Match each equation for calculating heat lost or gained (q) during a process to its correct application. Drag statements on the right to match the left. Heating or cooling within a phase if moles are given C- q = nCAT Heating or cooling during a phase change D-a 9 = NAH change Heating or cooling within a phase if mass is given CHO q=mcAT

To ensure safety while carrying out her experiment, Maria should follow proper laboratory protocols and take necessary precautions like handle equipment and glassware carefully,wear appropriate personal protective equipment (PPE),read safety data sheets (SDS) to understand the proper handling,never work alone in the laboratory,etc.

Here are some recommendations:

1.Wear appropriate personal protective equipment (PPE), including safety goggles, lab coat, and gloves, to protect her eyes, body, and hands from potential hazards.

2.Familiarize herself with the properties and potential risks associated with the chemicals she will be working with. Read safety data sheets (SDS) to understand the proper handling, storage, and disposal procedures.

3.Work in a well-ventilated area or use a fume hood to minimize exposure to any fumes or gases that may be generated during the experiment.

4.Handle equipment and glassware carefully to prevent accidents or breakages. Ensure that all equipment is in good condition and appropriate for the experiment.

5.Follow proper techniques for measuring, mixing, and transferring chemicals to prevent spills or splashes. Use appropriate containers and labels to clearly identify and store chemicals.

6.Be aware of emergency procedures, including the location of safety equipment such as fire extinguishers, eyewash stations, and emergency showers.

7.Never work alone in the laboratory. Inform a supervisor or lab mate about the experiment and maintain communication throughout the process.

By following these safety measures, Maria can minimize risks and ensure a safe working environment during her experiment.

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The concentration of cuso4 in cuvette 2 is 0.030 M. None of the options given in the question are exact, but the closest answer is 0.024 M.

We can use the formula: concentration of stock solution x volume of stock solution = concentration of diluted solution x volume of diluted solution Let's assume that we diluted the stock solution by a factor of 2 to prepare cuvette 2 (i.e. we added an equal volume of water to the stock solution).

In this case, the volume of stock solution and diluted solution are the same, so we can simplify the formula to: concentration of stock solution = concentration of diluted solution x dilution factor Substituting the values given in the question, we get:

0.060 M = concentration of diluted solution x 2 Solving for the concentration of diluted solution, we get: concentration of diluted solution = 0.060 M / 2 concentration of diluted solution = 0.030 M

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1.65 10-3 M of NaOCl is present in the equilibrium mixture at pH 8.5. As a disinfection and bleaching agent, sodium hypochlorite (NaOCl) is a chemical compound that is frequently employed.

We must understand the dissociation equilibrium constant (Kb) for the reaction NaOCl + H2O HOCl + Na+ + OH- in order to compute the concentration of NaOCl in the equilibrium mixture at pH 8.5. This reaction's Kb expression is: [HOCl] Kb = [Na+] NaOCl / [OH-] The concentration of hydroxide ions (OH-) at pH 8.5 can be determined using the equation: pH is equal to 14 minus pOH, and 8.5 divided by 14 equals 5.5. 3.16 × 10-6 M [OH-] = 10 pOH The mass and molar mass of NaOCl can be used to compute its concentration: Mass / molar mass equals n(NaOCl): n(NaOCl) = 5.76 g / 74.44 g/mol = 0.0774 mol [NaOCl] = volume n(NaOCl) NaOCl = 0.0774 mol/0.5 L, or 0.1548 M. Given that [HOCl] 0 M and [Na+] [OH-] are true, we can infer that the initial concentration of HOCl is insignificant. Thus, The Kb phrase can be made shorter to: K= [HOCl][Na+] NaOCl and [OH-] can be combined to get [OH-]2. Changing the values: Kb = (3.16 x 10^-6) ^2 / 0.1548 = 6.47 x 10^-11 Kw is the ion product constant for water (1.0 x 10-14), and Ka is the acid dissociation constant for HOCl. Since Kb = Kw / Ka, we can compute Ka as follows: Ka = Kw / Kb = (1.55 x 10-4) / (6.47 x 10-11) As the Kb expression is a second-order equation, it may be used to compute the equilibrium concentrations of HOCl and Na+: [HOCl] = [NaOCl] (Kb / Ka)(1/2) ^(1/2) [HOCl] = 1.55 x 10-4 / 6.47 x 10-11 ^(1/2) (0.1548 M) (0.1548 M) ^(1/2) ≈ 1.07 x 10^-5 M 3.16 x 10-6 M [Na+] = [OH-] Lastly, we can figure out how much NaOCl is present in the equilibrium mixture: [Na+] + [HOCl] = 3.16 for [NaOCl]. 1.38 x 10-5 M = x 10-6 M + 1.07 x 10-5 M As a result, the equilibrium mixture's NaOCl concentration at pH 8.5 is roughly 1.38 x 10-5 M.

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shell3=2×3^2=18

shell one =2

shell 2=8

2+8+18=28

28 electron all together one the 3rd shell

35-28=7

7 electrons on the 4th shell

In bromine's n=4 shell, we have a a total of 2 + 5 = 7 electrons.

In bromine's (atomic number 35) electron configuration, the next outer shell after the third shell (n=3) is the fourth shell (n=4).

We will subtract the total number of electrons in the previous shells, in order to determine the number of electrons in the n=4 shell

The electron configuration of bromine (Br) is:

\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^5\)

We then count the electrons in the n=4 shell, we consider the electrons in the 4s and 4p subshells.

In the 4s subshell, we have  2 electrons (\(4s^2\)).

In the 4p subshell, there are 5 electrons (\(4p^5\)).

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Description of Rhodospirillum:

Rhodospirillum is best described as a Nitrogen-fixing bacteria.

What is Rhodospirillum?:

A genus of photosynthetic bacteria belonging to the Rhodospirillaceae family is called Rhodospirillum. Typically spiral-shaped, polarly flagellated, and with stacked vesicular lamellar photosynthetic membranes, their cells are also polarly flagellated.

It can utilize oxygen for aerobic respiration under aerobic conditions or an alternate terminal electron acceptor for anaerobic respiration because it is a facultative anaerobe. Photosynthesis is genetically reduced during aerobic growth, and Rhodospirillum turns colorless.  

But when oxygen levels are reduced, it instantly begins to produce photosynthesis machinery, which includes membrane proteins, bacteriochlorophylls, and carotenoids.

Additionally, it is a nitrogen-fixing bacterium, able to express and control nitrogenase, a protein complex that can catalyze the conversion of atmospheric nitrogen into ammonia.      

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We would need to know the concentration , volume and moles of hydrogen peroxide in order to determine the stoichometry .

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

From the question

mass of gold = 200 g

density = 20.5 g/mL

It's volume is

\(volume = \frac{200}{20.5} \\ = 9.7560975609...\)

We have the final answer as

Hope this helps you

Answer:

non metals are elements and elements are pure substances

Explanation:

Answer:

1.09 moles

Explanation:

Sodium has a molar mass of 23 grams per mole. To get the number of moles of sodium, divide 25 grams by 23 grams per mole. The answer is 1.09 moles

The Wilke-Chang method is used to predict the diffusion coefficient of Phosphoric acid in water. The Wilke-Chang method is a widely used empirical equation to estimate the diffusion coefficient of a solute in a solvent.

Fick's Law of diffusion states that the mass transfer rate of a solute across a porous membrane is proportional to the concentration gradient and the diffusion coefficient.

a. It takes into account the molecular weight, viscosity, and density of the solute and solvent. By plugging in the relevant values for Phosphoric acid and water, we can calculate the diffusion coefficient.

To calculate the diffusion coefficient of Phosphoric acid in water using the Wilke-Chang method, we need to know the molecular weight of Phosphoric acid (H3PO4) and water. The molecular weight of H3PO4 is 98 g/mol, and the molecular weight of water is 18 g/mol.

The Wilke-Chang equation is given by:

D = (1 / Φ) * [(1/M1 + 1/M2) / (√(1/μ1) + √(1/μ2))] * (T / P)

where D is the diffusion coefficient, Φ is the void fraction of the ceramic filter, M1 and M2 are the molecular weights of the solute and solvent, μ1 and μ2 are the viscosities of the solute and solvent, and T is the temperature in Kelvin.

b. We have the mass transfer rate and the thickness of the ceramic filter, so by rearranging Fick's Law equation, we can calculate the concentration at the other side of the filter.

The equation is given by:

J = -D * ∆C/∆x

where J is the mass transfer rate, D is the diffusion coefficient, ∆C is the change in concentration, and ∆x is the thickness of the ceramic filter.

We have the mass transfer rate (1.4 x 10^(-9) kg mol H3PO4/s.m²) and the thickness of the ceramic filter (4.2 mm = 0.0042 m), so by rearranging the equation, we can calculate the change in concentration (∆C) and then use it to find the concentration at the other side of the ceramic filter.

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In the given redox equation, the species that is oxidized is ClO3-.

