Let וג 2 8 3 W = span 1 0 2 . (a) Find a basis B for W. (b) Write down the dimension of W.

Answer:

the answer is in the picture

Step-by-step explanation:

Answer:

18 is less than 34

16 ≤ 2x

x minus 13 multiplied by 5 is greater than or equal to 24

7> -15

It (B) cannot be determined that there is a statistically significant difference between Mr. Goodman's ratings and those of the History Department in the context of Mr. Goodmain and with all the material provided.

In statistics, a simple random sample (or SRS) is a subset of people (a sample) picked at random from a larger group of people (a population), all with the same probability.

It is a method of choosing a sample at random. Each subset of k people in SRS has the same chance of getting selected for the sample as any other subset of k people.  

An objective sampling strategy is a straightforward random sample. Simple random sampling is a fundamental kind of sampling that can be used in combination with other, more sophisticated sampling techniques.

So, in the given situation of Mr. Goodmain and with all the information given we can conclude that it cannot be concluded that there is a statistically significant difference in Mr. Goodman’s evaluations and the History Department’s.

Therefore, it (B) cannot be determined that there is a statistically significant difference between Mr. Goodman's ratings and those of the History Department in the context of Mr. Goodmain and with all the material provided.

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Complete question:

Students at a high school are asked to evaluate their experience in the class at the end of each school year. The courses are evaluated on a 1-4 scale – with 4 being the best experience possible. In the History Department, the courses typically are evaluated at 10% 1’s, 15% 2’s, 34% 3’s, and 41% 4’s. Mr. Goodman sets a goal to outscore these numbers. At the end of the year, he takes a random sample of his evaluations and finds 11 1’s, 14 2’s, 47 3’s, and 53 4’s. At the 0.05 level of significance, can Mr. Goodman claim that his evaluations are significantly different than the History Departments?

Hypotheses:

H0: There is (no difference /difference) in Mr. Goodman’s evaluations and the History Department’s.

H1: There is (no difference /difference) in Mr. Goodman’s evaluations and the History Department’s.

Enter the test statistic - round to 4 decimal places.

Enter the p-value - round to 4 decimal places.

Can it be concluded that there is a statistically significant difference between Mr. Goodman’s evaluations and the History Department’s?

a. Yes

b. No

Answer: D

Step-by-step explanation:

Answer:

there is no solution.

Step-by-step explanation:

1. it would have to be 8 to make the answer 16 because 2*8= 16 but 4*2=8 and the answers other than no solution are all 4 in positive and negative so i would say no solution.

Answer:

4.1

Step-by-step explanation:

5^2 + (2*8) / (2*2) + 3*3

25 + 16 / 4 + 6

41 / 10

4.1

The two plants would have the same height in 7 weeks and the height would be 31 inches.

The form of the expression that represents the length of the plant on the window sill is:

initial length + (length of growth per week x number of weeks)

3 + (4 x w)

3 + 4w

The form of the expression that represents the length of the plant on the coffee table is:

initial length + (length of growth per week x number of weeks)

17 + (2 x w)

17 + 2w

When the two plants have the same height, the two expressions would be equal:

17 + 2w = 3 + 4w

17 - 3 = 4w - 2w

14 = 2w

w = 14/2

w = 7 weeks

Height of the plant = 3 + 4(7)

3 + 28 = 31 inches

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Surface area of a square pyramid:

To find the surface area of the given pyramid as you don't have the length of the slant height, use the height of the pyramid and the radius of the base to form a right triangle and find the slant height:

Pythagorean theorem for the right triangle above:

Perimeter of the base is:

Area of the square base:

Then, the surface area of the given pyramid is

Answer:

.20

Step-by-step explanation:

We can begin by defining Penny's total wealth as a mix of a set sum and a portion of Susie's wealth to develop an expression of how much money she has. We are informed that Penny has at least $4.50 and an additional 2/5 of Susie's wealth. Hence, we can write:

p = $4.50 + (2/5)s

where p is Penny's wealth, s is Susie's wealth, and s is represented by the letters.

