Magnetism is a force that results from the movement of charged particles, such as electrons, within a magnetic field.
What is Magnetic Field?
A magnetic field is a region in space where a magnetic force is experienced by a magnetic material or a moving electric charge. It is produced by moving electric charges or magnetic materials, such as magnets. The magnetic field is a vector field, which means that it has both magnitude and direction. The direction of the magnetic field is conventionally represented by lines of magnetic flux that form closed loops around a magnet or a moving electric charge. The strength and direction of the magnetic field at any point in space can be determined by measuring the force exerted on a test charge or a magnet placed at that point. Magnetic fields are used in a wide range of applications, including electric motors, generators, magnetic resonance imaging (MRI) machines, and particle accelerators.
Magnetism is a fundamental force of nature that is responsible for the attraction or repulsion between magnetic objects. It is caused by the motion of charged particles, such as electrons, within atoms. Magnetism is associated with magnetic fields, which are invisible areas around a magnet where magnetic forces can be detected.
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what evidence supports the information consolidation theory?
PLEASE HELP ME ITS DUE NEXT PERIOD
Explanation:
Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.
Anybody what cloud is this
If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.
What is altocumulus clouds?Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.
Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.
While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.
Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.
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a ball dropped from a height of 10 meters will bounce more times before coming to rest than a ball dropped from a height of 5 meters. Use evidence and scientific reasoning to explain this phenomenon.
Answer:
plz mark brainliest again lol :)
Explanation:
When you drop a ball from a greater height, it has more kinetic energy just before it hits the floor and stores more energy during the bounce—it dents farther as it comes to a stop.
Answer:
When you drop a ball from a greater height, there is more potential energy. When you release the ball, the potential energy turns into kinetic energy. When the ball bounces off the ground, the ball go upward and then it has more potential energy. Then when it goes down it has more kinetic energy. The ball keeps doing this until there is not enough potential energy left.
Explanation:
Which of the following results of correlational studies implies that environmental contributes to the determination of IQ?
Correlations for children and their adoptive parents are statistically significant and positive
The right response is that identical twins have stronger correlations than fraternal twins do.
What is correlational example?If there are several pizza truck in the region, each with its own distinctive jingle, we would learn them all by heart and associate each one with a certain pizza truck. Establishing a connection between two variables, in this case "jingle" and "distance of the truck" in this example, is exactly what correlational research involves.
What is correlational in psychology?A nonexperimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) among them with little to no effort to control unrelated variables.
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what is kineamatics (60 words)
Kinematics is the study of motion of an object without considering the forces that caused the object to move.
Kinematics is a branch of mechanics, which is used to study about mechanical bodies or mechanical systems without the reference of the body's/system's physical properties or the forces acting on it.
Kinematics models different motion mathematically with the help of algebra. Therefore, it is referred as geometry of motion. The modelling is done to calculate the various factors of motion such as speed, acceleration etc.
Therefore, Kinematics is the study of motion of an object without considering the forces that caused the object to move.
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A pulse of sound takes 1 second to travel about 25 feet to the seafloor
100
and back. A ship stops in an area where the seafloor extends to the bottom
of the Sunlight Zone. At this spot an echosounder gives a pulse of sound
that takes 26 second to travel to the seafloor and back. How deep is the
100
ocean at the bottom of the Sunlight Zone?
HELP!!! I’m stumped!! Get max points ( if it lets me! )
Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.
The distance travelled by echo sound is given by the formula -
Speed = 2×distance/time
So, calculating the speed of sound from the formula using distance and time
Speed = 2×25/(1/100)
Speed = 50×1000
Speed of sound = 5000 feet/second
Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -
Distance = (speed×time)/2
Distance = (5000×26/100)/2
Distance = 1300/2
Distance = 650 feets
Hence, the depth of ocean is 650 feets.
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Answer:
We can start by using the formula:
distance = speed x time
where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.
The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).
Converting the round-trip time to seconds, we have:
26 seconds - 1 second = 25 seconds
Substituting the values into the formula:
2 x depth = 4,921 feet/second x 25 seconds
2 x depth = 123,025 feet
depth = 61,512.5 feet
Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.
3. How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot? Why do you think this happens?
Answer:
the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.
Explanation:
A conductor that does not obey Ohm's law is described as non - ohmic. An example is a filament lamp. It glows as the current passes through it.
How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot ?
The resistance of the light bulbs increase gradually as its temperature is increased.
So, the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.
Because the resistance of an impure metal wire is greater than the resistance of a pure metal wire of the same dimension.
The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichit is made has an index of refraction of 1.38, and its front surface is convex,with a radius of curvature of 5.00 {\rm mm}.(Note: The results obtained here are not strictlyaccurate, because, on one side, the cornea has a fluid with arefractive index different from that of air.)a) If this focal length is in air, what is the radius ofcurvature of the back side of the cornea? (in mm)b) The closest distance at which a typical person can focus onan object (called the near point) is about 25.0 {\rm cm}, although this varies considerably with age. Wherewould the cornea focus the image of an 10.0 {\rm mm}-tall object at the near point? (in mm)c) What is the height of the image in part B? (mm)d) Is this image real or virtual? Is it erect orinverted?
Answer:
Explanation:
a )
from lens makers formula
\(\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})\)
f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face
putting the values
\(\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})\)
1.462 = 2 - 1 / r₂
1 / r₂ = .538
r₂ = 1.86 cm .
= 18.6 mm .
b )
object distance u = 25 cm
focal length of convex lens f = 1.8 cm
image distance v = ?
lens formula
\(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\)
\(\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}\)
\(\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}\)
.5555 - .04
= .515
v = 1.94 cm
c )
magnification = v / u
= 1.94 / 25
= .0776
size of image = .0776 x size of object
= .0776 x 10 mm
= .776 mm
It will be a real image and it will be inverted.
convert 144 km/h to m/s
Answer:
40m/s
Explanation:
144km/h
1km=1000m
1hr=3600secs
144×1000/3600=
40m/s
Hank and Harry are two ice skaters whiling away time by playing 'tug of war' between practice sessions. They hold on to opposite ends of the same rope and pull the other toward him. The magnitude of Hank's acceleration is 1.26 times greater than the magnitude of Harry's acceleration. What is the ratio of Hank's mass to Harry's mass?
Answer:
the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1
Explanation:
Given the data in the question;
Hank and Harry are two ice skaters, since both are on top of ice, we assume that friction is negligible.
We know that from Newton's Second Law;
Force = mass × Acceleration
F = ma
Since they hold on to opposite ends of the same rope. They have the same magnitude of force |F|, which is the same as the tension in the rope.
Now,
Mass\(_{Hank\) × Acceleration\(_{Hank\) = Mass\(_{Henry\) × Acceleration\(_{Henry\)
so
Mass\(_{Hank\) / Mass\(_{Henry\) = Acceleration\(_{Henry\) / Acceleration\(_{Hank\)
given that; magnitude of Hank's acceleration is 1.26 times greater than the magnitude of Harry's acceleration,
Mass\(_{Hank\) / Mass\(_{Henry\) = 1 / 1.26
Mass\(_{Hank\) / Mass\(_{Henry\) = 0.7937 or [ 0.7937 : 1 ]
Therefore, the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1 ]
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Convert 3.0 x 10-3 micrometer to cm
Answer:
27
Explanation:
Please helpppppppppppppppppppp
Answer:
Explanation:
what do you really need help with
A 1.0 kg cube of ice is dropped into 1.0 kg of water, and when equilibrium is reached, there are 2.0 kg of ice at 0.0° C. The initial temperature of the water was 0°C. What was the original temperature of the ice? (Cw = 4186 J/kgo°C, c; = 2093 J/kg.°C, and If = 3.3 × 105 J/kg)
The initial temperature of the water was 0°C and the original temperature of the ice was -78.8°C.
First, we need to determine how much heat was transferred from the water to the ice to melt the ice and raise its temperature to 0°C.
The heat is required to melt the ice will be;
Q₁ = m_ice x Lf
where m_ice is the mass of the ice and\(L_{f}\) is the latent heat of fusion of ice.
Q₁ = 1.0 kg x 3.3 x 10⁵ J/kg
= 3.3 x 10⁵ J
The heat required to raise the temperature of the melted ice from -x°C to 0°C is;
Q₂ = m_ice x c_ice x ΔT
where c_ice is the specific heat capacity of ice and ΔT is the change in temperature.
Q₂ = 1.0 kg x 2093 J/kg.°C x (0 - (-x))°C
= 2093x J
The heat lost by the water will be equal to the heat gained by the ice;
Q₁ + Q₂ = m_water x Cw x ΔT
where m_water is the mass of the water and Cw is the specific heat capacity of water.
3.3 x 10⁵ J + 2093x J = 1.0 kg x 4186 J/kg.°C x (0 - T)°C
Solving for T, we get;
T = -[(3.3 x 10⁵ J + 2093x J)/(4186 J/kg.°C)]
= -78.8°C
Therefore, the original temperature of the ice was -78.8°C.
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onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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Find the magnitude of the gravitational force (in N) between a planet with mass 6.00 X 10^24 kg and its moon, with mass 2.50 X 10^22 kg, if the average distance between their centers is 2.70 X 10^8 m. What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.)
Answer:
Magnitude of gravitational force between this planet and its moon: approximately \(1.37 \times 10^{20}\; \rm N\).
Acceleration of this moon towards the planet: approximately \(5.49 \times 10^{-3}\; \rm m \cdot s^{-2}\).
Acceleration of this planet towards its moon: approximately \(2.29 \times 10^{-5}\; \rm m \cdot s^{-2}\).
Explanation:
Look up the gravitational constant, \(G\):
\(G \approx 6.67 \times 10^{-11}\; \rm m^3\cdot kg^{-1} \cdot s^{-2}\).
Assume that both this planet and its moon are spheres of uniform density. When studying the gravitational interaction between this planet and its moon, this assumption allows them to be considered as two point masses.
The formula for the size of gravitational force between two point masses \(m_1\) and \(m_2\) with a distance of \(r\) in between is:
\(\displaystyle F = \frac{G \cdot m_1 \cdot m_2}{r^2}\),
where \(G\) is the gravitational constant.
Let \(m_1\) and \(m_2\) denote the mass of this planet and its moon, respectively.
Calculate the size of gravitational force between this planet and its moon:
\(\begin{aligned} F &= \frac{G \cdot m_1 \cdot m_2}{r^2} \\ &\approx \frac{6.67 \times 10^{-11}\; \rm m^3 \cdot kg^{-1} \cdot s^{-2} \times 6.00 \times 10^{24}\; \rm kg \times 2.50 \times 10^{22}\; \rm kg}{{\left(2.70 \times 10^{8}\; \rm m\right)}^2} \\ &\approx 1.37 \times 10^{20}\; \rm N\end{aligned}\).
Assume that other than the gravitational force between this planet and its moon, all other forces (e.g., gravitational force between this planet and the star) are negligible. The magnitude of the net force on the planet and on the moon should both be approximately \(1.37 \times 10^{20}\; \rm N\).
Apply Newton's Second Law of motion to find the acceleration of this planet and its moon:
\(\displaystyle \text{acceleration} = \frac{\text{net force}}{\text{mass}}\).
For this moon:
\(\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{2.50 \times 10^{22}\; \rm kg} \approx 5.49\times 10^{-3}\; \rm m \cdot s^{-2}\).
For this planet:
\(\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{6.00 \times 10^{24}\; \rm kg} \approx 2.29 \times 10^{-5}\; \rm m \cdot s^{-2}\).
A 0.016-kg piece of iron absorbs 1086.75 joules of heat energy, and its
temperature changes from 25°C to 175°C. Calculate the specific heat
capacity of iron. Equation : c = Q/mt
Answer:
c = 115.92 q/g C
Explanation:
0.016 kg = 16 grams
q = Joules
m = mass (g)
t = (final temp. - initial temp)
c = specific heat
c = (1086.75 joules) / (175 C - 25 C) (16 g)
c = 115.92 q/g C
Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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The engineers are designing a base for the pools in the ladder. The base is a square with edge lengths of 1.5 meters. A criterion for the base is that it must withstand a stress of 3,200 N/m². In tests, a prototype of the base withstood a total force of 4,500 N before it failed.
Stress = Force / Area
Stress required = 3,200 N/m^2
Area = side ^2 = 1.5^2 = 2.25 m^2
Force = 4,500 N
Replace with the values given:
S = 4,500/2.25 = 2000 N/m^2 ( less than 3,200)
Correct answer:
NO, because it was able only to withstand a stress of 2000 N/m^2
A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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Two blocks of equal mass are connected by a string that passes over a pulley, as shown in the figure. Block 1 hangs from the string, and block 2 can slide on a table. The system is released from rest. Using conservation of energy, a student derives an expression for the speed v of block 1 when it has fallen a distance h after the system has been released from rest and obtains the equation v=gh−−√ . Question The figure presents a diagram of a pulley system at the edge of a table. A block labeled Block 1 is hanging off the table. Two other blocks are on the table. The block on the left is labeled Block 3 and the block on the right is labeled block 2. Block 1 is connected to a string that passes through a pulley. The left end of the string is connected to the right side of Block 2. Another string connected the left side of Block 2 to the right side of Block 3. A third block of the same mass as blocks 1 and 2 is attached to block 2 on the table, as shown in the figure. Using conservation of energy, the student repeats a derivation for the speed v of block 1 when it has fallen a distance h . Which of the following is a correct expression for v ? Responses gh√3 the fraction with numerator the square root of g h, and denominator 3 gh√2
Block y will experience a stronger pull from gravity and fall more quickly than block x since it has more mass than block x is 29.4 md
To complete this task, we will apply Newton's second law. Assume that a block with mass m is moving up.
T-W₁ = m a
W₃ - T = M a
w₃ - w₁ = (m + M) a
g = a = (3m - m) / (3m + m)
a = 2/4 g
a = ½ g
The blocks move at a pace of
v² = v₀² + 2 ½ g x
v = √ g x
b) As work is a scalar, it adds to other quantities.
luminous blocks
W1 = W d = mg
d = -a 3 m hefty block
W2 = 3m g d = W d
the entire project is
W = W₁ + W₂
W = 2 m g d
c) When all external pressures are applied to the centre of mass, they relate to it being
a = ½ g
T = 2m1m2g/(m2 + m1)
= 2x mx3x3mg/ 4m
= 14.7 m
Work done in moving by distance by tension on both masses d
= 2 x 14.7 m x d ( 2 x force x displacement ) ( 2 x force x displacement )
= 29.4 md .
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The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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Explain the
difference between an
oxygen atom and a carbon atom
Answer:
Carbon atoms are made up of 6 protons, 6 electrons, and 6 neutrons, whereas Oxygen atoms are made of 8 protons, 8 neutrons, and 8 electrons.
Explanation:
This may not sound like a big difference at the atomic level, but it is responsible for all of the differences between Oxygen and Carbon.
Newton's Three laws talk about all of the following:
Inertia, Mass, Force, Acceleration, and Velocity.
Which of these five things is involed/relevent to all three laws? Explain why.
please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING
A 0.05 kg tennis ball moves at a speed of 10 m/s and is struck by a racket causing it to rebound in the opposite direction at a speed 16 m/s. What is the change in momentum of the ball? What is the impulse exerted on the ball? What is the impulse exerted on the racket?
Answer:
Δp = -1.3 kg m/s
Impulse on the ball = Δp = -1.3 kg m/s
Impulse on the racket = 1.3 kg m/s
Explanation:
The change in momentum of the ball can be calculated as
\(\Delta p=mv_f-mv_i\)Where m is the mass of the tennis ball of 0.05 kg, vf is the final velocity and vi is the initial velocity. Since the ball rebound in the opposite direction, we will replace vf = -16 m/s and vi = 10 m/s
Replacing the values, we get
\(\begin{gathered} \Delta p=0.05\text{ kg\lparen-16 m/s\rparen-0.05 kg\lparen10 m/s\rparen} \\ \Delta p=-0.8\text{ kg m/s - 0.5 kg m/s} \\ \Delta p=-1.3\text{ kg m/s} \end{gathered}\)Therefore, the change in momentum of the ball is -1.3 kg m/s.
Then, the impulse exerted on the ball is equal to the change in momentum, so
Impulse on the ball = Δp = -1.3 kg m/s
Finally, the impulse exerted on the racket is equal to the impulse of the ball but with the opposite sign, so
Impulse on the racket = 1.3 kg m/s
At winter design conditions, a house is projected to lose heat at a rate of 60,000 Btu/h. The internal heat gain from people, lights, and appliances is estimated to be 6000 Btu/h. If this house is to be heated by electric resistance heaters, determine the requried rated power of these heaters in KW to maintain the house at constant temperature.
Answer:
15.83 KW
Explanation:
Losing heat at a rate = 60000btu/h
Gaining heat at a rate = 6,000btu/h
The difference in heat levels
= 60000btu/h - 6000btu/h
= 54000btu/h
So we need to convert 54000btu/h to KW
1kw = 3412.142btu
? = 54000btu
We cross multiply
54000btu x 1kw = ?3412.142btu
So we divide through by 3412.142 to get the unknown
54000/3412.142
= 15.83kw
So we can conclude that 15.83kw is the required power of this heater to keep the house at a constant temperature
Apply what is the momentum of a bicycle with a mass of 18 kg traveling at 20 m/s?.
Answer:
Below
Explanation:
Momentum = m v
= 18 kg * 20 m/s = 360 kg m/s
How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 390 m/s
Answer:
Explanation:
½(75)v² = ½(0.008)390²
v² = (0.008)390²/75
v² = 16.224
v = 4.027...
v = 4.0 m/s
A train of mass 3.3 × 10^6 kg is moving at a constant speed up a slope inclined at an angle of 0.64°
to the horizontal. The engine of the train is producing a useful output power of 14 MW.
Assume that there are no frictional forces opposing the motion of the train.
What is the speed of the train?
A 0.43 m s–1 B 4.2 m s–1 C 39 m s–1 D 380 m s–1.
Ans is C how?
ref: Q14 - 9702_s18_qp_11
Answer:
C. 39 m/s
Explanation:
First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:
Force = F = mg Sin θ
where,
m = mass of train = 3.3 x 10⁶ kg
g = 9.8 m/s²
θ = Angle of Inclination = 0.64°
Therefore,
F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°
F = 3.612 x 10⁵ N
Now, the formula for power is:
P = FV
V = P/F
where,
V = Velocity of Train = ?
P = Power of Engine = 14 MW = 1.4 x 10⁷ W
Therefore,
V = 1.4 x 10⁷ W/3.612 x 10⁵ N
V = 38.75 m/s
which is approximately equal to:
C. 39 m/s
The speed of train is 39 m/s. Hence, option (C) is correct.
Given data:
The mass of train is, \(m = 3.3 \times 10^{6} \;\rm kg\).
The angle of inclination is, \(\theta = 0.64^ {\circ}\).
The useful power output value is, \(P= 14 \;\rm MW = 14 \times 10^{6} \;\rm W\).
The work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present. So, the total force required to move the train along the inclined plane is given as,
\(F = mg sin \theta\\\\F = 3.3 \times 10^{6} \times 9.8 \times sin0.64\\\\F = 361233.75 \;\rm N\)
Now, use the formula of the power to obtain the value of speed as,
\(P = F \times v\\\\14 \times 10^{6} =361233.75 \times v\\\\v \approx 38.75 \;\rm m/s\)
Thus, the speed of train is 39 m/s. Hence, option (C) is correct.
Learn more about the power output here:
https://brainly.com/question/22285866