In the summer the median number of minutes late was 12.7 minutes.
The range of the number of minutes late was 11 minutes.
The results below show the number of minutes late in the winter.
8, 32, 44,
5, 17, 67, 9,
14, 10, 26
Calvin thinks that in the winter
the median number of minutes late increases
the train service is less consistent.
.
Is Calvin correct?
Show why you think these giving reasons with your answers.

I think how you approach this depends on your knowledge of calculus.

If you don't know how to compute definite integrals yet, but you do know that they represent signed areas under curves, then you can plot both curves |x - 4| and √(36 - x ²), then recognize that the areas represented by these integrals are areas of geometric shapes. (See attached images)

First integral: if you plot |x - 4| on the interval [3, 6], you'll see that the integral corresponds to the area of two triangles. One of them has base = height = 1, and the other has base = height = 2. Then

\(\displaystyle\int_3^6|x-4|\,\mathrm dx=\frac12\times1\times1+\frac12\times2\times2=\frac52\)

Second integral: if \(y=\sqrt{36-x^2}\), then \(x^2+y^2=6^2\), meaning this curve is the upper half of a circle with radius 6. On the interval [-6, 0], the area amounts to 1/4 of the total area of such a circle, so that

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=\frac{\pi\times6^2}4=9\pi\)

* * *

If you already know a few things about calculus and integration, you can compute these areas directly.

First integral:

\(\displaystyle\int_3^6|x-4|\,\mathrm dx=\int_3^4(4-x)\,\mathrm dx+\int_4^6(x-4)\,\mathrm dx\)

\(\displaystyle\int_3^6|x-4|\,\mathrm dx=\left(4x-\frac{x^2}2\right)\bigg|_{x=3}^{x=4}+\left(\frac{x^2}2-4x\right)\bigg|_{x=4}^{x=6}\)

\(\displaystyle\int_3^6|x-4|\,\mathrm dx=\left(\left(4\times4-\frac{4^2}2\right)-\left(4\times3-\frac{3^2}2\right)\right)+\left(\left(\frac{6^2}2-4\times6\right)-\left(\frac{4^2}2-4\times4\right)\right)\)

\(\displaystyle\int_3^6|x-4|\,\mathrm dx=\frac52\)

Second integral:

Substitute x = 6 sin(t ) and dx = 6 cos(t ) dt, then

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=\int_{-\frac\pi2}^0\sqrt{6^2-(6\sin(t))^2} (6\cos(t))\,\mathrm dt\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=36\int_{-\frac\pi2}^0\cos (t) \sqrt{1-\sin^2(t)} \,\mathrm dt\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=36\int_{-\frac\pi2}^0\cos (t) \sqrt{\cos^2(t)} \,\mathrm dt\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=36\int_{-\frac\pi2}^0\cos (t) |\cos(t)| \,\mathrm dt\)

For t ∈ [-π/2, 0], cos(t ) > 0, so |cos(t )| = cos(t ) :

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=36\int_{-\frac\pi2}^0\cos^2(t)\,\mathrm dt\)

Recall the half-angle identity,

cos²(t ) = (1 + cos(2t )) / 2

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=18\int_{-\frac\pi2}^0(1+\cos(2t))\,\mathrm dt\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=18\left(t+\frac{\sin(2t)}2\right)\bigg|_{t=-\frac\pi2}^{t=0}\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=18\left(\left(0+\frac{\sin(2\times0)}2\right)-\left(-\frac\pi2+\frac{\sin\left(2\times\left(-\frac\pi2\right)\right)}2\right)\right)\)

\(\displaystyle\int_{-6}^0\sqrt{36-x^2}\,\mathrm dx=9\pi\)

Answer:

|-5|

Step-by-step explanation:

I hope this helps!

Answer:

A round pencil is sharpened at both ends the hight of the pencil is 16cm the length of the pencil is 1cm the radius of the two sharpened ends is 16cm 1.2cm

Calculate the volume using the value 22/7. 

Step-by-step explanation:

The number of fidgets and pop bought was 15 each

From the information given, we have that;

1 fidget costs $3

1 Pop cost $4

Let the number of Fidgets be x

Let the number of Pop be y

Then, we have that a total of 20 fidgets and Pop cots $75

We have that;

20x + y = 75

Now, substitute the value of x as 3, we get;

20(3) + y= 75

expand the bracket

y = 75 - 60

y = 15

The number of fidgets is expressed as;

20x/4 = 20(3) /4 = 15

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On solving the provided question, we got to know that - the  cost of common equity is 11.84

Equity in mathematics education is defined by the National Council of Teachers of Mathematics as high standards and rewarding opportunities for everyone, addressing disparities to assist all kids learn mathematics, and making sure that all classrooms have resources and support for students.

here, the above question we have  -

D0 = $0.85;

P0 = $22.80;

g = 7.00%

  = 700

Answer is  -  The  cost of common equity is 11.84

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Answer:

x=-2

Step-by-step explanation:

Distribute, add 12 to both side, then simplify

Answer: -2

Let's solve your equation step-by-step.

