In Chapter 9 we will define the center of mass of an object and prove that its motion is described by the particle under constant acceleration model when constant forces act on the object. A gymnast jumps straight up, with her center of mass moving at 2.80 m/s as she leaves the ground. How high above this point is her center of mass (a) 0.100 s , (b) 0.200 s (c) 0.300 s, and (d) 0.500 s thereafter?

The current in the circuit will be 0.0167 Amperes when a light bulb is providing resistance and the batteries with 1.5 voltage.

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is measured.

To calculate current the formula used is V= IR

                                                                 1.5/90 = I

                                                                 0.016 A = I

Electronic components such as resistors, transistors, capacitors, inductors, and diodes are connected via conductive wires or traces that allow an electric current to pass between them.

Hence, the current in the circuit will be 0.0167 Amperes when a light bulb is providing resistance and the batteries with 1.5 voltage.

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Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)

When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.

In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.

When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.

Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.

If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.

Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)

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Answer:

tis unknown

Explanation:

dan dan duuun dun dun

Answer:

Similar to a lock and key, the biomedical model seeks to find a solution that fits the respective problem. Biopsychosocial. The biopsychosocial model is aptly named because of its three essential components: biological, psychological and social ideologies. As a result, the concept of health is viewed as a balance between these three sectors.

Explanation:

hope it helps

have a great day

:)

During change of state temperature remains constant. The reason is that the heat supplied is used up in changing the state of matter as it has to work against the force of attraction of molecules

Answer:

the answer would be D 65N

Explanation:

just got it correct on EDG

Answer: the link isnt loading

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

120 dB

Explanation:

Softest audible sound with intensity, Is

Sound, I, which is 1,000,000,000,000 times as loud ;

I = 1,000,000,000,000 * Is

Loudness of the sound in decibels :

10 log base 10 (1,000,000,000,000 * Is / Is)

= 10 log base 10 (1,000,000,000,000)

= 10 (12)

= 120 decibels

Answer:

The answer is magma

Explanation:

I'm 99.99% this is right

Answer: its magnetic reversal

Explanation: jus took the test make brainly

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

confounding cause they had exposure to many programmes

Answer:

Confounding should be your answer please mark brainliest

Answer:

I am confused, is this a true and false answer?

Answer:

10.0

Explanation:

Mechanical Advantage = distance moves along the plane/distance moved along the vertical

distance moves along the vertical = 0.3m

distance moves along the plane = 3.0m

Mechanical Advantage = 3.0/0.3

Mechanical Advantage = 10

Hence the mechanical advantage is 10.0

Answer:

C. Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

edge 2020 Brainliest would be appreciated

Answer:

Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

I just did the Cumulative Exam Review

Answer:

The answer is

Explanation:

The momentum of an object can be found by using the formula

From the question

m = 1400 kg

v = 40 m/s

We have

momentum = 1400 × 40

We have the final answer as

Hope this helps you

Answer:

60 km/hr

Explanation:

Looking for km / hr

12 km / (.20 hr) =   60 km/hr

The coefficient of static friction between the block of wood and the table is 0.449.

The weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.

The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.

Since the block is not accelerating vertically, we know that N = Mg, so we have:

μs = fs/N = 17.64 N / 39.24 N = 0.449

Therefore, the coefficient of static friction between the block of wood and the table is 0.449.

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Answer:

Final Temperature = 71 °C

Explanation:

In this case, the ideal gas equation is written as;

PV = mRT

Where;

P is pressure

V is volume

m is mass

R is gas constant

T is temperature

We will take the volume to be constant.

So, in the initial state, we have;

P1•V = m1•R•T1 - - - eq(1)

In the final state, we have;

P2•V = m2•R•T2 - - - - eq(2)

Combining eq (1) and eq(2),we have;

P1•m2•R•T2 = P2•m1•R•T1

Dividing both sides by R gives;

P1•m2•T2 = P2•m1•T1

Making T2 the subject gives;

T2 = (P2•m1•T1)/(P1•m2)

Now, we are given;

m1 = 2kg

m2 = ½*2 = 1kg

P1 = 4 atm

P2 = 2.2 atm

T1 = 40°C = 273 + 40 K = 313K

Plugging in this values into the T2 equation, we have;

T2 = (2.2 × 2 × 313)/(4 × 1)

T2 = 344 K

Converting to °C, we have;

T2 = 344 - 273 = 71 °C

If speed is 39 m/s and neglect drag, Maximum height of cannonball is 156m, rise time is 4s, and total flight time is 7.86 seconds.

Given that a student fires a cannonball vertically upwards with a speed of 39 m/s, and neglecting drag and initial height and horizontal motion of the cannonball, we can determine all unknowns as follows:

Maximum height: The maximum height of the cannonball can be determined using the equation for vertical motion under constant acceleration, which is:

h =\(vi * t - (1/2) * g * t^2,\)

where h: height

vi: initial velocity

t: time

g: acceleration due to gravity (9.8 m/s^2).

As maximum height occurs when the velocity is 0, we can set vi = 39 m/s, and t = (2 * vi) / g, to find that

h = \(39 m/s * t - (1/2) * 9.8 m/s^2 * t^2 = (39 * t) / 2.\)

\((39 * t) / 2 = (39 * (2 * vi) / g) / 2 = (39 * 2 * 39) / (2 * 9.8) = 78 * 39 / 19.6 = 78 * 2 = 156 m.\)

Rise time: The time it takes for the cannonball to rise to its maximum height can be determined using the above equation for maximum height. Plugging in h = (39 * t) / 2, and solving for t, we find that t = (2 * h) / 39.

The rise time is \((2 * h) / 39 = (2 * 156) / 39 = 4 s\)

Total flight time: The total flight time of the cannonball can be determined using the equation for vertical motion under constant acceleration, which is h = \(vi * t - (1/2) * g * t^2\). We know the initial velocity, vi = 39 m/s, and we can set h = 0 (since the cannonball lands back on the ground), to find that t = (2 * vi) / g.

total flight time is \((2 * vi) / g = (2 * 39) / 9.8 = 7.86 s.\)

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Answer:

Bubbles paused

Explanation:

the air bubble doesn't rise because it is no lighter than the water around it—there's no buoyancy. The droplet doesn't fall from the leaf because there's no force to pull it off. It's stuck there by molecular adhesion.

for instance, onto the International Space Station, gravity becomes negligible, and the laws of physics act differently than here on Earth

On Earth, the buoyancy of the air bubbles causes them to rise to the top together, creating a segregation between air and water. However, in microgravity, nothing forces the air bubbles to interact and thus rise together, Green said.

Answer:

The two methods will yield different results as one is subject to experimental errors that us the Archimedes method of measurement, the the density measurement method will be more accurate

Explanation:

This is because the density method using the calculated volume will huve room for less errors that's occur in practical method i.e Archimedes method due to human error

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          \(a_{average}= 1.5 \ \frac{m}{s^2}\)

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   \(\frac{dv}{dt}\)

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          \(a_{average} = \frac{\Delta v}{\Delta t }\)

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           \(a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\\)

           \(a_{average}= 1.5 \ m/s^2\)

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           \(a_{average} =\)  1.5 m / s²

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Answer:

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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Answer:

v = 100 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 10 m/s²

t = 10 s

Find: v

v = at + v₀

v = (10 m/s²) (10 s) + 0 m/s

v = 100 m/s

Answer:

C. Z, X, W, Y

Explanation:

The correct listing of the engines from most efficient to least efficient is. Z, X, W, Y. The correct option is C.

The efficiency of a heat engine is determined by the ratio of the work output to the heat input. The greater the work output for a given heat input, the higher the efficiency of the engine.

Here in the Question,

To determine which heat engine is the most efficient, we can calculate the efficiency of each engine using the formula:

efficiency = 1 - (T_cold / T_hot),

Where

T_cold =the temperature of the cold reservoir

T_hot = the temperature of the hot reservoir.

Using the data provided in the chart, we can calculate the efficiency of each engine as follows:

Engine W: efficiency = 1 - (120 K / 620 K) = 0.806

Engine X: efficiency = 1 - (100 K / 840 K) = 0.881

Engine Y: efficiency = 1 - (300 K / 900 K) = 0.667

Engine Z: efficiency = 1 - (25 K / 500 K) = 0.950

From the calculations above, we can see that Engine Z is the most efficient, with an efficiency of 0.950. Engine X is the second most efficient, followed by Engine W and then Engine Y.

Therefore, the correct listing of the engines from most efficient to least efficient is option C. i.e Z, X, W, Y.

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Answer:the gravitational force is always directed towards the centre of the earth

Explanation: