nuclear reactions harness the power of ________, a process where the nuclei of atoms are split to release energy.

Answer:

the time period is 22.63 years

Explanation:

The computation of the number of years taken is as follows:

According to the Keplers law

\(T^2 \propto R^3\)

Here T denotes the time period

And, R denotes the average distance among the sun and planet

Now let us assume for earth

R_1 & T_1 be 1 year

So, for Planet

\(R_2 = 8R_1 , T_2 = ?\)

Now applied Keplers law

\((\frac{T_2}{T_1})^2 \propto (\frac{R_2}{R_1})^3\\\\(T_2)^2 = (\frac{8R_1}{R_1})^3 \times 1^2\\\\(T_2)^2 = 512\\\\T_2 = 22.674\)

So, the time period is 22.63 years

Force is a vector quantity hence it can be resolved into a vertical and a horizontal components.

1) The horizontal component of the applied force is given by;

Fnet = F cos θ

Fnet = 70.0N × cos (45.0)

Fnet = 49.5 N

2) The horizontal component of the frictional force is;

F = -Ff + mgsinθ

F = applied force

Ff =mgsinθ - F

Ff = (11 × 10 × sin 45) - 49.5

Ff = 28.3 N

Horizontal component of Ff

28.3 N cos 45 = 19.9 N

3) The applied force is given by;

F = 11 Kg ×  1.00m/s^2 = 11.0 N

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Answer:

Q=mc∆tita.

490J= m× 0.5J/Kg/C × (18-0°C)

490J= m × 9J/kg

490J

9J/Kg = m.

m= 54.4Kg

The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.

The magnetic field at the center of a solenoid is given by the following formula,

B = μ₀nI

where;

I = B/μ₀n

I = (0.00394) / (4π x 10⁻⁷ x 1580)

I = 1.98 A

Thus, the current required in the windings of the given long solenoid is 1.98 A.

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Answer:

Explanation:

Helium, if released into the atmosphere, will continue to rise until it disappears into space, rendering it the only substance that cannot be recovered.

What lightning has in common with the shock you receive when you touch a doorknob is that both phenomena involve the transfer of electric charges between two objects or areas with different electrical potentials. This process is known as electrostatic discharge (ESD).

1. Formation of electric charge: In both cases, there is a buildup of electric charges due to friction or other processes. With lightning, this occurs within clouds, where ice particles collide and generate static electricity. In the case of the doorknob shock, static electricity builds up on your body as you walk across a carpet, for example.

2. Difference in electric potential: Once there is a significant charge buildup, there is a difference in electric potential between the charged object and another object or area with an opposite charge.

For lightning, this difference occurs between the cloud and the ground, while for the doorknob shock, it occurs between your body and the metal doorknob.

3. Discharge: When the electric potential difference is large enough, a sudden and rapid discharge of the built-up charges takes place. This results in the visible lightning bolt or the spark and shock experienced when touching the doorknob.

4. Release of energy: In both cases, the discharge of electric charges releases energy in the form of light, heat, and sound. This energy release is what causes the bright flash of lightning and the audible snap of a doorknob shock.

In summary, lightning and the shock you receive when touching a doorknob are similar because they both involve the buildup and discharge of electric charges between objects or areas with different electrical potentials, ultimately releasing energy in the process.

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By applying Coulomb's Law concept, it can be concluded that:

a. the third charge can be placed at 0.859 meters to the right of the second charge;

b. if both charges are positive, then the third can be placed at 0.109 meters to the left of the second charge

Coulomb's law states that if there are two electrically charged objects a force will be created between them, which will be directly proportional to the product of the values of the two charges and inversely proportional to the square of the distance between the two objects.

F = k * Q₁ * Q₂ / d² , where:

F = electric force

k = constant

Q₁, Q₂ = charges

d = distance

We have the following information:

Q₁ = 5.00 μC

Q₂ = -3.00 μC

d = 0.025 m

A. To calculate the position of Q₃ (F=0), we assume that it will be placed x meter at the right of Q₂, so the distance between Q₁ and Q₃ = d + x. Then we have the following equations:

(k * |Q₁| * |Q₃|) / (d+x)² = (k * |Q₂| * |Q₃|) / x²

                |Q₁| / (d+x)² = |Q₂| / x²

                                 x = d / ± √((|Q₁| / |Q₂|) - 1)

If we substitute the value of Q₁ and Q₂, we get:

x = d / ± √((|Q₁| / |Q₂|) - 1)

  = 0.025 / ±√((5/3) - 1)

  = 0.250 / (±1.291 - 1)

  = 0.250 / (1.291 - 1) or 0.250 / (-1.291 - 1)

  = 0.859 or −0.109

since x must be positive, we pick x = 0.859 meters

B. The position of Q₃ gives that the two charges are positive can be obtained by assuming it will be placed between Q₁ and Q₂. Thus the distance between Q₁ and Q₃ = d - x.