To balance the redox equation in basic solution, we need to ensure that the number of electrons gained in the reduction half-reaction equals the number of electrons lost in the oxidation half-reaction. Additionally, we need to balance the atoms and charges on both sides of the equation.

In the given equation, ClO3- is reduced to Cl-, which means it gains electrons. On the other hand, HS- is oxidized to S, indicating a loss of electrons. Therefore, ClO3- is the species that is oxidized in this reaction.

To balance the equation, we need to add water molecules (H2O) and hydroxide ions (OH-) to balance the atoms and charges. The balanced equation in basic solution would be:

HS-(aq) + 6ClO3-(aq) + 8OH-(aq) → S(s) + 6Cl-(aq) + 4H2O(l)

By adding six ClO3- ions on the left side and eight OH- ions on the right side, the electrons lost in the oxidation of HS- are balanced by the electrons gained in the reduction of ClO3-. The resulting equation satisfies both charge and atom balance, allowing the redox reaction to be properly represented.

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Isotopes are atoms of the same element with the same number of protons and electrons but varying atomic weights and neutron counts. The isotopes of an element have the same chemical characteristics because they share the same number of electrons, but because of their various atomic weights, they have varied physical characteristics.

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The number of moles of Al₂(SO₄)₃ were formed if 12 moles of H₂O were produced is 8 moles.

The balanced chemical equation for the formation of Al₂(SO₄)₃ from aluminum and sulfuric acid is given below:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂O

In this equation, 2 moles of aluminum react with 3 moles of sulfuric acid to produce 1 mole of Al₂(SO₄)₃ and 3 moles of water.

From the balanced chemical equation, it is clear that 3 moles of water are produced for every 2 moles of aluminum reacted. So, if 12 moles of H₂O were produced, then the number of moles of aluminum reacted is:

(12/3) × (2/1) = 8 moles

Therefore, 8 moles of Al₂(SO₄)₃ were formed.

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Answer:

Physical changes are the changes which can be reversed.

Chemical changes are changes which cannot be reversed.

Please mark me as brainlist answer.

Explanation:

You see, In a physical change, no new substance is formed. A chemical change is always accompanied by one or more new substance

The orbitals are accountable to the law of octaves are: 1s 2s 2p 2p 3s 3p 3d  4s 4p 4d 5s 5p 4f 5d 6s 6p 5f 6d 7s .

The law of octaves introduced by the English chemist named J.A.R Newlands. According to it if we arranged the chemical elements in the periodic table according to their atomic mass then those that have the similar physical and the chemical properties will occur after the each interval of the seven elements.

The last element that is known was the thorium with the atomic mass of 232. Newlands' law of octave was firstly applicable only up to the calcium with atomic mass of 40. Now there are more ninety elements known up to the thorium.

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Explanation:

It is mainly the very low density of gases that make them bad conductors of heat. In liquids and solids atoms and molecules are densely packed and transfer of energy has much smaller distances to happen.

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The reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.

The term spontaneous reaction refers to a reaction that occurs with n external input of energy. We know that a spontaneous reaction is one in which the value of the change in free energy is negative. If the change in the free energy is positive then the reaction is nonspontaneous.

If the value of the change in free energy is zero then it follows that the reaction has attained equilibrium.

Now;

ΔG = ΔH - TΔS

ΔH = 2 kJ/mol

T =  500 K

ΔS =  0.017 kJ/(K-mol)

When we substitute values;

ΔG = 2 kJ/mol - (500 K * 0.017 kJ/(K-mol))

ΔG = -6.5 kJ

It the follows that the reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.

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For mathematical calculation,  it important to know the difference between Celsius and Fahrenheit scales.

The Fahrenheit scale is indeed a temperature scale that was proposed by scientist Daniel Gabriel Fahrenheit in 1724. The degree Fahrenheit is the unit of measurement.

There are several tales of how he first created his scale, but the original report states that the lowest defining point, 0 °F, was set as that of the freezing temperature of such a brine solution generated from a combination of water, ice, as well as ammonium chloride. For mathematical calculation,  it important to know the difference between Celsius and Fahrenheit scales.

Therefore, for mathematical calculation,  it important to know the difference between Celsius and Fahrenheit scales.

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Explanation:

First find the mass of 1 mole of water (Molecular mass)

\( H_{2} O = 2H + O \)

\(

= 2(1) + 32 \)

\(

= 34 \: grams

\)

Hence 1 mole of water is 34 g

Compare

1 mole = 34 g

1.33 mole = x g

\( \frac{x}{34} = \frac{1.33}{1} \)

\(

x = 1.33 \times 34 \)

\(

\color{blue}{\boxed{x = 45.2}} \: \: \: \: to \: 3 \: s.f.

\)

Therefore 1.33 moles of water is 45.2 grams

The mass of the substances can be given by the molar mass and the moles of the substances. The mass of 1.33 mole of water is expressed in grams as, 23.94 grams.

The mass has been defined as the product of the moles of the substance and the molar mass in grams per mole. The mass is given in grams and has a formula,

Moles = mass ÷ molar mass

Mass = molar mass × moles

Given,

Moles = 1.33 moles

Molar mass of water (H₂O) is calculated as = 2 (1) + 16= 18 grams per mole

Using the formula of mole, mass is calculated as:

Mass = molar mass × moles

mass = 1.33 × 18

= 23.94 grams

The mass of the substance can be calculated if the value of the molar mass and the moles of the substance has been known. The molar mass of the substance can be calculated by adding the mass of the individual masses of the element in a molecule.

Therefore, 1.33 mol of water contains 23.94 grams.

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Answer:

C.

Explanation:

The main reason for this decrease is an increase in the number of vaccinations of young children. The smallpox vaccine which was created in 1796 completely allows individuals to easily and quickly fight off the smallpox disease if they were to get it. By being able to fight the disease quickly and effectively it provides less time for the disease to affect another individual. Therefore, causing cases to decrease and become very rare as time goes on.

Answer:69.8

Explanation:

Explanation:

Atomic;

Numb...

SymbolN

ame

Atomic Mass...1HHydrogen1.007972HeHelium4.002603LiLithium6.941

Answer:

Subscripts are small numbers that tell us the number of each type of atom in a compound

If there is no number stated then it automatically means there is one atom present

Coefficients are big numbers in front of formulas that tell us we have more than 1 molecule present

Using the example of 2H₂O

The coefficient (2) multiplies the number of atoms of each element in this formula. For hydrogen 2 × 2 = 4 hydrogen atoms and 2 × 1 = 2 oxygen atoms

Answer:

Photosynthesis Equation

Explanation:

Reactant side contains Glucose and Oxygen whiles

Product side contains Carbon dioxide and Water which are the raw materials for photosynthesis.

Answer:5600 years

Explanation:

the amount of time it takes for the quantity to lose 50% (Half life) of its value. The half-life of carbon-14 is about 5600 years. Thus, after 5600 years, a piece of cotton cloth will contain half the carbon-14 that was in the original cotton plant.

Based on the scenario provided, it is possible that the student did not add enough 6M HNO₃ to the test tube containing 15 M NH₃ ,the unknown metal cation, and chloride ions.

The lack of a precipitate after adding ~20 drops of acid could be due to the incomplete neutralization of NH₃ or insufficient interaction between HNO₃ and the metal cation to form a precipitate.

The student may need to add more HNO₃ until the precipitate appears, ensuring proper neutralization and formation of the expected product.

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Answer:

Iron (III) oxide reacts with carbon monoxide according to the balanced equation: Fe2O3 + 3CO

The diffusion coefficient for the BCC iron sheet is approximately 2.1 * 10^-11 m^2/s at 725°C.

To calculate the diffusion coefficient (D) for the BCC iron sheet, you can use Fick's first law of diffusion, which is given by:

J = -D * (dC/dx)

where J is the diffusion flux (1.4 * 10^-8 kg/m^2s), dC is the change in carbon concentration (0.011 - 0.0073 wt% = 0.0037 wt%), and dx is the thickness of the sheet (2.2 mm = 0.0022 m).

Rearranging the formula to solve for D, we have:

D = -J / (dC/dx)

Now, you need to convert the change in carbon concentration to kg/m^3. Assuming the density of iron is 7874 kg/m^3, we have:

dC = 0.0037 wt% * 7874 kg/m^3 = 291.338 kg/m^3

Now, substitute the values into the equation:

D = -(1.4 * 10^-8 kg/m^2s) / (291.338 kg/m^3 / 0.0022 m)

D ≈ 2.1 * 10^-11 m^2/s

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The cost of travelling from San Francisco to Los Angeles is $65

Now we know that it could be expensive to use an automobile because of the cost of gasoline. The cost of the use of gasoline depends on the distance that is travelled.

If 1 gallon is required for 24 miles

x gallons is required for 405 miles

x =  405 miles * 1 gallon/24 miles

x = 16.9 gallons

Now;

If 1 gallon costs $3.85

16.9 gallons costs  16.9 gallons * $3.85/1 gallon

= $65

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