Jannette says because 's sides form a Pythagorean triple and 's side lengths are multiples of 's side lengths. Is she correct? Explain your reasoning.

50%

since 98/2 = 49

Thats it

A ratio in mathematics displays how often one number occurs in another and the given situation's specific heat ratio is 1.24.

In mathematics, a ratio shows how frequently one number appears in another.

For instance, the ratio of oranges to lemons in a fruit plate would be eight to six if there were eight oranges and six lemons.

Oranges make up 8:14 of the total fruit, whereas lemons make up 6:8 of the total fruit.

So, e are informed that the volume is halved, and the pressure increases by a factor of 2.5.

We shall therefore have:

PVγ = 2.5P(0.5V)γ

We'll condense this to:

(1/0.5)γ = 2.5

γ = In2.5/In2

γ = 1.32

The volume temperature relation is written as follows if the volume expands in an adiabatic process:

T1V1∧γ-1 = T2V2∧γ-1

T1V1∧1.32-1 = T2(0.5V1)∧1.32-1

Condensing this results in:

T₁ = 1.24T₂

Therefore, a ratio in mathematics displays how often one number occurs in another and the given situation's specific heat ratio is 1.24.

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The statement that is true is that the amount of rain in the 24- hour period is 8 inches

From the question, we have the following parameters that can be used in our computation:

In 90 minutes 1/2 inch of rain falls

This means that

Rate = (1/2 inch)/90 minutes

So, we have

Rate = (1/2 inch)/(1.5 hour)

The amount of rain in the 24- hour period is

Amount = Rate * Time

So, we have

Amount = (1/2 inch)/(1.5 hour) * 24 hours

Evaluate

Amount = 8 inches

Hence, the amount of rain in the 24- hour period is 8 inches

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The correct values for a, b, c, d, and e are a = 16, b = 29, c = 24, d = 22, and e = 30 for group of 75 students on asking whether they like Algebra or Geometry.

For the values of a, b, c, d, and e, we can use the information provided in the table. Let's break it down step-by-step:

We are given that a total of 75 math students were surveyed. Therefore, the total number of students should be equal to the sum of the students who like algebra, the students who like geometry, and the students who do not like either subject.

75 = 45 (Likes Algebra) + 53 (Likes Geometry) + 6 (Does Not Like Either)

Simplifying this equation, we have:

75 = 98 + 6

75 = 104

This equation is incorrect, so we can eliminate options c and d.

Now, let's look at the information given for the students who do not like geometry. We know that a + b = 6, where a represents the number of students who like algebra and do not like geometry, and b represents the number of students who do not like algebra and do not like geometry.

Using the correct values for a and b, we have:

16 + b = 6

b = 6 - 16

b = -10

Since we can't have a negative value for the number of students, option a is also incorrect.

The remaining option is option e, where a = 29, b = 16, c = 24, d = 22, and e = 30. Let's verify if these values satisfy all the given conditions.

Likes Algebra: a + c = 29 + 24 = 53 (Matches the given value)

Does Not Like Algebra: b + d = 16 + 22 = 38 (Matches the given value)

Likes Geometry: c + d = 24 + 22 = 46 (Matches the given value)

Does Not Like Geometry: b + e = 16 + 30 = 46 (Matches the given value)

All the values satisfy the given conditions, confirming that option e (a = 29, b = 16, c = 24, d = 22, and e = 30) is the correct answer.

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Answer: 2.6

Step-by-step explanation:

1.25 + 1.35 = 2.6

Answer:

1.25+1.35=2.6

Step-by-step explanation:

Answer:

b/w 19 & 55

Step-by-step explanation:

average of four equally weighted 100-point tests,

mark has scored 90, 86, and 85 on the first three.

C average = 70 and 79

90+86+85+x = 4*70 = 280, so x=19

90+86+85+x = 4*79 = 316, so x=55

Answer:

5

Step-by-step explanation:

Replace variables with integers

(-2) - (-7)

Solve.

-2 - (-7) --> -2 + 7 --> 5

1. An example of a surjective NFA (Non-deterministic Finite Automaton) is one where every state has at least one outgoing transition for every input symbol.

2. An example of a bijective NFA is one where every state has exactly one outgoing transition for every input symbol.

3. An example of an injective NFA is one where no two states have the same outgoing transition for any input symbol.

An NFA is a computational model used in theoretical computer science and automata theory to describe the behavior of finite state machines. In the context of surjective, bijective, and injective NFAs, we consider the properties of the transitions between states.

