It takes light with a wavelength of 212 nm to break the n‒h bond in ammonia. What energy is required per photon to break this bond? what is the n‒h bond strength in terms of kj per mole?.

mass=30 force=50

(a) 50÷30

Every photon has some energy within it and that energy is called photon energy.

The energy of photon is \(2.38\times10^{-18}\;\rm J\).

Given that, frequency of the photon is \(3.6\times10^{15}\;\rm Hz\) and Planck's constant is \(6.626\times {{10}^{-34}}\).

So the energy of the photon can be calculated by the given formula.

\(E=h\nu\)

Where \(h\) is plank's constant and \(\nu\) is the frequency of the photon.

By substituting the values in the above formula, the photon energy is,

\(E=6.626\times10^{-34}\times3.6\times10^{15}\;\rm J\)

\(E=2.38\times10^{-18}\;\rm J\)

The energy of photon is \(2.38\times10^{-18}\;\rm J\).

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Minimum angle: θ ≈ 23.2 degrees | Rock's speed: v ≈ 2.65 m/s

To determine the minimum angle the string can make with the horizontal, we can analyze the forces acting on the rock when it is whirled in a horizontal circle.

Minimum angle:

The tension in the string provides the centripetal force required to keep the rock moving in a circle. The maximum tension the string can withstand before breaking is given as 150 N. At the minimum angle, the tension in the string will be equal to the breaking strength.

The centripetal force is given by the equation: \(F = m * (v^2 / r),\)where F is the force, m is the mass, v is the velocity, and r is the radius of the circle.

At the minimum angle, the tension (F) in the string is equal to the breaking strength, which is 150 N. The mass (m) of the rock is given as 970 g (0.97 kg), and the radius (r) is 1.8 in (0.04572 m). We can solve for the velocity (v).

\(150 N = 0.97 kg * (v^2 / 0.04572 m)v^2 = (150 N * 0.04572 m) / 0.97 kgv^2 = 7.0456 m^2/s^2v = √(7.0456) m/sv ≈ 2.65 m/s\)

Now, we can use trigonometry to find the minimum angle. The tension (150 N) is the vertical component of the tension force, and the horizontal component can be calculated using the angle θ:

Tension (horizontal component) = Tension (vertical component) / tan(θ)

Tension (horizontal component) = 150 N / tan(θ)

Since the tension in the horizontal direction is equal to the centripetal force, we can substitute the centripetal force equation:

\(m * (v^2 / r) = 150 N / tan(θ)\)

Now we can solve for the minimum angle (θ):

\(tan(θ) = (m * v^2) / (r * 150 N)θ = arctan((m * v^2) / (r * 150 N))\)

Substituting the given values, we can calculate the minimum angle.

Rock's speed at the minimum angle:

At the minimum angle, the rock's speed can be calculated using the previously derived velocity value (v).

The rock's speed at the minimum angle is approximately 2.65 m/s.

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The magnetic field strength inside a current-carrying coil is determined by the amount of current flowing through the coil and the number of turns in the coil, as well as the permeability of the material inside the coil.

In the given options, a vacuum has the highest permeability, so the magnetic field strength inside a current-carrying coil will be greater if the coil encloses a vacuum. Therefore, the correct answer is (E) vacuum.

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Physicians who are in doubt about the relative merits of the treatments in a study are said to be uncertain or indecisive.

Physicians who are in doubt about the relative merits of the treatments in a study are said to be uncertain or undecided. This uncertainty may arise when they are comparing the effectiveness, safety, or other aspects of different treatments being studied. To resolve this uncertainty, they may further review research data, seek expert opinions, or wait for more evidence to become available.

Physicians operating in the outpatient setting typically help to manage long-term chronic conditions over extended periods of time, along with regular health maintenance.

