In stable and simple environments, ________. Question 19 options: A) organic designs are most effective B) low formalization is necessary C) decentralization is necessary D) mechanistic designs are most effective

Kepler's 2nd law states that a line connecting the planets will sweeps equal areas of space in equal time intervals.

The imaginary line joining a planet and the Sun sweeps equal areas of space in equal time intervals as the planet orbits.

Basically ,that the planets do not move with the constant speed along their orbits.

Rather, their speed varies so that the line joining the centers of the Sun and planets sweeps out equal areas of space in equal time.

The point of nearest approach of the planet to the Sun is termed as the perihelion and the point of greatest separation is aphelion.

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Answer: 125 m/s

Multiply 15 m/s by 5.0 minutes, because this will give you the product.

15 x 5.0 = 125.

Add the m/s sign to the 125. 125 m/s.

Answer = 125 m/s. Hope this helps!

Answer:

The world would have been blown up by now.

Explanation:

Hypothetically, lets say that someone gave Kim Jong boi a cup of coffee.

He gets mad at the "public servant" since it didn't contain 3 posafa43asdunds of sugar which makes him "big".

The public servant claims they added jfoaj4su38093 units of sugar, which is equivalent to 3 posafa43asdunds.

He gets mad and launches big cannons at Trump since he blames Boe Jiden.

Answer:

please help

Explanation:

Answer:

A.) Hot to cold.

Explanation:

I took the quiz on Edge, 2022.

(See the attachment below.)

Hope this helped! <3

Based on scientific information, the direction that heat generally flow from is: A. hot to cold.

Heat is also known as thermal energy and it refers to a form of energy that is only transferred from an object to another due to a difference in temperature.

During the process of heat conduction, heat would only be transferred between objects that are having different levels of temperature and objects that are directly in contact with one another.

In conclusion, heat is generally transferred from a hot object to a cold object as a result of their varying temperature.

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A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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All of the following (radio waves, visible light, x-rays, and infrared light) travel at the speed of light, which is 299,792,458 meters per second. Therefore, none of them travel at the same speed.

Electromagnetic waves are a type of energy wave that consists of oscillating electric and magnetic fields, which propagate through space at the speed of light. They are created by the motion of charged particles, and they can travel through a vacuum or through various materials.

All of the options listed, including radio waves, visible light, X-rays, and infrared light, travel at the same speed, which is the speed of light in a vacuum and all of them are electromagnetic waves. This speed is approximately 299,792,458 meters per second (or about 186,282 miles per second).

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0.840s is the half-life of lithium-8 if the decay constant is 0.825/s. The decay constant is unique to each radioactive substance and measures the speed of radioactive decay. Therefore, the correct answer is option D.

The half-life of lithium-8 can be calculated using the formula:

\(t1/2 = ln(2) / \lambda\)

Where t1/2 is the half-life, ln is the natural logarithm, and λ is the decay constant. Substituting the given decay constant of 0.825/s into the formula:

t1/2 = ln(2) / 0.825/s

t1/2 ≈ 0.840s

Therefore, the half-life of lithium-8 is approximately 0.840s. The formula for half-life is a fundamental concept in nuclear physics, which determines the time required for a radioactive substance to decay by half of its original quantity. The decay constant, which is specific to each radioactive substance, measures the rate at which radioactive decay occurs.

The higher the decay constant, the shorter the half-life, indicating that the substance is more unstable and decays faster. In this case, the decay constant of lithium-8 is 0.825/s, indicating that it is relatively unstable and has a short half-life of approximately 0.840s.

In summary, the half-life of lithium-8 is approximately 0.840s with a decay constant of 0.825/s. Therefore, the correct answer is option D.

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Hi there!

We can use a summation of torques to solve.

Recall the equation for torque:
\(\large\boxed{\Sigma \tau = rF}\)

r = distance from fulcrum (balance point)

F = force (in this instance, weight, N)

We can set the fulcrum to be the balance point of 30 cm.

Thus:
Meter ruler:

Center of mass at 48 cm ⇒ 48 - 30 = 18 cm

Object:
At 6cm ⇒ 30 - 6 = 24 cm

For the ruler to be balanced:
\(\large\boxed{\Sigma \tau_{cc} = \Sigma \tau_{ccw}}\)

Thus:
\(M_Rg(18) = 60g(24)\\M_R = \frac{60(24)}{18} = \boxed{80 g}\)

The mass of the ruler is 80 grams.