A surjective NFA is one in which every state has at least one outgoing transition for every input symbol. This means that for any input symbol, there is a valid transition from every state to some other state or states. An example of a surjective NFA could be a state machine representing a regular expression that matches any sequence of characters.

A bijective NFA is one in which every state has exactly one outgoing transition for every input symbol. In other words, for each input symbol, there is a unique and deterministic transition from every state to another state. An example of a bijective NFA could be a state machine representing a simple calculator that performs addition or subtraction.

An injective NFA is one in which no two states have the same outgoing transition for any input symbol. This means that for any input symbol, there is a unique transition from each state to another state. An example of an injective NFA could be a state machine representing a binary counter, where each state corresponds to a unique binary number.

These examples illustrate the different properties of surjectivity, bijectivity, and injectivity in NFAs and how they affect the transitions between states.

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If the variables are not quantitative we cannot do the arithmetic required in the formulas for r.

Quantitative order:

Therefore, if the variables are not quantitative we cannot do the arithmetic required in the formulas for r.

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The equation of the line normal to the curve y = 8tan(x^2) at x = 0.1825 is y ≈ -0.117x + 1.451

To find the equation of the line normal to the curve y = 8tan(x^2) at x = 0.1825, we need to follow these steps:

Find the derivative of the curve y = 8tan(x^2) using the chain rule.

y' = 16xsec^2(x^2)

Evaluate the derivative at x = 0.1825 to find the slope of the tangent line at that point.

y'(0.1825) = 16(0.1825)sec^2(0.1825^2) ≈ 1.559

Since the normal line is perpendicular to the tangent line, its slope will be the negative reciprocal of the tangent line's slope.

m_normal = -1/m_tangent = -1/1.559 ≈ -0.641

Use the point-slope form of the equation of a line to find the equation of the normal line, using the point (0.1825, 8tan(0.1825^2)).

y - 8tan(0.1825^2) = -0.641(x - 0.1825)

Simplifying this equation, we get:

y ≈ -0.117x + 1.451

Therefore, the equation of the line normal to the curve y = 8tan(x^2) at x = 0.1825 is y ≈ -0.117x + 1.451.

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The sample space for the experiment of tossing a pair of dice consists of all possible outcomes of the two dice rolls. Using a rule method, we can represent the sample space as S = {(1,1), (1,2), (1,3), ..., (6,5), (6,6)}.

(a) The event A corresponds to the sum of the outcomes being greater than 8. The elements of event A are (3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6).
(b) The event B corresponds to a 2 occurring on either die. The elements of event B are (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (1,2), (3,2), (4,2), (5,2), (6,2).
(c) The event C corresponds to a number greater than 4 appearing on the green die. The elements of event C are (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).
(d) The event A∩C corresponds to the outcomes where both the sum is greater than 8 and a number greater than 4 appears on the green die. The elements of event A∩C are (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6).
(e) The event A∩B corresponds to the outcomes where both the sum is greater than 8 and a 2 occurs on either die. There are no elements in this event.
(f) The event B∩C corresponds to the outcomes where both a 2 occurs on either die and a number greater than 4 appears on the green die. The elements of event B∩C are (5,2), (6,2).
(g) The Venn diagram illustrating the intersections and unions of the events A, B, and C would have three overlapping circles representing each event. The area where all three circles intersect represents the event A∩B∩C, which is empty in this case. The area where circles A and C intersect represents the event A∩C, and the area where circles B and C intersect represents the event B∩C. The unions of the events can also be represented by the combinations of overlapping areas.

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2.4

(a) Sample space S: {(1, 1), (1, 2), ... (6, 5), (6, 6)}

(b) Rule method: S = {(x, y) | x, y ∈ {1, 2, 3, 4, 5, 6}}

2.8

(a) A: {(3, 6), (4, 5), ... (6, 6)}

(b) B: {(1, 2), (2, 1), (2, 2)}

(c) C: {(5, 1), (5, 2), ... (6, 6)}

(d) A∩C: {(5, 4), ... (6, 6)}

(e) A∩B: {}

(f) B∩C: {}

2.4

(a) Sample space S by listing the elements (x, y):

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

(b) Sample space S using the rule method:

S = {(x, y) | x, y ∈ {1, 2, 3, 4, 5, 6}}

2.8

(a) Elements corresponding to event A (the sum is greater than 8):

A = {(3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)}

(b) Elements corresponding to event B (a 2 occurs on either die):

B = {(1, 2), (2, 1), (2, 2)}

(c) Elements corresponding to event C (a number greater than 4 on the green die):

C = {(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

(d) Elements corresponding to event A∩C:

A∩C = {(5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)}

(e) Elements corresponding to event A∩B:

A∩B = {} (No common elements between A and B)

(f) Elements corresponding to event B∩C:

B∩C = {} (No common elements between B and C)

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The type of random variable in this scenario is a geometric random variable. Its parameter is the probability of failure for each integrated circuit being tested.