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Answer:

If the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3, then Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4

Explanation:

In order to solve this question, we must take into account that the force of gravity is given by the following formula:

\(F_{g0}=G \frac{mM_{E0}}{r^{2}}\)

So if the mass of the earth is increased by a factor of 2, this means that:

\(M_{Ef}=2M_{E0}\)

so:

\(F_{gf}=G \frac{2mM_{E0}}{r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{2mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=2\)

so if the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3

So if the mass of the earth is increased by a factor of 2, this means that:

\(M_{Ef}=3M_{E0}\)

so:

\(F_{gf}=G \frac{3mM_{E0}}{r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{3mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=3\)

so if the mass of the Earth is increased by a factor of 3, then the Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4

So if the mass of the earth is decreased by a factor of 4, this means that:

\(M_{Ef}=\frac{M_{E0}}{4}\)

so:

\(F_{gf}=G \frac{mM_{E0}}{4r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{mM_{E0}}{4r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=\frac{1}{4}\)

so if the mass of the Earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4.

The steady-state speed that can be achieved with a maximum drive power of 1.0 MW is approximately 9.73 m/s.

To determine the steady-state speed that can be achieved with a maximum drive power of 1.0 MW (megawatt), we need to consider the driving resistance and the available power.

Given information:

Mass of the locomotive (m1): 50 tonnes = 50,000 kg

Mass of each car (m2): 15 tonnes = 15,000 kg

Number of cars (n): 20

Gradient of the track (θ): 2% = 0.02

Friction coefficient (μ): 1%

Gravitational acceleration (g): 9.81 m/s^2

Maximum drive power (Pmax): 1.0 MW = 1,000,000 W

First, let's calculate the total mass of the train:

Total mass (M) = Mass of locomotive + Mass of cars

M = m1 + (m2 × n)

M = 50,000 kg + (15,000 kg × 20)

M = 50,000 kg + 300,000 kg

M = 350,000 kg

Next, we can calculate the driving resistance:

Driving resistance (R) = Gravitational resistance + Rolling resistance

Gravitational resistance (Rg) = M × g × sin(θ)

Rolling resistance (Rr) = μ × M × g × cos(θ)

R = Rg + Rr

Substituting the given values:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

R = Rg + Rr

Calculate Rg:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rg ≈ 350,000 kg × 9.81 m/s^2 × 0.02

Rg ≈ 68,430 N

Calculate Rr:

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

Rr ≈ 0.01 × 350,000 kg × 9.81 m/s^2 × 0.9998

Rr ≈ 34,267 N

Calculate R:

R = Rg + Rr

R ≈ 68,430 N + 34,267 N

R ≈ 102,697 N

Now, we can calculate the maximum velocity (vmax) using the maximum power available:

Power (P) = Force (F) × Velocity (v)

P = R × v

vmax = Pmax / R

Substituting the given values:

vmax = 1,000,000 W / 102,697 N

vmax ≈ 9.73 m/s

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Answer:

the wood for the stick is less dense so it would be easy to light on fire and maintain a fire on it, unlike a wood log witch will take a larger activation energy to have a fire last on it for a period of time.

Light bends away from the normal, because it's moving from higher to lower refractive index.

Same bend-direction as when it goes from water into air.

Answer:adapter

Explanation:

Answer:

A Tone generator sends a signal through a wire

Answer: Any particle, whether an atom, molecule or ion, that contains less electrons than protons is said to be positively charged. Conversely, any particle that contains more electrons than protons is said to be negatively charged.

Explanation: If there are more electrons than protons in a piece of matter, it will have a negative charge, if there are fewer it will have a positive charge, and if there are equal numbers it will be neutral.

The correct answer for the The last quarter phase of the moon is it crosses the meridian at sunrise .

A third quarter moon, or last quarter moon, rises around midnight and sets around noon. The Moon is nearly back to the point in its orbit where its dayside faces the Sun directly, and all we see from our vantage point is a thin curve.

The Last or Third Quarter is when we can see half of the Moon's illuminated portion and half of its shadow portion. This is why this phase is commonly referred to as Half Moon. We can only see half of the Moon because it is at a 90-degree angle to the Earth and Sun.

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General expression for the resonant wavelength in an open-closed resonator for any n:

a. λ=4L/n.

The resonant wavelength in an open-closed resonator can be found using the general expression λ=4L/n, where L is the length of the resonator and n is the mode number. This equation is valid for any value of n and is used to determine the resonant wavelengths for a variety of applications, such as in laser cavities and microwave resonators.

The expression shows that the resonant wavelength is inversely proportional to the mode number and directly proportional to the length of the resonator.

Therefore, the correct answer is a. λ=4L/n.

