Now identify the element oxidized and the element reduced.

which element is oxidized?
which element is reduced?
which elements undergo no oxidation or reduction?

The success of dislodging electrons from a metal surface depends on the energy of the photons that hit it. Photons of violet light have a higher energy than photons of red light.

The energy of photons is directly proportional to their frequency, and the frequency of violet light is higher than that of red light. Therefore, violet light photons are more successful in dislodging electrons from a metal surface. This is because when the photons hit the metal surface, they transfer their energy to the electrons, which get excited and are dislodged from the surface. The greater the energy of the photon, the greater the probability of it being absorbed by the metal surface and dislodging an electron.

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Answer:

A solid

the internolecular forces are packed and leave no space behind

To solve this problem, we can use the combined gas law formula, which relates the initial and final states of a gas:

V1/T1 = V2/T2
Where:
V1 = initial volume = 2.5 L
T1 = initial temperature = 273 K (since STP is 0°C, which is 273 K)
V2 = final volume (what we need to find)
T2 = final temperature = 373 K

Rearrange the formula to find V2:
V2 = V1 * (T2 / T1)
Substitute the known values:
V2 = 2.5 L * (373 K / 273 K)
V2 ≈ 3.42 L
So, the new volume of the gas when the temperature is raised to 373 K and the pressure remains constant will be approximately 3.42 L.

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Answer:

\(6.029 \times 10^{23} molecules\)

Answer:

Explanation:

Decomposition reaction, also known as analysis or dissociation, is a type of chemical reaction in which a compound breaks down into simpler substances or elements. In this reaction, a single reactant undergoes a chemical change and produces two or more products.

The decomposition reaction can be represented by the general equation:

AB → A + B

Where AB is the reactant, and A and B are the products. The reactant AB is usually a compound, and it breaks down into its constituent elements or simpler compounds.

There are different types of decomposition reactions, including:

Thermal decomposition: It occurs when a compound is heated, resulting in its decomposition into simpler substances. For example, the thermal decomposition of calcium carbonate (CaCO3) produces calcium oxide (CaO) and carbon dioxide (CO2):

CaCO3 → CaO + CO2

Electrolytic decomposition: It takes place when an electric current is passed through an electrolyte, causing it to break down into its component ions. For instance, the electrolysis of water (H2O) leads to the decomposition into hydrogen gas (H2) and oxygen gas (O2):

2H2O → 2H2 + O2

Photochemical decomposition: It occurs when a compound undergoes decomposition due to exposure to light energy. Chlorine gas (Cl2) can decompose into chlorine atoms (Cl) under the influence of light:

Cl2 → 2Cl

These are just a few examples of decomposition reactions. They are important in various chemical processes and are used in industries, laboratory experiments, and natural phenomena. By understanding and controlling decomposition reactions, scientists can gain insights into the behavior of different compounds and develop practical applications in fields such as chemistry, materials science, and environmental science.

Answer:

Explanation:

reaction in which a compound breaks down into simpler substances or elements

By the  factor of 2 the rate change if the concentration of hno2 is doubled.

The rate law describes the relationship between the rate of a chemical reaction and the concentrations of its reactants. When the concentration of one of the reactants is altered, the rate of the reaction also changes correspondingly. The relationship between the rate of the reaction and the concentration of reactants is given by the rate law equation.

A factor is calculated using the following formula:

Factor = New concentration / Original concentration

As per the question, if the concentration of HNO2 is doubled, the factor is calculated as follows:

Factor = New concentration / Original concentration = 2x / x = 2

The factor is 2. It means that if the concentration of HNO2 is doubled, the rate of the reaction will increase by two times.

This is because the rate of the reaction is directly proportional to the concentration of HNO2.

For example, if the original rate is 100 units and the concentration of HNO2 is doubled, the new rate will be 200 units (100 x 2).

In conclusion, the factor by which the rate changes if the concentration of HNO2 is doubled is 2. This implies that the rate of the reaction will double if the concentration of HNO2 is doubled. This is due to the direct proportionality of the rate of the reaction with the concentration of HNO2.

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Answer:

lol its D

Explanation:

cuz i know maths

Answer:

D

Explanation:

edge

Answer:

Lithium

Explanation:

One mole or 239.2 g of PbO₂ or 239.2 g gives two moles or 606.5  of lead sulphate. Thus, 23.6 g of lead oxide will give 59.84 g of lead sulphate.

Lead oxide is an ionic compound formed by the ionic bonding between the transition metal lead and oxygen by losing two electrons from lead to oxygen. It reacts with sulphuric acid giving lead sulphate PbSO₄.

As per the given balanced reaction, one mole of lead oxide gives two moles of lead sulphate.

Molar mass of PbO₂ = 239.2 g/mol

Molar mass of  PbSO₄ = 303.27 g/mol

2 moles of  PbSO₄ = 2 × 303.27  = 606.54 g.

Thus, 239.2 g of lead oxide gives 606.54 g of PbSO₄. The mass of PbSO₄ produced from 23.6 g of lead oxide is:

= (23.6 × 606 .54 )/ 239.2 g

= 59.84 g.

Therefore, the mass of PbSO₄ produced from 23.6 g of PbO2 is 59.84 g.

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One way chemicals can help the environment is by using synthetic pesticides and fertilizers to increase crop yields while minimizing water usage. This helps to reduce the land area needed for farming, which in turn reduces deforestation. It also decreases the need to clear additional land for cultivation, which reduces greenhouse gas emissions and helps to prevent soil erosion. Additionally, some chemicals can be used to clean up contaminated soil and water sources, such as in the case of oil spills or industrial pollution.

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Answer:

the one that has more power to it

Explanation :

As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.

He placed the elements with similar nature in the same group.

According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.

As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127  and tellurium isotopes are tellurium-128 and tellurium-130.

Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

Watch glass is used in weighing desired amount of solid.

Watch glass is majorly used in weighing desired amount of solid that is to be used in chemical reaction, a watch glass is often placed on the scale, which is then followed by taring or zeroing of the scale so that only the weight of the sample substance is obtained excluding the weight of the watch glass. A watch glass is not only used for observing precipitation patterns and crystals, it is also used for drying solids.

A watch glass is generally round in shape, it is concave glass dish which is used for evaporation in chemistry. Watch glass can also be employed for weighing solids and as a lid for flasks and beakers.

Hence, watch glass is one of the useful component of chemistry lab.

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Answer:

Explanation:

To find the number of moles given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

\(n = \frac{2.8 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.65116279069...\)

We have the final answer as

Hope this helps you

The orientation of the Sun on the left side or the right side has no effect on the actual phases of the Moon. The Moon phases are determined by the position of the Moon relative to the Sun and the Earth, and not by the orientation of a model or a diagram.

In reality, the phases of the Moon are determined by the relative positions of the Sun, Earth, and Moon. As the Moon orbits the Earth, the amount of sunlight that reflects off its surface changes, causing the observable changes in the Moon's appearance as seen from Earth.

So, whether the Sun is on the left side or the right side of a model or a diagram, the actual position of the Moon relative to the Sun and the Earth will remain the same, and the Moon phases will occur in the same order and at the same times as they do in reality.

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\(\\ \sf\ast\Rrightarrow 2H_2O\longrightarrow 2H_2+O_2,\Delta H=484J\)

\(\\ \sf\ast\Rrightarrow 2NH_3\longrightarrow N_2+3H_2,\Delta H=92J\)

\(\\ \sf\ast\Rrightarrow \Delta H=+ve(Endothermic)\)

\(\\ \sf\ast\Rrightarrow \Delta H=-ve(Exothermic)\)

The percentage by mass of Chromium(II) Sulfate in the solution is 40.32%.

The mass of Chromium(II) in the Solution is = Mass of Chromium(II) in CrSO4

CrSO4 = Cr2(SO4)3 x (Cr2+/Cr3+)

CrSO4 = 30 g/mol x (1/3)

CrSO4 = 10 g/mol

Therefore, the mass of Chromium(II) in the solution = 10 g/mol

Percentage by mass of Chromium(II) Sulfate in the solution can be calculated as follows:

Percentage by mass = (Mass of Chromium(II) / Total Mass of Solution) x 100

Percentage by mass = (10 / 24.8) x 100

Percentage by mass = 40.32%

Therefore, the percentage by mass of Chromium(II) Sulfate in the solution is 40.32%.

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Answer:

The higher its electronegativity, the more an element attracts electrons.

Explanation:

Electronegativity is a property that describes the tendency of an atom to attract electrons (or electron density) toward itself. An atom's electronegativity is affected by both its atomic number and the size of the atom.

Answer:

hey,the answer is d, 1:2

Answer: D

Explanation:

The equation shows that one mole of nitrogen reacted with three moles of hydrogen to produce two moles of ammonia.

In the equation, 4 moles of antimony react with 3 moles of oxygen to form 2 moles of antimony oxide. Therefore, when 20 moles of oxygen are present,

20/3 = 6.66 moles of antimony oxide will be formed.

In the given chemical equation, for every 3 moles of oxygen (O2), 2 moles of antimony oxide (Sb2O3) are produced. Therefore, to determine the number of moles of Sb2O3 that will be formed from 20.0 moles of O2, we can use the conversion factor between moles of O2 and moles of Sb2O3. To do this, we divide the number of moles of O2 by the coefficient of O2 on the reactant side of the equation, which is 3. So 20.0 moles O2 / 3, moles O2/1 mole Sb2O3 = 6.66 moles of Sb2O3 will be formed.

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The CEC for this soil sample is 675.2 cmol(+)/kg.

The % Base Saturation for this soil sample is approximately 136.62%.

The % Acid Saturation for this soil sample is approximately 60.55%.

To    calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:

a. Calculation of CEC (Cation Exchange Capacity):

CEC is the sum of exchangeable cations in the soil. From the given results, we have:

CEC = Ca2+ + Mg2+ + K+ + Al3+

CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)

CEC = 168.7 mg / (25 g / 1000)

CEC = 675.2 cmol(+)/kg

b. Calculation of % Base Saturation (B.S.):

% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:

% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100

% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100

% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100

% B.S. = 136.62%

c. Calculation of % Acid Saturation:

% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:

% Acid Saturation = (H+ + Al3+) / CEC * 100

% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 60.55%

Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).

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One way to prove that all the products were formed when sodium bicarbonate solution and calcium chloride solution were combined is by carrying out some simple tests for the presence of each product.

Calcium Carbonate: Calcium carbonate is a white solid that is insoluble in water. To test for its presence, add a few drops of hydrochloric acid to the solution obtained from the reaction. If calcium carbonate is present, it will react with the acid to produce carbon dioxide gas, which can be seen as bubbles in the solution. Alternatively, you can filter the solution and wash the solid with water to remove any soluble salts. The solid residue left after drying is calcium carbonate.

Sodium Chloride: Sodium chloride is a soluble salt that dissolves completely in water. To test for its presence, simply evaporate the solution obtained from the reaction to dryness. If sodium chloride is present, it will remain as a white solid after evaporation.

Water: Water is a liquid that cannot be easily separated from the other products. However, you can test for its presence by using a drying agent such as anhydrous calcium chloride or silica gel. Simply add a small amount of the drying agent to the solution and stir for a few minutes. If the drying agent absorbs water, then water is present in the solution.

Cabon Dioxide:r Carbon dioxide is a gas that is released during the reaction. To test for its presence, you can bubble the gas through lime water (calcium hydroxide solution). If carbon dioxide is present, it will react with the lime water to form a white precipitate of calcium carbonate.

By carrying out these tests, you can prove that all the products have been formed and that no reactants are left in the solution.

