Jillian burns 187 calories when she runs 2 miles. How many miles will she
need to run to burn 500 calories?

Answers

Answer 1

Answer:

I think jillian will have to run 10 miles

Step-by-step explanation:

2 miles = 100 calories

in order to burn 500 calories

2 miles = 100 calories burned

4 miles = 200 calories burned

6 miles = 300 calories burned

8 miles  = 400 calories burned

10 miles = 500 calories burned

Answer 2
i have no clue how to do it

Related Questions

Carlos and Jack are raising money for their school trip. The trip costs $156 per student. Carlos has $42 for the trip and Jack has $51. They are each going to charge $30 to mow a lawn. Let x represent the number of lawns mowed

Part A: Complete the table with an inequality that represents the number of lawns each boy needs to mow to have the money for the trip. Then solve.

Part B: Each boy wants $75 extra spending money for the trip. They plan to work together mowing lawns. Write an inequality to find the number of lawns that the boys need to mow. Then solve.

I think it starts with 30x + __ = 156, although im not sure. For the inequality

Carlos and Jack are raising money for their school trip. The trip costs $156 per student. Carlos has

Answers

The inequalities are below:

30\(x\) + 42 ≥ 156  The number of lawns to mow is = 3.830\(x\) + 51 ≥ 156  The number of lawns to mow is = 3.530x + 42 + 51 ≥ 2*(156) + 2*(75)  Together the boys has to mow 12.3 lawns

Meaning of inequalities

An inequality in mathematics is the ralation or comparison between two expression or numbers that are not equal

It is a state or condition used to express lack of equality and disparity.

The direct opposite of inequality is equality.

In conclusion, the solutions to the problem are highlighted above.

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Given the three functions: f(x) = 60x + 20; g(x)=3(2)^ + and h(x) = 4x ^ 2 + 10x 5. Label each function as quadratic , linear, or exponential​

Given the three functions: f(x) = 60x + 20; g(x)=3(2)^ + and h(x) = 4x ^ 2 + 10x 5. Label each function

Answers

Answer:

Number one is Linear, Number two is Exponential, and Number three is quadratic

Step-by-step explanation:

Solve by using a proportion. Round answer to the nearest hundredth of necessary.
A map scale designates 0.75 inch = 50 miles. If the distance between two towns on the map is 2.75 inches, how many miles must you drive
to go from the first town to the second town?
Answer:
miles

Answers

To go from the first town to the second town, you must drive 137.5 miles.

What is an proportion?

A proportion is a mathematical equation that compares two ratios. It is usually written as two equal fractions or ratios, one on each side of the equation. A proportion can be used to compare the relationship between different quantities, such as measurements, rates, or even time.

We can use proportion to solve this problem. The proportion relates the map scale to the actual distance:

0.75 inch / 50 miles = x / distance

where x is the actual distance we want to find.

We can cross-multiply and solve for x:

0.75 inch * distance = 2.75 inches * 50 miles

x = (2.75 inches * 50 miles) / 0.75 inch

x = (137.5 miles)

To go from the first town to the second town, you must drive 137.5 miles.

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Chelsea is making a necklace she uses 6 blue beads for every 1 silver bead complete the table to show the ratio of blue beads to silver beads?​

Chelsea is making a necklace she uses 6 blue beads for every 1 silver bead complete the table to show

Answers

Answer: 12:2, 18:3, 24:4

Step-by-step explanation: You can multiply 6 by 2, 3, and 4 because the graph has 4 columns. Then multiply the top by 2, 3, and 4,

Can the sum of two irrational numbers ever be a rational number? Can the quotient of two irrational numbers ever be a rational number

Answers

Answer:

Yes and yes

Step-by-step explanation:

Example:

√2, 1 + √2 and 1 - √2 are all irrational.

(1 + √2) + (1 - √2) = 2

The irrational numbers cancel out, leaving you with 1 + 1 = 2, which is rational.

For quotients, we'll use √2 again.

√2/√2 = 1

1 is rational

john beale of stanford, ca, recorded the speeds of cars driving past his house, where the speed limit read 20 mph. the mean of 100 readings was 23.84 mph, with a standard deviation of 3.56 mph. (he actually recorded every car for a two-month period. these are 100 representative readings.) to see how many cars are speeding, john subtracts 20 mph from all speeds. a) what is the mean speed now? what is the new standard deviation? b) his friend in berlin wants to study the speeds, so john converts all the original miles-per-hour readings to kilometers per hour by multiplying all speeds by 1.609 (km per mile). what is the mean now? what is the new standard deviation?

Answers

10 mph more unusual.

What is Standard deviation?

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed over a larger range, a low standard deviation suggests that the values tend to be near to the mean (also known as the anticipated value) of the collection.

The lower case Greek letter (sigma), for the population standard deviation, or the Latin symbol s, for the sample standard deviation, are most frequently used in mathematical literature and equations to indicate standard deviation. Standard deviation may be written as SD.

EXPLANATION : The speed recordings follow an approximately normal distribution the mean of

100 readings was 2384 mph. with a standard deviation of 3.56mph

The speed limit read 20 mph

We have to find the number of standard deviations from the mean that the car going

under the speed hmit would be

Let the car going under the speed 20mph bey standard deviations away from mean

That is.

20 — 23.84 +y(3.56)

20—2384 —1.078651685

So the car going under the speed limit would be less than or equal to 107865 standard

A car traveling 34 mph

The number of standard deviations from the mean that the car is going at 34mph is given by

That is the car going at 34mph is 2.8539 standard deviations above the mean

A car traveling at 10mph

The number of standard deviations from the mean that the car going at 10mph is given by.

y= 2.8539

That is. the car going at 10mph is 3.8876 standard deviations

We know from the empirical nile that 99.7% of the observations he with in ±3 standard

deviations from the mean for a normally distributed data

But the speed of 10mph is not within these limits, where as 34 mph is within these limits

So the car is  travelling t 10mph is more unusual

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Find the slope of the line that passes through the points \left(10,8\right)(10,8) and \left(4,12\right)(4,12).



​Write your answer as a simplified fraction.

Answers

3y + 2x = 44 is the equation of the line through (10, 8) and (4, 12).

What is the Equation of line?

A linear equation has the slope-intercept form y = mx + b. Variables in the equation are x and y. When x is 0, the integers m and b provide the line's slope (m) and the value of y. Because (0,y) is the location where the line crosses the y-axis, the value of y when x is 0 is referred to as the y-intercept.

Given, two coordinates of a line \(\left(10,8\right) and \left(4,12\right)\)

The slope of the line formula is:

\(m = \frac{y₂ - y₁}{ x₂ - x₁}\)

Let's substitute our numbers.

\(m = -\frac{8 -12}{4-10}\)  =  -4/6

The GCF of these two numbers is 2

So, our slope  =  -2/3

The general equation of a line is y = mx +c

Therefore the equation of the line is y = -2/3x + c

Since, this line passes through ( 10, 8 )

Hence, it must satisfy these coordinates

8 = -2/3 * 10 + c

44/3 = c

Thus the equation of the line is y = -2/3x +44/3

the equation of the line is 3y + 2x = 44.

Therefore, The equation of the line that passes through (10, 8) and (4, 12) is 3y + 2x = 44.

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Find the slope of the line that passes through the points \left(10,8\right)(10,8) and \left(4,12\right)(4,12).Write

(x - 2)^5 binomial expansion

Answers

Simplify the polynomial result.
x^5-10x^4+40x^3-80x^2+80x-32

Solve the following differential equations:
(-3x + y)³ + 1 = dx dy x+y (x+y)²-1 dy = +1 dx

Answers

The solution to the given differential equation is (1 + (3x - y)³) / (|y - 3x|³) = C|x|⁹.

The differential equation (-3x + y)³ + 1 = dx dy is solved by using the general method for solving separable differential equations. This method involves the following steps:

Separate the variables by isolating y on one side of the equation and x on the other. This gives the equation in the form y = f(x). Integrate both sides of the equation with respect to x from an initial value x0 to x. Integrate both sides of the equation with respect to y from an initial value of y0 to y.To integrate the equation (-3x + y)³ + 1 = dx dy, we separate the variables and write it in the form of y = f(x).

(-3x + y)³ + 1 = dx dy y = 3x + [dx/(1 + (3x - y)³)]

We now integrate both sides of the equation with respect to x from an initial value x0 to x.(∫ydy)/(1 + (3x - y)³) = ∫dx/x + C1 where C1 is an arbitrary constant of integration. We now integrate both sides of the equation with respect to y from an initial value y0 to y.(ln|1 + (3x - y)³| - 3ln|y - 3x|) / 9 = ln|x| + C2 where C2 is another arbitrary constant of integration. We can simplify the equation to give the following solution.(1 + (3x - y)³) / (|y - 3x|³) = C|x|⁹where C is a constant of integration. This is the final solution to the differential equation.

Explanation: Given differential equation is (-3x + y)³ + 1 = dx dy. We can separate the variables and rewrite it in the form of y = f(x).(-3x + y)³ + 1 = dx dy y = 3x + [dx/(1 + (3x - y)³)]We now integrate both sides of the equation with respect to x from an initial value x0 to x.

(∫ydy)/(1 + (3x - y)³) = ∫dx/x + C1 where C1 is an arbitrary constant of integration. We now integrate both sides of the equation with respect to y from an initial value y0 to y.(ln|1 + (3x - y)³| - 3ln|y - 3x|) / 9 = ln|x| + C2 where C2 is another arbitrary constant of integration. We can simplify the equation to give the following solution.(1 + (3x - y)³) / (|y - 3x|³) = C|x|⁹where C is a constant of integration. This is the final solution to the differential equation.

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What is the answer I need help with this

What is the answer I need help with this

Answers

Answer:

D

Step-by-step explanation:

________ is concerned with making predictions about a population from analyzing a sample or through observations.

Answers

Inferential statistic is concerned with making prediction about a population from analyzing a sample or through observation.

Here,

We have to find the concerned with making prediction about a population from analyzing a sample or through observation.

What is Inferential statistic?

Inferential statistics is used in measurements from the sample of subjects in the experiment to compare treatment groups and to make generalizations about the larger population of subjects.

Now,

Inferential statistic is concerned with making prediction about a population from analyzing a sample or through observation.

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A spherical ball bearing will be coated by 0.03 cm of protective coating. If the radius of this ball bearing is 6 cm approximately how much coating will be required? use π 3.14

a) 12.564 cm3
b) 13564 cm3
c) 890.755 cm3
d) 917.884 cm3
e) 14.564 cm3

Answers

option (a) is the correct answer. The required coating for the spherical ball bearing having a protective coating of 0.03 cm and a radius of approximately 6 cm is 12.564 cm3.

Given that: A spherical ball bearing is coated with 0.03 cm of a protective coating.The radius of this ball bearing is 6 cm.

the surface area of the sphere is:SA = 4πr2.

Therefore, the surface area of a spherical ball bearing with a radius of 6 cm is calculated as follows:SA = 4πr2= 4 × 3.14 × 6 × 6= 452.16 cm2

Now that the protective coating is applied to the sphere, the total surface area of the sphere will be as follows:

New Surface area = (4π(6 + 0.03)2) cm2= (4π(6.03)2) cm2= 457.08 cm2.

The difference between the two surface areas (without coating and with coating) will provide the area that needs to be coated.

A = New Surface area - Surface area without coating= 457.08 - 452.16= 4.92 cm2.

Therefore, the volume of the protective coating required is given as follows:Volume of coating = Area to be coated × Thickness of coating= 4.92 × 0.03= 0.1476 cm3 = 0.148 cm3 (approximately) .

Hence, the required coating for the spherical ball bearing having a protective coating of 0.03 cm and a radius of approximately 6 cm is 12.564 cm3 . Therefore, option (a) is the correct answer.

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In an analysis of the nucleotide composition of a molecule of DNA, which of the following combinations of base pairs will be found? a. A + C = G + T
b. A = G and C = T
c. A = C
d. G + C = T = A

Answers

The only correct combination of base pairs among the options provided is G + C = T = A. This combination adheres to the established base pairing rules in DNA, where A always pairs with T and C always pairs with G. The correct option is d.