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Answer:

Option C

Explanation:

Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom,  therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!

Answer:

11 N

Explanation:

You will need enough force to overcome the static friction

Fn = 2.50 kg * 9.81 m/s^2

F of static friction =  Fn * coeff static =  2.50 * 9.81 * .448 =~ 11 N

Answer:

the density is 0.301 :)

Answer:

Explanation:

Using the efficiency formula. Efficiency = MA/VR * 100%

MA = Mechanical Advantage

VR = velocity ratio = \(\frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}\)

Distance moved by effort = 4.5m

distance moved by load = 1.5m

VR = 4.5/1.5 =3

Assuming efficiency is 100% (since friction can be ignored)

100% = MA/3 * 100%

1 = MA/3

MA = 3*1

MA = 3

Mechanical Advantage of the ramp is 3

H everywhere is 20π p A/m in the azimuthal direction, where p is the radial coordinate in cylindrical coordinates.

The integral form of Ampere's Law relates the magnetic field H to the current passing through a closed loop. In cylindrical coordinates, the current density is given by J(r, θ, z) = N·P(r)·uϕ(θ), where N is the number of turns per unit length, P(r) is the volume current density, and uϕ(θ) is the unit vector in the azimuthal direction.

To find H everywhere, we consider a closed loop in the azimuthal direction (ϕ) at a fixed radial distance p. Along this loop, the length element dl is in the azimuthal direction, and the magnetic field H is also in the azimuthal direction.

Applying Ampere's Law, the integral of H·dl over the closed loop equals μ0 times the total current enclosed by the loop. Since the current is uniform and flowing in the azimuthal direction, the total current enclosed is J·2πp, where J is the volume current density and 2πp is the path length along the loop at radial distance p.

Setting up the integral and solving, we have:

H·2πp = μ0·J·2πp

H = μ0·J = μ0·N·P(r) = 20πp A/m.

Therefore, H everywhere in the azimuthal direction is given by H = 20πp A/m.

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The magnitude of F is 218.75 lbs and the resultant couple acts at a distance of 2.5 ft from point A on the beam.

Find the resultant force couple magnitude, the magnitude of the resultant force couple can be calculated as follows:

Resultant couple magnitude = -50 lbftIt can be observed that the magnitude of the resultant force couple is negative. This indicates that the resultant couple moment is clockwise and not counterclockwise as given in the problem.

Resultant couple magnitude = magnitude of counterclockwise force couple - the magnitude of clockwise force couple

Resultant couple magnitude = 200 - 150 = 50 lbft

Therefore, the magnitude of the resultant force couple is 50 lbft.

The principle of moments to find the magnitude of F

Mathematically, it can be represented as follows:

ΣM (clockwise) = ΣM (counterclockwise)

F (2) - 150 (3) = 200 (4) + 50 (1)

Solving the above equation for F, we get: F = 218.75 lbs

Therefore, the magnitude of F is 218.75 lbs.

The resultant force coupled to the beam

Moments about point A:

F (2) + 200 (4) = 150 (3) + 50 (x)

where x is the distance of the resultant couple from point A on the beam.

Solving the above equation for x, we get: x = 2.5 ft

Therefore, the resultant couple acts at a distance of 2.5 ft from point A on the beam.

The magnitude of F is 218.75 lbs and the resultant couple acts at a distance of 2.5 ft from point A on the beam.

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Answer:

D. Black

Explanation:

hope I help you.

i think number answer is D Black i hope help you

A frequency of 6.2 MHz is needed to produce a clear image of a tumor that is 1.0mm in diameter, assuming the speed of sound in the tissue is 1550m/s. To produce a clear image of a tumor that is 1.0mm in diameter, the wavelength of the sound should be around 1/4th the size of the object being viewed. This means that the wavelength of the sound should be approximately 0.25mm.

To determine the frequency of the sound needed to produce this wavelength, we can use the formula:
wavelength = speed of sound / frequency
0.25mm = 1550m/s / frequency
Solving for frequency, we get:
frequency = 1550m/s / 0.25mm
frequency = 6.2 MHz

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Answer:

La velocidad del sistema bala-bloque es 5 metros por segundo.

Explanation:

El enunciado tiene una omisión gramatical. La forma correcta es la siguiente:

Una bala de 0.8 kilogramos de masa se mueve horizontalmente con una velocidad de 30 metros por segundo y se introduce en un bloque de 4 kilogramos, inicialmente en reposo. ¿Cuál es la velocidad de la bala y el bloque después del impacto?

Esta situación es un caso clásico de colisión enteramente inelástica, en donde el sistema bala-bloque no tiene influencia de fuerzas externas, entonces la situación queda descrita por la siguiente ecuación:

\(m_{b}\cdot v_{b,o} = (m_{b}+m_{B})\cdot v\) (1)

Donde:

\(m_{b}\) - Masa de la bala, en kilogramos.

\(v_{b,o}\) - Velocidad inicial de la bala, en metros por segundo.

\(m_{B}\) - Masa del bloque, en kilogramos.

\(v\) - Velocidad del sistema bala-bloque, en metros por segundo.

Si sabemos que \(v_{b,o} = 30\,\frac{m}{s}\), \(m_{b} = 0.8\,kg\) y \(m_{B} = 4\,kg\), entonces la velocidad del sistema masa-bloque es:

\(v = \frac{m_{b}}{m_{b}+m_{B}}\cdot v_{b,o}\)

\(v = 5\,\frac{m}{s}\)

La velocidad del sistema bala-bloque es 5 metros por segundo.

Answer:

B. \(F = -k*x\)

Explanation:

The force of a spring can be easily calculated using Hooke's law which tells us that the force applied on a spring is equal to the product of the constant of a spring by the compressed or stretched distance of the spring.

That is:

\(F = k*x\)

k = spring constant [N/m]

x = distance [m]

As energy is conserve:

\(Epi+Ekl=Epf+Ekf\)

i - initial

f - final

Beginning object at rest, \(Eki=0\). Object on the lowest position, hence \(Epf=0\).

Therefore:

\(Epi=Epf\)

\(M.g.h.=\frac{1}{2} (v^{2} )\)

Assume no Mass changed:

\(g.h.=\frac{1}{2}( v^{2} )\)

V is at bottom and assuming that \(g=\frac{10m}{s^2}\):

\(v=\sqrt{2gh}\)

\(v=\sqrt{2(10)(80)}\)

\(v=\sqrt{1,600}\)

\(v=40\)

The velocity is \(40m/s\)

According to the question, the velocity of ball 2 after the collision is 30 m/s.

What is velocity?
Velocity is a vector quantity that describes the rate and direction of an object's motion. It is the displacement of an object over a period of time and is usually expressed in terms of distance (meters, feet, or kilometers) divided by time (seconds). It can also be expressed as the speed of an object in a particular direction. Velocity is a key factor in describing the motion of objects, as it accounts for both the speed and direction of an object's motion. It is an important concept in physics, and it is used to calculate forces and potential energy.

From the laws of conservation of momentum, the final velocity of ball 2 can be calculated as follows:

m1u + m2v = m1v1 + m2v2

0.2 x u + 0.2 x v = 0.2 x u + 0.2 x v2

v2 = u - (6N x 0.1s)/0.2kg

v2 = u - 30 m/s

Therefore, the velocity of ball 2 after the collision is 30 m/s.

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The minimum time required to raise the bucket a vertical distance of 12m without breaking the cord is 2.58s

Given the mass of bucket of water (m) = 5.60kg

The strength acting on bucket is (F) = 75N

The distance bucket is raised (s) = 12m

Let the time taken to raise the bucket = t

So, W = m x g as a force of gravity is always acting on a system.

W = 5.60 x 9.8 such that W = 54.88N

The maximum accelerating force acting on the cord (Fr) = 75 - 54.88 = 20.12N

We know that from Newtons laws of motion F = ma where a is the acceleration and F is the force.

Fr = ma then a = 20.12/5.60 = 3.59m/s^2

Then according to the problem s = ut + 1/2at^2 where u is initial velocity which is 0m/s as at rest initially.

So, s = 1/2at^2 then 12 = 1/2 x 3.59 x t^2

t^2 = 24/3.59  = 6.68

t = 2.58s

Hence the minimum time required to raise the bucket a vertical distance of 12 m without breaking the cord is 2.58seconds.

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Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt