The things/blessings that want to thank God for school
EducationTeachers and FriendsGrowth and development and human /material ResourcesSupportive environmentExtracurricular activitiesAchievements and ChallengesFuture opportunitiesWhat is thanking God?"Thank God" is an expression of gratitude towards a higher power. It's recognizing and thanking God for his help and blessings. "Thank God" is often used to express gratitude or relief for positive occurrences or blessings. Common expression of gratitude towards higher power.
I thank God for education, especially gaining knowledge, developing skills. Dedicated educators guiding, inspiring, and realizing my potentials
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The mean mass of five men is 76 kg. The masses of four of the men are 72 kg, 74 kg, 75 kg and 81 kg. What is the mass of the fifth man
Answer:
78kg
Step-by-step explanation:
76×5= 380kg
380-72-74-75-81= 78kg
if the outcome of event a is not affected by event b, then events a and b are said to be
Evaluate b(x)=18−0.5x when x=−2,0, and 5.
hope that helps :))
The value of the function b(x) = 18 - 0.5x when x = -2, 0, and 5 are 19, 18 and 15.5 respectively.
What is equation?A formula known as an equation uses the equals sign to express how two expressions are equal.
Given function is b(x) = 18 - 0.5x
Putting x = (-2) in b(x) = 18 - 0.5x
b(x) = 18 - 0.5(-2)
b(x) = 18 - (-1)
b(x) = 18 + 1
b(x) = 19
Putting x = 0 in b(x) = 18 - 0.5x
b(x) = 18 - 0.5(0)
b(x) = 18
Putting x = 5 in b(x) = 18 - 0.5x
b(x) = 18 - 0.5(5)
b(x) = 18 - 2.5
b(x) = 15.5
Hence, required answers are 19, 18 and 15.5 respectively.
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use the difference of two squares theorem to find the solution to each equation
We will investigate how to use the difference of two squares theorem to determine a solution to the equation.
The equation at hand is as follows:
\((\text{ x + }\frac{1}{7})^2\text{ = 8}\)We will move all the terms on the left hand side of the " = " sign as follows:
\((\text{ x + }\frac{1}{7})^2\text{ - 8 = 0}\)The difference of two squares theorem states that:
\(a^2-b^2\text{ = ( a + b ) }\cdot\text{ ( a - b )}\)We see from the above form that we have the following:
\(\begin{gathered} a\text{ = x + }\frac{1}{7} \\ \\ b\text{ = }\sqrt[]{8} \end{gathered}\)Using the difference of two squares formulation we can re-write as a multiple of two factors:
\((\text{ x + }\frac{1}{7})^2\text{ - 8 }\equiv\text{ ( x + }\frac{1}{7}\text{ + }\sqrt[]{8}\text{ ) }\cdot\text{ ( x + }\frac{1}{7}\text{ -}\sqrt[]{8}\text{ )}\)Then the factorized equation becomes:
\(\text{ ( x + }\frac{1}{7}\text{ + }\sqrt[]{8}\text{ ) }\cdot\text{ ( x + }\frac{1}{7}\text{ -}\sqrt[]{8}\text{ ) = 0}\)The solution of the equation becomes:
\(\begin{gathered} x\text{ = - }\frac{1}{7}\text{ - }\sqrt[]{8} \\ \\ x\text{ = }\sqrt[]{8}-\frac{1}{7} \end{gathered}\)We can condense our solution in the form:
\(x\text{ = - }\frac{1}{7}\pm2\sqrt[]{2}\)You can
Figure A to map it onto Figure Din a single transformation."
1.answers
2.rotate
3.reflect
4.translate
5.dilate
Answer: a
Step-by-step explanation:
Find the measure of exterior angle A.
Answer:
40* degress angled
Step-by-step explanation:
Answer:
I believe the answer is a 40 degree angle
Step-by-step explanation:
find 5 irrational number between 1/7 and 1/4
Five irrational number between 1/7 and 1/4 are 0.142857142857..., √2/5, π/10, e/8, √3/7.
To find five irrational numbers between 1/7 and 1/4, we can utilize the fact that between any two rational numbers, there are infinitely many irrational numbers. Here are five examples:
0.142857142857...
