In complete sentences please

Answer:

Light energy

Explanation:

This happens by means of chlorophyll combining with the carbon, from carbon dioxide, and the hydrogen and oxygen, from water, to form carbohydrates

The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.

Smax = 400 feet.

c) v = 32 ft/s

c) v = - 32 ft/s

(a)

The following is the function provided for ball height:

s = 160 t - 16 t²

Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):

So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.

As a result, the maximum distance is covered every 5 seconds.

Smax = (160)(5) - (16)(5)²

Smax = 800 - 400

Smax=400 feet

b)First, we determine the speed at which the ball travels 384 feet.

384 = 160 t - 16 t

16 t² - 160 t + 384 = 0

Quadratic Equation Solving:

Either:

t = 6 sec

or t = 4 seconds

Since it takes 5 seconds to reach the highest point,

t then equals 5 seconds.

t then equals 4 seconds.

Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:

v = 160 - 32 t

v = 160 - (32)(4)

v = 32 ft/s

c,Because t = 6 s > 5 s

The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.

So, at that moment, velocity will be:

v = 160 - (32)(6)

v = -32 ft/s

downward motion is a bad sign.

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Answer: The ratio of carnivorous species to all mammal species is 1:20

Explanation:

250:5000 = 250/250 = 1

250:5000 = 5000/250 = 20

Answer = 1:20

Answer:

2 and 4

Explanation:

right on edge

Answer:

can confirm its 2 and 4

Explanation:

Answer:

c...........................

The distance between two similar points in successive identical cycles in a wave is its wavelength. So, the correct option is c.

A waveform's wavelength is defined as the separation between two identical points (adjacent crests or troughs) in adjacent cycles as the wave travels through space or along a medium.

The crest is a term used to describe the highest point of a wave. The trough refers to the bottommost area.

The height difference between the wave's crest and trough is known as the wave height.

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Answer:

i can't sorry

Explanation:

I didn't really pay attention in that class

Given:

The mass on the table is,

The hanging mass is,

THe coefficient of friction is,

let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.

we can write,

Adding these equations we get,

Substituting the values we get,

Hence the acceleration is 6.66 m/s^2.

The net force is F   = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N

Coulomb's law states that the electrostatic force of attraction between two charges separated by a distance r, q 1 and q 2, is given by:

F = k (q1q2/r2)

Coulomb's constant k = 9×\(10^{9}\) Nm2/Kg2

Location of charge q3: P (0,d2,d2)

By Coulomb's law, the force on charge q0 due to q3 is:

F = k × q0 × q3 / \(d_{2} ^{2}\) × \(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^ k)

F   = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N

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0.268 because grams are 1000 times bigger than mg

1 milligram = 0.001 grams

268.0mg * 0.001g

\(=\fbox{0.268 grams}\)

The volume flow rate through the hose and nozzle is 0.339 l/s, the speed of the water in the nozzle is approximately 9.058 m/s.

To calculate the speed of the water in the nozzle, we can use the principle of continuity, which states that the volume flow rate is constant at any point along a pipe or hose.

The equation for the principle of continuity is given by A₁v₁ = A₂v₂, where A₁ and A₂ are the cross-sectional areas of the hose and nozzle, and v₁ and v₂ are the velocities of the water in the hose and nozzle, respectively.

First, we need to convert the given volume flow rate from liters per second to cubic meters per second, which gives us 0.339 × 10⁻³ m³/s.

Next, we can calculate the cross-sectional areas of the hose and nozzle using the given radii. The area of a circle is given by the formula A = πr².

For the hose, A₁ = π(0.01878 m)² and for the nozzle, A₂ = π(0.00595 m)².

Using the principle of continuity, we can rearrange the equation to solve for v₂: v₂ = (A₁v₁) / A₂.

Substituting the known values, we find v₂ ≈ (π(0.01878 m)² × 0.339 × 10⁻³ m³/s) / (π(0.00595 m)²).

Simplifying the equation, we get v₂ ≈ 9.058 m/s. Therefore, the speed of the water in the nozzle is approximately 9.058 m/s.

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Answer:

See explanation below

Explanation:

In this case, you want to know if you put an object between these forces, which direction would go.

To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:

M = F * d   (1)

And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:

anticlockwise moment = clockwise moment.

The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.

Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns

Anticlockwise moment = 34 * 3.5 = 119 Ns.

As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.

Hope this helps

The equivalent resistance of the circuit is 2Ω.

To find the equivalent resistance of the given circuit, we can analyze it step by step. Let's break down the process:

The circuit consists of resistors connected in series and parallel. We'll simplify it by combining resistors in series and parallel until we have a single equivalent resistance.

Starting from the right side, we can see that the 12Ω and 6Ω resistors are in parallel. The equivalent resistance for these two resistors is given by the formula: Req = (R1 * R2) / (R1 + R2). Substituting the values, we find Req = (12 * 6) / (12 + 6) = 4Ω.

Now, we can simplify the circuit further. The 4Ω resistor and the 2Ω resistor are in series. Adding their resistances, we get 6Ω.

