On August 5, 2021, Crane Furniture shipped 50 dining sets on consignment to Furniture Outlet, Inc. The cost of each dining set was $340 each. The cost of shipping the dining sets amounted to $1700 and was paid for by Crane Furniture. On December 30, 2021, the consignee reported the sale of 40 dining sets at $840 each. The consignee remitted payment for the amount due after deducting a 5% commission, advertising expense of $590, and installation and setup costs of $770. The total profit on units sold for the consignor is

Answer:

2.4088 x 10^24 atoms of H

Explanation:

+5

how many hydrogen atoms are in one mole of CuNH4Cl3

1 MOLECULE of CuNH4Cl3 contains 4 H atoms

1 molecules contain 2 X4 = 8 H atoms

a mole is 6.022 x 10^23 particles

1 mole of CuNH4Cl3 contains 6.022 x 10^23 molecules

so there are 4 x 6.022 x 10^23 H atoms = 24.088 x 10^23

=2.4088 x 10^24 atoms of H

2.4088 x 10^24 hydrogen atoms are in one mole of CuNH4Cl3.

An atom of the chemical element hydrogen is known as a hydrogen atom. The Coulomb force holds a single positively charged proton and a single negatively charged electron to the nucleus of the electrically neutral atom. About 75% of the universe's total baryonic mass is made up of atomic hydrogen.

Many other applications exist for hydrogen. It is used in the chemical industry to produce cyclohexane and methanol, which are intermediates in the synthesis of polymers and medicines, as well as ammonia for agricultural fertilizer (the Haber process). In the course of the oil-refining process, it is also employed to remove sulphur from fuels.

1 molecule of CuNH4Cl3 contains 4 Hydrogen atoms

1 molecule contain 2 X 4 = 8 Hydrogen atoms

1 mole is 6.022 x 10^23 particles

1 mole of CuNH4Cl3 contains 6.022 x 10^23 molecules

Then, there are 4 x 6.022 x 10^23 H atoms

= 24.088 x 10^23

Thus, 2.4088 x 10^24 hydrogen atoms are in one mole of CuNH4Cl3.

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Answer:

the answer should be 0.47

Explanation:

Answer:

Radiation,becauea of the UV rays its been radiating off

Answer:

the answer is radiation :)

The reaction flask contains the mass of 1000.176 g. This calculated using the concept of Mole.

CaCO3 + 2HCl ----->  CaCl2 + CO2 + H2O.

For 1 mole of CaCO3 require 2 moles of HCL to form 1 mole CaCL2 and 1 mole of CO2.

The Molar mass of CaCO3  is 100.0869 g /mole.

The Molar mass of HCL is 36.46 g/mole

The Molar mass of CO2 is 44.01 g/mole.

As 0.21 g of carbon dioxide is given off,

The Moles of CO2 given off =0.21/44.01

The Moles of CO2 given off = 0.00477 moles.

The ratio of Moles of CaCO3 : HCL : CO2 is 1: 2 : 1.

As 0.00477 moles of CO2 is given off, that means 0.00477 moles of CaCO3 and 0.00952 moles of Hydrochloric acid is reacted.

So, the moles = mass of solute /molar mass

For calcium carbonate,

0.00477 moles of calcium carbonate =mass of CaCO3 /100.0869

Mass of CaCO3 becomes 0.477 g

So , 0.477 g of calcium carbonate is reacted to form 0.21 g  of CO2.

The unreacted mass of calcium carbonate =1 - 0.477 = 0.523 g

For, Hydrochloric acid,

Moles = mass of HCL / molar mass of HCL

0.00952 = mass of HCL /36.46

Mass of HCL = 0.347 g.

Mass of Hydrochloric acid reacted = 0.347 g form 0.21 g CO2.

The unreacted mass of hydrochloric acid = 1000 - 0.347

The unreacted mass of HCL= 999.653 g

Total left mass in reaction  flask= unreacted mass of CaCO3 + unreacted mass of Hydrochloric acid

Total left mass in reaction flask is,

                    = 0.523 +999.653

Total left mass in reaction flask is 1000.176 g.

So The reaction flask contains 1000.176 g.

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answer :

this is the structure if you want it

Answer:

to my own understanding I think it's 65 percent

(A) R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery.

(a) To calculate R_L (L, r), we differentiate the equation with respect to L while keeping r constant:

\(R_L(L, r) = d/dL (kL/r^4) = k/r^4\)

R_L represents the rate of change of resistance with respect to the length of the artery, L. The units of R_L are mmHg/cm. A positive value for R_L indicates that an increase in the length of the artery will result in an increase in resistance, meaning it becomes harder for blood to flow through the longer artery.

To calculate R_r (L, r), we differentiate the equation with respect to r while keeping L constant:

\(R_r(L, r) = d/dr (kL/r^4) = -4kL/r^5\)

R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) To calculate R_rr (L, r), we differentiate R_r (L, r) with respect to r while keeping L constant:

\(R_rr(L, r) = d/dr (-4kL/r^5) = 20kL/r^6\)

R_rr represents the rate of change of R_r with respect to r. The units of R_rr are mmHg/mm^2. A positive value for R_rr indicates that as the radius of the artery increases, the rate of decrease in resistance increases. In other words, the wider the artery becomes, the easier it is for blood to flow through.

To calculate R_rL (L, r), we differentiate R_r (L, r) with respect to L while keeping r constant:

\(R_rL(L, r) = d/dL (-4kL/r^5) = 0\)

R_rL represents the rate of change of R_r with respect to L. The units of R_rL are mmHg/(cm·mm). The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery. This implies that changes in the length of the artery do not affect the rate of change of resistance with respect to the radius.

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Answer: The answers are A, B, and E.

Explanation: Got it wrong on Edge and that's what it showed.

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the correct option are option A,B,D,E.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. among given option Ba(NO\(_3\))\(_2\), CaSO\(_4\), H\(_2\)CO\(_3\) and Mg\(_3\)(PO\(_4\))\(_2\) will dissociate in water.

Therefore, the correct option are option A,B,D,E.

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There are 0.052 moles of NH3 in 0.892 g of NH3.

Ammonia is an inorganic compound of nitrogen and hydrogen with the formula NH₃.

To find the number of moles of ammonia (NH3) in 0.892 g, we need to use the molar mass of NH3, which is 17.03 g/mol. We can use the following formula:

moles = mass / molar mass

Substituting the given values, we get:

moles = 0.892 g / 17.03 g/mol = 0.0523 mol

Therefore, there are 0.052 moles of NH3 in 0.892 g of NH3.

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The temperature of the 45.0 g piece of metal changed from 241 °C to 32.0 °C. is 0.48 j/ 9°C.

Temperature is a measure of the average kinetic energy of the atoms or molecules in the system. The zeroth law of thermodynamics says that no heat is transferred between two objects in thermal equilibrium; therefore, they are the same temperature.

In other words, Temperature is the measure of hotness or coldness of a body measured using Celsius, Kelvin, and Fahrenheit scales. The change in temperature is based on the amount of heat released or absorbed. The S.I unit of temperature is Kelvin. The Temperature formula is given by, Δ T = Q / mc.

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Answer:

a disease causing painful inflammation and stiffness of the joints.

An Earth-like exoplanet with active volcanoes and no oceans would have a different atmosphere than that of Earth's. In such a planet, gases like hydrogen and helium will not be as dominant as they are in our solar system.

Rather, the dominant gas in an Earth-like exoplanet's atmosphere with active volcanoes and no oceans would be carbon dioxide. Active volcanoes are a source of carbon dioxide and other greenhouse gases. Therefore, the carbon dioxide that the volcanoes would produce would build up in the planet's atmosphere, increasing its concentration in the atmosphere.

This increase in concentration of carbon dioxide would cause the planet's temperature to rise, making it hotter than Earth. Additionally, the high concentration of carbon dioxide would make the planet's atmosphere denser, resulting in a stronger greenhouse effect. As a result, the planet's surface would be warmer than Earth's.

Therefore, an Earth-like exoplanet with active volcanoes and no oceans would have a carbon dioxide-dominated atmosphere.

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Answer:

\(Distance = 40km\)

Explanation:

Given

\(Speed = 80km/hr\)

\(Time = 0.5hr\)

Required

Determine the distance covered

Distance is calculated as:

\(Distance = Speed * Time\)

Substitute values for Speed and Time

\(Distance = 80km/hr * 0.5hr\)

\(Distance = 80km * 0.5\)

\(Distance = 40km\)

Hence, you travelled 40km

Vitamin C plays an important role in protecting cells and tissues from the harmful effects of radiation.

Vitamin C, also known as ascorbic acid, is a powerful antioxidant that can stabilize EBT (electron beam irradiation) by neutralizing free radicals. When EBT is exposed to high-energy radiation, it generates free radicals that can cause damage to DNA, proteins, and other molecules. Vitamin C can donate electrons to these free radicals, thereby stabilizing them and preventing them from causing further damage. In addition, vitamin C can also regenerate other antioxidants such as vitamin E, further enhancing the protective effect against EBT-induced damage.

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The helix has a characteristic rise of 5.4 angstroms per turn and an average of 3.6 residues per turn. It can be either right or left-handed, depending on the direction of the helical turn. So, The correct answer is option: d.

However, it is not true that the alpha helix can accommodate only glycine and alanine residues in the center core of the helix. Other residues can also be found in the core, depending on their size and chemical properties. Therefore, the correct answer is (d) can accommodate only glycine and alanine residues in the center core of the helix.

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This question was already answered here's the link

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Answer:

A. It is made up of only one substance

Explanation:

Answer:

atomic mass

Explanation:

Answer:

\(\boxed {\boxed {\sf 19 \ M}}\)

Explanation:

Molarity is a measure of concentration in moles per liter, so the formula is:

\(molarity= \frac{moles \ of \ solute}{liters \ of \ solution}}\)

This solution has 9.0 moles of solute and 462 milliliters of solution. We must convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

Create a ratio.

Multiply by the value we are converting: 462 milliliters

\(0.462 \ L\)

Now we know both values and we can solve for the molarity.

\(molarity= \frac{9.0 \ mol}{ 0.462 \ L}\)

Divide.

\(molarity= 19.4805195 \ mol/L\)

The original measurements of moles and milliliters have 2 and 3 significant figures respectively. We have to round our answer to the least number of sig figs, which is 2 in this case.

For the number we found, that is the ones place. The 4 in the tenths place (19.4805195) tells us to leave the 9 in the ones place.

\(molarity= 19 \ mol/L\)

1 mole per liter is equal to 1 molar or M, so our answer is equal to 19 M.

\(molarity \approx 19 \ M\)

The molarity of the solution is approximately 19 M.

Answer:red, orange, yellow, green, blue, indigo and violet.

Explanation:

Answer:

When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.

Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.

The arrangement of the given isoelectronic series in order of their decreasing radius is N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺.

We are aware that, on the periodic table, the atomic radius of an element drops as one moves to the right and increases as one moves downward.

As the protons now exert a stronger force on the remaining electrons, the atomic radius of elements reduces when an electron is removed from the atom. The radius gets smaller as more electrons are taken out. The radius of an isoelectronic species will therefore be smaller the more positive charge it possesses.

When electrons are added to an atom, the force of attraction between the protons weakens due to the more protons present, and the electrons experience greater self-repulsion as a result of being packed closer together. To counteract this, the atomic radius of the ion is increased in order to reduce self-repulsion. As a result, the radius of the isoelectronic species increases as negative charge increases.

We can see from this that the atomic radius reduces as the positive charge rises.

As a result, the species are arranged in order of decreasing atomic radius as follows:

N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺

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DADP is a nucleotide composed of deoxyadenosine, a nitrogenous base, a pentose sugar, and two phosphate groups attached to the 5' carbon. Nucleosides are organic molecules formed by the combination of a nitrogenous base with a pentose sugar. Ribonucleosides are when the pentose sugar is deoxyribose and deoxyribonucleosides when it is deoxyribose.

DADP (Deoxyadenosine 5'-diphosphate) is a nucleotide composed of deoxyadenosine, a nitrogenous base (adenine), a pentose sugar (deoxyribose), and two phosphate groups attached to the 5' carbon. Nucleosides are organic molecules formed by the combination of a nitrogenous base with a pentose sugar (five-carbon sugar). Ribose is when the pentose sugar is ribose, while deoxyribose is when the pentose sugar is deoxyribose. A nucleoside has no phosphate group, while a nucleotide consists of a nucleoside and a phosphate group.

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Depending on the extraction you are performing and the way it was washed, the separatory funnel can either be dried, washed again, or just used as is.

In an ideal case, the separatory funnel was thoroughly washed and rinsed with deionized water. Because most liquid-liquid extractions include an aqueous layer, the small amount of water already present in the funnel will not have any negative impact on the results of your experiment, and the funnel can be used as it is.

If you are not sure whether the funnel was properly washed, you can quickly wash it yourself using detergent and water, rinse it thoroughly with deionized water, and then use it.

Finally, you can rinse the funnel with some ethanol (or, if possible, acetone), which will pick up water and wash away any organic impurities that might be present, and then dry it with a hair dryer. Be careful to wait for the funnel to cool after drying because many organic solvents have low boiling points and might cause a problem if poured into a hot funnel.

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When it comes to chemical formulas, the chemical formula is used to show the elements that make up a compound. For instance, water has the chemical formula H2O, which shows that it is made up of two hydrogen atoms and one oxygen atom.

Hydrogen ion (H+) has the chemical formula H+

Hydroxide ion (OH-) has the chemical formula OH-

Hydronium ion (H3O+) has the chemical formula H3O+.

The chemical formulas of hydrogen ion, hydroxide ion, and hydronium ion are:

H+ for hydrogen ion OH- for hydroxide ionH3O+ for hydronium ion.

An ion is an atom or a molecule that has gained or lost electrons. These atoms or molecules become charged ions due to their gain or loss of electrons. Hydrogen ion, hydroxide ion, and hydronium ion are three of the most common ions in aqueous solution that have a significant impact on chemical reactions. The hydrogen ion, which has a positive charge, is an essential component of many chemical reactions, particularly those that take place in water. It is represented by the chemical symbol H+. The hydroxide ion, which has a negative charge, is also a crucial component of many chemical reactions, particularly those that take place in water. It is represented by the chemical symbol OH-.The hydronium ion, which has a positive charge, is another important component of many chemical reactions, particularly those that take place in aqueous solutions. It is represented by the chemical symbol H3O+.

In summary, hydrogen ion, hydroxide ion, and hydronium ion are important components of many chemical reactions. They have different chemical formulas, with hydrogen ion being represented by H+, hydroxide ion by OH-, and hydronium ion by H3O+.

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