The type of random variable you're dealing with in this scenario, where you are testing integrated circuits in sequence until you find the first failure, is called a Geometric Random Variable. This type of random variable represents the number of trials needed for the first success (or failure, in this case) in a series of independent Bernoulli trials with the same probability of failure. The parameter for a Geometric Random Variable is the probability of failure, denoted as p. In summary, the type of random variable in this problem is a Geometric Random Variable, and its parameter is the probability of failure (p).

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The best way of writing a prolog rule that gives you all the possible coin combinations adding to a dollar is using membership rules and arithmetic condition.

The Prolog interpreter warns that it can only find one occurrence of one or more variables, which is strange, since typically variables are used to perform unification, pass values from one predicate to another, etc.

Arithmetic in Prolog

In arithmetic expression, + - * / symbols are special type of infix operator, and these operators are also known as arithmetic operators. In Prolog, operators are used as predicates but here operators are functions and these operators return a numerical value.

Arithmetic expressions can include variables, numbers, operators, and arithmetic functions. These will be written in parentheses with their arguments. These will return numerical values just like the arithmetic operators.

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Answer: 15,600 different choices for initials

Step-by-step explanation:

26 choices for the first, 25 for the second, and 24 for the third. When multipled, this is 15600.

Answer:

Step-by-step explanation:

Plot 213, −56, and −312 on the number line.

Answer:

\(\Huge \boxed{\£55}\)

________________________________________________________

A 17% reduction means that the dress cost 83% (100 - 17) of the original amount.

\(\large \fbox{\begin{minipage}{8.1 cm}83\% of the original price = \£45.65\\\\$\Rightarrow$1\% of the original price = $\frac{45.65}{83}$\\\\$\Rightarrow$1\% of the original price = 0.55\\\\$\Rightarrow$100\% of the original price = 0.55 \times 100\\\\$\Rightarrow$100\% \text{ of the original price = \£55}\end{minipage}}\)

To work out 83% of the original price, you multiply by 0.83. We can do the inverse, which is dividing by 0.83.

                                 ×0.83

Original Price →→→→→→→→→→→→→ Sale Price

        £?           ←←←←←←←←←←←←←     £45.65

                                ÷0.83

\(\large \boxed{\begin{minipage}{7 cm}Original Price = $\frac{\text{Sale Price}}{0.83}$\\\\$\Rightarrow$Original Price = $\frac{45.65}{0.83}$\\\\$\Rightarrow$Original Price = \£55\end{minipage}}\)

Therefore, the original price of the dress is £55.

________________________________________________________

Answer:

m < 16

Step-by-step explanation:

598 + 15.75m < 850

15.75m < 850 - 598

15.75m < 252

m < 16

The products that are defined are given as follows:

LP, LQ.

The products that are not defined are given as follows:

NM, QM.

The multiplication of two matrices is possible when the number of columns of the first matrix is equals to the number of rows of the second matrix.

The dimensions of each matrix are given as follows:

Hence the defined products are:

LP, LQ.

The non-defined products are:

NM, QM.

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The above is an analysis of functions.

A) See the graph attached
1) This is a growth function

2) the asymptote is at y = -3

3) the domain is a real number

4) Range is ≥ -3
5) Y-intercept is (0, -11/4)


B) See attached graph.

1) this is a decay function

2) y=3 is the horizontal asymptote of the function
3) domain is a real number
4) Range ≤ 3
5) y-intercept is 5

A) The formula for f(x)  is 4( x-1)- 3 is an exponential  function with an exponent of (x- 1) and a base of 4 . Given that the base is bigger than 1,   it is therefore, a growth function.

The function's horizontal asymptote is y = -3. The function may accept any value greater than or equal to -3 and is defined for all real numbers. The function's y-intercept is -11/4.

B) The function f( x) = 2(1/2)^x + 3 is an exponential function with a base of 1/2 and an exponent of x.

Considering that the  base is smaller than 1 , it is a decay function. The function's horizontal asymptote is y = 3. The function may accept any value that is less than or equal to 3 and is defined for all real numbers. The function's y-intercept is 5.