This is an example of an irrational number that can be expressed as an infinite repeating decimal. The decimal representation of 1/7 is 0.142857142857..., which repeats indefinitely.
√2/5
The square root of 2 (√2) is an irrational number, and dividing it by 5 gives us another irrational number between 1/7 and 1/4.
π/10
π (pi) is another well-known irrational number. Dividing π by 10 gives us an irrational number between 1/7 and 1/4.
e/8
The mathematical constant e is also irrational. Dividing e by 8 gives us an irrational number within the desired range.
√3/7
The square root of 3 (√3) is another irrational number. Dividing it by 7 provides us with an additional irrational number between 1/7 and 1/4.
These are just a few examples of irrational numbers between 1/7 and 1/4. In reality, there are infinitely many irrational numbers in this range, but the examples provided should give you a good starting point.
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A suitcase has a lock on it consisting of four numbers. Each number could be any number 0-9. The only restriction is that the last slot has to be an even number. How many possible combinations for the lock
The suitcase has a lock consisting of four number.
Each number could be any number from 0 to 9.
for each of the first three numbers slot on the lock, there are 10 possible numbers that can fit in (that is 0,1,2,3,4,5,6,7,8,9)
And for the last slot, According to the restriction given in the question that it has to be an even number.
So, for the last slot the possible numbers that can fit in are (0,2,4,6,8), which are even numbers between 0 and 9. which means there are 5 possible numbers for the last slot.
The total number of possible combinations is equal to the product of the number of possible numbers for each slot.
\(N\text{ }=\text{ N1 }\times\text{ N2 }\times\text{ N3 }\times\text{ N4}\)Where N is the total number of possible combination for the slot, and N1,N2,N
True or false: You can represent the following situation with a division expression.
Joshua has three cats. Over a week they eat a total of 14 pounds of food. On average how much food does each cat eat in a week?
True
False
Answer:
true
Step-by-step explanation:
Answer:
true
Step-by-step explanation:
To represent the situation, you would have to do 14÷3 because there are 3 cats that eat 14 pounds of food in a week and to figure out how much a cat eats in a week, you would have to divide.
solve for x: x+15=45
Answer:
x = 30
EXPLANATION:
Move all terms not containing x to the right side of the equation.
Subtract
15 from 45 then you get your final answer x = 30
Exercise 10.12.2: Counting solutions to integer equations. How many solutions are there to the equation x1 + x2 + x3 + x4 + x5 + x6 = 25 in which each xi is a non-negative integer and(a) There are no other restrictions. (b) xi 2 3 for i 1, 2, 3, 4, 5, 6 (c) 3 s x1 s 10 (d) 3 s x1 s 10 and 2 s x2 s 7
a) There are 27,405 solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25 with no restrictions.
b) There are 1,001 solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, with xi ≥ 3 for i = 1, 2, 3, 4, 5.
c) There are 5,561 solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, where 3 ≤ x₁ ≤ 10.
d) There are 780 solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, where 3 ≤ x₁ ≤ 10 and 2 ≤ x₂ ≤ 7.
a) No Restrictions:
In this arrangement, the first urn contains 5 balls, the second urn contains 3 balls, the third urn contains 9 balls, and the fourth urn contains 8 balls.
By applying this method, we need to find the number of ways we can arrange the 25 balls and 4 separators. The total number of positions in this arrangement is 29 (25 balls + 4 separators). We choose 4 positions for the separators from the 29 available positions, which can be done in "29 choose 4" ways. Therefore, the number of solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25 with no restrictions is:
C(29, 4) = 29! / (4! * (29 - 4)!) = 27,405.
b) xi ≥ 3 for i = 1, 2, 3, 4, 5:
In this case, each xi should be greater than or equal to 3. We can use a similar approach to the previous case but with a few modifications. To ensure that each variable is at least 3, we subtract 3 from each variable before distributing the balls. This effectively reduces the equation to x₁' + x₂' + x₃' + x₄' + x₅' = 10, where x₁' = x₁ - 3, x₂' = x₂ - 3, and so on.
Now, we have 10 balls (representing the value of 10) and 4 urns (representing the variables x₁', x₂', x₃', and x₄'). Using the stars and bars method, we can determine the number of ways to arrange these balls and separators. The total number of positions is 14 (10 balls + 4 separators), and we need to choose 4 positions for the separators from the 14 available positions.
Therefore, the number of solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, where each xi is greater than or equal to 3, is:
C(14, 4) = 14! / (4! * (14 - 4)!) = 1001.
c) 3 ≤ x₁ ≤ 10:
Now, we have a specific restriction on the value of x₁, where 3 ≤ x₁ ≤ 10. This means x₁ can take any value from 3 to 10, inclusive. For each value of x₁, we can determine the number of solutions to the reduced equation x₂ + x₃ + x₄ + x₅ = 25 - x₁.
Using the stars and bars method as before, we have 25 - x₁ balls and 4 urns representing the variables x₂, x₃, x₄, and x₅. The total number of positions is 25 - x₁ + 4, and we need to choose 4 positions for the separators from the available positions.
By considering each value of x₁ from 3 to 10, we can calculate the number of solutions to the equation for each case and sum them up.
Therefore, the number of solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, where 3 ≤ x₁ ≤ 10, is:
∑(C(25 - x₁ + 4, 4)) for x₁ = 3 to 10.
By evaluating this sum, we find that there are 5,561 solutions.
d) 3 ≤ x₁ ≤ 10 and 2 ≤ x₂ ≤ 7:
In this case, we have restrictions on both x₁ and x₂. To count the number of solutions, we follow a similar approach as in the previous case. For each combination of x₁ and x₂ that satisfies their respective restrictions, we calculate the number of solutions to the reduced equation x₃ + x₄ + x₅ = 25 - x₁ - x₂.
By using the stars and bars method again, we have 25 - x₁ - x₂ balls and 3 urns representing the variables x₃, x₄, and x₅. The total number of positions is 25 - x₁ - x₂ + 3, and we choose 3 positions for the separators from the available positions.
We need to iterate over all valid combinations of x₁ and x₂, i.e., for each value of x₁ from 3 to 10, we choose x₂ from 2 to 7. For each combination, we calculate the number of solutions to the equation and sum them up.
Therefore, the number of solutions to the equation x₁ + x₂ + x₃ + x₄ + x₅ = 25, where 3 ≤ x₁ ≤ 10 and 2 ≤ x₂ ≤ 7, is:
∑(∑(C(25 - x₁ - x₂ + 3, 3))) for x₁ = 3 to 10 and x₂ = 2 to 7.
By evaluating this double sum, we find that there are 780 solutions.
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Select 2 points in the solution of the inequality graphed below.
654-
21
3
x
k
It is known that 10% of all clothing bought online is returned. If an online retailer sells 20 items of clothing, what is the probability at least 2 items are returned?
The probability of at least 2 items being returned when an online retailer sells 20 items of clothing is approximately 0.6082.
Probability refers to the measure of the likelihood or chance of an event occurring. It quantifies the possibility of different outcomes in an uncertain or random situation. Probability is typically represented as a number between 0 and 1, where 0 indicates an impossible event and 1 indicates a certain event.
The concept of probability is based on the understanding that outcomes of certain events are not always predictable with certainty, but they can be described and analyzed using mathematical methods.
The probability of at least 2 items being returned can be calculated using the binomial probability formula. In this case, the probability of success (returning an item) is 10% or 0.1, and the probability of failure (not returning an item) is 90% or 0.9. The formula is:
P(X ≥ k) = 1 - P(X < k)
Where X is the number of items returned and k is the minimum number of items required.
To find the probability of at least 2 items being returned out of the 20 items sold, we can use the formula:
P(X ≥ 2) = 1 - P(X < 2)
P(X < 2) is the probability of 0 or 1 items being returned. Let's calculate it step by step.
P(X = 0) = (0.9)^(20) ≈ 0.1216
P(X = 1) = (20C1) * (0.1)^(1) * (0.9)^(19) ≈ 0.2702
P(X < 2) = P(X = 0) + P(X = 1) ≈ 0.1216 + 0.2702 ≈ 0.3918
Now, we can calculate P(X ≥ 2):
P(X ≥ 2) = 1 - P(X < 2) ≈ 1 - 0.3918 ≈ 0.6082
Therefore, the probability of at least 2 items being returned when an online retailer sells 20 items of clothing is approximately 0.6082.
It's important to note that this calculation assumes each item sold is independent of each other, and the probability of returning an item is consistent for all items. Also, this is a theoretical probability, and actual results may vary.
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here is the next one. sorry
Answer:
$5.30
Step-by-step explanation:
23.85/9=$2.65
2.65*2=$5.30
Answer:
I don't know if this is right but I got $5.30.
Step-by-step explanation:
I did 23.85/9 to get how much each pane is than I multiplied by 2 to get the cost of the 2 new panes.
23.85/9= 2.65
2.65*2 = 5.3
Is 2/10 greater than 1/8?
Answer:
1/8 is SMALLER then 2/10
Answer:
2/10 is greater
Step-by-step explanation:
2/10 and 1/8, hard to tell since they have different denominators. So let's make them have the same denominators, multiply 2/10 with 4/4 and 1/8 with 5/5.
If u don't want to think too much to find a number they can both be multiplied too, simply multiply each fraction with the others denominator, so 2/10 times 8/8 and 1/8 times 10/10. It doesn't rlly matter what factor u choose to multiply with as long as the denominator is the same.
So back to the first one, 2/10 times 4/4 is 8/40, 1/8 times 5/5 is 5/40.
8/40 > 5/40
Therefore 2/10 is greater
LM is the midsegment of trapezoid ABCD. If AB = 34 and DC = 128 , what is LM
Answer:81
Step-by-step explanation: AB=base 1 DC=base 2
Base1+Base2 divided by 2
The length of the midsegment of the trapezoid is 81 units.
How to find the mid segment of a trapezoid?The midsegment of a trapezoid is the line segment connecting the midpoints of the two non-parallel sides of a trapezoid.
The length of the midsegment of a trapezium is half the sum of the top and bottom of the trapezoid.
Therefore, let's find LM, the midsegment of the trapezoid.
Hence,
LM = 1 / 2 (AB + DC)
AB = 34
DC = 128
LM = 1 / 2 (34 + 128)
LM = 1 / 2 (162)
LM = 81
Therefore,
LM = 81 units
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70 pupils in a sports centre are surveyed. The pupils can only use the swimming pool and the gym. 28 pupils use the swimming pool and the gym. 48 pupils use the swimming pool. 39 pupils use the gym. Find the probability to select a pupil that uses neither the swimming pool nor the gym.
The probability that a pupil uses neither pool nor gym is 11/70
What is Probability?Probability is the likelihood that an event will happen. This can range from an event being impossible to some likelihood to being absolutely certain. In math terms, probability is on a scale from 0 to 1. Zero means the event is impossible, like rolling a seven on a die that only has digits from 1 to 6.
Number of pupil that can use pool and gym = 28
Number of people that can use pool = 48
Number of people that can use gym = 39
Number of people that can use pool only = 48 - 28 which is 20
Number of people that can use gym only = 39 - 28 = 11
Total number of persons that can use either pool, gym or both = 20 + 11 + 28 which is 59
Number of people that cannot use either or both of the facilities = 70 - 59 which is 11.
Probability = required outcome / possible outcome
Required outcome = 11
possible outcome = 70
Probability = 11/70
In conclusion, the probability that a pupil uses neither swimming pool nor gym is 11/70
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(-x²+9) + (-3x²-11x+4)
Answer:
=-4x^2-11x+13
Step-by-step explanation:
What is the area of the figure shown below?
320 cm
80 cm
20 cm
16 cm
Step-by-step explanation:
2 1/2=5/2
5/2×8=20cm^2
Rafael rented a truck for one day. There was a base fee of 15.95, and there was an additional charge of 74 cents for each mile driven. Rafael had to pay 220.19 when he returned the truck. For how many miles did he drive the truck?
Answer: He drove 276b miles with the truck
Step-by-step explanation: 220.19 - 15.95 = 204.24
204.24 / .74 = 276
someone please help.
