in a charming 19th century hotel, an old style elevator is connected to a counterweight by a cable that passes over a rotating disk 2.50 m in diameter. the elevator is raised and lowered by turning the disk, and the cable does not slip on the rim of the disk but turns with it. at how many rpm must the disk turn to raise the elevator at 35.0 cm/s? to start the elevator moving, it must be accelerated at 18g. what must be the angular acceleration of the disk, in r a d / s 2 ? through what angle (in radians ) has the disk turned when it has raised the elevator 2.55 m between floors?

ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

momentum= mass × velocity

p= 50×18

momentum= 900 kg m/s

Using a saltwater aquarium to model the ocean has limitations, such as showing only a small part of the actual ocean and being unable to replicate the vastness and complexity of the ocean ecosystem.

One limitation of using a saltwater aquarium to model the ocean is that it can only show a small part of the actual ocean. Since an aquarium is confined and limited in size, it cannot realistically replicate the vastness and complexity of the ocean ecosystem. For example, it may not have the space to accommodate large marine animals like whales or the turbulent currents that exist in the open ocean. Therefore, it is important to recognize that while a saltwater aquarium can provide some insights into the ocean, it cannot fully capture the dynamic nature and diverse interactions found within the entire ocean ecosystem.

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Answer:

0.675

Explanation:

hope you get it right

Answer:

\(0.675\:\mathrm{s}\)

Explanation:

Displacement can be given as \(\Delta x=v_x\cdot t\)

Substituting given values, we have:

\(27=40t,\\t=\frac{27}{40}=\boxed{0.675\:\mathrm{s}}\)

Answer:

\(\boxed {\boxed {\sf 15 \ kg*m/s}}\)

Explanation:

Momentum is the product of mass and velocity.

\(p=m*v\)

The mass of the ball is 1.5 kilograms and the velocity is 10 meters per second.

\(m= 1.5 \ kg \\v= 10 \ m/s\)

Substitute the values into the formula.

\(p= 1.5 \ kg* 10 \ m/s\)

Multiply.

\(p=15 \ kg*m/s\)

The momentum of the ball is 15 kilogram meters per second.

Answer:

15 kg m/s

Explanation:

\(p = mv \: = 1.5 \times 10 = 15 \: kgm {s}^{ - 1} \)

The differential equation is given as;

                                              dy(t) +ay(t) = Skx(t) dt

The step response of a system is defined as the output when the input of a system is a step function.

The value of K is 13.9.

The rise time is the time it takes for the output of a system to rise from 10% to 90% of the final value, in other words, the time it takes for the system to reach from 0.1 to 0.9 of its final value.

The steady-state gain of the step response y(t) is 10, and the rise time is 4.

The differential equation can be converted to the Laplace domain as;

                                            Y(s)[s+a] = Kx(s)/s..............(1)

where Y(s) and x(s) are the Laplace transforms of y(t) and x(t), respectively.

The step response in the Laplace domain is given by;

                                             Y(s) = Kx(s)/[s(s+a)]........................(2)

The rise time for a first-order system is given as;

                                              Tr=1.8/ζωn,

where ζ is the damping ratio, and ωn is the natural frequency of the system.

We know that the steady-state gain of the system is 10; therefore, the magnitude of the output in the Laplace domain at s = 0 is 10.

Thus, we can write;

                            lim_(s→0)⁡Y(s) = lim_(s→0)⁡Kx(s)/[s(s+a)]

                                                  = 10

Therefore;

                            lim_(s→0)⁡Kx(s)/[s(s+a)] = 10

                            lim_(s→0)⁡Kx(s) = lim_(s→0)⁡10s(s+a)

                            lim_(s→0)⁡Kx(s) = 10a

Therefore;

                            K = 10a

                           lim_(s→0)⁡x(s) = Ks/[s(s+a)]

Now substituting,

                               Tr = 4

                                and

                       gain K = 10;

                               a = 1/(ζTr)ωn

                                   = 1/TrK

                                    = 10a lim_(s→0)⁡x(s)

                                    = 10×1/(1.8/ζ4)

                                    = 10ζ/0.72=13.9

Therefore, the value of K is 13.9.

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Answer:

The acceleration is 5km/h

Explanation:

Given

Initial Velocity (u) = 30km/h

Final Velocity (v) = 50km/h

Time (t) = 4h

Required

Determine the acceleration

This question will be answered using the first equation of motion;

\(v = u + at\)

Substitute values for u, v and t

\(50 = 30 + a * 4\)

\(50 = 30 + 4a\)

Subtract 30 from both sides

\(50 - 30 = 30 - 30+ 4a\)

\(20 = 4a\)

Divide both sides by 4

\(\frac{20}{4} = \frac{4a}{4}\)

\(5 = a\)

\(a = 5\)

Hence;

The acceleration is 5km/h

Answer:

Too what i know its because of the air

Explanation:

The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air

Answer:

a. The arrow follows a parabolic path

b. As the arrow hits the ground,

Explanation:

a Describe the arrow's trajectory, in particular noting approximately when the arrow has the most deceleration, the most acceleration, and then why the shift begins to happen. Cover all major points in the trajectory from initial shot to final resting place.

This is because, the arrow is a projectile and its path follows a parabolic curve as it goes from initial shot to final resting place.

Its equation of motion is governed by y = ut - 1/2gt² where y = parabolic path, u = initial speed of arrow, t = time and g = acceleration due to gravity.

As the arrow rises, it undergoes the most deceleration. This is because as it rises, its speed decreases until it gets to the peak of its path, where its velocity is momentarily zero.  

Also, as the arrow drops, it undergoes the most acceleration. This is because as it drops from its peak, its speed increases until it gets to the bottom of its path, where its velocity is maximum and given by v = u' - gt where u' = velocity at peak = 0 m/s. So, v = 0 - gt = -gt.

b. When is the arrow moving fastest?

As the arrow hits the ground, its velocity is highest (maximum), so it is fastest at this point.

Cepheid variable stars are important to astronomers because their periods of variability are related to their absolute luminosity.

A Cepheid variable is a particular kind of variable star that pulses radially and undergoes changes in temperature and diameter. With a well defined, constant period and amplitude, its brightness varies. Cepheid variable stars are a unique class of variable star because they are hot, massive, and have a propensity to pulse radially. They also have a tendency to change in diameter and temperature.

An objective way to quantify the radiant power that a light-emitting device emits over time is luminosity. The total quantity of electromagnetic energy released by a star, galaxy, or other celestial object in a given amount of time is measured as luminosity in astronomy.

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The built-in voltage Vbi at 700◦C is -0.28 V, which means that the P-N junction is reverse-biased.

The built-in voltage Vbi of a P-N junction is given by:

\(Vbi = (kT/q) * ln(ND*NA/ni^2)\)

where k is Boltzmann's constant, T is the temperature in Kelvin, q is the electron charge, ND and NA are the N-type and P-type doping levels, and ni is the intrinsic carrier concentration.

(a) At room temperature (T = 300 K) and with ni = \(1.5 * 10^1^0 cm^3\) (for silicon), we have:

\(Vbi = (kT/q) * ln(ND*NA/ni^2)\)
\(= (1,38* 10^-^2^3 * 300 / 1.6 * 10^-^1^9) * ln (5 * 10^1^6 * 5 * 10^1^6 / (1.5 * 10^1^0)^2)\\= 0.71 V\)

Therefore, the built-in voltage Vbi at room temperature is 0.71 V.

(b) At 700◦C (T = 973 K) and with \(ni = 1.10 * 10^1^8 cm^3\), we have:

\(Vbi = (kT/q) * ln(ND*NA/ni^2)\)
\(= (1.38 * 10^-^2^3 * 973 / 1.6 * 10^-^1^9) * ln(5 * 10^1^6 * 5 * 10^1^6 / (1.10 * 10^1^8)^2)\\= -0.28 V\)

Therefore, the built-in voltage Vbi at 700◦C is -0.28 V, which means that the P-N junction is reverse-biased. A negative value for Vbi means that the majority carriers (electrons in the N-type and holes in the P-type) are attracted to the junction and will tend to flow away from it when an external voltage is applied in the forward direction.

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Answer:

1. C

2. B

5. C

B. The recoil is a result of conservation of momentum. The force of the ignition of the gunpowder that pushes the bullet forward will be balanced out by also pushing against the gun.

Newton's third law is displayed in each of these questions.

Answer:

1.) c

2.) b

3.) c

Explanation:

I actually had the same test and made a 90%

Answer:

(of the moon) have a progressively smaller part of its visible surface illuminated, so that it appears to decrease in size.

Explanation:

If the hanging mass were placed at the very end of the meter stick, the balance point would be located at the center of mass, which can be found using the formula and steps provided. The exact location of the balance point depends on the values of the hanging mass and the mass of the meter stick.

If the hanging mass were placed at the very end of the meter stick, the balance point would be located at the center of the mass of the system.

To determine the center of mass, follow these steps:

Step 1: Identify the masses and their locations. In this case, we have the hanging mass (m1) placed at the very end of the meter stick (L) and the mass of the meter stick itself (m2) with a uniform distribution.

Step 2: Calculate the center of mass of the meter stick. Since the meter stick's mass is uniformly distributed, its center of mass is at its midpoint (L/2).

Step 3: Use the formula for the center of mass of a system:
Center of mass = (m1 * x1 + m2 * x2) / (m1 + m2)

Step 4: Plug in the values:
Center of mass = (m1 * L + m2 * (L/2)) / (m1 + m2)

Step 5: Solve the equation to find the balance point.

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The types of interactions between molecules in solution have a significant effect on the viscosity Arrhenius activation energy in binary mixtures. The nature of the interaction can either increase or decrease the energy required for the reaction to occur, which in turn affects the viscosity of the mixture.