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By finding a common denominator, we can rewrite the sum as:

3/8 + 7/12 = 9/24 + 14/24 = 23/24

Here we want to find the sum between two fractions that have different denominators.

To sum them, we need to find a common denominator, so we need to find a common multiple between 8 and 12.

We know that:

8*3 = 24

12*2 = 24

Then we can multiply and divide the first fraction by 3:

3/8*(3/3) = 9/24

7/12*(2/2) = 14/24

Then the sum will give:

9/24 + 14/24 = 23/24

That is the outcome.

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Answer:

You are left with $1.44

Step-by-step explanation:

Subtract the amount of money you payed to how much the cost actually was to get your answer.

Answer:

180 cm²

Step-by-step explanation:

Area of Triangle: 1/2bh

You can divide the figure into two parts: top and bottom.

Top:

1/2(4)(12)

1/2 (48)

24

24 • 2 (two triangles) = 48 cm²

Bottom:

1/2(12)(11)

1/2 (132)

66 • 2 (two triangles) = 132 cm²

Add them up: 48 cm² + 132 cm² = 180 cm²

To obtain the vertex of the parabola, we are going to re-write the given parabola equation into its vertex form.

The vertex form of a parabola is given as:

Thus, by completing the square of the given parabola equation, we have:

Comapring this equation with the vertex form of a parabola;

Hence, the vertex of the parabola is:

The focus of a parabola is at the point;

The parabola obtained opens up. An alternative equation for a parabola that opens up is:

We must find the value of a that makes the equation true at any point (x,y).

Suppose x=1;

Hence, the focus of the parabola is:

The directrix is:

Answer:

$66.50, and you saved $28.50

The answer of the question based on the container is in the shape of cube answer is, the volume of the container is (1/512)t⁹u¹², not 1/24t⁹u¹² as Parker claimed.

A volume is  measure of  amount of space occupied by  three-dimensional object. It is typically measured in a cubic units, like  cubic meters, cubic centimeters, or cubic feet.

Parker is not correct.

The volume of a cube is calculated by multiplying the length, width, and height of the cube. In this case, the length of the container is given as 1/8t³u⁴, but we do not have any information about the width and height. Assuming that the width and height are also 1/8t³u⁴, the volume of the cube would be:

V = (1/8t³u⁴) x (1/8t³u⁴) x (1/8t³u⁴)

V = (1/512)t⁹u¹²

Therefore, the volume of the container is (1/512)t⁹u¹², not 1/24t⁹u¹² as Parker claimed.

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Answer:

D

Step-by-step explanation:

No, the probability be found by using the binomial probability formula with x counting the number who are left-handed. The correct option is (c) No, because the 100 adults were selected without replacement, the selections are dependent.

The binomial distribution assumes that the trials are independent, meaning that the outcome of one trial does not affect the outcome of any other trial. However, in this case, the 100 adults were selected without replacement, which means that the outcome of one selection affects the probability of the next selection. Therefore, the trials are dependent, and the binomial probability formula cannot be used.

Instead, we can use the hypergeometric distribution to calculate the probability of at least 30 left-handed adults in a sample of 100 adults selected without replacement from the U.S. population. The hypergeometric distribution takes into account the fact that the selections are dependent and is appropriate for this type of problem.

Therefore, the correct option is (c) No, because the 100 adults were selected without replacement, the selections are dependent.

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\(80\left(\frac{3}{5} \right)=\boxed{48}\)

The number of adults that take part in the race if the ratio of children to adults is 2 : 3 is 48.

Given that:

Total number of people who take part in the race = 80

The ratio of children to adults who take part in the race = 2 : 3

So, for a constant k,

Number of children who take part in the race = 2k

Number of adults who take part in the race = 3k

Total number of people who take part in the race = 2k + 3k

                                                                                   = 5k

Equating the total number of people,

5k = 80

Divide both sides by 5,

k = 16

Substituting k = 16, the total number of adults who take part in the race is:

Adults = 3 × 16

           = 48

Hence, the number of adults is 48.

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Answer:

We can use the properties of logarithms to simplify this expression:

log2(9x^10/y²) = log2(9) + log2(x^10) - log2(y²)

Now we can apply the power rule of logarithms to the second term:

log2(x^10) = 10 log2(x)

Substituting back into the original expression:

log2(9x^10/y²) = log2(9) + 10 log2(x) - log2(y²)

This is the simplified form of the expression.

Answer:

t = 64

Step-by-step explanation:

Multiply by 4 on both sides and you get t = 64 :)