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1. The glyoxylate cycle synthesizes glucose from acetyl-CoA under carbon limitation, while the citric acid cycle oxidizes acetyl-CoA for energy production.

2. Citric acid cycle intermediates oxaloacetate and α-ketoglutarate are replenished through anaplerotic reactions, including carboxylation of pyruvate or phosphoenolpyruvate, and transamination of glutamate.

3. Anaplerosis via amino acid metabolism and alternative carbon sources increases citric acid cycle intermediates' concentration.

1. The glyoxylate cycle differs from the citric acid cycle in that it operates in certain organisms (such as plants and bacteria) under conditions of carbon limitation, allowing the net synthesis of glucose from two molecules of acetyl-CoA. In contrast,

the citric acid cycle is a central metabolic pathway occurring in most organisms, involved in the oxidation of acetyl-CoA and energy production.

2. Two citric acid cycle intermediates and the pathways that replenish them are:

Oxaloacetate can be replenished through anaplerotic reactions, such as the carboxylation of pyruvate by pyruvate carboxylase or through the carboxylation of phosphoenolpyruvate by phosphoenolpyruvate carboxylase.

α-Ketoglutarate can be replenished through the transamination of glutamate by glutamate dehydrogenase or through the oxidative decarboxylation of isocitrate by isocitrate dehydrogenase.

3. One process to increase the concentration of citric acid cycle intermediates is through anaplerosis, which refers to the replenishment of depleted intermediates by various pathways,

including amino acid metabolism or by utilizing alternative carbon sources that can be converted into citric acid cycle intermediates through anaplerotic reactions.

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At a pressure pf 20.9 kpa as well as a temperature near 37 °C, the mass liquid oxygen gas needed to fill a volume od 6 l is 1.56G.

It all comes together in the celebration of the Eucharist mass, the main act of worship in the Roman Catholic Church. Ite, missa est, the Latin ecclesiastical expression for the congregation's dismissal, is where the word "mass" originates.

A: An object's volume, which is expressed in cubic units, is the space that it takes up in three dimensions. Both cm3 and in3 are examples of cubic units. The quantity of matter in an item is quantified by its mass, on the other hand. How much is a common way of determining mass.

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The cause of potassium ions leaving the axon just after the peak of the action potential is due to the opening of voltage-gated potassium channels. These channels open in response to the depolarization that occurs during the action potential.

And also during an action potential, depolarization causes voltage-gated sodium channels to open, allowing sodium ions to flow into the axon. This influx of positive ions causes the membrane potential to rapidly rise and eventually reach a peak. At this point, voltage-gated potassium channels begin to open, allowing potassium ions to flow out of the axon. This outflow of positive ions causes the membrane potential to rapidly repolarize and eventually reach a hyperpolarized state. This rapid efflux of potassium ions is what causes them to leave the axon just after the peak of the action potential.

When the membrane potential reaches its peak, the voltage-gated potassium channels open, allowing potassium ions to flow out of the axon, leading to repolarization and the eventual return of the membrane potential to its resting state.

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Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

The allowed energies of a particle in a one-dimensional box are given by:

E = (n^2 * h^2) / (8 * m * L^2)

Where:

E is the energy of the particle

n is the quantum number (1, 2, 3, ...)

h is the Planck's constant (approximately 6.626 x 10^-34 J*s)

m is the mass of the particle (mass of a proton = 1.673 x 10^-27 kg)

L is the length of the box (5.0 fm = 5.0 x 10^-15 m)

For n = 1:

E1 = (1^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 2:

E2 = (2^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 3:

E3 = (3^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

Now we can calculate the values:

E1 ≈ 1.808 x 10^-13 J

E2 ≈ 7.234 x 10^-13 J

E3 ≈ 1.631 x 10^-12 J

Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

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Answer:

fdhhdhdhdhhshdgdvdvebehbehdhehdhhddhdf

Answer:

No Se Espanol

Explanation: