Jake is in chemistry class. he makes a list of the chemicals his instructor described and the properties of each. silver: bonds with other atoms because of the weak forces of the valence electrons water: bonds allow for liquid state at room temperature and prevent conduction carbon: bonds with other atoms through strong shared electrical bonds niobium: bonds allow for a strong conductivity found in stainless steel which is most likely true about the chemicals? silver and niobium are metals. water and carbon are metals. silver and carbon are metals. water and niobium are metals.

0.050 moles of hydrogen gas are liberated when a given quantity of charge liberates 0.050 moles of lead.

The amount in moles of hydrogen produced when the same quantity of electricity is passed through different electrolytes is inversely proportional to the charge on the ions.

The charge on the Lead ion is +2.

The charge on the hydrogen ion is +1.

2 atoms of hydrogen gives one molecule of hydrogen gas.

Hence, equal charge liberates equal amounts in moles of lead and hydrogen gas.

Therefore, 0.050 moles of hydrogen gas are liberated when a given quantity of charge liberates 0.050 moles of lead.

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Answer:

B solvent

Explanation:

Answer:

Explanation: the answer is YES

CO(NH2)2  and (NH2)2 CO is the urea

Answer:

3.60X10^-12 is equal to 0.360X10^-11 (move decimal one place left)

Now you can add 3.60X10^-11 and 0.360X10^-11:

3.60X10^-11 + 0.360X10^-11 = 3.96X10^-11

You're really just adding 3.60 to 0.36 since the "X10^-11" is the same for both.

Specific Heat of the metal will be = 4.184 J/C

Mass of metal = 28 g

Mass of water = 28 g

Rise in temperature = 23.8 - 19 = 4.8 C

Specific heat of water = 4.184 J/C

Let the specific heat of metal =S

The heat released by metal =mass of metal * specific heat of metal * Change in temperature

\(& =28\times S \times 4.8{ }^{\circ} \mathrm{C} \\& =134.4 S^{\circ} \mathrm{C}\)

Heat absorbed by water = mass of water x specific heat of water x change in temp. \(=28 \times 4.184 \times 4.8=562.3296 J\)

Using the principal of Caloriemeter:

We have, Heat released by metal = Heat absorbed by water

134.4S = 562.3296 =>4.184 J/C

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The correct question should be:

if we are heated a metal with 28g mass then we add it in a coffee cup with 28g water. the water temperature raised from 19 degree to 23.8 oc. what was the specific heat of the metal. the water specific heat of water is 4.184 j/g oc.

Assuming the quantity of current passing through the zinc and copper electrolytes is the same, mass of Zinc deposited is (x/64) × 65.0 g.

Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through its solution or molten form.

The mass of an electrolyte deposited when current is passed is dependent on the current and the charge on the ion.

In the electrolysis of copper and zinc, assuming the quantity of current passed through their solution are the same, the moles of each zinc and copper deposited will be the same since the charges on their ions are the same.

Assuming x g of copper is deposited.

molar mass of copper = 64.0 g

molar mass of Zinc = 65.0 g

moles of copper deposited = x/64

moles of zinc deposited = x/64

mass of Zinc deposited = (x/64) × 65.0 g

Therefore, the mass of Zinc deposited is (x/64) × 65.0 g.

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Answer:

4.70 grams of NH4Cl is needed to prepare 350 mL of a 0.25 M ammonium chloride solution.

We need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To determine the mass of NH4Cl needed to prepare the solution, we us use the formula:

m=M x V x MM ... (i)

where,

m= mass in grams

M=molarity of solution

MM= molar mass of compound

V= volume in litres

The number of moles of NH4Cl needed can be calculated using:

  Moles = Molarity x Volume ...(ii)

  Moles = 0.25 mol/L x 0.350 L

  Moles = 0.0875 mol

Hence we can replace M x V with number of moles in equation i.

The molar mass of NH4Cl is :

  Molar mass of NH4Cl = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (1 x 35.45 g/mol)

  Molar mass of NH4Cl = 53.49 g/mol

We have all the variables

Putting them in equation i.

Hence,

  Mass (g) = Moles x Molar mass

  Mass (g) = 0.0875 mol x 53.49 g/mol

  Mass (g) = 4.68 g

Therefore, you would need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

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The shelf-life of the reconstituted ampicillin suspension remains unchanged at 16 days when stored at room temperature (25°C) compared to storing it in the refrigerator at 5°C.

To calculate the shelf-life of the reconstituted ampicillin suspension at room temperature, we'll assume that the degradation follows an Arrhenius relationship.

Shelf-life at 5°C (T₁) = 16 days

Temperature at 5°C (T₁) = 5°C

Temperature at room temperature (T₂) = 25°C

To find the shelf-life at room temperature, we can use the Arrhenius equation:

k₁ / k₂ = exp((Ea / R) * (1/T₂ - 1/T₁))

Since we don't have specific values for Ea and the reaction rate constants, we'll assume that they are the same for simplicity. Thus, we can write:

k₁ / k₂ = exp((Ea / R) * (1/25 - 1/5))

Simplifying the equation, we get:

exp((Ea / R) * (4/125)) = 1

To satisfy this equation, the exponential term must be zero, which implies:

(Ea / R) * (4/125) = 0

Solving for Ea, we find:

Ea = 0

Since Ea is zero, it means the reaction rate constants and degradation rates are the same at both temperatures. Therefore, the shelf-life at room temperature (25°C) is the same as the shelf-life at 5°C, which is 16 days.

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Answer:

Heat = 3138J

Explanation:

In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.

Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):

Q = C×m×ΔT

Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)

Replacing:

Q = 4.184J/molK×50g×15°C

Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).

Answer:

heat=3138j

Explanation:

In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.

Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):

Q = C×m×ΔT

Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)

Replacing:

Q = 4.184J/molK×50g×15°C

Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).

The correct answer is option 4: 2,3-Dimethyloxan-4-one. In a crossed aldol addition reaction, two different aldehydes or ketones are used as reactants to form a β-hydroxy aldehyde or ketone.

The reaction involves the nucleophilic addition of an enolate ion to the carbonyl group of the other reactant, followed by dehydration.

When considering the reaction between ethanal (CH3CHO) and butanal (CH3(CH2)2CHO), there are several possible products that can be formed. Let's evaluate the options:

3-Hydroxybutanal (CH3(CH2)2CH(OH)CHO): This product can be formed by the nucleophilic addition of the enolate of ethanal to the carbonyl group of butanal. It is a valid product.

4-Hydroxybutanal (CH3(CH2)2CHOHCHO): This product can also be formed by the nucleophilic addition of the enolate of butanal to the carbonyl group of ethanal. It is a valid product.

2-Hydroxy-2-methylbutanal (CH3(CH2)2C(OH)(CH3)CHO): This product can be formed by the nucleophilic addition of the enolate of ethanal to the carbonyl group of butanal, followed by dehydration and methyl migration. It is a valid product.

2,3-Dimethyloxan-4-one: This compound does not correspond to a possible product resulting from the crossed aldol addition between ethanal and butanal. It does not involve the formation of a β-hydroxy aldehyde or ketone. Therefore, option 4 is not a possible product in this reaction.

Therefore, the correct answer is option 4: 2,3-Dimethyloxan-4-one.

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The most effective method of for increasing the rate of evaporation Only so much water vapour can be contained in air. You will ultimately hit the condensation point if you keep adding more. The airborne water vapour transforms back into liquid at this point.

The temperature of the air affects this location. In comparison to cooler air, warmer air will store more water vapour. Therefore, warm air above the water would be helpful if you wanted to speed up evaporation.Simply put, we refer to the water vapour in the air as humidity. The percentage of water vapour in the air over the air's maximal vapor-holding capacity is known as relative humidity. As a result, if the air is only carrying half of the water vapour.

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The correct answer is B. NaHCO3 (sodium bicarbonate) is soluble in water because NaHCO3 is an ionic compound with polar characteristics, allowing it to dissolve in the polar solvent water..

Water is a polar solvent, meaning it has a partial positive and negative charge due to the uneven distribution of electrons between the hydrogen and oxygen atoms. Hexane (C6H14), on the other hand, is a nonpolar solvent, meaning it lacks any significant charge separation.
Solubility of a solute is determined by the principle "like dissolves like," which means that polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.
The other options are incorrect because:
A. CaCl2 (calcium chloride) is soluble in water, not hexane, due to its polar nature as an ionic compound.
C. Octane (C8H18) is nonpolar and soluble in nonpolar solvents like hexane, not in polar solvents like water.
D. Mineral oil is nonpolar and soluble in nonpolar solvents, not in polar solvents like water.

Therefore, NaHCO3 (sodium bicarbonate) is soluble in water (Option b). This is because NaHCO3 is an ionic compound with polar characteristics, allowing it to dissolve in the polar solvent water.

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Here are the answers

\(\\ \tt\hookrightarrow HCl+NaOH\longrightarrow NaCl+H_2O\)

\(\\ \tt\hookrightarrow H_2SO_4+2NaOH\longrightarrow Na_2SO_4+2H_2O\)

\(\\ \tt\hookrightarrow 2HCl+Ba (OH)_2\longrightarrow BaCl_2+2H_2O\)

Answer:

Explanation:

Hello there, I think this is a limiting agent question.

When 3 moles of Mg is reacted with 2 moles of Br2, because of ratio, we just need 1.5 moles of Br2, so Mg is a limiting agent.

So 3 moles of Mg will make 3 moles of MgBr

Answer:

Use the given functions to set up and simplify

Mg+Br2→MgBr⋅2.

3=

2=

Mg+Br2→gBr⋅2=r2B+gM→MgBr⋅2

Explanation:

SORRY IF I AM WRONG HAVE A BLESS DAY :D

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

Answer:

The energy of the wave particle is 3.058 x 10⁻²³ J.

Explanation:

Given;

wavelength of the wave particle, λ = 6.5 x 10⁶ nm = (6.5 x 10⁶) x 10⁻⁹ m

The energy of the wave particle is calculated as;

\(E = hf\\\\E = \frac{hc}{\lambda}\)

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/Hz

c is speed of light = 3 x 10⁸ m/s

\(E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{6.5 \times 10^6 \times 10^{-9}} \\\\E = 3.058 \times 10^{-23} \ J\)

Therefore, the energy of the wave particle is 3.058 x 10⁻²³ J.

Answer:

The initial volume of the container was 1.27L

Explanation:

Avogadro's law states that under the same pressure and temperature, equal moles of gases occupies equal volume. The equation is:

V₁n₂ = V₂n₁

Where V is volume and n moles of 1, initial state and 2, final state.

In the problem, initial moles are 5.67x10⁻², final moles after the addition are:

5.67x10⁻² + 2.95x10⁻² = 8.62x10⁻² moles

And, after the addition, the volume is 1.93L.

Replacing in Avogadro's law:

V₁×8.62x10⁻² moles = 1.93L×5.67x10⁻² moles

V₁ = 1.27L

Answer: exothermic

Explanation: The key is to look at the enthalpy (-136kJ/mol). Since it’s negative, the reaction is losing heat, therefore it’s exothermic.

Answer: voltage drops in each resistor ΔU= RI

Explanation: if lamps or other resistor which cause load are in series in

Electric circuit, current I passing circuit is same. Voltage decreases

In every resistor

The most stable resonance structure if nitrogen is the central atom in the CNO⁻ ion is seen in the first structure in the image attached below.

Resonance structures show the different forms of lewis structure in which a compound can exist whether as a stable resonance or an unstable resonance. It also explains the electronic bonding existing in a polyatomic compound with its bonds and charges.

The structure carrying the negative charge on the most electronegative atom is the most stable structure in resonance structures.

In the given compound CNO⁻, the lewis structure in which the resonance can exist is shown in the image attached below.

The first structure is the most stable because the negative charge is on the most electronegative element (oxygen).

The second structure has a (-2) oxidation state with two non-bonding electron pairs.

