of the 20 standard amino acids, only is not optically active. the reason is that its side chain .

Answer:

0.012atm pressure

Explanation:

pressure is inversly proportional to volume. Mathematically,

V1/P1=V2/P2

When additional 0.25 moles of H2 are added to the reaction at equilibrium, the equilibrium would shift to the right to relieve the stress caused by the increase in H2 concentration.

According to Le Chatelier's principle, the system would respond by favoring the forward reaction to restore equilibrium. This means that more HI would be formed from the excess H2 and I2. As a result, the concentrations of H2 and I2 would decrease, while the concentration of HI would increase. The reaction would continue until a new equilibrium is reached. Note that the extent of the shift and the change in concentrations depend on the reaction's equilibrium constant and stoichiometry.

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Comparing the electronegativities of the two elements is one method of predicting the type of bond that will form between them.

Ionic bonds are produced between atoms of metals and non-metals where the metal loses an electron to complete its octet and the non-metal acquires that electron to complete its octet. Covalent bonds are formed when two atoms share electrons to complete their octets.

Ionic chemicals are bound together by ionic bonds, whereas covalent compounds are held together by strong covalent bonds. While covalent molecules are normally insoluble in water, ionic compounds are. Additionally, covalent molecules are typically more flammable than ionic ones.

If the electronegativity of the two atoms differs by enough to allow one to totally draw an electron away from the other, the connection is ionic.

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To determine the molar concentration of the hydrochloric acid (HCl) solution, we need to use the information provided about the mass of anhydrous sodium carbonate and the volume of HCl solution used in the titration.

Given:

Mass of anhydrous sodium carbonate: 0.338 g

Volume of HCl solution used: 15.3 mL

First, we need to convert the volume of the HCl solution to liters:

Volume of HCl solution = 15.3 mL = 0.0153 L

Next, we need to determine the number of moles of anhydrous sodium carbonate (Na2CO3) using its molar mass. The molar mass of Na2CO3 is 105.99 g/mol.

Number of moles of Na2CO3 = Mass / Molar mass

Number of moles of Na2CO3 = 0.338 g / 105.99 g/mol

Now, since the balanced chemical equation between Na2CO3 and HCl is 1:2, we can determine the number of moles of HCl required for the reaction.

Number of moles of HCl = (Number of moles of Na2CO3) * 2

Next, we calculate the molar concentration of the HCl solution using the moles of HCl and the volume of the HCl solution.

Molar concentration of HCl = (Number of moles of HCl) / Volume of HCl solution

Substituting the values:

Molar concentration of HCl = (0.338 g / 105.99 g/mol) * 2 / 0.0153 L

Calculating the value:

Molar concentration of HCl ≈ 0.442 mol/L

Therefore, the molar concentration of the hydrochloric acid (HCl) solution is approximately 0.442 mol/L.

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The total number of oxygen atoms in the mixture is 3.49 x \(10^{23\) atoms.

To determine the number of oxygen atoms in the given mixture, we need to first calculate the number of oxygen atoms in each compound and then add them up.

So, 3.49x10^23 molecules of H2O will contain:

3.49x10^23 x 1 oxygen atom = 3.49x10^23 oxygen atoms

Number of oxygen atoms in 78.1g of CH3OH:

To find the number of moles of CH3OH, we can use its molar mass:

Therefore, 78.1 g of CH3OH will contain:

2.44 mol x 1 oxygen atom = 2.44 oxygen atoms

The molecular formula of CO2 is CO2, which contains 2 oxygen atoms.

To find the number of moles of CO2, we can use the ideal gas law:

Assuming standard temperature and pressure (STP), which is 1 atm and 0°C (273 K), we have:

n = (1 atm x 14.2 L) / (0.0821 L·atm/mol·K x 273 K) = 0.58 mol

Therefore, 14.2 L of CO2 will contain:

0.58 mol x 2 oxygen atoms = 1.16 oxygen atoms

Now we can add up the number of oxygen atoms in each compound to find the total number of oxygen atoms in the mixture:

3.49x10^23 + 2.44 + 1.16 = 3.49x10^23 + 3.6 = 3.49 x \(10^{23\)

Therefore, the mixture contains 3.49 x \(10^{23\) oxygen atoms.

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When 2 moles of ethylene at 27°C are compressed from 49.4 L to 5 L, the work done in joules is -1219 J. This means that work is done on the gas, and the gas is compressed.

a. The van der Waals equation of state is:

\(\begin{equation}(P + \frac{a}{V^2})(V - b) = nRT\)

where:

P is the pressure

V is the volume

n is the number of moles of gas

R is the ideal gas constant

T is the temperature

a and b are van der Waals constants

The work done in an isothermal, reversible compression is:

\(W = -nRT \int_V^V_2 \frac{P}{V} dV\)

Substituting the van der Waals equation into the work equation, we get:

\(W = -nRT \int_V^V_2 \frac{(P + a/V^2)(V - b)}{V} dV\)

We can simplify this equation by expanding the parentheses and rearranging the terms:

\(W = -nRT \int_V^V_2 \frac{PV}{V} + \frac{a}{V^3} dV - nRT \int_V^V_2 \frac{b}{V} dV\)

The first integral can be simplified using the ideal gas law:

\(W = -nRT \int_V^V_2 \frac{PV}{V} dV = -nRT \int_V^V_2 \frac{nRT}{V} dV = -n^2RT \int_V^V_2 \frac{1}{V} dV\)

The second integral can be simplified using the following:

\(\int \frac{1}{V^3} dV = -\frac{1}{2V^2}\)

The third integral can be simplified using the following:

\(\int \frac{b}{V} dV = -\frac{b}{2}\)

Substituting these integrals into the work equation, we get:

\(W = -n^2RT \int_V^V_2 \frac{1}{V} dV + \frac{a}{2V^2}_V^V_2 - \frac{nb}{2}_V^V_2\)

Evaluating the integrals, we get:

\(W = -n^2RT \left[\ln(V_2) - \ln(V_1)\right] + \frac{a}{2(V_2^2 - V_1^2)} - \frac{nb}{2}(V_2 - V_1)\)

b. The number of moles of ethylene is 2 moles. The temperature is 27°C, which is 300 K. The initial volume is 49.4 L and the final volume is 5 L. The van der Waals constants for ethylene are a=0.0154L

2atm/mol

2 and b=0.065L/mol.

Substituting these values into the work equation, we get:

\(W = -(2)^2(0.08206 L atm/mol K)(300 K) \left[\ln(5 L) - \ln(49.4 L)\right] + \frac{0.0154 L^2 atm/mol^2}{2(5^2 L^2 - 49.4^2 L^2)} - \frac{0.065 L/mol}{2}(5 L - 49.4 L)\)

Evaluating this expression, we get:

W = -12.19 L atm = -1219 J

Therefore, the work done in joules when 2 moles of ethylene at 27°C are compressed from 49.4 L to 5 L is -1219 J.

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Complete question :

a) Derive the equation for the work done in an isothermal, reversible compression of one mole of a gas obeying the van der Waals equation of state.

b) Calculate the work in joules when 2 moles of ethylene at 27°C are compressed from 49.4L to 5L.

Answer:

Physical changes can include changing the colour, shape, state of matter, or volume of a substance.

The most vulnerable species to overexploitation among the given options is option c Tuna.

Overexploitation is the act of exploiting natural resources faster and more than they can be replenished. The process leads to the depletion of the natural resources, and the species becomes vulnerable to extinction.Explanation:Tuna is the species that is most vulnerable to overexploitation among the given options. Tuna is one of the most valuable fish globally and is among the most consumed fish species.

As a result, the tuna population has decreased rapidly due to overfishing.Overfishing is the main reason behind the depletion of tuna populations in many parts of the world. Moreover, tuna is among the species that are on the verge of extinction. Therefore, overexploitation can lead to a drastic decline in the population of tuna and, as a result, making the species vulnerable to overexploitation.The correct answer is c.

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Answer:

fitness. the ability of an organism to survive and reproduce in its environment. adaptation. the inherited characteristic that increases an organism's chance of survival.

An inherited characteristic of an organism is called a heredity.

The term heredity refers to the genetic heritage passed down by our biological parents. It is the transmission of traits from one generation to another generation. These traits can be physical, such as eye colour, blood type or a disease, or behavioral.

Heredity is also called biological inheritance, is the exiting of of traits from parents to their offspring either through asexual reproduction or sexual reproduction.

Heredity is a process in which organisms develop characteristics from their parents. These characteristics are called traits. Inheritance is the transmission of information from one generation of individuals to the next.

Thus, An inherited characteristic of an organism is called a heredity.

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Answer: Electrons

Explanation:

The oxidation state of Ba is +2, S in SO2 is +4, S in SO42- is +6, and Zn in ZnSO4 is +2.

Here are the oxidation states of each species:

Ba2+: The oxidation state of Ba is +2. This is because the barium ion has a charge of +2.

S in SO2: The oxidation state of S in SO2 is +4. This is because the sum of the oxidation states of all the atoms in a molecule must equal the charge of the molecule. Oxygen has an oxidation state of -2, so two oxygen atoms would have an oxidation state of -4. Therefore, the sulfur atom must have an oxidation state of +4 to balance the charge.

S in SO42-: The oxidation state of S in SO42- is +6. This is because the sum of the oxidation states of all the atoms in an anion must equal the negative charge of the anion. Oxygen has an oxidation state of -2, so four oxygen atoms would have an oxidation state of -8. Therefore, the sulfur atom must have an oxidation state of +6 to balance the charge.

Zn in ZnSO4: The oxidation state of Zn in ZnSO4 is +2. This is because the zinc ion has a charge of +2, and the sulfate ion has a charge of -2. Therefore, the sum of the oxidation states of Zn and S must equal 0.

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Answer:

help

Explanation:

How much carbon will turn into carbon 14 every year?

Science

Please help asap

The volume of the original CuCl2 solution needed to prepare the diluted solution is 2.98 mL.

We need to determine the moles of CuCl2 in 4.23 g.

To do that, we'll divide the mass by the molar mass of CuCl2:

Moles of CuCl2 = Mass of CuCl2 / Molar mass of CuCl2= 4.23 g / (63.55 + 2 * 35.45) g/mol= 0.024 mol

Now, we can determine the molarity of the diluted solution:M2 = moles of solute / volume of solutionM2 = 0.024 mol / 51.5 mL

Convert the volume from milliliters to liters:51.5 mL = 0.0515 L

Substitute the values in the above formula:M2 = 0.024 mol / 0.0515 LM2 = 0.465 M

Now we can use the formula M1V1 = M2V2 to find the volume of the initial solution needed to prepare the diluted solution.

V1 = (M2V2) / M1

Substitute the values:

M1 = 8.05 MV2 = 0.0515 LM2 = 0.465 MV1 = (0.465 * 0.0515) / 8.05V1 = 0.00298 L = 2.98 mL

Therefore, the volume of the original CuCl2 solution needed to prepare the diluted solution is 2.98 mL.

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One term that applies to eosin methylene blue (EMB) agar is "methylene blue." Methylene blue is a vital ingredient in EMB agar as it is responsible for inhibiting the growth of Gram-positive bacteria, while allowing the growth of Gram-negative bacteria.

It accomplishes this by entering the bacterial cell and binding to its DNA, interfering with the cell's metabolic processes and leading to its death. The presence of methylene blue in EMB agar allows for the differentiation between Gram-negative and Gram-positive bacteria based on their ability to grow in the presence of the dye. Another term that applies to EMB agar is "ingredient." EMB agar is a microbiological culture medium that contains a variety of ingredients that are essential for the growth and differentiation of bacteria. In addition to methylene blue, EMB agar contains eosin Y, which acts as a pH indicator and allows for the identification of lactose-fermenting bacteria. It also contains peptone, a source of nitrogen and carbon, and agar, which provides a solid surface for bacterial growth. The combination of these ingredients allows for the selective growth of Gram-negative bacteria, such as fecal coliforms, and the identification of lactose-fermenting bacteria. In summary, methylene blue and ingredient are both applicable terms when discussing EMB agar. Methylene blue is a critical component that allows for the differentiation of Gram-negative and Gram-positive bacteria, while ingredient refers to the various components that make up EMB agar and are necessary for its function.

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If a liquid is less dense than the liquid it is placed in, it will float. An unidentified material is added to a graded water cylinder. The stuff hits the bottom right away. Mass/volume equals density.

When placed in water, an object will float if its density is lower than that of the water, whereas it will sink if its density is higher. The density of a material is a distinguishing quality that is independent of the substance's volume. This assertion is supported by the Archimedes principle. This is due to the fact that the buoyant force pulling on the object is smaller than its weight. The object floats on the liquid's surface if its density is less than or equal to that of the liquid.

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The free energy required to synthesize ATP in a rat hepatocyte is 24,365.6364 J/mol

To calculate the free energy required to synthesize ATP in a rat hepatocyte, we can use the formula:

ΔG'º = -RTln(Q)

where:

ΔG'º is the standard free energy change,

R is the gas constant (8.314 J/(mol·K)),

T is the temperature in Kelvin,

ln(Q) is the natural logarithm of the mass-action ratio.

Given:

ΔG'º = -30.5 kJ/mol

T = 37°C = 37 + 273.15 = 310.15 K

Q = 5.33 x \(10^{(-10)\) M

First, we need to convert ΔG'º from kJ/mol to J/mol:

ΔG'º = -30.5 kJ/mol = -30.5 x \(10^3\) J/mol

Next, we can calculate the free energy required to synthesize ATP using the formula:

ΔG = ΔG'º - RTln(Q)

ΔG = \((-30.5 * 10^3 J/mol) - (8.314 J/(molK) * 310.15 K) * ln(5.33 x 10^{(-10))\)

≈ -30,500 J/mol - 2576.1911 J × (-21.3364)

≈ -30,500 J/mol + 54,865.6364 J

≈ 24,365.6364 J/mol

Calculating this expression will give us the value of ΔG, which represents the free energy required to synthesize ATP in a rat hepatocyte.

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Answer:

the beaker is the correct answer

There are several chemicals that do not induce vasodilation and permeability at an infection site.

One example is corticosteroids, which have anti-inflammatory properties and can reduce swelling and inflammation without causing vasodilation or increased permeability. Other examples include nonsteroidal anti-inflammatory drugs (NSAIDs) and certain antibiotics. However, it is important to note that the effectiveness of these chemicals may vary depending on the specific infection and individual response.

Vasoconstrictors, such as epinephrine and norepinephrine, narrow blood vessels, while anti-inflammatory agents, like corticosteroids, reduce inflammation and decrease permeability. These chemicals work in contrast to those that promote vasodilation and increased permeability, such as histamine and bradykinin, which contribute to the inflammatory response.

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Answer:

sodium bicarbonate, potassium bicarbonate and ammonium bicarbonate are the most commonly used bases.

Hello. You did not say what is the experiment to which this question refers, which makes it impossible for it to be answered accurately.

However, advice that should be given to anyone who should start an experiment is: establish a control treatment, provide all treatments with the same variables and the same resources, write down everything that happened in the experiment from implementation to data collection and results, make measurements and analyzes on the same date in all treatments and keep the steaks in the same environment.

Answer:

Which Lab are you doing?

Answer:

B. Water moving pieces of rock from one place to another is an example of chemical weathering!

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The atom that would gain electrons if lithium and chlorine were to combine chemically is chlorine. Lithium tends to lose electrons, while chlorine tends to gain electrons, so when they combine, lithium will lose an electron to chlorine, which will gain an electron. This forms an ionic compound called lithium chloride. Therefore, the correct answer is d. chlorine.

Let us discuss this in detail.

When lithium (an alkali metal) and chlorine (a halogen) combine chemically, lithium loses one electron, and chlorine gains that electron. This is because lithium has one valence electron that it readily gives up to achieve a stable electron configuration, while chlorine needs one more electron to complete its outer electron shell. As a result, chlorine gains an electron and becomes a negatively charged ion (Cl⁻), while lithium loses an electron and becomes a positively charged ion (Li⁺).

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Answer:

Breaking the bread

Explanation:

Because you're just breaking the bread into pieces.

0.67 moles of glucose are dissolved in 250 mL of a 2.67 M solution.

Thus, The name "glucose" is derived from the Greek word for "sweet." Your body uses this particular sort of sugar, which it obtains from the food you consume, as fuel.

It is referred to as blood glucose or blood sugar when it passes through your bloodstream to reach your cells. The hormone insulin transports glucose from the blood into the cells for use as fuel and storage. Blood glucose levels are higher in diabetics than in healthy people.

Either their cells don't react to insulin as insulin should or they don't have enough insulin to get it through. Long-term high blood glucose levels can harm your kidneys, eyes, and other organs.

Thus, 0.67 moles of glucose are dissolved in 250 mL of a 2.67 M solution.

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Answer:

the surface area of a solid reactant.

temperature.  

presence/absence of a catalyst.

Answer:

the property of air shown in the figure describe A.mass

The molecular mass of the unknown gas is 16, which means it is also oxygen gas (O2).

To solve this problem, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass.

First, we need to find the rate of diffusion of oxygen gas (O2) using the given information. Let's assume that the volume of oxygen gas that diffused through the porous plug is 1 liter. Then, we have:

Rate of diffusion of O2 = Volume of O2 diffused / Time taken = 1 L / 41 s

Next, we need to find the molecular mass of the unknown gas that diffuses through the same volume of the porous plug in 48 seconds under the same conditions. Let's call the molecular mass of this gas "M". Then, we can use Graham's law to set up the following equation:

Rate of diffusion of O2 / Rate of diffusion of unknown gas = sqrt(Molecular mass of unknown gas / Molecular mass of O2)

Substituting the values we have:

1/41 / Rate of diffusion of unknown gas = sqrt(M / 32)

Rate of diffusion of unknown gas = 1/48

Solving for M, we get:

M = (32 x (1/48)^2) / (1/41)^2

M = 16

Therefore, the molecular mass of the unknown gas is 16, which means it is also oxygen gas (O2).

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Sulfate ions will move from left to right through the salt bridge. The salt bridge allows the passage of ions between solutions.

An electrochemical cell is a cell where electrical energy is produced as a result of chemical reactions.

We have to note that the anions tend to move from the cathode to the anode hence, sulfate ions will move from left to right through the salt bridge.

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Chloroacetic acid is the strongest acid among the given options. The correct option is C.

To determine the strength of acids, we consider their dissociation in water and the resulting concentration of hydrogen ions (H⁺). The stronger the acid, the greater its dissociation and the higher the concentration of H⁺.

Chloroacetic acid (ClCH₂COOH) is the strongest acid among the given options because chlorine (Cl) is more electronegative than bromine (Br) and fluorine (F). The electronegativity of the halogens affects the acidity of the corresponding haloacetic acids. Chlorine's higher electronegativity facilitates the dissociation of H⁺, making chloroacetic acid stronger than bromoacetic acid (BrCH₂COOH) and fluoroacetic acid (FCH₂COOH).

Acetic acid (CH₃COOH) is the weakest acid among the options because it lacks the electronegative halogen atom. Acetic acid is a weak acid that only partially dissociates in water, resulting in a lower concentration of H⁺ compared to the haloacetic acids.

In summary, the increasing order of acid strength is: acetic acid < fluoroacetic acid < bromoacetic acid < chloroacetic acid. Therefore, the correct option is C.

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