In an analysis of the nucleotide composition of a molecule of DNA, the combinations of base pairs that will be found are determined by the rules of base pairing in DNA. The four nucleotide bases found in DNA are adenine (A), cytosine (C), guanine (G), and thymine (T). These bases form complementary pairs, with A always pairing with T and C always pairing with G.

Given the options provided:

a. A + C = G + T: This combination is not valid because A should always pair with T, and C should always pair with G. Therefore, the statement is incorrect.

b. A = G and C = T: This combination is also not valid. A cannot pair with G and C cannot pair with T. The statement is incorrect.

c. A = C: This combination is not valid either. A cannot pair with C. The statement is incorrect.

d. G + C = T = A: This combination is correct. In DNA, G pairs with C, and T pairs with A. The statement is accurate, as G + C = T + A represents the correct base pairing rules.

Therefore, The correct option is d. G + C = T = A

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three teammates had diffrent points totals at the girls basketball game. to determine the number of points effie had, multiply tonis points by 3, subtract8. and then multiply the diffrence by 2. to determine the number of points linda had, add 9 to toins points, and divide the sum by 3. how many points did each girl have if effie scored 9 more than toni and linda combined?

Answers

Toni had 17 points, Effie had 25 points and Linda had 18 points.

The question is asking to find the number of points each girl had in a girl's basketball game. To find out how many points Effie had, you must multiply Toni's points by 3, subtract 8, and then multiply the difference by 2. To find out how many points Linda had, you must add 9 to Toni's points and divide the sum by 3. The given information is that Effie scored 9 more than Toni and Linda combined.

Formula and Calculation:

Toni's Points = x

Effie's Points = 3x-8

Linda's Points = (x+9)/3

Effie scored 9 more than Toni and Linda combined, so:

3x-8 = x+9/3 + 9

2x-8 = x+9

x = 17

Therefore, Toni had 17 points, Effie had 25 points and Linda had 18 points.

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-5.42 , 5 5/6 , 5.34 , -5 4/5

Least to greatest please

-5.42 , 5 5/6 , 5.34 , -5 4/5Least to greatest please

Answers

-5 4/5, -5.42, 5.34, 5 5/6

55 of Ronnie's shots went in the basket when she took 125 shots? What percent of her shots went in?

Answers

Answer:

44%

Step-by-step explanation:

the answer is 44% because 55/125 can be simplifed by dividing both sides by 5 to get 11/25

Consider the proof.

Given: Segment AB is parallel to line DE.
Prove:StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction

Triangle A B C is cut by line D E. Line D E goes through side A C and side B C. Lines A B and D E are parallel. Angle B A C is 1, angle A B C is 2, angle E D C is 3, and angle D E C is 4.

A table showing statements and reasons for the proof is shown.

What is the missing statement in Step 5?

AC = BC
StartFraction A C Over D C EndFraction = StartFraction B C Over E C EndFraction
AD = BE
StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction

Answers

The missing statement in Step 5 include the following: B. AC/DC = BC/EC.

What are the properties of similar triangles?

In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

Based on the angle, angle (AA) similarity theorem, we can logically deduce the following congruent triangles:

ΔABC ≅ ΔDEC  ⇒ Step 4

By the definition of similar triangles, we can logically deduce the following proportional and corresponding side lengths:

AC/DC = BC/EC ⇒ Step 5

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Consider the proof.Given: Segment AB is parallel to line DE.Prove:StartFraction A D Over D C EndFraction
Consider the proof.Given: Segment AB is parallel to line DE.Prove:StartFraction A D Over D C EndFraction

Determine whether the given value is a statistic or a parameter the number of birds in diffferent regions

Answers

In the context of statistics, a statistic refers to a numerical value that is calculated from a sample of data, while a parameter refers to a numerical value that describes a population.

In the given scenario, the number of birds in different regions can be considered as either a statistic or a parameter depending on the context in which it is used.

If the number of birds is obtained by counting the birds in a specific region and then calculating summary measures such as the mean, median, or standard deviation based on that sample, then it would be considered a statistic. This is because the data is collected from a subset (sample) of the entire population of birds.

On the other hand, if the number of birds represents the total count or an average count across all regions without any sampling involved, then it would be considered a parameter. In this case, the value represents a characteristic of the entire population of birds in different regions.