The completed table with regards to terms of an expression are presented as follows;
Condition \({}\) (6·x + 3) + (5·x - 4) (-4·y - 16) - 8·y + 10 + 2·y
Exactly 3 terms N/A \({}\) N/A
Exactly 5 terms N/A \({}\) N/A
Includes a zero pair No \({}\) No
Uses distributive property No No
Includes a negative factor No
Has no like terms False False
Condition \(8 - \dfrac{1}{2} \cdot \left(4 \cdot x - \dfrac{1}{2} + 12\cdot x -\dfrac{1}{4} \right)\) 0.25·(8·m - 12) - 0.5·(-4·m + 2)
Exactly 3 terms No \({}\) No
Exactly 5 terms Yes \({}\) \({}\) No
Includes a zero pair No \({}\) \({}\) Yes
Uses the distributive property Yes \({}\) Yes
Includes a negative factor Yes \({}\) Yes
Has no like terms No \({}\) No
What is a mathematical expression?A mathematical expression is a collection of variables and numbers along with mathematical operators which are all properly arranged.
The details of the conditions in the question are as follows;
Terms of an expression
A term is a subunit of an algebraic expression which are joined together by operators such as addition or subtraction
Zero pair
A zero pair are two numbers that when added together have a zero result
Distributive property
The distributive property of multiplication states that the multiplication of a number or variable by an addend is equivalent to the sum of the multiplication of the number or variable and each member of the addend
Negative factor
A negative factor is a factor that has a negative sign prefix
Like terms
Like terms are terms consisting of identical variables with the same powers of the variable
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8.88 = 4.44(x-7)
Solve for x
Show or explain your method
Answer:
x=9
Step-by-step explanation:
8.88=4.44x-31.088.88-4.44x=-31.08-4.44x=-31.08-8.88-4.44x=-39.96x=9(we divided both rquations by -4.44)the expected value of an unbiased estimator is equal to the parameter whose value is being estimated. true/false
The statement "the expected value of an unbiased estimator is equal to the parameter whose value is being estimated" is true.
An estimator is a function of the sample data used to estimate the value of a population parameter. An estimator is said to be unbiased if its expected value is equal to the true value of the population parameter. In other words, if we were to repeatedly take samples from the population and calculate the estimator for each sample, the average value of the estimator over all the samples would be equal to the true value of the population parameter. The expected value of an unbiased estimator is a key property because it ensures that the estimator is not systematically overestimating or underestimating the population parameter. Instead, the estimator provides an unbiased estimate of the population parameter on average across all possible samples. It is important to note that not all estimators are unbiased. Biased estimators may systematically overestimate or underestimate the population parameter, leading to incorrect conclusions. Therefore, unbiasedness is a desirable property for an estimator to have.
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Find the area of the region inside the circle r=4cos(theta) and outside the circle r=2.
Area of the region inside the circle r=4cos(theta) and outside the circle r=2 is 4π/3 + 2√3
What is the polar curve?A form created using the polar coordinate system is called a polar curve. Points on polar curves have varying distances from the origin (the pole), depending on the angle taken off the positive x-axis to calculate distance. Both well-known Cartesian shapes like ellipses and some less well-known shapes like cardioids and lemniscates can be described by polar curves.
r = 1 − cosθsin3θ
Polar curves are more useful for describing paths that are an absolute distance from a certain point than Cartesian curves, which are good for describing paths in terms of horizontal and vertical lengths. Polar curves can be used to explain directional microphone pickup patterns, which is a useful application. Depending on where the sound is coming from outside the microphone, a directional microphone will take up sounds with varied tonal characteristics. A cardioid microphone, for instance, has a pickup pattern like a cardioid.
The area between two polar curves can be found by subtracting the area inside the inner curve away from the area inside the outer curve.
The figure attached shows the bounded region of the two graphs. The red curve is r=4cos(θ) and the blue curve is r=2.
The points of intersection of the two curves are
θ = π/3 and 5π/3
The area is calculated as follows:
Since the bounded region is symmetric about the horizontal axis, we will find the area of the top region, and then multiply by 2, so as to get the total area.