(k * |Q₁| * |Q₃|) / (d-x)² = (k * |Q₂| * |Q₃|) / x²

               |Q₁| / (d-x)² = |Q₂| / x²

                               x = d / (1 ± √((|Q₁| / |Q₂|))

If we substitute the value of Q₁ and Q₂, we get:

x = 0.250 / (1 ± √((|5|/|3|))

  = 0.250 / (1 ± √((5/3))

  = 0.250 / (1 ± 1.291)

  = 0.250 / (1 + 1.291) or 0.250 / (1 - 1.291)

  = 0.109 or −0.859

since x must be positive, we pick x = 0.109 meters

Thus, the third charge can be placed at 0.859 meters to the right of the second charge; and if both charges are positive, then it can be placed at 0.109 meters to the left of the second charge.

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Answer:

1.2m/s

Explanation:

two speeds added together divided by total time.

(b) the presence of technetium in giant star spectra. Astronomers have direct evidence supporting the formation of heavy elements in stars through the observation of certain elements in their spectra.

Here correct answer is B.

One such element is technetium (Tc), which is not naturally occurring on Earth and has no stable isotopes. The presence of Tc in the spectra of certain types of stars, particularly red giants and Mira variables, is a strong indicator of heavy element nucleosynthesis in stars.

This is because Tc is a radioactive element with a short half-life, so any Tc present in a star's atmosphere must have been produced relatively recently through nuclear reactions within the star itself.

Gamma-ray emissions from cobalt 56 decay in supernovae (a) and observed elemental abundances (c) are also used to support the idea of heavy element formation in stars, but they are not direct evidence.

The light curves of type-I supernovae (d) are used to study the expansion and evolution of these events and are not directly related to heavy element formation in stars. Therefore, the correct answer is (b) the presence of technetium in giant star spectra.

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Answer:

8.04 seconds

Explanation:

Assuming that the child starts from rest at the bottom of the hill and travels until she comes to a stop, we can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

where v_f is the final velocity (which is zero since the child comes to a stop), v_i is the initial velocity (which is the velocity at the bottom of the hill), a is the acceleration (-0.392 m/s²), and d is the distance traveled.

We can solve for d:

d = (v_f^2 - v_i^2) / (2a)

= (0 - v_i^2) / (2-0.392)

= v_i^2 / 0.784

Since the child is sliding along flat snow-covered ground, there is no change in elevation, so we can use the distance traveled from the bottom of the hill to the stopping point as the distance d.

To find the time it takes for the child to travel this distance, we can use the following kinematic equation:

d = v_it + 0.5a*t^2

where t is the time and all other variables are as previously defined.

Substituting the expression for d obtained above, we get:

v_i^2 / 0.784 = v_it + 0.5(-0.392)*t^2

Solving for t, we get:

t = (2 * v_i) / 0.392

We still need to find the value of v_i, the initial velocity of the child at the bottom of the hill. To do so, we can use conservation of energy. The child starts at rest at the top of the hill, so all the initial energy is potential energy. At the bottom of the hill, all the potential energy has been converted to kinetic energy. Assuming no energy is lost to friction, we can equate these two energies:

mgh = 0.5mv_i^2

where m is the mass of the child, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the hill.

Solving for v_i, we get:

v_i = √(2gh)

Substituting this expression for v_i into the expression for t obtained earlier, we get:

t = (2 * √(2gh)) / 0.392

Plugging in the values of g, h, and a, we get:

t = (2 * √(29.820)) / 0.392 = 8.04 seconds

The molarity of the solution is 1.496 M.

To find the molarity of a solution, you need to use the formula Molarity = moles of solute / liters of solution.

First, you need to find the moles of solute (HCl gas) in the solution. You can do this by using the formula moles = mass / molar mass.

The molar mass of HCl gas is 36.5 g/mol.

So, the moles of HCl gas in the solution is:

moles = 54.7 g / 36.5 g/mol = 1.496 mol

Next, you need to find the liters of solution. The question states that there is 1L of solution, so this is already given to you.

Finally, you can plug in the values you found for moles of solute and liters of solution into the formula for molarity:

Molarity = 1.496 mol / 1 L = 1.496 M

So, the molarity of the solution is 1.496 M.

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Answer:

Explanation:

speed of sound in 24 degrees celsius

345.48m/s

hence 345.48m/s x 3s = 1036.44m

A) The mass of 28.76 mL of acetone is approximately 22.7 g.

B) The volume of 6.40 g of acetone is approximately 8.12 mL.

A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:

Mass = Volume * Density

Mass = 28.76 mL * 0.789 g/mL

Performing the calculation:

Mass ≈ 22.67564 g

Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.

B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:

Volume = Mass / Density

Volume = 6.40 g / 0.789 g/mL

Performing the calculation:

Volume ≈ 8.116 g/mL

Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.

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Answer:

1.Magnetic field

2.Potential energy

3.Magnetic force

4.kinetic energy

Answer:

i think its d

Explanation:

Answer:

See explanation

Explanation:

Observe, question, research, hypothesize, experiment, review hypothesis, report results.

Answer:

Explanation:

We are told that the height of the water tank is 3.5 m.