If Susie has $11.50, we may enter s = $11.50 into the formula for p to see how much Penny has:

p = $4.50 + (2/5)($11.50)

p = $4.50 + $4.60

p = $9.10

As a result, Penny has $9.10 and Susie has $11.50.

In conclusion, the equation for Penny's wealth in terms of Susie's wealth is p = $4.50 + (2/5)s. When we enter s = $11.50 into the formula, we obtain p = $9.10, which is how much money Penny has while Susie has $11.50.

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Based on your question about the sampling distributions of the sample mean for samples of two different sizes, I will provide an answer using the terms you requested.
1. The Central Limit Theorem (CLT) states that the distribution of the sample mean approaches a normal distribution as the sample size increases, regardless of the shape of the original population.
2. Sampling distributions for larger sample sizes tend to be more tightly clustered around the population mean and have a smaller standard error compared to those with smaller sample sizes.
Now, let's analyze the two graphs:
Graph i: This graph represents a sampling distribution with a wider spread and a larger standard error.
Graph ii: This graph represents a sampling distribution with a narrower spread and a smaller standard error.
Based on the CLT and the properties of the sampling distributions mentioned above, the following statement must be true about the sample sizes:

- The sample size for graph ii is larger than the sample size for graph i. This is because the spread of the sampling distribution is narrower, indicating a smaller standard error and a larger sample size as per the Central Limit Theorem.

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If segment BD is congruent to segment BC, and BD = 4x - 18, BC = x + 3, and AC = 34, then AB = 31/x.

Let the equation be AB + BC = AC

substitute the values in the above equation, we get

AB + x + 3 = 34

simplifying the value of x,

Subtract A B from both sides AB + x + 3 - AB = 34 - A B

x + 3 = 34 - AB

Subtract 3 from both sides,

x + 3 - 3 = 34 - AB - 3

x = -AB + 31

Plug in this value of x into the line segments to find BC and AC.

Where, BC = x + 3

substitute the value of x in the above equation, we get

BC = [-AB + 31 ] + 3

BC = -AB + 34

Then, AB + BC = AC

x = -AB + 31

AB = 31/x

Hence, If segment BD is congruent to segment BC, and BD = 4x - 18,

BC = x + 3, and AC = 34, then AB = 31/x.

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Answer:

Positive

Step-by-step explanation:

-13 plus positive 20 equals positive 7

a. The median number of calls = 55

b. The first and third quartiles, Q1 = 48 and Q3 = 66

c. The first decile and the ninth decile, D1 = 45 and D9 = 71.

d. The 33rd percentile = 52.5

To answer the questions, let's first organize the data in ascending order:

38 40 41 45 48 48 50 50 51 51 52 52 53 54 55 55 55 56 56 57 59 59 59 62 62 62 63 64 65 66 66 67 67 69 69 71 77 78 79 79

(a) The median is the middle value of a dataset when arranged in ascending order.

Since we have 40 observations, the median is the value at the 20th position.

In this case, the median is the 55th visit.

(b) The quartiles divide the data into four equal parts.

To find the first quartile (Q1), we need to locate the position of the 25th percentile, which is 40 * (25/100) = 10.

The first quartile is the value at the 10th position, which is 48.

To find the third quartile (Q3), we need to locate the position of the 75th percentile, which is 40 * (75/100) = 30.

The third quartile is the value at the 30th position, which is 66.

Therefore, Q1 = 48 and Q3 = 66.

(c) The deciles divide the data into ten equal parts.

To find the first decile (D1), we need to locate the position of the 10th percentile, which is 40 * (10/100) = 4.

The first decile is the value at the 4th position, which is 45.

To find the ninth decile (D9), we need to locate the position of the 90th percentile, which is 40 * (90/100) = 36.

The ninth decile is the value at the 36th position, which is 71.

Therefore, D1 = 45 and D9 = 71.

(d) To find the 33rd percentile, we need to locate the position of the 33rd percentile, which is 40 * (33/100) = 13.2 (rounded to 13). The 33rd percentile is the value at the 13th position.

