Many bacteria and fungi are important in the environment because they?

Answers

Answer 1

Answer:

Bacteria and fungi is important in the environment because they return energy to the environment. By returning energy to the environment, they make the energy available for plants to utilize.  They also recycle nutrients that other organisms will then use.  

Explanation:


Related Questions

what impact does global warming have on plants and animals in the us and what role does the us government play in this injustice?

Answers

Global warming has significant impacts on plants and animals in the United States. Rising temperatures, altered precipitation patterns, and more severe weather events are changing the distribution and abundance of species. The US government plays a role in addressing the injustices caused by global warming.

Changes in temperature and precipitation patterns can alter the timing of seasonal events such as flowering and migration, which can disrupt the relationships between species. Warmer temperatures also increase the risk of wildfire and drought, which can damage or destroy habitats. Additionally, sea level rise can flood coastal habitats and threaten species that rely on them.

The Federal government has a responsibility to protect and manage public lands and waters, and to ensure that the nation's wildlife and natural resources are conserved for future generations. The US government has implemented policies such as the Clean Air Act and the Clean Water Act to regulate emissions of greenhouse gases, which are the primary drivers of global warming. However, the current administration has been rolling back some of these regulations.

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In the United States, there are substantial effects of global warming on flora and animals.

The distribution and quantity of species are shifting as a result of increased temperatures, altered precipitation patterns, and more extreme weather events. In addressing the injustices brought on by global warming, the US government has a part to play. The timing of seasonal activities like flowering and migration can be altered by changes in temperature and precipitation patterns, which can cause havoc with the interactions between species. Warmer temperatures also raise the danger of drought and wildfire, which can harm or obliterate habitats. Sea level rise can also inundate coastal ecosystems, endangering the animals that depend on them.

The federal government is responsible for managing public lands and streams, protecting wildlife, and preserving the nation's natural resources.

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1. According to the text, what is cross-training? A. doing two or more different types of exercise in one workout B. doing two or more of the same type of exercise in one workout C. doing the same exercise in many workouts throughout the week D. doing two or more different exercises that make muscles stronger​

Answers

Answer:

A. doing two or more different types of exercise in one workout

Explanation:

Mark all of the terms that relate to the structure of RNA.

a
thymine

b
double helix

c
ribonucleic acid

d
adenine

e
cytosine

f
single helix

g
guanine

h
uracil

i
hydrogen bonds

j
deoxyribonucleic acid

Answers

everything except answer f)

Explain how to identify
a starting position on a line.

Answers

Answer:

We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

Answer:

Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.

Explanation:

Explain the unique bonding properties of carbon.

Answers

Atomic number of carbon = 6.Electronic configuration has 2 electrons in k shell and 4 electrons in L shell.In order to attain the noble gas configuration, carbon should either gain 4 electrons or lose 4 electrons or can share it's 4 electrons with some other element.Gain of 4 electrons to form octet , 8 electrons in C⁴‐ anion is difficult because then a nucleus with 6 protons will uave to hold extra four electrons. Loss of 4 electrons to attain duplet , 2 electrons like He atom in C⁴+ cation is difficult as it requires large amount of energy to remove four electrons. Carbon , hence overcomes this difficulty by sharing its four valance electrons with other atoms of carbon or with atoms of other elements. These electrons contributed by the atoms for mutual sharing in order to acquire the stable noble configuration is called covalency of that atom . Hence carbon shows tetracovalency.The simplest molecule formed by sharing electrons, cvalent bonds can represent by electron dot structure.

Carbon , hence overcomes this difficulty by sharing its four valance electrons with other atoms of carbon or with atoms of other elements.

What do you mean by valence electrons?

A valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed.

Valence electrons are the electrons in the outermost shell, or energy level, of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table.

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A structural change in the alpha-factor of Saccharomyces (a type of yeast) is shown to render the molecule defective. What effect would this mutation have on the reproductive behavior for this yeast cell species? Justify your claim by discussing cell signaling and response events.

Answers

The ability of the yeast cell to divide and reproduce is lost if the alpha receptor's structure is damaged. Structure loss leads to function loss.

What is alpha factor in yeast?

The alpha cells of Saccharomyces cerevisiae release alpha-Factor, a 13-amino-acid pheromone, which binds to Ste2p, a seven-transmembrane, G-protein-coupled receptor, to trigger a signal transduction pathway necessary for mating and conjugation.

Yeast has two mating types, MATa and MAT. A yeast cell undergoes physiological changes when triggered by pheromone from an opposing mating type cell. These include alterations in the expression of 200 genes (approximately 3% of the genome), pause in the G1 phase of the cell cycle, directed growth toward the mating partner, and the fusion of the mating partners' plasma membranes, followed by the fusion of their nuclei. Process takes 4 h.

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b) Propose ONE type of mating behavior that could have resulted in the observed change in the number of spots per adult male guppy between 6 and 20 months in the absence of the predator.

Answers

One type of mating behavior that could have resulted in the observed change in the number of spots per adult male guppy between 6 and 20 months in the absence of the predator is female preference for males with more spots.

This could lead to males with more spots having a higher chance of mating and passing on their genes for more spots to their offspring. Over time, this could result in an increase in the number of spots per adult male guppy population. Additionally, male competition for mating opportunities could also play a role in this mating behavior, with males with more spots being more successful in outcompeting their rivals for female attention.

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A forest fire destroys an area. A small population of trees and a large population of birds are both affected. Which type
of limiting factor causes this?
O density dependent
O density independent
O population dependent
O population independent

A forest fire destroys an area. A small population of trees and a large population of birds are both

Answers

Answer:

Density independent is the correct answer

The type of limiting factor that causes this scenario are density-independent factors, which is Option B, because they affect populations regardless of their size or density.

What are density-independent factors?

Density-independent factors are environmental factors that affect populations regardless of their size or density. These factors can include natural disasters such as forest fires, floods, hurricanes, droughts, and other extreme weather events. Other examples of density-independent factors include habitat destruction, pollution, and climate change. In the scenario described, a forest fire destroyed an area, which can lead to the decline of both tree and bird populations. The fire could kill the trees and destroy their habitats, making it difficult for the surviving trees to grow or reproduce.

Hence, the type of limiting factor that causes this scenario are density-independent factors, which is Option B, because they affect populations regardless of their size or density.

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The ecologists had too little time and too little money to count species in the entire 1,000-hectare reserve in which the 100-ha plot was established. Instead, they spent their time inventorying species in subsets of the 100-ha plot. They arranged their plots so they could build a species-area graph from data collected within the 100 hectares. The plots were established so that each plot was completely contained in each successively bigger plot. They started with inventorying a 1-ha plot, then a 10-ha plot, a 20-ha plot, a 50-ha plot, and the whole 100-ha plot. After plotting the data on a log-log graph, they calculated c and z. Consider that log(c) = 0.699 and z = 0.608 for these data, how many species would you predict occur in the entire 1000 ha reserve?

Answers

We can predict that approximately 3166 species would occur in the entire 1000-hectare reserve based on the provided data and the species-area relationship.

To predict the number of species that would occur in the entire 1000-hectare reserve, we can use the species-area relationship and the values of c and z provided. The species-area relationship is typically modeled using a power law equation of the form:

\(S = cA^z\)

where S represents the number of species, A represents the area, c is a constant, and z is the slope of the relationship.

In this case, we have log(c) = 0.699 and z = 0.608.

To find the value of c, we need to take the antilog (base 10 exponentiation) of log(c). Therefore:

\(c = 10^{(log(c))\)

\(c = 10^{(0.699)\)

c = 4.997

Now we can use the equation \(S = cA^z\) to calculate the number of species for the entire 1000-hectare reserve. Substitute A = 1000 into the equation:

\(S = 4.997 * 1000^{0.608\)

S = 4.997 * 633.939

S = 3166.40

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***WILL MARK BRAINLIEST!!! Which of the following correctly explains why the first anaerobic organisms on earth are not classified as autotrophs?

A. Chemicals were not available for these organisms to produce their own food

B. oxygen was in abundance and it was more efficient to eat food rather than make their own

C. carbon dioxide was not present on earth at that time

D. The first organisms did not have sunlight available to make their own food

Answers

Answer:

The correct answer is B.Oxygen was in abundance and it was more efficient to eat food rather than make their own.

Explanation:

The first organisms were a group of bacteria. They were probably heterotrophic anaerobes because there was virtually no oxygen in the atmosphere at that time. These bacteria did not breathe oxygen, thus they were anaerobic. They cannot make their own food. These early bacteria  probably consume amino acids which were present in nature . Amino acids, sugars, and other organic compounds formed spontaneously in the atmosphere.

Answer:

Oxygen was in abundance and it was more efficient to eat food rather than make their own.

Explanation:

when it is ovulated, the female gamete is at a stage called the

Answers

When an ovum is ovulated, the female gamete is at a stage called metaphase II.

This is the second stage of meiosis, a type of cell division that creates gametes, which are reproductive cells. During this stage, the cell divides in half to form two haploid, or single-stranded, gametes. The chromosomes of the ovum have already been replicated and arranged in a line at the center of the cell.

In metaphase II, the spindle fibers, which are thin protein filaments, attach to the centromere of each chromosome and pull them to opposite poles of the cell. This process is called segregation, and it helps to create the two daughter cells with exactly half of the genetic material as the parent cell. Once segregation is complete, the cell enters the telophase stage and the two daughter cells begin to form a cell wall, completing the meiotic process.

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During interphase, most of the nucleus is filled with a complex of dna and protein in a dispersed form called.

Answers

Answer:

Chromatin

Explanation:


Which is NOT considered FIRST line of defense?
(1 Point)
White Blood Cells
Mucous Membranes
Hair
Skin

Answers

Answer:

A. White Blood Cells

Explanation:

Which is NOT considered FIRST line of defense?(1 Point)White Blood CellsMucous MembranesHairSkin

which contributes most to the development of drug-resistant bacteria?

Answers

Answer:

Repeated and improper uses of antibiotics are primary causes of the increase in drug-resistant bacteria

Explanation:

. While antibiotics should be used to treat bacterial infections, they are not effective against viral infections like the common cold, most sore throats, and the flu.

Mitochondria resemble bacteria of which type in terms of their structure?

Answers

Mitochondria resemble alpha-proteobacteria in terms of their structure. This is because they have a double membrane structure, similar to the outer and inner membrane of alpha-proteobacteria.

Additionally, mitochondria have their own DNA and replicate independently of the cell they are found in, which is also a characteristic of alpha-proteobacteria.


Hi! Mitochondria resemble Gram-negative bacteria in terms of their structure. Both have a double membrane and share similarities in size and shape. Additionally, they both contain circular DNA, which further supports the endosymbiotic theory of mitochondrial evolution.

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If a cell's lysosomes were damaged, which of the following would most likely occur?

A: The cell would be less able to regulate the amount of fluid in its cytoplasm

B: The cell would be less able to break down molecules in its cytoplasm

C: The cell would have chloroplasts that appear yellow rather than green

D:The cell would produce more proteins than it needs

Answers

Answer:

interpret the function and interrelation of the brain and the nerves system

Without the process of translation, our cells would not be able to:
make DNA
make RNA
make amino acids
make proteins

Answers

Answer:

Make protein

Explanation:

Make protein by RNA


13. What type of energy does the plant use to convert CO2 and H20 into sugar?

Answers

Answer:

light energy

Explanation:

Answer:

It's light energy.

Explanation:

can you make me brainliest please

*(b) Enzyme technology can be used in the production of foods including sweets, vegetarian
cheese and lactose-free milk.
Describe how enzyme technology can be used to produce these food products.
(6)

Answers

Answer:

Enzyme technology is a process that involves using specific enzymes to modify the chemical and physical properties of food ingredients. This technology can be used in the production of various food products, including sweets, vegetarian cheese, and lactose-free milk.

In the production of sweets, enzymes such as amylase and invertase can be used to break down complex sugars into simpler ones. This results in a sweeter taste and smoother texture. Additionally, enzymes like pectinase and cellulase can be used to break down fruit and vegetable fibers, making them more easily digestible and enhancing the flavor and texture of the sweets.

For vegetarian cheese production, rennet is traditionally used to coagulate milk protein and form cheese curds. However, enzymes such as microbial proteases and lipases can also be used to coagulate the milk proteins and form the cheese curds. This allows for the production of vegetarian cheese without the use of animal-based rennet.

In the production of lactose-free milk, lactase enzyme is used to break down lactose, which is the main sugar in milk. This enzyme is added to milk to hydrolyze lactose into glucose and galactose, which are more easily digested by people with lactose intolerance. The result is lactose-free milk that has the same taste and nutritional value as regular milk.

In summary, enzyme technology can be used in the production of food products by modifying the properties of food ingredients to achieve desired characteristics, such as taste, texture, and nutritional value. The use of enzymes in food production is a safe and effective way to improve food quality and meet consumer needs.


4) This is the word geologists use for loose pieces of minerals and rock. The particles are transported by wind, water, or ice,
and/or the force of gravity and eventually deposited.

Answers

Answer:sediment

Explanation:

name the three functional group in the compound pictured.

name the three functional group in the compound pictured.

Answers

The functional groups in the molecule is;

- ketone- alkene- hydroxylWhat is the functional group?

The functional group is the atom, group of atoms or bond that is the central point where chemical reactions occur in a compound. Now we know that some compounds could have a number of chemical functional groups which could be arranged in order of priority.

Let us look at the compound as shown. We can see that there are a number of functional groups in the molecule. The three functional groups here are;

- ketone- alkene- hydroxyl

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How do polar water molecules pass through the plasma membrane? (3 points)
Water molecules pass through channel proteins to cross the membrane.
Water molecules can pass through the membrane freely and rapidly.
Water molecules dissolve into the lipid bilayer and cross the membrane.
Water molecules attach to cholesterol and cross the membrane.

Answers

Water passes through the membrane in a diffusion process called osmosis. During active transport, energy is expended to assist material movement across the membrane in a direction against their concentration gradient. Active transport may take place with the help of protein pumps or through the use of vesicles.

what is an additional amount added to the total purchase price

Answers

Answer: The Tax

Explanation: Taxes

The Saffir-Simpson scale measures?
the density of water
the ocean temperature
none of the above
the pH of the ocean
the salinity of the ocean

Answers

The Saffir -Simpson scale measures  cosmogenous sediments.

The Saffir-Simpson Hurricane Wind Scale is used to predicts or measure the ( the accurate number from one to five) hurricane's strength by which speed it is coming , and mainly to get ready to face the upcoming natural clammities. The sustained wind speed of a storm defines its category. This method is used in determining the extent of probable property damage along a hurricane's course.Tropical cyclones which occurs in the northern Pacific Ocean and North Atlantic Ocean are measured by using the Saffir Simpson scale by meteorologists.

A meteorite is the solid piece of debris from which an object in deep space which can survives its passage by the atmosphere mainly to reach the surface of the planet or moon, such as ------a comet, asteroid, or meteoroid and so the meteorites are also known as cosmogenous sediments.

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“Dear Basketball" by Kobe Bryant Analysis
+
Kobe says that basketball "asked for his hustle", but he "gave his heart because it came with so much
more". What could his heart give to the game of basketball that his hustle could not?

Answers

Answer:

He describes basketball as asking him for his “hustle.” Instead, he gave the sport his heart. The speaker worked hard because he wanted to do the game justice. He wanted to show his love for the sport because that's “what you do / When someone makes you feel as / Alive” as basketball made him feel.

A substitution mutation occurred and changed the 5th base in the DNA from a C to a T. Write the sequence of RNA codons that would result from this kind of mutation. **Separate each codon with a space. TACACGCAATTACCAGGGTAGCCATTGATT

Answers

The sequence of RNA codons resulting from the substitution mutation that changed the 5th base in the DNA from a C to a T is AUGUGCGUUAUCCAGGGUAGCCAAUUGA.

In DNA, the base C (cytosine) pairs with G (guanine), while in RNA, the base C pairs with G. However, due to the substitution mutation, the original C is replaced by a T (thymine) in the DNA sequence.

In RNA, thymine is replaced by uracil (U). Therefore, the RNA codons corresponding to the mutated DNA sequence can be derived by replacing each T with U and maintaining the sequence order.

The original DNA sequence TACACGCAATTACCAGGGTAGCCATTGATT would have the corresponding RNA codons AUGUGCGUUAUCCAGGGUAGCCAAUUGA. Each codon consists of three bases and represents a specific amino acid or a start or stop signal in the translation process of protein synthesis.

It's important to note that the given DNA sequence is provided as a single continuous string, and without additional information about the reading frame or specific gene sequence, it is not possible to determine the precise protein sequence or the functional implications of the mutation.

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barium-137 emits a gamma ray from an excited state ( 137ba *). what is the resulting daughter nuclide?

Answers

When barium-137 (137Ba) emits a gamma ray from its excited state (137Ba*), it does not undergo any change in its atomic mass or atomic number.

Therefore, the resulting daughter nuclide would still be barium-137. The gamma ray emission occurs due to the transition of the nucleus from a higher energy level to a lower energy level, releasing energy in the form of gamma radiation.

This process is known as gamma decay and it does not alter the identity of the original nucleus. Barium-137 is a radioactive isotope with a half-life of 2.55 minutes and is commonly used in medical applications such as diagnostic imaging.

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Organism a is eukaryotic, unicellular, and lacks a cell wall. Organism b is eukaryotic, multicellular, has cell walls, and is autotrophic. In which kingdoms should these organisms be classified?.

Answers

The Kingdom Animalia stands apart among them due to the presence of multicellular bodies, a heterotrophic source of nutrition, eukaryotic cells, and cells without a cell wall.

The five Kingdom system has been used to group all creatures into these five categories. The Kingdom Animalia stands out among them due to the presence of multicellular organisms, a heterotrophic mode of nutrition, eukaryotic cells, and cells without a cell wall.

Members of the kingdom Monera include unicellular prokaryotic BGA and bacteria. Algae, every type of protozoa, and eukaryotic unicellular organisms are all included in the Protista kingdom. The kingdom fungus includes multicellular heterotrophic eukaryotes with chitinous cell walls. Kingdom Plantae is home to autotrophic organisms with cellulose cell walls while kingdom Animalia is home to heterotrophic animals without one.

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Two heterozygous white (brown fur is recessive) rabbits are crossed.
a. Make a Punnett square.
b. Describe all possible phenotypes.
c. List probabilities of all possible genotypes.

Answers

The cross for the given trait would be a monohybrid cross as only one trait has to be studied.

When two heterozygous white rabbits are crossed, the offspring that would be formed are as shown in the attached image.

The allele for white fur which is dominant can be denoted by W and thus, the allele for recessive brown fur will be denoted by w.

The resulting genotypes would be WW, Ww and ww in the ratio 1:2:1

The resulting phenotypes of the offspring would be 3 white and 1 brown, due to the genotypes of 1 homozygous dominant, 2 heterozygous dominant and 1 homozygous recessive.

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Two heterozygous white (brown fur is recessive) rabbits are crossed.a. Make a Punnett square.b. Describe

Sort the following Into whether they occur In metaphase l/anaphase
Sort the following into whether they occur in metaphase l/anaphase I of meiosis, in metaphase/anaphase of mitosis, or both.
• metaphase l/anaphase I of meiosis:……….
• Metaphase/anaphase of mitosis:………..
• Mitosis and meiosis:……..
1. bivalents are formed
2. a cell division follows
3. homologous chromosomes separate from one another
4. the number of chromosomes will be reduced overall
5. centromeres will divide in two
6. a telophase will follovw
7. the number of chromosomes stays the same overall
8. crossing over occurred just before

Answers

Metaphase I/anaphase 1 of meiosis: bivalents are formed, the number of chromosomes will be reduced overall, crossing over occurred just before.

Metaphase/anaphase of mitosis: homologous chromosomes separate from one another, centromeres will divide in two, the number of chromosomes stays the same overall

Both: a cell division follows, a telophase will follow.

Cell division

Cell division can be meiosis or mitosis. Sex cells undergo meiotic division while vegetative cells undergo mitotic division.

During meiosis, chromosomal reduction takes place. The daughter cells have half the chromosome number of the parent cell.

During mitosis, no chromosomal reduction. The daughter cells have the same number of chromosomes as the parent cell.

During the early stages of meiosis, homologous chromosomes pair up to form bivalents and crossing over occurs between non-sister chromatids.

Both cell divisions occur in 4 main stages: prophase, telophase, anaphase, and telophase. Meiosis is further divided to prophase I, metaphase I, anaphase I, telophase I, prophase II, metaphase II, anaphase II, and telophase II.

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