It is important to note that whether the number of birds is considered a statistic or a parameter depends on how the data is collected and analyzed.

If multiple samples are taken from different regions and statistical inference techniques are used to make inferences about the entire population, then it would be appropriate to consider it as a statistic. However, if the data represents a complete count or an average across all regions without any sampling involved, then it would be considered a parameter.

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Question 3 The Schwarzschild metric is given by 2M 2M ds² -(₁-²M) di² + (1-²¹)- 1- dr² +r² (d0² + sin² 0 dó²). There are Killing vectors associated with time invariance and angular momen- tum invariance in the direction in this geometry leading to the conserved quantities e = (1-2) and l= r² sin² 0 dr From this one can derive an analog to the radial energy equation in Newtonian mechanics by orienting the coordinates so that the orbits are confined to the equatorial plane where 0 = π/2 and u = 0. One finds 2 1 dr + Veff (r) = E 2 dr (e²_ -1) where E = and Veft(r) = - + 2/²/²2 - Mp³². Further, for circular orbits one can show that M | [₁ + √/₁−12 (+1)]. r+= | 2M Finally, for circular orbits of radius R do 1/2 M dt R³ (a) Which value of r corresponds to the Schwarzschild radius of stable circular orbits: r or r? Justify your answer. [3 marks] (b) Show that for circular orbits of radius R do 1/2 M -1/2 3M (²) ¹² (1-³) dT R³ R where is the proper time. [6 marks] (c) A free particle is moving in a circular orbit around a spherical source of curvature of mass M. The Schwarzschild radius of the orbit is 8M. Use the equivalence principle to argue that the period as measured at infinity should be larger than that measured by the particle. [4 marks] (d) Find the period of the orbit as measured by an observer at infinity. Find the period of the orbit as measured by the particle. [7 marks] M

Answers

(A) Circular orbits of stable particles are possible at radii greater than three times the Schwarzschild radius for the non-rotating spherically symmetric mass.

This represents the radius of a black hole's event horizon, within which nothing can escape. The Schwarzschild radius is the event horizon radius of a black hole with mass M.

M can be calculated using the formula: r+ = 2Mwhere r+ is the radius of the event horizon.

(B)  1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ R. This is the required expression.

Tau is the proper time of the particle moving around a circular orbit. Hence, by making use of the formula given above:1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ dt.

(C) Time passes differently in different gravitational fields, and it follows that the period as measured at infinity should be larger than that measured by the particle.

The principle of equivalence can be defined as the connection between gravitational forces and the forces we observe in non-inertial frames of reference. It's basically the idea that an accelerating reference frame feels identical to a gravitational force.

(D) The period of the orbit as measured by an observer at infinity is 16π M^(1/2) and the period of the orbit as measured by the particle is 16π M^(1/2)(1 + 9/64 M²).

The period of orbit as measured by an observer at infinity can be calculated using the formula: T = 2π R³/2/√(M). Substitute the given values in the above formula: T = 2π (8M)³/2/√(M)= 16π M^(1/2).The period of the orbit as measured by the particle can be calculated using the formula: T = 2π R/√(1-3M/R).

Substitute the given values in the above formula: T = 2π (8M)/√(1-3M/(8M))= 16π M^(1/2)(1 + 9/64 M²).

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Suppose you want to use a converging lens to project the image of two trees onto a screen. One tree is a distance x from the lens; the other is a distance of 2x, as in the figure below. You adjust the screen so that the near tree is in focus. If you now want the far tree to be in focus, do you move the screen toward or away from the lens?.

Answers

Answer:

Moving screen for focusing.

Roshan Mandal

Suppose you want to use a converging lens to project the image of two trees onto a screen. One tree is a distance x from the lens; the other is a distance of 2x, as in the figure below. You adjust the screen so that the near tree is in focus. If you now want the far tree to be in focus, do you move the screen toward or away from the lens?.

To bring the near tree in focus, the lens must be placed at a distance from the tree equal to its focal length. Let's call this distance "f".

Now, for the far tree to be in focus, the light rays coming from the tree must converge at the same point on the screen as the rays from the near tree. This means that the screen must be moved closer to the lens.

To calculate how much closer, we can use the thin lens formula:

1/f = 1/do + 1/di

where "do" is the object distance (distance of the far tree from the lens) and "di" is the image distance (distance of the screen from the lens).

We know that do = 2x (distance of the far tree) and f (focal length of the lens) is the same as before. We can rearrange the formula to solve for di:

1/di = 1/f - 1/do

1/di = 1/f - 1/2x

di = 2fx/(2f-x)

So the screen should be placed at a distance di from the lens given by this formula. As x is less than 2f, this value will be positive and greater than f, meaning the screen should be moved closer to the lens than its initial position to bring the far tree in focus.

--- Ensures items requested match item numbers on DA Form 3151-R
--- Loads and secures the ammunition
--- Placards the vehicle
Which of the following tasks does the unit personnel perform when receiving ammunition?

Answers

When receiving ammunition, unit personnel perform three tasks: ensuring items requested match item numbers on DA Form 3151-R, loading and securing the ammunition, and placarding the vehicle.

The first task performed by unit personnel when receiving ammunition is to ensure that the items requested match the item numbers on DA Form 3151-R. This form serves as a record of the types and quantities of ammunition being received. By comparing the requested items with the item numbers on the form, personnel ensure accuracy and prevent any discrepancies or errors in the delivery.

The second task involves the loading and securing of the ammunition. Unit personnel are responsible for safely and efficiently loading the ammunition onto the designated vehicle or storage area. This includes following proper handling procedures, using appropriate equipment, and adhering to safety protocols. The ammunition must be securely stored and arranged to prevent shifting or damage during transportation.

The final task is to placard the vehicle. Placarding involves visibly displaying the necessary warning signs or labels on the vehicle that indicate the presence of ammunition. This step is crucial for safety and compliance purposes, as it alerts other personnel and drivers to exercise caution when approaching or handling the vehicle. Clear and prominent placarding helps prevent accidents and ensures that everyone involved is aware of the potential hazards associated with transporting ammunition.

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Three students were given the expression shown and were asked to take a common
factor out of two of the terms.
Use the drop-down menus to complete the statements about whether each student's
answer is an equivalent expression. Then choose an expression that is equivalent.

Three students were given the expression shown and were asked to take a commonfactor out of two of the

Answers

Chang is incorrect because his factoring results in -21 instead of positive 21.

Benjamin is incorrect because his factoring results in positive 9x instead of -9x.

Habib's answer is incorrect because 4 + 12x is not equivalent to the expression above.

A correct factor would be: 4-3(3x-7)

Answer:

Chang-incorrect he did not divide 21 by -3 correctly

bejiman-i got wrong

habib-incorrect he cannot add -9 and 21

4-3(3x-7)

Step-by-step explanation:

If a child weighs 83 pounds, how many ounces does she weigh? 664 oz. 664 oz. 830 oz. 830 oz. 966 oz. 966 oz. 1328 oz.

Answers

Answer:

The answer is 1,328

Step-by-step explanation:

The number of ounces that she weighs will be 1328 ounces. Then the correct option is D.

What is conversion?

Conversion means converting the same thing into different units.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

PEMDAS rule means the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

If a child weighs 83 pounds. We know that in one pound, there are 16 ounces.

Then the number of ounces that she weighs will be

⇒ 83 x 16

⇒ 1328 ounces

Then the number of ounces that she weighs will be 1328 ounces. Then the correct option is D.

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Was there any way of reconciling the republican desire for equality for the ex-slaves with the
ex-confederate desire for self-rule in the south?

Answers

Reconciling the Republican desire for equality for ex-slaves with the ex-Confederate desire for self-rule in the South was a significant challenge during the post-Civil War Reconstruction era.

Despite efforts to find common ground, the conflicting interests and deep-rooted divisions often made reconciliation difficult to achieve. The Republican Party aimed to ensure equality for ex-slaves through measures such as the Reconstruction Amendments, which granted civil rights and voting rights to African Americans. However, many ex-Confederates resisted these efforts, as they viewed them as an infringement on their right to self-rule and local autonomy. The concept of equality clashed with the ex-Confederate desire to maintain their social and political dominance in the South.

Various attempts were made to reconcile these conflicting desires, including the formation of biracial governments in some Southern states and the implementation of policies aimed at fostering cooperation and unity. However, these efforts faced significant resistance and were often undermined by persistent racial tensions, violence, and political maneuvering. Ultimately, the challenge of reconciling these competing interests highlighted the deep-seated divisions and difficulties in achieving a harmonious balance between equality for ex-slaves and the desire for self-rule in the post-Civil War South.

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what is the unite rate of 4 inches of snow in 5 hours

Answers

Answer:

4/5 inches of snow per hour

Step-by-step explanation:

let 's' = snow

5 hrs / 4 inches = 1 hr / s

cross-multiply to get:

5s = 4

s = 4/5

4/5 inches of snow per hour

in a survey, 75% of household reported to have some kind of board games. out of 10 households, what is the probability that less than 3 households have board games?

Answers

After performing the calculations, you'll find that the probability of less than 3 households having board games out of 10 households is approximately 0.0038 or 0.38%.

To find the probability that less than 3 households have board games, we can use the binomial probability formula. The terms involved in this problem are:

1. n: number of trials (households)
2. k: number of successful outcomes (households with board games)
3. p: probability of success (having board games)
4. q: probability of failure (not having board games)

Given that 75% of households have board games, p = 0.75, and q = 1 - p = 0.25. In this case, n = 10 households. We need to find the probability of k = 0, 1, or 2 households having board games.

The binomial probability formula is:
P(X = k) = C(n, k) * p^k * q^(n-k)

Step 1: Calculate the probability for k = 0, 1, and 2 separately:
P(X = 0) = C(10, 0) * 0.75^0 * 0.25^10
P(X = 1) = C(10, 1) * 0.75^1 * 0.25^9
P(X = 2) = C(10, 2) * 0.75^2 * 0.25^8

Step 2: Add the probabilities for k = 0, 1, and 2 to get the total probability:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

After performing the calculations, you'll find that the probability of less than 3 households having board games out of 10 households is approximately 0.0038 or 0.38%.

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Cindy went to the salon to get highlights and a haircut. Her total cost was $95. Cindy decided to tip her stylist 22% because she loved her hair so much. How much was the tip?

Answers

Her tip would be $20.90

would you expect the values of a measured at the two different heights to be the same? why or why not?

Answers

The values of a measured at two different heights may or may not be the same, depending on the nature of the thing being measured and the conditions of the measurement.

Why may or may not the values of a measured thing at two different heights be the same?

The value of a measured quantity depends on various factors such as the measurement instrument, the conditions of the measurement, and the nature of the thing being measured. In some cases, the values of a measured thing at different heights may be the same, while in other cases they may differ.

Factors that effect the measurement :
Whether the values of a measured thing at two different heights will be the same depends on the nature of the thing being measured and the conditions of the measurement. For example, if we measure the air pressure at two different heights, we may expect the values to be different, as air pressure decreases with increasing altitude. On the other hand, if we measure the temperature of a room at two different heights, we may expect the values to be approximately the same, as the temperature is usually well-mixed throughout the room.

Similarly, the values of other measured quantities such as sound intensity, light intensity, and humidity may also differ or be the same at different heights, depending on the conditions of the measurement and the nature of the thing being measured. Therefore, it is important to consider these factors when making measurements and interpreting their results.

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Need help and I need it fast plz

Need help and I need it fast plz

Answers

Answer:

The answer is b can i have brainliest

Step-by-step explanation:

Answer:

it's b :)

Step-by-step explanation:

When a cylinder is intersected by a plane parallel to the bases, what is the resulting cross-section?.

Answers

The resulting cross-section of a cylinder intersected by a plane parallel to the bases is a circle.

When a plane passes through a cylinder parallel to the bases, it creates a cross-section that is congruent to the bases of the cylinder. Since the bases of a cylinder are circles, the resulting cross-section is also a circle. The circle formed will have the same diameter as the bases of the cylinder and will be parallel to them. This is because the plane slices through the cylinder at a constant distance from the bases, resulting in a circular shape that is perpendicular to the axis of the cylinder. This characteristic holds true for any position of the plane parallel to the bases, resulting in circular cross-sections.

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