If the body were moved to 13 cm:
B (balance point) - 13 = distance of object

48 - B = distance from ruler center of mass to balance point

\(80g(48 - B) = 60g(B - 13)\\\\3840 - 80B = 60B - 780\\\\4620 = 140B\\\boxed{B = 33 cm}\)

The new balance point would be 33cm from the zero end.

\(\\ \sf\longmapsto Time=\dfrac{Distance}{Speed}\)

\(\\ \sf\longmapsto Time=\dfrac{20}{55}\)

\(\\ \sf\longmapsto Time=0.36h\)

\(\\ \sf\longmapsto Time=22min\)

Answer:

\( \dashrightarrow \: { \tt{time = \frac{distance}{time} }} \\ \\ \dashrightarrow \: { \tt{time = \frac{20}{55} \: hours }} \\ \\ \dashrightarrow \: { \tt{time = (\frac{20}{55} \times 60) \: mins }} \\ \\ \dashrightarrow \: { \boxed{ \tt{time = 21.8 \: minutes}}}\)

The surface charge density on the inner surface of the conducting shell can be expressed as: σ = q / (4πb^2), or σ = εq / (4πb^2).

To find the surface charge density on the inner surface of the conducting shell, we can use the formula:

σ = Q / A

where σ is the surface charge density, Q is the charge enclosed by the surface, and A is the area of the surface.

In this case, the charge enclosed by the surface is the charge q, since the conducting shell is neutral and does not contribute to the charge. The area of the inner surface of the shell is 4πb^2. Therefore, we have:

σ = q / (4πb^2)

Alternatively, we can use the fact that the electric field just outside the inner surface of the shell is E = q / (4πεb^2), where ε is the permittivity of free space. The electric field just inside the inner surface of the shell is zero, since the electric field inside a conductor is zero. Therefore, the charge density on the inner surface of the shell is given by:

σ = εE = εq / (4πb^2)

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A combination of longitudinal and transverse waves is called a "surface wave."

Surface waves are a type of wave that travel along the boundary or surface between two different materials or mediums, such as between air and water or between two layers of rock. These waves are characterized by a complex motion that combines both longitudinal and transverse components, resulting in a wave that moves both up and down and side to side.

Surface waves are often the most destructive type of wave in seismic activity, such as earthquakes, as they can cause the ground to move in a circular or elliptical motion. They are also important in the study of fluid dynamics, such as ocean waves and the behavior of fluids in pipes and channels.

Examples of surface waves include Rayleigh waves and Love waves, which are named after the scientists who first studied them. Rayleigh waves are primarily responsible for the shaking that occurs during earthquakes, while Love waves are responsible for the horizontal movement of the ground.

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Answer:

9.6 m/s

Explanation:

Equation is v=d/t so plug 120m to d (distance) and 12.5 sec to t (time).

v=120/12.5

v=9.6 meters per second

Answer:

D (maybe)

Explanation:

I have this question too but I think it might be D just let me check

Edit: no it wasn't D sorry

On a level ice surface, a 55-kilogram skater glides over it while being subject to a friction force of 11 newtons. The skater's acceleration is -0.2 m/s^2.

The force of friction acting on the skater can be calculated as follows:

friction = μ * N

where

μ = coefficient of friction between the ice and skates (assumed to be constant)

N = normal force, which is equal to the weight of the skater

N = m * g

where

m = mass of the skater (55 kg)

g = acceleration due to gravity (9.8 m/s^2)

By substituting the values, we get:

friction = μ * m * g = 11 N

Finally, the net force acting on the skater can be calculated as follows:

net force = friction = -11 N (opposite direction to motion)

The acceleration of the skater can be calculated using Newton's second law of motion:

a = F / m

= -11 N / 55 kg

= -0.2 m/s^2

The acceleration of the skater is -0.2 m/s^2.

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Note: The correct question would be as bellow,

A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons. Find the coefficients of static and kinetic friction between the skates and the ice.

Answer:

Explanation:

The sum of all the forces acting on an object is the net force or resultant force. If all the forces cancel out, the resultant force is zero, else, the unbalanced force will cause acceleration of the object. Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity. Once we know all the forces that are acting on a body, we resolve all of them into components (typically horizontal and vertical) and take summation of forces in each direction. If such forces cancel out (in each direction), the object maintains its state of rest or constant motion. If however, forces do not cancel out, there is a net resultant force on the object that will cause acceleration of the object (as given by Newton's second law of motion).  

Hope this helps.

The sum of all of the forces acting on an object is called net force. It is categorized as a vector quantity because it has both direction and magnitude to be considered.

Force may be defined as the process of pushing or pulling on an object with mass provoking it to change its velocity. It is an external agent capable of altering a body's state of rest or motion. It has a magnitude and a direction, so it is a vector quantity.

Net force in a case where forces of different magnitude and opposite directions will be the difference between greater and lesser force. The combination of the resultant of all the forces acting on an object is called Net Force, which is basically the sum of all the forces acting on that object.

Therefore, the sum of all of the forces acting on an object is called net force.

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Explanation:

fertilazation in the land

Answer:

current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.

Explanation:

Answer:

current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.

trust me i just did it

Explanation:

The car's acceleration can be calculated as: a = v2/R = (18.0 m/s) 2/(12.0 m) = 27.0 m/s2. The conventional method can be used to determine net force: 13500 N is equal to Fnet = m•a = (500 kg)•(27.0 m/s2).

It may slow down or decelerate when traveling uphill or straight ahead. Roller coasters accelerate as they travel down hills due to the force of gravity dragging them downward.

Calculus and other fundamental mathematical concepts are used to calculate the maximum speed, the angles of ascent and descent, and the height necessary for the automobile to climb the next hill. The roller coaster's safety is further ensured by these calculations.

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In order to calculate the distance to the reflecting object, we can use the formula: Distance = (Speed of Sound × Time) / 2 the reflecting object is approximately 445.3 meters away from the foghorn.

Distance is a numerical or occasionally qualitative measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria (e.g. "two counties over"). Given that the speed of sound is 343 m/s and the time for the echo to be heard is 2.60 seconds, we can substitute these values into the formula to calculate the distance:

Distance = (Speed of Sound × Time) / 2

Distance = (343 m/s × 2.60 s) / 2

Distance = 890.6 m / 2

Distance = 445.3 m

Therefore, the reflecting object is approximately 445.3 meters away from the foghorn.

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Suppose that at midnight you observe the Moon due south on the meridian. It will be about 26 degrees east of my meridian two nights later at midnight. Therefore, option (b) It will be about 26 degrees east of my meridian, is correct.

When you observe the moon due south on the meridian, it is at the highest point it can be in the sky at your position. The moon's movement in the sky is from east to west. As a result, two nights later at midnight, it will be about 26 degrees east of your meridian. On Earth, the sky is divided into 24 time zones, with each time zone spanning 15 degrees of longitude. The sky can be seen in its entirety over a period of one year by an observer in Bellingham. The sky is constantly changing as the earth rotates on its axis, causing the stars to appear in different positions each night. In Bellingham, the observer can see roughly half of the overall sky over the course of one year.

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Correct question:

Suppose that at midnight you observe the Moon due south on the meridian. Where will it be two nights later at midnight?

a.It will be about 26 degrees west of my meridian.

b.It will be about 26 degrees east of my meridian.

c.It will be about 26 degrees north of my meridian.

d.It will be about 26 degrees south of my meridian.

Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?

Answer:

Explanation:

As a seismologist studying earthquakes in a particular region, you might expect to find certain features of the earth's crust in that region that are indicative of tectonic activity. Some examples of these features include:

Fault lines: These are fractures in the earth's crust where two tectonic plates have moved relative to each other, often resulting in earthquakes when the movement is sudden and violent.

Folded mountain ranges: When tectonic plates collide, the resulting pressure can cause the earth's crust to fold and form mountain ranges.

Volcanoes: Many earthquakes occur in regions with volcanic activity, as the movement of magma beneath the earth's surface can cause the ground to shake.

Plate boundaries: The boundary between two tectonic plates is often a zone of high seismic activity, as the plates grind against each other and cause earthquakes.

Seismic gaps: Some areas along a fault line may have experienced few or no earthquakes in recent history, and are therefore considered "seismic gaps." These areas may be more prone to earthquakes in the future as the pressure builds up.

By studying these and other features of the earth's crust, you can gain a better understanding of the underlying tectonic processes that contribute to earthquakes in the region.

To calculate the pressure required to reduce the edge length of a solid copper cube from 85.5 cm to 85 cm, we can use the concept of bulk modulus.

K = -V(ΔP/ΔV)

ΔV = (ΔL)^3

The bulk modulus (K) relates the change in pressure (ΔP) to the fractional change in volume (ΔV/V) of a material:

K = -V(ΔP/ΔV)

Here, we are given the change in length (ΔL) as 85.5 cm - 85 cm = 0.5 cm. The original length (L) is 85.5 cm. Since the copper cube is a cube, the change in volume (ΔV) is equal to the change in length cubed:

ΔV = (ΔL)^3

Substituting these values into the equation, we get:

K = -V(ΔP/ΔV)

K = -V(ΔP/(ΔL)^3)

K = -(L^3)(ΔP/(ΔL)^3)

K = -(85.5 cm)^3(ΔP/(0.5 cm)^3)

K = -85.5^3(ΔP/0.125)

Now, since we know the bulk modulus of copper, we can substitute its value into the equation:

140 GPa = -85.5^3(ΔP/0.125)

Solving for ΔP, we can rearrange the equation:

ΔP = (140 GPa * 0.125)/(-85.5^3)

Evaluating this expression, we find:

ΔP ≈ -1.609 GPa

Therefore, approximately 1.609 GPa of pressure must be applied to reduce the edge length of the copper cube from 85.5 cm to 85 cm.

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Answer:

3,033,276 J

Explanation:

The work can be calculated as

W = Fd

Where F is the force and d is the distance.

Replacing F by 29,738 N and d by 102 m, we get:

W = (29,738 N)(102 m)

W = 3,033,276 J

Then, it has done 3,033,276 J

Answer:

a) 60kg

Explanation:

mass is not affected by gravity

The mass of Joe on the moon is approximately 60 kg. Hence, option (a) is correct.

Given data:

The weight of Joe is, W = 600 N.

The weight of any object is the product of mass and gravitational acceleration of an object. It is the expressed as,

W = mg

Here,

m is the mass of Joe.

g is the gravitational acceleration.

Solving as,

W = mg

600 = m × 10

m = 60 kg.

Thus, we can conclude that the mass of Joe on the moon is approximately 60 kg. Hence, option (a) is correct.

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The plane was flying at 39.6 m/s when the bottle was released .

\(h = ut + 1/2at^2\)

distance fallen h= 500m

Initial velocity u=0

a=98 m/s2

\(h = 1/2at^2\)

\(t^2 = 2h/a\)

\(t^2 = 1000/9.8 = 10.1s\)

\(d_h = 400, t = 10.1s\)

\(v = d_h/t\\v = 400/10.1\)

v = 39.6 m/s

Altitude or Height  (also known as depth) is a measurement of the distance between a reference point and a point or object, usually in a vertical or "upward" direction. The exact definition and reference value varies depending on the context (eg, aeronautics, geometry, geodesy, sports, or barometric pressure). Although the term height is often used to refer to the height of a place above sea level, in geography the term height is often preferred for this use.

The vertical measurement of distance in the "down" direction is usually called depth.

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Answer:

False

Explanation:

Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.

Answer:

20

27

Explanation:

Given parameters:

Atomic mass  = 47

Atomic number  = 20

Unknown:

Number of protons  = ?

Number of neutrons  = ?

Solution:

To solve this problem,

  Atomic mass  = number of protons + number of neutrons

    Atomic number  = number of protons

So;

   Number of protons  = 20

 Now;

    Number of neutrons  = Atomic mass  - number of protons

     Number of neutrons  = 47  - 20  = 27

The tension in the lower segment of the belt is 219 N. To find the tension in the lower segment of the belt, we can start by analyzing the forces acting on the flywheel.

The net torque acting on the flywheel can be expressed as the product of its moment of inertia and angular acceleration, given by the equation:

\(\[ \tau = I \alpha \]\)

Since the axle is frictionless, the only torque acting on the flywheel is due to the tension in the lower segment of the belt. The moment of inertia of a solid disk can be calculated using the equation:

\(\[ I = \frac{1}{2} m r^2 \]\)

where m is the mass of the flywheel and r is its radius. Substituting this into the torque equation, we have:

\(\[ T_{\text{u}} \cdot r_{\text{pulley}} = \frac{1}{2} m r^2 \cdot \alpha \]\)

Rearranging the equation, we can solve for the tension in the lower segment of the belt:

\(\[ T_{\text{u}} = \frac{1}{2} \frac{m r^2 \alpha}{r_{\text{pulley}}} \]\)

Plugging in the given values, with the mass of the flywheel (m = 66.5 kg), radius of the flywheel (r = 0.625 m), radius of the pulley \((r_{\text{pulley}} = 0.230 m)\), and the angular acceleration \((\alpha = 1.67 rad/s^2)\), we can calculate the tension in the lower segment of the belt:

\(\[ T_{\text{u}} = \frac{1}{2} \frac{66.5 \cdot 0.625^2 \cdot 1.67}{0.230} = 219 \, \text{N} \]\)

Therefore, the tension in the lower segment of the belt is 219 N.

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