To find Α n Α, we need to find the intersection of the two subsets A={1,3,5,11) and A={1,3,5,11). The intersection of two sets is the set of elements that are common to both sets. Therefore A ∩ A = {1, 3, 5, 11}.
In this case, we can see that the common elements in A and A are 1, 3, 5, and 11. Therefore, the intersection of A and A is {1, 3, 5, 11}.
It's worth noting that since A and A are the same set, their intersection is simply the set itself. This is because all the elements in A are also in A, and vice versa.
In general, when we talk about sets, the universal set U refers to the set of all possible elements, and subsets are smaller sets that are contained within the universal set. The intersection of two sets is the set of elements that are common to both sets, and it's denoted by the symbol 'n'.
Hi! It looks like you want to find the intersection of subsets A and A, using the given universal set U. Here's a step-by-step explanation:
1. The universal set U = {0, 1, 2, 3, 4, 5, 6, 7, 9, 11}
2. Subset A = {1, 3, 5, 11}
3. To find the intersection of A and A (written as A ∩ A), we need to find the elements that are common to both subsets A and A.
Since A and A are the same sets, their intersection will include all the elements present in subset A.
So, A ∩ A = {1, 3, 5, 11}.
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Find the product.
a 413 a 22a + 1)
3 a
-2 a
+1a
Answer:
\(=13a^{437}+12a\)
Step-by-step explanation:
\(\left(a^{413}a^{22}a+1\right)\cdot \:13a-2a+1\cdot \:a\)
\(\mathrm{Add\:similar\:elements:}\:-2a+1\cdot \:a=-a\)
\(=\left(a^{413}a^{22}a+1\right)\cdot \:13a-a\)
\(=\left(a^{436}+1\right)\cdot \:13a-a\)
\(=13a\left(a^{436}+1\right)-a\)
\(=13a^{437}+13a-a\)
\(\mathrm{Add\:similar\:elements:}\:13a-a=12a\)
\(=13a^{437}+12a\)
Kite ABCD is drawn with diagonals. To find the area of ABCD, Alex imagined the kite divided into two triangles. What is the area of ABCD?
The area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.
How to find the area of ABCD?Since kite ABCD is divided into two triangles by its diagonals, we can find the area of the kite by finding the sum of the areas of these two triangles.
Let AC and BD be the diagonals of the kite, intersecting at point E. Then triangle ABE and triangle CDE are the two triangles formed by the diagonals.
The area of a triangle can be found using the formula: Area = (base x height) / 2
For triangle ABE, the base is AB and the height is the distance from E to the line containing AB. Similarly, for triangle CDE, the base is CD and the height is the distance from E to the line containing CD.
Since the diagonals of a kite are perpendicular and bisect each other, the distance from E to the line containing AB is the same as the distance from E to the line containing CD.
Therefore, the heights of the two triangles are equal.
So, we can find the area of ABCD as follows:
Area of ABCD = Area of triangle ABE + Area of triangle CDE
= (AB x height)/2 + (CD x height)/2
= (AB + CD) x height / 2
Therefore, the area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.
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Expand this equation to write an identity: (a-b)^3
The equation using the identity rule is a^3 - 3a^2b + 3ab^2 - b^3
How to expand the equation using the identity ruleThe equation (a-b)^3 can be expanded using the binomial theorem, where the variables are the two numbers (a and b),
From the question, we have the following parameters that can be used in our computation:
(a-b)^3
When expanded, we have
a^3 - 3a^2b + 3ab^2 - b^3
Hence, the expansion is a^3 - 3a^2b + 3ab^2 - b^3
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please help or I fail
Answer:
G
Step-by-step explanation:
you just see the place value of the number you are multiplying by and you you put the place value. For example ( 3× 0.01) is going to be ( 0.03) if it makes it easier just take the 3 and substitute it for the 1.