−2(x+6)=4x:

Step 1: Simplify both sides of the equation.

−2(x + 6) = 4x

(−2)(x) + (−2)(6) = 4x (Distribute)

−2x + (−12) = 4x

−2x − 12 = 4x

Step 2: Subtract 4x from both sides.

−2x − 12 − 4x = 4x − 4x

−6x − 12 = 0

Step 3: Add 12 to both sides.

−6x − 12 + 12 = 0 + 12

−6x = 12

Step 4: Divide both sides by -6.

−6x/−6 = 12/−6

x = −2

Huda's error in evaluating (3) squared incorrectly led to the incorrect final result.

The correct answer should be -20, not 34.

Huda's error was that she evaluated (3) squared incorrectly.

Instead of calculating 3 squared as 9, she mistakenly considered it as 3. This error led to incorrect subsequent calculations and the final result of 34, which is not the correct answer.

To evaluate the expression correctly, let's go through the steps:

Negative 3 (8 minus 5) squared minus (negative 7) \(= -3(3)^2 - (-7)\)

First, we simplify the expression within the parentheses:

\(-3(3)^2 - (-7) = -3(9) - (-7)\)

Next, we evaluate the exponent:

-3(9) - (-7) = -3(9) + 7

Now, we perform the multiplication and addition/subtraction:

-3(9) + 7 = -27 + 7 = -20

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There are no possible real values for the first term 'a' that satisfy both equations.

Let's denote the first term of the geometric progression as 'a' and the common ratio as 'r'.

The sum of the first two terms can be expressed as:

a + ar = 16

To find the sum to infinity, we can use the formula:

Sum to infinity = a / (1 - r)

Given that the sum to infinity is 25, we have:

25 = a / (1 - r)

We now have two equations:

a + ar = 16

a / (1 - r) = 25

We can solve these equations simultaneously to find the possible values of 'a'.

From the first equation, we can factor out 'a' to get:

a(1 + r) = 16

Dividing both sides of the second equation by 25, we have:

a / (1 - r) = 1

We can rearrange this equation to get:

a = 1 - r

Substituting this expression for 'a' in the first equation, we get:

(1 - r)(1 + r) = 16

Expanding the equation, we have:

1 - r^2 = 16

Rearranging the terms, we get:

r^2 = -15

Since we are dealing with a geometric progression, the common ratio 'r' must be a real number. However, we observe that r^2 = -15 has no real solutions. Therefore, there are no possible real values for the first term 'a' that satisfy both equations.

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The value of x in the triangles are 9.

For variable x : ax² + bx + c = 0, where a≠0 is a standard quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution since it is a second-order polynomial equation, which is guaranteed by the algebraic basic theorem.

Given:

The triangles are congruent.

That means, their corresponding angles are also congruent.

In ΔJKL,

the sum of all the angles of the triangle is 180°.

So,

x²-2x + x + 29 + 3x + 52 = 180

x² + 2x - 99 = 0

Solving the quadratic equation,

x² +11x - 9x - 99 = 0.

x (x + 11) -9 (x + 11) = 0

x = 9 and x = -11

Here, we take x = 9.

Therefore, the value of x is 9.

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The values of the constants m and c include the following:

m = -1.3

c = 7.1

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;

y = mx + c

Where:

Since the point P(-7, 2) is mapped onto P' (3, -11) by the reflection y = mx + c, we can write the following system of equations;

2 = -7m + c    ...equation 1.

-11 = 3m + c    ...equation 2.

By solving the system of equations simultaneously, we have:

2 = -7m - 3m - 11

11 + 2 = -10m

13 = -10m

m = -1.3

c = 7m + 2

c = 7(-1.3) + 2

c = -7.1

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Answer:

2x² + 5x + c = 0

For this quadratic equation to have one double root, the discriminant must equal 0.

5² - 4(2)(c) = 0

25 - 8c = 0

c = 25/8

2x² + 5x is not a perfect square because the coefficient of x², 2, is not a perfect square.

2x² + 5x is not a perfect square.

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Answer:

5

Step-by-step explanation:

\(35/a\), when a = 7

Substitute

\(35/7\) \(=5\)

Answer:

5

Step-by-step explanation:

You substitute 7 for a in the equation.

35/a ——> 35/7

Evaluate it and your answe is 5.

I hope it helps! Have a great day!

Lilac~

By solving a linear equation for the concentration we will see that the guy needs to use 18 ounces.

We know that the guy used 10 ounces of 6% solution with x ounces of a 12% solution to make a 8% solution, then we can write the concentration equation:

0.06*12 + 0.12*x = (12 + x)*0.08

So we just need to solve a linear equation for x.

0.06*12 + 0.12*x = (12 + x)*0.08

0.06*12 + 0.12*x = 12*0.08 + x*0.08

0.12*x - 0.08*x = 12*0.08 - 0.06*12

0.04*x = 0.06*12

x = 0.06*12/0.04 = 18

Which means that the guy needs to use 18 ounces of the 12% substance.

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The  equation of the parabola with the following properties y = (-1/4)(x+3)^2 -1

To find the equation of a parabola, we can use the formula f(x) = ax^2 + bx + c, where a, b and c are congruent vertices.

Alternatively, we can use PF = PM to find the equation of the parabola.

vertex is half way between the focus and directrix

It's a downward opening parabola, general form

y= a(x-h)^2 + k

where (h,k) = vertex= (-3,-1)

plug in another point on the parabola to solve for a which gives

am answer with either x coefficient = -1'/4 or =4 Check the math.

one or the other is right another point is the y intercept = 9a-1

Another point is directly to the right of the focus  (-1, -2)  It's 2 down from the directrix and 2 to the right of the focus, equidistant.   plug that point into y= a(x+3)^2 -1 and solve for "a"  

-2 = a((-1+3)^2 -1

-2 = 4a -1

4a = -

a = -1/4

The parabola is y = (-1/4)(x+3)^2 -1

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Answer: 18.75 lb.ft

Step-by-step explanation:

Given

Force required to stretch spring 8 in. is 18 lb

it can be written

\(\Rightarrow F=kx\\\Rightarrow 18=k(8)\\\\\Rightarrow k=\dfrac{18}{8}=\dfrac{9}{2}\ lb/in.\)

Work done in stretching from its natural length to 10 in.

\(\Rightarrow W=\dfrac{1}{2}kx^2\\\\\Rightarrow W=0.5\times \dfrac{9}{2}\times (10)^2\\\\\Rightarrow W=225\ lb.in.\ or\\\Rightarrow W=18.75\ lb.ft\)

The probability of drawing a king from a standard deck of 52 cards is 1/13.

In a standard deck of 52 playing cards, there are four kings: the king of hearts, the king of diamonds, the king of clubs, and the king of spades.

To find the probability of drawing a king, we need to determine the ratio of favorable outcomes (drawing a king) to the total number of possible outcomes (drawing any card from the deck).

The total number of possible outcomes is 52 because there are 52 cards in the deck.

The favorable outcomes, in this case, are the four kings.

Therefore, the probability of drawing a king is given by:

Probability = (Number of favorable outcomes) / (Number of possible outcomes)

= 4 / 52

= 1 / 13

Thus, the probability of drawing a king from a standard deck of 52 cards is 1/13.

This means that out of every 13 cards drawn, on average, one of them will be a king.

It is important to note that the probability of drawing a king remains the same regardless of any previous cards that have been drawn or any other factors.

Each draw is independent, and the probability of drawing a king is constant.

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Answer:

the second option is the right one pretty sure

Solution

We can use the following formula:

v= d/t

where v= velocity, d= distance, t= time

Nacy speed in good weather is:

x+ 8 mph

the speed of Nancy in storm will be x mph

The time taken to drive 45 mi in good weather is:

t1= 45/(x+8)

The time to drive 60 mi in storm is:

t2= 60/x

The total time is 3hr so we have:

And we can solve for x and we got:

then solving for x we got:

x= 32

The answer would be : 32 mph

Answer:

To find the weight of the plane with 77 gallons of fuel in its tank, we can use the linear equation for the weight of the plane in terms of the amount of fuel in its tank. The equation has the form:Weight = m * Fuel + bWhere m is the slope of the line, which is 5.9, and b is the y-intercept, which is the weight of the plane when the amount of fuel is 0. We know that the weight of the plane with 48 gallons of fuel is 2383.2 pounds, so we can use this information to solve for b:2383.2 = 5.9 * 48 + b

b = 2383.2 - 5.9 * 48

b = 2383.2 - 280.8

b = 2102.4Now that we have the value of b, we can plug it back into the equation to find the weight of the plane with 77 gallons of fuel:Weight = 5.9 * 77 + 2102.4

Weight = 456.3 + 2102.4

Weight = 2558.7 poundsSo the weight of the plane with 77 gallons of fuel in its tank is 2558.7 pounds.

Step-by-step explanation:

The figure that would make the following "a reflection in line k." is: A. first figure.

In Geometry, a reflection can be defined as a type of transformation which moves every point of the object by producing a flipped but mirror image of the geometric figure.

Generally speaking, reflections and dilations are types of transformation that preserve angle measure. Additionally, reflection can be used to preserve the direction the vertices (coordinates) that are traced around a geometric figure.

In this context, we can reasonably infer and logically deduce that the first figure is a transformation that would produce a reflection in line k because it preserves the direction of its vertices.

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The value of the variable x = 21/32

Algebraic expressions are simply described as expressions that are composed of variables, coefficients, terms, constants and factors.

These expressions are also made up of certain arithmetic or mathematical operations.

These operations includes;

From the information given, we have that;

3/8=4/7x

cross multiply the values, we have;

7x(3) = 8(4)

multiply the values and expand the brackets, we get the values;

21x = 32

Divide both sides by the coefficient of the variable x, we get;

x = 32/21

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If m/n is the probability that you do not eat green candy after you eat a red candy, then m + n is 6.

A bag contains 8 green candies and 4 red candies. If you eat five candies, there are relatively prime positive integers m and n so that m/n is the probability that you do not eat green candy after you eat a red candy. Below list the ways to accomplish this ordering along with their respective probabilities:

GRRRR : \(\frac{8}{12}\times\frac{4}{11} \times\frac{3}{10} \times\frac{2}{9} \times\frac{1}{8}\)

GGRRR : \(\frac{8}{12}\times\frac{7}{11} \times\frac{4}{10} \times\frac{3}{9} \times\frac{2}{8}\)

GGGRR : \(\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{4}{9} \times\frac{3}{8}\)

GGGGR : \(\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{5}{9} \times\frac{4}{8}\)

GGGGG : \(\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{5}{9} \times\frac{4}{8}\)

The sum is \(\frac{8\times3\times4(2+14+42+70+70)}{12.11.10.9.8}\)

Probability that you do not eat green candy after you eat a red candy =\(\frac{1}{5}\)

so m = 1 and n = 5

m + n =6

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Additive inverse property of real numbers was used to transition from step 3 to step 4

The property of real numbers used to transition from Step 3 to Step 4 is the additive inverse property or the property of adding the opposite. The additive inverse property states that for any real number a, there exists an additive inverse -a, such that a + (-a) = 0. In other words, adding the opposite of a number results in the sum being zero.

In Step 3 of the given expression, we have "12 + (-12) + 6x." Notice that "-12" is the opposite of "12." To simplify this expression further, we can apply the additive inverse property by combining the positive and negative numbers.

Adding 12 and its additive inverse (-12) results in 0, according to the additive inverse property. So, in Step 4, we replace "12 + (-12)" with "0." By applying the additive inverse property, the expression simplifies to "0 + 6x," which can be further simplified to just "6x."

The use of the additive inverse property is crucial in algebraic simplifications as it allows us to eliminate terms that add up to zero. This property helps streamline calculations and reduce complex expressions to simpler forms.

Overall, the transition from Step 3 to Step 4 in the given expression utilizes the additive inverse property to eliminate the sum of opposite numbers and simplify the expression to its final form, which is "6x."

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Answer:

25

Step-by-step explanation:

Given:

n = 33

e = 7

Basically n is the product of p and q

The value of n is given as 33

e is a value chosen such that e , 1<e<ϕ, and that gcd (e,ϕ)

Here the value of e is given as 7

The text/number to be encrypted is also given that is 16

So this means we have to compute the cipher text

We use the following formula from RSA algorithm to compute encrypt number 16. Lets say m = 16

\(c=m^{e} mod\) \(n\)

Here

e = 7

m = 16

n = 33

So putting in the values:

c = 16⁷ mod 33

  = 268435456 mod 33

  = 25     use modulo operator

c = 25

So the encrypted number is 25

The encrypted number is 25 and this can be determined by using the formula from RSA algorithm.

Given :

Alice has shared that her RSA public key is n = = 33, e = 7.

The formula from the RSA algorithm is used to encrypt the number 16. The formula is given by:

\(\rm c=m^e\;mod \;n\)

where e = 7, n = 33 and m = 16.

Now, substitute the known values in the above equation.

\(\rm c=16^7\; mod \;33\)

\(\rm c = 268435456\; mod \;33\)

Now, by using the modulo function the above expression becomes:

c = 25

So, the encrypted number is 25.

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Answer:

32

Step-by-step explanation:

90 = 7y + 27

7y = 63

y = 9

180 = 58 + 7(9) + 27 + $

$ = 32

It might be wrong