A = 2 \(\(\int_{0}^{\pi /3}\) ½ (4 cos (θ)² − ½ (2)² dθ
= \(\(\int_{0}^{\pi /3}\) 16 cos2 (θ) − 4dθ
= \(\(\int_{0}^{\pi /3}\) 8 (1+cos(2θ)) − 4dθ
=\(\(\int_{0}^{\pi /3}\) 4 + 8 cos (2θ) dθ
= [4θ + 4sin (2θ)] \(\(\int_{0}^{\pi /3}\)
= 4π/3 + 2√3
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Fay opens a credit card with an APR of 15.25% compounded monthly. How much is charged in interest this month if her balance is $1,300? (4 points)
Answer:
total charge = $ 16.52
refer to the Attachment please :)
hope this helps you ^^"
Joey is buying plants for his garden. he wants to have at least twice as many flowering plants as nonflowering plants and a minimum of 36 plants in his garden. flowering plants sell for $8, and nonflowering plants sell for $5. joey wants to purchase a combination of plants that minimizes cost. let x represent the number of flowering plants and y represent the number of nonflowering plants. what are the vertices of the feasible region for this problem?
The Feasible region's vertices are as follows.
(24,12)(0,36)
What is vertices?A vertex in geometry is the intersection of two or more curves, lines, or edges. Vertices are frequently represented by the letters P, Q, R, or S. The intersection of two lines to form an angle, as well as the corners of polygons and polyhedra, are vertices according to this definition.
He desires at least two times as many flowering plants as non-flowering ones.
According to the given information:the amount of blossoming plants be = x
the number of non-flowering plants be. = y
The question states
Assuming the following circumstance, inequality is:
x ≥ 2y = 0 ..............(1)
Additionally, the inequality must be reflected by at least as many flowers in the garden as:
x + 2y ≥36 .................(2)
The price of x blooming plants will be. = 8x
the cost of y nonflowering plants be = 9y
Additionally, in order to prevent inequality, he must reduce costs.
the lowest price
Now,
Ones that meet the requirements (1) and are feasible (2).
In order to overcome constraints (1) and (2), we get
using equation (1)'s value as the value for equation (2)
2y + y = 36
3y = 36
y = 36/3
y = 12
then
x = 24
With Equation (1) & (1) once more solved, we obtain x = 0 & y = 36.
Hence,
The Feasible region's vertices are as follows.
(24,12)(0,36)
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Answer:
d
Step-by-step explanation:
on edge
what is the prime number of 65
Answer:
Factors of 65: 1, 5, 13, and 65.
Prime Factorization of 65: 65 = 5 × 13.
Step-by-step explanation:
hope this helps!
Answer:
1, 5, 13, and 65.
Step-by-step explanation:
Solve for x. Your answer must be simplified. x-24>_9
Answer:
x>33
Step-by-step explanation:
x-24>9
-24 moves to the other side and becomes positive
x>9+24
x>33
Please help! Easy question, answer pls, 15 pts.
Answer:
360 in
Step-by-step explanation:
To figure out how many inches the dressmaker has in 10, 3 ft rolls, we can multiply by the conversion ratio:
\(\dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies (10 \cdot 3 \text{ ft}) \cdot \dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies 30 \text{ ft} \cdot \dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies 30\cdot 12 \text{ in} \\ \\ \text{} \ \ \implies \boxed{360 \text{ in}}\)
So, the dressmaker has 360 in of ribbon.
how many squares with side 2 cm can cover the surface of a rectangle with length 24 cm and width 8 cm ?
The number of 48 squares cover the surface of a rectangle.
What is a formula of area of square?Area of a Square = Side × Side. Therefore, the area of square = \(Side^2\) square units. and the perimeter of a square = 4 × side units.
We have the information :
The side of a square is 2cm
and, Length of the rectangle is = 24 cm
Breadth of the rectangle is = 8cm
We have to find the how many square cover the surface of a rectangle.
The area of the square is
2 × 2
=4
The area of the rectangle is
L × W
=24 ×8
=192
The number of squares is
192 ÷ 4
=48
Hence, The number of 48 squares cover the surface of a rectangle.
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