Hope this helped : )
Warren earns $21.75 per hour and worked 36.5 hours last week and 32 hours the
week before. What is Warren's gross pay for the two weeks? Show your work.
Answer:
$1,489.88 (nearest cent)
Step-by-step explanation:
To calculate gross pay, multiply the number of hours worked by the pay per hour.
Warren worked 36.5 hours one week and 32 hours the week before.
Therefore, the total number of hours Warren worked was:
36.5 + 32 = 68.5 hoursMultiply the total number of hours worked by Warren's rate of pay of $21.75 per hour:
68.5 × 21.75 = 1489.875Therefore, Warren's gross pay for the two weeks was $1,489.88 (nearest cent).
Answer:
$1489.875
Step-by-step explanation:
Warren's gross pay for 36.5 hours last week can be calculated as follows:
Gross pay for 36.5 hours = $21.75/hour * 36.5 hours = $793.875
Similarly, Warren's gross pay for 32 hours the week before can be calculated as follows:
Gross pay for 32 hours = $21.75/hour * 32 hours = $696
Adding the gross pay for the two weeks, we get:
Gross pay for 2 weeks = $793.875 + $696 = $1489.875
help me solve this problem please
Answer:
Step-by-step explanation:
If you put all the numbers on the number line it would be, -4/3, -4/5, -2/3, 7/10, 7/10, so the correct answer is letter A.
.Independent random samples of business managers and college economics faculty were asked to respond on a scale from 1 (strongly disagree) to 7 (strongly agree) to this statement: Grades in advanced economics are good indicators of students’ analytical skills. For a sample of 70 business managers, the mean response was 4.4 and the sample standard deviation was 1.3. For a sample of 106 economics faculty, the mean response was 5.3 and the sample standard deviation was 1.4.
a) Test, at the 5% level, the null hypothesis that the population mean response for business managers would be at most 4.0. (10marks)
b) Test, at the 5% level, the null hypothesis that the population means are equal against the alternative that the population mean response is higher for economics faculty than for business managers. Assume unequal variance.
Step-by-step explanation:
a) The test statistic is (4.4-4)/(1.3/sqrt(70)) = 2.83. The p-value is 0.0023. Since the p-value is less than 0.05, we reject the null hypothesis.
b) The test statistic is (5.3-4.4)/sqrt((1.4^2/106)+(1.3^2/70)) = 4.09. The p-value is less than 0.0001. Since the p-value is less than 0.05, we reject the null hypothesis.
Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2).
y = mx + b
1. Substitute the known values: negative 2 = negative two-fifths (15) + b. 2. Solve for b: negative 2 = negative 6 + b. b = 4.
What is the equation of the line in slope-intercept form?
Negative 2 = negative two-fifths x + 4
y = negative two-fifths (15) + 4
y = negative two-fifths x minus 4
y = negative two-fifths x + 4
Answer:
y=negative two fifths x plus 4
Step-by-step explanation:
DNA tbh ishrb jd ge kem is j.g cr. ks i.v rgjs gusnrie84b isbsuosb sojdl
Answer:
its A
Step-by-step explanation:
mark me brainliest
pls and ty
<3 anmol
what is this answer to this question?
Answer:
13?
Step-by-step explanation:
find the nth term of 11, 20, 35, 56, 83, . . .
nth number is 83 hope you understand my answer thanks
Answer: 3n^2 + 8
Step-by-step explanation:
an^2 + bn + c
It is a quadratic sequence
11, 20, 35, 56, 83
+8 +15 +21 +27
+6 +6 +6
a + b + c
4a + 2b + c
9a + 3b + c
4a + 2b + c - a + b + c = 20 - 11
4a + 2b + c - a + b + c = 9
3a + b = 9
9a + 3b + c - 4a + 2b + c = 35 - 20
5a + b = 15
-2a = -6
a = -6/-2
a = 3
Substitute to find the values of b & c
For b
5(3) + b = 15
15 + b = 15
b = 15 - 15
b = 0
For c
9(3) + 3(0) + c = 35
27 + c = 35
c = 35 - 27
c = 8
3n^2 + 0n + 8
3n^2 + 8
Determine all values of h and f for which the system x + 3y = h and -4x + ky = -9 has no solution.
For any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.
To determine the values of h and okay for which the device of equations has no answer, we want to locate the situations underneath which the equations are inconsistent or parallel.
The given system of equations is:
Equation 1: x + 3y = h
Equation 2: -4x + ky = -9
For the gadget to haven't any answer, the lines represented with the aid of these equations should be parallel and in no way intersect. In different phrases, the slopes of the traces need to be equal, but the y-intercepts should be specific.
Let's first discover the slopes of the traces. The slope-intercept form of Equation 1 is y = (-1/3)x + (h/3), wherein the slope is -1/3. The slope-intercept shape of Equation 2 is y = (4/k)x - (9/k), wherein the slope is 4/k.
For the strains to be parallel, the slopes should be equal. Therefore, we have the condition: -1/3 = 4/k.
To locate the values of h and okay for which the gadget has no answer, we need to locate the values of h that satisfy the situation -1/3 = 4/k.
Solving this equation for ok, we've got:
-1/3 = 4/k
-1 = 12/k
k = -12
Substituting k = -12 returned into the equation -1/3 = 4/k, we've:
-1/3 = 4/(-12)
-1/3 = -1/3
Since the equation holds real for any value of h, there aren't any restrictions at the price of h.
Therefore, for any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.
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The system of equations has no solution when k is equal to 12. The value of h can be any real number.
To determine the values of h and f for which the system has no solution, we need to analyze the coefficients of the variables and the constants in the equations.
The given system of equations is:
x + 3y = h
-4x + ky = -9
We can rewrite the second equation as:
-4x + ky = -9
Dividing both sides of the equation by -4, we get:
x - (k/4)y = 9/4
Comparing the coefficients of x and y in the two equations, we can see that the slopes of the lines represented by the equations are different when k is not equal to 12.
Therefore, for the system to have no solution, k must be equal to 12.
As for the value of h, it can be any real number since it does not affect the slopes of the lines.
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suppose that a water fountain produces a stream of water that follows the shape of a parabola. assigning the origin of a coordinate system to the point where the water stream emerges from the fountain, a measurement shows that the maximum height of the stream occurs at the point (6, 5). use symmetry to identify a third point and find a quadratic regression equation for the stream of water.a.y
Quadratic equation for stream of water; (x-6)² = -36/5(y-5)
Using symmetry;
if (0,0) is taken as origin and maximum height is reached by stream at (6,5); the stream will strike the ground at (12,0);
Equation of a parabola whose mouth is open toward negative y- axis;
x² = -4ay
Parabola vertex shifted from (0,0) to (6,5);
(x-6)² = -4a(y-5);
Put x = 0, y = 0, as it lies on parabola;
36 = -4a(-5);
36 = 20a;
a = 36/20;
Quadratic equation for stream of water; (x-6)² = -36/5(y-5);
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Solve for the indicated variable.
y = mx + b for x
Step-by-step explanation:
mx+b=y
mx=y-b
x=y-b/m
Please help me with this question :(
Answer:
∠1 and ∠3 as well as ∠5 and ∠7 are corresponding
∠2 and ∠7 are alternate
Step-by-step explanation:
Triangle TRS is similar to triangle TMN. Angle T = 40°, angle R = 60°, and angle S = 80° . What is the measure of angle M
Answer:
60degrees
Step-by-step explanation:
For similar triangles, the angles of their angles are equal to matter the size.
Hence if triangle TRS is similar to triangle TMN, then;
<R = <M and <S = <N
Given that;
<T = 40 degrees
<R = 60degrees
<S = 80 degrees
Since <R = <M, then <M = 60degrees
Can u please double check I answered this correctly! The first time I got 4pi. The second I got 2pi…
Given:
Given a table of values of a cosine function.
Required: Period of the function
Explanation:
The maximum of the cosine function occurs at the points
\(x=-2\pi\text{ and }x=2\pi\)The period of the function is the modulus of the difference of the consecutive values at which the function attains maximum/minimum.
\(\begin{gathered} \text{ Period=}|-2\pi-2\pi| \\ =|-4\pi| \\ =4\pi \end{gathered}\)Final Answer: The period of the given cosine function f(x) is
\(4\pi\)using trig to solve for the missing angle
Step-by-step explanation:
Since there is a 45 and 90 degree angle, this is a 45-45-90 triangle. The legs are equal in a 45-45-90 ttiangle. The hypotenuse sqr root of 2 times more than the legs. So this means the hypotenuse measure is
\(18 \sqrt{2} \)
So we can set up a equation.
\( {18}^{2} + {x}^{2} = ({18 \sqrt{2}) }^{2} \)
\(x = 18\)
So the missing side is 18
trucks in a delivery fleet travel a mean of 90 miles per day with a standard deviation of 18 miles per day. the mileage per day is distributed normally. find the probability that a truck drives between 122 and 127 miles in a day. round your answer to four decimal places.
The probability that a truck drives between 122 and 127 miles in a day is 0.0165, rounded to four decimal places.
To find the probability that a truck drives between 122 and 127 miles in a day, we'll use the z-score formula and standard normal distribution table. Follow these steps:
Step 1: Calculate the z-scores for 122 and 127 miles.
z = (X - μ) / σ
For 122 miles:
z1 = (122 - 90) / 18
z1 = 32 / 18
z1 ≈ 1.78
For 127 miles:
z2 = (127 - 90) / 18
z2 = 37 / 18
z2 ≈ 2.06
Step 2: Use the standard normal distribution table to find the probabilities for z1 and z2.
P(z1) ≈ 0.9625
P(z2) ≈ 0.9803
Step 3: Calculate the probability of a truck driving between 122 and 127 miles.
P(122 ≤ X ≤ 127) = P(z2) - P(z1)
P(122 ≤ X ≤ 127) = 0.9803 - 0.9625
P(122 ≤ X ≤ 127) ≈ 0.0178
So, the probability that a truck drives between 122 and 127 miles in a day is approximately 0.0178 or 1.78%.
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In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is \(t = 2(\frac{2h}{32} )\frac{1}2\) , where t is the time in seconds, and h is the height of the jump, in feet.
Player 1 had a hang time of 0.9 s. Player 2 had a hang time of 0.8 s. To the nearest inch, how much higher did Player 1 jump than Player 2?
Answer:
8 inches
Step-by-step explanation:
Given:
t = 2 ( 2h/32 ) ^1/2 ( or: t = 2 * sqrt ( 2h/32) ).
Step 1: First Player
0.9 = 2 * sqrt( 2h/32 ) / ^2 ( we will square both sides of equation )
0.81 = 4* 2h/32
0.81 = h/4
h 1 = 0.81 * 4 = 3.24 ft
Step 2: Second Player
0.8 = 2 * sqrt( 2h/32 ) /^2
0.64 = 4 * 2 h/32
h 2 = 0.64 * 4 = 2.56 ft
Step 3: Simplify
h 2 - h 1 = 3.24 - 2.56 = 0.68 ft
and since 12 in = 1 ft:
0.68 * 12 = 8.16 in ≈ 8 in.
example of two nonlinear functions that dont dominate each other
An example of two nonlinear functions that don't dominate each other is the sin function (f(x) = sin(x)) and the exponential function (g(x) = e^x).
For any given value of x, the sin function oscillates between -1 and 1, taking on both positive and negative values. It has a periodic nature and does not grow or decay exponentially as x increases or decreases.
On the other hand, the exponential function grows or decays exponentially as x increases or decreases. It is characterized by a constant positive growth rate. The exponential function increases rapidly when x is positive and approaches zero as x approaches negative infinity.