The viscosity Arrhenius activation energy in binary mixtures is influenced by the types of interactions that occur between molecules in solution. In a binary mixture, two different types of molecules are mixed, and the nature of the interaction between the two types of molecules determines the viscosity of the mixture.

The viscosity of a liquid is dependent on the intermolecular forces of attraction between molecules. Strong intermolecular forces result in a higher viscosity, while weak forces result in a lower viscosity. This is because stronger forces require more energy to be overcome when the molecules move past one another, resulting in a higher resistance to flow.

The Arrhenius activation energy is a measure of the energy required to initiate a chemical reaction. In binary mixtures, the type of interaction between the two types of molecules determines the activation energy. If the interaction is strong, a higher activation energy is required to initiate the reaction.

On the other hand, if the interaction is weak, a lower activation energy is required.

Thus, the types of interactions between molecules in solution have a significant effect on the viscosity Arrhenius activation energy in binary mixtures. The nature of the interaction can either increase or decrease the energy required for the reaction to occur, which in turn affects the viscosity of the mixture.

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The last option is correct i.e. the train stopped for 3 second.

Looking at the many choices, we can see that only the final choice is the train may be the right one.

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Answer:

The last option is correct i.e. the train stopped for 3 second.

Explanation:

The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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Answer:

Sound waves bend around the corners of various obstacles.

Explanation:

I took the test

Black holes are among the most extreme and fascinating objects in the universe, and their study has greatly advanced our understanding of gravity, the properties of matter, and the structure of the universe.

What is Gravitation?

Gravitation is the force of attraction between two masses in the universe. Every object in the universe that has mass exerts a gravitational force on every other object that has mass. The strength of the gravitational force depends on the mass of the objects and the distance between them. The greater the mass of an object, the stronger the gravitational force it exerts, and the closer two objects are, the stronger the gravitational force between them.

An object that exerts such a strong gravitational pull that no light can escape is called a black hole. Black holes are formed by the collapse of massive stars, in which the star's core collapses under the force of gravity to a point of zero volume and infinite density known as a singularity. The gravitational force of a black hole is so strong that even light, which has no mass, cannot escape its pull.

The boundary around a black hole beyond which nothing can escape is called the event horizon. Once something crosses the event horizon, it is inevitably pulled towards the singularity at the center of the black hole. The boundary of the event horizon is also known as the point of no return, beyond which escape is impossible.

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Answer:

Cell theory is the scientific theory that states that all living things are composed of cells and that cells are the basic unit of life. The three principles of cell theory are the cell is the smallest unit of life, all cells come from preexisting cells, and cells are the basic unit of function in living things.

Explanation:

Please mark me brainliest

Answer:

B. Friction

Explanation:

Answer:

Explanation:

Thousands of avalanches occur in Canada each year. They happen in all regions of Canada, but are more frequent in the mountains of British Columbia, Yukon and Alberta. Avalanches can be triggered by wind, rain, warming temperatures, snow and earthquakes. They can also be triggered by skiers, snowmobiles, hikers, vibrations from machinery or construction.            Avalanche facts:

An avalanche occurs when a layer of snow collapses and slides downhill.

Avalanches are caused by four factors: a steep slope, snow cover, a weak layer in the snow cover and a trigger.

Roads and railway tracks may be rerouted to reduce risks.

Safe avalanches may be triggered in dangerous snow packs.

Avalanches can travel up to 90 km/h.

After one hour, only one in three victims buried in an avalanche is found alive. The most common causes of death are suffocation, wounds and hypothermia.

The value of the current flowing through the shunt is 0.08 A.

The value of the current flowing through the shunt is calculated by applying the following formula.

I = V/R

where;

The voltage flowing through the shunt is calculated as;

V/V'  = L/L'

where;

V/3 = 80/100

V = (3 x 80 ) / 100

V = 2.4 V

The current flowing through the shunt is calculated as;

I = 2.4 / 30

I = 0.08 A

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Answer:

heart, lungs, blood vessels

Explanation:

Answer:

\(a=\frac{v^2}{r}\)

\(v=\sqrt{a*r}\)

\(r=\frac{v^2}{a}\)

Explanation:

This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r).  The expression for the acceleration is already given, so simply type it as shown:

\(a=\frac{v^2}{r}\)

For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:

\(a*r=v^2\\v=\sqrt{a*r}\)

For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:

\(a*r=v^2\\r=\frac{v^2}{a}\)

Answer:

D

Explanation:

just did the quiz :)

The height reached by the two carts after collision is determined as 5.34 m.

Apply the principle of conservation of mechanical energy.

K.E = P.E

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

8(15.34) + 4(0) = v(8 + 4)

122.72 = 12v

v = 10.23 m/s

Apply the principle of conservation of mechanical energy.

P.E = K.E

mgh = ¹/₂mv²

h = v²/(2g)

h = (10.23²) / (2 x 9.8)

h = 5.34 m

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