Finally, we have two resistors in parallel: the 6Ω resistor and the 3Ω resistor. Using the parallel resistance formula again, we find Req = (6 * 3) / (6 + 3) = 2Ω.

Therefore, the equivalent resistance of the circuit is 2Ω.

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Answer:

0

Explanation:

F1 = G•2.2•4.66/3² (pointed right)

F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

The gravitational force on the 2.20 Kg mass is 7.53 × 10⁻¹¹ N to the right and and the same to the left. The same forces are in opposite direction and thus balances each other.

The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:

g = G m1 m2/r²

where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N

Given the mass at the  origin = 2.20 kg

mass in right side = 4.66 Kg.

distance = 3 m.

then g = 6.67 × 10⁻¹¹ N × (2.20 × 4.66 kg)/3² =  7.53 × 10⁻¹¹ N

However, the equal force acts from the equal distance by the same mass from the left side also. Therefore, both forces cancel each other in magnitude and the net gravitational force will be zero.

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9) a) formula = h(ρ)g by default g=9.8m/s²

Pressure = 2×1000×9.8 = 19600Pa

b)

Answer:

Protostars

Explanation:

Answer:

87 kph

Explanation:

Answer:

hope it helps make brainlliest ty

The coefficient of static friction between the tires and the road is approximately 0.252

The maximum speed that a car can travel without skidding is determined by the maximum force of static friction that the tires can exert on the road. The formula for this maximum force of static friction is:

f_s = m × g × μ_s

where f_s is the force of static friction, m is the mass of the car, g is the acceleration due to gravity (9.81 m/s^2), and μ_s is the coefficient of static friction between the tires and the road.

When the car reaches a speed of 20 m/s, it is moving in a circular path of radius 139 m. The centripetal force required to keep the car moving in this circular path is given by:

f_c = m × v^2 / r

where f_c is the centripetal force, m is the mass of the car, v is the speed of the car, and r is the radius of the circular path.

At the point where the tires start to skid, the maximum force of static friction is equal to the centripetal force required to keep the car moving in the circular path:

f_s = f_c

Substituting the formulas for f_s and f_c and solving for μ_s, we get:

m × g × μ_s = m × v^2 / r

μ_s = v^2 / (g × r)

We are given that the car increases its speed at a uniform rate of 5.26 m/s^2. We can use the formula for uniform acceleration to find the time it takes for the car to reach a speed of 20 m/s:

v = u + a × t

20 = 0 + 5.26 × t

t = 20 / 5.26 = 3.8 s

Using this time, we can find the distance traveled by the car before the tires start to skid:

s = u × t + 1/2 × a × t^2

s = 0 + 1/2 × 5.26 × (3.8)^2

s = 36.6 m

Now we can substitute the given values into the formula for μ_s:

μ_s = v^2 / (g × r)

μ_s = (20)^2 / (9.81 × 139)

μ_s = 0.252

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B 10,000 - 30,000 K Blue-white stars

A 7,500 - 10,000 K White stars

F 6,000 - 7,500 K Yellow-white stars

G 5,000 - 6,000 K Yellow stars (like the Sun)

The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body.

Answer:

Explanation:

Given,

Speed of a car = 25 km

Converting 25 km into m

\( \sf{1km = 1000m}\)

\( \sf{25 \: km = 25 \times 1000m = 25000m}\)

Time taken ( t ) = 15 minutes

Converting minutes into seconds

\( \sf{1 \: minutes = 60 \: seconds}\)

\( \sf{15 \: minutes = 15 \times 60 sec = 900 \: seconds}\)

Finding the speed of the car

\( \boxed{ \sf{speed = \frac{distance \: travelled}{time \: taken} }}\)

\( \sf{ = \frac{25000 \: m}{900 \: s} }\)

\( \sf{ = 27.78 \: m/s}\)

Hope I helped!

Best regards!!

One third of the total distance of 3900 m is 1300 m. The time taken to travel this distance is 5 minutes or 300 seconds. Then, the velocity of the person is 4.3 m/s.

The velocity of a moving object is the measure of its distance travelled per unit time. It is a vector quantity having both magnitude and acceleration. The units of velocity are m/s, km/hr, ft./s etc.

Velocity of an object is the ratio of the change in distance to the change in time. It is given that the total distance to the grocery is 3900 m

1/3rd of 3900 m=  1300 m

Lee travels 1300 m in 5 minutes or 300 seconds,

Hence, the velocity = distance/ time

v = 1300 m / 300 s = 4.3 m/s

Therefore, the Lee has a velocity of 4.3 m/s.

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The magnitude of the second charge was changed by a factor of √(1/3), or approximately 0.577.

Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, and the equation is:

F = k × q1 × q2 / r²

where k is the Coulomb constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Initially, q1 = q, and q2 = q. The magnitude of the force is 10 N:

10 = k × q² / r²

After the magnitude of the first charge is tripled, the magnitude of the force becomes 5 N:

5 = k × 3q² / r²

Solving for q2, we get:

q2 = √(q² / 3)

q2 = √(1/3)

q2 = 0.577

So the magnitude of the second charge was changed by a factor of √(1/3), or approximately 0.577.

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The velocity of the car upon impact is 10.8 m/s, or about 24.2 mph. Velocity is typically measured in units of meters per second (m/s) or kilometres per hour (km/h).

What is Velocity ?

Velocity is a vector quantity that describes the rate and direction of an object's motion. It is defined as the change in displacement over time. In other words, velocity is how fast an object is moving and in what direction.  For example, if a car is traveling north at a speed of 20 m/s, its velocity would be 20 m/s in the northward direction.

First, we can calculate the initial velocity of the car in meters per second:

45.0 mi/hr = 66.0 ft/s

1 mile = 5280 ft

66.0 ft/s x 1 mile/5280 ft = 0.0250 mile/s

1 hour = 3600 s

45.0 mi/hr = 45.0 x 1 mile/1 hour = 45.0 mile/hr

45.0 mile/hr x 1 hour/3600 s = 0.0125 mile/s

0.0125 mile/s x 1609.34 m/mile = 20.12 m/s

The initial velocity of the car is 20.12 m/s.

Next, we can calculate the acceleration of the car using the coefficient of friction and the acceleration due to gravity:

μ = 0.77 (coefficient of friction)

g = 9.81 m/s² (acceleration due to gravity)

a = μg = 0.77 x 9.81 = 7.56 m/s²

The acceleration of the car is 7.56 m/s².

Now we can use the kinematic equation for uniformly accelerated motion to calculate the distance the car will travel before stopping:

v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Since the car stops, the final velocity is zero:

v = 0

Plugging in the known values, we get:

0² = (20.12 m/s)² + 2(-7.56 m/s²)s

Solving for s, we get:

s = (20.12 m/s)² / (2 x 7.56 m/s²)

s = 53.3 m

Therefore, the car will not stop in time to avoid a collision with the other car, since the stopping distance of the car is 53.3 meters, which is greater than the distance between the two cars (90.0 ft or 27.4 meters).

To calculate the velocity of the car upon impact, we can use the same kinematic equation:

v² = u² + 2as

but this time, the distance travelled is the distance between the two cars, since the car will not stop before hitting the other car:

s = 27.4 m

Plugging in the known values and solving for v, we get:

v = √[(20.12 m/s)² + 2(-7.56 m/s²)(27.4 m)]

v = 10.8 m/s

Therefore, the velocity of the car upon impact is 10.8 m/s, or about 24.2 mph.

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Answer:

1.7 g/cm³

Explanation:

Given that:

Density of substance = 3.4 g/cm³

Relative density to another substance = 2

Density of second substance=?

Let density of second substance = x

Relative density = density of substance / density of second substance

Relative density = density of substance / x

2.0 = 3.4g/cm³ / x

2 * x = 3.4 g /cm³

x = 3.4 g/cm³ ÷ 2

x = 1.7 g/cm³

Answer:

Explanation:

Answer:

please mark me as brainlest

11/28/20      2:14 pm   name tom

hello i hope this is what you needed

What does seafloor spreading result in?

Explanation:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Explanation:

On a position vs time graph (x vs t), displacement is the difference in positions (Δx = x₂ − x₁).

On a velocity vs time graph (v vs t), displacement is the area under the graph (Δx = ∫ v dt).

The correct answer is "the pitch drops to a lower pitch once the ambulance passes by Juan".

When there is relative motion between the source and the listener, the Doppler effect causes the frequency to rise or decrease. The frequency determines the pitch. When the frequency rises, the pitch rises with it.

When the source and the listener get closer to each other, the frequency rises. There is a reduction in frequency as the source and listener move away from each other.

Juan is standing on the street in the provided situation. When an ambulance approaches Juan and then passes by, the pitch dips to a lower level.

Hence "The pitch decreases to a lower pitch once the ambulance passes by Juan," is the right answer.

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Answer:

Explanation:

c.the pitch drops to a lower pitch once the ambulance passes by Juan

The force that the space shuttle exerts on the astronaut floating a distance of 14m away from it depends on the mass of the astronaut and the gravitational pull of the earth.

When the astronaut is floating a distance of 14m away from the space shuttle, there are several forces acting on them, including the gravitational pull of the earth and the gravitational pull of the space shuttle. However, the force that the space shuttle exerts on the astronaut can be calculated using Newton's law of universal gravitation.

According to this law, the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Therefore, to calculate the force that the space shuttle exerts on the astronaut, we need to know their masses and the distance between them.

Assuming that the mass of the astronaut is 80kg and the mass of the space shuttle is much larger, we can approximate the force that the space shuttle exerts on the astronaut using the following formula:
force = (G * M * m) / d^2
Where G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), M is the mass of the space shuttle, m is the mass of the astronaut, and d is the distance between them (14m).

Since we don't know the exact mass of the space shuttle, we can't calculate the force directly. However, we can estimate that the force will be very small compared to the gravitational pull of the earth. Therefore, the astronaut will continue to float away from the space shuttle and eventually be pulled back towards the earth's surface by the earth's gravity.

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