Now, the formula for pressure is;

P = ρgh

Where;

ρ is density of water = 1000 kg/m³

g is acceleration due to gravity = 9.8 m/s²

h = 3.5 m

Thus;

P = 1000 × 9.8 × 3.5

P = 34300 N/m²

When a vehicle turns, its rear wheels will follow a shorter path than its front wheels.

This is because the rear wheels of a vehicle follow a narrower radius in a turn compared to the front wheels due to the vehicle's turning pivot being closer to the front. This difference in path results in a phenomenon called "oversteer" where the rear of the vehicle swings out wider than the front during a turn. Oversteer can be used to intentionally initiate drifts in high-performance driving or corrected using counter-steering techniques to regain control of the vehicle.

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The free-fall acceleration on Mars is 3.71 m/s²

Given :

gravitational force acting on the robot is 504.6 N

F= 504.6 N

mass of the robot  = 136 kg

a = F/ m

= 504.6/ 136 =3.71 m/s²

The free-fall acceleration on Mars is 3.71 m/s²

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Answer:

200 J

Explanation:

In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:

100 N * 2 m = 200 J

If a mass of 40.0 n is postponed from a spring that has a force constant of 200 n/m. then maximum value of the force is 317.94 N

A force is an effect with the ability to change a motion of an object. An massed object can change its velocity, or accelerate, as a result of a force.

According to the given question

weight of the object w=40 N

hence mass will be m=w/g = 40/9.81

spring constant k= 200 N/m

frequency f=10 Hz

anplitude generated A=2cm= 2*10^-2m

As the system is undamped equation for amplitude can be

simplified as

A= F/m[(w^2-Wo^2)^2+(bW/m)^2]^1/2 here b=0

so,

A= F/m(w^2-wo^2)

hence force is F=Am(w^2-wo^2)

F=0.02*(40/9.81)[(2

10)^2 -(200/40)*9.81 ]

= 317.94 N

hence maximum value of force is F= 317.94 N

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The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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Answer:

No we cannot

Explanation:

But what causes a ring to appear around the moon? This phenomenon is called a "moon halo." According to the National Weather Service, this ring of light, which is actually an optical illusion, forms around the moon when moonlight refracts off ice crystals in cirrus clouds, high up in the Earth's atmosphere.

Answer:

375J

Explanation:

W=F x d

=250 x 15

=375J

The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea. If the force is applied at an angle to the displacement, the work is W = fd cos.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, For a constant force that is oriented in the same direction as the motion, it is easiest expressed as the product of the force's magnitude and the distance travelled.

A desk is being subjected to applied force if someone is pushing it across the room. The person's force applied to the desk is known as the applied force.

Mass and weight are not the same.The normal force is the supporting force exerted on an object when it collides with another stable object.

Therefore, W=F × d =250 × 15 =375J

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To design separate oscillators of 97 kHz and 79 MHz using the NE555 timer and a crystal oscillator.

Follow the steps below:

Designing an oscillator with the NE555 timer for a frequency of 97 kHz:

1. Connect pins 1 (Ground) and 8 (Vcc) of the NE555 to the appropriate power supply.

2. Connect pin 4 (Reset) to Vcc to disable the reset function.

3. Connect pin 5 (Control Voltage) to Ground.

4. Connect a resistor (R1) and a capacitor (C1) in series between pins 6 (Threshold) and 7 (Discharge). Choose values for R1 and C1 to set the desired time constant.

5. Connect pin 2 (Trigger) to the junction of R1 and C1.

6. Connect pin 3 (Output) to an appropriate load or circuit.

7. Provide necessary decoupling capacitors and stabilize the power supply.

8. Adjust the values of R1 and C1 to achieve the desired frequency of 97 kHz.

Designing an oscillator with a crystal oscillator for a frequency of 79 MHz:

1. Choose a crystal oscillator with a resonant frequency of 79 MHz.

2. Connect the crystal oscillator component to the appropriate pins of a suitable oscillator circuit or microcontroller.

3. Provide necessary decoupling capacitors and stabilize the power supply.

4. Configure the oscillator circuit or microcontroller to use the crystal oscillator component as the clock source.

5. Program or adjust the oscillator circuit or microcontroller to generate an output signal with a frequency of 79 MHz.

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Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

Answer:When the 5.0 kg cylinder fell 100 m, the final temperature of the water was

✔ 26.17

°C and the change in temperature was

✔ 1.17

°C.

When the 5.0 kg cylinder fell 500 m, the final temperature of the water was

✔ 30.86

°C and the change in temperature was

✔ 5.86

°C.

Explanation:

Answer:

26.17. 1.17. 30.86. 5.86.

Explanation:

Answer:

The answer is SYMBOL B.

Explanation:

The correct schematic is the one that shows three groups of long and short lines. A schematic with one long and one short (one group) would be a one cell; a schematic with a long, a short, a long, a short (two group), would be a two cell; and a schematic with a long, a short, a long, a short, a long and a short (three group), would be a three cell- hence why the answer is symbol B.

Answer:

Symbol B

Explanation:

I took the test :)