Since the value at the 13th position is between 52 and 53, we can calculate the percentile using interpolation:

Lower value: 52

Upper value: 53

Position: 13

Percentage: (13 - 12) / (13 - 12 + 1) = 1 / 2 = 0.5

33rd percentile = Lower value + (Percentage * (Upper value - Lower value))

                = 52 + (0.5 * (53 - 52))

                = 52.5

Therefore, the 33rd percentile is 52.5.

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The minimal point does not have x = 0.

(a) Kuhn-Tucker conditions for the minimal value of fThe Kuhn-Tucker conditions are a set of necessary conditions for a point x* to be a minimum of a constrained optimization problem subject to inequality constraints. These conditions provide a way to find the optimal values of x1, x2, ..., xn that maximize or minimize a function f subject to a set of constraints. Let's first write down the Lagrangian: L(x, y, λ1, λ2, λ3) = f(x, y) - λ1(x+y-1) - λ2(xy-3) - λ3x - λ4y Where λ1, λ2, λ3, and λ4 are the Kuhn-Tucker multipliers associated with the constraints. Taking partial derivatives of L with respect to x, y, λ1, λ2, λ3, and λ4 and setting them equal to 0, we get the following set of equations: 4x - 2y - λ1 - λ2y - λ3 = 0 2y - 2x - λ1 - λ2x - λ4 = 0 x + y - 1 ≤ 0 xy - 3 ≤ 0 λ1 ≥ 0 λ2 ≥ 0 λ3 ≥ 0 λ4 ≥ 0 λ1(x + y - 1) = 0 λ2(xy - 3) = 0 From the complementary slackness condition, λ1(x + y - 1) = 0 and λ2(xy - 3) = 0. This implies that either λ1 = 0 or x + y - 1 = 0, and either λ2 = 0 or xy - 3 = 0. If λ1 > 0 and λ2 > 0, then x + y - 1 = 0 and xy - 3 = 0. If λ1 > 0 and λ2 = 0, then x + y - 1 = 0. If λ1 = 0 and λ2 > 0, then xy - 3 = 0. We now consider each case separately. Case 1: λ1 > 0 and λ2 > 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have the following possibilities: x + y - 1 = 0, xy - 3 ≤ 0 (i.e., xy = 3), λ1 > 0, λ2 > 0 x + y - 1 ≤ 0, xy - 3 = 0 (i.e., x = 3/y), λ1 > 0, λ2 > 0 x + y - 1 = 0, xy - 3 = 0 (i.e., x = y = √3), λ1 > 0, λ2 > 0 We can exclude the second case because it violates the constraint x, y ≥ 0. The first and third cases satisfy all the Kuhn-Tucker conditions, and we can check that they correspond to local minima of f subject to the constraints. For the first case, we have x = y = √3/2 and f(x, y) = -1/2. For the third case, we have x = y = √3 and f(x, y) = -2. Case 2: λ1 > 0 and λ2 = 0From λ1(x + y - 1) = 0, we have x + y - 1 = 0 (because λ1 > 0). From the first Kuhn-Tucker condition, we have 4x - 2y - λ1 = λ1y. Since λ1 > 0, we can solve for y to get y = (4x - λ1)/(2 + λ1). Substituting this into the constraint x + y - 1 = 0, we get x + (4x - λ1)/(2 + λ1) - 1 = 0. Solving for x, we get x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4. We can check that this satisfies all the Kuhn-Tucker conditions for λ1 > 0, and we can also check that it corresponds to a local minimum of f subject to the constraints. For this value of x, we have y = (4x - λ1)/(2 + λ1), and we can compute f(x, y) = -3/4 + (5λ1^2 + 4λ1 + 1)/(2(2 + λ1)^2). Case 3: λ1 = 0 and λ2 > 0From λ2(xy - 3) = 0, we have xy - 3 = 0 (because λ2 > 0). Substituting this into the constraint x + y - 1 ≥ 0, we get x + (3/x) - 1 ≥ 0. This implies that x^2 + (3 - x) - x ≥ 0, or equivalently, x^2 - x + 3 ≥ 0. The discriminant of this quadratic is negative, so it has no real roots. Therefore, there are no feasible solutions in this case. Case 4: λ1 = 0 and λ2 = 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have x + y - 1 ≤ 0 and xy - 3 ≤ 0. This implies that x, y > 0, and we can use the first and second Kuhn-Tucker conditions to get 4x - 2y = 0 2y - 2x = 0 x + y - 1 = 0 xy - 3 = 0 Solving these equations, we get x = y = √3 and f(x, y) = -2. (b) Show that the minimal point does not have x=0.To show that the minimal point does not have x=0, we need to find the optimal value of x that minimizes f subject to the constraints and show that x > 0. From the Kuhn-Tucker conditions, we know that the optimal value of x satisfies one of the following conditions: x = y = √3/2 (λ1 > 0, λ2 > 0) x = √3 (λ1 > 0, λ2 > 0) x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4 (λ1 > 0, λ2 = 0) If x = y = √3/2, then x > 0. If x = √3, then x > 0. If x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4, then x > 0 because λ1 ≥ 0.

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Answer:

1 13/15 is your answer

Step-by-step explanation:

2 1/3 x 4/5 = 1 13/15

Sam is 25 years old, and Harry is 5 years old.

If we multiply the age of Harry (5) five times, it will give us 25:

5×5= 25

and if we multiply Harry's age three times and then add up ten, it will give us 25:

(5×3) +10 = 25

15 + 10 = 25

25 = 25

Answer:

Step-by-step explanation:

I am assuming  that the number 1 is not included.

This is an arithmetic sequence of integers with first term 1 and last term 999.

Number required  = (999-1) / 2

                              = 499.

There are 20 integers between 1 and 1000 that meet the given criteria.

To find this answer, we can start by noticing that there are only five odd digits: 1, 3, 5, 7, and 9. Therefore, any integer that meets the criteria must be made up of some combination of these digits.

Next, we can focus on the requirement that the digits be distinct. This means that we cannot repeat any of the odd digits within the same integer. We can use combinations to count the number of ways to choose three distinct odd digits from the set {1, 3, 5, 7, 9}:
5C3 = (5!)/(3!2!) = 10

Finally, we need to consider the requirement that the digits be in ascending order. Once we have chosen our three distinct odd digits, there is only one way to arrange them in ascending order. So each combination of three odd digits corresponds to exactly one integer that meets all the criteria.

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Answer:

It would need to be 324.23 feet high (not reasonable)

Step-by-step explanation:

If you plug it into the pendulum formula given T = 2 π √(L/32), all you would have to do is set T=20 and solve for L

You would end up getting 3200/(π²)

this is equal to 324.227

This was the formula given to me by the assignment, not sure if it is the same on yours. Good luck! ;)

Answer:

105

Step-by-step explanation:

2x17=34

17x2.5=42.5

1.5x17=25.5

1/2x2x2x1.5=3

34+42.5+25.5+3=105

Answer Po Ba Ay 11.33?

Step-by-step explanation:

Calc

Answer:

-288

Step-by-step explanation:

math

Answer:

5 x 3 = 15, 15 x 4 = 60

60 x 1/3(basically just dividing by 3) = 20 in3

Answer:

H) 20

Step-by-step explanation:

Formula for the volume of a rectangular pyramid:

V = (whl)/3

Given:

w = 3

h = 4

l = 5

Work:

V = (whl)/3

V = (3 × 4 × 5)/3

V = (60)/3

V = 20

Answer:

∆DEF and ∆LMN are congruent meaning the same. also meaning all three angles are the same so you draw two triangles after drawing your triangles start with the first triangle you drew an on the bottom left angle put your D then your bottom right angle put your F now on the second triangle you will do the same thing but it will be with you ∆LMN. YOU will start left bottom angle an put you L an on the right bottom angle put your N

Answer:

1

Step-by-step explanation:

A linear equation (degree 1) will have one root. A quadratic equation (degree 2) will have two roots. A cubic equation (degree 3) will have three roots. An nth degree polynomial equation will have n roots.

Answer:

A quadratic equation with real coefficients can have either one or two distinct real roots, or two distinct complex roots. In this case the discriminant determines the number and nature of the roots. There are three cases: If the discriminant is positive, then there are two distinct roots.

Step-by-step explanation:

A degree 2 polynomial (a quadratic) has 2 roots. A linear equation in the form y = mx + b is degree 1, since this is and has one root. A linear equation in the form y = c is degree 0, since this is and has zero roots.

PLZ PLZ MARK ME AS BRAINLIST!!

We would need 453 more observations to increase your confidence level to 95% certainty.

To determine the required number of observations to be 90% sure of being within ±2.5% of the population mean for an activity occurring 30% of the time, we'll use the sample size formula for proportions:

n = (Z^2 * p * (1-p)) / E^2

Here, n is the sample size, Z is the z-score corresponding to the desired confidence level, p is the proportion (30% or 0.30), and E is the margin of error (±2.5% or 0.025).

For a 90% confidence level, the z-score (Z) is 1.645. Plugging the values into the formula:

n = (1.645^2 * 0.30 * (1-0.30)) / 0.025^2
n ≈ 1023.44

So, you would need approximately 1024 observations to be 90% sure of being within ±2.5% of the population mean.

To increase the confidence level to 95%, the z-score (Z) changes to 1.96. Using the same formula:

n = (1.96^2 * 0.30 * (1-0.30)) / 0.025^2
n ≈ 1476.07

So, you would need approximately 1477 observations for a 95% confidence level.

To find the additional number of observations needed, subtract the initial sample size from the new sample size:

1477 - 1024 = 453

Therefore, you would need 453 more observations to increase your confidence level to 95% certainty.

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Using central limit theorem, the probability that the class of 20 students will have a mean completion time greater than 60 minutes on the unit 5 test is 0.00017332

We can use the Central Limit Theorem (CLT) to approximate the distribution of the sample mean completion time for the class. According to CLT, the distribution of the sample mean is approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In this case, the population mean is given as 48 minutes, the population standard deviation is given as 15 minutes, and the sample size is 20. Therefore, the mean of the sample mean completion time is also 48 minutes, and the standard deviation of the sample mean completion time is 15/√20 ≈ 3.3541 minutes.

To find the probability that the class mean completion time is greater than 60 minutes, we can standardize the distribution of the sample mean completion time using the z-score formula:

z = (x - μ) / (σ / √n)

where x is the value we want to find the probability for (in this case, x = 60), μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we get:

z = (60 - 48) / (15 / √20) = 3.5777

Using a standard normal distribution table (or calculator), we can find the probability that a z-score is greater than 3.5777.

P = 0.00017332

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The set of numbers {6, 8, 14} and the set {11, 14, 22} could represent the three sides of a triangle.

To determine whether a set of numbers could represent the sides of a triangle, we need to check if it satisfies the triangle inequality theorem. According to the theorem, the sum of any two sides of a triangle must be greater than the length of the third side.

Let's evaluate each set of numbers:

1. {6, 8, 14}

  The sum of the two smaller sides is 6 + 8 = 14, which is greater than the third side 14. Therefore, this set could represent the sides of a triangle.

2. {13, 20, 34}

  The sum of the two smaller sides is 13 + 20 = 33, which is less than the third side 34. Hence, this set cannot represent the sides of a triangle.

3. {11, 14, 22}

  The sum of the two smaller sides is 11 + 14 = 25, which is greater than the third side 22. Therefore, this set could represent the sides of a triangle.

4. {13, 20, 35}

  The sum of the two smaller sides is 13 + 20 = 33, which is less than the third side 35. Hence, this set cannot represent the sides of a triangle.

In summary, the sets {6, 8, 14} and {11, 14, 22} could represent the three sides of a triangle.

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Answer:

See below

Step-by-step explanation:

I do not see any options, but it is important to note that the bigger the level of confidence, the larger the margin of error will be.