other animals. This ability gives woodlice in this family their common names of pill bugs or roly polies.Other common names include slaters, potato bugs, and doodle bugs. Most species are native to the Mediterranean Basin, while a few species have wider European distributions. The best-known species, Armadillidium vulgare, was introduced to New England in the early 19th century and has become widespread throughout North America.

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Answer:

This equation is already balanced.

Explanation:

If your teacher requires that you put coefficients in front of each compound, then put a 1 in front of every compound.

Answer:

warming

Explanation:

True: Oxygen molecules at 25°C are moving faster than oxygen molecules at 0°C. Gases exert pressure by colliding with container walls.

False: In a sample of hydrogen gas at 25°C, all hydrogen molecules are not moving with the same velocity. Nitrogen gas exerts more pressure than hydrogen gas because nitrogen molecules are heavier than hydrogen molecules. Nitrogen molecules remain suspended in the atmosphere not because they are not attracted to Earth by gravitational forces.

Explanation:

Oxygen molecules at higher temperatures have more kinetic energy, resulting in faster movement compared to oxygen molecules at lower temperatures. This statement is true.

In a sample of hydrogen gas at 25°C, individual hydrogen molecules have a distribution of velocities due to the Maxwell-Boltzmann distribution. Hence, not all hydrogen molecules move with the same velocity. This statement is false.

The pressure exerted by a gas is not solely determined by the mass of its molecules. It depends on factors such as the number of gas molecules, temperature, and volume. Therefore, the statement that nitrogen gas exerts more pressure than hydrogen gas because nitrogen molecules are heavier is false.

Gases exert pressure by colliding with the walls of the container. This statement is true as the kinetic energy of gas molecules leads to frequent collisions with the container walls, resulting in pressure.

Nitrogen molecules remain suspended in the atmosphere due to Earth's gravitational forces. Gravity affects all objects with mass, including nitrogen molecules. The statement that nitrogen molecules are not attracted to Earth by gravitational forces is false.

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Answer:

Explanation:

At the outer zone of candle flame, there are more oxygen available for the combustion reaction. So the flame is yellow in color.

The answer is D. yellow.

Answer:

B. blue

Explanation:

The candle's flame is divided into three zones: blue on the outside, yellow in the midst, and black on the inside. This is the result of the wax that is formed after the meltdown of the candle.

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1. A neutron outside a nucleus decays into a proton, electron, and antineutrino: This process is known as beta decay, and it is governed by the weak nuclear force. The weak nuclear force is responsible for interactions involving particles that undergo radioactive decay, such as the transformation of a neutron into a proton.

2. Protons and neutrons attract each other in a nucleus: This is the result of the strong nuclear force, also known as the strong interaction. The strong force is responsible for binding protons and neutrons together within the atomic nucleus. It overcomes the electromagnetic repulsion between positively charged protons and holds the nucleus together.

3. The Earth pulls on the Moon: This is an example of gravitational interaction. Gravity is responsible for the attractive force between objects with mass. In this case, the Earth's gravitational pull is responsible for the Moon orbiting around it.

4. Protons in a nucleus repel each other: This is due to the electromagnetic force, which is responsible for interactions between charged particles. Protons, being positively charged, repel each other due to the electromagnetic repulsion. It is the electromagnetic force that prevents the nucleus from collapsing under the repulsive forces between protons.

Understanding the fundamental interactions helps us explain the behavior and interactions of particles at the atomic and subatomic level, providing insights into various natural phenomena and the structure of matter.

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Match the process with the fundamental interaction responsible for this process. - Protons in a nucleus repel each other. -The Earth pulls on the Moon. -Protons and neutrons attract each other in a nucleus. -A neutron outside a nucleus decays into a proton, electron, and antineutrino. with these : 1- The electromagnetic interaction 2- the gravitational interaction 3- The weak interaction 4- The strong interaction

The hypothetical atom 3415X1534X contains B. 34 protons, and E. 49 nucleons.


The given atom is represented as 3415X1534X, where the first number (34) is the atomic number and the second number (15) is the mass number.

A. 15 orbital electrons: Incorrect. The atomic number (34) represents the number of protons and also the number of electrons in a neutral atom. Therefore, there are 34 electrons, not 15.

B. 34 protons: Correct. The atomic number (34) represents the number of protons in the atom.

C. 15 protons: Incorrect. The atomic number (34) represents the number of protons in the atom, not 15.

D. 19 neutrons: Incorrect. The mass number (15) represents the total number of protons and neutrons in the atom. To find the number of neutrons, subtract the number of protons (34) from the mass number (15): 15 - 34 = -19. However, a negative number of neutrons is not possible, so this choice is incorrect.

E. 49 nucleons: Correct. The term "nucleons" refers to the total number of protons and neutrons in the atom. In this case, there are 34 protons and 15 neutrons, so there are a total of 34 + 15 = 49 nucleons.

In summary, the hypothetical atom 3415X1534X contains 34 protons and 49 nucleons.

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Option B and D are false about chemical equilibria.

Option A is true, at equilibrium, there is no net change in the concentrations of the reactants and products. The rates of the forward and reverse reactions are equal, so the concentrations of the reactants and products remain constant.

Option C is also true, the relative amounts of the reactants and products may not necessarily be equal. The equilibrium constant (Kc) gives information about the relative amounts of the reactants and products at equilibrium, but it does not necessarily mean that they are equal.

Option B is false because concentrations of products and reactants do not oscillate between a set range of values at equilibrium. The concentrations remain constant, and any small fluctuations are quickly balanced by the reverse reaction to restore the equilibrium.

Option D is false because at equilibrium, the forward and reverse reactions are still occurring, but at the same rate. It is a dynamic equilibrium, and the system is constantly shifting back and forth between the reactants and products, but the overall concentrations remain constant.

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The ranking of the given carboxylic acids in order of increasing acid strength is as follows: B < A < D < C.

The reason for this trend is that electron-withdrawing fluorine atoms in the carboxylic acids increase the acidity of molecule by withdrawing electron density from the carboxyl group, which makes it easier to release a proton. The more electron-withdrawing the substituents, more acidic the carboxylic acid. In this case, compound C has the strongest electron-withdrawing group (CF3), which makes it most acidic of the four. Compound D has a weaker electron-withdrawing group (CHF2), making it less acidic than C but more acidic than B. Therefore, the acid strength of the given carboxylic acids can be ranked as: C > D > A > B.

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