The key characteristic here is that the sine function oscillates while the exponential function grows or decays exponentially.
Due to their fundamentally different natures, neither function dominates the other over their entire domains.
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Which graph represents the function?
f(x)=1x+1−2
IS MY ANSWER CORRECT???
Answer:yes
Step-by-step explanation:
Answer:
yes it is
Step-by-step explanation:
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
Answer:
540,000+67,000= ((607,000))
Step-by-step explanation:
(5.4*10^5= 540,000)+(6.7*10^4= 67,000)
Answer:
\(6.07 \times {10}^{5} \)
Step-by-step explanation:
\(5.4 \times {10}^{5} + 6.7 \times {10}^{4} \)
\(540000 + 67000 = 607000\)
\(607000 = 6.07 \times {10}^{5} \)
Cassie has a small cube-shaped box. Its volume is 64 cubic centimeters.
What is the area of one face of the box?
Answer:
16 cm^2
Step-by-step explanation:
Sqrt 64 = 4
Area of one face is 4 x 4 = 16 cm^2
Consider the expression.
5n - 2 = 9
Which statement best describes this expression?
O A number less than two times five is 9.
O Five times a number subtracted from two equals 9.
O Five minus two times a number equals 9.
O. Two less than five times a number is 9.
2+2 i know the answer is four
Answer:
5 50bw syfnauw dux fyq euw eywvr6b
There are 180 players on 15 teams how much players are on each team
Answer:
180/15=12
12 players per team
Step-by-step explanation:
Hope this helps :D
Have a good day/night <3
a card is drawn at random from a full deck of 52 cards. what is the probability that the card is either a jack or black card
The probability that a card drawn at random from a full deck of 52 cards is either a jack or a black card is 27/52 or approximately 0.519.
To find the probability, we first need to determine the number of cards that meet the criteria. There are 4 jacks in the deck, so the probability of drawing a jack is 4/52 or 1/13. There are also 26 black cards in the deck (13 clubs and 13 spades), so the probability of drawing a black card is 26/52 or 1/2. However, we must subtract the 2 black jacks (the jack of clubs and the jack of spades) that we have already counted, so the total number of cards that are either a jack or black is 4 + 26 - 2 = 28. Thus, the probability of drawing a card that is either a jack or black is 28/52 or 7/13, which can be simplified to 27/52 or approximately 0.519.
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What are the mensure of 1 angle and 2 angle? Show ur work or explain
Answer:
angle 1 = 105º
angle 2 = 75º
Step-by-step explanation:
angle 2 = 75º
corresponding angle to the 75º angle
angle 1 = 105º
it's supplementary to angle 2
180 - 75 = 105
isabel needs to memorize words on a vocabulary list for Spanish class. She has 8 words to memorize, and she is one-fourth done. how many words has Isabel memorized so far?
Answer:
2
Step-by-step explanation:
1/4 × 8 = 2
:))))nakajsisj
Answer:
2
Step-by-step explanation:
8/ 1/41/4=2Hello,How can I find the difference quotient of the following?
The given function as;
f(x) = x² - 8x + 3
f(x + h) , susbtitute x = x + h in the given expression as;
f(x+h) = (x+h)² - 8(x+h) + 3
f(x+h) = (x² + h² + 2xh) -8x - 8h + 3
f(x+h) = x² + h² + 2xh - 8x - 8h + 3
Now substitute the value of f(x+h) in the expression as;
\(\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{(x^2+h^2+2xh-8x-8h+3)-(x^2-8x+3)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2+h^2+2xh-8x-8h+3-x^2+8x-3}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2-x^2+h^2+2xh-8x+8x-8h+3-3}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{2xh+h^2-8h}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{h(2x+h-8)}{h} \\ \frac{f(x+h)-f(x)}{h}=2x+h-8 \end{gathered}\)Answer : 2x + h - 8
.........