The third structure has a positive oxidation charge the electronegative oxygen which also makes it unstable.

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When Benzoic Acid reacts with aqueous NaOH, a species of ester and Benzene named, Benzoate Ion is formed.

When Benzoic acid is reacted with aqueous NaOH, water and Sodium benzoate is formed.

Sodium benzoate is present with water, So, the sodium benzoate dissolves in water and forms benzoate ion.

Benzoate are species of ester.

Benzoate ion is soluble in water while benzoic acid is not soluble in water.

Benzoic acid forms a layer over water.

Benzoate is of great use in industrial purposes, it is used in food preservative and beauty products.

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Metallic ions differ from the ions in ionic solids in their bonding and structure. Metallic ions form a metallic bond, which is a sea of delocalized electrons surrounding positively charged ions. These electrons are free to move and allow metals to conduct electricity and heat. In contrast, ionic solids consist of a lattice structure, where positively charged cations and negatively charged anions are bonded together through electrostatic forces called ionic bonds.

Metallic ions and ions in ionic solids differ in their properties and behavior due to the different nature of their bonding. Metallic ions are found in metals, which have a delocalized electron sea that allows for the formation of a metallic bond. This bond is characterized by the sharing of valence electrons among the atoms, creating a lattice of positively charged ions surrounded by a sea of electrons. In contrast, ionic solids consist of a lattice of positively and negatively charged ions held together by electrostatic forces. The ions in ionic solids are held rigidly in place and cannot move freely like the delocalized electrons in metallic bonding. This difference results in different physical and chemical properties, such as the higher electrical conductivity and malleability of metals compared to ionic solids. Overall, the nature of the bonding between the ions determines their properties and behavior.

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Answer:

cholera and salmonella

Explanation:

i believe so

The complete chemical formula for the unknown compound is P2Cl4.

Based on the given information, the compound is composed of phosphorus (P) and chlorine (Cl) atoms. The chemical formula PxCI4 indicates that there is one phosphorus atom bonded with four chlorine atoms. However, the value of x, which represents a whole number, is unknown at this point. To determine the complete chemical formula, we need to find the appropriate value of x based on the given measurements of the compound.

To determine the value of x, we can compare the mole ratios of phosphorus and chlorine in the compound. The molar ratio between phosphorus and chlorine can be obtained by dividing the number of moles of each element by their respective coefficients in the chemical formula. In this case, the number of moles of phosphorus (5.3 mol) divided by the coefficient of phosphorus (1) is equal to 5.3. Similarly, the number of moles of chlorine (10.8 mol) divided by the coefficient of chlorine (4) is equal to 2.7.Since the ratio of phosphorus to chlorine is 5.3:2.7, we can simplify this ratio by dividing both sides by 2.7. This gives us approximately 1.96:1. From this simplified ratio, we can conclude that x, the value representing the number of phosphorus atoms, is approximately 2.

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The hydrogen atoms are each sharing a single bond, which means they are each sharing one electron. All atoms have a full valence shell, and there are no lone pairs left. Therefore, the Lewis structure for \(N_2H_2\)(HNNH) is.

H       H

 \     /

  N==N

 /     \

H       H

A lone pair is a pair of electrons that is not involved in bonding with other atoms or molecules. Lone pairs are typically found in the valence shell of atoms, which is the outermost shell of electrons that participates in chemical reactions. These pairs of electrons are called "lone" because they are not shared with another atom or molecule to form a covalent bond.

Lone pairs can have a significant impact on the chemical and physical properties of a molecule. For example, they can influence the shape and polarity of a molecule, which in turn can affect its reactivity and interactions with other molecules. In some cases, lone pairs can even participate in chemical reactions, such as in acid-base chemistry. The presence and location of lone pairs can be predicted using molecular orbital theory and can be observed using techniques such as X-ray crystallography or infrared spectroscopy.

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Answer:

9. b

10. a

Density would have to do with if the powder is floating or sinking, conductivity would have to do with heat and mass would have to do with weight, leaving solubility as the only reasonable answer.